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Current Electricity Notes for JEE Main 2015 - Part II

Current Electricity Notes for JEE Main 2015 - Part II by ednexa.com

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Current Electricity Notes for JEE Main 2015 - Part II

  1. 1. 9011041155 / 9011031155 1 Whetstone’s Network
  2. 2. 9011041155 / 9011031155 2 1 3 2 4 R R R R  Whetstone’s metrebridge x x B R l R R l   Errors  The wire may not be uniformly thick.  The contact resistance between the plates and wires at A and C. Minimization of Errors  Two sets of 3 readings are taken by interchanging positions of RX and R B, and average is calculated
  3. 3. 9011041155 / 9011031155 3  The resistance RB is adjusted such that the null point is obtained at the middle of AB. Resistance of Galvanometer Here, instead of null point equal deflection point is obtained The resistance of galvanometer is given by g B R l G R l  
  4. 4. 9011041155 / 9011031155 4 Multiple Choice Questions 1. Each of the resistance in the network shown in the figure is equal to R. The resistance between the terminals A and B is (a) 3R (b) R (c) 5R (d) 6R
  5. 5. 9011041155 / 9011031155 5 Ans : (b) R The equivalent circuit of the given network is a balanced wheatstone’s network as shown in the figure No current will flow through the branch LK ∴ Resistance in the branch ALB = 2R and resistance in the branch AKB = 2R. As they are in parallel, their effective resistance = R
  6. 6. 9011041155 / 9011031155 6 • Ask Your Doubts • For inquiry and registration, call 9011041155 / 9011031155.

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