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By Prof. Hitesh Dholakiya
Signal Flow Graph
Examples
Control Engineering
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Engineering Funda Android App Control System YT Playlist
Steps to find transfer function from Signal flow graph
โ– Find Forward paths. (E.g. ๐‘ญ๐Ÿ, ๐‘ญ๐Ÿ, โ€ฆ โ€ฆ , ๐‘ญ๐’)
โ– Find Single Loops. (E.g. ๐‘ณ๐Ÿ, ๐‘ณ๐Ÿ, โ€ฆ โ€ฆ , ๐‘ณ๐’Œ)
โ– Find Two Non-Touching Loops (E.g. ๐‘ณ๐Ÿ
โ€ฒ
= ๐‘ณ๐Ÿ ร— ๐‘ณ๐Ÿ)
โ– Find โˆ†
โˆ†= ๐Ÿ โˆ’ เท ๐‘บ๐’Š๐’๐’ˆ๐’๐’† ๐‘ณ๐’๐’๐’‘๐’” + เท ๐‘ป๐’˜๐’ ๐‘ต๐’๐’ ๐‘ป๐’๐’–๐’„๐’‰๐’Š๐’๐’ˆ ๐‘ณ๐’๐’๐’‘๐’” โˆ’ โ€ฆ โ€ฆ โ€ฆ โ€ฆ
โ– Find โˆ†๐Ÿ, โˆ†๐Ÿ, โ€ฆ โ€ฆ , โˆ†๐’ based on forward path
โˆ†๐Ÿ= ๐Ÿ โˆ’ เท ๐‘บ๐’Š๐’๐’ˆ๐’๐’† ๐‘ณ๐’๐’๐’‘๐’” ๐‘ต๐’๐’• ๐’•๐’๐’–๐’„๐’‰๐’Š๐’๐’ˆ ๐’‘๐’‚๐’•๐’‰ ๐‘ญ๐Ÿ
โˆ†๐Ÿ= ๐Ÿ โˆ’ เท ๐‘บ๐’Š๐’๐’ˆ๐’๐’† ๐‘ณ๐’๐’๐’‘๐’” ๐‘ต๐’๐’• ๐’•๐’๐’–๐’„๐’‰๐’Š๐’๐’ˆ ๐’‘๐’‚๐’•๐’‰ ๐‘ญ๐Ÿ
โ– Transfer Function
๐‘ช(๐’”)
๐‘น(๐’”)
=
๐‘ญ๐Ÿโˆ†๐Ÿ + ๐‘ญ๐Ÿโˆ†๐Ÿ + โ€ฆ โ€ฆ + ๐‘ญ๐’โˆ†๐’
โˆ†
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R C
-1
-1 -1
1 1
๐บ1 ๐บ2 ๐บ3
๐บ4 ๐บ5
๐บ6
๐น1 = 1 ร— ๐บ1 ร— ๐บ2 ร— ๐บ3 ร— 1 = ๐บ1๐บ2๐บ3
Find Forward Path
๐น2 = 1 ร— ๐บ4 ร— ๐บ5 ร— 1 = ๐บ4๐บ5
Find Single Loops
๐ฟ1 = ๐บ1 ร— ๐บ2 ร— ๐บ3 ร— โˆ’1 = โˆ’๐บ1๐บ2๐บ3
๐ฟ2 = ๐บ2 ร— โˆ’1 = โˆ’๐บ2
๐ฟ3 = ๐บ3 ร— โˆ’1 = โˆ’๐บ3
๐ฟ4 = ๐บ6
๐ฟ5 = ๐บ4 ร— ๐บ5 ร— โˆ’1 = โˆ’๐บ4๐บ5
Find Two Non Touching Loops
๐ฟ1
โ€ฒ
= ๐ฟ1 ร— ๐ฟ4 = โˆ’๐บ1๐บ2๐บ3 ร— ๐บ6 = โˆ’๐บ1๐บ2๐บ3๐บ6
๐ฟ2
โ€ฒ
= ๐ฟ2 ร— ๐ฟ4 = โˆ’๐บ2 ร— ๐บ6 = โˆ’๐บ2๐บ6
๐ฟ3
โ€ฒ
= ๐ฟ2 ร— ๐ฟ5 = โˆ’๐บ2 ร— โˆ’๐บ4๐บ5 = ๐บ2๐บ4๐บ5
๐ฟ4
โ€ฒ
= ๐ฟ3 ร— ๐ฟ4 = โˆ’๐บ3 ร— ๐บ6 = โˆ’๐บ3๐บ6
Find โˆ†
โˆ†= 1 โˆ’ เท ๐‘†๐‘–๐‘›๐‘”๐‘™๐‘’ ๐ฟ๐‘œ๐‘œ๐‘๐‘  + เท ๐‘‡๐‘ค๐‘œ ๐‘๐‘œ๐‘› ๐‘‡๐‘œ๐‘ข๐‘โ„Ž๐‘–๐‘›๐‘” ๐ฟ๐‘œ๐‘œ๐‘๐‘ 
โˆ†= 1 โˆ’ โˆ’๐บ1๐บ2๐บ3 โˆ’ ๐บ2 โˆ’ ๐บ3 + ๐บ6 โˆ’ ๐บ4๐บ5 + (โˆ’๐บ1๐บ2๐บ3๐บ6 โˆ’ ๐บ2๐บ6 + ๐บ2๐บ4๐บ5 โˆ’ ๐บ3๐บ6)
Find โˆ†๐’Š
โˆ†๐Ÿ= ๐Ÿ โˆ’ เท ๐‘บ๐’Š๐’๐’ˆ๐’๐’† ๐‘ณ๐’๐’๐’‘๐’” ๐‘ต๐’๐’• ๐’•๐’๐’–๐’„๐’‰๐’Š๐’๐’ˆ ๐’‘๐’‚๐’•๐’‰ ๐‘ญ๐Ÿ
โˆ†๐Ÿ= ๐Ÿ โˆ’ ๐‘ฎ๐Ÿ”
โˆ†๐Ÿ= ๐Ÿ โˆ’ เท ๐‘บ๐’Š๐’๐’ˆ๐’๐’† ๐‘ณ๐’๐’๐’‘๐’” ๐‘ต๐’๐’• ๐’•๐’๐’–๐’„๐’‰๐’Š๐’๐’ˆ ๐’‘๐’‚๐’•๐’‰ ๐‘ญ๐Ÿ
โˆ†๐Ÿ= ๐Ÿ + ๐‘ฎ๐Ÿ
๐‘ช(๐’”)
๐‘น(๐’”)
=
๐‘ญ๐Ÿโˆ†๐Ÿ + ๐‘ญ๐Ÿโˆ†๐Ÿ
โˆ†
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R C
1 1 1
๐บ1 ๐บ2 ๐บ3
๐บ4
๐ป1
โˆ’๐ป1
โˆ’๐ป2
Find Forward Path
๐น1 = 1 ร— ๐บ1 ร— ๐บ2 ร— ๐บ3 ร— 1 ร— 1 = ๐บ1๐บ2๐บ3
๐น2 = ๐บ4 ร— 1 = ๐บ4
Find Single Loops
๐ฟ1 = ๐บ1 ร— ๐บ2 ร— ๐ป1 = ๐บ1๐บ2๐ป1
๐ฟ2 = ๐บ2 ร— โˆ’๐ป1 = โˆ’๐บ2๐ป1
๐ฟ3 = ๐บ2 ร— ๐บ3 ร— โˆ’๐ป2 = โˆ’๐บ2๐บ3๐ป2
No Two Non Touching Loops
Find โˆ†
โˆ†= ๐Ÿ โˆ’ เท ๐‘บ๐’Š๐’๐’ˆ๐’๐’† ๐‘ณ๐’๐’๐’‘๐’” + เท ๐‘ป๐’˜๐’ ๐‘ต๐’๐’ ๐‘ป๐’๐’–๐’„๐’‰๐’Š๐’๐’ˆ ๐‘ณ๐’๐’๐’‘๐’”
โˆ†= ๐Ÿ โˆ’ ๐‘ฎ๐Ÿ๐‘ฎ๐Ÿ๐‘ฏ๐Ÿ โˆ’ ๐‘ฎ๐Ÿ๐‘ฏ๐Ÿ โˆ’ ๐‘ฎ๐Ÿ๐‘ฎ๐Ÿ‘๐‘ฏ๐Ÿ
Find โˆ†๐’Š
โˆ†๐Ÿ= ๐Ÿ โˆ’ เท ๐‘บ๐’Š๐’๐’ˆ๐’๐’† ๐‘ณ๐’๐’๐’‘๐’” ๐‘ต๐’๐’• ๐’•๐’๐’–๐’„๐’‰๐’Š๐’๐’ˆ ๐’‘๐’‚๐’•๐’‰ ๐‘ญ๐Ÿ = ๐Ÿ
โˆ†๐Ÿ= ๐Ÿ โˆ’ เท ๐‘บ๐’Š๐’๐’ˆ๐’๐’† ๐‘ณ๐’๐’๐’‘๐’” ๐‘ต๐’๐’• ๐’•๐’๐’–๐’„๐’‰๐’Š๐’๐’ˆ ๐’‘๐’‚๐’•๐’‰ ๐‘ญ๐Ÿ = ๐Ÿ + ๐‘ฎ๐Ÿ๐‘ฎ๐Ÿ‘๐‘ฏ๐Ÿ + ๐‘ฎ๐Ÿ๐‘ฏ๐Ÿ โˆ’ ๐‘ฎ๐Ÿ๐‘ฎ๐Ÿ๐‘ฏ๐Ÿ
๐‘ช(๐’”)
๐‘น(๐’”)
=
๐‘ญ๐Ÿโˆ†๐Ÿ + ๐‘ญ๐Ÿโˆ†๐Ÿ
โˆ†
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Signal Flow Graph Examples

  • 1. By Prof. Hitesh Dholakiya Signal Flow Graph Examples Control Engineering E n g i n e e r i n g F u n d a Engineering Funda Android App Control System YT Playlist
  • 2. Steps to find transfer function from Signal flow graph โ– Find Forward paths. (E.g. ๐‘ญ๐Ÿ, ๐‘ญ๐Ÿ, โ€ฆ โ€ฆ , ๐‘ญ๐’) โ– Find Single Loops. (E.g. ๐‘ณ๐Ÿ, ๐‘ณ๐Ÿ, โ€ฆ โ€ฆ , ๐‘ณ๐’Œ) โ– Find Two Non-Touching Loops (E.g. ๐‘ณ๐Ÿ โ€ฒ = ๐‘ณ๐Ÿ ร— ๐‘ณ๐Ÿ) โ– Find โˆ† โˆ†= ๐Ÿ โˆ’ เท ๐‘บ๐’Š๐’๐’ˆ๐’๐’† ๐‘ณ๐’๐’๐’‘๐’” + เท ๐‘ป๐’˜๐’ ๐‘ต๐’๐’ ๐‘ป๐’๐’–๐’„๐’‰๐’Š๐’๐’ˆ ๐‘ณ๐’๐’๐’‘๐’” โˆ’ โ€ฆ โ€ฆ โ€ฆ โ€ฆ โ– Find โˆ†๐Ÿ, โˆ†๐Ÿ, โ€ฆ โ€ฆ , โˆ†๐’ based on forward path โˆ†๐Ÿ= ๐Ÿ โˆ’ เท ๐‘บ๐’Š๐’๐’ˆ๐’๐’† ๐‘ณ๐’๐’๐’‘๐’” ๐‘ต๐’๐’• ๐’•๐’๐’–๐’„๐’‰๐’Š๐’๐’ˆ ๐’‘๐’‚๐’•๐’‰ ๐‘ญ๐Ÿ โˆ†๐Ÿ= ๐Ÿ โˆ’ เท ๐‘บ๐’Š๐’๐’ˆ๐’๐’† ๐‘ณ๐’๐’๐’‘๐’” ๐‘ต๐’๐’• ๐’•๐’๐’–๐’„๐’‰๐’Š๐’๐’ˆ ๐’‘๐’‚๐’•๐’‰ ๐‘ญ๐Ÿ โ– Transfer Function ๐‘ช(๐’”) ๐‘น(๐’”) = ๐‘ญ๐Ÿโˆ†๐Ÿ + ๐‘ญ๐Ÿโˆ†๐Ÿ + โ€ฆ โ€ฆ + ๐‘ญ๐’โˆ†๐’ โˆ† E n g i n e e r i n g F u n d a Engineering Funda Android App Control System YT Playlist
  • 3. R C -1 -1 -1 1 1 ๐บ1 ๐บ2 ๐บ3 ๐บ4 ๐บ5 ๐บ6 ๐น1 = 1 ร— ๐บ1 ร— ๐บ2 ร— ๐บ3 ร— 1 = ๐บ1๐บ2๐บ3 Find Forward Path ๐น2 = 1 ร— ๐บ4 ร— ๐บ5 ร— 1 = ๐บ4๐บ5 Find Single Loops ๐ฟ1 = ๐บ1 ร— ๐บ2 ร— ๐บ3 ร— โˆ’1 = โˆ’๐บ1๐บ2๐บ3 ๐ฟ2 = ๐บ2 ร— โˆ’1 = โˆ’๐บ2 ๐ฟ3 = ๐บ3 ร— โˆ’1 = โˆ’๐บ3 ๐ฟ4 = ๐บ6 ๐ฟ5 = ๐บ4 ร— ๐บ5 ร— โˆ’1 = โˆ’๐บ4๐บ5 Find Two Non Touching Loops ๐ฟ1 โ€ฒ = ๐ฟ1 ร— ๐ฟ4 = โˆ’๐บ1๐บ2๐บ3 ร— ๐บ6 = โˆ’๐บ1๐บ2๐บ3๐บ6 ๐ฟ2 โ€ฒ = ๐ฟ2 ร— ๐ฟ4 = โˆ’๐บ2 ร— ๐บ6 = โˆ’๐บ2๐บ6 ๐ฟ3 โ€ฒ = ๐ฟ2 ร— ๐ฟ5 = โˆ’๐บ2 ร— โˆ’๐บ4๐บ5 = ๐บ2๐บ4๐บ5 ๐ฟ4 โ€ฒ = ๐ฟ3 ร— ๐ฟ4 = โˆ’๐บ3 ร— ๐บ6 = โˆ’๐บ3๐บ6 Find โˆ† โˆ†= 1 โˆ’ เท ๐‘†๐‘–๐‘›๐‘”๐‘™๐‘’ ๐ฟ๐‘œ๐‘œ๐‘๐‘  + เท ๐‘‡๐‘ค๐‘œ ๐‘๐‘œ๐‘› ๐‘‡๐‘œ๐‘ข๐‘โ„Ž๐‘–๐‘›๐‘” ๐ฟ๐‘œ๐‘œ๐‘๐‘  โˆ†= 1 โˆ’ โˆ’๐บ1๐บ2๐บ3 โˆ’ ๐บ2 โˆ’ ๐บ3 + ๐บ6 โˆ’ ๐บ4๐บ5 + (โˆ’๐บ1๐บ2๐บ3๐บ6 โˆ’ ๐บ2๐บ6 + ๐บ2๐บ4๐บ5 โˆ’ ๐บ3๐บ6) Find โˆ†๐’Š โˆ†๐Ÿ= ๐Ÿ โˆ’ เท ๐‘บ๐’Š๐’๐’ˆ๐’๐’† ๐‘ณ๐’๐’๐’‘๐’” ๐‘ต๐’๐’• ๐’•๐’๐’–๐’„๐’‰๐’Š๐’๐’ˆ ๐’‘๐’‚๐’•๐’‰ ๐‘ญ๐Ÿ โˆ†๐Ÿ= ๐Ÿ โˆ’ ๐‘ฎ๐Ÿ” โˆ†๐Ÿ= ๐Ÿ โˆ’ เท ๐‘บ๐’Š๐’๐’ˆ๐’๐’† ๐‘ณ๐’๐’๐’‘๐’” ๐‘ต๐’๐’• ๐’•๐’๐’–๐’„๐’‰๐’Š๐’๐’ˆ ๐’‘๐’‚๐’•๐’‰ ๐‘ญ๐Ÿ โˆ†๐Ÿ= ๐Ÿ + ๐‘ฎ๐Ÿ ๐‘ช(๐’”) ๐‘น(๐’”) = ๐‘ญ๐Ÿโˆ†๐Ÿ + ๐‘ญ๐Ÿโˆ†๐Ÿ โˆ† E n g i n e e r i n g F u n d a
  • 4. R C 1 1 1 ๐บ1 ๐บ2 ๐บ3 ๐บ4 ๐ป1 โˆ’๐ป1 โˆ’๐ป2 Find Forward Path ๐น1 = 1 ร— ๐บ1 ร— ๐บ2 ร— ๐บ3 ร— 1 ร— 1 = ๐บ1๐บ2๐บ3 ๐น2 = ๐บ4 ร— 1 = ๐บ4 Find Single Loops ๐ฟ1 = ๐บ1 ร— ๐บ2 ร— ๐ป1 = ๐บ1๐บ2๐ป1 ๐ฟ2 = ๐บ2 ร— โˆ’๐ป1 = โˆ’๐บ2๐ป1 ๐ฟ3 = ๐บ2 ร— ๐บ3 ร— โˆ’๐ป2 = โˆ’๐บ2๐บ3๐ป2 No Two Non Touching Loops Find โˆ† โˆ†= ๐Ÿ โˆ’ เท ๐‘บ๐’Š๐’๐’ˆ๐’๐’† ๐‘ณ๐’๐’๐’‘๐’” + เท ๐‘ป๐’˜๐’ ๐‘ต๐’๐’ ๐‘ป๐’๐’–๐’„๐’‰๐’Š๐’๐’ˆ ๐‘ณ๐’๐’๐’‘๐’” โˆ†= ๐Ÿ โˆ’ ๐‘ฎ๐Ÿ๐‘ฎ๐Ÿ๐‘ฏ๐Ÿ โˆ’ ๐‘ฎ๐Ÿ๐‘ฏ๐Ÿ โˆ’ ๐‘ฎ๐Ÿ๐‘ฎ๐Ÿ‘๐‘ฏ๐Ÿ Find โˆ†๐’Š โˆ†๐Ÿ= ๐Ÿ โˆ’ เท ๐‘บ๐’Š๐’๐’ˆ๐’๐’† ๐‘ณ๐’๐’๐’‘๐’” ๐‘ต๐’๐’• ๐’•๐’๐’–๐’„๐’‰๐’Š๐’๐’ˆ ๐’‘๐’‚๐’•๐’‰ ๐‘ญ๐Ÿ = ๐Ÿ โˆ†๐Ÿ= ๐Ÿ โˆ’ เท ๐‘บ๐’Š๐’๐’ˆ๐’๐’† ๐‘ณ๐’๐’๐’‘๐’” ๐‘ต๐’๐’• ๐’•๐’๐’–๐’„๐’‰๐’Š๐’๐’ˆ ๐’‘๐’‚๐’•๐’‰ ๐‘ญ๐Ÿ = ๐Ÿ + ๐‘ฎ๐Ÿ๐‘ฎ๐Ÿ‘๐‘ฏ๐Ÿ + ๐‘ฎ๐Ÿ๐‘ฏ๐Ÿ โˆ’ ๐‘ฎ๐Ÿ๐‘ฎ๐Ÿ๐‘ฏ๐Ÿ ๐‘ช(๐’”) ๐‘น(๐’”) = ๐‘ญ๐Ÿโˆ†๐Ÿ + ๐‘ญ๐Ÿโˆ†๐Ÿ โˆ† E n g i n e e r i n g F u n d a Engineering Funda Android App Control System YT Playlist