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HOW can algebraic concepts be
applied to geometry?
Geometry
Course 3, Lesson 5-1
To
• classify the angles formed when two
lines are cut by a transversal,
• find missing angle measures when two
parallel lines are cut by a transversal
Course 3, Lesson 5-1
Geometry
Symbol
• perpendicular lines
• parallel lines
• transversal
• interior angles
• exterior angles
• alternate interior angles
• alternate exterior angles
• corresponding angles
• m1: the measure of  1
Course 3, Lesson 5-1
Geometry
Course 3, Lesson 5-1
Geometry
A line that intersects two or more lines is called a
, and eight angles are formed.transversal
Interior angles
Exterior angles
Alternate interior angles
Alternate exterior angles
Corresponding angles
lie inside the lines.
Examples: 3, 4, 5, 6  
lie outside the lines
Examples: 1, 2, 7, 8   
are interior angles that lie on opposite sides of the
transversal. When the lines are parallel, their measures are equal.
Examples: 4 6; m 3 5m m m     
are exterior angles that lie on opposite sides of
the transversal. When the lines are parallel, their measures are equal.
Examples: 1 7; 2 8m m m m     
are those angles that are in the same position on the two
lines in relation to the transversal. When the lines are parallel, their measures are
equal. Examples: 1 5; 2 6; 4 8; 3 7m m m m m m m m           
1
Need Another Example?
Step-by-Step Example
1. Classify the pair of angles in the figure
as alternate interior, alternate exterior,
or corresponding.
∠1 and ∠7
∠1 and ∠7 are exterior angles that lie on
opposite sides of the transversal. They
are alternate exterior angles.
Answer
Need Another Example?
Classify the pair of angles as alternate interior,
alternate exterior, or corresponding.
∠3 and ∠7
corresponding
1
Need Another Example?
Step-by-Step Example
2. Classify the pair of angles in the figure
as alternate interior, alternate exterior,
or corresponding.
∠2 and ∠6
∠2 and ∠6 are in the same position on the two
lines. They are corresponding angles.
Answer
Need Another Example?
Classify the pair of angles as alternate interior,
alternate exterior, or corresponding.
∠2 and ∠8
alternate interior
1
Need Another Example?
Step-by-Step Example
3. A furniture designer built the bookcase
shown. Line a is parallel to line b.
If m∠2 = 105°, find m∠6 and m∠3.
Justify your answer.
Since ∠2 and ∠6 are supplementary,
the sum of their measures is 180°.
m∠6 = 180° – 105° or 75°
2 Since ∠6 and ∠3 are interior angles
that lie on opposite sides of the
transversal, they are alternate interior
angles. The measures of alternate
interior angles are equal. m∠3 = 75°
Answer
Need Another Example?
Mr. Adams installed the gate
shown. Line c is parallel to line
d. If m∠4 = 40°, find m∠6 and
m∠7. Justify your answer.
m∠6 = 40° and m∠7 = 140°; Sample answer:
∠4 and ∠6 are alternate interior angles, so they
are congruent. ∠6 and ∠7 are supplementary.
Since m∠6 = 40°, m∠7 = 140°.
1
Need Another Example?
2
3
4
Step-by-Step Example
4. In the figure, line m is parallel to
line n, and line q is perpendicular
to line p. The measure of ∠1 is
40°. What is the measure of ∠7?
Since ∠1 and ∠6 are alternate
exterior angles, m∠6 = 40°.
40 + 90 + m∠7 = 180
Since ∠6, ∠7, and ∠8 form a straight line,
the sum of their measures is 180°.
So, m∠7 is 50°.
Answer
Need Another Example?
In the figure, line a is parallel to line b,
and line c is perpendicular to line d.
The measure of ∠7 is 125°. What is
the measure of ∠4?
35°
To prove a conjecture
• using a paragraph proof,
• using a two-column proof
Course 3, Lesson 5-2
Geometry
• inductive reasoning
• deductive reasoning
• proof
• paragraph proof
• informal proof
• two-column proof
• formal proof
• theorem
Course 3, Lesson 5-2
Geometry
Course 3, Lesson 5-2
Geometry
Step 1 List the given information, or what you know. If
possible, draw a diagram to illustrate this
information.
Step 2 State what is to be proven.
Step 3 Create a deductive argument by forming a
logical chain of statements linking the given
information to what you are trying to prove.
Step 4 Justify each statement with a reason.
Reasons include definitions, algebraic
properties, and theorems.
Step 5 State what it is you have proven
1
Need Another Example?
2
3
Step-by-Step Example
1. The diamondback
rattlesnake has a
diamond pattern on its
back. An enlargement
of the skin is shown.
If m∠1 = m∠4, write a
paragraph proof to show
that m∠2 = m∠3.
Given: m∠1 = m∠4
Proof:
Prove: m∠2 = m∠3
m∠1 = m∠2 because they are vertical angles. Since m∠1 = m∠4,
m∠2 = m∠4 by substitution. m∠4 = m∠3 because they are vertical
angles. Since m∠2 = m∠4, then m∠2 = m∠3 also by substitution.
Therefore, m∠2 = m∠3.
Answer
Need Another Example?
Refer to the diagram. If
m∠1 = m∠5, write a paragraph
proof to show that m∠1 = m∠11.
m∠1 = m∠9 because they are corresponding
angles. m∠9 = m∠11 because they are vertical
angles. Since m∠9 = m∠11, then m∠1 = m∠11
by substitution.
1
Need Another Example?
2
3
4
Step-by-Step Example
2. Write a two-column proof to show that if two
angles are vertical angles, then they have the
same measure.
Statements
lines m and n intersect;
∠1 and ∠3 are vertical angles.
Given: lines m and n intersect; ∠1 and ∠3 are vertical angles
Prove: m∠1 = m∠3
Reasons
a. Given
∠1 and ∠2 are a linear pair
and ∠3 and ∠2 are a linear pair.
b. Definition of linear pair
m∠1 + m∠2 = 180º
m∠3 + m∠2 = 180º
c. Definition of supplementary angles
m∠1 + m∠2 = m∠3 + m∠2d. Substitution
5 m∠1 = m∠3 Subtraction Property of Equalitye.
Answer
Need Another Example?
Write a two-column proof to show that if
PQ = QS and QS = ST, then PQ = ST.
Given: PQ = QS; QS = ST
Prove: PQ = ST
Statements
PQ = QS and QS = ST
Reasons
a. Given
PQ = STb. Substitution
To
• find missing angle measures in a triangle,
• find missing angle measures in a triangle
using the exterior angles
Course 3, Lesson 5-3
Geometry
• triangle
• interior angle
• exterior angle
• remote interior angles
Course 3, Lesson 5-3
Geometry
Course 3, Lesson 5-3
Geometry
Words The sum of the measures of the interior angles of a
triangle is 180˚
Model
Symbols x + y + z = 180˚
1
Need Another Example?
2
Step-by-Step Example
1. Find the value of x in the
Antigua and Barbuda flag.
x + 55 + 90 = 180
The value of x is 35.
x + 145 = 180
– 145 = – 145
x = 35
Write the equation.
Simplify.
Subtract.
Simplify.
Answer
Need Another Example?
The city park shown at the
right is in the shape of a
triangle. Find the value of x.
116
1
Need Another Example?
2
3
4
Step-by-Step Example
2. The measures of the angles of ABC are in the
ratio 1:4:5. What are the measures of the angles?
Let x represent the measure of angle A.
Since x = 18, 4x = 4(18) or 72, and 5x = 5(18) or 90.
The measures of the angles are 18°, 72°, and 90°.
x + 4x + 5x = 180
x = 18
Write the equation.
Then 4x and 5x represent angle B and angle C.
10x = 180 Collect like terms.
Division Property of Equality
Answer
Need Another Example?
The measures of the angles of triangle DEF
are in the ratio 1:2:3. What are the measures
of the angles?
30°, 60°, and 90°
Course 3, Lesson 5-3
Geometry
Words The measure of an exterior angle of a triangle is equal to
the sum of the measures of its two remote interior angles.
Model
Symbol 1m A m B    
1
Need Another Example?
2
3
4
5
Step-by-Step Example
3. Suppose m∠4 = 135°.
Find the measure of ∠2.
Angle 4 is an exterior angle.
Its two remote interior angles
are ∠2 and ∠LKM.
So, the m∠2 = 45°.
x + 90° = 135°
x = 45°
Write the equation.m∠2 + m∠LKM = m∠4
m∠2 = x°, m∠LKM = 90°, m∠4 = 135°
Subtraction Property of Equality
Answer
Need Another Example?
Find the value of x in
the triangle.
80
To
• find the measure of an interior
or exterior angle of a regular
polygon
Course3, Lesson 5-4.
Geometry
• polygon
• equiangular
• regular polygon
Course3, Lesson 5-4
Geometry
Course3, Lesson 5-4
Geometry
Words The sum of the measures of the interior angles of a
polygon is (n – 2)180, where n represents the number of
sides.
Symbols S = (n – 2)180
1
Need Another Example?
2
3
4
Step-by-Step Example
1. Find the sum of the measures of the interior
angles of a decagon.
The sum of the measures of the interior angles of a decagon
is 1,440°.
S = (8)180 or 1,440
Write the equation.S = (n – 2) 180
A decagon has 10 sides. Replace n with 10.
Simplify.
S = (10 – 2) 180
Answer
Need Another Example?
Find the sum of the measures of the interior
angles of a 13-gon.
1,980°
1
Need Another Example?
2
3
Step-by-Step Example
2. Each chamber of a bee honeycomb is a regular
hexagon. Find the measure of an interior angle
of a regular hexagon.
Find the sum of the measures of the angles.
Write an equation.S = (n – 2) 180
Simplify.
The sum of the measures of the interior angles is 720°.
Replace n with 6.S = (6 – 2) 180
S = (4)180 or 720
Divide 720 by 6, the number of interior angles, to find the
measure of one interior angle. So, the measure of one
interior angle of a regular hexagon is 720° ÷ 6 or 120°.
Answer
Need Another Example?
A designer is creating a new logo for a
bank. The logo consists of a regular
pentagon surrounded by isosceles
triangles. Find the measure of an
interior angle of a regular pentagon.
108°
Course3, Lesson 5-4
Geometry
Words In a polygon, the sum of the measures of the exterior
angles, one at each vertex, is 360˚
Model
Symbols 1 2 3 4 5 360m m m m m          
1
Need Another Example?
2
3
Step-by-Step Example
3. Find the measure of an exterior angle in a
regular hexagon.
Let x represent the measure of each exterior angle.
Write an equation. A hexagon has 6 exterior angles.6x = 360
Division Property of Equalityx = 60
So, each exterior angle of a regular hexagon measures 60°.4
Answer
Need Another Example?
Find the measure of an exterior angle in a
regular 30-gon.
12°
To
• find the missing side length of a right
triangle by using the Pythagorean
Theorem,
• determine whether a triangle is a right
triangle by using the converse of the
Pythagorean Theorem
Course 3, Lesson 5-5
Geometry
• legs
• hypotenuse
• Pythagorean Theorem
• converse
Course 3, Lesson 5-5
Geometry
Course 3, Lesson 5-5
Geometry
Words In a right triangle, the sum of the squares of the lengths of
the legs is equal to the square of the length of the
hypotenuse.
Model
Symbols 2 2 2
a b c 
1
Need Another Example?
2
3
4
5
6
Step-by-Step Example
1. Write an equation you could use to find the
length of the missing side of the right triangle.
Then find the missing length. Round to the
nearest tenth if necessary.
Check:
Pythagorean Theorema2 + b2 = c2
Replace a with 12 and b with 9.
144 + 81 = c2
The equation has two solutions, 15 and –15. However, the length of a side
must be positive. So, the hypotenuse is 15 inches long.
122 + 92 = c2
Evaluate 122 and 92.
225 = c2 Add 81 and 144.
Definition of square root
c = 15 or –15 Simplify.
a2 + b2 = c2
122 + 92 = 152
144 + 81 = 225
225 = 225
?
?
±√225 = c
Answer
Need Another Example?
Write an equation you could use to find the
length of the missing side of the right triangle
shown. Then find the missing length. Round to
the nearest tenth if necessary.
122 + 162 = c2; 20 in.
1
Need Another Example?
2
3
4
5
6
Step-by-Step Example
2. Write an equation you could use to find the length
of the missing side of the right triangle. Then find
the missing length. Round to the nearest tenth if
necessary.
Check for
Reasonableness
Pythagorean Theorema2 + b2 = c2
Replace a with 8 and c with 24.
64 + b2 = 576
The length of side b is about 22.6 meters.
82 + b2 = 242
Evaluate 82 and 242.
64 – 64 + b2 = 576 – 64 Subtract 64 from each side.
Definition of square root
b2 = 512 Simplify.
The hypotenuse is always the longest side in
a right triangle. Since 22.6 is less than 24,
the answer is reasonable.
7
b ≈ 22.6 or –22.6 Use a calculator.
b = ±√512
Answer
Need Another Example?
Write an equation you
could use to find the length
of the missing side of the right
triangle shown. Then find the missing length.
Round to the nearest tenth if necessary.
a2 + 282 = 332; 17.5 in.
Course 3, Lesson 5-5
Geometry
If the sides of a triangle have lengths a, b, and c units such that
, then the triangle is a right triangle.2 2 2
a b c 
1
Need Another Example?
2
3
4
5
Step-by-Step Example
3. The measures of three sides of a triangle are
5 inches, 12 inches, and 13 inches. Determine
whether the triangle is a right triangle.
Pythagorean Theorema2 + b2 = c2
a = 5, b = 12, c = 13
25 + 144 = 169
The triangle is a right triangle.
52 + 122 = 132
Evaluate 52, 122, and 132.
169 = 169 Simplify.
?
?
Answer
Need Another Example?
The measures of three sides of a
triangle are 24 inches, 7 inches, and
25 inches. Determine whether the
triangle is a right triangle.
yes; 72 + 242 = 252
To
• apply the Pythagorean Theorem to find
unknown side lengths in right triangles
in real-world situations,
• use the Pythagorean Theorem to find
missing measures in three-dimensional
figures
Course 3, Lesson 5-6
Geometry
1
Need Another Example?
2
3
4
5
6
Step-by-Step Example
1. Write an equation that can be used to find the
length of the ladder. Then solve. Round to the
nearest tenth.
Pythagorean Theorema2 + b2 = c2
Replace a with 8.75 and b with 18.
76.5625 + 324 = c2
Notice that the distance from the building, the
building itself, and the ladder form a right
triangle. Use the Pythagorean Theorem.
8.752 + 182 = c2
Evaluate 8.752 and 182.
400.5625 = c2 Add 76.5625 and 324.
Definition of square root
Use a calculator.±20.0 ≈ c
Since length cannot be negative, the ladder is about 20 feet long.
±√400.5625 = c
Answer
Need Another Example?
Write an equation that can be
used to find the length of the
boat ramp. Then solve. Round
to the nearest tenth.
4.22 + 252 = c2; 25.4 ft
1
Need Another Example?
2
3
4
5
Step-by-Step Example
2. Write an equation that can be used to find the
height of the plane. Then solve. Round to the
nearest tenth.
Pythagorean Theorema2 + b2 = c2
Replace a with 10 and c with 12.
100 + b2 = 144
The distance between the planes is the
hypotenuse of a right triangle. Use the
Pythagorean Theorem.
102 + b2 = 122
Evaluate 102 and 122.
b2 = 44 Subtraction Property of Equality
Since length cannot be negative, the height of the plane is about 6.6 miles.
Definition of square root
Use a calculator.b ≈ ±6.6
b = ±√44
Answer
Need Another Example?
Write an equation that can be
used to find the length of the
backboard. Then solve. Round to
the nearest tenth.
422 + x2 = 83.42; 72.1 in.
1
Need Another Example?
2
3
4
5
Step-by-Step Example
3. A 12-foot flagpole is placed in the center of a
square area. To stabilize the pole, a wire will
stretch from the top of the pole to each corner of
the square. The flagpole is 7 feet from each corner
of the square. What is the length of each wire?
Round to the nearest tenth.
Pythagorean TheoremAB2 + AC2 = BC2
Replace AB with 7 and AC with 12.
49 + 144 = BC2
Draw right triangle ABC. You want to find the length of
each wire or BC. This is the hypotenuse of a right
triangle, so use the Pythagorean Theorem.
72 + 122 = BC2
Evaluate 72 and 122.
193 = BC2 Simplify
Since length cannot be negative, the length of the wire is about 13.9 feet.
Definition of square root
Use a calculator.±13.9 ≈ BC
±√193 = BC
Answer
Need Another Example?
The slant height of a pyramid is the
height of each lateral face. What is
the slant height of the pyramid
shown? Round to the nearest tenth.
11.7 cm
To
• use the Pythagorean Theorem to find
the distance between two points on a
coordinate plane,
• use the Distance Formula to find the
distance between two points on a
coordinate plane
Course 3, Lesson 5-7
Geometry
• Distance Formula
Course 3, Lesson 5-7
Geometry
1
Need Another Example?
2
3
4
5
6
Step-by-Step Example
1. Graph the ordered pairs (3, 0) and (7, –5). Then
find the distance c between the two points.
Round to the nearest tenth.
Pythagorean Theorema2 + b2 = c2
Replace a with 4 and b with 5.42 + 52 = c2
Definition of square root
41 = c2 42 + 52 = 16 + 25 or 41
The points are about 6.4 units apart.
Use a calculator.±6.4 ≈ c
±√41 = √c2
Answer
Need Another Example?
Graph the ordered pairs (0, –6) and (5, –1).
Then find the distance between the points.
Round to the nearest tenth.
7.1 units
Course 3, Lesson 5-7
Geometry
Symbols The distance d between two points with coordinates
and is given by the formula
Model
1 1
( , y )x 2 2
( , y )x
2 2
2 1 2 1
( ) ( ) .d x x y y   
1
Need Another Example?
2 3
4
5 6
Step-by-Step Example
2. On the map, each unit represents 45 miles. West Point,
New York, is located at (1.5, 2) and Annapolis, Maryland,
is located at (–1.5, –1.5). What is the approximate
distance between West Point and Annapolis?
a2 + b2 = c2
32 + 3.52 = c2
21.25 = c2
Let c represent the distance between West Point
and Annapolis. Then a = 3 and b = 3.5.
±4.6 ≈ c
7
Use the Pythagorean Theorem
Let (x1, y1) = (1.5, 2) and (x2, y2) = (–1.5, –1.5).
Use the Distance Formula
c ≈ ±4.6
Since each map unit equals 45 miles, the distance
between the cities is 4.6 · 45 or about 207 miles.
±√21.25 = √c2
c = √(x2 – x1)2 + (y2 – y1)2
c = √(–1.5 – 1.5)2 + (–1.5 – 2)2
c = √(–3)2 + (–3.5)2
c = √9 + 12.25
c = √21.25
Answer
Need Another Example?
Reed lives in Seattle,
Washington. One unit on this
map is 0.08 mile. Find the
approximate distance he
drives between Broad Street
at Denny Way (–1, 0) and
Broad Street at Dexter Ave N.
(4, 5).
0.57 mi
1
Need Another Example?
2
3
4
5
Step-by-Step Example
3. Use the Distance Formula to find the distance
between X(5, –4) and Y(–3, –2). Round to the
nearest tenth if necessary.
XY ≈ ±8.2
So, the distance between points X and Y is about 8.2 units.
Distance Formula
(x1, y1) = (5, –4),
(x2, y2) = (–3, –2)
Simplify.
Evaluate (–8)2 and 22.
Add 64 and 4.
Simplify.
XY = √(–3 – 5)2 + [–2 – (–4)]2
XY = √(–8)2 + 22
XY = √64 + 4
XY = √68
d = √(x2 – x1)2 + (y2 – y1)2
Answer
Need Another Example?
Use the Distance Formula to find the distance
between G(–3, –2) and H(–6, 5). Round to
the nearest tenth.
7.6 units

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Chapter 5

  • 1. HOW can algebraic concepts be applied to geometry? Geometry Course 3, Lesson 5-1
  • 2. To • classify the angles formed when two lines are cut by a transversal, • find missing angle measures when two parallel lines are cut by a transversal Course 3, Lesson 5-1 Geometry
  • 3. Symbol • perpendicular lines • parallel lines • transversal • interior angles • exterior angles • alternate interior angles • alternate exterior angles • corresponding angles • m1: the measure of  1 Course 3, Lesson 5-1 Geometry
  • 4. Course 3, Lesson 5-1 Geometry A line that intersects two or more lines is called a , and eight angles are formed.transversal Interior angles Exterior angles Alternate interior angles Alternate exterior angles Corresponding angles lie inside the lines. Examples: 3, 4, 5, 6   lie outside the lines Examples: 1, 2, 7, 8    are interior angles that lie on opposite sides of the transversal. When the lines are parallel, their measures are equal. Examples: 4 6; m 3 5m m m      are exterior angles that lie on opposite sides of the transversal. When the lines are parallel, their measures are equal. Examples: 1 7; 2 8m m m m      are those angles that are in the same position on the two lines in relation to the transversal. When the lines are parallel, their measures are equal. Examples: 1 5; 2 6; 4 8; 3 7m m m m m m m m           
  • 5. 1 Need Another Example? Step-by-Step Example 1. Classify the pair of angles in the figure as alternate interior, alternate exterior, or corresponding. ∠1 and ∠7 ∠1 and ∠7 are exterior angles that lie on opposite sides of the transversal. They are alternate exterior angles.
  • 6. Answer Need Another Example? Classify the pair of angles as alternate interior, alternate exterior, or corresponding. ∠3 and ∠7 corresponding
  • 7. 1 Need Another Example? Step-by-Step Example 2. Classify the pair of angles in the figure as alternate interior, alternate exterior, or corresponding. ∠2 and ∠6 ∠2 and ∠6 are in the same position on the two lines. They are corresponding angles.
  • 8. Answer Need Another Example? Classify the pair of angles as alternate interior, alternate exterior, or corresponding. ∠2 and ∠8 alternate interior
  • 9. 1 Need Another Example? Step-by-Step Example 3. A furniture designer built the bookcase shown. Line a is parallel to line b. If m∠2 = 105°, find m∠6 and m∠3. Justify your answer. Since ∠2 and ∠6 are supplementary, the sum of their measures is 180°. m∠6 = 180° – 105° or 75° 2 Since ∠6 and ∠3 are interior angles that lie on opposite sides of the transversal, they are alternate interior angles. The measures of alternate interior angles are equal. m∠3 = 75°
  • 10. Answer Need Another Example? Mr. Adams installed the gate shown. Line c is parallel to line d. If m∠4 = 40°, find m∠6 and m∠7. Justify your answer. m∠6 = 40° and m∠7 = 140°; Sample answer: ∠4 and ∠6 are alternate interior angles, so they are congruent. ∠6 and ∠7 are supplementary. Since m∠6 = 40°, m∠7 = 140°.
  • 11. 1 Need Another Example? 2 3 4 Step-by-Step Example 4. In the figure, line m is parallel to line n, and line q is perpendicular to line p. The measure of ∠1 is 40°. What is the measure of ∠7? Since ∠1 and ∠6 are alternate exterior angles, m∠6 = 40°. 40 + 90 + m∠7 = 180 Since ∠6, ∠7, and ∠8 form a straight line, the sum of their measures is 180°. So, m∠7 is 50°.
  • 12. Answer Need Another Example? In the figure, line a is parallel to line b, and line c is perpendicular to line d. The measure of ∠7 is 125°. What is the measure of ∠4? 35°
  • 13. To prove a conjecture • using a paragraph proof, • using a two-column proof Course 3, Lesson 5-2 Geometry
  • 14. • inductive reasoning • deductive reasoning • proof • paragraph proof • informal proof • two-column proof • formal proof • theorem Course 3, Lesson 5-2 Geometry
  • 15. Course 3, Lesson 5-2 Geometry Step 1 List the given information, or what you know. If possible, draw a diagram to illustrate this information. Step 2 State what is to be proven. Step 3 Create a deductive argument by forming a logical chain of statements linking the given information to what you are trying to prove. Step 4 Justify each statement with a reason. Reasons include definitions, algebraic properties, and theorems. Step 5 State what it is you have proven
  • 16. 1 Need Another Example? 2 3 Step-by-Step Example 1. The diamondback rattlesnake has a diamond pattern on its back. An enlargement of the skin is shown. If m∠1 = m∠4, write a paragraph proof to show that m∠2 = m∠3. Given: m∠1 = m∠4 Proof: Prove: m∠2 = m∠3 m∠1 = m∠2 because they are vertical angles. Since m∠1 = m∠4, m∠2 = m∠4 by substitution. m∠4 = m∠3 because they are vertical angles. Since m∠2 = m∠4, then m∠2 = m∠3 also by substitution. Therefore, m∠2 = m∠3.
  • 17. Answer Need Another Example? Refer to the diagram. If m∠1 = m∠5, write a paragraph proof to show that m∠1 = m∠11. m∠1 = m∠9 because they are corresponding angles. m∠9 = m∠11 because they are vertical angles. Since m∠9 = m∠11, then m∠1 = m∠11 by substitution.
  • 18. 1 Need Another Example? 2 3 4 Step-by-Step Example 2. Write a two-column proof to show that if two angles are vertical angles, then they have the same measure. Statements lines m and n intersect; ∠1 and ∠3 are vertical angles. Given: lines m and n intersect; ∠1 and ∠3 are vertical angles Prove: m∠1 = m∠3 Reasons a. Given ∠1 and ∠2 are a linear pair and ∠3 and ∠2 are a linear pair. b. Definition of linear pair m∠1 + m∠2 = 180º m∠3 + m∠2 = 180º c. Definition of supplementary angles m∠1 + m∠2 = m∠3 + m∠2d. Substitution 5 m∠1 = m∠3 Subtraction Property of Equalitye.
  • 19. Answer Need Another Example? Write a two-column proof to show that if PQ = QS and QS = ST, then PQ = ST. Given: PQ = QS; QS = ST Prove: PQ = ST Statements PQ = QS and QS = ST Reasons a. Given PQ = STb. Substitution
  • 20. To • find missing angle measures in a triangle, • find missing angle measures in a triangle using the exterior angles Course 3, Lesson 5-3 Geometry
  • 21. • triangle • interior angle • exterior angle • remote interior angles Course 3, Lesson 5-3 Geometry
  • 22. Course 3, Lesson 5-3 Geometry Words The sum of the measures of the interior angles of a triangle is 180˚ Model Symbols x + y + z = 180˚
  • 23. 1 Need Another Example? 2 Step-by-Step Example 1. Find the value of x in the Antigua and Barbuda flag. x + 55 + 90 = 180 The value of x is 35. x + 145 = 180 – 145 = – 145 x = 35 Write the equation. Simplify. Subtract. Simplify.
  • 24. Answer Need Another Example? The city park shown at the right is in the shape of a triangle. Find the value of x. 116
  • 25. 1 Need Another Example? 2 3 4 Step-by-Step Example 2. The measures of the angles of ABC are in the ratio 1:4:5. What are the measures of the angles? Let x represent the measure of angle A. Since x = 18, 4x = 4(18) or 72, and 5x = 5(18) or 90. The measures of the angles are 18°, 72°, and 90°. x + 4x + 5x = 180 x = 18 Write the equation. Then 4x and 5x represent angle B and angle C. 10x = 180 Collect like terms. Division Property of Equality
  • 26. Answer Need Another Example? The measures of the angles of triangle DEF are in the ratio 1:2:3. What are the measures of the angles? 30°, 60°, and 90°
  • 27. Course 3, Lesson 5-3 Geometry Words The measure of an exterior angle of a triangle is equal to the sum of the measures of its two remote interior angles. Model Symbol 1m A m B    
  • 28. 1 Need Another Example? 2 3 4 5 Step-by-Step Example 3. Suppose m∠4 = 135°. Find the measure of ∠2. Angle 4 is an exterior angle. Its two remote interior angles are ∠2 and ∠LKM. So, the m∠2 = 45°. x + 90° = 135° x = 45° Write the equation.m∠2 + m∠LKM = m∠4 m∠2 = x°, m∠LKM = 90°, m∠4 = 135° Subtraction Property of Equality
  • 29. Answer Need Another Example? Find the value of x in the triangle. 80
  • 30. To • find the measure of an interior or exterior angle of a regular polygon Course3, Lesson 5-4. Geometry
  • 31. • polygon • equiangular • regular polygon Course3, Lesson 5-4 Geometry
  • 32. Course3, Lesson 5-4 Geometry Words The sum of the measures of the interior angles of a polygon is (n – 2)180, where n represents the number of sides. Symbols S = (n – 2)180
  • 33. 1 Need Another Example? 2 3 4 Step-by-Step Example 1. Find the sum of the measures of the interior angles of a decagon. The sum of the measures of the interior angles of a decagon is 1,440°. S = (8)180 or 1,440 Write the equation.S = (n – 2) 180 A decagon has 10 sides. Replace n with 10. Simplify. S = (10 – 2) 180
  • 34. Answer Need Another Example? Find the sum of the measures of the interior angles of a 13-gon. 1,980°
  • 35. 1 Need Another Example? 2 3 Step-by-Step Example 2. Each chamber of a bee honeycomb is a regular hexagon. Find the measure of an interior angle of a regular hexagon. Find the sum of the measures of the angles. Write an equation.S = (n – 2) 180 Simplify. The sum of the measures of the interior angles is 720°. Replace n with 6.S = (6 – 2) 180 S = (4)180 or 720 Divide 720 by 6, the number of interior angles, to find the measure of one interior angle. So, the measure of one interior angle of a regular hexagon is 720° ÷ 6 or 120°.
  • 36. Answer Need Another Example? A designer is creating a new logo for a bank. The logo consists of a regular pentagon surrounded by isosceles triangles. Find the measure of an interior angle of a regular pentagon. 108°
  • 37. Course3, Lesson 5-4 Geometry Words In a polygon, the sum of the measures of the exterior angles, one at each vertex, is 360˚ Model Symbols 1 2 3 4 5 360m m m m m          
  • 38. 1 Need Another Example? 2 3 Step-by-Step Example 3. Find the measure of an exterior angle in a regular hexagon. Let x represent the measure of each exterior angle. Write an equation. A hexagon has 6 exterior angles.6x = 360 Division Property of Equalityx = 60 So, each exterior angle of a regular hexagon measures 60°.4
  • 39. Answer Need Another Example? Find the measure of an exterior angle in a regular 30-gon. 12°
  • 40. To • find the missing side length of a right triangle by using the Pythagorean Theorem, • determine whether a triangle is a right triangle by using the converse of the Pythagorean Theorem Course 3, Lesson 5-5 Geometry
  • 41. • legs • hypotenuse • Pythagorean Theorem • converse Course 3, Lesson 5-5 Geometry
  • 42. Course 3, Lesson 5-5 Geometry Words In a right triangle, the sum of the squares of the lengths of the legs is equal to the square of the length of the hypotenuse. Model Symbols 2 2 2 a b c 
  • 43. 1 Need Another Example? 2 3 4 5 6 Step-by-Step Example 1. Write an equation you could use to find the length of the missing side of the right triangle. Then find the missing length. Round to the nearest tenth if necessary. Check: Pythagorean Theorema2 + b2 = c2 Replace a with 12 and b with 9. 144 + 81 = c2 The equation has two solutions, 15 and –15. However, the length of a side must be positive. So, the hypotenuse is 15 inches long. 122 + 92 = c2 Evaluate 122 and 92. 225 = c2 Add 81 and 144. Definition of square root c = 15 or –15 Simplify. a2 + b2 = c2 122 + 92 = 152 144 + 81 = 225 225 = 225 ? ? ±√225 = c
  • 44. Answer Need Another Example? Write an equation you could use to find the length of the missing side of the right triangle shown. Then find the missing length. Round to the nearest tenth if necessary. 122 + 162 = c2; 20 in.
  • 45. 1 Need Another Example? 2 3 4 5 6 Step-by-Step Example 2. Write an equation you could use to find the length of the missing side of the right triangle. Then find the missing length. Round to the nearest tenth if necessary. Check for Reasonableness Pythagorean Theorema2 + b2 = c2 Replace a with 8 and c with 24. 64 + b2 = 576 The length of side b is about 22.6 meters. 82 + b2 = 242 Evaluate 82 and 242. 64 – 64 + b2 = 576 – 64 Subtract 64 from each side. Definition of square root b2 = 512 Simplify. The hypotenuse is always the longest side in a right triangle. Since 22.6 is less than 24, the answer is reasonable. 7 b ≈ 22.6 or –22.6 Use a calculator. b = ±√512
  • 46. Answer Need Another Example? Write an equation you could use to find the length of the missing side of the right triangle shown. Then find the missing length. Round to the nearest tenth if necessary. a2 + 282 = 332; 17.5 in.
  • 47. Course 3, Lesson 5-5 Geometry If the sides of a triangle have lengths a, b, and c units such that , then the triangle is a right triangle.2 2 2 a b c 
  • 48. 1 Need Another Example? 2 3 4 5 Step-by-Step Example 3. The measures of three sides of a triangle are 5 inches, 12 inches, and 13 inches. Determine whether the triangle is a right triangle. Pythagorean Theorema2 + b2 = c2 a = 5, b = 12, c = 13 25 + 144 = 169 The triangle is a right triangle. 52 + 122 = 132 Evaluate 52, 122, and 132. 169 = 169 Simplify. ? ?
  • 49. Answer Need Another Example? The measures of three sides of a triangle are 24 inches, 7 inches, and 25 inches. Determine whether the triangle is a right triangle. yes; 72 + 242 = 252
  • 50. To • apply the Pythagorean Theorem to find unknown side lengths in right triangles in real-world situations, • use the Pythagorean Theorem to find missing measures in three-dimensional figures Course 3, Lesson 5-6 Geometry
  • 51. 1 Need Another Example? 2 3 4 5 6 Step-by-Step Example 1. Write an equation that can be used to find the length of the ladder. Then solve. Round to the nearest tenth. Pythagorean Theorema2 + b2 = c2 Replace a with 8.75 and b with 18. 76.5625 + 324 = c2 Notice that the distance from the building, the building itself, and the ladder form a right triangle. Use the Pythagorean Theorem. 8.752 + 182 = c2 Evaluate 8.752 and 182. 400.5625 = c2 Add 76.5625 and 324. Definition of square root Use a calculator.±20.0 ≈ c Since length cannot be negative, the ladder is about 20 feet long. ±√400.5625 = c
  • 52. Answer Need Another Example? Write an equation that can be used to find the length of the boat ramp. Then solve. Round to the nearest tenth. 4.22 + 252 = c2; 25.4 ft
  • 53. 1 Need Another Example? 2 3 4 5 Step-by-Step Example 2. Write an equation that can be used to find the height of the plane. Then solve. Round to the nearest tenth. Pythagorean Theorema2 + b2 = c2 Replace a with 10 and c with 12. 100 + b2 = 144 The distance between the planes is the hypotenuse of a right triangle. Use the Pythagorean Theorem. 102 + b2 = 122 Evaluate 102 and 122. b2 = 44 Subtraction Property of Equality Since length cannot be negative, the height of the plane is about 6.6 miles. Definition of square root Use a calculator.b ≈ ±6.6 b = ±√44
  • 54. Answer Need Another Example? Write an equation that can be used to find the length of the backboard. Then solve. Round to the nearest tenth. 422 + x2 = 83.42; 72.1 in.
  • 55. 1 Need Another Example? 2 3 4 5 Step-by-Step Example 3. A 12-foot flagpole is placed in the center of a square area. To stabilize the pole, a wire will stretch from the top of the pole to each corner of the square. The flagpole is 7 feet from each corner of the square. What is the length of each wire? Round to the nearest tenth. Pythagorean TheoremAB2 + AC2 = BC2 Replace AB with 7 and AC with 12. 49 + 144 = BC2 Draw right triangle ABC. You want to find the length of each wire or BC. This is the hypotenuse of a right triangle, so use the Pythagorean Theorem. 72 + 122 = BC2 Evaluate 72 and 122. 193 = BC2 Simplify Since length cannot be negative, the length of the wire is about 13.9 feet. Definition of square root Use a calculator.±13.9 ≈ BC ±√193 = BC
  • 56. Answer Need Another Example? The slant height of a pyramid is the height of each lateral face. What is the slant height of the pyramid shown? Round to the nearest tenth. 11.7 cm
  • 57. To • use the Pythagorean Theorem to find the distance between two points on a coordinate plane, • use the Distance Formula to find the distance between two points on a coordinate plane Course 3, Lesson 5-7 Geometry
  • 58. • Distance Formula Course 3, Lesson 5-7 Geometry
  • 59. 1 Need Another Example? 2 3 4 5 6 Step-by-Step Example 1. Graph the ordered pairs (3, 0) and (7, –5). Then find the distance c between the two points. Round to the nearest tenth. Pythagorean Theorema2 + b2 = c2 Replace a with 4 and b with 5.42 + 52 = c2 Definition of square root 41 = c2 42 + 52 = 16 + 25 or 41 The points are about 6.4 units apart. Use a calculator.±6.4 ≈ c ±√41 = √c2
  • 60. Answer Need Another Example? Graph the ordered pairs (0, –6) and (5, –1). Then find the distance between the points. Round to the nearest tenth. 7.1 units
  • 61. Course 3, Lesson 5-7 Geometry Symbols The distance d between two points with coordinates and is given by the formula Model 1 1 ( , y )x 2 2 ( , y )x 2 2 2 1 2 1 ( ) ( ) .d x x y y   
  • 62. 1 Need Another Example? 2 3 4 5 6 Step-by-Step Example 2. On the map, each unit represents 45 miles. West Point, New York, is located at (1.5, 2) and Annapolis, Maryland, is located at (–1.5, –1.5). What is the approximate distance between West Point and Annapolis? a2 + b2 = c2 32 + 3.52 = c2 21.25 = c2 Let c represent the distance between West Point and Annapolis. Then a = 3 and b = 3.5. ±4.6 ≈ c 7 Use the Pythagorean Theorem Let (x1, y1) = (1.5, 2) and (x2, y2) = (–1.5, –1.5). Use the Distance Formula c ≈ ±4.6 Since each map unit equals 45 miles, the distance between the cities is 4.6 · 45 or about 207 miles. ±√21.25 = √c2 c = √(x2 – x1)2 + (y2 – y1)2 c = √(–1.5 – 1.5)2 + (–1.5 – 2)2 c = √(–3)2 + (–3.5)2 c = √9 + 12.25 c = √21.25
  • 63. Answer Need Another Example? Reed lives in Seattle, Washington. One unit on this map is 0.08 mile. Find the approximate distance he drives between Broad Street at Denny Way (–1, 0) and Broad Street at Dexter Ave N. (4, 5). 0.57 mi
  • 64. 1 Need Another Example? 2 3 4 5 Step-by-Step Example 3. Use the Distance Formula to find the distance between X(5, –4) and Y(–3, –2). Round to the nearest tenth if necessary. XY ≈ ±8.2 So, the distance between points X and Y is about 8.2 units. Distance Formula (x1, y1) = (5, –4), (x2, y2) = (–3, –2) Simplify. Evaluate (–8)2 and 22. Add 64 and 4. Simplify. XY = √(–3 – 5)2 + [–2 – (–4)]2 XY = √(–8)2 + 22 XY = √64 + 4 XY = √68 d = √(x2 – x1)2 + (y2 – y1)2
  • 65. Answer Need Another Example? Use the Distance Formula to find the distance between G(–3, –2) and H(–6, 5). Round to the nearest tenth. 7.6 units