5. XC = 79.62Ω
IR = 0.32A
R1 = 100Ω
R2 = 50Ω
V = 32V
f = 500Hz

6. ZC = √ 50² + 79.6² = 94 Ω
ZC = 94 Ω

7. 32
IC = = 0.34 A
94
Answer IC = 0.34 A

9. 50
ΦC = cos¯¹
= 0.5319
94
Answer ΦC = 57.9°
(current leading the voltage as
branch is capacitive).

10. IC = O.34A (leading by 57.9°)
IR = O.32A
(in phase with the voltage as
branch is resistive).

11. I = 0.58A

12. (0.58A)
Answer Φ = 30°
(with current leading the voltage as circuit
is capacitive)