4Fe+3O2=> 2Fe2O3 n(Fe2O3) =16.7/160=0.104375mole are u sure that Fe not Fe2O3 in the ore? because the later solution doesn\'t make any sense. give a response, I\'ll try to take care of it after u check the given. Solution 4Fe+3O2=> 2Fe2O3 n(Fe2O3) =16.7/160=0.104375mole are u sure that Fe not Fe2O3 in the ore? because the later solution doesn\'t make any sense. give a response, I\'ll try to take care of it after u check the given..