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TIF 21101 
APPLIED MATH 1 
(MATEMATIKA TERAPAN 1) 
Week 4 
Relation and Function I 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
Overview 
Obviously, we do not realize that there many connections 
are happened in our circumtances. For examples, day and 
night happens because of earth rotation, all students in 
math are also connected to other subjects and so on. 
Strictly speaking, something happens because of other 
subject called “reason”. 
Relations can be used to solve problems such as 
determining which pairs of cities are linked by airline flights 
in a network, finding a viable order for the different phases 
of a complicated project, or producing a useful way to store 
information in computer databases. 
For couple weeks later, you all will be introduced this 
“connection” in mathematic’s view. And we shall learn to 
“map” or “transform” the “connection”. 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
Objectives 
 Cartesian Product 
 Relation 
 Invers Relation 
 Pictoral Repesentation of Relation 
 Composition of Relation 
 Relation Properties 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
Cartesian Product 
Consider two sets A and B. The set of all ordered 
pairs (a, b) where aÎA and bÎB is called the 
product, or Cartesian product, of A and B. 
The short designation of this product is A x B, 
which is read “A cross B”. 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
Ex. 
Let A={1, 2} and B={a, b, c}. 
Then 
AxB {(1,a},(1,b),(1,c),(2,a),(2,b),(2,c)} 
BxA {(a, 1), (a,2), (b, 1), (b,2), (c,1),(c,2)} 
AxA {(1, 1), (1,2), (2,1), (2,2)} 
From the example above we can conclude, that, 
First, 
A x B ¹ B x A 
The Cartesian product deals with ordered pairs, so naturally the order in 
which the sets are considered is important. 
Second, using n(s) for the number of elements in a set S, we have 
n(A x B) = n(A) . n(B) = 2 x 3 = 6 
Therefore, there will be 26 = 64 relation from A to B 
So…..what is relation????? 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
Relation 
Relation is just a subset of the Cartesian product 
of the sets. 
Definition. 
Let A and B be sets. A binary relation or, simply, 
relation from A to B is a subset of A x B. 
In other words, a binary relation from A to B is a 
set R of ordered pairs where the first element 
(domain) of each ordered pair comes from A and 
the second element (codomain or range) comes 
from B. 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
We use the notation a R b to denote that (a, b) Î R 
and a / 
R b to denote that (a, b) Ï R. 
Moreover, when (a, b) belongs to R, a is said to be 
related to b by R. 
Assume C= {1,2,3} and D ={x,y,z} and let R {(1,y), (1,z), 
(3,y)}. Put the R or R for the followings: 
/ 
1…X 1…Y 1…Z 
2…X 2…Y 2…Z 
3…X 3…Y 3…Z 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
Invers Relation 
The invers relation of set is defined as the opposite 
mapping of relation itself. 
Let R be any relation from a set A to a set B. The 
inverse of R, denoted by R-1, is the relation from B 
to A which consists of those ordered pairs which, 
when reversed, belong to R; that is, 
R-1= {(b,a): (a,b) Î R} 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
Ex. 
Let R = {(1,y), (1,z), (3,y)} from A = {1,2,3} to 
B = {x,y,z}, then 
R-1 = {(y, 1), (z, 1), (y,3)} 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
Pictoral Repesentation of Relation 
Arrow Diagram 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
Table Representation 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
Matrice Representation 
Suppose R is the relation from A to B, where 
A={ a1,a2,a3,…,am} and B={ b1,b2,b3,…,bn}. 
The relation can be describe in matrice M=[mij] as 
folow: 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
Ex. 
a1 = 2 
a2 = 3 
a3 = 4 
b1 = 2 
b2 = 4 
b3 = 8 
b4 = 9 
b5 = 15 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
Directed Graph 
First we write down the elements of the set, and 
then we drawn an arrow from each element x to 
each element y whenever x is related to y. 
The point is, directed graph does not show the 
relation between one set to the other. It just shows 
the relation among the element inside the set. 
Ex. R is relation on the set A = {1,2,3,4} 
R = {(1,2), (2,2), (2,4), (3,2), (3,4), (4,1), (4,3)} 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
Prac. 
Show the relation from 
the directed graph 
Bandung 
Jakarta Surabaya 
Medan 
Makassar 
Kupang 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
Composition of Relation 
Suppose A, B, and C be sets, and let R be a 
relation from A to B and let S be a relation 
from B to C. R Í A x B and S Í B x C. 
Then R and S give rise to a relation from A 
to C, which is denoted by RoS and defined 
as 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
Ex. 
Assume A= {1,2,3,4}, B ={a,b,c,d}, C ={x,y,z} 
and let R= {(1,a), (2,d), (3,a) (3,b), (3,d)} and 
S ={(b,x), (b,z), (c,y), (d,z)} . Show the 
relation a(RoS)c! 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
From the picture we can observe that there is an arrow 
from 2 to d which is followed by an arrow from d to z. We 
can view these two arrows as a “path” which “connects” the 
element 2 Î A to the element z Î C. Thus, 
2(R o S)z since 2Rd and dSz 
Similarly there is a path from 3 to x and a path from 3 to z. 
Hence, 
3(R o S)x and 3(R o S)z 
No other element of A is connected to an element of C. 
Therefore, the composition of relations R o S gives 
RoS= {(2,z), (3,x), (3,z)} 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
Soal : 
R = {(1, 2), (1, 6), (2, 4), (3, 4), (3, 6), (3, 8)} 
S = {(2, u), (4, s), (4, t), (6, t), (8, u)} 
Gambarkan grafiknya dan tentukan R o S 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
R o S = {(1, u), (1, t), (2, s), (2, t), (3, s), (3, t), (3, u) } 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
Exercises : 
1 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
Relation and Function 
2. 
2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1

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Matematika terapan week 4

  • 1. TIF 21101 APPLIED MATH 1 (MATEMATIKA TERAPAN 1) Week 4 Relation and Function I 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 2. Relation and Function Overview Obviously, we do not realize that there many connections are happened in our circumtances. For examples, day and night happens because of earth rotation, all students in math are also connected to other subjects and so on. Strictly speaking, something happens because of other subject called “reason”. Relations can be used to solve problems such as determining which pairs of cities are linked by airline flights in a network, finding a viable order for the different phases of a complicated project, or producing a useful way to store information in computer databases. For couple weeks later, you all will be introduced this “connection” in mathematic’s view. And we shall learn to “map” or “transform” the “connection”. 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 3. Relation and Function Objectives Cartesian Product Relation Invers Relation Pictoral Repesentation of Relation Composition of Relation Relation Properties 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 4. Relation and Function Cartesian Product Consider two sets A and B. The set of all ordered pairs (a, b) where aÎA and bÎB is called the product, or Cartesian product, of A and B. The short designation of this product is A x B, which is read “A cross B”. 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 5. Relation and Function Ex. Let A={1, 2} and B={a, b, c}. Then AxB {(1,a},(1,b),(1,c),(2,a),(2,b),(2,c)} BxA {(a, 1), (a,2), (b, 1), (b,2), (c,1),(c,2)} AxA {(1, 1), (1,2), (2,1), (2,2)} From the example above we can conclude, that, First, A x B ¹ B x A The Cartesian product deals with ordered pairs, so naturally the order in which the sets are considered is important. Second, using n(s) for the number of elements in a set S, we have n(A x B) = n(A) . n(B) = 2 x 3 = 6 Therefore, there will be 26 = 64 relation from A to B So…..what is relation????? 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 6. Relation and Function Relation Relation is just a subset of the Cartesian product of the sets. Definition. Let A and B be sets. A binary relation or, simply, relation from A to B is a subset of A x B. In other words, a binary relation from A to B is a set R of ordered pairs where the first element (domain) of each ordered pair comes from A and the second element (codomain or range) comes from B. 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 7. Relation and Function We use the notation a R b to denote that (a, b) Î R and a / R b to denote that (a, b) Ï R. Moreover, when (a, b) belongs to R, a is said to be related to b by R. Assume C= {1,2,3} and D ={x,y,z} and let R {(1,y), (1,z), (3,y)}. Put the R or R for the followings: / 1…X 1…Y 1…Z 2…X 2…Y 2…Z 3…X 3…Y 3…Z 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 8. Relation and Function Invers Relation The invers relation of set is defined as the opposite mapping of relation itself. Let R be any relation from a set A to a set B. The inverse of R, denoted by R-1, is the relation from B to A which consists of those ordered pairs which, when reversed, belong to R; that is, R-1= {(b,a): (a,b) Î R} 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 9. Relation and Function Ex. Let R = {(1,y), (1,z), (3,y)} from A = {1,2,3} to B = {x,y,z}, then R-1 = {(y, 1), (z, 1), (y,3)} 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 10. Relation and Function Pictoral Repesentation of Relation Arrow Diagram 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 11. Relation and Function Table Representation 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 12. Relation and Function Matrice Representation Suppose R is the relation from A to B, where A={ a1,a2,a3,…,am} and B={ b1,b2,b3,…,bn}. The relation can be describe in matrice M=[mij] as folow: 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 13. Relation and Function Ex. a1 = 2 a2 = 3 a3 = 4 b1 = 2 b2 = 4 b3 = 8 b4 = 9 b5 = 15 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 14. Relation and Function Directed Graph First we write down the elements of the set, and then we drawn an arrow from each element x to each element y whenever x is related to y. The point is, directed graph does not show the relation between one set to the other. It just shows the relation among the element inside the set. Ex. R is relation on the set A = {1,2,3,4} R = {(1,2), (2,2), (2,4), (3,2), (3,4), (4,1), (4,3)} 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 15. Relation and Function 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 16. Relation and Function Prac. Show the relation from the directed graph Bandung Jakarta Surabaya Medan Makassar Kupang 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 17. Relation and Function Composition of Relation Suppose A, B, and C be sets, and let R be a relation from A to B and let S be a relation from B to C. R Í A x B and S Í B x C. Then R and S give rise to a relation from A to C, which is denoted by RoS and defined as 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 18. Relation and Function Ex. Assume A= {1,2,3,4}, B ={a,b,c,d}, C ={x,y,z} and let R= {(1,a), (2,d), (3,a) (3,b), (3,d)} and S ={(b,x), (b,z), (c,y), (d,z)} . Show the relation a(RoS)c! 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 19. Relation and Function From the picture we can observe that there is an arrow from 2 to d which is followed by an arrow from d to z. We can view these two arrows as a “path” which “connects” the element 2 Î A to the element z Î C. Thus, 2(R o S)z since 2Rd and dSz Similarly there is a path from 3 to x and a path from 3 to z. Hence, 3(R o S)x and 3(R o S)z No other element of A is connected to an element of C. Therefore, the composition of relations R o S gives RoS= {(2,z), (3,x), (3,z)} 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 20. Relation and Function Soal : R = {(1, 2), (1, 6), (2, 4), (3, 4), (3, 6), (3, 8)} S = {(2, u), (4, s), (4, t), (6, t), (8, u)} Gambarkan grafiknya dan tentukan R o S 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 21. Relation and Function R o S = {(1, u), (1, t), (2, s), (2, t), (3, s), (3, t), (3, u) } 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 22. Relation and Function Exercises : 1 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1
  • 23. Relation and Function 2. 2014/2015 M. Ilyas Hadikusuma, M.Eng Matematika Terapan 1