Write a Java program in which a method named digitSum that accepts a.pdf
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Winnebagel Corp. currently sells 20,000 motor homes per year at $58,000 each, and 7,000 luxury motor coaches per year at $95,000 each. The company wants to introduce a new portable camper to fill out its product line; it hopes to sell 15,000 of these campers per year at $9,000 each. An independent consultant has determined that if Winnebagel introduces the new campers, it should boost the sales of its existing motor homes by 2,300 units per year, and reduce the sales of its motor coaches by 1,000 units per year. What is the amount to use as the annual sales figure when evaluating this project? (Enter your answer in dollars, not millions of dollars, e.g. 1,234,567.) Solution Sales revenue from new portable camper = 15000*$9000 = $ 13,50,00,000 Additional sales of motor homes = 2300*$58000 = $ 13,34,00,000 Decrease in sales of motor coaches = 1000*$95000 = $ -9,50,00,000 Annual sales figure for evaluating the project $ 17,34,00,000.
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![Write a Java program in which a method named digitSum that accepts an integer as a parameter
and returns the sum of the digits of that number. For example, the call digitSum(29107) returns
2+9+1+0+7 or 19. For negative numbers, return the same value that would result if the number
were positive. For example, digitSum(-456) returns 4+5+6 or 15.The call digitSum(0) returns 0
Solution
DigitSumTest.java
import java.util.Scanner;
public class DigitSumTest {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.print("Enter an integer: ");
int n = scan.nextInt();
int sum = digitSum(n);
System.out.println("The sum of digits is "+sum);
}
public static int digitSum (int n) {
int sum = 0;
if(n == 0){
return 0;
}
else if(n < 0){
n = -n;
}
do {
sum += n % 10;
} while ((n = n / 10) != 0);
return sum;
}
}](https://image.slidesharecdn.com/writeajavaprograminwhichamethodnameddigitsumthatacceptsa-230704110643-4be8b803/85/Write-a-Java-program-in-which-a-method-named-digitSum-that-accepts-a-pdf-1-320.jpg)
Recommended
Write a static method named numberoddSum that accepts a positive inte.pdf
Write a static method named numberoddSum that accepts a positive integer returns the sum of
its odd digits. For example, the call numberOddSum (1436527) should return 16.
Solution
Hi, PLease find my implementtion.
Please let me know in case of any issue.
import java.util.Scanner;
public class OddDigitsSum {
public static int numberOddSum(int n){
int sum = 0; // variable to store sum of odd digits
// if n is negative, making it positive
if(n < 0)
n = -n;
while( n > 0){
int digit = n%10; // getting current digit
if(digit % 2 == 1)
sum = sum + digit;
n = n/10;
}
return sum;
}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print(\"Enter a integer: \");
int number = sc.nextInt();
System.out.println(\"Odd digit sum: \"+numberOddSum(number));
}
}
/*
Sample run:
Enter a integer: 4321234
Odd digit sum: 7
*/.
SumNumbers.java import java.util.Scanner;public class SumNumbe.pdf
SumNumbers.java
import java.util.Scanner;
public class SumNumbers {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
int sum = 0;
while(true){
System.out.println(\"Enter integer:\");
int n = scan.nextInt();
if(n == -1){
break;
}
sum = sum + n;
}
System.out.println(\"The sum is \"+sum);
}
}
Output:
Enter integer:
1
Enter integer:
2
Enter integer:
3
Enter integer:
4
Enter integer:
5
Enter integer:
6
Enter integer:
7
Enter integer:
8
Enter integer:
9
Enter integer:
-1
The sum is 45
Solution
SumNumbers.java
import java.util.Scanner;
public class SumNumbers {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
int sum = 0;
while(true){
System.out.println(\"Enter integer:\");
int n = scan.nextInt();
if(n == -1){
break;
}
sum = sum + n;
}
System.out.println(\"The sum is \"+sum);
}
}
Output:
Enter integer:
1
Enter integer:
2
Enter integer:
3
Enter integer:
4
Enter integer:
5
Enter integer:
6
Enter integer:
7
Enter integer:
8
Enter integer:
9
Enter integer:
-1
The sum is 45.
CODEimport java.util.; public class test { public static voi.pdf
CODE:
import java.util.*;
public class test {
public static void main(String args[]) {
int num, sum=0;
Scanner input=new Scanner(System.in);
System.out.print(\"Input num : \");
num=input.nextInt();
while(num != 13) {
sum=sum+num;
System.out.print(\"Input num : \");
num=input.nextInt();
}
sum=sum+num;
System.out.println(\"Sum = \"+sum);
}
}
save the above file as test.java
Output:
javac test.java
java test
Input num :
1
Input num :
2
Input num :
3
Input num :
4
Input num :
5
Input num :
6
Input num :
7
Input num :
8
Input num :
9
Input num :
0
Input num :
13
Sum = 58
Solution
CODE:
import java.util.*;
public class test {
public static void main(String args[]) {
int num, sum=0;
Scanner input=new Scanner(System.in);
System.out.print(\"Input num : \");
num=input.nextInt();
while(num != 13) {
sum=sum+num;
System.out.print(\"Input num : \");
num=input.nextInt();
}
sum=sum+num;
System.out.println(\"Sum = \"+sum);
}
}
save the above file as test.java
Output:
javac test.java
java test
Input num :
1
Input num :
2
Input num :
3
Input num :
4
Input num :
5
Input num :
6
Input num :
7
Input num :
8
Input num :
9
Input num :
0
Input num :
13
Sum = 58.
Recommended
Write a static method named numberoddSum that accepts a positive inte.pdf
Write a static method named numberoddSum that accepts a positive integer returns the sum of
its odd digits. For example, the call numberOddSum (1436527) should return 16.
Solution
Hi, PLease find my implementtion.
Please let me know in case of any issue.
import java.util.Scanner;
public class OddDigitsSum {
public static int numberOddSum(int n){
int sum = 0; // variable to store sum of odd digits
// if n is negative, making it positive
if(n < 0)
n = -n;
while( n > 0){
int digit = n%10; // getting current digit
if(digit % 2 == 1)
sum = sum + digit;
n = n/10;
}
return sum;
}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print(\"Enter a integer: \");
int number = sc.nextInt();
System.out.println(\"Odd digit sum: \"+numberOddSum(number));
}
}
/*
Sample run:
Enter a integer: 4321234
Odd digit sum: 7
*/.
SumNumbers.java import java.util.Scanner;public class SumNumbe.pdf
SumNumbers.java
import java.util.Scanner;
public class SumNumbers {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
int sum = 0;
while(true){
System.out.println(\"Enter integer:\");
int n = scan.nextInt();
if(n == -1){
break;
}
sum = sum + n;
}
System.out.println(\"The sum is \"+sum);
}
}
Output:
Enter integer:
1
Enter integer:
2
Enter integer:
3
Enter integer:
4
Enter integer:
5
Enter integer:
6
Enter integer:
7
Enter integer:
8
Enter integer:
9
Enter integer:
-1
The sum is 45
Solution
SumNumbers.java
import java.util.Scanner;
public class SumNumbers {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
int sum = 0;
while(true){
System.out.println(\"Enter integer:\");
int n = scan.nextInt();
if(n == -1){
break;
}
sum = sum + n;
}
System.out.println(\"The sum is \"+sum);
}
}
Output:
Enter integer:
1
Enter integer:
2
Enter integer:
3
Enter integer:
4
Enter integer:
5
Enter integer:
6
Enter integer:
7
Enter integer:
8
Enter integer:
9
Enter integer:
-1
The sum is 45.
CODEimport java.util.; public class test { public static voi.pdf
CODE:
import java.util.*;
public class test {
public static void main(String args[]) {
int num, sum=0;
Scanner input=new Scanner(System.in);
System.out.print(\"Input num : \");
num=input.nextInt();
while(num != 13) {
sum=sum+num;
System.out.print(\"Input num : \");
num=input.nextInt();
}
sum=sum+num;
System.out.println(\"Sum = \"+sum);
}
}
save the above file as test.java
Output:
javac test.java
java test
Input num :
1
Input num :
2
Input num :
3
Input num :
4
Input num :
5
Input num :
6
Input num :
7
Input num :
8
Input num :
9
Input num :
0
Input num :
13
Sum = 58
Solution
CODE:
import java.util.*;
public class test {
public static void main(String args[]) {
int num, sum=0;
Scanner input=new Scanner(System.in);
System.out.print(\"Input num : \");
num=input.nextInt();
while(num != 13) {
sum=sum+num;
System.out.print(\"Input num : \");
num=input.nextInt();
}
sum=sum+num;
System.out.println(\"Sum = \"+sum);
}
}
save the above file as test.java
Output:
javac test.java
java test
Input num :
1
Input num :
2
Input num :
3
Input num :
4
Input num :
5
Input num :
6
Input num :
7
Input num :
8
Input num :
9
Input num :
0
Input num :
13
Sum = 58.
Programming in C Lab
Semester 1. Practical File for Introduction to computers and programming in C Lab
CountStringCharacters.javaimport java.util.Scanner; public cla.pdf
CountStringCharacters.java
import java.util.Scanner;
public class CountStringCharacters {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter a sentence or phrase: \");
String s = scan.nextLine();
int numOfCharacters = getNumOfCharacters(s);
System.out.println(\"You entered: \"+s);
System.out.println(\"Number of characters: \"+numOfCharacters);
outputWithoutWhitespace(s);
}
public static int getNumOfCharacters(String s){
int numOfCharCount = 0;
for(int i=0; i
Solution
CountStringCharacters.java
import java.util.Scanner;
public class CountStringCharacters {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter a sentence or phrase: \");
String s = scan.nextLine();
int numOfCharacters = getNumOfCharacters(s);
System.out.println(\"You entered: \"+s);
System.out.println(\"Number of characters: \"+numOfCharacters);
outputWithoutWhitespace(s);
}
public static int getNumOfCharacters(String s){
int numOfCharCount = 0;
for(int i=0; i.
import java.util.Scanner;public class Digits { public static v.pdf
import java.util.Scanner;
public class Digits
{
public static void main(String[] args)
{
int oddCount = 0, evenCount = 0, zeroCount = 0; //digit counters
int value, digit; //stores input value and digit respectively
int copy; //stores copy of entry
Scanner scan = new Scanner(System.in);
//Get value from user
System.out.println(\"enter number :\");
int value=scan.nextInt();
copy=value;
//Make the value positive
value=Math.abs(value);
//What if the value is actually zero?
if(value==0)
zeroCount++;
while(value>0)
{
digit=value10;
if(digit==0)
zerocount++;
if(digit%2==0)
evenCount++;
else
oddCount++;
value=value/10;
}
System.out.println(\"original value:\"+copy);
System.out.println(\"zero digits :\"+zeroCount);
System.out.println(\"odd digits :\"+oddCount);
System.out.println(\"even digits :\"+evenCount)
}
}
Solution
import java.util.Scanner;
public class Digits
{
public static void main(String[] args)
{
int oddCount = 0, evenCount = 0, zeroCount = 0; //digit counters
int value, digit; //stores input value and digit respectively
int copy; //stores copy of entry
Scanner scan = new Scanner(System.in);
//Get value from user
System.out.println(\"enter number :\");
int value=scan.nextInt();
copy=value;
//Make the value positive
value=Math.abs(value);
//What if the value is actually zero?
if(value==0)
zeroCount++;
while(value>0)
{
digit=value10;
if(digit==0)
zerocount++;
if(digit%2==0)
evenCount++;
else
oddCount++;
value=value/10;
}
System.out.println(\"original value:\"+copy);
System.out.println(\"zero digits :\"+zeroCount);
System.out.println(\"odd digits :\"+oddCount);
System.out.println(\"even digits :\"+evenCount)
}
}.
PCA-2 Programming and Solving 2nd Sem.pdf
C language Basic Questions for 1st year, 2nd sem Engineering Students Specially for MAKAUT students
PCA-2 Programming and Solving 2nd Sem.docx
C language Basic Questions for 1st year, 2nd sem Engineering Students Specially for MAKAUT students
An object of class StatCalc can be used to compute several simp.pdf
/*
An object of class StatCalc can be used to compute several simple statistics
for a set of numbers. Numbers are entered into the dataset using
the enter(double) method. Methods are provided to return the following
statistics for the set of numbers that have been entered: The number
of items, the sum of the items, the average, the standard deviation,
the maximum, and the minimum.
*/
public class Stats {
private int count; // Number of numbers that have been entered.
private double sum; // The sum of all the items that have been entered.
private double squareSum; // The sum of the squares of all the items.
private double max = Double.NEGATIVE_INFINITY; // Largest item seen.
private double min = Double.POSITIVE_INFINITY; // Smallest item seen.
int[] myList;
public int getCount() {
System.out.println(myList.size());
count = myList.size().
// Return number of items that have been entered.
return count;
}
public double getSum() {
int sum = 0;
for (int i = 0; i < myList.length; i++)
{
sum +=mylist[i];
}
return sum;
}
public double getMean() {
int sum = 0;
for (int i = 0; i < myList.length; i++)
{
sum +=mylist[i];
}
if(count > 0)
return sum / count;
else
return -1;
}
public double getMin() {
int smallest = myList[0];
int largetst = myList[0];
for(int i=1; i< mylist.length; i++)
{
if(mylist[i] > largetst)
largetst = numbers[i];
else if (mylist[i] < smallest)
smallest = numbers[i];
}
return smallest;
}
public double getMax() {
int smallest = myList[0];
int largetst = myList[0];
for(int i=1; i< mylist.length; i++)
{
if(mylist[i] > largetst)
largetst = numbers[i];
else if (mylist[i] < smallest)
smallest = numbers[i];
}
return largetst;
}
stats(int [] data)
{
if(data.count <= count)
{
if(myList.size() > 0)
System.arraycopy( myList, 0, data, 0, count );
}
}
stats()
{
Scanner s = new Scanner(System.in);
int count = s.nextInt();
s.nextLine(); // throw away the newline.
int [] numbers = new int[count];
Scanner numScanner = new Scanner(s.nextLine());
for (int i = 0; i < count; i++) {
if (numScanner.hasNextInt()) {
numbers[i] = numScanner.nextInt();
} else {
System.out.println(\"You didn\'t provide enough numbers\");
break;
}
}
System.arraycopy( myList, 0, numbers, 0, count );
}
stats(int size)
{
setValue(size);
}
private void setValue(int size)
{
count = size;
myList = new int[size];
}
} // end class StatCalc
public class SimpleStats {
public static void main(String[] args) {
Stat calc; // Computes stats for numbers entered by user.
calc = new Stat(100);
int arry[] = {20.20.40,30.80,,70,4,5,6,7,10}
calc.setvalue(array);
double item; // One number entered by the user.
TextIO.putln(\"Enter your numbers. Enter 0 to end.\");
TextIO.putln();
do {
TextIO.put(\"? \");
item = TextIO.getlnDouble();
if (item != 0)
calc.enter(item);
} while ( item != 0 );
TextIO.putln(\"\ Statistics about your calc:\ \");
TextIO.putln(\" Count: \" + calc.getCount());
TextIO.putln(\" Sum: \" + calc.getSum());
TextIO.putln(\" Minimum: \" + calc.getMin());
TextIO.putln(\" Maximum: \" + ca.
Question Completion Status QUESTION In the absence of oxygen, animal.pdf
Question Completion Status: QUESTION In the absence of oxygen, animal cells, through a
series of reactions, convert pyruvate to O lactic O CO2 and ethyl alcohol O carbon dioxide O
citric acid QUESTION 2 The prepatory reaction converts the pyruvate into for use in the citric
acid cycle) and (which leaves the cell O NADH: NAD O ATP: ADP O glucose; CO2 O acetyl-
CoA, carbon dioxide QUESTION 3 Energy released as electrons are transported down the
electron transport chain in cellular respiration is directly used to O oxygen O produce co2 O
produce NADH and FADH2 O establish a proton (H gradient OS
Solution
1.pyruvate is converted to CO2 and ethyl alcohol.
2.preparatory reaction convertpyruvate to acetyl coA and CO2
3.to produce oxygen.
4.glucose is ultimately converted to CO2.
5.cellular respiration requires glucose and CO2.
6.TCA, ETS take place in mitochondria.
7.purpose of dellular respiration to produce ATP.
8.ATP SYNTHASE PHOSPHORYLATES ADP TP ATP.
9.all organisms respire.
10.oxygen is not a product of respiration.
11.oxygen is the final electron acceptor.
12.glycolysis break glucose in 2 molecule pyruvate.
13.CO2 is produced in the preparatory reaction of citric acid cycle.
14.FADH2 and NADH carry electron .
15.in CYTRIC ACID CYCLE 34 molecule ATP produced from one glucose..
Short Answer 1. What are the 5 mechanisms of evolutionary ch.pdf
Short Answer: 1. What are the 5 mechanisms of evolutionary change that make up Modern
synthesis?
Solution
Answer = 1]
Five mechanisms of evolutionary change that make up modern synthesis are
1] Natural selection = is the process by which traits that enhance survival & reproduction
becomes more common in succesive generations of population
2] Biased mutation =When there are different probabilities occure at molecular level for different
mutations to occur known as biased mutation
3] Genetic drift = is the change in allele frequency from one generation to next that occure
because alleles are subjected to sampling error
drift acts faster & has more drastic effects in smaller populations
genetic drift contribute to speciation
4] Genetic hitchhiking =When one allele in particular haplotype is strongly beneficial natural
selection can drive a selective sweep that will also cause the other allales in haplotype to become
more common in population is called as genetic hitchhiking
5] Gene flow = Involves the exchange of genes between populations & species
gene flow between population can introduce traits & alleles.
Review Preparation for Statistics A statistics instructor wanted to s.pdf
Review Preparation for Statistics A statistics instructor wanted to see if student participation in
review preparation methods led to higher examination scores. Five students were randomly
selected and placed in each test group for a three-week unit on statistical inference. Everyone
took the same examination at the end of the unit, and the resulting scores are shown below Is
there sufficient evidence at 0.05 to conclude an interaction between the two factors? Is there
sufficient evidence to conclude a difference in mean scores based on formula delivery system? Is
there sufficient evidence to conclude a difference in mean scores based on the review
organization technique? (12-3)
Solution.
Problem 3-8BRIDGEPORT ADVERTISING TRIAL BALANCE DECEMBER 31, 2.pdf
Problem 3-8
BRIDGEPORT ADVERTISING
TRIAL BALANCE
DECEMBER 31, 2017
Unadjusted
Adjusted
Dr.
Cr.
Dr.
Cr.
$148,820
$148,820
$158,950
$158,950
No.
Date
Account Titles and Explanation
Debit
Credit
(To record accrued service revenue)
(To record supplies used)
(To expired insurance)
(To record depreciation on equiment)
(To record interest accrued on the note)
(To record service revenue earned)
(To record accrued wages)
Assets
Liabilities and Stockholders’ Equity
%
Open Show Work
SAVE FOR LATER
SUBMIT ANSWER
Problem 3-8 Bridgeport Advertising was founded by Murali Vedula in January 2015. Presented
below are both the adjusted and unadjusted trial balances as of December 31, 2017.
BRIDGEPORT ADVERTISING
TRIAL BALANCE
DECEMBER 31, 2017
Unadjusted
Adjusted
Dr.
Cr.
Dr.
Cr.Cash$16,740$16,740Accounts Receivable19,17023,012Supplies9,7606,845Prepaid
Insurance4,2202,625Equipment64,70064,700Accumulated Depreciation-
Equipment$24,120$29,050Notes Payable8,6008,600Accounts Payable1,8901,890Interest
Payable0602Unearned Service Revenue5,3503,405Salaries and Wages Payable0756Common
Stock19,22019,220Retained Earnings27,24727,247Dividends19,30019,300Service
Revenue62,39368,180Salaries and Wages Expense9,40010,156Insurance Expense1,595Interest
Expense602Depreciation Expense4,930Supplies Expense2,915Rent Expense5,5305,530
$148,820
$148,820
$158,950
$158,950Journalize the annual adjusting entries that were made. (Credit account titles are
automatically indented when amount is entered. Do not indent manually. If no entry is required,
select \"No entry\" for the account titles and enter 0 for the amounts.)
No.
Date
Account Titles and Explanation
Debit
Credit1.Dec. 31
(To record accrued service revenue)2.Dec. 31
(To record supplies used)3.Dec. 31
(To expired insurance)4.Dec. 31
(To record depreciation on equiment)5.Dec. 31
(To record interest accrued on the note)6.Dec. 31
(To record service revenue earned)7.Dec. 31
(To record accrued wages)Prepare an income statement for the year ended December 31. (Enter
loss using either a negative sign preceding the number e.g. -45 or parentheses e.g. (45).)
BRIDGEPORTADVERTISING
Income Statement
December 31, 2017For the Year Ended December 31, 2017For the Quarter Ended December
31, 2017
DividendsExpensesNet Income / (Loss)Retained Earnings, Janaury 1Retained Earnings,
December 31RevenuesTotal ExpensesTotal Revenues
$
DividendsExpensesNet Income / (Loss)Retained Earnings, Janaury 1Retained Earnings,
December 31RevenuesTotal ExpensesTotal Revenues
$
Dividends Expenses Net Income / (Loss) Retained Earnings, Janaury 1 Retained
Earnings, December 31 Revenues Total Expenses Total Revenues
DividendsExpensesNet Income / (Loss)Retained Earnings, Janaury 1Retained Earnings,
December 31RevenuesTotal ExpensesTotal Revenues$
Prepare a retained earnings statement for the year ended December 31. (List items that increase
retained earnings first.)
BRIDGEPORTADVERTISING
Retained Earnings Statement
December 31, 2017For the Year Ended December 31, 2017For .
Q1 Define the three types of data flow. Q2 What are the t.pdf
Q1: Define the three types of data flow.
Q2: What are the two principles of Protocol Layering?
Q3: A sine wave is offset 1/4 cycle with respect to time 0. What is its phase in degrees and
radians?
Q4: List three properties for Infrared waves.
Solution
: 4) Infrared (IR) waves are :
- electromagnetic in nature with longer wavelengths than visible light
- wavelength is from 0.74 micrometres (µm) to 300 µm.
- frequency range is from 1 to 400 THz
IR is thermal radiation emitted by objects near room temperature.
3) phase in degree :
1 complete cycle = 360 °
Then 1/4th cycle =1/4*360= 90°
Phase in radians :
1° =2/360 radians
Then 90° = 90*2/360 = /2 rad = 1.57 rad
1)
Simplex:All the data flow is unidirectional from transmitter to receiver.
Duplex communication is two way in that we have two types:
Half-duplex: communication may be likened to two way Either can may be used to transmit or
receive, but not at the same time
Fullduplex:Full-duplex communication is more like a true telephone, where two people can talk
at the same time and hear one another simultaneously.
1)
When communication is simple we may need only one protocol. When the communication is
Complex we need a protocol at each layer which is called protocol layering
We need to understand two simple principles for that
a) The first principle dictates that if we want
bidirectional communication, we need to make each
layer so that it is able to perform two opposite tasks,
one in each direction.
b) The second principle that we need to follow in
protocol layering is that the two objects under each
layer at both sides should be identical..
Multiple choice A young girl is staring at the raindrops running do.pdf
Multiple choice: A young girl is staring at the raindrops running down her window. She notices
that the raindrops remain more or less intact, even as they cascade down the windowpane. This is
a result of:
ionic bonds between water molecules.
oxygen bonds between water molecules.
covalent bonds between water molecules.
hydrogen bonds between water molecules.
polar covalent bonds between water molecules.
Solution
d). hydrogen bonds between water molecules.
Because of the hydrogen bonding, water exhibits high surface tension. So, water molecules on
the surface are more strongly attracted to each other than to the air above. So that the raindrops
remain more or less intact, even as they cascade down the windowpane..
mitosis is a special set of events that occur in what region of .pdf
mitosis is a special set of events that occur in what region of the cell?
mitosis is a special set of events that occur in what region of the cell?
mitosis is a special set of events that occur in what region of the cell?
Solution
Mitosis is found to occur in the cell nuclei of eukaryotic cells.
In the process of mitosis, one cell divides into two cells and these two cells will be genetically
identical to the original cell.
Our body will grow and repair itself due to the process of mitosis.
Mitosis includes five phases: prophase, prometaphase, metaphase, anaphase and telophase..
If you were looking at an mRNA and saw the codon AUG, what would you .pdf
If you were looking at an mRNA and saw the codon AUG, what would you conclude about it?
What does it mean to that the genetic code is redundant, but not ambiguous? The genetic code is
nearly universal, meaning the same RNA codon that designates tryptophan in humans, designates
tryptophan in bacteria. a. What has this knowledge allowed us to conclude about the code? b.
What has this knowledge allowed us to do with genes Transcription is the DNA-directed
synthesis of RNA: a closer look Describe the general model of transcription. Include in your
answer the steps of transcription and the key elements of each step. Compare and contrast
transcription between prokaryotes and eukaryotes What makes RNA polymerase start
transcribing in a gene at the right place on the DNA of a prokaryotic cell? What makes RNA
polymerase start transcribing in a gene at the right place on the DNA of a eukaryotic cell?
Solution
A)Transcription is the first step in gene expression. It involves copying a gene\'s DNA sequence
to make an RNA molecule.Transcription can be divided into four distinct stages:
Template recognition
Initiation
Elongation
Termination
Initiation:RNA polymerase binds to a sequence of DNA called the promoter,found near the
beginning of a gene.Each gene has its own promoter.Once bound,RNA polymerase separates the
DNA strands,providing the single-stranded template needed for transcription.
Elongation:One strand of DNA,the template strand,acts as a template for RNA polymerase.As it
reads this template one base at a time,the polymerase builds an RNA molecule out of
complementary nucleotides,making a chain that grows from 5\' to 3\'.The RNA transcript carries
the same information as the non-template (coding) strand of DNA,but it contains the base uracil
instead of thymine .
Termination:Sequences called terminators signal that the RNA transcript is complete.Once they
are transcribed,they cause the transcript to be released from the RNA polymerase.
B)Prokaryotes do not have an organized nucleus,so the nuclear materials or DNA is in the
cytoplasm.Therefore,the transcription occurs in the cytoplasm and all the precursors needed for
the transcription are found in the cytoplasm.Prokaryotic transcription requires the RNA
polymerase enzyme in order for the transcription to be successfully completed.The enzyme binds
to the sigma factor and the promoter region,and then initiate the transcription by completing the
holoenzyme.In prokaryotes,DNA is not bound to histones.Thus,the transcription initiates
directly.This could be advantageous when prokaryotes have overlapping genes.Transcription
starts at the promoter region and elongate through the coding region and ends when the RNA
polymerase reads the termination signal.There are two types of termination signals,Rho-
dependent and independant.Transcribed mRNA will be completely translated during the
transcription,and no post-transcription processing will be undergoing most of the
time.Transcriptionl unit has one or more .
If the proportion of an African population that is susceptible to Ma.pdf
If the proportion of an African population that is susceptible to Malaria is 0.49, what proportion
of the population is affected with Sickle Cell Anemia? A. 0.68. B. 0.09. C. 0.45. D. 0.34.
Solution
B 0.09
In literature it was mentioned that 40% of popullation in africa suffering from malaria are
sucessiptible to sickel cell anemia..
Identify nursing diagnoses goal and outcome criteria and interven.pdf
Identify nursing diagnoses goal and outcome criteria and interventions for the postoperative
patient
Identify nursing diagnoses goal and outcome criteria and interventions for the postoperative
patient
Solution
ASSESSMENT: - After the surgery, when the operation procedure is completed, the patient is
usually shifted to intensive care unit. When patient is admitted to PACU determine the medical
diagnosis, the surgery procedure, pain, consciousness, vital signs, medical history, how patient
tolerated the procedure? what was the medication given, and other assessment data listed earlier.
Check and set up equipment like oxygen, suction devices, urinary drainage etc. A more detailed
assessment should be performed when a patient returns to the nursing unit. It is actually
collecting, organizing, validating, and documenting patient data and its purpose is to establish a
database about the patient’s response to health concerns or illness and the ability to manage
health care needs.
DIAGNOSIS: - Medical diagnoses are important factors influencing patient outcomes during
hospitalization. For example, ICU patients with infectious diseases at admission had higher
mortality than the patients with gastrointestinal diseases. After surgery patients are at an
increased risk of severe complication. Nursing diagnosis is the nurse’s clinical judgment about
the patient’s response to potential health conditions and comorbid medical conditions. Several
studies show that these diagnosis influence 31 different types of patient outcomes (e.g. hospital
mortality, the length of stay, and ICU readmission) and interventions. A standard nursing
diagnosis includes three structural components: the problem, the etiology and supporting data. Its
purpose is to identify patient’s strengths and health problems that can be prevented or resolved
by collaborative and independent nursing interventions. and to develop a list of nursing
diagnoses and collaborative problems.
GOAL AND OUTCOME: - The goal is aimed at the medical diagnosis. The outcomes are aimed
at meeting the goals. A patient goal represents a predicted resolution of a diagnosis, evidence of
progress toward resolution, progress toward improved health, or continued maintenance of good
health. Each goal is limited to a time so the health care team has a common time limit for solving
the problem. For example, the goal of “patient will achieve pain relief. A short-term goal is an
objective behavior or response that you expect a patient to achieve in a short time, usually in a
week. A long-term goal is an objective behavior or response that you expect a patient to achieve
over a longer period, usually over several weeks, or even several months (for example “Patient
will leave nicotine products within two months”). Determine how to prevent, reduce, or resolve
the identified patient problems; how to support patient strengths; and how to implement nursing
interventions in a well organized, individualized, and goal-directed way, .
How would you arrange these concepts in terms of concreteness (from .pdf
How would you arrange these concepts in terms of concreteness (from most to least concrete)?
Justify your arrangement.
Asset
Common stock
Equity
Investment
Security
Stock
Solution
Below is the arrangement of concepts in terms of concreteness (most to least):
1. Stock 2. Common Stock 3. Security 4. Investment 5. Asset 6. Equity
Justification : As per my understanding, I have arranged all concepts based on how easily can we
do the valuation and the scope of a particular concept.
Stock is a current asset i.e. the valuation of stock can be done on an yearly basis. Since, it is short
term in nature and can be valued at cost using methods like FIFO, LIFO, etc. Cost is easily
available by looking at the invoices, purchase orders, etc.
Common Stock is a long term liability also called as equity shares. They can be valued using
different techniques like Dividend Discount model. Stock prices are easily available in the
exchange markets.
Securities comes next as they are wider than Common stock. They are the tradeable financial
instruments. They are divided into three parts - equity securities, debt securities and derivatives.
We can value securities from the market which is determined by the demand and supply forces.
Investments includes short term and long term investments. They are valued at the lesser of cost
or fair market value. The market value of investemnts can not be seen on stock exchanges and
hence lesser concrete than securities.
Assets includes both short term and long term assets. Fixed assets like Long term investments,
building, factory, machinery and current assets like Stock, short term investments, account
receivables, cash are included in the broad defination of assets. Hence, investments are a subset
of assets and hence more concrete than assets. Again, there is no trade market for assets to do the
asset valuation.
Equity is difference between assets and liabilities. Equity is a wider term which includes
common stock, preffered stock, retained earnings (calculated from Income statement), security
premium, revaluation reserves (calculated as the difference between the fair market value and
book value of assets). Hence, they can be regarded as least concrete of the given list..
More Related Content
Similar to Write a Java program in which a method named digitSum that accepts a.pdf
Programming in C Lab
Semester 1. Practical File for Introduction to computers and programming in C Lab
CountStringCharacters.javaimport java.util.Scanner; public cla.pdf
CountStringCharacters.java
import java.util.Scanner;
public class CountStringCharacters {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter a sentence or phrase: \");
String s = scan.nextLine();
int numOfCharacters = getNumOfCharacters(s);
System.out.println(\"You entered: \"+s);
System.out.println(\"Number of characters: \"+numOfCharacters);
outputWithoutWhitespace(s);
}
public static int getNumOfCharacters(String s){
int numOfCharCount = 0;
for(int i=0; i
Solution
CountStringCharacters.java
import java.util.Scanner;
public class CountStringCharacters {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter a sentence or phrase: \");
String s = scan.nextLine();
int numOfCharacters = getNumOfCharacters(s);
System.out.println(\"You entered: \"+s);
System.out.println(\"Number of characters: \"+numOfCharacters);
outputWithoutWhitespace(s);
}
public static int getNumOfCharacters(String s){
int numOfCharCount = 0;
for(int i=0; i.
import java.util.Scanner;public class Digits { public static v.pdf
import java.util.Scanner;
public class Digits
{
public static void main(String[] args)
{
int oddCount = 0, evenCount = 0, zeroCount = 0; //digit counters
int value, digit; //stores input value and digit respectively
int copy; //stores copy of entry
Scanner scan = new Scanner(System.in);
//Get value from user
System.out.println(\"enter number :\");
int value=scan.nextInt();
copy=value;
//Make the value positive
value=Math.abs(value);
//What if the value is actually zero?
if(value==0)
zeroCount++;
while(value>0)
{
digit=value10;
if(digit==0)
zerocount++;
if(digit%2==0)
evenCount++;
else
oddCount++;
value=value/10;
}
System.out.println(\"original value:\"+copy);
System.out.println(\"zero digits :\"+zeroCount);
System.out.println(\"odd digits :\"+oddCount);
System.out.println(\"even digits :\"+evenCount)
}
}
Solution
import java.util.Scanner;
public class Digits
{
public static void main(String[] args)
{
int oddCount = 0, evenCount = 0, zeroCount = 0; //digit counters
int value, digit; //stores input value and digit respectively
int copy; //stores copy of entry
Scanner scan = new Scanner(System.in);
//Get value from user
System.out.println(\"enter number :\");
int value=scan.nextInt();
copy=value;
//Make the value positive
value=Math.abs(value);
//What if the value is actually zero?
if(value==0)
zeroCount++;
while(value>0)
{
digit=value10;
if(digit==0)
zerocount++;
if(digit%2==0)
evenCount++;
else
oddCount++;
value=value/10;
}
System.out.println(\"original value:\"+copy);
System.out.println(\"zero digits :\"+zeroCount);
System.out.println(\"odd digits :\"+oddCount);
System.out.println(\"even digits :\"+evenCount)
}
}.
PCA-2 Programming and Solving 2nd Sem.pdf
C language Basic Questions for 1st year, 2nd sem Engineering Students Specially for MAKAUT students
PCA-2 Programming and Solving 2nd Sem.docx
C language Basic Questions for 1st year, 2nd sem Engineering Students Specially for MAKAUT students
An object of class StatCalc can be used to compute several simp.pdf
/*
An object of class StatCalc can be used to compute several simple statistics
for a set of numbers. Numbers are entered into the dataset using
the enter(double) method. Methods are provided to return the following
statistics for the set of numbers that have been entered: The number
of items, the sum of the items, the average, the standard deviation,
the maximum, and the minimum.
*/
public class Stats {
private int count; // Number of numbers that have been entered.
private double sum; // The sum of all the items that have been entered.
private double squareSum; // The sum of the squares of all the items.
private double max = Double.NEGATIVE_INFINITY; // Largest item seen.
private double min = Double.POSITIVE_INFINITY; // Smallest item seen.
int[] myList;
public int getCount() {
System.out.println(myList.size());
count = myList.size().
// Return number of items that have been entered.
return count;
}
public double getSum() {
int sum = 0;
for (int i = 0; i < myList.length; i++)
{
sum +=mylist[i];
}
return sum;
}
public double getMean() {
int sum = 0;
for (int i = 0; i < myList.length; i++)
{
sum +=mylist[i];
}
if(count > 0)
return sum / count;
else
return -1;
}
public double getMin() {
int smallest = myList[0];
int largetst = myList[0];
for(int i=1; i< mylist.length; i++)
{
if(mylist[i] > largetst)
largetst = numbers[i];
else if (mylist[i] < smallest)
smallest = numbers[i];
}
return smallest;
}
public double getMax() {
int smallest = myList[0];
int largetst = myList[0];
for(int i=1; i< mylist.length; i++)
{
if(mylist[i] > largetst)
largetst = numbers[i];
else if (mylist[i] < smallest)
smallest = numbers[i];
}
return largetst;
}
stats(int [] data)
{
if(data.count <= count)
{
if(myList.size() > 0)
System.arraycopy( myList, 0, data, 0, count );
}
}
stats()
{
Scanner s = new Scanner(System.in);
int count = s.nextInt();
s.nextLine(); // throw away the newline.
int [] numbers = new int[count];
Scanner numScanner = new Scanner(s.nextLine());
for (int i = 0; i < count; i++) {
if (numScanner.hasNextInt()) {
numbers[i] = numScanner.nextInt();
} else {
System.out.println(\"You didn\'t provide enough numbers\");
break;
}
}
System.arraycopy( myList, 0, numbers, 0, count );
}
stats(int size)
{
setValue(size);
}
private void setValue(int size)
{
count = size;
myList = new int[size];
}
} // end class StatCalc
public class SimpleStats {
public static void main(String[] args) {
Stat calc; // Computes stats for numbers entered by user.
calc = new Stat(100);
int arry[] = {20.20.40,30.80,,70,4,5,6,7,10}
calc.setvalue(array);
double item; // One number entered by the user.
TextIO.putln(\"Enter your numbers. Enter 0 to end.\");
TextIO.putln();
do {
TextIO.put(\"? \");
item = TextIO.getlnDouble();
if (item != 0)
calc.enter(item);
} while ( item != 0 );
TextIO.putln(\"\ Statistics about your calc:\ \");
TextIO.putln(\" Count: \" + calc.getCount());
TextIO.putln(\" Sum: \" + calc.getSum());
TextIO.putln(\" Minimum: \" + calc.getMin());
TextIO.putln(\" Maximum: \" + ca.
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More from naveenkumar29100
Question Completion Status QUESTION In the absence of oxygen, animal.pdf
Question Completion Status: QUESTION In the absence of oxygen, animal cells, through a
series of reactions, convert pyruvate to O lactic O CO2 and ethyl alcohol O carbon dioxide O
citric acid QUESTION 2 The prepatory reaction converts the pyruvate into for use in the citric
acid cycle) and (which leaves the cell O NADH: NAD O ATP: ADP O glucose; CO2 O acetyl-
CoA, carbon dioxide QUESTION 3 Energy released as electrons are transported down the
electron transport chain in cellular respiration is directly used to O oxygen O produce co2 O
produce NADH and FADH2 O establish a proton (H gradient OS
Solution
1.pyruvate is converted to CO2 and ethyl alcohol.
2.preparatory reaction convertpyruvate to acetyl coA and CO2
3.to produce oxygen.
4.glucose is ultimately converted to CO2.
5.cellular respiration requires glucose and CO2.
6.TCA, ETS take place in mitochondria.
7.purpose of dellular respiration to produce ATP.
8.ATP SYNTHASE PHOSPHORYLATES ADP TP ATP.
9.all organisms respire.
10.oxygen is not a product of respiration.
11.oxygen is the final electron acceptor.
12.glycolysis break glucose in 2 molecule pyruvate.
13.CO2 is produced in the preparatory reaction of citric acid cycle.
14.FADH2 and NADH carry electron .
15.in CYTRIC ACID CYCLE 34 molecule ATP produced from one glucose..
Short Answer 1. What are the 5 mechanisms of evolutionary ch.pdf
Short Answer: 1. What are the 5 mechanisms of evolutionary change that make up Modern
synthesis?
Solution
Answer = 1]
Five mechanisms of evolutionary change that make up modern synthesis are
1] Natural selection = is the process by which traits that enhance survival & reproduction
becomes more common in succesive generations of population
2] Biased mutation =When there are different probabilities occure at molecular level for different
mutations to occur known as biased mutation
3] Genetic drift = is the change in allele frequency from one generation to next that occure
because alleles are subjected to sampling error
drift acts faster & has more drastic effects in smaller populations
genetic drift contribute to speciation
4] Genetic hitchhiking =When one allele in particular haplotype is strongly beneficial natural
selection can drive a selective sweep that will also cause the other allales in haplotype to become
more common in population is called as genetic hitchhiking
5] Gene flow = Involves the exchange of genes between populations & species
gene flow between population can introduce traits & alleles.
Review Preparation for Statistics A statistics instructor wanted to s.pdf
Review Preparation for Statistics A statistics instructor wanted to see if student participation in
review preparation methods led to higher examination scores. Five students were randomly
selected and placed in each test group for a three-week unit on statistical inference. Everyone
took the same examination at the end of the unit, and the resulting scores are shown below Is
there sufficient evidence at 0.05 to conclude an interaction between the two factors? Is there
sufficient evidence to conclude a difference in mean scores based on formula delivery system? Is
there sufficient evidence to conclude a difference in mean scores based on the review
organization technique? (12-3)
Solution.
Problem 3-8BRIDGEPORT ADVERTISING TRIAL BALANCE DECEMBER 31, 2.pdf
Problem 3-8
BRIDGEPORT ADVERTISING
TRIAL BALANCE
DECEMBER 31, 2017
Unadjusted
Adjusted
Dr.
Cr.
Dr.
Cr.
$148,820
$148,820
$158,950
$158,950
No.
Date
Account Titles and Explanation
Debit
Credit
(To record accrued service revenue)
(To record supplies used)
(To expired insurance)
(To record depreciation on equiment)
(To record interest accrued on the note)
(To record service revenue earned)
(To record accrued wages)
Assets
Liabilities and Stockholders’ Equity
%
Open Show Work
SAVE FOR LATER
SUBMIT ANSWER
Problem 3-8 Bridgeport Advertising was founded by Murali Vedula in January 2015. Presented
below are both the adjusted and unadjusted trial balances as of December 31, 2017.
BRIDGEPORT ADVERTISING
TRIAL BALANCE
DECEMBER 31, 2017
Unadjusted
Adjusted
Dr.
Cr.
Dr.
Cr.Cash$16,740$16,740Accounts Receivable19,17023,012Supplies9,7606,845Prepaid
Insurance4,2202,625Equipment64,70064,700Accumulated Depreciation-
Equipment$24,120$29,050Notes Payable8,6008,600Accounts Payable1,8901,890Interest
Payable0602Unearned Service Revenue5,3503,405Salaries and Wages Payable0756Common
Stock19,22019,220Retained Earnings27,24727,247Dividends19,30019,300Service
Revenue62,39368,180Salaries and Wages Expense9,40010,156Insurance Expense1,595Interest
Expense602Depreciation Expense4,930Supplies Expense2,915Rent Expense5,5305,530
$148,820
$148,820
$158,950
$158,950Journalize the annual adjusting entries that were made. (Credit account titles are
automatically indented when amount is entered. Do not indent manually. If no entry is required,
select \"No entry\" for the account titles and enter 0 for the amounts.)
No.
Date
Account Titles and Explanation
Debit
Credit1.Dec. 31
(To record accrued service revenue)2.Dec. 31
(To record supplies used)3.Dec. 31
(To expired insurance)4.Dec. 31
(To record depreciation on equiment)5.Dec. 31
(To record interest accrued on the note)6.Dec. 31
(To record service revenue earned)7.Dec. 31
(To record accrued wages)Prepare an income statement for the year ended December 31. (Enter
loss using either a negative sign preceding the number e.g. -45 or parentheses e.g. (45).)
BRIDGEPORTADVERTISING
Income Statement
December 31, 2017For the Year Ended December 31, 2017For the Quarter Ended December
31, 2017
DividendsExpensesNet Income / (Loss)Retained Earnings, Janaury 1Retained Earnings,
December 31RevenuesTotal ExpensesTotal Revenues
$
DividendsExpensesNet Income / (Loss)Retained Earnings, Janaury 1Retained Earnings,
December 31RevenuesTotal ExpensesTotal Revenues
$
Dividends Expenses Net Income / (Loss) Retained Earnings, Janaury 1 Retained
Earnings, December 31 Revenues Total Expenses Total Revenues
DividendsExpensesNet Income / (Loss)Retained Earnings, Janaury 1Retained Earnings,
December 31RevenuesTotal ExpensesTotal Revenues$
Prepare a retained earnings statement for the year ended December 31. (List items that increase
retained earnings first.)
BRIDGEPORTADVERTISING
Retained Earnings Statement
December 31, 2017For the Year Ended December 31, 2017For .
Q1 Define the three types of data flow. Q2 What are the t.pdf
Q1: Define the three types of data flow.
Q2: What are the two principles of Protocol Layering?
Q3: A sine wave is offset 1/4 cycle with respect to time 0. What is its phase in degrees and
radians?
Q4: List three properties for Infrared waves.
Solution
: 4) Infrared (IR) waves are :
- electromagnetic in nature with longer wavelengths than visible light
- wavelength is from 0.74 micrometres (µm) to 300 µm.
- frequency range is from 1 to 400 THz
IR is thermal radiation emitted by objects near room temperature.
3) phase in degree :
1 complete cycle = 360 °
Then 1/4th cycle =1/4*360= 90°
Phase in radians :
1° =2/360 radians
Then 90° = 90*2/360 = /2 rad = 1.57 rad
1)
Simplex:All the data flow is unidirectional from transmitter to receiver.
Duplex communication is two way in that we have two types:
Half-duplex: communication may be likened to two way Either can may be used to transmit or
receive, but not at the same time
Fullduplex:Full-duplex communication is more like a true telephone, where two people can talk
at the same time and hear one another simultaneously.
1)
When communication is simple we may need only one protocol. When the communication is
Complex we need a protocol at each layer which is called protocol layering
We need to understand two simple principles for that
a) The first principle dictates that if we want
bidirectional communication, we need to make each
layer so that it is able to perform two opposite tasks,
one in each direction.
b) The second principle that we need to follow in
protocol layering is that the two objects under each
layer at both sides should be identical..
Multiple choice A young girl is staring at the raindrops running do.pdf
Multiple choice: A young girl is staring at the raindrops running down her window. She notices
that the raindrops remain more or less intact, even as they cascade down the windowpane. This is
a result of:
ionic bonds between water molecules.
oxygen bonds between water molecules.
covalent bonds between water molecules.
hydrogen bonds between water molecules.
polar covalent bonds between water molecules.
Solution
d). hydrogen bonds between water molecules.
Because of the hydrogen bonding, water exhibits high surface tension. So, water molecules on
the surface are more strongly attracted to each other than to the air above. So that the raindrops
remain more or less intact, even as they cascade down the windowpane..
mitosis is a special set of events that occur in what region of .pdf
mitosis is a special set of events that occur in what region of the cell?
mitosis is a special set of events that occur in what region of the cell?
mitosis is a special set of events that occur in what region of the cell?
Solution
Mitosis is found to occur in the cell nuclei of eukaryotic cells.
In the process of mitosis, one cell divides into two cells and these two cells will be genetically
identical to the original cell.
Our body will grow and repair itself due to the process of mitosis.
Mitosis includes five phases: prophase, prometaphase, metaphase, anaphase and telophase..
If you were looking at an mRNA and saw the codon AUG, what would you .pdf
If you were looking at an mRNA and saw the codon AUG, what would you conclude about it?
What does it mean to that the genetic code is redundant, but not ambiguous? The genetic code is
nearly universal, meaning the same RNA codon that designates tryptophan in humans, designates
tryptophan in bacteria. a. What has this knowledge allowed us to conclude about the code? b.
What has this knowledge allowed us to do with genes Transcription is the DNA-directed
synthesis of RNA: a closer look Describe the general model of transcription. Include in your
answer the steps of transcription and the key elements of each step. Compare and contrast
transcription between prokaryotes and eukaryotes What makes RNA polymerase start
transcribing in a gene at the right place on the DNA of a prokaryotic cell? What makes RNA
polymerase start transcribing in a gene at the right place on the DNA of a eukaryotic cell?
Solution
A)Transcription is the first step in gene expression. It involves copying a gene\'s DNA sequence
to make an RNA molecule.Transcription can be divided into four distinct stages:
Template recognition
Initiation
Elongation
Termination
Initiation:RNA polymerase binds to a sequence of DNA called the promoter,found near the
beginning of a gene.Each gene has its own promoter.Once bound,RNA polymerase separates the
DNA strands,providing the single-stranded template needed for transcription.
Elongation:One strand of DNA,the template strand,acts as a template for RNA polymerase.As it
reads this template one base at a time,the polymerase builds an RNA molecule out of
complementary nucleotides,making a chain that grows from 5\' to 3\'.The RNA transcript carries
the same information as the non-template (coding) strand of DNA,but it contains the base uracil
instead of thymine .
Termination:Sequences called terminators signal that the RNA transcript is complete.Once they
are transcribed,they cause the transcript to be released from the RNA polymerase.
B)Prokaryotes do not have an organized nucleus,so the nuclear materials or DNA is in the
cytoplasm.Therefore,the transcription occurs in the cytoplasm and all the precursors needed for
the transcription are found in the cytoplasm.Prokaryotic transcription requires the RNA
polymerase enzyme in order for the transcription to be successfully completed.The enzyme binds
to the sigma factor and the promoter region,and then initiate the transcription by completing the
holoenzyme.In prokaryotes,DNA is not bound to histones.Thus,the transcription initiates
directly.This could be advantageous when prokaryotes have overlapping genes.Transcription
starts at the promoter region and elongate through the coding region and ends when the RNA
polymerase reads the termination signal.There are two types of termination signals,Rho-
dependent and independant.Transcribed mRNA will be completely translated during the
transcription,and no post-transcription processing will be undergoing most of the
time.Transcriptionl unit has one or more .
If the proportion of an African population that is susceptible to Ma.pdf
If the proportion of an African population that is susceptible to Malaria is 0.49, what proportion
of the population is affected with Sickle Cell Anemia? A. 0.68. B. 0.09. C. 0.45. D. 0.34.
Solution
B 0.09
In literature it was mentioned that 40% of popullation in africa suffering from malaria are
sucessiptible to sickel cell anemia..
Identify nursing diagnoses goal and outcome criteria and interven.pdf
Identify nursing diagnoses goal and outcome criteria and interventions for the postoperative
patient
Identify nursing diagnoses goal and outcome criteria and interventions for the postoperative
patient
Solution
ASSESSMENT: - After the surgery, when the operation procedure is completed, the patient is
usually shifted to intensive care unit. When patient is admitted to PACU determine the medical
diagnosis, the surgery procedure, pain, consciousness, vital signs, medical history, how patient
tolerated the procedure? what was the medication given, and other assessment data listed earlier.
Check and set up equipment like oxygen, suction devices, urinary drainage etc. A more detailed
assessment should be performed when a patient returns to the nursing unit. It is actually
collecting, organizing, validating, and documenting patient data and its purpose is to establish a
database about the patient’s response to health concerns or illness and the ability to manage
health care needs.
DIAGNOSIS: - Medical diagnoses are important factors influencing patient outcomes during
hospitalization. For example, ICU patients with infectious diseases at admission had higher
mortality than the patients with gastrointestinal diseases. After surgery patients are at an
increased risk of severe complication. Nursing diagnosis is the nurse’s clinical judgment about
the patient’s response to potential health conditions and comorbid medical conditions. Several
studies show that these diagnosis influence 31 different types of patient outcomes (e.g. hospital
mortality, the length of stay, and ICU readmission) and interventions. A standard nursing
diagnosis includes three structural components: the problem, the etiology and supporting data. Its
purpose is to identify patient’s strengths and health problems that can be prevented or resolved
by collaborative and independent nursing interventions. and to develop a list of nursing
diagnoses and collaborative problems.
GOAL AND OUTCOME: - The goal is aimed at the medical diagnosis. The outcomes are aimed
at meeting the goals. A patient goal represents a predicted resolution of a diagnosis, evidence of
progress toward resolution, progress toward improved health, or continued maintenance of good
health. Each goal is limited to a time so the health care team has a common time limit for solving
the problem. For example, the goal of “patient will achieve pain relief. A short-term goal is an
objective behavior or response that you expect a patient to achieve in a short time, usually in a
week. A long-term goal is an objective behavior or response that you expect a patient to achieve
over a longer period, usually over several weeks, or even several months (for example “Patient
will leave nicotine products within two months”). Determine how to prevent, reduce, or resolve
the identified patient problems; how to support patient strengths; and how to implement nursing
interventions in a well organized, individualized, and goal-directed way, .
How would you arrange these concepts in terms of concreteness (from .pdf
How would you arrange these concepts in terms of concreteness (from most to least concrete)?
Justify your arrangement.
Asset
Common stock
Equity
Investment
Security
Stock
Solution
Below is the arrangement of concepts in terms of concreteness (most to least):
1. Stock 2. Common Stock 3. Security 4. Investment 5. Asset 6. Equity
Justification : As per my understanding, I have arranged all concepts based on how easily can we
do the valuation and the scope of a particular concept.
Stock is a current asset i.e. the valuation of stock can be done on an yearly basis. Since, it is short
term in nature and can be valued at cost using methods like FIFO, LIFO, etc. Cost is easily
available by looking at the invoices, purchase orders, etc.
Common Stock is a long term liability also called as equity shares. They can be valued using
different techniques like Dividend Discount model. Stock prices are easily available in the
exchange markets.
Securities comes next as they are wider than Common stock. They are the tradeable financial
instruments. They are divided into three parts - equity securities, debt securities and derivatives.
We can value securities from the market which is determined by the demand and supply forces.
Investments includes short term and long term investments. They are valued at the lesser of cost
or fair market value. The market value of investemnts can not be seen on stock exchanges and
hence lesser concrete than securities.
Assets includes both short term and long term assets. Fixed assets like Long term investments,
building, factory, machinery and current assets like Stock, short term investments, account
receivables, cash are included in the broad defination of assets. Hence, investments are a subset
of assets and hence more concrete than assets. Again, there is no trade market for assets to do the
asset valuation.
Equity is difference between assets and liabilities. Equity is a wider term which includes
common stock, preffered stock, retained earnings (calculated from Income statement), security
premium, revaluation reserves (calculated as the difference between the fair market value and
book value of assets). Hence, they can be regarded as least concrete of the given list..
For 12 pages randomly selected from War and Peace by Leo Tolstoy, th.pdf
For 12 pages randomly selected from War and Peace by Leo Tolstoy, the data set lists the mean
number of words per sentence, the mean number of characters per word.
Words/sentence
Characters/word
20.6
4.3
28.0
4.5
12.0
4.5
11.5
4.5
17.4
4.5
19.7
4.8
20.3
4.3
17.8
4.2
22.1
4.7
31.4
4.3
18.3
4.4
11.7
4.5
1. ( 15 points) Prepare a frequency distribution of words/sentence with a class width of 3 words
and another with class width of 4 words.
Words/sentence
Characters/word
20.6
4.3
28.0
4.5
12.0
4.5
11.5
4.5
17.4
4.5
19.7
4.8
20.3
4.3
17.8
4.2
22.1
4.7
31.4
4.3
18.3
4.4
11.7
4.5
Solution
Words/sentence
cumulative
midpoint
width
frequency
percent
frequency
percent
11.5-14.4
13.0
3.0
3
25.0
3
25.0
14.5-17.4
16.0
3.0
1
8.3
4
33.3
17.5-20.4
19.0
3.0
4
33.3
8
66.7
20.5-23.4
22.0
3.0
2
16.7
10
83.3
23.5-26.4
25.0
3.0
0
0.0
10
83.3
26.5-29.4
28.0
3.0
1
8.3
11
91.7
29.5-32.4
31.0
3.0
1
8.3
12
100.0
12
100.0
Words/sentence
cumulative
midpoint
width
frequency
percent
frequency
percent
11.5-15.4
13.5
4.0
3
25.0
3
25.0
15.5-19.4
17.5
4.0
3
25.0
6
50.0
19.5-23.4
21.5
4.0
4
33.3
10
83.3
23.5-27.4
25.5
4.0
0
0.0
10
83.3
27.5-31.4
29.5
4.0
2
16.7
12
100.0
12
100.0
Words/sentence
cumulative
midpoint
width
frequency
percent
frequency
percent
11.5-14.4
13.0
3.0
3
25.0
3
25.0
14.5-17.4
16.0
3.0
1
8.3
4
33.3
17.5-20.4
19.0
3.0
4
33.3
8
66.7
20.5-23.4
22.0
3.0
2
16.7
10
83.3
23.5-26.4
25.0
3.0
0
0.0
10
83.3
26.5-29.4
28.0
3.0
1
8.3
11
91.7
29.5-32.4
31.0
3.0
1
8.3
12
100.0
12
100.0.
Explain what an enumerated type isSolutionEnum is also called.pdf
Explain what an enumerated type is?
Solution
Enum is also called enumerated Data type
Enum is a user defined data type
Syntax: of enumerated data type
Enum is a data type which contains fixed set of constants
identifier is a user defined datatype variable name
val1,val2,val3.....valn is a set of enum values
enum is just used for generation index values.
index starts from 0 to n
example
solution.cpp
#include//header for input output function
using namespace std;//it tells the compiler to link std namespace
int main()
{//main function
int i;
enum season {winter,summer,spring,fall};//enum data type
for(i=winter;i<=fall;i++)//for loop
cout<.
Explain how the three germ layers participate in the formation of ext.pdf
Explain how the three germ layers participate in the formation of extraembryonic membranes,
and discuss the importance of the placenta as an endocrine organ.
Solution
The three germ layers are not only responsible for the differentiation of specialized tissue rather
are also responsible for the formation of the extraembryonic membrane, that protects and
nourishes the embryo. The three extraembryonic membranes are formed from the primitive germ
layers:
The yolk sac is the membrane that forms from the endoderm and splanchnic mesoderm that
grows from the area opaca to form the sac. the yolk sac surrounds the yolk and draws the. the
endodermal gets more specialized and digest the yolk and pass its nutrients to the vitelline
circulation and thus to the membrane.
The amnion is formed from the ectoderm and somatic mesoderm that surrounds the embryo,
forming a protective cover for the embryo. the inner layer of the main secretes amniotic fluid in
which the embryo floats and prevents it from drying.
The chorion-allantoic membrane in which the chorion is made from the ectoderm and somatic
mesoderm while the allantoic membrane is formed from the endoderm and splanchnic
mesoderm. the allantoic membrane works with the chorion to exchange gasses between the
embryo and the outside environment. The allantois also stores the wastes of the embryo.
The placenta is considered as an endocrine gland present temporarily during pregnancy. the
placenta is responsible for the production of hormones that are responsible for the healthy
pregnancy. It secretes placental lactogen, placental growth relaxin as these hormones are
important for the healthy propagation of the pregnancy..
Ethical issue What would you doTony, a data analyst for a major c.pdf
Ethical issue: What would you do
Tony, a data analyst for a major casino, is working after normal business hours to finish an
important project. He realizes that he is missing data that had been sent to his coworker Robert.
Tony had inadvertently observed Robert typing his password several days ago and decides to log
into Robert\'s computer and resend the data to himself. Upon doing so, Tony sees an open email
regarding gambling bets Robert placed over the last several days with a local sports book. All
employees of the casino are forbidden to engage in gambling activities to avoid any hint of
conflict of interest.
Tony knows he should report this but would have to admit to violating the company\'s
information technology regulations by logging into Robert\'s computer. If he warns Robert to
stop his betting, he would also have to reveal the source of his information. What does Tony do
in this situation?
Solution
In this situation, Tony should warn Robert to stop his betting. He should clearly specify Robert
that he has accidently seen his password few days back. Due to the urgency of data, he logged
onto his computer and seen the mails. He should apologize for his mistake for logging into his
account without his permission. However, at the same time he should warn Robert that if he
found his further involvement in gambling activities through any source, then he would report it
to the management..
Compare and contrast the structure of a nephron with that of an alve.pdf
Compare and contrast the structure of a nephron with that of an alveolus in the lung. Identify
TWO (2) similarities and TWO (2) differences. (2 marks)
Solution
DIFFERENCES:1=Each alveolas is a very small bag_like structure bearing a component known
as Surfactant while as each nephron is a curled tube_like arrangement with a cup_shaped
structure called Bowman\'s capsule.2=Alveoli are present inside the lungs while as nephrons are
lying in kidneys. SIMILARITIES:1=Both Alveoli and nephrons are present in larger quantity in
their respective organs.2=Both the structures act as functional units..
Classless addressing was introduced to extend the life of the IPv ad.pdf
Classless addressing was introduced to extend the life of the IPv address scheme:
a. True b. False
Solution
True.
Explanation:
IP addresses are described as consisting of two groups of bits in the address: the most significant
bits are the network address (or network prefix or network block), which identifies a whole
network or subnet, and the least significant set forms the host identifier, which specifies a
particular interface of a host on that network. This division is used as the basis of traffic routing
between IP networks and for address allocation policies. Classful network design for IPv4 sized
the network address as one or more 8-bit groups, resulting in the blocks of Class A, B, or C
addresses. Classless Inter-Domain Routing allocates address space to Internet service providers
and end users on any address bit boundary, instead of on 8-bit segments. In IPv6, however, the
interface identifier has a fixed size of 64 bits by convention, and smaller subnets are never
allocated to end users..
C++ Complexity analysis Represent the time complexity of the follow.pdf
C++ Complexity analysis: Represent the time complexity of the following recursive algorithm,
T(n), as a recurrence equation:
int pow_7( int n ){
if ( n==1)
return 7;
if ( n > 1)
return ( 7 * pow_7( n-1 ) );
}
Solution
T(n) = T(n-1) + 1
T(n) = T(n-2)+2
suppose after k iteration
T(n) = T(n-k)+k
then T(n) = T(n-k-1)+k+1....T(n) = T(n-(k+1))+(k+1)
=> true for k+1 also.
T(n) = O(n).
Can someone provide a solution for this assignmentPurpose of This.pdf
Can someone provide a solution for this assignment?
Purpose of This Assignment
The purpose of this assignment is to develop your abilities to write a larger application involving
arrays, structures and linked lists. It also introduces switchable tracing.
Graphs and Terminology
This assignment uses weighted graphs, as described in assignment 4. Be sure that you are
familiar with weighted graphs.
Two vertices are said to be adjacent if there is an edge that connects them directly to one another.
A given edge is incident on each of the vertices that it connects.
Think of the vertices of a weighted graph as towns and the edges as roads. The weight of an edge
is the length of the road. One thing that you might like to know is how to get from one town to
another by the shortest possible route. For example, in the following weighted graph, the shortest
route from vertex 1 to vertex 5 is to go from 1 to 3 and then from 3 to 5, and the length of that
route is 27. You add the weights of the edges that you use.
For this assignment, the weights are real numbers (type double). All of the weights are required
to be nonnegative. Edges of weight 0 are allowed.
Assignment Requirements
Functional Requirements
Write a program that reads information about a weighted graph from the standard input. The
input format is described in detail below. After the description of the graph, the input has two
vertex numbers, s and t.
Your program should print a description of the graph, followed by the shortest path from s to t
and the distance from s to t via that path, on the standard output.
For example, the input might look like this.
That says that there are five vertices. There is an edge from vertex 1 to vertex 2 with weight 9.0,
an edge from vertex 1 to vertex 3 with weight 12.0, etc. The start vertex s is 1, and the end vertex
t is 5. The output for this input would be as follows.
Nonfunctional Requirements
Create a directory to hold assignment 6 and call your program dijkstra.cpp. Start with the
standard template.
Below is a description of an algorithm, based on Dijkstra\'s algorithm, for solving this problem.
You are required to use that algorithm, and to follow the guidelines for its implementation. It is
not acceptable to rely on a different approach to the problem. Follow the design.
Make variable and function names sensible. Use sensible terminology. If something is a graph,
do not call it an edge. If something is an edge, do not call it a vertex. Keep functions short and
simple.
As always, you must follow the coding standards for this course.
Representing Graphs: Types Vertex, Edge and Graph
This assignment uses a different graph representation from assignment 4. Here, we use the
adjacency list representation.
1. Type Vertex
Create and document type Vertex. Each vertex v has the following pieces of information.
A pointer to a linked list of edges listing all edges that are incident on v. This list is called an
adjacency list.
A real number indicating v\'s shor.
Before first law of thermodynamics, there is zeroth law of thermodyn.pdf
Before first law of thermodynamics, there is zeroth law of thermodynamics. The thermometer
works on the principle of zeroth law of thermodynamics. Can you explain what is a zeroth law of
thermodynamics?
Solution
Zeroth law states that Objects into contact will reach a thermal equilibrium (and heat transfers
from hotter to colder), this means one can use a device that can measure this difference of this
quantity as follows:
We have a device (called a thermometer) which has an indication. When the \"thermometer
device\" comes into contact with another object, 0th law states that they wil reach thermal
equilibrium . Then the indication of the device will change to reflect the difference of this
quantity that changed or transfered and refered to as temperature .
One such device is the thermometer based on mercury (which is used as the indicator due to its
special heat expansion factor)..
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Write a Java program in which a method named digitSum that accepts a.pdf
- 1. Write a Java program in which a method named digitSum that accepts an integer as a parameter and returns the sum of the digits of that number. For example, the call digitSum(29107) returns 2+9+1+0+7 or 19. For negative numbers, return the same value that would result if the number were positive. For example, digitSum(-456) returns 4+5+6 or 15.The call digitSum(0) returns 0 Solution DigitSumTest.java import java.util.Scanner; public class DigitSumTest { public static void main(String[] args) { Scanner scan = new Scanner(System.in); System.out.print("Enter an integer: "); int n = scan.nextInt(); int sum = digitSum(n); System.out.println("The sum of digits is "+sum); } public static int digitSum (int n) { int sum = 0; if(n == 0){ return 0; } else if(n < 0){ n = -n; } do { sum += n % 10; } while ((n = n / 10) != 0); return sum; } }
- 2. Output: Enter an integer: -456 The sum of digits is 15 Enter an integer: 29107 The sum of digits is 19