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7 UNIT 7..44 SSIIMMIILLAARRIITTYY IINN RRIIGGHHTT 
Holt Geometry 
TTRRIIAANNGGLLEESS
Warm Up 
1. Write a similarity statement 
comparing the two triangles. 
ΔADB ~ ΔEDC 
Simplify. 
2. 3. 
Solve each equation. 
4. 5. 2x2 = 50 
±5
Objectives 
Use geometric mean to find segment 
lengths in right triangles. 
Apply similarity relationships in right 
triangles to solve problems.
Vocabulary 
geometric mean
In a right triangle, an altitude drawn from the 
vertex of the right angle to the hypotenuse forms 
two right triangles.
7.3
Example 1: Identifying Similar Right Triangles 
Write a similarity 
statement comparing the 
three triangles. 
Sketch the three right triangles with the 
angles of the triangles in corresponding 
positions. 
W 
Z 
By Theorem 8-1-1, ΔUVW ~ ΔUWZ ~ ΔWVZ.
Check It Out! Example 1 
Write a similarity statement 
comparing the three triangles. 
Sketch the three right triangles with 
the angles of the triangles in 
corresponding positions. 
By Theorem 8-1-1, ΔLJK ~ ΔJMK ~ ΔLMJ.
Consider the proportion . In this case, the 
means of the proportion are the same number, and 
that number is the geometric mean of the extremes. 
The geometric mean of two positive numbers is the 
positive square root of their product. So the geometric 
mean of a and b is the positive number x such 
that , or x2 = ab.
Example 2A: Finding Geometric Means 
Find the geometric mean of each pair of 
numbers. If necessary, give the answer in 
simplest radical form. 
4 and 25 
Let x be the geometric mean. 
x2 = (4)(25) = 100 Def. of geometric mean 
x = 10 Find the positive square root.
Example 2B: Finding Geometric Means 
Find the geometric mean of each pair of 
numbers. If necessary, give the answer in 
simplest radical form. 
5 and 30 
Let x be the geometric mean. 
x2 = (5)(30) = 150 Def. of geometric mean 
Find the positive square root.
Check It Out! Example 2a 
Find the geometric mean of each pair of 
numbers. If necessary, give the answer in 
simplest radical form. 
2 and 8 
Let x be the geometric mean. 
x2 = (2)(8) = 16 Def. of geometric mean 
x = 4 Find the positive square root.
Check It Out! Example 2b 
Find the geometric mean of each pair of 
numbers. If necessary, give the answer in 
simplest radical form. 
10 and 30 
Let x be the geometric mean. 
x2 = (10)(30) = 300 Def. of geometric mean 
Find the positive square root.
Check It Out! Example 2c 
Find the geometric mean of each pair of 
numbers. If necessary, give the answer in 
simplest radical form. 
8 and 9 
Let x be the geometric mean. 
x2 = (8)(9) = 72 Def. of geometric mean 
Find the positive square root.
You can use Theorem 8-1-1 to write proportions 
comparing the side lengths of the triangles formed 
by the altitude to the hypotenuse of a right triangle. 
All the relationships in red involve geometric means.
7.3.1 
7.3.2
Example 3: Finding Side Lengths in Right Triangles 
Find x, y, and z. 
62 = (9)(x) 6 is the geometric mean of 
9 and x. 
x = 4 Divide both sides by 9. 
y2 = (4)(13) = 52 y is the geometric mean of 
4 and 13. 
Find the positive square root. 
z2 = (9)(13) = 117 z is the geometric mean of 
9 and 13. 
Find the positive square root.
Helpful Hint 
Once you’ve found the unknown side lengths, 
you can use the Pythagorean Theorem to check 
your answers.
Check It Out! Example 3 
Find u, v, and w. 
92 = (3)(u) 9 is the geometric mean of 
u and 3. 
u = 27 Divide both sides by 3. 
w2 = (27 + 3)(27) w is the geometric mean of 
u + 3 and 27. 
Find the positive square root. 
v2 = (27 + 3)(3) v is the geometric mean 
of 
Find the positivue + s 3q uaanrde 3ro. ot.
Example 4: Measurement Application 
To estimate the height of a 
Douglas fir, Jan positions 
herself so that her lines of 
sight to the top and bottom 
of the tree form a 90º 
angle. Her eyes are about 
1.6 m above the ground, 
and she is standing 7.8 m 
from the tree. What is the 
height of the tree to the 
nearest meter?
Example 4 Continued 
Let x be the height of the tree above eye level. 
(7.8)2 = 1.6x 
x = 38.025 ≈ 38 
7.8 is the geometric mean of 
1.6 and x. 
Solve for x and round. 
The tree is about 38 + 1.6 = 39.6, or 40 m tall.
Check It Out! Example 4 
A surveyor positions himself 
so that his line of sight to 
the top of a cliff and his line 
of sight to the bottom form 
a right angle as shown. 
What is the height of the 
cliff to the nearest foot?
Check It Out! Example 4 Continued 
Let x be the height of cliff above eye level. 
(28)2 = 5.5x 28 is the geometric mean of 
5.5 and x. 
Divide x » 142.5 both sides by 5.5. 
The cliff is about 142.5 + 5.5, or 
148 ft high.
Lesson Quiz: Part I 
Find the geometric mean of each pair of 
numbers. If necessary, give the answer in 
simplest radical form. 
1. 8 and 18 
12 
2. 6 and 15
Lesson Quiz: Part II 
For Items 3–6, use ΔRST. 
3. Write a similarity statement comparing the 
three triangles. 
ΔRST ~ ΔRPS ~ ΔSPT 
4 
4. If PS = 6 and PT = 9, find PR. 
5. If TP = 24 and PR = 6, find RS. 
6. Complete the equation (ST)2 = (TP + PR)(?). 
TP
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Copyright Act 1976, 
allowance is made for "fair 
use" for purposes such as 
criticism, comment, news 
reporting, TEACHING, 
scholarship, and research. 
Fair use is a use permitted 
by copyright statute that 
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infringing. 
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Geometry unit 7.4

  • 1. 7 UNIT 7..44 SSIIMMIILLAARRIITTYY IINN RRIIGGHHTT Holt Geometry TTRRIIAANNGGLLEESS
  • 2. Warm Up 1. Write a similarity statement comparing the two triangles. ΔADB ~ ΔEDC Simplify. 2. 3. Solve each equation. 4. 5. 2x2 = 50 ±5
  • 3. Objectives Use geometric mean to find segment lengths in right triangles. Apply similarity relationships in right triangles to solve problems.
  • 5. In a right triangle, an altitude drawn from the vertex of the right angle to the hypotenuse forms two right triangles.
  • 6. 7.3
  • 7. Example 1: Identifying Similar Right Triangles Write a similarity statement comparing the three triangles. Sketch the three right triangles with the angles of the triangles in corresponding positions. W Z By Theorem 8-1-1, ΔUVW ~ ΔUWZ ~ ΔWVZ.
  • 8. Check It Out! Example 1 Write a similarity statement comparing the three triangles. Sketch the three right triangles with the angles of the triangles in corresponding positions. By Theorem 8-1-1, ΔLJK ~ ΔJMK ~ ΔLMJ.
  • 9. Consider the proportion . In this case, the means of the proportion are the same number, and that number is the geometric mean of the extremes. The geometric mean of two positive numbers is the positive square root of their product. So the geometric mean of a and b is the positive number x such that , or x2 = ab.
  • 10. Example 2A: Finding Geometric Means Find the geometric mean of each pair of numbers. If necessary, give the answer in simplest radical form. 4 and 25 Let x be the geometric mean. x2 = (4)(25) = 100 Def. of geometric mean x = 10 Find the positive square root.
  • 11. Example 2B: Finding Geometric Means Find the geometric mean of each pair of numbers. If necessary, give the answer in simplest radical form. 5 and 30 Let x be the geometric mean. x2 = (5)(30) = 150 Def. of geometric mean Find the positive square root.
  • 12. Check It Out! Example 2a Find the geometric mean of each pair of numbers. If necessary, give the answer in simplest radical form. 2 and 8 Let x be the geometric mean. x2 = (2)(8) = 16 Def. of geometric mean x = 4 Find the positive square root.
  • 13. Check It Out! Example 2b Find the geometric mean of each pair of numbers. If necessary, give the answer in simplest radical form. 10 and 30 Let x be the geometric mean. x2 = (10)(30) = 300 Def. of geometric mean Find the positive square root.
  • 14. Check It Out! Example 2c Find the geometric mean of each pair of numbers. If necessary, give the answer in simplest radical form. 8 and 9 Let x be the geometric mean. x2 = (8)(9) = 72 Def. of geometric mean Find the positive square root.
  • 15. You can use Theorem 8-1-1 to write proportions comparing the side lengths of the triangles formed by the altitude to the hypotenuse of a right triangle. All the relationships in red involve geometric means.
  • 17. Example 3: Finding Side Lengths in Right Triangles Find x, y, and z. 62 = (9)(x) 6 is the geometric mean of 9 and x. x = 4 Divide both sides by 9. y2 = (4)(13) = 52 y is the geometric mean of 4 and 13. Find the positive square root. z2 = (9)(13) = 117 z is the geometric mean of 9 and 13. Find the positive square root.
  • 18. Helpful Hint Once you’ve found the unknown side lengths, you can use the Pythagorean Theorem to check your answers.
  • 19. Check It Out! Example 3 Find u, v, and w. 92 = (3)(u) 9 is the geometric mean of u and 3. u = 27 Divide both sides by 3. w2 = (27 + 3)(27) w is the geometric mean of u + 3 and 27. Find the positive square root. v2 = (27 + 3)(3) v is the geometric mean of Find the positivue + s 3q uaanrde 3ro. ot.
  • 20. Example 4: Measurement Application To estimate the height of a Douglas fir, Jan positions herself so that her lines of sight to the top and bottom of the tree form a 90º angle. Her eyes are about 1.6 m above the ground, and she is standing 7.8 m from the tree. What is the height of the tree to the nearest meter?
  • 21. Example 4 Continued Let x be the height of the tree above eye level. (7.8)2 = 1.6x x = 38.025 ≈ 38 7.8 is the geometric mean of 1.6 and x. Solve for x and round. The tree is about 38 + 1.6 = 39.6, or 40 m tall.
  • 22. Check It Out! Example 4 A surveyor positions himself so that his line of sight to the top of a cliff and his line of sight to the bottom form a right angle as shown. What is the height of the cliff to the nearest foot?
  • 23. Check It Out! Example 4 Continued Let x be the height of cliff above eye level. (28)2 = 5.5x 28 is the geometric mean of 5.5 and x. Divide x » 142.5 both sides by 5.5. The cliff is about 142.5 + 5.5, or 148 ft high.
  • 24. Lesson Quiz: Part I Find the geometric mean of each pair of numbers. If necessary, give the answer in simplest radical form. 1. 8 and 18 12 2. 6 and 15
  • 25. Lesson Quiz: Part II For Items 3–6, use ΔRST. 3. Write a similarity statement comparing the three triangles. ΔRST ~ ΔRPS ~ ΔSPT 4 4. If PS = 6 and PT = 9, find PR. 5. If TP = 24 and PR = 6, find RS. 6. Complete the equation (ST)2 = (TP + PR)(?). TP
  • 26. All rights belong to their respective owners. Copyright Disclaimer Under Section 107 of the Copyright Act 1976, allowance is made for "fair use" for purposes such as criticism, comment, news reporting, TEACHING, scholarship, and research. Fair use is a use permitted by copyright statute that might otherwise be infringing. Non-profit, EDUCATIONAL or personal use tips the balance in favor of fair use.