টিটিটিসি হাইড্রোলিক্স ট্রেনিং

1. Welcome
To
Our Presentation

2. Title
Subject Based Practical Training
on
Hydraulics
Dated- 23/11/2019 to 28/11/2019

3. Name of Experiment
“Impactsof jet APPARATUS”

4. Engr. Md. Ramjan Ali
Principal
TTTC, Dhaka.
Mr. Rownak Mahmud
Additional Secretary And
Director General, DTE, Dhaka.
GRATEFULNESS

5. A.M.Atiqullah
Instructor (RAC)
Dhaka Polytechnic Institute.
G.M.Akter Hossain
Jr.Instructor (RAC)
Dhaka Polytechnic Institute.
Md. Aminul Islam Bhuiyan
Instructor (Civil)
Dhaka Polytechnic Institute.
Mohammad Nasir Uddin
Instructor (RAC)
Chandpur Polytechnic Institute.
Ranajit Kumar Das
Instructor (Power)
Khulna Polytechnic Institute.
Our Group Member’s

6.  B.M Aminul Islam
Head of the department (Civil)
and
Course Co-ordinator
T.T.T.C, Dhaka.
 Mst. Shahela Pervin
Asst. Professor (Civil)
T.T.T.C, Dhaka.
 Salma Begum
Asst. Professor (Civil)
T.T.T.C, Dhaka.
Shanjida Hossain
TT Instructor(Civil)
T.T.T.C, Dhaka.
Instructed by

7. Name of the Experiments:- IMPACT OF JET APPARATUS
Aims : To determine the impact of jet apparatus
Objectives :
To demonstrate that the force on a vane is proportional to the rate of
delivery of momentum.
To show that we can predict the force on a vane from a combination
of its surface shape and the properties of the jet directed at it.

8. Equipment & Materials
Impact of Jet Hydraulic Bench with Impact of Jet

9. Experiment Theory
0.15 m
y
s
y
Jockey Weight
Weigh beam
0.15 m
g
F
M

10. The weight beam forms a lever, pivoted at one end, with the jet force
upwards at a distance of 150 mm from the pivot. The mass of the
jockey weight and gravity are an opposing force downwards. At initial
balance, you cancel out the mass of the weigh beam itself using the
balance spring. This allows you to calculate the force using moments,
so that:
As the mass M of the Jockey Weight is 0.6 kg, then F = 4gy (3)
and as gravity g is constant, then F = 39.24y
Fx 0.15= Mgy
Or F=
𝑀𝑔𝑦
0.15

12. M= Mass flow=ρAV
Or V=
𝑀
ρ𝐴
Impulsive force, F=
𝑀𝑔𝑦
0.15
= 39.24y
Jet momentum –
ρav2 for Ѳ= 90°
1.5 ρav2 for Ѳ= 120°
2 ρav2 for Ѳ= 180°

F
u0
u
Vane Theory

13.  Create a blank results table similar to Table
 Make sure the weigh beam is at balance with the jockey weight at the zero
position.
 Start the hydraulic bench and set to maximum flow.
 Move the jockey weight until the beam balances again. Note the distance y
from the zero position.
 Record the flow rate using your hydraulic bench.
 Reduce the hydraulic bench flow in steps to give at least eight more readings
of distance y and flow in relatively equal increments.
 Repeat for the other vanes (plates) that you need to test.
Working procedure

14. General Layout of jet impact

15. Observation Flow rate
L/sec
MassFlow
rate
m
kg.s-1
Distance
y
(m)
Velocity
u
(m.s-1)
Velocity
u0
(m.s-1)
Rate of
delivery of
momentum
mu0
(kg m.s-2)
Force
F (N)
01 0.192 0.192 0.01 2.52 2.38 0.47 0.391
02 0.210 0.210 0.02 2.67 2.54 0.53 0.78
03 0.320 0.320 0.03 4.07 3.98 1.28 1.17
04 0.370 0.370 0.04 4.71 4.64 1.72 1.56
05 0.405 0.405 0.05 5.16 5.09 2.06 1.96
Data Sheet

16. Data Analysis
Convert your flow rate into mass flow rate m· .
Calculate the flow velocity u and use this to calculate u0. Calculate the rate
of delivery of momentum m· u0 and force F.
Create a chart of force F on the vane (vertical axis) against rate of delivery
momentum m· u0 . Add to the chart, the results for each of the plates
(vanes) that you test.
Compare your actual results with the theoretical results and identify any
differences or causes of error.

17. Use of Impact of Jet
 One of the applications of jet impact is used to
generate electricity.
 Impact of jet is used to rotate the turbine namely
Pelton wheel in the generator.
 The water jet is applying force tangential to the
wheel.
 The tangential forces of water jet generate moment or
torque on the wheel to its maximum value and
therefore increase the mechanical energy of Pelton
wheel.

18. Turbine Wheel

19. Conclusion
Actual results are very similar to theory, but overall
slightly lower. This suggests that the measured forces
were lower than expected or the momentum was higher
than expected

21. Any Questions???