According to Gay-Lussacs law what happens to the pressure of a gas if the temperature changes from 40.0 degree Celsius to 85.0 degrees Celsius a)pressure decreases b)pressure increases c)pressure stays the same since temperature have to be in kelvin for gas la s to work According to Gay-Lussacs law what happens to the pressure of a gas if the temperature changes from 40.0 degree Celsius to 85.0 degrees Celsius a)pressure decreases b)pressure increases c)pressure stays the same since temperature have to be in kelvin for gas la s to work Solution When volume remains constant if temperature of a given mass of gas is increased pressure increases. ( Gay- Lussacs law is P/T = constant, when V,n are constant) P1/313K = P2/358K P2/P1 = 358K/313K = 1.14 P2 = 1.14 times of P1 As temperature increases KE of the gas molecules increases and collisions with the wall of the container increases and hence more pressure is exerted. .

1. According to Gay-Lussacs law what happens to the pressure of a gas if the temperature changes
from 40.0 degree Celsius to 85.0 degrees Celsius a)pressure decreases b)pressure increases
c)pressure stays the same since temperature have to be in kelvin for gas la s to work
According to Gay-Lussacs law what happens to the pressure of a gas if the temperature changes
from 40.0 degree Celsius to 85.0 degrees Celsius a)pressure decreases b)pressure increases
c)pressure stays the same since temperature have to be in kelvin for gas la s to work
Solution
When volume remains constant if temperature of a given mass of gas is increased pressure
increases. ( Gay- Lussacs law is P/T = constant, when V,n are constant)
P1/313K = P2/358K
P2/P1 = 358K/313K = 1.14
P2 = 1.14 times of P1
As temperature increases KE of the gas molecules increases and collisions with the wall of the
container increases and hence more pressure is exerted.