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MH-CET 2014 Exam Pattern and Syllabus

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MH-CET 2014 Exam Pattern and Syllabus by ednexa.com

MH-CET 2014 Exam Pattern and Syllabus by ednexa.com

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  • 1. JEE / MHCET 2014 PHYSICS An Approach ……………………………by Dr. Arun Shridharan Pillai
  • 2. Sr. No. CLASS XI CLASS XII 1 Physical world and measurement Electrostatics 2 Kinematics Current Electricity 3 Laws of Motion Magnetic Effects of Current and Magnetism 4 Work, Energy and Power Electromagnetic Induction and Alternating Currents 5 Rotational Motion Electromagnetic Waves 6 Gravitation Optics 7 Properties of Bulk Matter Dual Nature of Matter and Radiation 8 Thermodynamics Atoms and Nuclei 9 Behavior of Perfect Gas and Kinetic Theory Electronic Devices 10 Oscillations and Waves Communication Systems TOPICS in Physics for JEE
  • 3. • No change in Pattern and marking scheme. • The format is the same with 90 questions in total and 30 questions each for Physics, Chemistry and Mathematics. • Each correct answer gets 4 marks • Each wrong answer gets -1 mark.
  • 4. Simple Questions with confusing replies
  • 5. 1. (x+5)/(x+5) = 1 (a) Always (b) Not Always (c) Only for Positive Numbers (d) Only for Negative Numbers
  • 6. Correct Answer is (b) Not Always?????Why Suppose x = - 5 We know that 0/0=absurd
  • 7. 2. Sin θ X Cot θ = Cos θ WE THINK Sin θ X Cos θ = Cos θ Sin θ Now is it valid for θ =0
  • 8. 1 Which of the following quantities have unit, but not the dimensions. (a) dielectric constant (b) coefficient of viscosity (c) plane angle (d) refractive index
  • 9. 2. A block of mass 10kg is resting on a horizontal surface. A force of 50N is applied on it. If coefficient of friction between the block and the surface is 0.6. what will be the force of friction? (g = 10 m/s2) (a) Zero (b) 50 N (c) 60 N (d) 40 N
  • 10. CORRECT OPTION IS (b) 50 N fs = mgμ fs = 10×10×0.6 fs = 60N But applied force is 50N. Hence, the block will not move.
  • 11. g Rcos R cos g  R cos 2 g   1 g 2 R cos  3. A hemispherical bowl of radius R is revolved around its vertical axis. A Light weight sphere in it also revolves in it, without sliping. The radius of the hemispherical passing through the sphere makes angle θ with the axis of rotation. The angular velocity of the sphere is: (a) (b) (c) (d)
  • 12. Solution: Motion of the sphere is like motion of conical pendulum. Hence R cos T 2 g 2 but T 2 R cos 2 g g R cos               
  • 13. 1.Charge q moves around charge Q in circular path. The work done by charge Q on q is (a) (b) (c) Zero (d) 2 0 1 Qq 4 k r  0 1 q 4 k r  2 0 1 Qq 2 r 4 k r    
  • 14. Solution: Charge q is moving over an equipotential surface Hence, work done is zero.
  • 15. 2. Time taken by radio waves to go come back from communication satellite is nearly (a) 1s (b) (c) (d) 4s 1 s 4 1 s 8
  • 16. Height of communication satellite above the surface of the earth is 36000 km. ∴ Distance travelled by radio waves = 72000 km Velocity of radio waves = 3 × 108 m/s        8 6 6 72000km time 3 10 m / s 72 10 1 time 300 10 4
  • 17. •Identify theoretical chapters •Identify numerical based chapters •Take Practice test
  • 18. • An other very important aspect of your JEE/NEET preparation will be the coaching institute –FACULTY –Delivery of Lecture –Concept Understanding and doubt solving session –Periodic Test –Evaluation of test –Infrastructure
  • 19. Full Portion Tests Time Table Time Allotment Mistakes Confidence
  • 20. • Suggested Books For IIT-JEE/ NEET –Physics by H.C. Verma –Problems in Physics by I.E. Irodov –Problems in Physics by Resnick and Halliday –ELECRICITY AND MAGNETISM by Resnick and Halliday –Circuits devices and systems by R.J. Smith
  • 21. Thank you ...! Prof. (Dr) Arun Shridharan Pillai Ph.D (Physics) , M.Sc (Physics), C-VLSI 9819110096 / profarun@gmail.com