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HALL EFFECT
PRACTICAL
Akshita Chaudhary
Btech 1st year
Chemical Engineering
Aim:
To determine the Hall voltage developed
across the sample material.
To calculate the Hall coefficient and the carrier
concentration of the sample material.
Apparatus:
Two solenoids, Constant current supply, Four
probe, Digital gauss meter, Hall effect
apparatus (which consist of Constant Current
Generator (CCG), digital milli voltmeter and
Hall probe).
Theory:
If a current carrying conductor placed in a
perpendicular magnetic field, a potential
difference will generate in the conductor which
is perpendicular to both magnetic field and
current. This phenomenon is called Hall Effect.
In solid state physics, Hall effect is an
important tool to characterize the materials
especially semiconductors. It directly
determines both the sign and density of charge
carriers in a given sample.
Consider a rectangular conductor of
thickness t kept in XY plane. An
electric field is applied in X-direction
using Constant Current Generator
(CCG), so that current I flow through
the sample. If w is the width of the
sample and t is the thickness. There
for current density is given by:-
Fig.1 Schematic representation of Hall Effect in a
conductor.
CCG – Constant Current Generator, JX – current
density
ē – electron, B – applied magnetic field
t – thickness, w – width
VH – Hall voltage
If the magnetic field is applied along
negative z-axis, the Lorentz force moves
the charge carriers (say electrons) toward
the y-direction. This results in
accumulation of charge carriers at the top
edge of the sample. This set up a
transverse electric field Ey in the sample.
This develop a potential difference along
y-axis is known as Hall voltage VH and
this effect is called Hall Effect.
A current is made to flow through the sample material and the
voltage difference between its top and bottom is measured
using a volt-meter. When the applied magnetic field B=0,the
voltage difference will be zero.
We know that a current flows in response to an applied
electric field with its direction as conventional and it is either
due to the flow of holes in the direction of current or the
movement of electrons backward. In both cases, under the
application of magnetic field the magnetic Lorentz
force(fm=q(v×b))causes the carriers to curve upwards. Since
the charges cannot escape from the material, a vertical charge
imbalance builds up. This charge imbalance produces an
electric field which counteracts with the magnetic force and a
steady state is established. The vertical electric field can be
measured as a transverse voltage difference using a
In steady state condition, the magnetic force is balanced
by the electric force. Mathematically we can express it as
eE=evB ...(2)
Where 'e' the electric charge, 'E' the hall electric field
developed, 'B' the applied magnetic field and 'v' is the
drift velocity of charge carriers.
And the current 'I' can be expressed as,
I=neAv ...(3)
Where 'n' is the number density of electrons in the
conductor l,breadth w and thickness t.
Vh=Ew=vBw=IB/net
Vh=Rh*(IB/t) ...(4)
by rearranging eq(4) we get as:-
Rh=Vh*t/I*B ...(5)
Where RH is called the Hall coefficient
Rh=1/(n*e) ...(6)
Procedure:
 Controls
 Combo box
 Select procedure: This is used to select the part
of the experiment to perform.
1) Magnetic field Vs Current.
2) Hall effect setup.
 Select Material: This slider activate only if Hall
Effect setup is selected. And this is used to select
the material for finding Hall coefficient and carrier
concentration.
 Button
 Insert Probe/ Remove Probe: This button used to
insert/remove the probe in between the solenoid.
 Show Voltage/ Current: This will activate only if Hall
Effect setup selected and it used to display the Hall voltage/
current in the digital meter.
 Reset: This button is used to repeat the experiment.
 Slider
 Current : This slider used to vary the current flowing
through the Solenoid.
 Hall Current: This slider used to change the hall current
 Thickness: This slider used to change the thickness of the
material selected.
 Procedure for doing the simulation:
 To measure the magnetic field generated in the
solenoid
 Select Magnetic field Vs Current from the
procedure combo-box.
 Click Insert Probe button
 Placing the probe in between the solenoid by
clicking the wooden stand in the simulator.
 Using Current slider, varying the current through
the solenoid and corresponding magnetic field is to
be noted from Gauss meter.
 Hall Effect apparatus
 Select Hall Effect Setup from the Select the
procedure combo box
 Click Insert Hall Probe button
 Placing the probe in between the solenoid by
clicking the wooden stand in the simulator.
 Set "current slider" value to minimum.
 Select the material from “Select Material” combo-
box.
 Select the Thickness of the material using the
slider Thickness.
 Vary the Hall current using the sllider Hall
current.
 Note down the corresponding Hall voltage by
clicking “show voltage” button.
 Then calculate Hall coefficient and carrier
concentration of that material using the equation
 Equation :
 RH=VHt/(I*B)
 Where RH is the Hall coefficient
 RH=1/ne ,where n is the carrier concentration
S No. Current through solenoid Magnetic field generated
1 1 0.1482
2 1.5 0.2223
3 2 0.2964
4 2.5 0.3706
5 3 0.4447
6 3.5 0.5188
7 4 0.5929
S No. Thickness(m) Hall Current(A) Hall Voltage(V) Hall Coefficient
1 0.0002 0.001 0.021567 0.19403508
2 0.0002 0.0015 0.03235 0.19403208
3 0.0002 0.002 0.043133 0.19403058
4 0.0002 0.0025 0.053917 0.19403328
5 0.0002 0.003 0.0647 0.19403208
6 0.0002 0.0035 0.075484 0.19403380
 Procedure for doing real lab:-
 Connect ‘Constant current source’ to the solenoids.
 Four probe is connected to the Gauss meter and placed at
the middle of the two solenoids.
 Switch ON the Gauss meter and Constant current source.
 Vary the current through the solenoid from 1A to 5A with
the interval of 0.5A, and note the corresponding Gauss
meter readings.
 Switch OFF the Gauss meter and constant current source
and turn the knob of constant current source towards
minimum current.
 Fix the Hall probe on a wooden stand. Connect green wires
to Constant Current Generator and connect red wires to milli
voltmeter in the Hall Effect apparatus
 Replace the Four probe with Hall probe and place the
 Switch ON the constant current source and CCG.
 Carefully increase the current I from CCG and measure the
corresponding Hall voltage VH. Repeat this step for different
magnetic field B.
 Thickness t of the sample is measured using screw gauge.
 Hence calculate the Hall coefficient RH using the equation 5.
 Then calculate the carrier concentration n. using equation 6.
 Result
 Hall coefficient of the material =
 Carrier concentration of the material =

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HALL EFFECT-Akshita.pptx

  • 1. HALL EFFECT PRACTICAL Akshita Chaudhary Btech 1st year Chemical Engineering
  • 2. Aim: To determine the Hall voltage developed across the sample material. To calculate the Hall coefficient and the carrier concentration of the sample material. Apparatus: Two solenoids, Constant current supply, Four probe, Digital gauss meter, Hall effect apparatus (which consist of Constant Current Generator (CCG), digital milli voltmeter and Hall probe).
  • 3. Theory: If a current carrying conductor placed in a perpendicular magnetic field, a potential difference will generate in the conductor which is perpendicular to both magnetic field and current. This phenomenon is called Hall Effect. In solid state physics, Hall effect is an important tool to characterize the materials especially semiconductors. It directly determines both the sign and density of charge carriers in a given sample.
  • 4. Consider a rectangular conductor of thickness t kept in XY plane. An electric field is applied in X-direction using Constant Current Generator (CCG), so that current I flow through the sample. If w is the width of the sample and t is the thickness. There for current density is given by:-
  • 5. Fig.1 Schematic representation of Hall Effect in a conductor. CCG – Constant Current Generator, JX – current density ē – electron, B – applied magnetic field t – thickness, w – width VH – Hall voltage
  • 6. If the magnetic field is applied along negative z-axis, the Lorentz force moves the charge carriers (say electrons) toward the y-direction. This results in accumulation of charge carriers at the top edge of the sample. This set up a transverse electric field Ey in the sample. This develop a potential difference along y-axis is known as Hall voltage VH and this effect is called Hall Effect.
  • 7. A current is made to flow through the sample material and the voltage difference between its top and bottom is measured using a volt-meter. When the applied magnetic field B=0,the voltage difference will be zero. We know that a current flows in response to an applied electric field with its direction as conventional and it is either due to the flow of holes in the direction of current or the movement of electrons backward. In both cases, under the application of magnetic field the magnetic Lorentz force(fm=q(v×b))causes the carriers to curve upwards. Since the charges cannot escape from the material, a vertical charge imbalance builds up. This charge imbalance produces an electric field which counteracts with the magnetic force and a steady state is established. The vertical electric field can be measured as a transverse voltage difference using a
  • 8. In steady state condition, the magnetic force is balanced by the electric force. Mathematically we can express it as eE=evB ...(2) Where 'e' the electric charge, 'E' the hall electric field developed, 'B' the applied magnetic field and 'v' is the drift velocity of charge carriers. And the current 'I' can be expressed as, I=neAv ...(3) Where 'n' is the number density of electrons in the conductor l,breadth w and thickness t. Vh=Ew=vBw=IB/net Vh=Rh*(IB/t) ...(4)
  • 9. by rearranging eq(4) we get as:- Rh=Vh*t/I*B ...(5) Where RH is called the Hall coefficient Rh=1/(n*e) ...(6)
  • 10. Procedure:  Controls  Combo box  Select procedure: This is used to select the part of the experiment to perform. 1) Magnetic field Vs Current. 2) Hall effect setup.  Select Material: This slider activate only if Hall Effect setup is selected. And this is used to select the material for finding Hall coefficient and carrier concentration.
  • 11.  Button  Insert Probe/ Remove Probe: This button used to insert/remove the probe in between the solenoid.  Show Voltage/ Current: This will activate only if Hall Effect setup selected and it used to display the Hall voltage/ current in the digital meter.  Reset: This button is used to repeat the experiment.  Slider  Current : This slider used to vary the current flowing through the Solenoid.  Hall Current: This slider used to change the hall current  Thickness: This slider used to change the thickness of the material selected.
  • 12.  Procedure for doing the simulation:  To measure the magnetic field generated in the solenoid  Select Magnetic field Vs Current from the procedure combo-box.  Click Insert Probe button  Placing the probe in between the solenoid by clicking the wooden stand in the simulator.  Using Current slider, varying the current through the solenoid and corresponding magnetic field is to be noted from Gauss meter.
  • 13.  Hall Effect apparatus  Select Hall Effect Setup from the Select the procedure combo box  Click Insert Hall Probe button  Placing the probe in between the solenoid by clicking the wooden stand in the simulator.  Set "current slider" value to minimum.  Select the material from “Select Material” combo- box.
  • 14.  Select the Thickness of the material using the slider Thickness.  Vary the Hall current using the sllider Hall current.  Note down the corresponding Hall voltage by clicking “show voltage” button.  Then calculate Hall coefficient and carrier concentration of that material using the equation  Equation :  RH=VHt/(I*B)  Where RH is the Hall coefficient  RH=1/ne ,where n is the carrier concentration
  • 15. S No. Current through solenoid Magnetic field generated 1 1 0.1482 2 1.5 0.2223 3 2 0.2964 4 2.5 0.3706 5 3 0.4447 6 3.5 0.5188 7 4 0.5929
  • 16. S No. Thickness(m) Hall Current(A) Hall Voltage(V) Hall Coefficient 1 0.0002 0.001 0.021567 0.19403508 2 0.0002 0.0015 0.03235 0.19403208 3 0.0002 0.002 0.043133 0.19403058 4 0.0002 0.0025 0.053917 0.19403328 5 0.0002 0.003 0.0647 0.19403208 6 0.0002 0.0035 0.075484 0.19403380
  • 17.  Procedure for doing real lab:-  Connect ‘Constant current source’ to the solenoids.  Four probe is connected to the Gauss meter and placed at the middle of the two solenoids.  Switch ON the Gauss meter and Constant current source.  Vary the current through the solenoid from 1A to 5A with the interval of 0.5A, and note the corresponding Gauss meter readings.  Switch OFF the Gauss meter and constant current source and turn the knob of constant current source towards minimum current.  Fix the Hall probe on a wooden stand. Connect green wires to Constant Current Generator and connect red wires to milli voltmeter in the Hall Effect apparatus  Replace the Four probe with Hall probe and place the
  • 18.  Switch ON the constant current source and CCG.  Carefully increase the current I from CCG and measure the corresponding Hall voltage VH. Repeat this step for different magnetic field B.  Thickness t of the sample is measured using screw gauge.  Hence calculate the Hall coefficient RH using the equation 5.  Then calculate the carrier concentration n. using equation 6.  Result  Hall coefficient of the material =  Carrier concentration of the material =