Which statement is true of serous membranesA) They line closed cavi.pdf
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Which statement is true of serous membranes?A) They line closed cavities such as the pleural, peritoneal, and pericardial cavities.B) They are dry and form the epithelia of the skin.C) They cover small areas within the body.D) Their openings are made of stratified squamous epithelial tissue.E) They secrete mucus. Solution A,C and E statements are correct. They are not dry and will not form epithelia of skin. They secrete mucous like substance. They are not made of compound epithelium.they are made of simple epithelium..
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Explain what differential cell affinity is, how this process is acco.pdf
Explain what differential cell affinity is, how this process is accomplished and why it is
important for morphogenesis.
Solution
Morphogenesis is a process through which the organism develops its shape. The spatial
distribution of organs and cells that belong to a specific group is controlled by this process.
During the stage of embryonic development, the cells are restricted to particular layers
(differential affinity) because all of them are joined by the same adhesion molecules. This
homotypic cell adhesion keeps all the cells of similar type intact and form boundaries with the
cells with different type of adhesion molecules, thus maintaining the organ’s or tissue’s shape..
Explain in detail how OFDM helps mitigates multipath fading effects..pdf
Explain in detail how OFDM helps mitigates multipath fading effects.
Thank you! As detailed as possible!
Solution
Multipath fading is a feature that needs to be taken into account when designing or developing a
radio communications system. In any terrestrial radio communications system, the signal will
reach the receiver not only via the direct path, but also as a result of reflections from objects such
as buildings, hills, ground, water, etc that are adjacent to the main path.The overall signal at the
radio receiver is a summation of the variety of signals being received. As they all have different
path lengths, the signals will add and subtract from the total dependent upon their relative
phases.
At times there will be changes in the relative path lengths. This could result from either the radio
transmitter or receiver moving, or any of the objects that provides a reflective surface moving.
This will result in the phases of the signals arriving at the receiver changing, and in turn this will
result in the signal strength varying as a result of the different way in which the signals will sum
together. It is this that causes the fading that is present on many signals.
Multipath fading can affect radio communications channels in two main ways. This can give the
way in which the effects of the multipath fading are mitigated..
Entamoeba histolytica is an amoeba responsible for the gastrointestin.pdf
Entamoeba histolytica is an amoeba responsible for the gastrointestinal disease amebic
dysentery. While E. histolytica is found in the environment as both an active trophozoite and as
an inactive cyst, virtually all cases of amebic dysentery can be traced to infection with the cyst
form of the organism. Speculate on why the active form of the pathogen causes far fewer cases
of disease.
Solution
Mature cysts are more resistant to atmosphere as well as for antibiotics and Immune system than
mature organism, upon ingestion of active form of organism which gets killed while if mature
cyst enters the human body it remains as it is and later it develops to an active organism which
can cause actual disease..
Describe briefly each mouth part of the grasshopper. b. Describe how.pdf
Describe briefly each mouth part of the grasshopper. b. Describe how each of the following
mouth parts of the moth, flesh fly. and mosquito have been modified in comparison to the
grasshopper. Vocabulary used in drawings: lbr = labrum lbm = labium md = mandible mx =
maxillae hyp = hypopharyn p = palp: mxp = maxillary palp lbp = labial palp fc = food
channel sc = salivary channel clp = lower part of the head capsule (not a mouth part) Parts of
labium: bk, hst, lbl
Solution
Answer:
2a)Mouthparts of grass hoper:
1)Mandibles:A grasshoper has a pair of mandibles on each side of head. the mandibles are the
largest and most robust mouthparts of a chewing insect, and it uses them to cut, tear, crush, chew
food items. Two sets of muscles move the mandibles in the coronal plane abductor muscles
move insects mandibles apart adductor muscles bring them together . This they do mainly in
opening and closing their jaws in feeding, but also useful the mandibles as tools, or possibly help
in fighting .The mandibles are caudal to the labrum and anterior to the maxillae.
2)LABRUM: A simple plate-like sclerite that serves as a front lip to help contain the food.it is
broad ,roughly rectangular shaped.
3)MAXILLAE:—pair of structures lying outside and behind the mandibles. Each of them consist
of 5-segmented sensory maxillary palp in addition to other parts. The maxillae are used to
manipulate the food before it enters the mouth. paired appendages with the following parts:
Forms the broad median lower lip consisting of several parts in addition to a pair of 3-segmented
labial palps on either side.
The mandibles and the maxillae grind the food by moving it laterally.
5)HYPOPHARYNX: a tongue-like process that helps mix food and saliva.it is found attached to
the labrum.The hypopharynx is a somewhat globular structure, located medially to the mandibles
and the maxillae. it is membranous and associated with salivary glands. It assists in swallowing
the food.....
Contrast the views of Piaget and Bandura on how children develop..pdf
Contrast the views of Piaget and Bandura on how children develop.
Solution
Piaget\'s theory of child - cognitive development:
According to Piaget, cognitive reversibility is a tangible operation state in which children
initially habituate and gain knowledge to understand the things how it works and alter they gain
knowledge to return to their original state.
Paiget illustrated children’s cognitive development in four stages
They are 1. Sensory motor stage
2. Pre-operational stage (2 to7 years of old)
3. Concrete operational (children of 7 to 11 years old)
4. Formal operations (11 to 16 years adolescence stage)
Preoperational stage defined as the stage at which children mainly habituate and gain knowledge
to speak at the age of 2 to 7 years. In this stage child develops to use symbols initially and finally
form enduring and manipulating symbols. In this stage, children do not develop logical thinking
or reasoning. In concrete operational stage, children often develop logical thinking and efficient
cognitive abilities.
Preoperational stage includes the following stages of features such as a. animism; b. artificialism
c. transductive reasoning.
According Piaget conservation has illustrated as the process in which children at the age of 2 to
seven are unable to think logically. But their logical thinking starts at the age of seven to eleven
years. The formal operational stage starts after 11 years in which children often learn about
mathematical models and apply them to solve a variety of problems.
According to Bandura, children learning perspective is mainly associated with anticipated
outcomes based on observational learning where environmental cues has specific impact on
them.
Behavioral cognitive theory: According to Bandura, behavior is resultant response due to
complex interplay between environmental cues & inner processes in any species finally attain
empirical validity.
As per cognitive theories behavioral concern always involves a variety of environmental
stimulus and concerned response, it could be voluntary response or reflexive response. These
responses are associated with cues. This behavior is mainly based on external rewards through
cortico-striatal pathway..
Compute the probability of event E if the odds in favor of E are 31.pdf
Compute the probability of event E if the odds in favor of E are 3/19 14/27 6/11 11/7 P(E) =
(Type the probability as a fraction. Simplify your answer)
Solution
(A) Given odds in the favour of event E are 3/19
Therefore, probability = 3/(3+19) = 3/22
(B) Given odds in favour of event E are 14/27. Therefore,
probability = 14/(14+27) = 14/41
(c) Given odds in favour of event E are 6/11. Therefore,
probability = 6/(6+11) = 6/17
(d) Given odds in favour of event E are 11/7. Therefore,
probability =11/(11+7) = 11/18.
Compare and contrast the world population with that of the United St.pdf
Compare and contrast the world population with that of the United States. Is the United States
becoming a larger or a smaller part of the world\'s population?
Solution
According to the results of the 2015 Revision, the world population reached 7.3 billion as of
mid-
2015 (table 1), implying that the world has added approximately one billion people in the span
of the last
twelve years. Sixty per cent of the global population lives in Asia (4.4 billion), 16 per cent in
Africa (1.2
billion), 10 per cent in Europe (738 million), 9 per cent in Latin America and the Caribbean (634
million),
and the remaining 5 per cent in Northern America (358 million) and Oceania (39 million). China
(1.4
billion) and India (1.3 billion) remain the two largest countries of the world, both with more
than 1 billion
people, representing 19 and 18 per cent of the world’s population, respectively.
It is becoming larger part of worlds population.
In 2013 its was 4.42% of worlds population..
8. What protocol is are layers 6 and 7 of the OSI model based on.pdf
8. What protocol is are layers 6 and 7 of the OSI model based on?
1. TCP/IP
2. IPsec
3. FTP
4. PPTP
9. Which network services provides the mapping and translation of domain names to IP
addresses?
1. HTTP
2. DHCP
3. DNS
4. FTP
10. With a proxy server enabled on a firewall, the firewall stores web pages where?
1. Local usb drive
2. RAM
3. Local hard drive
4. FTP server
11 The ________ provides definitions for seen layers, which each layer provides services that
depend on higher level layers depend on.
2. TCP
3. FTP
4. OSI
5. DNS
12. Which of the ways listed below can firewall security be completely bypassed? (Multiple
answers)
1. HTTP sites are never secure
2. E-mail is never secure
3. A computer not owned by the enterprise should never be connected to the enterprise
4. Files from home computers and files from office computers should never commingle.
Solution
Osi model 6 and 7 layer consist of FTP as the 7 th layer is application layer.This layer is used to
access network services.
It is useful for remote file sharing.
remote printer access etc..
Recommended
Explain what differential cell affinity is, how this process is acco.pdf
Explain what differential cell affinity is, how this process is accomplished and why it is
important for morphogenesis.
Solution
Morphogenesis is a process through which the organism develops its shape. The spatial
distribution of organs and cells that belong to a specific group is controlled by this process.
During the stage of embryonic development, the cells are restricted to particular layers
(differential affinity) because all of them are joined by the same adhesion molecules. This
homotypic cell adhesion keeps all the cells of similar type intact and form boundaries with the
cells with different type of adhesion molecules, thus maintaining the organ’s or tissue’s shape..
Explain in detail how OFDM helps mitigates multipath fading effects..pdf
Explain in detail how OFDM helps mitigates multipath fading effects.
Thank you! As detailed as possible!
Solution
Multipath fading is a feature that needs to be taken into account when designing or developing a
radio communications system. In any terrestrial radio communications system, the signal will
reach the receiver not only via the direct path, but also as a result of reflections from objects such
as buildings, hills, ground, water, etc that are adjacent to the main path.The overall signal at the
radio receiver is a summation of the variety of signals being received. As they all have different
path lengths, the signals will add and subtract from the total dependent upon their relative
phases.
At times there will be changes in the relative path lengths. This could result from either the radio
transmitter or receiver moving, or any of the objects that provides a reflective surface moving.
This will result in the phases of the signals arriving at the receiver changing, and in turn this will
result in the signal strength varying as a result of the different way in which the signals will sum
together. It is this that causes the fading that is present on many signals.
Multipath fading can affect radio communications channels in two main ways. This can give the
way in which the effects of the multipath fading are mitigated..
Entamoeba histolytica is an amoeba responsible for the gastrointestin.pdf
Entamoeba histolytica is an amoeba responsible for the gastrointestinal disease amebic
dysentery. While E. histolytica is found in the environment as both an active trophozoite and as
an inactive cyst, virtually all cases of amebic dysentery can be traced to infection with the cyst
form of the organism. Speculate on why the active form of the pathogen causes far fewer cases
of disease.
Solution
Mature cysts are more resistant to atmosphere as well as for antibiotics and Immune system than
mature organism, upon ingestion of active form of organism which gets killed while if mature
cyst enters the human body it remains as it is and later it develops to an active organism which
can cause actual disease..
Describe briefly each mouth part of the grasshopper. b. Describe how.pdf
Describe briefly each mouth part of the grasshopper. b. Describe how each of the following
mouth parts of the moth, flesh fly. and mosquito have been modified in comparison to the
grasshopper. Vocabulary used in drawings: lbr = labrum lbm = labium md = mandible mx =
maxillae hyp = hypopharyn p = palp: mxp = maxillary palp lbp = labial palp fc = food
channel sc = salivary channel clp = lower part of the head capsule (not a mouth part) Parts of
labium: bk, hst, lbl
Solution
Answer:
2a)Mouthparts of grass hoper:
1)Mandibles:A grasshoper has a pair of mandibles on each side of head. the mandibles are the
largest and most robust mouthparts of a chewing insect, and it uses them to cut, tear, crush, chew
food items. Two sets of muscles move the mandibles in the coronal plane abductor muscles
move insects mandibles apart adductor muscles bring them together . This they do mainly in
opening and closing their jaws in feeding, but also useful the mandibles as tools, or possibly help
in fighting .The mandibles are caudal to the labrum and anterior to the maxillae.
2)LABRUM: A simple plate-like sclerite that serves as a front lip to help contain the food.it is
broad ,roughly rectangular shaped.
3)MAXILLAE:—pair of structures lying outside and behind the mandibles. Each of them consist
of 5-segmented sensory maxillary palp in addition to other parts. The maxillae are used to
manipulate the food before it enters the mouth. paired appendages with the following parts:
Forms the broad median lower lip consisting of several parts in addition to a pair of 3-segmented
labial palps on either side.
The mandibles and the maxillae grind the food by moving it laterally.
5)HYPOPHARYNX: a tongue-like process that helps mix food and saliva.it is found attached to
the labrum.The hypopharynx is a somewhat globular structure, located medially to the mandibles
and the maxillae. it is membranous and associated with salivary glands. It assists in swallowing
the food.....
Contrast the views of Piaget and Bandura on how children develop..pdf
Contrast the views of Piaget and Bandura on how children develop.
Solution
Piaget\'s theory of child - cognitive development:
According to Piaget, cognitive reversibility is a tangible operation state in which children
initially habituate and gain knowledge to understand the things how it works and alter they gain
knowledge to return to their original state.
Paiget illustrated children’s cognitive development in four stages
They are 1. Sensory motor stage
2. Pre-operational stage (2 to7 years of old)
3. Concrete operational (children of 7 to 11 years old)
4. Formal operations (11 to 16 years adolescence stage)
Preoperational stage defined as the stage at which children mainly habituate and gain knowledge
to speak at the age of 2 to 7 years. In this stage child develops to use symbols initially and finally
form enduring and manipulating symbols. In this stage, children do not develop logical thinking
or reasoning. In concrete operational stage, children often develop logical thinking and efficient
cognitive abilities.
Preoperational stage includes the following stages of features such as a. animism; b. artificialism
c. transductive reasoning.
According Piaget conservation has illustrated as the process in which children at the age of 2 to
seven are unable to think logically. But their logical thinking starts at the age of seven to eleven
years. The formal operational stage starts after 11 years in which children often learn about
mathematical models and apply them to solve a variety of problems.
According to Bandura, children learning perspective is mainly associated with anticipated
outcomes based on observational learning where environmental cues has specific impact on
them.
Behavioral cognitive theory: According to Bandura, behavior is resultant response due to
complex interplay between environmental cues & inner processes in any species finally attain
empirical validity.
As per cognitive theories behavioral concern always involves a variety of environmental
stimulus and concerned response, it could be voluntary response or reflexive response. These
responses are associated with cues. This behavior is mainly based on external rewards through
cortico-striatal pathway..
Compute the probability of event E if the odds in favor of E are 31.pdf
Compute the probability of event E if the odds in favor of E are 3/19 14/27 6/11 11/7 P(E) =
(Type the probability as a fraction. Simplify your answer)
Solution
(A) Given odds in the favour of event E are 3/19
Therefore, probability = 3/(3+19) = 3/22
(B) Given odds in favour of event E are 14/27. Therefore,
probability = 14/(14+27) = 14/41
(c) Given odds in favour of event E are 6/11. Therefore,
probability = 6/(6+11) = 6/17
(d) Given odds in favour of event E are 11/7. Therefore,
probability =11/(11+7) = 11/18.
Compare and contrast the world population with that of the United St.pdf
Compare and contrast the world population with that of the United States. Is the United States
becoming a larger or a smaller part of the world\'s population?
Solution
According to the results of the 2015 Revision, the world population reached 7.3 billion as of
mid-
2015 (table 1), implying that the world has added approximately one billion people in the span
of the last
twelve years. Sixty per cent of the global population lives in Asia (4.4 billion), 16 per cent in
Africa (1.2
billion), 10 per cent in Europe (738 million), 9 per cent in Latin America and the Caribbean (634
million),
and the remaining 5 per cent in Northern America (358 million) and Oceania (39 million). China
(1.4
billion) and India (1.3 billion) remain the two largest countries of the world, both with more
than 1 billion
people, representing 19 and 18 per cent of the world’s population, respectively.
It is becoming larger part of worlds population.
In 2013 its was 4.42% of worlds population..
8. What protocol is are layers 6 and 7 of the OSI model based on.pdf
8. What protocol is are layers 6 and 7 of the OSI model based on?
1. TCP/IP
2. IPsec
3. FTP
4. PPTP
9. Which network services provides the mapping and translation of domain names to IP
addresses?
1. HTTP
2. DHCP
3. DNS
4. FTP
10. With a proxy server enabled on a firewall, the firewall stores web pages where?
1. Local usb drive
2. RAM
3. Local hard drive
4. FTP server
11 The ________ provides definitions for seen layers, which each layer provides services that
depend on higher level layers depend on.
2. TCP
3. FTP
4. OSI
5. DNS
12. Which of the ways listed below can firewall security be completely bypassed? (Multiple
answers)
1. HTTP sites are never secure
2. E-mail is never secure
3. A computer not owned by the enterprise should never be connected to the enterprise
4. Files from home computers and files from office computers should never commingle.
Solution
Osi model 6 and 7 layer consist of FTP as the 7 th layer is application layer.This layer is used to
access network services.
It is useful for remote file sharing.
remote printer access etc..
Which of the following is not included in the calculation of the VIX .pdf
Which of the following is not included in the calculation of the VIX cross-asset rank? O
Treasury bond volatility Gold volatility High yield corporate bond volatility EUR volatility
Solution
which of the following is not involed in VIX Cross asset rank
Answer:high yeild coporate bond volatility.
What is an Accountable Care Organizations (ACO) How does an ACOs .pdf
What is an Accountable Care Organizations (ACO)? How does an ACO\'s economics work to
manage costs and quality?
Solution
Accountable Care Organizations (ACOs) are groups of doctors, hospitals, and other health care
providers, who come together voluntarily to give coordinated high quality care to their Medicare
patients.
An accountable care organization (ACO) is a healthcare organization characterized by a payment
and care delivery model that seeks to tie provider reimbursements to quality metrics and
reductions in the total cost of care for an assigned population of patients. A group of coordinated
health care providers forms an ACO, which then provides care to a group of patients. The ACO
may use a range of payment models (capitation, fee-for-service with asymmetric or symmetric
shared savings, etc.). The ACO is accountable to the patients and the third-party payer for the
quality, appropriateness and efficiency of the health care provided. According to the Centers for
Medicare and Medicaid Services (CMS), an ACO is \"an organization of health care providers
that agrees to be accountable for the quality, cost, and overall care of Medicare beneficiaries who
are enrolled in the traditional fee-for-service program who are assigned to it.
Design and Structure
There is no single organizational model for developing an ACO. ACOs may be formed and
organized by health systems using employed and contracted physicians, by integrated delivery
systems, by physician groups (either primary care or multispecialty) or through joint ventures or
contractual relationships among providers. Regardless of the organizational structure, an ACO
must be physician-led and physician-driven. Physician leadership is critical because an ACO is
primarily a vehicle for clinical integration, not financial or risk integration. Only physicians are
able to develop, monitor and adjust clinical care protocols that can more efficiently use resources
based on documented effectiveness.
Qualifying ACOs will be assigned a pool of patients whose care the ACO will be responsible for
managing in a cost-effective and clinically appropriate manner. The ACO will need to develop
internal mechanisms for monitoring and managing costs and quality that cut across traditional
reporting lines and result in a higher degree of clinical interdependence than is typical in a less-
integrated medical community.
The PPACA states that any of the following groups of providers of services and suppliers that
have established a mechanism for shared governance are eligible to participate, in accordance
with regulations to be developed by the Secretary of Health and Human Services (HHS):
ACOs Under Health Reform
Section 3022 of PPACA requires HHS to establish a shared savings program under which
qualifying ACOs may be eligible for incentive payments. The criteria in the statute, which will
need to be further defined by regulation, include:
ACOs will be required to measure and report their progress to HHS, includ.
True or false A selective force (such as antibiotics) must be prese.pdf
True or false: A selective force (such as antibiotics) must be present for DNA mutations to occur.
Solution
Answer: False
Reason:
Selective forces are not going to exert any impact on the alterations of genome mainly via
causing DNA mutations. For example, antibiotics are going to cause change in the RNA
structure or change in enzyme moieties inside the cells of microbial species result in inhibition of
growth without causing damage or random change (mutation) in the DNA. Natural selection
always trying to eliminate any deleterious alleles in the host cells but do not cause any selective
DNA mutation when taking antibiotics.
The receptors in the feedback loop regulating ADH secretion are osmor.pdf
The receptors in the feedback loop regulating ADH secretion are osmoreceptors in the kidneys
True False
Solution
Ans 39: The receptor in feedback loop regulating ADH secretion are osmoreceptors in kidneys-
False because hypothalmus regulate vasopressin (ADH) secretion from the posterior pituitary to
return blood concentration to normal.
The UV spectrum of the hot B0V star is significantly below the conti.pdf
The UV spectrum of the hot B0V star is significantly below the continuum level due to a large
number of absorption lines caused by highly ionized heavy elements. Can you explain why the
B0V star, rather than the cooler stars, has all those lines?
http://i67.tinypic.com/2u9hn2v.jpg
Solution
In B0V stars have these emission and absorption lines due to radiative recombination between
Hydrogen and Helium ions with electrons and other excitd metal ions present withine the star.
Hot and young stars are able to ionize the gas around them which then produces emission
spectra. This region is known as H|| region. This occurs only around hot stars as UV photons are
required to ionize hydrogen atoms..
Q2 For any drosophila population, what is the proportion of live ho.pdf
Q2: For any drosophila population, what is the proportion of live homozygous (Cy/Cy) flies?
Explain.
Solution
The proportion of live homozygous (Cy/Cy) flies in a drosophila population will be 0.This is
because Cy acts as a mutation that is recessive and lethal.In homozygous condition,Cy/Cy flies
will die even before they will reach the adult stage..
Prove asymptotic upper and lower hounds for each of the following sp.pdf
Prove asymptotic upper and lower hounds for each of the following specified otherwise, assume
that in each case, T(n) = 1 (or any small constant) for small value You may assume that n = c^k
for some constant c that you choose. Make your bounds as tight as (No need to specify the
origin of your guess.) T(n0 = 8T(n/3) + n^1.83838383... T(n) = T(n - 1) = 1/n T(n) = 16T(n/2)
+ (n log n)^4. T(n) = 2T(n/2) + n/lg n. T(n) = T(n - 1) + T(n - 2) + 1 with base case of T(1) = 1
and T(2) = 2
Solution
A statement are often outlined as a declaratory sentence, or a part of a sentence, that\'s capable of
getting a truth-value, like being true or false. So, as an example, the subsequent area unit
statements:
George W. Bush is that the forty third President of the us.
Paris is that the capital of France.
Everyone born on Monday has purple hair.
Sometimes, a press release will contain one or a lot of alternative statements as elements.
contemplate as an example, the subsequent statement:
Either Ganymede may be a moon of Jupiter or Ganymede may be a moon of Saturn.
While the on top of sentence is itself a press release, as a result of it\'s true, the 2 elements,
\"Ganymede may be a moon of Jupiter\" and \"Ganymede may be a moon of Saturn\", area unit
themselves statements, as a result of the primary is true and therefore the second is fake.
The term proposition is typically used synonymously with statement. However, it\'s typically
accustomed name one thing abstract that 2 totally different statements with an equivalent which
means area unit each aforementioned to \"express\". during this usage, nation sentence, \"It is
raining\", and therefore the French sentence \"Il pleut\", would be thought-about to specific an
equivalent proposition; equally, the 2 English sentences, \"Callisto orbits Jupiter\" and \"Jupiter
is orbitted by Callisto\" would even be thought-about to specific an equivalent proposition.
However, the character or existence of propositions as abstract meanings continues to be a matter
of philosophical dispute, and for the needs of this text, the phrases \"statement\" and
\"proposition\" area unit used interchangeably.
Propositional logic, conjointly referred to as linguistic string logic, is that branch of logic that
studies ways that of mixing or neutering statements or propositions to create a lot of difficult
statements or propositions. change of integrity 2 easier propositions with the word \"and\" is one
common approach of mixing statements. once 2 statements area unit joined along side \"and\",
the advanced statement fashioned by them is true if and as long as each the element statements
area unit true. owing to this, associate argument of the subsequent kind is logically valid:
Paris is that the capital of France and Paris contains a population of over 2 million.
Therefore, Paris contains a population of over 2 million.
Propositional logic for the most part involves learning logical connectives like the words \"and\"
and \"or\" and therefo.
pls show details.thx 1. Consider the vectors v1 (a Find the projecti.pdf
pls show details.thx 1. Consider the vectors v1 (a Find the projection, proj1(v2), of v2 on v1 and
draw a somewhat accurate picture to show the vectors and the projection. (b) Find the projection,
proju2(v1), of vi on v2 and draw a somewhat accurate picture to show the vectors and the
projection.
Solution
1).
Please create an infographic for medical fraud! Thank you so much.pdf
Please create an infographic for medical fraud! Thank you so much!
Please create an infographic for medical fraud! Thank you so much!
Solution
causing unintended injury or illness. Duplicate medical records and overlays can also lead to
reimbursement losses, reductions in medical data integrity, administrative inefficiencies,
resource drains, liability concerns, and perhaps most significantly, compromised care delivery
and threats to patient safety. Adding fuel to the fire, the biggest threat to the creation of
duplicates and overlays in healthcare is when a hospital adopts an electronic health record system
(EHR) and these numbers threaten to grow exponentially as hospitals share more information
through Integrated Delivery Networks (IDNs) and Health Information Exchanges (HIEs).
The continued threat that duplicate medical records and overlays place on patient safety and
hospital liability causes unintended injuries and illnesses from patient data matching errors.
Despite the absence of patient identification industry standards and a lack of national leadership
on mandating unique patient identifiers, the healthcare industry is increasingly deploying
modernized patient identification technologies that are drastically reducing the number of
duplicate medical records and overlays to help secure patient safety, reduce the overall cost of
care delivery, and improve medical data integrity
Technologies such as iris biometrics for patient identification and smart cards are rising stars of
securing patient data matching accuracy and provide healthcare providers with competitive
advantages to help stop duplicate medical records and overlays. This Infographic on the effect
that duplicate medical records and overlays have on the healthcare industry is a stark reminder
that this problem still persists and negatively impacts patient safety, medical data integrity, and
the cost of care delivery but modern patient data matching tools are available to help prevent
their creation and keep patients safe..
Internet Programming. For event-driven architecture, how does pollin.pdf
Internet Programming. For event-driven architecture, how does polling work?
Solution
Answer:-
Event-driven Architecture :
The service-oriented architecture (SOA), combining the intelligence and proactiveness of event-
driven architecture with the organizational capabilities found in service offerings.
Before event-driven SOA, the typical SOA platform orchestrated services centrally, through pre-
defined business processes, assuming that what should have already been triggered is defined in
a business process.
This older approach does not account for events that occur across, or outside of, specific business
processes.
Prototypical Service-oriented Architecture :
The prototypical service-oriented architecture paradigm contains four essential elements:
1) multiple low-level system events that, separately do not appear to have any relationship but
through pattern detection by comparing these many events some unusual or less obvious
correlation becomes clear.
2) some amount of data enrichment by infusion of related information to each event to more
clearly illustrate how the many events are related.
3) a trigger condition which when not met, the business-level event is not created, but when the
trigger condition is met, the higher-level business event is created.
4) some human or automated process that is invoked when the trigger event is reached.
Multiple low-level system events:
1) The human intelligence processes and gathers these relationships faster than current artificial
computational capability
2) The engine uses preponderant causal vector rate-of-change propagation to code the
relationship among the events and establishes a partial order in which it validates the causality
perceived between multiple occurrences.
3) Multiple low-level system events are processed by the Causal Vector Engine and compared
against these rules to trigger higher-level Business Events
4) a Service Component Architecture (SCA). Like any SCA component, the program accesses a
mediation flow through exports that it provides, and the mediation flow forwards messages to
other external services via imports.
5) Once the developers have coded the custom binding for both export and import, they can start
to focus on the mediation flow component.
6) In the WebSphere Integration Developer assembly editor, this is done by the JMS Custom
Binding Mediation Component where each operation on the flow component\'s interface is
represented by a request and a response .
7) Service Data Objects (SDO) framework provides a unified framework for data application
development. With SDO, developers do not need to be familiar with any specific API in order to
access and utilize data.
Business-level trigger condition :
A business-level trigger condition enables the service-oriented architecture, architecture to
establish real-time customer intelligence, marketing automation and customer loyalty solutions,
among other features..
PCAOB Please respond to the followingGo to the PCAOB Website..pdf
\"PCAOB\" Please respond to the following:
Go to the PCAOB Website. Next, analyze the role of the PCAOB to protect the public. Based on
your analysis, give your opinion as to whether you believe they possess enough of the requisite
power to be effective in accomplishing their mission. Provide support for your opinion.
Solution
The Public Company Accounting Oversight Board is a nonprofit corporation set up to protect
investors and the public interest by providing informative, accurate, and independent audit
reports and to oversee the audits of public companies and broker-dealers.
ROLE OF PCAOB
1.It explore ways to improve its audit requirements and their implementation by audit firms,
while preserving the intended benefits.
2. It helps to inform a current standards setting project dealing with firms’ systems of quality
controls.
3. helps in setting standard for the project on the supervision of other auditors that
strengthen the standards in that area.
4.looks after auditing requirements that will aid users and investors of financial statements to
make informed decisions and assist in restoring the confidence
5.The ultimate mission of PCAOB is to protect public interest and to protect investors by
overseeing whether set out norms are being adhered to or not.
OPINION
There has been a period of extreme economic stress, triggered and then compounded by a
meltdown of financial system.PCAOB shall succeed in meeting its goal by Improving the
transparency of the financial condition of registered accounting firms .Another way to enhance
transparency is to improve the reporting model for financial statements which would contribute
to the investor’s understanding of the financial statements and the audit process..
pleaase I want manual solution forData Structures and Algorithm An.pdf
pleaase I want manual solution for
Data Structures and Algorithm Analysis in C++, Third Edition
By Clifford A. Shaffer
because my question from this book.page270 ,question 7.4
The implementation for Mergesort given in Section 7.4 takes an array as input and sorts that
array. At the beginning of Section 7.4 there is a simple pseudocode implementation for sorting a
linked list using Mergesort. Implement both a linked list-based version of Mergesort and the
array-based version of Mergesort, and compare and analyze their running times.
Solution
Linked list:
#include
#include
struct node
{
int data;
struct node* next;
};
struct node* SortedMerge(struct node* a, struct node* b);
void FrontBackSplit(struct node* source,
struct node** frontRef, struct node** backRef);
void MergeSort(struct node** headRef)
{
struct node* head = *headRef;
struct node* a;
struct node* b;
if ((head == NULL) || (head->next == NULL))
{
return;
}
FrontBackSplit(head, &a, &b);
MergeSort(&a);
MergeSort(&b);
*headRef = SortedMerge(a, b);
}
struct node* SortedMerge(struct node* a, struct node* b)
{
struct node* result = NULL;
if (a == NULL)
return(b);
else if (b==NULL)
return(a);
if (a->data <= b->data)
{
result = a;
result->next = SortedMerge(a->next, b);
}
else
{
result = b;
result->next = SortedMerge(a, b->next);
}
return(result);
}
void FrontBackSplit(struct node* source,
struct node** frontRef, struct node** backRef)
{
struct node* fast;
struct node* slow;
if (source==NULL || source->next==NULL)
{
*frontRef = source;
*backRef = NULL;
}
else
{
slow = source;
fast = source->next;
while (fast != NULL)
{
fast = fast->next;
if (fast != NULL)
{
slow = slow->next;
fast = fast->next;
}
}
*frontRef = source;
*backRef = slow->next;
slow->next = NULL;
}
}
void printList(struct node *node)
{
while(node!=NULL)
{
printf(\"%d \", node->data);
node = node->next;
}
}
void push(struct node** head_ref, int new_data)
{
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
new_node->data = new_data;
new_node->next = (*head_ref);
(*head_ref) = new_node;
}
int main()
{
struct node* res = NULL;
struct node* a = NULL;
push(&a, 15);
push(&a, 10);
push(&a, 5);
push(&a, 20);
push(&a, 3);
push(&a, 2);
MergeSort(&a);
printf(\"\ Sorted Linked List is: \ \");
printList(a);
getchar();
return 0;
}
Time complexity:o(nlogn)
Array :
#include
#include
void merge(int arr[], int l, int m, int r)
{
int i, j, k;
int n1 = m - l + 1;
int n2 = r - m;
int L[n1], R[n2];
for (i = 0; i < n1; i++)
L[i] = arr[l + i];
for (j = 0; j < n2; j++)
R[j] = arr[m + 1+ j];
i = 0; // Initial index of first subarray
j = 0;
k = l;
while (i < n1 && j < n2)
{
if (L[i] <= R[j])
{
arr[k] = L[i];
i++;
}
else
{
arr[k] = R[j];
j++;
}
k++;
}
while (i < n1)
{
arr[k] = L[i];
i++;
k++;
}
while (j < n2)
{
arr[k] = R[j];
j++;
k++;
}
}
void mergeSort(int arr[], int l, int r)
{
if (l < r)
{
int m = l+(r-l)/2;
// Sort first and second halves
mergeSort(arr, l, m);
mergeSort(arr, m+1, r);
merge(arr, l, m, r);
}
}
void printArray(int A[], i.
Part A Select the TRUE statement regarding plasma cells. They live .pdf
Part A Select the TRUE statement regarding plasma cells. They live for many years and
function as memory cells. The antibodies they produce can remain in circulation for years. They
are descended from activated T cells. They can produce large quantities of antibodies on a daily
basis. They secrete a variety of antibody molecules specific for multiple epitopes.
Solution
True statement regarding plasma cells is
They produce and secrete antibodies; they produce large quantities of antibodies on a daily basis.
On the code which has a class in which I implementing a binary tree .pdf
On the code which has a class in which I implementing a binary tree using an array. This array,
named store, stores Node in entries corresponding to
nodes in the tree and null if the node does not exist. Complete the countLeavesmethod so that it
returns the number of leaves in this tree.
Code:
Solution
import java.util.AbstractSet; import java.util.Arrays; import java.util.Iterator; import
java.util.NoSuchElementException; /** * Implementation of an abstract set using an array-
based binary tree. This is * used to help teach binary tree\'s and will have more details explained
in * future lectures. * * @author William J. Collins * @author Matthew Hertz * @param
Data type (which must be Comparable) of the elements in this tree. */ public class
ArrayBinaryTree> extends AbstractSet { /** Entry in the data store where the root node can be
found. */ private static final int ROOT = 0; /** Array used to store the nodes which consist of
this binary tree. */ protected Node[] store; /** Number of elements within the tree. */
protected int size; /** * Initializes this ArrayBinaryTree object to be empty. This creates the
array * in which items will be stored. */ @SuppressWarnings(\"unchecked\") public
ArrayBinaryTree() { store = new Node[63]; size = 0; } /** * Initializes this
ArrayBinaryTree object to contain a shallow copy of a * specified ArrayBinaryTree object.
The worstTime(n) is O(n), where n is the * number of elements in the specified
ArrayBinaryTree object. * * @param otherTree The tree which will be copied to create our
new tree, */ @SuppressWarnings(\"unchecked\") public ArrayBinaryTree(ArrayBinaryTree
otherTree) { store = (Node[]) Arrays.copyOf(otherTree.store, otherTree.store.length); size =
otherTree.size; } public int countLeaves() { } /** * Returns the size of this
ArrayBinaryTree object. * * @return the size of this ArrayBinaryTree object. */
@Override public int size() { return size; } /** * Returns an iterator that will return the
elements in this ArrayBinaryTree, * but without any specific ordering. * * @return Iterator
positioned at the smallest element in this ArrayBinaryTree * object. */ @Override
public Iterator iterator() { return new ArrayTreeIterator(); } /** * Determines if there is at
least one element in this ArrayBinaryTree object * that equals a specified element. The
worstTime(n) is O(n) and * averageTime(n) is O(log n). * * @param obj - the element
sought in this ArrayBinaryTree object. * @return true - if there is an element in this
ArrayBinaryTree object that * equals obj; otherwise, return false. * @throws
ClassCastException - if obj cannot be compared to the elements in * this
ArrayBinaryTree object. * @throws NullPointerException - if obj is null. */ @Override
public boolean contains(Object obj) { return getEntry(obj) != null; } /** * Ensures that
this ArrayBinaryTree object contains a specified element. The * worstTime(n) is O(n) for this
addition. * * @param element Element we want to be certain is contained within.
Not sure why my program wont run.Programmer S.Villegas helper N.pdf
Not sure why my program wont run.
//Programmer: S.Villegas helper Noah
//File name: PP88ArrayList.java
//Description:
//****************************
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;
public class PP88ArrayList
{
public static void main(String[]args)
{
ArrayList persons = new ArrayList(25);
String fileName = \"Zips.dat\";
int i;
Scanner filescasnner = null;
try
{
filescasnner=new Scanner(new File(fileName));
for(i=0;i persons)
{
for (int i = 0; i < persons.size(); i++)
{
for (int j = 0; j < persons.size()-1; j++)
{
if((persons.get(j).getFirstName().compareTo(persons.get(j+1).getFirstName()))>0)
{
Person temp= persons.get(j);
persons.set(j, persons.get(j+1));
persons.set(j+1, temp);
}
}
}
}
public static void sortByZipCode(ArrayList persons)
{
for (int i = 0; i < persons.size(); i++)
{
for (int j = 0; j < persons.size()-1; j++)
{
if(persons.get(j).getZipCode()>persons.get(j+1).getZipCode())
{
Person temp= persons.get(j);
persons.set(j, persons.get(j+1));
persons.set(j+1, temp);
}
}
}
}
}
//Programmer: S.Villegas helper Noah
//File name: PersonList.java
//Description:
//******************************
public class PersonList
{
private String firstName, lastName;
private int Zip;
public PersonList(String firstName,String lastName, int Zip)
{
this.firstName = firstName;
this.lastName = lastName;
this.Zip = Zip;
}
public String getFirstName()
{
return firstName;
}
public int getZipCode()
{
return Zip;
}
public String toString()
{
return String.format(\"%-15s%-15s%-10d\",firstName,lastName,Zip);
}
}
Solution
//File name: PersonList.java
public class PersonList
{
private String firstName, lastName;
private int Zip;
public PersonList(String firstName,String lastName, int Zip)
{
this.firstName = firstName;
this.lastName = lastName;
this.Zip = Zip;
}
public String getFirstName()
{
return firstName;
}
public int getZipCode()
{
return Zip;
}
public String toString()
{
return String.format(\"%-15s%-15s%-10d\",firstName,lastName,Zip);
}
}
//File name: PP88ArrayList.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;
public class PP88ArrayList
{
public static void main(String[]args)
{
ArrayList persons = new ArrayList(25);
String fileName = \"Zips.dat\";
int i;
Scanner filescasnner = null;
try
{
filescasnner=new Scanner(new File(fileName));
while(filescasnner.hasNextLine())
{
String firstName = filescasnner.next();
String lastName = filescasnner.next();
int Zip = filescasnner.nextInt();
persons.add(new PersonList(firstName, lastName, Zip));
}
filescasnner.close();
}
catch (FileNotFoundException e)
{
System.out.println(e.getMessage());
}
System.out.println(\"\ List of names and zip codes: \");
System.out.printf(\"%-15s%-15s%-15s\ \",\"First Name\",\"Last Name\",\"Zip\");
for (int j = 0; j < persons.size(); j++)
{
System.out.println(persons.get(j));
}
System.out.println(\"\ List of names sort by first name\");
sortByNa.
Let X be a random variable with cumulative distribution function Is .pdf
Let X be a random variable with cumulative distribution function Is X a discrete or continuous
random variable? Explain clearly in terms of the property of a discrete or continuous random
variable.
Solution
If a variable is defined at specific values and it cannot take values between the values then it will
be discrete random variable. Given CDF is defined at 0.1, 0.2, 0.3 and 0.4 and not in between
values. So it is discrete distribution..
Java Question Consider a maze made up of a rectangular array of squ.pdf
Java Question: Consider a maze made up of a rectangular array of squares. The maze will
contain a character (either +, -, or |) to represent a blocked square, and to form the walls of the
maze. Mazes will have only one entrance at the Coordinate (0, 1), with only one exit in the lower
right hand corner of the maze. Beginning at the entrance to the maze, find a path to the exit at the
bottom right of the maze. You may only move up, down, left, and right. Each square in the maze
can be in one of four states: clear (space), blocked (X), path (.), or visited (*). Initially, after the
maze has been read in from the file, each square will be either clear or blocked. If a square lies
on a successful path, mark it with a period. If you visit a square but it does not lead to a
successful path, mark it as visited with an asterisk.
Solution
import java.io.*;
class Maze
{
// Any MazeSquare field is true if the corresponding
// wall exists, and false otherwise.
class MazeSquare
{
public boolean hasTopWall;
public boolean hasRightWall;
public boolean hasLeftWall;
public boolean hasBottomWall;
public MazeSquare()
{
hasTopWall = hasRightWall = hasLeftWall = hasBottomWall = false;
}
}
// This Exception class will help pinpoint format errors in the data file.
class MazeFormatException extends Exception
{
public final static int noError = 0;
public final static int badRowAndColumnCounts = 1;
public final static int wrongNumberOfEntriesInRow = 2;
public final static int badEntry = 3;
public int lineNumber;
public int problem;
public MazeFormatException( int line, int prob )
{
lineNumber = line;
problem = prob;
}
}
// Number of rows and columns in the maze.
private int nRows;
private int nColumns;
// The array of maze squares themselves.
MazeSquare[][] square;
public static void main( String[] args )
{
if( args.length != 1 )
{
System.err.println( \"Usage: java Maze mazeFileName\" );
System.exit( 1 );
}
Maze knosos = null;
try
{
knosos = new Maze( args[0] );
}
catch( FileNotFoundException e )
{
System.err.println( \"Can\'t open \" + args[0] + \". Check your spelling.\" );
System.exit( 1 );
}
catch( IOException e )
{
System.err.println( \"Severe input error. I give up.\" );
System.exit( 1 );
}
catch( MazeFormatException e )
{
switch( e.problem )
{
case MazeFormatException.badRowAndColumnCounts:
System.err.println( args[0] + \", line \" + e.lineNumber + \": row and column counts
expected\" );
break;
case MazeFormatException.wrongNumberOfEntriesInRow:
System.err.println( args[0] + \", line \" + e.lineNumber + \": wrong number of entries\"
);
break;
case MazeFormatException.badEntry:
System.err.println( args[0] + \", line \" + e.lineNumber + \": non-hexadecimal digit
detected\" );
break;
default:
System.err.println( \"This should never get printed.\" );
break;
}
System.exit( 1 );
}
knosos.print( System.out );
}
public Maze()
{
square = null;
nRows = nColumns = 0;
}
public Maze( String fileName ) throws FileNotFoundException, IOException,
MazeFormatException
{
Buffered.
In terms of IT Infrastructure What is binding and why is it importa.pdf
In terms of IT Infrastructure: What is binding and why is it important. Is it different from a
remote procedure call and why?
Solution
Binding is to make an association between two or more programming objects or value items for
some scope of time and place.
It is important due to substitute a real for a variable value in the program or to ensure that
additional programming will be loaded into storage along with the compiled program.
Yes, it is different from a remote procedure call because Remote Procedure Call (RPC) provides
a different paradigm for accessing network services. Instead of accessing remote services by
sending and receiving messages, a client invokes services by making a local procedure call. The
local procedure hides the details of the network communication..
In nature, how is most carbon dioxide replaceda. plant photosynth.pdf
In nature, how is most carbon dioxide replaced?
a. plant photosynthesis
b. production of plant biomass
c. oxidative use of biomass for energy (respiration and combustion)
Solution
A. Plant photosynthesis.
By photosynthesis most of the Carbon Dioxide is replaced by Oxygen which goes into
atmosphere where from it is used by libing organisms for cellulat respiration..
In a murder investigation, the temperature of the corpse was 33 degre.pdf
In a murder investigation, the temperature of the corpse was 33 degree C at 1:30pm and 25
degree C 2 hours later. Normal body temperature is 37 degree C and the surrounding temperature
was 7 degree C. How long (in hours) before 1:30pm did the murder take place?
Solution
The murder time is 10:45 I.e. three hours forty five minute.
special B.ed 2nd year old paper_20240531.pdf
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Polish students' mobility in the Czech Republic
Polish students mobility to the Czech Republic within eTwinning project "Medieval adventures with Marco Polo"
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Which of the following is not included in the calculation of the VIX .pdf
Which of the following is not included in the calculation of the VIX cross-asset rank? O
Treasury bond volatility Gold volatility High yield corporate bond volatility EUR volatility
Solution
which of the following is not involed in VIX Cross asset rank
Answer:high yeild coporate bond volatility.
What is an Accountable Care Organizations (ACO) How does an ACOs .pdf
What is an Accountable Care Organizations (ACO)? How does an ACO\'s economics work to
manage costs and quality?
Solution
Accountable Care Organizations (ACOs) are groups of doctors, hospitals, and other health care
providers, who come together voluntarily to give coordinated high quality care to their Medicare
patients.
An accountable care organization (ACO) is a healthcare organization characterized by a payment
and care delivery model that seeks to tie provider reimbursements to quality metrics and
reductions in the total cost of care for an assigned population of patients. A group of coordinated
health care providers forms an ACO, which then provides care to a group of patients. The ACO
may use a range of payment models (capitation, fee-for-service with asymmetric or symmetric
shared savings, etc.). The ACO is accountable to the patients and the third-party payer for the
quality, appropriateness and efficiency of the health care provided. According to the Centers for
Medicare and Medicaid Services (CMS), an ACO is \"an organization of health care providers
that agrees to be accountable for the quality, cost, and overall care of Medicare beneficiaries who
are enrolled in the traditional fee-for-service program who are assigned to it.
Design and Structure
There is no single organizational model for developing an ACO. ACOs may be formed and
organized by health systems using employed and contracted physicians, by integrated delivery
systems, by physician groups (either primary care or multispecialty) or through joint ventures or
contractual relationships among providers. Regardless of the organizational structure, an ACO
must be physician-led and physician-driven. Physician leadership is critical because an ACO is
primarily a vehicle for clinical integration, not financial or risk integration. Only physicians are
able to develop, monitor and adjust clinical care protocols that can more efficiently use resources
based on documented effectiveness.
Qualifying ACOs will be assigned a pool of patients whose care the ACO will be responsible for
managing in a cost-effective and clinically appropriate manner. The ACO will need to develop
internal mechanisms for monitoring and managing costs and quality that cut across traditional
reporting lines and result in a higher degree of clinical interdependence than is typical in a less-
integrated medical community.
The PPACA states that any of the following groups of providers of services and suppliers that
have established a mechanism for shared governance are eligible to participate, in accordance
with regulations to be developed by the Secretary of Health and Human Services (HHS):
ACOs Under Health Reform
Section 3022 of PPACA requires HHS to establish a shared savings program under which
qualifying ACOs may be eligible for incentive payments. The criteria in the statute, which will
need to be further defined by regulation, include:
ACOs will be required to measure and report their progress to HHS, includ.
True or false A selective force (such as antibiotics) must be prese.pdf
True or false: A selective force (such as antibiotics) must be present for DNA mutations to occur.
Solution
Answer: False
Reason:
Selective forces are not going to exert any impact on the alterations of genome mainly via
causing DNA mutations. For example, antibiotics are going to cause change in the RNA
structure or change in enzyme moieties inside the cells of microbial species result in inhibition of
growth without causing damage or random change (mutation) in the DNA. Natural selection
always trying to eliminate any deleterious alleles in the host cells but do not cause any selective
DNA mutation when taking antibiotics.
The receptors in the feedback loop regulating ADH secretion are osmor.pdf
The receptors in the feedback loop regulating ADH secretion are osmoreceptors in the kidneys
True False
Solution
Ans 39: The receptor in feedback loop regulating ADH secretion are osmoreceptors in kidneys-
False because hypothalmus regulate vasopressin (ADH) secretion from the posterior pituitary to
return blood concentration to normal.
The UV spectrum of the hot B0V star is significantly below the conti.pdf
The UV spectrum of the hot B0V star is significantly below the continuum level due to a large
number of absorption lines caused by highly ionized heavy elements. Can you explain why the
B0V star, rather than the cooler stars, has all those lines?
http://i67.tinypic.com/2u9hn2v.jpg
Solution
In B0V stars have these emission and absorption lines due to radiative recombination between
Hydrogen and Helium ions with electrons and other excitd metal ions present withine the star.
Hot and young stars are able to ionize the gas around them which then produces emission
spectra. This region is known as H|| region. This occurs only around hot stars as UV photons are
required to ionize hydrogen atoms..
Q2 For any drosophila population, what is the proportion of live ho.pdf
Q2: For any drosophila population, what is the proportion of live homozygous (Cy/Cy) flies?
Explain.
Solution
The proportion of live homozygous (Cy/Cy) flies in a drosophila population will be 0.This is
because Cy acts as a mutation that is recessive and lethal.In homozygous condition,Cy/Cy flies
will die even before they will reach the adult stage..
Prove asymptotic upper and lower hounds for each of the following sp.pdf
Prove asymptotic upper and lower hounds for each of the following specified otherwise, assume
that in each case, T(n) = 1 (or any small constant) for small value You may assume that n = c^k
for some constant c that you choose. Make your bounds as tight as (No need to specify the
origin of your guess.) T(n0 = 8T(n/3) + n^1.83838383... T(n) = T(n - 1) = 1/n T(n) = 16T(n/2)
+ (n log n)^4. T(n) = 2T(n/2) + n/lg n. T(n) = T(n - 1) + T(n - 2) + 1 with base case of T(1) = 1
and T(2) = 2
Solution
A statement are often outlined as a declaratory sentence, or a part of a sentence, that\'s capable of
getting a truth-value, like being true or false. So, as an example, the subsequent area unit
statements:
George W. Bush is that the forty third President of the us.
Paris is that the capital of France.
Everyone born on Monday has purple hair.
Sometimes, a press release will contain one or a lot of alternative statements as elements.
contemplate as an example, the subsequent statement:
Either Ganymede may be a moon of Jupiter or Ganymede may be a moon of Saturn.
While the on top of sentence is itself a press release, as a result of it\'s true, the 2 elements,
\"Ganymede may be a moon of Jupiter\" and \"Ganymede may be a moon of Saturn\", area unit
themselves statements, as a result of the primary is true and therefore the second is fake.
The term proposition is typically used synonymously with statement. However, it\'s typically
accustomed name one thing abstract that 2 totally different statements with an equivalent which
means area unit each aforementioned to \"express\". during this usage, nation sentence, \"It is
raining\", and therefore the French sentence \"Il pleut\", would be thought-about to specific an
equivalent proposition; equally, the 2 English sentences, \"Callisto orbits Jupiter\" and \"Jupiter
is orbitted by Callisto\" would even be thought-about to specific an equivalent proposition.
However, the character or existence of propositions as abstract meanings continues to be a matter
of philosophical dispute, and for the needs of this text, the phrases \"statement\" and
\"proposition\" area unit used interchangeably.
Propositional logic, conjointly referred to as linguistic string logic, is that branch of logic that
studies ways that of mixing or neutering statements or propositions to create a lot of difficult
statements or propositions. change of integrity 2 easier propositions with the word \"and\" is one
common approach of mixing statements. once 2 statements area unit joined along side \"and\",
the advanced statement fashioned by them is true if and as long as each the element statements
area unit true. owing to this, associate argument of the subsequent kind is logically valid:
Paris is that the capital of France and Paris contains a population of over 2 million.
Therefore, Paris contains a population of over 2 million.
Propositional logic for the most part involves learning logical connectives like the words \"and\"
and \"or\" and therefo.
pls show details.thx 1. Consider the vectors v1 (a Find the projecti.pdf
pls show details.thx 1. Consider the vectors v1 (a Find the projection, proj1(v2), of v2 on v1 and
draw a somewhat accurate picture to show the vectors and the projection. (b) Find the projection,
proju2(v1), of vi on v2 and draw a somewhat accurate picture to show the vectors and the
projection.
Solution
1).
Please create an infographic for medical fraud! Thank you so much.pdf
Please create an infographic for medical fraud! Thank you so much!
Please create an infographic for medical fraud! Thank you so much!
Solution
causing unintended injury or illness. Duplicate medical records and overlays can also lead to
reimbursement losses, reductions in medical data integrity, administrative inefficiencies,
resource drains, liability concerns, and perhaps most significantly, compromised care delivery
and threats to patient safety. Adding fuel to the fire, the biggest threat to the creation of
duplicates and overlays in healthcare is when a hospital adopts an electronic health record system
(EHR) and these numbers threaten to grow exponentially as hospitals share more information
through Integrated Delivery Networks (IDNs) and Health Information Exchanges (HIEs).
The continued threat that duplicate medical records and overlays place on patient safety and
hospital liability causes unintended injuries and illnesses from patient data matching errors.
Despite the absence of patient identification industry standards and a lack of national leadership
on mandating unique patient identifiers, the healthcare industry is increasingly deploying
modernized patient identification technologies that are drastically reducing the number of
duplicate medical records and overlays to help secure patient safety, reduce the overall cost of
care delivery, and improve medical data integrity
Technologies such as iris biometrics for patient identification and smart cards are rising stars of
securing patient data matching accuracy and provide healthcare providers with competitive
advantages to help stop duplicate medical records and overlays. This Infographic on the effect
that duplicate medical records and overlays have on the healthcare industry is a stark reminder
that this problem still persists and negatively impacts patient safety, medical data integrity, and
the cost of care delivery but modern patient data matching tools are available to help prevent
their creation and keep patients safe..
Internet Programming. For event-driven architecture, how does pollin.pdf
Internet Programming. For event-driven architecture, how does polling work?
Solution
Answer:-
Event-driven Architecture :
The service-oriented architecture (SOA), combining the intelligence and proactiveness of event-
driven architecture with the organizational capabilities found in service offerings.
Before event-driven SOA, the typical SOA platform orchestrated services centrally, through pre-
defined business processes, assuming that what should have already been triggered is defined in
a business process.
This older approach does not account for events that occur across, or outside of, specific business
processes.
Prototypical Service-oriented Architecture :
The prototypical service-oriented architecture paradigm contains four essential elements:
1) multiple low-level system events that, separately do not appear to have any relationship but
through pattern detection by comparing these many events some unusual or less obvious
correlation becomes clear.
2) some amount of data enrichment by infusion of related information to each event to more
clearly illustrate how the many events are related.
3) a trigger condition which when not met, the business-level event is not created, but when the
trigger condition is met, the higher-level business event is created.
4) some human or automated process that is invoked when the trigger event is reached.
Multiple low-level system events:
1) The human intelligence processes and gathers these relationships faster than current artificial
computational capability
2) The engine uses preponderant causal vector rate-of-change propagation to code the
relationship among the events and establishes a partial order in which it validates the causality
perceived between multiple occurrences.
3) Multiple low-level system events are processed by the Causal Vector Engine and compared
against these rules to trigger higher-level Business Events
4) a Service Component Architecture (SCA). Like any SCA component, the program accesses a
mediation flow through exports that it provides, and the mediation flow forwards messages to
other external services via imports.
5) Once the developers have coded the custom binding for both export and import, they can start
to focus on the mediation flow component.
6) In the WebSphere Integration Developer assembly editor, this is done by the JMS Custom
Binding Mediation Component where each operation on the flow component\'s interface is
represented by a request and a response .
7) Service Data Objects (SDO) framework provides a unified framework for data application
development. With SDO, developers do not need to be familiar with any specific API in order to
access and utilize data.
Business-level trigger condition :
A business-level trigger condition enables the service-oriented architecture, architecture to
establish real-time customer intelligence, marketing automation and customer loyalty solutions,
among other features..
PCAOB Please respond to the followingGo to the PCAOB Website..pdf
\"PCAOB\" Please respond to the following:
Go to the PCAOB Website. Next, analyze the role of the PCAOB to protect the public. Based on
your analysis, give your opinion as to whether you believe they possess enough of the requisite
power to be effective in accomplishing their mission. Provide support for your opinion.
Solution
The Public Company Accounting Oversight Board is a nonprofit corporation set up to protect
investors and the public interest by providing informative, accurate, and independent audit
reports and to oversee the audits of public companies and broker-dealers.
ROLE OF PCAOB
1.It explore ways to improve its audit requirements and their implementation by audit firms,
while preserving the intended benefits.
2. It helps to inform a current standards setting project dealing with firms’ systems of quality
controls.
3. helps in setting standard for the project on the supervision of other auditors that
strengthen the standards in that area.
4.looks after auditing requirements that will aid users and investors of financial statements to
make informed decisions and assist in restoring the confidence
5.The ultimate mission of PCAOB is to protect public interest and to protect investors by
overseeing whether set out norms are being adhered to or not.
OPINION
There has been a period of extreme economic stress, triggered and then compounded by a
meltdown of financial system.PCAOB shall succeed in meeting its goal by Improving the
transparency of the financial condition of registered accounting firms .Another way to enhance
transparency is to improve the reporting model for financial statements which would contribute
to the investor’s understanding of the financial statements and the audit process..
pleaase I want manual solution forData Structures and Algorithm An.pdf
pleaase I want manual solution for
Data Structures and Algorithm Analysis in C++, Third Edition
By Clifford A. Shaffer
because my question from this book.page270 ,question 7.4
The implementation for Mergesort given in Section 7.4 takes an array as input and sorts that
array. At the beginning of Section 7.4 there is a simple pseudocode implementation for sorting a
linked list using Mergesort. Implement both a linked list-based version of Mergesort and the
array-based version of Mergesort, and compare and analyze their running times.
Solution
Linked list:
#include
#include
struct node
{
int data;
struct node* next;
};
struct node* SortedMerge(struct node* a, struct node* b);
void FrontBackSplit(struct node* source,
struct node** frontRef, struct node** backRef);
void MergeSort(struct node** headRef)
{
struct node* head = *headRef;
struct node* a;
struct node* b;
if ((head == NULL) || (head->next == NULL))
{
return;
}
FrontBackSplit(head, &a, &b);
MergeSort(&a);
MergeSort(&b);
*headRef = SortedMerge(a, b);
}
struct node* SortedMerge(struct node* a, struct node* b)
{
struct node* result = NULL;
if (a == NULL)
return(b);
else if (b==NULL)
return(a);
if (a->data <= b->data)
{
result = a;
result->next = SortedMerge(a->next, b);
}
else
{
result = b;
result->next = SortedMerge(a, b->next);
}
return(result);
}
void FrontBackSplit(struct node* source,
struct node** frontRef, struct node** backRef)
{
struct node* fast;
struct node* slow;
if (source==NULL || source->next==NULL)
{
*frontRef = source;
*backRef = NULL;
}
else
{
slow = source;
fast = source->next;
while (fast != NULL)
{
fast = fast->next;
if (fast != NULL)
{
slow = slow->next;
fast = fast->next;
}
}
*frontRef = source;
*backRef = slow->next;
slow->next = NULL;
}
}
void printList(struct node *node)
{
while(node!=NULL)
{
printf(\"%d \", node->data);
node = node->next;
}
}
void push(struct node** head_ref, int new_data)
{
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
new_node->data = new_data;
new_node->next = (*head_ref);
(*head_ref) = new_node;
}
int main()
{
struct node* res = NULL;
struct node* a = NULL;
push(&a, 15);
push(&a, 10);
push(&a, 5);
push(&a, 20);
push(&a, 3);
push(&a, 2);
MergeSort(&a);
printf(\"\ Sorted Linked List is: \ \");
printList(a);
getchar();
return 0;
}
Time complexity:o(nlogn)
Array :
#include
#include
void merge(int arr[], int l, int m, int r)
{
int i, j, k;
int n1 = m - l + 1;
int n2 = r - m;
int L[n1], R[n2];
for (i = 0; i < n1; i++)
L[i] = arr[l + i];
for (j = 0; j < n2; j++)
R[j] = arr[m + 1+ j];
i = 0; // Initial index of first subarray
j = 0;
k = l;
while (i < n1 && j < n2)
{
if (L[i] <= R[j])
{
arr[k] = L[i];
i++;
}
else
{
arr[k] = R[j];
j++;
}
k++;
}
while (i < n1)
{
arr[k] = L[i];
i++;
k++;
}
while (j < n2)
{
arr[k] = R[j];
j++;
k++;
}
}
void mergeSort(int arr[], int l, int r)
{
if (l < r)
{
int m = l+(r-l)/2;
// Sort first and second halves
mergeSort(arr, l, m);
mergeSort(arr, m+1, r);
merge(arr, l, m, r);
}
}
void printArray(int A[], i.
Part A Select the TRUE statement regarding plasma cells. They live .pdf
Part A Select the TRUE statement regarding plasma cells. They live for many years and
function as memory cells. The antibodies they produce can remain in circulation for years. They
are descended from activated T cells. They can produce large quantities of antibodies on a daily
basis. They secrete a variety of antibody molecules specific for multiple epitopes.
Solution
True statement regarding plasma cells is
They produce and secrete antibodies; they produce large quantities of antibodies on a daily basis.
On the code which has a class in which I implementing a binary tree .pdf
On the code which has a class in which I implementing a binary tree using an array. This array,
named store, stores Node in entries corresponding to
nodes in the tree and null if the node does not exist. Complete the countLeavesmethod so that it
returns the number of leaves in this tree.
Code:
Solution
import java.util.AbstractSet; import java.util.Arrays; import java.util.Iterator; import
java.util.NoSuchElementException; /** * Implementation of an abstract set using an array-
based binary tree. This is * used to help teach binary tree\'s and will have more details explained
in * future lectures. * * @author William J. Collins * @author Matthew Hertz * @param
Data type (which must be Comparable) of the elements in this tree. */ public class
ArrayBinaryTree> extends AbstractSet { /** Entry in the data store where the root node can be
found. */ private static final int ROOT = 0; /** Array used to store the nodes which consist of
this binary tree. */ protected Node[] store; /** Number of elements within the tree. */
protected int size; /** * Initializes this ArrayBinaryTree object to be empty. This creates the
array * in which items will be stored. */ @SuppressWarnings(\"unchecked\") public
ArrayBinaryTree() { store = new Node[63]; size = 0; } /** * Initializes this
ArrayBinaryTree object to contain a shallow copy of a * specified ArrayBinaryTree object.
The worstTime(n) is O(n), where n is the * number of elements in the specified
ArrayBinaryTree object. * * @param otherTree The tree which will be copied to create our
new tree, */ @SuppressWarnings(\"unchecked\") public ArrayBinaryTree(ArrayBinaryTree
otherTree) { store = (Node[]) Arrays.copyOf(otherTree.store, otherTree.store.length); size =
otherTree.size; } public int countLeaves() { } /** * Returns the size of this
ArrayBinaryTree object. * * @return the size of this ArrayBinaryTree object. */
@Override public int size() { return size; } /** * Returns an iterator that will return the
elements in this ArrayBinaryTree, * but without any specific ordering. * * @return Iterator
positioned at the smallest element in this ArrayBinaryTree * object. */ @Override
public Iterator iterator() { return new ArrayTreeIterator(); } /** * Determines if there is at
least one element in this ArrayBinaryTree object * that equals a specified element. The
worstTime(n) is O(n) and * averageTime(n) is O(log n). * * @param obj - the element
sought in this ArrayBinaryTree object. * @return true - if there is an element in this
ArrayBinaryTree object that * equals obj; otherwise, return false. * @throws
ClassCastException - if obj cannot be compared to the elements in * this
ArrayBinaryTree object. * @throws NullPointerException - if obj is null. */ @Override
public boolean contains(Object obj) { return getEntry(obj) != null; } /** * Ensures that
this ArrayBinaryTree object contains a specified element. The * worstTime(n) is O(n) for this
addition. * * @param element Element we want to be certain is contained within.
Not sure why my program wont run.Programmer S.Villegas helper N.pdf
Not sure why my program wont run.
//Programmer: S.Villegas helper Noah
//File name: PP88ArrayList.java
//Description:
//****************************
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;
public class PP88ArrayList
{
public static void main(String[]args)
{
ArrayList persons = new ArrayList(25);
String fileName = \"Zips.dat\";
int i;
Scanner filescasnner = null;
try
{
filescasnner=new Scanner(new File(fileName));
for(i=0;i persons)
{
for (int i = 0; i < persons.size(); i++)
{
for (int j = 0; j < persons.size()-1; j++)
{
if((persons.get(j).getFirstName().compareTo(persons.get(j+1).getFirstName()))>0)
{
Person temp= persons.get(j);
persons.set(j, persons.get(j+1));
persons.set(j+1, temp);
}
}
}
}
public static void sortByZipCode(ArrayList persons)
{
for (int i = 0; i < persons.size(); i++)
{
for (int j = 0; j < persons.size()-1; j++)
{
if(persons.get(j).getZipCode()>persons.get(j+1).getZipCode())
{
Person temp= persons.get(j);
persons.set(j, persons.get(j+1));
persons.set(j+1, temp);
}
}
}
}
}
//Programmer: S.Villegas helper Noah
//File name: PersonList.java
//Description:
//******************************
public class PersonList
{
private String firstName, lastName;
private int Zip;
public PersonList(String firstName,String lastName, int Zip)
{
this.firstName = firstName;
this.lastName = lastName;
this.Zip = Zip;
}
public String getFirstName()
{
return firstName;
}
public int getZipCode()
{
return Zip;
}
public String toString()
{
return String.format(\"%-15s%-15s%-10d\",firstName,lastName,Zip);
}
}
Solution
//File name: PersonList.java
public class PersonList
{
private String firstName, lastName;
private int Zip;
public PersonList(String firstName,String lastName, int Zip)
{
this.firstName = firstName;
this.lastName = lastName;
this.Zip = Zip;
}
public String getFirstName()
{
return firstName;
}
public int getZipCode()
{
return Zip;
}
public String toString()
{
return String.format(\"%-15s%-15s%-10d\",firstName,lastName,Zip);
}
}
//File name: PP88ArrayList.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;
public class PP88ArrayList
{
public static void main(String[]args)
{
ArrayList persons = new ArrayList(25);
String fileName = \"Zips.dat\";
int i;
Scanner filescasnner = null;
try
{
filescasnner=new Scanner(new File(fileName));
while(filescasnner.hasNextLine())
{
String firstName = filescasnner.next();
String lastName = filescasnner.next();
int Zip = filescasnner.nextInt();
persons.add(new PersonList(firstName, lastName, Zip));
}
filescasnner.close();
}
catch (FileNotFoundException e)
{
System.out.println(e.getMessage());
}
System.out.println(\"\ List of names and zip codes: \");
System.out.printf(\"%-15s%-15s%-15s\ \",\"First Name\",\"Last Name\",\"Zip\");
for (int j = 0; j < persons.size(); j++)
{
System.out.println(persons.get(j));
}
System.out.println(\"\ List of names sort by first name\");
sortByNa.
Let X be a random variable with cumulative distribution function Is .pdf
Let X be a random variable with cumulative distribution function Is X a discrete or continuous
random variable? Explain clearly in terms of the property of a discrete or continuous random
variable.
Solution
If a variable is defined at specific values and it cannot take values between the values then it will
be discrete random variable. Given CDF is defined at 0.1, 0.2, 0.3 and 0.4 and not in between
values. So it is discrete distribution..
Java Question Consider a maze made up of a rectangular array of squ.pdf
Java Question: Consider a maze made up of a rectangular array of squares. The maze will
contain a character (either +, -, or |) to represent a blocked square, and to form the walls of the
maze. Mazes will have only one entrance at the Coordinate (0, 1), with only one exit in the lower
right hand corner of the maze. Beginning at the entrance to the maze, find a path to the exit at the
bottom right of the maze. You may only move up, down, left, and right. Each square in the maze
can be in one of four states: clear (space), blocked (X), path (.), or visited (*). Initially, after the
maze has been read in from the file, each square will be either clear or blocked. If a square lies
on a successful path, mark it with a period. If you visit a square but it does not lead to a
successful path, mark it as visited with an asterisk.
Solution
import java.io.*;
class Maze
{
// Any MazeSquare field is true if the corresponding
// wall exists, and false otherwise.
class MazeSquare
{
public boolean hasTopWall;
public boolean hasRightWall;
public boolean hasLeftWall;
public boolean hasBottomWall;
public MazeSquare()
{
hasTopWall = hasRightWall = hasLeftWall = hasBottomWall = false;
}
}
// This Exception class will help pinpoint format errors in the data file.
class MazeFormatException extends Exception
{
public final static int noError = 0;
public final static int badRowAndColumnCounts = 1;
public final static int wrongNumberOfEntriesInRow = 2;
public final static int badEntry = 3;
public int lineNumber;
public int problem;
public MazeFormatException( int line, int prob )
{
lineNumber = line;
problem = prob;
}
}
// Number of rows and columns in the maze.
private int nRows;
private int nColumns;
// The array of maze squares themselves.
MazeSquare[][] square;
public static void main( String[] args )
{
if( args.length != 1 )
{
System.err.println( \"Usage: java Maze mazeFileName\" );
System.exit( 1 );
}
Maze knosos = null;
try
{
knosos = new Maze( args[0] );
}
catch( FileNotFoundException e )
{
System.err.println( \"Can\'t open \" + args[0] + \". Check your spelling.\" );
System.exit( 1 );
}
catch( IOException e )
{
System.err.println( \"Severe input error. I give up.\" );
System.exit( 1 );
}
catch( MazeFormatException e )
{
switch( e.problem )
{
case MazeFormatException.badRowAndColumnCounts:
System.err.println( args[0] + \", line \" + e.lineNumber + \": row and column counts
expected\" );
break;
case MazeFormatException.wrongNumberOfEntriesInRow:
System.err.println( args[0] + \", line \" + e.lineNumber + \": wrong number of entries\"
);
break;
case MazeFormatException.badEntry:
System.err.println( args[0] + \", line \" + e.lineNumber + \": non-hexadecimal digit
detected\" );
break;
default:
System.err.println( \"This should never get printed.\" );
break;
}
System.exit( 1 );
}
knosos.print( System.out );
}
public Maze()
{
square = null;
nRows = nColumns = 0;
}
public Maze( String fileName ) throws FileNotFoundException, IOException,
MazeFormatException
{
Buffered.
In terms of IT Infrastructure What is binding and why is it importa.pdf
In terms of IT Infrastructure: What is binding and why is it important. Is it different from a
remote procedure call and why?
Solution
Binding is to make an association between two or more programming objects or value items for
some scope of time and place.
It is important due to substitute a real for a variable value in the program or to ensure that
additional programming will be loaded into storage along with the compiled program.
Yes, it is different from a remote procedure call because Remote Procedure Call (RPC) provides
a different paradigm for accessing network services. Instead of accessing remote services by
sending and receiving messages, a client invokes services by making a local procedure call. The
local procedure hides the details of the network communication..
In nature, how is most carbon dioxide replaceda. plant photosynth.pdf
In nature, how is most carbon dioxide replaced?
a. plant photosynthesis
b. production of plant biomass
c. oxidative use of biomass for energy (respiration and combustion)
Solution
A. Plant photosynthesis.
By photosynthesis most of the Carbon Dioxide is replaced by Oxygen which goes into
atmosphere where from it is used by libing organisms for cellulat respiration..
In a murder investigation, the temperature of the corpse was 33 degre.pdf
In a murder investigation, the temperature of the corpse was 33 degree C at 1:30pm and 25
degree C 2 hours later. Normal body temperature is 37 degree C and the surrounding temperature
was 7 degree C. How long (in hours) before 1:30pm did the murder take place?
Solution
The murder time is 10:45 I.e. three hours forty five minute.
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In this webinar you will learn how your organization can access TechSoup's wide variety of product discount and donation programs. From hardware to software, we'll give you a tour of the tools available to help your nonprofit with productivity, collaboration, financial management, donor tracking, security, and more.
Introduction to Quality Improvement Essentials
This is a presentation by Dada Robert in a Your Skill Boost masterclass organised by the Excellence Foundation for South Sudan (EFSS) on Saturday, the 25th and Sunday, the 26th of May 2024.
He discussed the concept of quality improvement, emphasizing its applicability to various aspects of life, including personal, project, and program improvements. He defined quality as doing the right thing at the right time in the right way to achieve the best possible results and discussed the concept of the "gap" between what we know and what we do, and how this gap represents the areas we need to improve. He explained the scientific approach to quality improvement, which involves systematic performance analysis, testing and learning, and implementing change ideas. He also highlighted the importance of client focus and a team approach to quality improvement.
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Event Link:-
https://meetups.mulesoft.com/events/details/mulesoft-mysore-presents-exploring-gemini-ai-and-integration-with-mulesoft/
Agenda
● Java 17 Upgrade Overview
● Why and by when do customers need to upgrade to Java 17?
● Is there any immediate impact to upgrading to Mule Runtime 4.6 and beyond?
● Which MuleSoft products are in scope?
For Upcoming Meetups Join Mysore Meetup Group - https://meetups.mulesoft.com/mysore/
YouTube:- youtube.com/@mulesoftmysore
Mysore WhatsApp group:- https://chat.whatsapp.com/EhqtHtCC75vCAX7gaO842N
Speaker:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Organizers:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Giridhar Meka - https://www.linkedin.com/in/giridharmeka
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Shyam Raj Prasad-
https://www.linkedin.com/in/shyam-raj-prasad/
Digital Tools and AI for Teaching Learning and Research
This Presentation in details discusses on Digital Tools and AI for Teaching Learning and Research
Palestine last event orientationfvgnh .pptx
An EFL lesson about the current events in Palestine. It is intended to be for intermediate students who wish to increase their listening skills through a short lesson in power point.
Synthetic Fiber Construction in lab .pptx
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