Use the code below from the previous assignment that we need to exte.pdf
•
0 likes•5 views
Use the code below from the previous assignment that we need to extend just follow the instructions above. ***Make sure after you are done to show the output of your results*** main.cpp #include #include "Contact.h" int main() { // create Contact object using parameterized constructor Contact c1("Barbara", "Liskov", "Huberman", "404 Ridgeway Dr", "NC", "27403", "336-274- 3344"); // show contact details c1.showContact(); cout << endl; // create Contact object using default constructor Contact c2; // test the overloaded input and output operators cin >> c2; cout << endl; cout << c2; return 0; } Address.h #ifndef ADDRESS_H #define ADDRESS_H #include using namespace std; // create a class named Address class Address { private: // private instance variables string streetAddress, state, zip; public: // default constructor Address() { // initialize instance variables with empty strings streetAddress = ""; state = ""; zip = ""; } // parameterized constructor Address(string streetAddress, string state, string zip) { // initialize instance variables to given parameters this->streetAddress = streetAddress; this->state = state; this->zip = zip; } // copy constructor Address(const Address &a) { streetAddress = a.streetAddress; state = a.state; zip = a.zip; } // setters for all instance variables void setStreetAddress(string streetAddress) { this->streetAddress = streetAddress; } void setState(string state) { this->state = state; } void setZip(string zip) { this->zip = zip; } // getters for all instance variables string getStreetAddress() { return streetAddress; } string getState() { return state; } string getZip() { return zip; } // method to display the address void showAddress() { cout << streetAddress << "\n" << state << " " << zip << endl; } // declare the overloaded input and output operators friend ostream &operator<<(ostream &out, const Address &a); friend istream &operator>>(istream &in, Address &a); }; // define the overloaded output operator ostream &operator<<(ostream &out, const Address &a) { out << a.streetAddress << "\n" << a.state << " " << a.zip << endl; return out; } // define the overloaded input operator istream &operator>>(istream &in, Address &a) { cout << "Enter street address: "; getline(in, a.streetAddress); cout << "Enter state: "; getline(in, a.state); cout << "Enter zip: "; getline(in, a.zip); return in; } #endif Contact.h #ifndef CONTACT_H #define CONTACT_H #include #include "Name.h" #include "Address.h" using namespace std; // create a class named Contact class Contact { private: // private instance variables Name name; Address address; string phone; public: // default constructor Contact() { // initialize phone with empty string phone = ""; } // parameterized constructor Contact(string first_name, string last_name, string middle_name, string streetAddress, string state, string zip, string phone) { // initialize name and address to given strings setName(first_name, last_name, middle_name); setAddress(streetAddress, state, zip).
Report
Share
Report
Share
Download to read offline
Recommended
So here is the code from the previous assignment that we need to ext.pdf
So here is the code from the previous assignment that we need to extend just follow the
instructions above.
main.cpp
#include
#include "Contact.h"
int main()
{
// create Contact object using parameterized constructor
Contact c1("Barbara", "Liskov", "Huberman", "404 Ridgeway Dr", "NC", "27403", "336-274-
3344");
// show contact details
c1.showContact();
cout << endl;
// create Contact object using default constructor
Contact c2;
// test the overloaded input and output operators
cin >> c2;
cout << endl;
cout << c2;
return 0;
}
Address.h
#ifndef ADDRESS_H
#define ADDRESS_H
#include
using namespace std;
// create a class named Address
class Address
{
private:
// private instance variables
string streetAddress, state, zip;
public:
// default constructor
Address()
{
// initialize instance variables with empty strings
streetAddress = "";
state = "";
zip = "";
}
// parameterized constructor
Address(string streetAddress, string state, string zip)
{
// initialize instance variables to given parameters
this->streetAddress = streetAddress;
this->state = state;
this->zip = zip;
}
// copy constructor
Address(const Address &a)
{
streetAddress = a.streetAddress;
state = a.state;
zip = a.zip;
}
// setters for all instance variables
void setStreetAddress(string streetAddress) { this->streetAddress = streetAddress; }
void setState(string state) { this->state = state; }
void setZip(string zip) { this->zip = zip; }
// getters for all instance variables
string getStreetAddress() { return streetAddress; }
string getState() { return state; }
string getZip() { return zip; }
// method to display the address
void showAddress()
{
cout << streetAddress << "\n"
<< state << " " << zip << endl;
}
// declare the overloaded input and output operators
friend ostream &operator<<(ostream &out, const Address &a);
friend istream &operator>>(istream &in, Address &a);
};
// define the overloaded output operator
ostream &operator<<(ostream &out, const Address &a)
{
out << a.streetAddress << "\n"
<< a.state << " " << a.zip << endl;
return out;
}
// define the overloaded input operator
istream &operator>>(istream &in, Address &a)
{
cout << "Enter street address: ";
getline(in, a.streetAddress);
cout << "Enter state: ";
getline(in, a.state);
cout << "Enter zip: ";
getline(in, a.zip);
return in;
}
#endif
Contact.h
#ifndef CONTACT_H
#define CONTACT_H
#include
#include "Name.h"
#include "Address.h"
using namespace std;
// create a class named Contact
class Contact
{
private:
// private instance variables
Name name;
Address address;
string phone;
public:
// default constructor
Contact()
{
// initialize phone with empty string
phone = "";
}
// parameterized constructor
Contact(string first_name, string last_name, string middle_name, string streetAddress, string
state, string zip, string phone)
{
// initialize name and address to given strings
setName(first_name, last_name, middle_name);
setAddress(streetAddress, state, zip);
// initialize phone to the given parameter
this->phone = phone;
}
/.
PersonData.h#ifndef PersonData_h #define PersonData_h#inclu.pdf
// PersonData.h
#ifndef PersonData_h
#define PersonData_h
#include
#include
#include
using namespace std;
class PersonData {
protected:
//member variables
string lastName; //holds the users last name
string firstName; //holds the users first name
string address; //holds the users address
string city; //holds the users city
string state; //holds the users state
int zip; //holds the users zip code
int phone; //holds the users phone number
public:
//constructors and destructor
PersonData(); //default constructor
PersonData( string ln , string fn , string addr , string c , string s , int z , int p); // overloaded
constructor
~PersonData(){ /*cout << \"The object has been deleted.\" << endl ;*/ } //destructor
//member functions
//returns the users lastName
string getLastName();
//sets the users lastName
void setLastName( string lastN );
//returns the users firstName
string getFirstName();
//sets the users firstName
void setFirstName( string firstN );
//returns the users address
string getAddress();
//sets the users address
void setAddress( string addr );
//returns the users city
string getCity();
//sets the users city
void setCity( string city );
//returns the users state
string getState();
//sets the users state
void setState( string state );
//returns the users zip
int getZip();
//sets the users zip
void setZip( int zip );
//returns the users phone
int getPhone();
//sets the users phone
void setPhone( int phone );
};
#endif /* PersonData_h */
// PersonData.cpp
#include
#include \"PersonData.h\"
using namespace std;
//constructors and destructor
PersonData::PersonData(){
//defining arbitrary values for member variables
string lastName = \"\"; //holds the users last name
string firstName = \"\"; //holds the users first name
string address = \"\"; //holds the users address
string city = \"\"; //holds the users city
string state = \"\"; //holds the users state
int zip = 0; //holds the users zip code
int phone = 0; //holds the users phone number
}//default constructor
PersonData::PersonData( string strln , string name , string stradd , string liveingcity , string
livingstate , int code , int number){
// user defined values for member variables
string lastName = strln; //holds the users last name
string firstName = name; //holds the users first name
string address = stradd; //holds the users address
string city = liveingcity; //holds the users city
string state = livingstate; //holds the users state
int zip = code; //holds the users zip code
int phone = number; //holds the users phone number
}// overloaded constructor
//member functions
//returns the users lastName
string PersonData::getLastName(){
return lastName;
}
//sets the users lastName
void PersonData::setLastName( string lastN ){
lastName = lastN;
}
//returns the users firstName
string PersonData::getFirstName(){
return firstName;
}
//sets the users firstName
void PersonData::setFirstName( string firstN ){
firstName = firstN;
}
//returns the users address
string PersonData::getAddress(){
retur.
Need done for Date Structures please! 4-18 LAB- Sorted number list imp.pdf
Need done for Date Structures please!
4.18 LAB: Sorted number list implementation with linked lists
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node
with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
then output is:
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
then output is:
main.cpp
#include <iostream>
#include <string>
#include <vector>
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector<string> SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector<string> terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = SpaceSplit(inputLine);
// Remove each value
for (auto term : terms) {
double number = stod(term);
cout << "List after removing " << number << ": " << endl;
list.Remove(number.
CONSTRUCTORS, DESTRUCTORS AND OPERATOR OVERLOADING.pptx
Certainly, here's a brief explanation of constructors, destructors, and operator overloading without using code:
Constructors: Constructors are special methods used to initialize objects of a class. They set the initial state of an object when it is created.
Destructors: Destructors are special methods used to clean up resources and perform necessary cleanup when an object is no longer needed or goes out of scope. They ensure proper resource management.
Operator Overloading: Operator overloading is a feature that allows you to define custom behaviors for operators such as +, -, *, /, etc., when they are applied to objects of your class. It enables you to work with objects in a way that is meaningful for your specific class.
Constructors can be of different types:
Default Constructors: Initialize objects with default values.
Parameterized Constructors: Accept arguments to initialize objects with specific values.
Copy Constructors: Create a new object as a copy of an existing object.
Constructor Overloading: A class can have multiple constructors with different parameter lists, providing flexibility in object initialization.
Destructors are executed automatically when an object is destroyed. They are essential for releasing resources like memory, file handles, or network connections, ensuring proper cleanup and preventing resource leaks.
Operator overloading enables you to define how operators work with objects of your class. For instance, you can specify what the + operator does when applied to two objects of your class, allowing for custom operations that make sense in the context of your class's functionality.
In summary, constructors initialize objects, destructors handle cleanup, and operator overloading allows custom operations with operators when working with objects. These features are crucial for building custom classes in object-oriented programming.
in c languageTo determine the maximum string length, we need to .pdf
in c language
To determine the maximum string length, we need to create a new callback function that utilizes
an alternative user data structure. This callback function should adhere to the same format as
demonstrated in the example.
The data provided to our callback consists of:
A node containing the node->data pointer, which will store our string.
A userdata argument, represented as (void *), capable of holding any desired content. We
possess complete control over the content at this pointer location, as it will be whatever value we
have passed. Consequently, we can:
Establish a structure to store any pertinent values we require.
Transmit the address of this structure into the function.
use this code and just add your code where it says TO DO
#include
#include
#include
#include
#include "LLGeneric.h"
/** define the maximum length of a line that we can read */
#defineLINE_BUFFER_SIZE1024
/**
* We can use this as our "user data" to help us calculate the maximum
* length string
*
* Add anything else to this structure that you wish
*/
struct maxData {
size_t maxLenSoFar;
char *maxStringSoFar;
};
/**
* our "user function" or "callback" for printing.
*
* We know what "void *userdata" is going to be because it is
* simply what we pass in at the call below, so it is safe to
* cast back to a FILE * as that is what we passed it.
*
* This is called a "callback" as it "call back into" our own
* code from within a generic routine.
*/
int myFindLongestStringNode(GenericListNode *node, int index, void *userdata)
{
/**
* Add more code here. You will need to:
* - convert the GenericListNode payload in the field "data" to your
* known (char *) type
* - conver the (void *) userdata into your known (struct maxData *)
* type
* - use the fact that you can examine and store the values provided
* through the userdata to see what has been calculated by earlier
* calls to this function and update based on what you see here,
* in order to determine what the longest string is in the whole
* set of nodes.
*/
return 1;
}
int
doListActivities(GenericListNode *list)
{
/** create an instance of our structure for use as the user data */
struct maxData maxDataWorkingStruct;
int nProcessed = 0;
/** initialize our structure -- if you added fields, set them up here */
maxDataWorkingStruct.maxLenSoFar = 0;
maxDataWorkingStruct.maxStringSoFar = NULL;
/**
* TO DO: Iterate using the callback, which should calculate what
* the longest string in the list is
*/
nProcessed = lstPerformIterativeAction(
list, /* pointer to the first list node */
myFindLongestStringNode, /* pointer to our function */
(void *) &maxDataWorkingStruct);
/** print out the result */
printf("The longest string has %ld characters\n",
maxDataWorkingStruct.maxLenSoFar);
printf("The longest string is: %s\n",
maxDataWorkingStruct.maxStringSoFar);
return nProcessed;
}
/**
**Tools provided below here you won't need to edit -- they
**simply process the command line, and load and free the
**generic linked list and the st.
Main issues with the following code-Im not sure if its reading the fil.pdf
Main issues with the following code:Im not sure if its reading the file correctly because its
adding all terms together. In other words the the first line of terms is adding the second line of
terms but thats not my intention. Each line of term should have their own polynomial expression
as shown below
Basic specifications :
The code should add the polynomial numbers using a linked list. Java . Keep in mind the
polynomials will be gotten from a file.
Things to keep in mind the list should be in decending order and traverse the list after
all coefficient/exponent pair Term nodes from one input line have been
inserted.
Here are the specifications
//The Polynomial class would likely have a single private data member (reference to
class Term) called head.
//The Term class would likely have three private data
members (coefficient and exponent of type int) and next of type reference to
Term.
//The latter class would also have the following public methods:
constructor(s), gets and sets for each data member, and perhaps a formatting
method with the special output requirements.
An example of input is 7 1 2 4 6 2 -3 2 -1 -1 3
Negative negative
pair signals the termination
***NO doubly linked list , it should be a single linked list **
Input file contains the following :
7 1 2 4 6 2 -3 2 -1 -1 3 ----> 2x^4 - 3x^2 +6x^2 + 7x
5 1 2 3 6 0 -3 2 -1 -1 3 ----> 2*X^3 + (-3)*X^2 + 5*X + 6 // thats the ouput for one line of the
the file , each line of the file should have one polynomial output
Code
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class Polynomial {
private Term head;
// Constructor for creating an empty polynomial object
public Polynomial() {
head = null;
}
// Method for adding a term to the polynomial, this is inside the polynomial term
public void addTerm(int coefficient, int exponent) {
// Create a new term object
Term newTerm = new Term(coefficient, exponent);
// If the polynomial is empty, set the new term as the head
if (head == null) {
head = newTerm;
} else {
// Traverse the polynomial until we find the correct position for the new term
Term current = head;
Term previous = null;
while (current != null && current.getExponent() > exponent) {
previous = current;
current = current.getNext();
}
// If a term with the same exponent already exists, add the coefficients
if (current != null && current.getExponent() == exponent) {
current.setCoefficient(current.getCoefficient() + coefficient);
} else {
// Otherwise, insert the new term into the polynomial
if (previous == null) {
head = newTerm;
} else {
previous.setNext(newTerm);
}
newTerm.setNext(current);
}
}
// Method for formatting the polynomial as a string
public String toString() {
StringBuilder sb = new StringBuilder();
if (head != null) {
sb.append(head.toString());
Term current = head.getNext();
while (current != null) {
if (current.getCoefficient() > 0) {
sb.append(" + ");
} else {
sb.append(" - ");
}
sb.append(current.toString());
current = cur.
Getting the following errorsError 1 error C2436 {ctor} mem.pdf
Getting the following errors:
Error 1 error C2436: \'{ctor}\' : member function or nested class in constructor initializer list on
line 565
Error 2 error C2436: \'{ctor}\' : member function or nested class in constructor initializer list on
line 761
I need this code to COMPILE and RUN, but I cannot get rid of this error. Please Help!!
#include
#include
#include
#include
using namespace std;
enum contactGroupType
{// used in extPersonType
FAMILY,
FRIEND,
BUSINESS,
UNFILLED
};
class addressType
{
private:
string st_address;
string city;
string state;
int zip;
public:
void print(string, string, string, int)const;
void setStreet(string);
string getStreet()const;
void setCity(string);
string getCity()const;
void setState(string);
string getState()const;
void setZip(int);
int getZip()const;
void set(string, string, string, int);// set all address fields
string get()const;// get address as one concatenated string
addressType();
// ~addressType();
};
class personType
{
private:
string firstName;
string lastName;
public:
void print()const;
void setName(string first, string last);
string getFirstName()const;
string getLastName()const;
string get()const;// return First Last names concatenated
personType & operator=(const personType &);
personType(string, string);
personType();
};
class dateType
{
private:
int dMonth;
int dDay;
int dYear;
public:
void setDate(int month, int day, int year);
int getDay()const;
int getMonth()const;
int getYear()const;
void print()const;
string get()const;// return string representation as DD/MM/YYYY
dateType & operator=(const dateType & d);
dateType(int, int, int);
dateType();
};
class extPersonType :public personType {
private:
addressType address;// added members
dateType birthday;
contactGroupType group;
string phone;
public:
// methods
void setPhone(string);
string getPhone()const;
void setGroup(contactGroupType);
contactGroupType getGroup()const;
void setBirthday(int, int, int);
dateType getBirthday()const;
void print();
string get()const;// return string representation of ext person type
extPersonType & operator=(const extPersonType & p);
string groupToString(contactGroupType)const;
contactGroupType stringToGroup(string)const;
// constructors
extPersonType();
extPersonType(string first, string last);
};
// because we have no arrayListType, we are using our own
// implementation with a small subset of functions
class arrayListType
{
extPersonType array[500];
int size;
public:
arrayListType();
extPersonType & operator[](int i);
void removeLast();// remove last element
void add(const extPersonType &);// add new element
int getSize()const;// get array size
};
class addressBookType :public arrayListType
{
private:
static const char FS = \'\\t\';// field separator in file (TAB char)
int current;// current position
string fileName;// filename
fstream fileStream;// file as fstream
/* filiters */
contactGroupType fltGroup;
string fltFromLast, fltToLast;
dateType fltFromDate, fltTiDate;
/* flags for effective filters */
bool fl.
I have the following code and I need to know why I am receiving the .pdf
Edwards Manufacturing Company purchases two component parts from three different suppliers.
The suppliers have limited capacity, and no one supplier can meet all the company’s needs. In
addition, the suppliers charge different prices for the components. Component price data (in
price per unit) are as follows:
Each supplier has a limited capacity in terms of the total number of components it can supply.
However, as long as Edwards provides sufficient advance orders, each supplier can devote its
capacity to component 1, component 2, or any combination of the two components, if the total
number of units ordered is within its capacity. Supplier capacities are as follows:
If the Edwards production plan for the next period includes 1000 units of component 1 and 800
units of component 2, what purchases do you recommend? That is, how many units of each
component should be ordered from each supplier? Round your answers to the nearest whole
number.
What is the total purchase cost for the components? Round your answer to the nearest dollar.
$ ????SupplierComponent1231$11$10$132$10$11$11
Solution
For component 1:
supplier 2 have minimum cost and capacity 1050.
So all the component 1 (1000) can be purchased from supplier 2.
So, supplier 2 have 50 more capacity.
Now, supplier 1 have minimum cost for component 2 and have capacity of 650.
so, number of component 2 from supplier1 can be 650.
Now, we need 150 more component 2.
supplier 2 and 3 have same cost for component 2.
supllier have only 50 capacity now and supplier have 850.
So, 150 component 2 can be purchased from supplier 3.
Let y be the number of components fromSupplier123TotalcostComponent
1010000100010000Component 265001508008150Total cost18150.
Recommended
So here is the code from the previous assignment that we need to ext.pdf
So here is the code from the previous assignment that we need to extend just follow the
instructions above.
main.cpp
#include
#include "Contact.h"
int main()
{
// create Contact object using parameterized constructor
Contact c1("Barbara", "Liskov", "Huberman", "404 Ridgeway Dr", "NC", "27403", "336-274-
3344");
// show contact details
c1.showContact();
cout << endl;
// create Contact object using default constructor
Contact c2;
// test the overloaded input and output operators
cin >> c2;
cout << endl;
cout << c2;
return 0;
}
Address.h
#ifndef ADDRESS_H
#define ADDRESS_H
#include
using namespace std;
// create a class named Address
class Address
{
private:
// private instance variables
string streetAddress, state, zip;
public:
// default constructor
Address()
{
// initialize instance variables with empty strings
streetAddress = "";
state = "";
zip = "";
}
// parameterized constructor
Address(string streetAddress, string state, string zip)
{
// initialize instance variables to given parameters
this->streetAddress = streetAddress;
this->state = state;
this->zip = zip;
}
// copy constructor
Address(const Address &a)
{
streetAddress = a.streetAddress;
state = a.state;
zip = a.zip;
}
// setters for all instance variables
void setStreetAddress(string streetAddress) { this->streetAddress = streetAddress; }
void setState(string state) { this->state = state; }
void setZip(string zip) { this->zip = zip; }
// getters for all instance variables
string getStreetAddress() { return streetAddress; }
string getState() { return state; }
string getZip() { return zip; }
// method to display the address
void showAddress()
{
cout << streetAddress << "\n"
<< state << " " << zip << endl;
}
// declare the overloaded input and output operators
friend ostream &operator<<(ostream &out, const Address &a);
friend istream &operator>>(istream &in, Address &a);
};
// define the overloaded output operator
ostream &operator<<(ostream &out, const Address &a)
{
out << a.streetAddress << "\n"
<< a.state << " " << a.zip << endl;
return out;
}
// define the overloaded input operator
istream &operator>>(istream &in, Address &a)
{
cout << "Enter street address: ";
getline(in, a.streetAddress);
cout << "Enter state: ";
getline(in, a.state);
cout << "Enter zip: ";
getline(in, a.zip);
return in;
}
#endif
Contact.h
#ifndef CONTACT_H
#define CONTACT_H
#include
#include "Name.h"
#include "Address.h"
using namespace std;
// create a class named Contact
class Contact
{
private:
// private instance variables
Name name;
Address address;
string phone;
public:
// default constructor
Contact()
{
// initialize phone with empty string
phone = "";
}
// parameterized constructor
Contact(string first_name, string last_name, string middle_name, string streetAddress, string
state, string zip, string phone)
{
// initialize name and address to given strings
setName(first_name, last_name, middle_name);
setAddress(streetAddress, state, zip);
// initialize phone to the given parameter
this->phone = phone;
}
/.
PersonData.h#ifndef PersonData_h #define PersonData_h#inclu.pdf
// PersonData.h
#ifndef PersonData_h
#define PersonData_h
#include
#include
#include
using namespace std;
class PersonData {
protected:
//member variables
string lastName; //holds the users last name
string firstName; //holds the users first name
string address; //holds the users address
string city; //holds the users city
string state; //holds the users state
int zip; //holds the users zip code
int phone; //holds the users phone number
public:
//constructors and destructor
PersonData(); //default constructor
PersonData( string ln , string fn , string addr , string c , string s , int z , int p); // overloaded
constructor
~PersonData(){ /*cout << \"The object has been deleted.\" << endl ;*/ } //destructor
//member functions
//returns the users lastName
string getLastName();
//sets the users lastName
void setLastName( string lastN );
//returns the users firstName
string getFirstName();
//sets the users firstName
void setFirstName( string firstN );
//returns the users address
string getAddress();
//sets the users address
void setAddress( string addr );
//returns the users city
string getCity();
//sets the users city
void setCity( string city );
//returns the users state
string getState();
//sets the users state
void setState( string state );
//returns the users zip
int getZip();
//sets the users zip
void setZip( int zip );
//returns the users phone
int getPhone();
//sets the users phone
void setPhone( int phone );
};
#endif /* PersonData_h */
// PersonData.cpp
#include
#include \"PersonData.h\"
using namespace std;
//constructors and destructor
PersonData::PersonData(){
//defining arbitrary values for member variables
string lastName = \"\"; //holds the users last name
string firstName = \"\"; //holds the users first name
string address = \"\"; //holds the users address
string city = \"\"; //holds the users city
string state = \"\"; //holds the users state
int zip = 0; //holds the users zip code
int phone = 0; //holds the users phone number
}//default constructor
PersonData::PersonData( string strln , string name , string stradd , string liveingcity , string
livingstate , int code , int number){
// user defined values for member variables
string lastName = strln; //holds the users last name
string firstName = name; //holds the users first name
string address = stradd; //holds the users address
string city = liveingcity; //holds the users city
string state = livingstate; //holds the users state
int zip = code; //holds the users zip code
int phone = number; //holds the users phone number
}// overloaded constructor
//member functions
//returns the users lastName
string PersonData::getLastName(){
return lastName;
}
//sets the users lastName
void PersonData::setLastName( string lastN ){
lastName = lastN;
}
//returns the users firstName
string PersonData::getFirstName(){
return firstName;
}
//sets the users firstName
void PersonData::setFirstName( string firstN ){
firstName = firstN;
}
//returns the users address
string PersonData::getAddress(){
retur.
Need done for Date Structures please! 4-18 LAB- Sorted number list imp.pdf
Need done for Date Structures please!
4.18 LAB: Sorted number list implementation with linked lists
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node
with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
then output is:
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
then output is:
main.cpp
#include <iostream>
#include <string>
#include <vector>
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector<string> SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector<string> terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = SpaceSplit(inputLine);
// Remove each value
for (auto term : terms) {
double number = stod(term);
cout << "List after removing " << number << ": " << endl;
list.Remove(number.
CONSTRUCTORS, DESTRUCTORS AND OPERATOR OVERLOADING.pptx
Certainly, here's a brief explanation of constructors, destructors, and operator overloading without using code:
Constructors: Constructors are special methods used to initialize objects of a class. They set the initial state of an object when it is created.
Destructors: Destructors are special methods used to clean up resources and perform necessary cleanup when an object is no longer needed or goes out of scope. They ensure proper resource management.
Operator Overloading: Operator overloading is a feature that allows you to define custom behaviors for operators such as +, -, *, /, etc., when they are applied to objects of your class. It enables you to work with objects in a way that is meaningful for your specific class.
Constructors can be of different types:
Default Constructors: Initialize objects with default values.
Parameterized Constructors: Accept arguments to initialize objects with specific values.
Copy Constructors: Create a new object as a copy of an existing object.
Constructor Overloading: A class can have multiple constructors with different parameter lists, providing flexibility in object initialization.
Destructors are executed automatically when an object is destroyed. They are essential for releasing resources like memory, file handles, or network connections, ensuring proper cleanup and preventing resource leaks.
Operator overloading enables you to define how operators work with objects of your class. For instance, you can specify what the + operator does when applied to two objects of your class, allowing for custom operations that make sense in the context of your class's functionality.
In summary, constructors initialize objects, destructors handle cleanup, and operator overloading allows custom operations with operators when working with objects. These features are crucial for building custom classes in object-oriented programming.
in c languageTo determine the maximum string length, we need to .pdf
in c language
To determine the maximum string length, we need to create a new callback function that utilizes
an alternative user data structure. This callback function should adhere to the same format as
demonstrated in the example.
The data provided to our callback consists of:
A node containing the node->data pointer, which will store our string.
A userdata argument, represented as (void *), capable of holding any desired content. We
possess complete control over the content at this pointer location, as it will be whatever value we
have passed. Consequently, we can:
Establish a structure to store any pertinent values we require.
Transmit the address of this structure into the function.
use this code and just add your code where it says TO DO
#include
#include
#include
#include
#include "LLGeneric.h"
/** define the maximum length of a line that we can read */
#defineLINE_BUFFER_SIZE1024
/**
* We can use this as our "user data" to help us calculate the maximum
* length string
*
* Add anything else to this structure that you wish
*/
struct maxData {
size_t maxLenSoFar;
char *maxStringSoFar;
};
/**
* our "user function" or "callback" for printing.
*
* We know what "void *userdata" is going to be because it is
* simply what we pass in at the call below, so it is safe to
* cast back to a FILE * as that is what we passed it.
*
* This is called a "callback" as it "call back into" our own
* code from within a generic routine.
*/
int myFindLongestStringNode(GenericListNode *node, int index, void *userdata)
{
/**
* Add more code here. You will need to:
* - convert the GenericListNode payload in the field "data" to your
* known (char *) type
* - conver the (void *) userdata into your known (struct maxData *)
* type
* - use the fact that you can examine and store the values provided
* through the userdata to see what has been calculated by earlier
* calls to this function and update based on what you see here,
* in order to determine what the longest string is in the whole
* set of nodes.
*/
return 1;
}
int
doListActivities(GenericListNode *list)
{
/** create an instance of our structure for use as the user data */
struct maxData maxDataWorkingStruct;
int nProcessed = 0;
/** initialize our structure -- if you added fields, set them up here */
maxDataWorkingStruct.maxLenSoFar = 0;
maxDataWorkingStruct.maxStringSoFar = NULL;
/**
* TO DO: Iterate using the callback, which should calculate what
* the longest string in the list is
*/
nProcessed = lstPerformIterativeAction(
list, /* pointer to the first list node */
myFindLongestStringNode, /* pointer to our function */
(void *) &maxDataWorkingStruct);
/** print out the result */
printf("The longest string has %ld characters\n",
maxDataWorkingStruct.maxLenSoFar);
printf("The longest string is: %s\n",
maxDataWorkingStruct.maxStringSoFar);
return nProcessed;
}
/**
**Tools provided below here you won't need to edit -- they
**simply process the command line, and load and free the
**generic linked list and the st.
Main issues with the following code-Im not sure if its reading the fil.pdf
Main issues with the following code:Im not sure if its reading the file correctly because its
adding all terms together. In other words the the first line of terms is adding the second line of
terms but thats not my intention. Each line of term should have their own polynomial expression
as shown below
Basic specifications :
The code should add the polynomial numbers using a linked list. Java . Keep in mind the
polynomials will be gotten from a file.
Things to keep in mind the list should be in decending order and traverse the list after
all coefficient/exponent pair Term nodes from one input line have been
inserted.
Here are the specifications
//The Polynomial class would likely have a single private data member (reference to
class Term) called head.
//The Term class would likely have three private data
members (coefficient and exponent of type int) and next of type reference to
Term.
//The latter class would also have the following public methods:
constructor(s), gets and sets for each data member, and perhaps a formatting
method with the special output requirements.
An example of input is 7 1 2 4 6 2 -3 2 -1 -1 3
Negative negative
pair signals the termination
***NO doubly linked list , it should be a single linked list **
Input file contains the following :
7 1 2 4 6 2 -3 2 -1 -1 3 ----> 2x^4 - 3x^2 +6x^2 + 7x
5 1 2 3 6 0 -3 2 -1 -1 3 ----> 2*X^3 + (-3)*X^2 + 5*X + 6 // thats the ouput for one line of the
the file , each line of the file should have one polynomial output
Code
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class Polynomial {
private Term head;
// Constructor for creating an empty polynomial object
public Polynomial() {
head = null;
}
// Method for adding a term to the polynomial, this is inside the polynomial term
public void addTerm(int coefficient, int exponent) {
// Create a new term object
Term newTerm = new Term(coefficient, exponent);
// If the polynomial is empty, set the new term as the head
if (head == null) {
head = newTerm;
} else {
// Traverse the polynomial until we find the correct position for the new term
Term current = head;
Term previous = null;
while (current != null && current.getExponent() > exponent) {
previous = current;
current = current.getNext();
}
// If a term with the same exponent already exists, add the coefficients
if (current != null && current.getExponent() == exponent) {
current.setCoefficient(current.getCoefficient() + coefficient);
} else {
// Otherwise, insert the new term into the polynomial
if (previous == null) {
head = newTerm;
} else {
previous.setNext(newTerm);
}
newTerm.setNext(current);
}
}
// Method for formatting the polynomial as a string
public String toString() {
StringBuilder sb = new StringBuilder();
if (head != null) {
sb.append(head.toString());
Term current = head.getNext();
while (current != null) {
if (current.getCoefficient() > 0) {
sb.append(" + ");
} else {
sb.append(" - ");
}
sb.append(current.toString());
current = cur.
Getting the following errorsError 1 error C2436 {ctor} mem.pdf
Getting the following errors:
Error 1 error C2436: \'{ctor}\' : member function or nested class in constructor initializer list on
line 565
Error 2 error C2436: \'{ctor}\' : member function or nested class in constructor initializer list on
line 761
I need this code to COMPILE and RUN, but I cannot get rid of this error. Please Help!!
#include
#include
#include
#include
using namespace std;
enum contactGroupType
{// used in extPersonType
FAMILY,
FRIEND,
BUSINESS,
UNFILLED
};
class addressType
{
private:
string st_address;
string city;
string state;
int zip;
public:
void print(string, string, string, int)const;
void setStreet(string);
string getStreet()const;
void setCity(string);
string getCity()const;
void setState(string);
string getState()const;
void setZip(int);
int getZip()const;
void set(string, string, string, int);// set all address fields
string get()const;// get address as one concatenated string
addressType();
// ~addressType();
};
class personType
{
private:
string firstName;
string lastName;
public:
void print()const;
void setName(string first, string last);
string getFirstName()const;
string getLastName()const;
string get()const;// return First Last names concatenated
personType & operator=(const personType &);
personType(string, string);
personType();
};
class dateType
{
private:
int dMonth;
int dDay;
int dYear;
public:
void setDate(int month, int day, int year);
int getDay()const;
int getMonth()const;
int getYear()const;
void print()const;
string get()const;// return string representation as DD/MM/YYYY
dateType & operator=(const dateType & d);
dateType(int, int, int);
dateType();
};
class extPersonType :public personType {
private:
addressType address;// added members
dateType birthday;
contactGroupType group;
string phone;
public:
// methods
void setPhone(string);
string getPhone()const;
void setGroup(contactGroupType);
contactGroupType getGroup()const;
void setBirthday(int, int, int);
dateType getBirthday()const;
void print();
string get()const;// return string representation of ext person type
extPersonType & operator=(const extPersonType & p);
string groupToString(contactGroupType)const;
contactGroupType stringToGroup(string)const;
// constructors
extPersonType();
extPersonType(string first, string last);
};
// because we have no arrayListType, we are using our own
// implementation with a small subset of functions
class arrayListType
{
extPersonType array[500];
int size;
public:
arrayListType();
extPersonType & operator[](int i);
void removeLast();// remove last element
void add(const extPersonType &);// add new element
int getSize()const;// get array size
};
class addressBookType :public arrayListType
{
private:
static const char FS = \'\\t\';// field separator in file (TAB char)
int current;// current position
string fileName;// filename
fstream fileStream;// file as fstream
/* filiters */
contactGroupType fltGroup;
string fltFromLast, fltToLast;
dateType fltFromDate, fltTiDate;
/* flags for effective filters */
bool fl.
I have the following code and I need to know why I am receiving the .pdf
Edwards Manufacturing Company purchases two component parts from three different suppliers.
The suppliers have limited capacity, and no one supplier can meet all the company’s needs. In
addition, the suppliers charge different prices for the components. Component price data (in
price per unit) are as follows:
Each supplier has a limited capacity in terms of the total number of components it can supply.
However, as long as Edwards provides sufficient advance orders, each supplier can devote its
capacity to component 1, component 2, or any combination of the two components, if the total
number of units ordered is within its capacity. Supplier capacities are as follows:
If the Edwards production plan for the next period includes 1000 units of component 1 and 800
units of component 2, what purchases do you recommend? That is, how many units of each
component should be ordered from each supplier? Round your answers to the nearest whole
number.
What is the total purchase cost for the components? Round your answer to the nearest dollar.
$ ????SupplierComponent1231$11$10$132$10$11$11
Solution
For component 1:
supplier 2 have minimum cost and capacity 1050.
So all the component 1 (1000) can be purchased from supplier 2.
So, supplier 2 have 50 more capacity.
Now, supplier 1 have minimum cost for component 2 and have capacity of 650.
so, number of component 2 from supplier1 can be 650.
Now, we need 150 more component 2.
supplier 2 and 3 have same cost for component 2.
supllier have only 50 capacity now and supplier have 850.
So, 150 component 2 can be purchased from supplier 3.
Let y be the number of components fromSupplier123TotalcostComponent
1010000100010000Component 265001508008150Total cost18150.
maincpp Build and procees a sorted linked list of Patie.pdf
main.cpp
/*
Build and procees a sorted linked list of Patient objects.
The list is sorted in ascending order by name.
Assume that the name is unique.
*/
#include <iostream>
#include <iomanip>
#include <fstream>
#include <sstream>
#include <string>
#include <cctype>
#include "LinkedList.h"
using namespace std;
void buildList(const string &filename, LinkedList &list);
void deleteManager(LinkedList &list);
void searchManager(const LinkedList &list);
void displayManager(const LinkedList &list);
int main() {
string inputFileName;
LinkedList list;
cout << "Enter file name: ";
getline(cin, inputFileName);
buildList(inputFileName, list);
displayManager(list);
searchManager(list);
deleteManager(list);
displayManager(list);
return 0;
}
/*
This function reads data from a file and inserts them
into a sorted linked list. The list is sorted in ascending order by name
*/
void buildList(const string &filename, LinkedList &list) {
ifstream inFile(filename);
cout << "Reading data from "" << filename << ""n";
if(!inFile) {
cout << "Error opening the input file: ""<< filename << """ << endl;
exit(EXIT_FAILURE);
}
string id;
int year;
string name;
int amount;
string line;
while (getline(inFile, line)) {
stringstream temp(line);
temp >> id >> year;
temp.ignore();
getline(temp, name, ';');
temp >> amount;
// create a Sales object and initialize it with data from file
/* Write your code here */
// call insert to insert this new Sales object into the sorted list
/* Write your code here */
}
inFile.close();
}
/*
Delete manager: delete items from the list until the user enters Q to quit
deleting
Input Parameter: list
*/
void deleteManager(LinkedList &list) {
string target = "";
cout << " Delete" << endl;
cout << "========" << endl;
while(target != "Q") {
cout << "Enter a name (or Q to stop deleting):" << endl;
getline(cin, target);
target[0] = toupper(target[0]);
if(target != "Q") {
if(list.deleteNode(target))
cout << target << " has been deleted!" << endl;
else
cout << target << " not found!" << endl;
}
}
cout << "___________________END DELETE SECTION_____" << endl;
}
/*
Search manager: search the list until the user enters Q to quit searching
Input Parameter: list
*/
void searchManager(const LinkedList &list) {
string target = "";
Sales obj;
cout << " Search" << endl;
cout << "========" << endl;
/* Write your code here */
cout << "___________________END SEARCH SECTION _____" << endl;
}
/*
Display manager: all, average, or year hired reports including header and footer where
appropriate,
depending on the user's choice;
displays the number of nodes (always)
Input Parameter: list
*/
void displayManager(const LinkedList &list) {
// Sub-functions of displayManager()
void showMenu(void);
string getOption(void);
void showHeader(string line);
string line = "==== ==================== =============n";
string option;
showMenu();
option = getOption();
while(option[0] != 'Q') {
switch (option[0]) {
case 'A':
showHeader(line);
list.displayList();
cout << line;
break;
case 'G':
cou.
operating system Ubunut,Linux,Mac filename messageService.cpp.pdf
// operating system Ubunut,Linux,Mac
// filename messageService.cpp
#include
#include // for vector
#include
using namespace std;
/*Main function start*/
int main()
{
std::vector > store;// we are using vector for storing pair of name and message
std::vector >::reverse_iterator it;// used to reverse iteration
std::string name,message,input,choice;// variable for purpose
do{
std::cout<<\"Enter User Name> \";
std::cin>>name;
std::cout<<\"Enter Message> \";// prompt for user input
/* we are taking input from user as string
* if line contains $$ then it will break and come out from loop
* otherwise it will create pair and insert it into vector*/
while(std::getline(std::cin,input)){
if(input==\"$$\")
break;
message+=input+\"\ \";
}
store.push_back(std::pair(name,message));// inserting pair into vector
message=\"\";
std::cout<<\"Any More Users? > \";
std::cin>>choice;
}while(choice==\"yes\");
/*while loop break if choice value other then \"yes\" */
std::cout << \"The current messages are: \ \";
/*Iterating vector in reverse order for printing desirable output*/
for (it=store.rbegin(); it!=store.rend(); ++it){
std::cout << it->first << \" >> \"<second << \'\ \';
}
return 0;
}
/*Main function End*/
/*Output*/
gopal@gopal:~/Desktop/chegg$ g++ messageService.cpp
gopal@gopal:~/Desktop/chegg$ ./a.out
Enter User Name> Kate
Enter Message> Get in the loop and join our War Eagle group!
Sunner in st. John\'s islands was fun.
How was your summer?
$$
Any More Users? > yes
Enter User Name> Daniel
Enter Message> I\'m in!
$$
Any More Users? > yes
Enter User Name> Joey
Enter Message> Count me in.
We were in Tokyo; intersting!
$$
Any More Users? > yes
Enter User Name> Kevin
Enter Message> What\'s new?
we had a great time in the Outback.
$$
Any More Users? > no
The current messages are:
Kevin >>
What\'s new?
we had a great time in the Outback.
Joey >>
Count me in.
We were in Tokyo; intersting!
Daniel >>
I\'m in!
Kate >>
Get in the loop and join our War Eagle group!
Sunner in st. John\'s islands was fun.
How was your summer?
Solution
// operating system Ubunut,Linux,Mac
// filename messageService.cpp
#include
#include // for vector
#include
using namespace std;
/*Main function start*/
int main()
{
std::vector > store;// we are using vector for storing pair of name and message
std::vector >::reverse_iterator it;// used to reverse iteration
std::string name,message,input,choice;// variable for purpose
do{
std::cout<<\"Enter User Name> \";
std::cin>>name;
std::cout<<\"Enter Message> \";// prompt for user input
/* we are taking input from user as string
* if line contains $$ then it will break and come out from loop
* otherwise it will create pair and insert it into vector*/
while(std::getline(std::cin,input)){
if(input==\"$$\")
break;
message+=input+\"\ \";
}
store.push_back(std::pair(name,message));// inserting pair into vector
message=\"\";
std::cout<<\"Any More Users? > \";
std::cin>>choice;
}while(choice==\"yes\");
/*while loop break if choice value other then \"yes\.
FUNCTIONS, CLASSES AND OBJECTS.pptx
Functions, classes, and objects are fundamental concepts in object-oriented programming. Here's a brief explanation of each:
Functions:
Functions are blocks of code that perform specific tasks or computations.
They encapsulate a set of instructions and can take parameters (input) and return values (output).
Functions are reusable, promoting code modularity and maintainability.
Classes:
Classes are blueprints or templates for creating objects.
They define the structure and behavior of objects by specifying attributes (data members) and methods (functions) that the objects will have.
Classes serve as a model for creating multiple instances (objects) with similar characteristics.
Objects:
Objects are instances of classes.
They are concrete representations of the class's blueprint, with their own unique data values and the ability to perform actions using the methods defined in the class.
Objects are used to model and manipulate real-world entities in code.
In summary, functions are used to define specific tasks or operations, classes serve as templates for creating objects with shared attributes and behaviors, and objects are instances of classes that represent real-world entities and can interact with their environment. These concepts are central to object-oriented programming and software development.
write the To Dos to get the exact outputNOte A valid Fraction .pdf
write the To Do\'s to get the exact output:
NOte: A valid Fraction number has a non-negative numerator and a positive denominator.
Default constructor initializes the object to safe empty state (an object with denom equals -1).
The two-argument constructor also validates the parameters and sets the object to the safe empty
state if the parameters are not valid.
Write the definitions and prototypes of following functions in Fraction.cpp and Fraction.h
respectively (They are indicated in the files by //TODO tag):
Define isEmpty function as a member function, which returns true if the object is in safe empty
state (an object is in the safe empty state if denominator (denom) equals -1).
Define display function, which sends a Fraction number to the output stream (with the
“Numerator/denominator” format). This function just prints \"Invalid Fraction Object!\" in the
screen if the object is in the safe empty state. In case that object denominator equals 1, it just
print the numerator.
Define the operator functions for the following operators:
“+=”, “+”, “*”
The overload of the above operators should make the following code possible:
The member operator+ : Adds two Fraction numbers and returns a Fraction number as the result.
This function returns an object with the safe empty state if either of Fraction numbers (operands)
is in safe empty state. It makes following code possible:
A+B ( where A and B are Fraction objects)
The member operator+= : Adds two Fraction numbers and assigns the result to the left operand,
then returns a reference to the left operand. If either of Fraction numbers (operands) is in safe
empty state, it initializes the left operand to the safe empty state, then returns a reference to the
left operand. It makes following code possible:
A+=B ( where A and B are Fraction objects)
The member operator* : Multiplies two Fraction numbers and returns a Fraction number as the
result. This function returns an object with the safe empty state if either of Fraction numbers
(operands) is in safe empty state. It makes following code possible:
A*B ( where A and B are Fraction objects)
fraction.cpp
#include \"Fraction.h\"
using namespace std;
namespace sict{
Fraction::Fraction(){
denom =-1; // safe empty state
}
Fraction::Fraction(int n, int d) // n: numerator, d: denominator
{
if(n >= 0 && d > 0){
num = n;
denom = d;
reduce();
}
else
denom =-1; // set to safe empty state
}
int Fraction::gcd() // returns the greatest common divisor of num and
denom
{
int mn = min(); // min of num and denom
int mx = max(); // mX of num and denom
for (int x=mn ; x > 0 ; x--) // find the greatest common divisor
if( mx % x == 0 && mn % x == 0)
return x;
return 1;
}
void Fraction::reduce() // simplify the Fraction number
{
int tmp = gcd();
num /= tmp;
denom /= tmp;
}
int Fraction::max ()
{
return (num >= denom) ? num : denom;
}
int Fraction::min()
{
return (num >= denom) ? denom : num;
}
// in_lab
// TODO: write the implementation of display function HERE
// TODO: w.
Assignment isPage 349-350 #4 and #5 Use the Linked List lab.pdf
Assignment is:
\"Page 349-350 #4 and #5 Use the \"Linked List lab\" you have been working on in class and add
the two functions the questions are asking you to develop: divideMid and divideAt. Be sure to
include comments Use meaningful identifier names (constants where appropriate) Turn in .cpp
file AND Turn in a \"print-screen\' of your output (press \"print-screen\' on keyboard, then
\'paste\' in MS-Word)\"
How do you solve QUESTION #4 in the book data structures using c++ by D.S. Malik in Visiual
Studios using the linked list below with what is being asked? Please need help
Linked list :
#include
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *first, *last;
int num;
createList(first, last);
int choice;
while(true)
{
cout<<\"1. Insert Front.\ 2. Insert Last.\ 3. Delete Front.\ 4. Delete Last.\ 5. Print List.\ 6. Exit.\
\";
cout<<\"Enter your choice: \";
cin>>choice;
switch(choice)
{
case 1: insertFront(first); break;
case 2: insertBack(last); break;
case 3: deleteFirst(first); break;
case 4: deleteLast(last, first); break;
case 5: printList(first); break;
case 6: return 0;
default: cout<<\"Invalid menu option. Try again.\"<>number;
while (number != -999)
{
newNode = new nodeType; // create new node
newNode->info = number;
newNode->link = NULL;
if (first == NULL)
{
first = newNode;
last = newNode;
}
else
{
last->link = newNode;
last = newNode;
}
cout<<\"Enter an integer (-999 to stop): \";
cin>>number;
} // end of while-loop
} // end of build list function
void deleteFirst(nodeType*& first)
{
nodeType *temp;
temp= first;
first= temp->link;
delete temp;
return;
}
void deleteLast(nodeType*& last, nodeType* current)
{
nodeType *temp;
while(current->link != NULL)
{
temp=current;
current=current->link;
}
temp=last;
current->link=NULL;
delete temp;
last = current;
return;
}
void insertFront(nodeType*& front)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= front;
front= newNode;
return;
}
void insertBack(nodeType*& last)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= NULL;
last->link= newNode;
last = newNode;
return;
}
void printList(nodeType*& first)
{
cout<<\"Inside printList...printing linked list...\ \"<info << \" \";
current = current->link;
}
cout<
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *firs.
Assignment is Page 349-350 #4 and #5 Use the Linked Lis.pdf
Assignment is :
\"Page 349-350 #4 and #5 Use the \"Linked List lab\" you have been working on in class and add
the two functions the questions are asking you to develop: divideMid and divideAt. Be sure to
include comments Use meaningful identifier names (constants where appropriate) Do not work
together; no two people should have identical work!?!? Turn in .cpp file AND Turn in a \"print-
screen\' of your output (press \"print-screen\' on keyboard, then \'paste\' in MS-Word)\"
How do you solve QUESTION #5 in the book data structures using c++ by D.S. Malik in Visiual
Studios using the linked list below with what is being asked? Please need help
Linked list :
#include
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *first, *last;
int num;
createList(first, last);
int choice;
while(true)
{
cout<<\"1. Insert Front.\ 2. Insert Last.\ 3. Delete Front.\ 4. Delete Last.\ 5. Print List.\ 6. Exit.\
\";
cout<<\"Enter your choice: \";
cin>>choice;
switch(choice)
{
case 1: insertFront(first); break;
case 2: insertBack(last); break;
case 3: deleteFirst(first); break;
case 4: deleteLast(last, first); break;
case 5: printList(first); break;
case 6: return 0;
default: cout<<\"Invalid menu option. Try again.\"<>number;
while (number != -999)
{
newNode = new nodeType; // create new node
newNode->info = number;
newNode->link = NULL;
if (first == NULL)
{
first = newNode;
last = newNode;
}
else
{
last->link = newNode;
last = newNode;
}
cout<<\"Enter an integer (-999 to stop): \";
cin>>number;
} // end of while-loop
} // end of build list function
void deleteFirst(nodeType*& first)
{
nodeType *temp;
temp= first;
first= temp->link;
delete temp;
return;
}
void deleteLast(nodeType*& last, nodeType* current)
{
nodeType *temp;
while(current->link != NULL)
{
temp=current;
current=current->link;
}
temp=last;
current->link=NULL;
delete temp;
last = current;
return;
}
void insertFront(nodeType*& front)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= front;
front= newNode;
return;
}
void insertBack(nodeType*& last)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= NULL;
last->link= newNode;
last = newNode;
return;
}
void printList(nodeType*& first)
{
cout<<\"Inside printList...printing linked list...\ \"<info << \" \";
current = current->link;
}
cout<
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void dele.
OverviewWe will be adding some validation to our Contact classes t.pdf
On March 4 of the current year, Barefoot Bay, Inc. reacquired 5,000 shares of its common stock
at $89 per share. On August 7, Barefoot Bay sold 3,500 of the reacquired shares at $100 per
share. The remaining 1,500 shares were sold at $88 per share on November 29.
1. Journalize the transactions of March 4, August 7, and November 29. If an amount box does
not require an entry, leave it blank or enter \"0\".
2. What is the balance in Paid-in Capital from Sale of Treasury Stock on December 31 of the
current year?
$Mar. 4Aug. 7Nov. 29
Solution
4-Mar Treasury stock 445000 =5000*89 Cash 445000 7-Aug Cash 350000
=3500*100 Treasury stock 311500 =3500*89 Paid in capital-Treasury stock
38500 29-Nov Cash 132000 =1500*88 Paid in capital-Treasury stock 1500
Treasury stock 133500 =1500*89 2 Balance in Paid-in Capital from Sale of Treasury
Stock = 38500-1500 = $37000.
Frequency .java Word frequency counter package frequ.pdf
Frequency .java
/**
* Word frequency counter
*/
package frequency;
import java.util.Iterator;
/**
*
* @author UMD CS
*/
public class Frequency implements Iterable{
private Node first;
private int N;
Frequency(){
N = 0;
first = null;
}
@Override
public Iterator iterator() {
return new ListIterator();
}
/**
*
* List iterator
*
*/
private class ListIterator implements Iterator{
private Node current;
private int index ;
ListIterator(){
current = first;
index = 0;
}
@Override
public boolean hasNext() {
return current != null;
}
public String next() {
if(!hasNext()){
return null;
}
String word = current.key;
int count = current.count;
String r = \"(\"+word + \",\" + Integer.toString(count)+\")\";
current = current.next;
return r;
}
@Override
public void remove() {
}
}
/**
*
* Node class
*
*/
private class Node {
private String key;
private int count;
private Node next;
Node(String item){
key = item;
count = 1;
next = null;
}
@Override
public String toString(){
return \"(\"+key +\",\"+count+\")\";
}
}
/*
* Inserts a word into the linked list. If the word exists, increment the
* count by q.
*/
public void insert(String word){
if(word.equals(\"\")){
return;
}
//TODO
/*
* implement here
*/
}
/**
*
* @param str input string
* This method splits a string into words and pass the words to insert method
*
*/
public void insertWords(String str){
String delims = \"[ .,?!\'\\\"()}{;/<>&=#-:\\\\ _]+\";
String[] words = str.split(delims);
for(String s: words){
s = s.toLowerCase();
insert(s);
}
}
/**
* prints the word frequency list
*/
public void print(){
Node c = first;
while(c != null){
System.out.print(\"(\"+c.key + \",\" + c.count+\")\");
c = c.next;
}
System.out.print(\"\ \");
}
}
--------------------------------------------------------------------------------------------------------------------
------------------------------------------------------
WordFrequency.java
package frequency;
import utils.In;
import utils.Stopwatch;
/**
*
* @author UMD CS
*/
public class WordFrequency {
/**
* @param input source
* @param
* This method receives input resource and return the word frequency string
* DO NOT CHANGE THIS METHOD.
*/
public static String freq(String inputSource, int maxLines){
In in;
// Frequency class can only count the frequency of strings. DO NOT CHANGE THIS.
Frequency freq = new Frequency();
int MAX = 100;
String inputSourceName = inputSource;
try {
in = new In(inputSourceName);
while (!in.isEmpty()) {
String s = in.readLine();
//System.out.println(s);
freq.insertWords(s);
}
}
catch (Exception e) {
e.printStackTrace();
}
StringBuilder strFrequency = new StringBuilder();
int cnt = 0;
for(String s: freq){
strFrequency.append(s);
strFrequency.append(\",\");
cnt++;
if(cnt >= maxLines){break;}
}
return strFrequency.toString();
}
/**
*
*/
public static void main(String[] args) {
In in;
Frequency freq = new Frequency();
int MAX = 100;
// String inputSourceName =
\"http://www.cs.umd.edu/class/summer2015/cmsc132/projects/P3_WordFrequency/test1.html\";
String .
Hey, I need some help coding this C++ assignment.ObjectivesThis.pdf
Hey, I need some help coding this C++ assignment.
Objectives:
This assignment will access your C++ language skills. After completing this assignment you will
be able to do the following:
(1) allocate memory dynamically (2) implement a default, explicit-value and copy constructor,
(3) a destructor, (4)parse string, (5) identify substrings in a string, and (6) fully implement and
manage a string class.
In this assignment you will implement the WORD ADT (abstract data type) using a singly-linked
list of characters. The WORD ADT is defined below. Call the class you implement \"WORD\".
Remember, a singly-linked list is composed of nodes. You will also implement a class called
\"character\" that has two fields: a char field called \"symbol\"; and a pointer field called \"next\".
Essentially, each character is really a node in the list. Each node (character) in the list (word) will
contain one alpha/numeric character of a word. Consider the following declaration of a character.
A WORD is composed of characters:
class character
{
public:
char symbol;
character *next;
};
The state (private data members) of your WORD class should contain a pointer to the front of the
list of characters called \"front\" and a pointer to the back of the list called \"back\". You may add
more members to the state and more member functions to the behavior of the class if you
determine necessary. Store the definition of your class in a file called \"word.cpp.\" and the
declaration of your class in a file called \"word.h .\" You will implement all the code necessary
to maintain a word. See the ADT below. Test the complete functionality of the class WORD.
Use the file \"word_driver.cpp\" as a guide to help you understand and test all the functionality
of the class. If you discover that you need more tests while implementing the functionality of
WORD, then add more tests to your driver.
ADT---WORD
Data:
A set of characters
Operations:
1. IsEmpty: Check to see if the word A is empty; A is the current object;
2. Length: Determines the length of the word A; remember A is the current object;
6. operator<<: Overload the insertion operator as a friend function with chaining to print a word
A;
7. operator= : Overload the assignment operator as a member function to take a string (C-style or
C++ string, just be consistent in your implementation) as an argument and assigns its value to A,
the current object;
8. operator= : Overload the assignment operator as a member function with chaining to take a
word object as an argument and assigns its value to A, the current object;
9. operator+: Overload the ‘+” operator as a member function without chaining to add word B
(adds the set of symbols that makep B\'s linked list to the back of A\'s linked list) to the back of
word A; remember A is the current object;
10. Default constructor: The default constructor will initialize your state variables. The front of
the linked list is initially set to NULL or 0; this implies a non-header node implemen.
Task #1 Correcting Logic Errors in FormulasCopy and compile the so.pdf
Task #1 Correcting Logic Errors in Formulas
Copy and compile the source file NumericTypes.java, run the program, and observe the output.
Some of the output is incorrect. You need to correct logic errors in the average formula and the
temperature conversion formula. The logic errors could be due to conversion between data types,
order of operations, or formula problems. The necessary formulas are
average = (score1+score2) / numberOfScores
C = 5/9 (F-32)
Make sure that the output makes sense before you continue. The average of 95 and 100 should be
97.5 and the temperature that water boils is 100 degrees Celsius
Task #2 Using the Scanner Class for User Input
1. Add an import statement above the class declaration to make the Scanner
class available to your program.
2. In the main method, create a Scanner object and connect it to the System.in
object.
3. Prompt the user to enter his or her first name.
4. Read the name from the keyboard using the nextLine method, and store it into
a variable called firstName (you will need to declare any variables you use).
5. Prompt the user to enter his or her last name.
6. Read the name from the keyboard and store it in a variable called lastName.
7. Concatenate the firstName and lastName with a space between them and
store the result in a variable called fullName.
8. Print out the fullName.
9. Compile, debug, and run, using your name as test data.
10. Since we are adding on to the same program, each time we run the program we
will get the output from the previous tasks before the output of the current task.
Task #3 Working with Strings
1. Use the charAt method to get the first character in firstName and store it in a
variable called firstInitial (you will need to declare any variables that you
use).
2. Print out the user’s first initial.
3. Use the toUpperCase method to change the fullName to uppercase and store
it back into the fullName variable.
4. Add a line that prints out the value of fullName and how many characters
(including the space) are in the string stored in fullName (use the length
method to obtain that information).
5. Compile, debug, and run. The new output added on after the output from the
previous tasks should have your initials and your full name in uppercase
characters.
Task #4 Using Predefined Math Functions
Task #4 UsingPredefined Math Functions
Add a line that prompts the user to enter the diameter of a sphere.
Read in and store the number into a variable called diameter (you will need to declare any
variables that you use).
The diameter is twice as long as the radius, so calculate and store the radius in an appropriately
named variable.
The formula for the volume of a sphere is
r3
Convert the formula to Java and add a line which calculates and stores the value of volume in an
appropriately named variable. Use Math.PI for and Math.pow to cube the radius.
Print your results to the screen with an appropriate message.
Compile, debug, and run using the following test data and record the resu.
could you implement this function please, im having issues with it..pdf
could you implement this function please, im having issues with it.
void makeList (const ListNode::value_type [],const size_t& count)
class ListNode
{
public:
typedef int value_type;
ListNode (value_type d = value_type(), ListNode* n = NULL) { datum = d; next = n; }
//Assessor
value_type getDatum () const { return datum; }
ListNode const* getNext () const { return next; }
//Mutator
void setDatum (const value_type& d) {datum = d; }
ListNode* getNext () { return next; }
void setNext (ListNode* new_link) {next = new_link; }
private:
value_type datum;
ListNode* next;
};
class LinkedList
{
public:
LinkedList ();
virtual ~LinkedList ();
void insertItem (ListNode::value_type);
void makeList (const ListNode::value_type [],const size_t& count);
void deleteList ();
//The following friend function is implemented in lablinklist.cpp
friend std::ostream& operator<<(std::ostream&, const LinkedList&);
private:
ListNode* head;
};
This is the pseudocode, but i still have a hard time undertanding it.
Creating a List (makeList(const ListNode::value_type [],const size_t& count)) This function
receives an array in the order that we want to add it to the linkedlist. Index 0 will be the head
node, index n will be the last node.
First, create a node initialized with a data value and a NULL pointer. Set the \"head\" to point to
the first node. Set up a current-pointer to the first node (or \"head\"). Get a data value for the next
node. While more nodes to add { Create a new node initialized with the data value and a NULL
pointer. Set the current-pointer link member (\"next\") to the new node. Set the current-pointer to
point to the new node. Get a data value for the next node. }
Thanks.
Solution
//linkedList.h
#ifndef LINKEDLIST_H
#define LINKEDLIST_H
#include
#include
class ListNode
{
public:
typedef int value_type;
ListNode(value_type d = value_type(), ListNode* n = NULL) { datum = d; next = n; }
//Assessor
value_type getDatum() const { return datum; }
ListNode const* getNext() const { return next; }
//Mutator
void setDatum(const value_type& d) { datum = d; }
ListNode* getNext() { return next; }
void setNext(ListNode* new_link) { next = new_link; }
private:
value_type datum;
ListNode* next;
};
class LinkedList
{
public:
LinkedList();
virtual ~LinkedList();
void insertItem(ListNode::value_type);
void makeList(const ListNode::value_type[], const size_t& count);
void deleteList();
//The following friend function is implemented in lablinklist.cpp
friend std::ostream& operator<<(std::ostream&, const LinkedList&);
private:
ListNode* head;
};
#endif
-------------------------------------------------------------
//linkedList.cpp
#include \"linkedlist.h\"
LinkedList::LinkedList()
{
head = NULL;
}
LinkedList::~LinkedList()
{
ListNode *tmp = head;
while (tmp != NULL)
{
head = head->getNext();
delete tmp;
tmp = head;
}
}
void LinkedList::insertItem(ListNode::value_type item)
{
ListNode *newNode,*cur = head;
newNode = new ListNode;
newNode->setDatum(item);
newNode->setNext(NULL);.
#include iostream #includeData.h #includePerson.h#in.pdf
#include
#include\"Data.h\"
#include\"Person.h\"
#include\"Report.h\"
#include
#include
#include \"Menu.h\"
using namespace std;
/*
Programmers: Javier A. Molina, Eduardo Bonnet
Students #:79249
*/
int main()
{
int cnt;
int idx;
string fileName;
Report * telefonia;
Menu menu(\"Reports\");
bool fileNameExists(string fileName);
Report * addReport(Report * reports, int & totalReports);
Report * delReport(Report * reports, int & totalReports, int idx);
int displayReports(Report * reports, int totalReports);
menu.addItem(\"New report\");
menu.addItem(\"Delete a report\");
menu.addItem(\"Display a report\");
cnt = 0;
telefonia = NULL;
do {
cout << menu;
cin >> menu;
//cls();
switch (menu.getOption()) {
case 1:
cout << \"Enter report name (TE?????): \";
cin >> fileName;
if (fileNameExists(fileName + \".tel\")) {
telefonia = addReport(telefonia, cnt);
idx = cnt - 1;
telefonia[idx].setFileName(fileName);
// telefonia[idx].loadReport();
}
else {
cls();
cerr << \"Error: Report name \'\" << fileName << \"\' does not exists!\ \ \ \";
//pause();
}
break;
case 2:
if (telefonia != NULL) {
do {
cls();
cout << \"Delete a Report:\ \ \";
idx = displayReports(telefonia, cnt);
if (between(idx, 0, cnt - 1)) {
cls();
telefonia = delReport(telefonia, cnt, idx);
idx = 0;
// pause();
}
} while (idx != cnt);
}
else {
cerr << \"No reports available for deleting!\ \ \ \";
//pause();
}
break;
case 3:
char ans;
if (telefonia != NULL) {
do {
// cls();
cout << \"Display/Filed a Report:\ \ \";
idx = displayReports(telefonia, cnt);
if (between(idx, 0, cnt - 1)) {
// cls();
cout << \"Would you like the report to be display otherwise save into a file? \";
cin >> ans;
cls();
cin.ignore();
if (upper(ans) == \'Y\') {
cout << telefonia[idx] << endl;
}
else {
//telefonia[idx].saveReport();
cout << \"Report \'\" << telefonia[idx].getFileName() << \"\' saved as \'\" <<
telefonia[idx].getFileName() << \".rep\'.\ \ \";
}
//pause();
}
} while (idx != cnt);
}
else {
cerr << \"No reports available for displaying!\ \ \ \";
// pause();
}
break;
case 4:
cout << \"Thanks for using Telefonia Reports System!!!\ \ \ \";
break;
}
} while (menu.getLast() != menu.getOption());
delete[] telefonia;
return 0;
}
//Funcion que verifica si existe un archivo en disco
bool fileNameExists(string fileName) {
ifstream fin(fileName.c_str());
bool exists = !(fin.fail());
if (exists) fin.close();
return(exists);
}
//Anade dinamicamente objetos tipo Report al arreglo reports
Report * addReport(Report * reports, int & totalReports) {
if (totalReports == 0) {
reports = new Report[1];
}
else {
Report * tmp = new Report[totalReports];
for (int i = 0; i < totalReports; ++i) {
tmp[i] = reports[i];
}
delete[] reports;
reports = new Report[totalReports + 1];
for (int i = 0; i < totalReports; ++i) {
reports[i] = tmp[i];
}
delete[] tmp;
}
totalReports++;
return(reports);
}
//Borra objetos del arreglo reports segun el idx enviado
Report * delReport(Report * reports, int & totalReports, int idx) {
Report * tmp = new Report[tota.
Help with the following code1. Rewrite to be contained in a vecto.pdf
Help with the following code:
1. Rewrite to be contained in a vector object.
2. Using linked lists, redo to handle as many entries as required.
3. Add the ability to add or delete a new entry to the address book.
4. When the program terminates, write the data in the address book to a disk.
# include
# include
# include
using namespace std;
class addressbook
{
private:
char name[500];
long ph_num; //class addressType :public addressbook
char address[500];
int year;
int mounth;
int day;
char gender;
int d, Th, y;
char M, F, m, f;
// char freind[];
public:
addressbook();
void setName();
void getName();
void getphone();
long setphone();
void setAddress();
void getAddress();
float getAverage();
int setDay();
void getDay();
int setMounth();
void getMounth();
int setYear();
void getYear();
char setGender();
void getGender();
};
addressbook::addressbook() // constructor
{
name;
ph_num = 0;
year = 0;
mounth = 0;
day = 0;
}
int addressbook::setDay()
{
cout << \"\ \\tEnter the day:\ \\t\" << endl;
cin >> d;
day = (d >= 1 && d<32) ? d : 0;
return day;
}
int addressbook::setMounth()
{
cout << \"\ \\tEnter the mounth:\ \\t\" << endl;
cin >> m;
mounth = (Th >= 1 && Th<13) ? Th : 0;
return mounth;
}
int addressbook::setYear()
{
cout << \"\ \\tEnter the year :\ \\t\" << endl;
cin >> y;
year = (y >= 1 && y<2008) ? y : 0;
return year;
}
void addressbook::getMounth()
{
cout << mounth << \"/\";
}
void addressbook::getDay()
{
cout << \"\\tBIRTH DAY : \" << day << \"/\";
}
void addressbook::getYear()
{
cout << year;
}
char addressbook::setGender()
{
int flag = 0;
cout << \" \ \\tEnter the gender,(F)for female (M)for male:\ \\t\";
cin >> gender;
while (flag != 1)
{
if (gender == (\'F\') || gender == (\'M\') || gender == (\'m\') || gender == (\'f\'))
flag = 1;
else
{
cout << \"\\t error.....Try Again\ \\t\";
cin >> gender;
return gender;
}
}
}
void addressbook::getGender()
{
cout << \"\\tGender : \" << gender << endl;
}
void addressbook::getAddress()
{
cout << \"\\tAddress : \" << address << endl;
}
float addressbook::getAverage()
{
return 0.0f;
}
void addressbook::setAddress()
{
cout << \" \ \\tEnter the address:\ \\t\" << endl;
gets_s(address);
}
void addressbook::setName()
{
cout << \" \\tEnter the name:\ \\t\" << endl;
gets_s(name);
}
void addressbook::getName()
{
cout << \"\ \\tName : \" << name << \" \" << endl;
}
long addressbook::setphone()
{
cout << \" \ \\tEnter the person number:\ \\t\" << endl;
cin >> ph_num;
return ph_num;
}
void addressbook::getphone()
{
cout << \"\\tPerson # : \" << ph_num << endl;
}
/*class addressType :public addressbook
{
do that
};*/
int main()
{
int s;
cout << \" Enter number person max(500): \";
cin >> s;
addressbook book[10];
for (int i = 1; i<2; i++)
{
book[i].setName();
book[i].setphone();
book[i].setAddress();
book[i].setDay();
book[i].setMounth();
book[i].setYear();
book[i].setGender();
cout << \"\ \ ***********************************\ \";
}
for (int u = 0; u<2; u++)
{
book[u].getName();
book[u].getphone();
book[u].getAddre.
Using Martelle�s Chapters 12-14, please describe the impact of WWII .pdf
Using Martelles Chapters 12-14, please describe the impact of WWII on life in Detroit. How did
things improve (over the GD)? What happened when African Americans started moving beyond
the boundaries of segregated neighborhoods? What was the impact of the post-WWII boom on
the city? Finally, what were two errors, according to Martelle, that took place post WWII that
set up the city for catastrophe in subsequent decades?.
Using htmljscss, recreate the sliders. I have attached all images..pdf
Using html/js/css, recreate the sliders. I have attached all images. Please post screenshot to show
it works. OIL $25
A).
More Related Content
Similar to Use the code below from the previous assignment that we need to exte.pdf
maincpp Build and procees a sorted linked list of Patie.pdf
main.cpp
/*
Build and procees a sorted linked list of Patient objects.
The list is sorted in ascending order by name.
Assume that the name is unique.
*/
#include <iostream>
#include <iomanip>
#include <fstream>
#include <sstream>
#include <string>
#include <cctype>
#include "LinkedList.h"
using namespace std;
void buildList(const string &filename, LinkedList &list);
void deleteManager(LinkedList &list);
void searchManager(const LinkedList &list);
void displayManager(const LinkedList &list);
int main() {
string inputFileName;
LinkedList list;
cout << "Enter file name: ";
getline(cin, inputFileName);
buildList(inputFileName, list);
displayManager(list);
searchManager(list);
deleteManager(list);
displayManager(list);
return 0;
}
/*
This function reads data from a file and inserts them
into a sorted linked list. The list is sorted in ascending order by name
*/
void buildList(const string &filename, LinkedList &list) {
ifstream inFile(filename);
cout << "Reading data from "" << filename << ""n";
if(!inFile) {
cout << "Error opening the input file: ""<< filename << """ << endl;
exit(EXIT_FAILURE);
}
string id;
int year;
string name;
int amount;
string line;
while (getline(inFile, line)) {
stringstream temp(line);
temp >> id >> year;
temp.ignore();
getline(temp, name, ';');
temp >> amount;
// create a Sales object and initialize it with data from file
/* Write your code here */
// call insert to insert this new Sales object into the sorted list
/* Write your code here */
}
inFile.close();
}
/*
Delete manager: delete items from the list until the user enters Q to quit
deleting
Input Parameter: list
*/
void deleteManager(LinkedList &list) {
string target = "";
cout << " Delete" << endl;
cout << "========" << endl;
while(target != "Q") {
cout << "Enter a name (or Q to stop deleting):" << endl;
getline(cin, target);
target[0] = toupper(target[0]);
if(target != "Q") {
if(list.deleteNode(target))
cout << target << " has been deleted!" << endl;
else
cout << target << " not found!" << endl;
}
}
cout << "___________________END DELETE SECTION_____" << endl;
}
/*
Search manager: search the list until the user enters Q to quit searching
Input Parameter: list
*/
void searchManager(const LinkedList &list) {
string target = "";
Sales obj;
cout << " Search" << endl;
cout << "========" << endl;
/* Write your code here */
cout << "___________________END SEARCH SECTION _____" << endl;
}
/*
Display manager: all, average, or year hired reports including header and footer where
appropriate,
depending on the user's choice;
displays the number of nodes (always)
Input Parameter: list
*/
void displayManager(const LinkedList &list) {
// Sub-functions of displayManager()
void showMenu(void);
string getOption(void);
void showHeader(string line);
string line = "==== ==================== =============n";
string option;
showMenu();
option = getOption();
while(option[0] != 'Q') {
switch (option[0]) {
case 'A':
showHeader(line);
list.displayList();
cout << line;
break;
case 'G':
cou.
operating system Ubunut,Linux,Mac filename messageService.cpp.pdf
// operating system Ubunut,Linux,Mac
// filename messageService.cpp
#include
#include // for vector
#include
using namespace std;
/*Main function start*/
int main()
{
std::vector > store;// we are using vector for storing pair of name and message
std::vector >::reverse_iterator it;// used to reverse iteration
std::string name,message,input,choice;// variable for purpose
do{
std::cout<<\"Enter User Name> \";
std::cin>>name;
std::cout<<\"Enter Message> \";// prompt for user input
/* we are taking input from user as string
* if line contains $$ then it will break and come out from loop
* otherwise it will create pair and insert it into vector*/
while(std::getline(std::cin,input)){
if(input==\"$$\")
break;
message+=input+\"\ \";
}
store.push_back(std::pair(name,message));// inserting pair into vector
message=\"\";
std::cout<<\"Any More Users? > \";
std::cin>>choice;
}while(choice==\"yes\");
/*while loop break if choice value other then \"yes\" */
std::cout << \"The current messages are: \ \";
/*Iterating vector in reverse order for printing desirable output*/
for (it=store.rbegin(); it!=store.rend(); ++it){
std::cout << it->first << \" >> \"<second << \'\ \';
}
return 0;
}
/*Main function End*/
/*Output*/
gopal@gopal:~/Desktop/chegg$ g++ messageService.cpp
gopal@gopal:~/Desktop/chegg$ ./a.out
Enter User Name> Kate
Enter Message> Get in the loop and join our War Eagle group!
Sunner in st. John\'s islands was fun.
How was your summer?
$$
Any More Users? > yes
Enter User Name> Daniel
Enter Message> I\'m in!
$$
Any More Users? > yes
Enter User Name> Joey
Enter Message> Count me in.
We were in Tokyo; intersting!
$$
Any More Users? > yes
Enter User Name> Kevin
Enter Message> What\'s new?
we had a great time in the Outback.
$$
Any More Users? > no
The current messages are:
Kevin >>
What\'s new?
we had a great time in the Outback.
Joey >>
Count me in.
We were in Tokyo; intersting!
Daniel >>
I\'m in!
Kate >>
Get in the loop and join our War Eagle group!
Sunner in st. John\'s islands was fun.
How was your summer?
Solution
// operating system Ubunut,Linux,Mac
// filename messageService.cpp
#include
#include // for vector
#include
using namespace std;
/*Main function start*/
int main()
{
std::vector > store;// we are using vector for storing pair of name and message
std::vector >::reverse_iterator it;// used to reverse iteration
std::string name,message,input,choice;// variable for purpose
do{
std::cout<<\"Enter User Name> \";
std::cin>>name;
std::cout<<\"Enter Message> \";// prompt for user input
/* we are taking input from user as string
* if line contains $$ then it will break and come out from loop
* otherwise it will create pair and insert it into vector*/
while(std::getline(std::cin,input)){
if(input==\"$$\")
break;
message+=input+\"\ \";
}
store.push_back(std::pair(name,message));// inserting pair into vector
message=\"\";
std::cout<<\"Any More Users? > \";
std::cin>>choice;
}while(choice==\"yes\");
/*while loop break if choice value other then \"yes\.
FUNCTIONS, CLASSES AND OBJECTS.pptx
Functions, classes, and objects are fundamental concepts in object-oriented programming. Here's a brief explanation of each:
Functions:
Functions are blocks of code that perform specific tasks or computations.
They encapsulate a set of instructions and can take parameters (input) and return values (output).
Functions are reusable, promoting code modularity and maintainability.
Classes:
Classes are blueprints or templates for creating objects.
They define the structure and behavior of objects by specifying attributes (data members) and methods (functions) that the objects will have.
Classes serve as a model for creating multiple instances (objects) with similar characteristics.
Objects:
Objects are instances of classes.
They are concrete representations of the class's blueprint, with their own unique data values and the ability to perform actions using the methods defined in the class.
Objects are used to model and manipulate real-world entities in code.
In summary, functions are used to define specific tasks or operations, classes serve as templates for creating objects with shared attributes and behaviors, and objects are instances of classes that represent real-world entities and can interact with their environment. These concepts are central to object-oriented programming and software development.
write the To Dos to get the exact outputNOte A valid Fraction .pdf
write the To Do\'s to get the exact output:
NOte: A valid Fraction number has a non-negative numerator and a positive denominator.
Default constructor initializes the object to safe empty state (an object with denom equals -1).
The two-argument constructor also validates the parameters and sets the object to the safe empty
state if the parameters are not valid.
Write the definitions and prototypes of following functions in Fraction.cpp and Fraction.h
respectively (They are indicated in the files by //TODO tag):
Define isEmpty function as a member function, which returns true if the object is in safe empty
state (an object is in the safe empty state if denominator (denom) equals -1).
Define display function, which sends a Fraction number to the output stream (with the
“Numerator/denominator” format). This function just prints \"Invalid Fraction Object!\" in the
screen if the object is in the safe empty state. In case that object denominator equals 1, it just
print the numerator.
Define the operator functions for the following operators:
“+=”, “+”, “*”
The overload of the above operators should make the following code possible:
The member operator+ : Adds two Fraction numbers and returns a Fraction number as the result.
This function returns an object with the safe empty state if either of Fraction numbers (operands)
is in safe empty state. It makes following code possible:
A+B ( where A and B are Fraction objects)
The member operator+= : Adds two Fraction numbers and assigns the result to the left operand,
then returns a reference to the left operand. If either of Fraction numbers (operands) is in safe
empty state, it initializes the left operand to the safe empty state, then returns a reference to the
left operand. It makes following code possible:
A+=B ( where A and B are Fraction objects)
The member operator* : Multiplies two Fraction numbers and returns a Fraction number as the
result. This function returns an object with the safe empty state if either of Fraction numbers
(operands) is in safe empty state. It makes following code possible:
A*B ( where A and B are Fraction objects)
fraction.cpp
#include \"Fraction.h\"
using namespace std;
namespace sict{
Fraction::Fraction(){
denom =-1; // safe empty state
}
Fraction::Fraction(int n, int d) // n: numerator, d: denominator
{
if(n >= 0 && d > 0){
num = n;
denom = d;
reduce();
}
else
denom =-1; // set to safe empty state
}
int Fraction::gcd() // returns the greatest common divisor of num and
denom
{
int mn = min(); // min of num and denom
int mx = max(); // mX of num and denom
for (int x=mn ; x > 0 ; x--) // find the greatest common divisor
if( mx % x == 0 && mn % x == 0)
return x;
return 1;
}
void Fraction::reduce() // simplify the Fraction number
{
int tmp = gcd();
num /= tmp;
denom /= tmp;
}
int Fraction::max ()
{
return (num >= denom) ? num : denom;
}
int Fraction::min()
{
return (num >= denom) ? denom : num;
}
// in_lab
// TODO: write the implementation of display function HERE
// TODO: w.
Assignment isPage 349-350 #4 and #5 Use the Linked List lab.pdf
Assignment is:
\"Page 349-350 #4 and #5 Use the \"Linked List lab\" you have been working on in class and add
the two functions the questions are asking you to develop: divideMid and divideAt. Be sure to
include comments Use meaningful identifier names (constants where appropriate) Turn in .cpp
file AND Turn in a \"print-screen\' of your output (press \"print-screen\' on keyboard, then
\'paste\' in MS-Word)\"
How do you solve QUESTION #4 in the book data structures using c++ by D.S. Malik in Visiual
Studios using the linked list below with what is being asked? Please need help
Linked list :
#include
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *first, *last;
int num;
createList(first, last);
int choice;
while(true)
{
cout<<\"1. Insert Front.\ 2. Insert Last.\ 3. Delete Front.\ 4. Delete Last.\ 5. Print List.\ 6. Exit.\
\";
cout<<\"Enter your choice: \";
cin>>choice;
switch(choice)
{
case 1: insertFront(first); break;
case 2: insertBack(last); break;
case 3: deleteFirst(first); break;
case 4: deleteLast(last, first); break;
case 5: printList(first); break;
case 6: return 0;
default: cout<<\"Invalid menu option. Try again.\"<>number;
while (number != -999)
{
newNode = new nodeType; // create new node
newNode->info = number;
newNode->link = NULL;
if (first == NULL)
{
first = newNode;
last = newNode;
}
else
{
last->link = newNode;
last = newNode;
}
cout<<\"Enter an integer (-999 to stop): \";
cin>>number;
} // end of while-loop
} // end of build list function
void deleteFirst(nodeType*& first)
{
nodeType *temp;
temp= first;
first= temp->link;
delete temp;
return;
}
void deleteLast(nodeType*& last, nodeType* current)
{
nodeType *temp;
while(current->link != NULL)
{
temp=current;
current=current->link;
}
temp=last;
current->link=NULL;
delete temp;
last = current;
return;
}
void insertFront(nodeType*& front)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= front;
front= newNode;
return;
}
void insertBack(nodeType*& last)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= NULL;
last->link= newNode;
last = newNode;
return;
}
void printList(nodeType*& first)
{
cout<<\"Inside printList...printing linked list...\ \"<info << \" \";
current = current->link;
}
cout<
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *firs.
Assignment is Page 349-350 #4 and #5 Use the Linked Lis.pdf
Assignment is :
\"Page 349-350 #4 and #5 Use the \"Linked List lab\" you have been working on in class and add
the two functions the questions are asking you to develop: divideMid and divideAt. Be sure to
include comments Use meaningful identifier names (constants where appropriate) Do not work
together; no two people should have identical work!?!? Turn in .cpp file AND Turn in a \"print-
screen\' of your output (press \"print-screen\' on keyboard, then \'paste\' in MS-Word)\"
How do you solve QUESTION #5 in the book data structures using c++ by D.S. Malik in Visiual
Studios using the linked list below with what is being asked? Please need help
Linked list :
#include
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *first, *last;
int num;
createList(first, last);
int choice;
while(true)
{
cout<<\"1. Insert Front.\ 2. Insert Last.\ 3. Delete Front.\ 4. Delete Last.\ 5. Print List.\ 6. Exit.\
\";
cout<<\"Enter your choice: \";
cin>>choice;
switch(choice)
{
case 1: insertFront(first); break;
case 2: insertBack(last); break;
case 3: deleteFirst(first); break;
case 4: deleteLast(last, first); break;
case 5: printList(first); break;
case 6: return 0;
default: cout<<\"Invalid menu option. Try again.\"<>number;
while (number != -999)
{
newNode = new nodeType; // create new node
newNode->info = number;
newNode->link = NULL;
if (first == NULL)
{
first = newNode;
last = newNode;
}
else
{
last->link = newNode;
last = newNode;
}
cout<<\"Enter an integer (-999 to stop): \";
cin>>number;
} // end of while-loop
} // end of build list function
void deleteFirst(nodeType*& first)
{
nodeType *temp;
temp= first;
first= temp->link;
delete temp;
return;
}
void deleteLast(nodeType*& last, nodeType* current)
{
nodeType *temp;
while(current->link != NULL)
{
temp=current;
current=current->link;
}
temp=last;
current->link=NULL;
delete temp;
last = current;
return;
}
void insertFront(nodeType*& front)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= front;
front= newNode;
return;
}
void insertBack(nodeType*& last)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= NULL;
last->link= newNode;
last = newNode;
return;
}
void printList(nodeType*& first)
{
cout<<\"Inside printList...printing linked list...\ \"<info << \" \";
current = current->link;
}
cout<
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void dele.
OverviewWe will be adding some validation to our Contact classes t.pdf
On March 4 of the current year, Barefoot Bay, Inc. reacquired 5,000 shares of its common stock
at $89 per share. On August 7, Barefoot Bay sold 3,500 of the reacquired shares at $100 per
share. The remaining 1,500 shares were sold at $88 per share on November 29.
1. Journalize the transactions of March 4, August 7, and November 29. If an amount box does
not require an entry, leave it blank or enter \"0\".
2. What is the balance in Paid-in Capital from Sale of Treasury Stock on December 31 of the
current year?
$Mar. 4Aug. 7Nov. 29
Solution
4-Mar Treasury stock 445000 =5000*89 Cash 445000 7-Aug Cash 350000
=3500*100 Treasury stock 311500 =3500*89 Paid in capital-Treasury stock
38500 29-Nov Cash 132000 =1500*88 Paid in capital-Treasury stock 1500
Treasury stock 133500 =1500*89 2 Balance in Paid-in Capital from Sale of Treasury
Stock = 38500-1500 = $37000.
Frequency .java Word frequency counter package frequ.pdf
Frequency .java
/**
* Word frequency counter
*/
package frequency;
import java.util.Iterator;
/**
*
* @author UMD CS
*/
public class Frequency implements Iterable{
private Node first;
private int N;
Frequency(){
N = 0;
first = null;
}
@Override
public Iterator iterator() {
return new ListIterator();
}
/**
*
* List iterator
*
*/
private class ListIterator implements Iterator{
private Node current;
private int index ;
ListIterator(){
current = first;
index = 0;
}
@Override
public boolean hasNext() {
return current != null;
}
public String next() {
if(!hasNext()){
return null;
}
String word = current.key;
int count = current.count;
String r = \"(\"+word + \",\" + Integer.toString(count)+\")\";
current = current.next;
return r;
}
@Override
public void remove() {
}
}
/**
*
* Node class
*
*/
private class Node {
private String key;
private int count;
private Node next;
Node(String item){
key = item;
count = 1;
next = null;
}
@Override
public String toString(){
return \"(\"+key +\",\"+count+\")\";
}
}
/*
* Inserts a word into the linked list. If the word exists, increment the
* count by q.
*/
public void insert(String word){
if(word.equals(\"\")){
return;
}
//TODO
/*
* implement here
*/
}
/**
*
* @param str input string
* This method splits a string into words and pass the words to insert method
*
*/
public void insertWords(String str){
String delims = \"[ .,?!\'\\\"()}{;/<>&=#-:\\\\ _]+\";
String[] words = str.split(delims);
for(String s: words){
s = s.toLowerCase();
insert(s);
}
}
/**
* prints the word frequency list
*/
public void print(){
Node c = first;
while(c != null){
System.out.print(\"(\"+c.key + \",\" + c.count+\")\");
c = c.next;
}
System.out.print(\"\ \");
}
}
--------------------------------------------------------------------------------------------------------------------
------------------------------------------------------
WordFrequency.java
package frequency;
import utils.In;
import utils.Stopwatch;
/**
*
* @author UMD CS
*/
public class WordFrequency {
/**
* @param input source
* @param
* This method receives input resource and return the word frequency string
* DO NOT CHANGE THIS METHOD.
*/
public static String freq(String inputSource, int maxLines){
In in;
// Frequency class can only count the frequency of strings. DO NOT CHANGE THIS.
Frequency freq = new Frequency();
int MAX = 100;
String inputSourceName = inputSource;
try {
in = new In(inputSourceName);
while (!in.isEmpty()) {
String s = in.readLine();
//System.out.println(s);
freq.insertWords(s);
}
}
catch (Exception e) {
e.printStackTrace();
}
StringBuilder strFrequency = new StringBuilder();
int cnt = 0;
for(String s: freq){
strFrequency.append(s);
strFrequency.append(\",\");
cnt++;
if(cnt >= maxLines){break;}
}
return strFrequency.toString();
}
/**
*
*/
public static void main(String[] args) {
In in;
Frequency freq = new Frequency();
int MAX = 100;
// String inputSourceName =
\"http://www.cs.umd.edu/class/summer2015/cmsc132/projects/P3_WordFrequency/test1.html\";
String .
Hey, I need some help coding this C++ assignment.ObjectivesThis.pdf
Hey, I need some help coding this C++ assignment.
Objectives:
This assignment will access your C++ language skills. After completing this assignment you will
be able to do the following:
(1) allocate memory dynamically (2) implement a default, explicit-value and copy constructor,
(3) a destructor, (4)parse string, (5) identify substrings in a string, and (6) fully implement and
manage a string class.
In this assignment you will implement the WORD ADT (abstract data type) using a singly-linked
list of characters. The WORD ADT is defined below. Call the class you implement \"WORD\".
Remember, a singly-linked list is composed of nodes. You will also implement a class called
\"character\" that has two fields: a char field called \"symbol\"; and a pointer field called \"next\".
Essentially, each character is really a node in the list. Each node (character) in the list (word) will
contain one alpha/numeric character of a word. Consider the following declaration of a character.
A WORD is composed of characters:
class character
{
public:
char symbol;
character *next;
};
The state (private data members) of your WORD class should contain a pointer to the front of the
list of characters called \"front\" and a pointer to the back of the list called \"back\". You may add
more members to the state and more member functions to the behavior of the class if you
determine necessary. Store the definition of your class in a file called \"word.cpp.\" and the
declaration of your class in a file called \"word.h .\" You will implement all the code necessary
to maintain a word. See the ADT below. Test the complete functionality of the class WORD.
Use the file \"word_driver.cpp\" as a guide to help you understand and test all the functionality
of the class. If you discover that you need more tests while implementing the functionality of
WORD, then add more tests to your driver.
ADT---WORD
Data:
A set of characters
Operations:
1. IsEmpty: Check to see if the word A is empty; A is the current object;
2. Length: Determines the length of the word A; remember A is the current object;
6. operator<<: Overload the insertion operator as a friend function with chaining to print a word
A;
7. operator= : Overload the assignment operator as a member function to take a string (C-style or
C++ string, just be consistent in your implementation) as an argument and assigns its value to A,
the current object;
8. operator= : Overload the assignment operator as a member function with chaining to take a
word object as an argument and assigns its value to A, the current object;
9. operator+: Overload the ‘+” operator as a member function without chaining to add word B
(adds the set of symbols that makep B\'s linked list to the back of A\'s linked list) to the back of
word A; remember A is the current object;
10. Default constructor: The default constructor will initialize your state variables. The front of
the linked list is initially set to NULL or 0; this implies a non-header node implemen.
Task #1 Correcting Logic Errors in FormulasCopy and compile the so.pdf
Task #1 Correcting Logic Errors in Formulas
Copy and compile the source file NumericTypes.java, run the program, and observe the output.
Some of the output is incorrect. You need to correct logic errors in the average formula and the
temperature conversion formula. The logic errors could be due to conversion between data types,
order of operations, or formula problems. The necessary formulas are
average = (score1+score2) / numberOfScores
C = 5/9 (F-32)
Make sure that the output makes sense before you continue. The average of 95 and 100 should be
97.5 and the temperature that water boils is 100 degrees Celsius
Task #2 Using the Scanner Class for User Input
1. Add an import statement above the class declaration to make the Scanner
class available to your program.
2. In the main method, create a Scanner object and connect it to the System.in
object.
3. Prompt the user to enter his or her first name.
4. Read the name from the keyboard using the nextLine method, and store it into
a variable called firstName (you will need to declare any variables you use).
5. Prompt the user to enter his or her last name.
6. Read the name from the keyboard and store it in a variable called lastName.
7. Concatenate the firstName and lastName with a space between them and
store the result in a variable called fullName.
8. Print out the fullName.
9. Compile, debug, and run, using your name as test data.
10. Since we are adding on to the same program, each time we run the program we
will get the output from the previous tasks before the output of the current task.
Task #3 Working with Strings
1. Use the charAt method to get the first character in firstName and store it in a
variable called firstInitial (you will need to declare any variables that you
use).
2. Print out the user’s first initial.
3. Use the toUpperCase method to change the fullName to uppercase and store
it back into the fullName variable.
4. Add a line that prints out the value of fullName and how many characters
(including the space) are in the string stored in fullName (use the length
method to obtain that information).
5. Compile, debug, and run. The new output added on after the output from the
previous tasks should have your initials and your full name in uppercase
characters.
Task #4 Using Predefined Math Functions
Task #4 UsingPredefined Math Functions
Add a line that prompts the user to enter the diameter of a sphere.
Read in and store the number into a variable called diameter (you will need to declare any
variables that you use).
The diameter is twice as long as the radius, so calculate and store the radius in an appropriately
named variable.
The formula for the volume of a sphere is
r3
Convert the formula to Java and add a line which calculates and stores the value of volume in an
appropriately named variable. Use Math.PI for and Math.pow to cube the radius.
Print your results to the screen with an appropriate message.
Compile, debug, and run using the following test data and record the resu.
could you implement this function please, im having issues with it..pdf
could you implement this function please, im having issues with it.
void makeList (const ListNode::value_type [],const size_t& count)
class ListNode
{
public:
typedef int value_type;
ListNode (value_type d = value_type(), ListNode* n = NULL) { datum = d; next = n; }
//Assessor
value_type getDatum () const { return datum; }
ListNode const* getNext () const { return next; }
//Mutator
void setDatum (const value_type& d) {datum = d; }
ListNode* getNext () { return next; }
void setNext (ListNode* new_link) {next = new_link; }
private:
value_type datum;
ListNode* next;
};
class LinkedList
{
public:
LinkedList ();
virtual ~LinkedList ();
void insertItem (ListNode::value_type);
void makeList (const ListNode::value_type [],const size_t& count);
void deleteList ();
//The following friend function is implemented in lablinklist.cpp
friend std::ostream& operator<<(std::ostream&, const LinkedList&);
private:
ListNode* head;
};
This is the pseudocode, but i still have a hard time undertanding it.
Creating a List (makeList(const ListNode::value_type [],const size_t& count)) This function
receives an array in the order that we want to add it to the linkedlist. Index 0 will be the head
node, index n will be the last node.
First, create a node initialized with a data value and a NULL pointer. Set the \"head\" to point to
the first node. Set up a current-pointer to the first node (or \"head\"). Get a data value for the next
node. While more nodes to add { Create a new node initialized with the data value and a NULL
pointer. Set the current-pointer link member (\"next\") to the new node. Set the current-pointer to
point to the new node. Get a data value for the next node. }
Thanks.
Solution
//linkedList.h
#ifndef LINKEDLIST_H
#define LINKEDLIST_H
#include
#include
class ListNode
{
public:
typedef int value_type;
ListNode(value_type d = value_type(), ListNode* n = NULL) { datum = d; next = n; }
//Assessor
value_type getDatum() const { return datum; }
ListNode const* getNext() const { return next; }
//Mutator
void setDatum(const value_type& d) { datum = d; }
ListNode* getNext() { return next; }
void setNext(ListNode* new_link) { next = new_link; }
private:
value_type datum;
ListNode* next;
};
class LinkedList
{
public:
LinkedList();
virtual ~LinkedList();
void insertItem(ListNode::value_type);
void makeList(const ListNode::value_type[], const size_t& count);
void deleteList();
//The following friend function is implemented in lablinklist.cpp
friend std::ostream& operator<<(std::ostream&, const LinkedList&);
private:
ListNode* head;
};
#endif
-------------------------------------------------------------
//linkedList.cpp
#include \"linkedlist.h\"
LinkedList::LinkedList()
{
head = NULL;
}
LinkedList::~LinkedList()
{
ListNode *tmp = head;
while (tmp != NULL)
{
head = head->getNext();
delete tmp;
tmp = head;
}
}
void LinkedList::insertItem(ListNode::value_type item)
{
ListNode *newNode,*cur = head;
newNode = new ListNode;
newNode->setDatum(item);
newNode->setNext(NULL);.
#include iostream #includeData.h #includePerson.h#in.pdf
#include
#include\"Data.h\"
#include\"Person.h\"
#include\"Report.h\"
#include
#include
#include \"Menu.h\"
using namespace std;
/*
Programmers: Javier A. Molina, Eduardo Bonnet
Students #:79249
*/
int main()
{
int cnt;
int idx;
string fileName;
Report * telefonia;
Menu menu(\"Reports\");
bool fileNameExists(string fileName);
Report * addReport(Report * reports, int & totalReports);
Report * delReport(Report * reports, int & totalReports, int idx);
int displayReports(Report * reports, int totalReports);
menu.addItem(\"New report\");
menu.addItem(\"Delete a report\");
menu.addItem(\"Display a report\");
cnt = 0;
telefonia = NULL;
do {
cout << menu;
cin >> menu;
//cls();
switch (menu.getOption()) {
case 1:
cout << \"Enter report name (TE?????): \";
cin >> fileName;
if (fileNameExists(fileName + \".tel\")) {
telefonia = addReport(telefonia, cnt);
idx = cnt - 1;
telefonia[idx].setFileName(fileName);
// telefonia[idx].loadReport();
}
else {
cls();
cerr << \"Error: Report name \'\" << fileName << \"\' does not exists!\ \ \ \";
//pause();
}
break;
case 2:
if (telefonia != NULL) {
do {
cls();
cout << \"Delete a Report:\ \ \";
idx = displayReports(telefonia, cnt);
if (between(idx, 0, cnt - 1)) {
cls();
telefonia = delReport(telefonia, cnt, idx);
idx = 0;
// pause();
}
} while (idx != cnt);
}
else {
cerr << \"No reports available for deleting!\ \ \ \";
//pause();
}
break;
case 3:
char ans;
if (telefonia != NULL) {
do {
// cls();
cout << \"Display/Filed a Report:\ \ \";
idx = displayReports(telefonia, cnt);
if (between(idx, 0, cnt - 1)) {
// cls();
cout << \"Would you like the report to be display otherwise save into a file? \";
cin >> ans;
cls();
cin.ignore();
if (upper(ans) == \'Y\') {
cout << telefonia[idx] << endl;
}
else {
//telefonia[idx].saveReport();
cout << \"Report \'\" << telefonia[idx].getFileName() << \"\' saved as \'\" <<
telefonia[idx].getFileName() << \".rep\'.\ \ \";
}
//pause();
}
} while (idx != cnt);
}
else {
cerr << \"No reports available for displaying!\ \ \ \";
// pause();
}
break;
case 4:
cout << \"Thanks for using Telefonia Reports System!!!\ \ \ \";
break;
}
} while (menu.getLast() != menu.getOption());
delete[] telefonia;
return 0;
}
//Funcion que verifica si existe un archivo en disco
bool fileNameExists(string fileName) {
ifstream fin(fileName.c_str());
bool exists = !(fin.fail());
if (exists) fin.close();
return(exists);
}
//Anade dinamicamente objetos tipo Report al arreglo reports
Report * addReport(Report * reports, int & totalReports) {
if (totalReports == 0) {
reports = new Report[1];
}
else {
Report * tmp = new Report[totalReports];
for (int i = 0; i < totalReports; ++i) {
tmp[i] = reports[i];
}
delete[] reports;
reports = new Report[totalReports + 1];
for (int i = 0; i < totalReports; ++i) {
reports[i] = tmp[i];
}
delete[] tmp;
}
totalReports++;
return(reports);
}
//Borra objetos del arreglo reports segun el idx enviado
Report * delReport(Report * reports, int & totalReports, int idx) {
Report * tmp = new Report[tota.
Help with the following code1. Rewrite to be contained in a vecto.pdf
Help with the following code:
1. Rewrite to be contained in a vector object.
2. Using linked lists, redo to handle as many entries as required.
3. Add the ability to add or delete a new entry to the address book.
4. When the program terminates, write the data in the address book to a disk.
# include
# include
# include
using namespace std;
class addressbook
{
private:
char name[500];
long ph_num; //class addressType :public addressbook
char address[500];
int year;
int mounth;
int day;
char gender;
int d, Th, y;
char M, F, m, f;
// char freind[];
public:
addressbook();
void setName();
void getName();
void getphone();
long setphone();
void setAddress();
void getAddress();
float getAverage();
int setDay();
void getDay();
int setMounth();
void getMounth();
int setYear();
void getYear();
char setGender();
void getGender();
};
addressbook::addressbook() // constructor
{
name;
ph_num = 0;
year = 0;
mounth = 0;
day = 0;
}
int addressbook::setDay()
{
cout << \"\ \\tEnter the day:\ \\t\" << endl;
cin >> d;
day = (d >= 1 && d<32) ? d : 0;
return day;
}
int addressbook::setMounth()
{
cout << \"\ \\tEnter the mounth:\ \\t\" << endl;
cin >> m;
mounth = (Th >= 1 && Th<13) ? Th : 0;
return mounth;
}
int addressbook::setYear()
{
cout << \"\ \\tEnter the year :\ \\t\" << endl;
cin >> y;
year = (y >= 1 && y<2008) ? y : 0;
return year;
}
void addressbook::getMounth()
{
cout << mounth << \"/\";
}
void addressbook::getDay()
{
cout << \"\\tBIRTH DAY : \" << day << \"/\";
}
void addressbook::getYear()
{
cout << year;
}
char addressbook::setGender()
{
int flag = 0;
cout << \" \ \\tEnter the gender,(F)for female (M)for male:\ \\t\";
cin >> gender;
while (flag != 1)
{
if (gender == (\'F\') || gender == (\'M\') || gender == (\'m\') || gender == (\'f\'))
flag = 1;
else
{
cout << \"\\t error.....Try Again\ \\t\";
cin >> gender;
return gender;
}
}
}
void addressbook::getGender()
{
cout << \"\\tGender : \" << gender << endl;
}
void addressbook::getAddress()
{
cout << \"\\tAddress : \" << address << endl;
}
float addressbook::getAverage()
{
return 0.0f;
}
void addressbook::setAddress()
{
cout << \" \ \\tEnter the address:\ \\t\" << endl;
gets_s(address);
}
void addressbook::setName()
{
cout << \" \\tEnter the name:\ \\t\" << endl;
gets_s(name);
}
void addressbook::getName()
{
cout << \"\ \\tName : \" << name << \" \" << endl;
}
long addressbook::setphone()
{
cout << \" \ \\tEnter the person number:\ \\t\" << endl;
cin >> ph_num;
return ph_num;
}
void addressbook::getphone()
{
cout << \"\\tPerson # : \" << ph_num << endl;
}
/*class addressType :public addressbook
{
do that
};*/
int main()
{
int s;
cout << \" Enter number person max(500): \";
cin >> s;
addressbook book[10];
for (int i = 1; i<2; i++)
{
book[i].setName();
book[i].setphone();
book[i].setAddress();
book[i].setDay();
book[i].setMounth();
book[i].setYear();
book[i].setGender();
cout << \"\ \ ***********************************\ \";
}
for (int u = 0; u<2; u++)
{
book[u].getName();
book[u].getphone();
book[u].getAddre.
Similar to Use the code below from the previous assignment that we need to exte.pdf (20)
maincpp Build and procees a sorted linked list of Patie.pdf
maincpp Build and procees a sorted linked list of Patie.pdf
operating system Ubunut,Linux,Mac filename messageService.cpp.pdf
operating system Ubunut,Linux,Mac filename messageService.cpp.pdf
write the To Dos to get the exact outputNOte A valid Fraction .pdf
write the To Dos to get the exact outputNOte A valid Fraction .pdf
Assignment isPage 349-350 #4 and #5 Use the Linked List lab.pdf
Assignment isPage 349-350 #4 and #5 Use the Linked List lab.pdf
Assignment is Page 349-350 #4 and #5 Use the Linked Lis.pdf
Assignment is Page 349-350 #4 and #5 Use the Linked Lis.pdf
OverviewWe will be adding some validation to our Contact classes t.pdf
OverviewWe will be adding some validation to our Contact classes t.pdf
Frequency .java Word frequency counter package frequ.pdf
Frequency .java Word frequency counter package frequ.pdf
Hey, I need some help coding this C++ assignment.ObjectivesThis.pdf
Hey, I need some help coding this C++ assignment.ObjectivesThis.pdf
Task #1 Correcting Logic Errors in FormulasCopy and compile the so.pdf
Task #1 Correcting Logic Errors in FormulasCopy and compile the so.pdf
could you implement this function please, im having issues with it..pdf
could you implement this function please, im having issues with it..pdf
#include iostream #includeData.h #includePerson.h#in.pdf
#include iostream #includeData.h #includePerson.h#in.pdf
Help with the following code1. Rewrite to be contained in a vecto.pdf
Help with the following code1. Rewrite to be contained in a vecto.pdf
More from sales87
Using Martelle�s Chapters 12-14, please describe the impact of WWII .pdf
Using Martelles Chapters 12-14, please describe the impact of WWII on life in Detroit. How did
things improve (over the GD)? What happened when African Americans started moving beyond
the boundaries of segregated neighborhoods? What was the impact of the post-WWII boom on
the city? Finally, what were two errors, according to Martelle, that took place post WWII that
set up the city for catastrophe in subsequent decades?.
Using htmljscss, recreate the sliders. I have attached all images..pdf
Using html/js/css, recreate the sliders. I have attached all images. Please post screenshot to show
it works. OIL $25
A).
using financial calculatorusing fi.pdf
using financial calculator
using financial calculator
using financial calculator
using financial calculator
1. Suppose a State of New York bond will pay $1,000 ten years from now. If the going interest
rate on these 10 -year bonds is 6.0%, how much is the bond worth today?.
Using a Blackjack game that has the classesentities Blackjack, Card.pdf
Using a Blackjack game that has the classes/entities Blackjack, Card, CardDeck, Game, Rank,
Suit. Using the java code create/provide the classes/entities to create a UML Class diagram that
uses aggregation, inheritance, and composition. The diagram should have the necessary classes,
associations, and multiplicities. The diagram also depicts an architecture that follows the
principles of OOD such as cohesion, coupling, delegation, and encapsulation..
Using an Arduino microcontroller to code the following projectDet.pdf
Using an Arduino microcontroller to code the following project:
Detect a person's presence and trigger electrical items to flicker on and off sporadically. Do this
with physical computing using:
- two digital inputs (this could be a button, light sensor, toggle)
- two LEDs (or a motor, or something else you can turn on/off)
- code to make it blink in different patterns depending on which button(s) is pressed
Please write the code using Arduino that would complete this project and explain the steps to
complete the physical computing on a controller board..
Use the internet to find an example of a chart or graph.Insert an .pdf
Use the internet to find an example of a chart or graph.
Insert an image or attach a file containing your example.
What type of chart/graph is it? (Pie, stacked bar, scatter, line etc.)
Explain why the choice of chart/graph type is a good way to display this data.
Could you roughly recreate this chart/graph using what you learned in class this week? Give it a
shot and attach your results..
Use The Wobblies video as a guide httpswww.youtube.comwatchv.pdf
Use "The Wobblies" video as a guide:
https://www.youtube.com/watch?v=K7fDSzQcIuE&t=1s&ab_channel=LaSoliFilms
1.What is the IWW? Roughly, during what period of history did the IWW start?
2.What did the IWW members want? What were their goals?
3. What kinds of tactics and strategies did the IWW employ to achieve their goals?
4. How were the IWW and its actions portrayed in the media? What explains this portrayal?
5. What happened to the IWW and its leadership?
6. What tactics did the opponents of the IWW use to go after the IWW?.
Use the singly linked list class introduced in the lab to implement .pdf
Use the singly linked list class introduced in the lab to implement integers of unlimited size.
Each node of the list should store one digit of the integer. You are to implement the addition,
subtraction and multiplication operations. Please note that any additional data structure to be
used in solving this problem has to be taken from the ones introduced in the ICS 202 lab. In
addition, provide a test class that will do the following: It will keep asking the user to enter two
integers, choose one of the operations (addition, subtraction, multiplication) and then display the
result. The program will stop upon entering the # character (without the double quotes).
this singly linked list class:
public class SLL {
private class SLLNode {
private T info;
private SLLNode next;
int value;
public SLLNode() {
this(null, null);
}
public SLLNode(T el) {
this(el, null);
}
public SLLNode(T el, SLLNode ptr) {
info = el;
next = ptr;
}
}
protected SLLNode head, tail;
public SLL() {
head = tail = null;
}
public boolean isEmpty() {
return head == null;
}
public void addToHead(T el) {
head = new SLLNode(el, head);
if (tail == null)
tail = head;
}
public void addToTail(T el) {
if (!isEmpty()) {
tail.next = new SLLNode(el);
tail = tail.next;
} else
head = tail = new SLLNode(el);
}
public T deleteFromHead() { // delete the head and return its info;
if (isEmpty())
return null;
T el = head.info;
if (head == tail) // if only one node on the list;
head = tail = null;
else
head = head.next;
return el;
}
public T deleteFromTail() { // delete the tail and return its info;
if (isEmpty())
return null;
T el = tail.info;
if (head == tail) // if only one node in the list;
head = tail = null;
else { // if more than one node in the list,
SLLNode tmp; // find the predecessor of tail;
for (tmp = head; tmp.next != tail; tmp = tmp.next)
;
tail = tmp; // the predecessor of tail becomes tail;
tail.next = null;
}
return el;
}
public void delete(T el) { // delete the node with an element el;
if (!isEmpty())
if (head == tail && el.equals(head.info)) // if only one
head = tail = null; // node on the list;
else if (el.equals(head.info)) // if more than one node on the list;
head = head.next; // and el is in the head node;
else { // if more than one node in the list
SLLNode pred, tmp;// and el is in a nonhead node;
for (pred = head, tmp = head.next; tmp != null
&& !tmp.info.equals(el); pred = pred.next, tmp = tmp.next)
;
if (tmp != null) { // if el was found;
pred.next = tmp.next;
if (tmp == tail) // if el is in the last node;
tail = pred;
}
}
}
@Override
public String toString() {
if (head == null)
return "[ ]";
String str = "[ ";
SLLNode tmp = head;
while (tmp != null) {
str += tmp.info + " ";
tmp = tmp.next;
}
return str + "]";
}
public boolean contains(T el) {
if (head == null)
return false;
SLLNode tmp = head;
while (tmp != null) {
if (tmp.info.equals(el))
return true;
tmp = tmp.next;
}
return false;
}
public int size() {
if (head == null)
return 0;
int count = 0;
SLLNode p = head;
w.
Use the Plan X and Plan Y tax schemes to complete the following tabl.pdf
Use the Plan X and Plan Y tax schemes to complete the following table by deriving the marginal
and average tax rates under each tax plan at the consumption levels of 500 beets, 1,200 beets,
and 2,500 beets, respectively. Consumption Level Plan X Plan Y (Quantity of beets) Marginal
Tax Rate Average Tax Rate Marginal Tax Rate Average Tax Rate (Percent) (Percent) (Percent)
(Percent) 500 1,200 2,500.
Use the pervious question to answer question 4. Suppose that in car.pdf
Use the pervious question to answer question 4. Suppose that in carrot plants, the I gene controls
root length while the c gene controls root colour. Each gene has two alleles. The I+allele gives
long roots while I homozygotes have short roots. I+is dominant to I. Homozygosity for the
c+allele gives dark-orange carrots while homozygosity for the c allele gives white carrots. c+and
c are incompletely dominant. A pure-breeding strain of long, dark-orange carrots is crossed with
purebreeding short, white carrots. What are the genotype and phenotype of the F1 generation?
1+1+c+c+; long, dark-orange Ilcc; short, white I+lcc; long, white 1+l+c; long, light-orange
1+1+c+c; long, light-orange Question 4 9 pts For the carrots in the above question... Two
individuals from the F1 generation are crossed to produce the F2 generation. What is the
phenotypic ratio of the F2 generation? [Hint: Draw a Punnett Square to show the genotypes and
predict the phenotypic ratio seen in the F2 generation]. 3 long, dark-orange; 6 long, light-orange;
3 long, white; 1 short, dark-orange; 2 short, light-orange; 1 short, white 3 long, dark-orange; 3
long, light-orange; 6 long, white; 1 short, dark-orange; 2 short, light-orange; 1 short, white 3
long, dark-orange; 6 long, light-orange; 3 long, white; 1 short, dark-orange; 1 short, light-orange;
2 short, white 6 long, dark-orange; 3 long, light-orange; 3 long, white; 1 short, dark-orange; 2
short, light-orange; 1 short, white.
Use the information below to Developdraw a Systemigram for enviro.pdf
Use the information below to Develop/draw a Systemigram for environmental water pollution.
Drivers: These are the underlying causes or factors that lead to water pollution. They include
industrial processes, agricultural practices, urbanization, transportation, natural events, and
household practices.
Pollution sources: These are the specific activities or practices that directly contribute to water
pollution. They include industrial waste discharge, agricultural runoff, sewage disposal,
stormwater runoff, oil spills, and littering.
Pathways: These are the routes by which pollutants enter water bodies. They include surface
runoff, direct discharge, atmospheric deposition, and groundwater infiltration.
Impacts: These are the negative effects of water pollution on the environment, human health, and
the economy. They include harm to aquatic life, degraded water quality, reduced recreational
opportunities, and economic losses.
Mitigation measures: These are the actions that can be taken to reduce or prevent water pollution.
They include improved wastewater treatment, reduced use of hazardous chemicals, better
agricultural practices, increased public awareness and education, and better regulatory
enforcement.
Monitoring and evaluation: This is the process of tracking progress in reducing water pollution
and assessing the effectiveness of mitigation measures. It involves collecting data on water
quality, monitoring pollution sources, and evaluating the success of mitigation measures.
Stakeholders: These are the groups and individuals who have an interest in reducing water
pollution. They include government agencies, industry groups, environmental organizations, and
the general public. Effective collaboration and engagement of stakeholders is essential for
successful water pollution reduction efforts..
Use the phylogeny below to determine whether each statement is true .pdf
Use the phylogeny below to determine whether each statement is true or false. Then drag and
drop the appropriate term.
1. The numbers on the phylogeny are called nodes and represent ancestors. blank
2. Species B is equally related to species A and C. blank
3. Species C is the ancestor of species D and E. blank
4. Species D is most closely related to species E. blank
5. The most recent common ancestor of species A and C is 1. blank
6. A group consisting of species A and B is monophyletic. blank
7. A group consisting of species C and D is monophyletic. blank
8. Species E is the most advanced species on this phylogeny. blank
The blanks are either filled with true, or false..
Use the input function to ask the user for a positive, whole number..pdf
Use the input function to ask the user for a positive, whole number. Then use a for loop to
generate a vector containing as many elements of the following sequence as the user requested.
For example, if the user entered 7 then your program should generate a vector containing: 1/2 3/4
5/6 7/8 9/10 11/12 13/14 The numerator of the sequence starts at 1 and is always odd. The
denominator starts at 2 and is always even. Both the numerator and denominator go up by two
each time..
Use este estudio de caso para responder las siguientes preguntas. .pdf
Use este estudio de caso para responder las siguientes preguntas.
CASO CAPTULO 1: INTRODUCCIN A LA INVESTIGACIN EMPRESA DE CARAMELOS
LAROCHE
En 1864, Henricus Laroche comenz a hacer chocolate de alta calidad en su cocina en Ooigem,
Blgica. Henricus aprendi su oficio en una famosa tienda de chocolates en Pars, y l y su esposa
comenzaron a hacer chocolate en barras, obleas y otras formas poco despus de que Henricus
regresara a Blgica para iniciar su propio negocio. El pueblo belga amaba el chocolate de Laroche
y el xito inmediato le llev pronto a aumentar sus instalaciones de produccin. Henricus decidi
construir una fbrica de chocolate en Kortrijk, una ciudad cercana en la provincia flamenca de
Flandes Occidental. Con la produccin en masa, la compaa pudo reducir los costos por unidad y
hacer que el chocolate, que alguna vez fue un artculo de lujo, fuera asequible para todos. The
Laroche Candy Company floreci, ampli sus lneas de productos y adquiri empresas relacionadas
durante las siguientes dcadas. En un siglo, la empresa se haba convertido en el principal
fabricante de dulces de Blgica y empleaba a ms de 2.500 personas. En la actualidad, The Laroche
Candy Company es uno de los mayores fabricantes de productos de confitera de chocolate y sin
chocolate de Europa. Bajo el liderazgo actual de Luc Laroche, la empresa se ha vuelto
verdaderamente innovadora. Adems, la empresa ha adoptado un enfoque muy proactivo para la
planificacin de marketing y, por lo tanto, es un competidor feroz en un mercado cada vez ms
global. La cantidad de productos que la empresa produce y comercializa ha aumentado
drsticamente; en este momento hay ms de 250 artculos de Laroche Candy distribuidos
internacionalmente a granel, bolsas y cajas. Luc Laroche, nacido en 1946, es la quinta generacin
de su familia en dirigir The Laroche Candy Company. Es tataranieto del fundador de la empresa,
Henricus Laroche, y actual presidente y director ejecutivo de la empresa. Pero Luc est a punto de
jubilarse. Ha planeado dejar de trabajar en dos o tres aos. Mientras que retirarse del poder es algo
muy difcil de hacer para muchas personas, es algo fcil de hacer para Luc: est deseando pasar
tiempo con sus nietos y conducir su Harley Davidson por Europa. Es ms, nunca ha encontrado
tiempo para jugar al golf y tiene previsto pasar tres veranos enteros aprendiendo si es necesario.
Y, sin embargo, aunque 'dejarse ir' no es un problema para Luc, todava tiene sus preocupaciones
sobre su retiro inminente. Como en la mayora de las empresas familiares, los dos hijos de Luc
pasaban parte de los veranos trabajando para la empresa. El hijo mayor de Luc, Davy, ha
trabajado repetidamente para el departamento de contabilidad, mientras que el hermano menor
de Davy, Robert, ha trabajado con poca frecuencia en el campo. Sin embargo, nunca han
mostrado un inters serio en el negocio. Davy, de 35 aos, actualmente trabaja como profesor
asociado de contabilidad de gestin en una prestigiosa universidad de Blgica. Ro.
Usar su autoridad y poder formal para resolver un conflicto, mientra.pdf
Usar su autoridad y poder formal para resolver un conflicto, mientras ignora en gran medida las
necesidades de la otra parte, es caracterstico del estilo ________ de manejo de conflictos.
comprometer
forzando
evitando
integrando
servicial
comprometer
forzando
evitando
integrando
servicial.
Usando la teor�a de la expectativa de la motivaci�n como marco para .pdf
Usando la teora de la expectativa de la motivacin como marco para el anlisis, responda las
siguientes preguntas para cada caso.
Caso No. 1
El ayudante que descuid la atencin al paciente
Brenda, una asistente en el tercer piso, ha estado en el hospital durante seis aos. Sus funciones se
dividen en dos reas: funciones asignadas regularmente que se realizan durante el turno y atender
a los pacientes cuando se les solicita. El supervisor ha notado que Brenda pasa la primera parte
socializando con otros empleados. En la ltima mitad del turno, muestra un esfuerzo monumental
para completar las tareas asignadas que ha logrado completar unos minutos antes del final de su
turno. La enfermera registrada de turno se queja de que Brenda descuida la atencin de sus
pacientes durante la ltima parte del turno, ya que tiene poco tiempo para cualquier cosa adems de
las tareas asignadas. Brenda, una supervisora, se acerc a ella con respecto a la negligencia en la
atencin del paciente. Brenda respondi: "Hago mi trabajo".
Caso No. 2
El RN que perdi el cdigo
Cindy se gradu recientemente de un programa de enfermera de cuatro aos en una prestigiosa
escuela privada en Nueva Inglaterra. Termin entre los mejores de su clase y se desempe
excepcionalmente bien en el examen nacional de enfermera. En sus tres meses en el hospital del
condado, siempre llega temprano al trabajo y se queda diez minutos ms para asegurarse de que
todo est correcto para el siguiente turno. Linda, la otra enfermera registrada del turno, se quej
con el supervisor de que, desde que Cindy ha estado trabajando en el turno, han ocurrido tres das
de mayo. Si bien Cindy no fue de ninguna manera responsable de estos eventos, en las tres
ocasiones se llam a una enfermera registrada de otra estacin de enfermera porque no se pudo
encontrar a Cindy para ayudar. El supervisor se acerc a Cindy sobre el problema. Cindy
respondi: Debo haber estado ocupada en otro lugar y me perd la llamada de Mayday en dos
ocasiones. En la tercera ocasin, escuch la llamada pero asum que Linda podra manejar la
situacin. No estoy muy seguro de si podra ser de mucha ayuda. Despus de todo, Linda y los
camilleros estaban trabajando en la situacin"..
Usando Internet o fuentes de bibliotecas, seleccione cuatro organiza.pdf
Usando Internet o fuentes de bibliotecas, seleccione cuatro organizaciones: dos en el sector
privado y dos en el sector pblico. Encuentre sus declaraciones de misin. Complete el siguiente
anexo identificando las partes interesadas que se mencionan. Evaluar las diferencias entre las
empresas del sector privado y las del sector pblico".
Nombre de la Organizacin
Estado de la misin
Partes interesadas
(ponga una marca donde se mencionaron en la declaracin de misin)
1. Clientes
2. Proveedores
3. Gerentes/empleados
4. Comunidad en general
5. Propietarios
6. Otros?
7. Otros?.
URGENTAssignment 3 - Software DesginPauline is considering how.pdf
*URGENT*
Assignment 3 - Software Desgin
Pauline is considering how she would go out developing a Point of Sale (POS) system. The
system would be used by the customer service staff to enter customer orders.
Create a Class Object Diagram for a POS System that would suit Mario's Coffee
Create a menu hierarchy for the POS system
Create a storyboard, showing major screens for a product order and fulfilment. (see the attached
as an example)
All drawings must be done using appropriate CASE tools, no hand drawn images accepted.
UX Storyboard Example.
Uscinski and his co-authors describe how belief in political conspir.pdf
Uscinski and his co-authors describe how belief in political conspiracy theories can be formed.
What do they find, and how might it relate to prominent conspiracy or misinformation topics in
American politics today?
In his chapter, Weeks talks about the role of communication structures such as social networks
or journalistic norms in creating misperceptions in people's minds. How do our methods of
communicating through media contribute to misperception? What examples can you identify of
this with current issues?
And to widen our thinking:
All the readings get at the importance of individual characteristics for the formation of false
beliefs. That is, people are predisposed to belief things that are consistent with their existing
attitudes, or that align with their own identities and values. On the flipside, people are disposed
to reject things that conflict with existing attitudes. Neither of these happen 100% of the time
they're predispositions only but they are common enough to make it difficult to simply
counterargue someone's false belief. Given this, how might communicators (including
journalists, campaign professionals, and even individuals talking with people they know) help
those they communicate with reach correct beliefs, or correct the incorrect beliefs they already
hold?.
Uno de los beneficios del estado de flujos de efectivo es que ayuda .pdf
Uno de los beneficios del estado de flujos de efectivo es que ayuda a los usuarios a evaluar la
flexibilidad financiera. Cul de las siguientes explicaciones es una descripcin de la flexibilidad
financiera? La capacidad de la empresa para invertir en una serie de proyectos con diferentes
objetivos y costos.
La capacidad de la empresa para responder y adaptarse a la adversidad financiera y las
necesidades y oportunidades inesperadas.
La capacidad de la empresa para pagar sus deudas a medida que vencen.
La cercana al efectivo de los activos y pasivos..
More from sales87 (20)
Using Martelle�s Chapters 12-14, please describe the impact of WWII .pdf
Using Martelle�s Chapters 12-14, please describe the impact of WWII .pdf
Using htmljscss, recreate the sliders. I have attached all images..pdf
Using htmljscss, recreate the sliders. I have attached all images..pdf
Using a Blackjack game that has the classesentities Blackjack, Card.pdf
Using a Blackjack game that has the classesentities Blackjack, Card.pdf
Using an Arduino microcontroller to code the following projectDet.pdf
Using an Arduino microcontroller to code the following projectDet.pdf
Use the internet to find an example of a chart or graph.Insert an .pdf
Use the internet to find an example of a chart or graph.Insert an .pdf
Use The Wobblies video as a guide httpswww.youtube.comwatchv.pdf
Use The Wobblies video as a guide httpswww.youtube.comwatchv.pdf
Use the singly linked list class introduced in the lab to implement .pdf
Use the singly linked list class introduced in the lab to implement .pdf
Use the Plan X and Plan Y tax schemes to complete the following tabl.pdf
Use the Plan X and Plan Y tax schemes to complete the following tabl.pdf
Use the pervious question to answer question 4. Suppose that in car.pdf
Use the pervious question to answer question 4. Suppose that in car.pdf
Use the information below to Developdraw a Systemigram for enviro.pdf
Use the information below to Developdraw a Systemigram for enviro.pdf
Use the phylogeny below to determine whether each statement is true .pdf
Use the phylogeny below to determine whether each statement is true .pdf
Use the input function to ask the user for a positive, whole number..pdf
Use the input function to ask the user for a positive, whole number..pdf
Use este estudio de caso para responder las siguientes preguntas. .pdf
Use este estudio de caso para responder las siguientes preguntas. .pdf
Usar su autoridad y poder formal para resolver un conflicto, mientra.pdf
Usar su autoridad y poder formal para resolver un conflicto, mientra.pdf
Usando la teor�a de la expectativa de la motivaci�n como marco para .pdf
Usando la teor�a de la expectativa de la motivaci�n como marco para .pdf
Usando Internet o fuentes de bibliotecas, seleccione cuatro organiza.pdf
Usando Internet o fuentes de bibliotecas, seleccione cuatro organiza.pdf
URGENTAssignment 3 - Software DesginPauline is considering how.pdf
URGENTAssignment 3 - Software DesginPauline is considering how.pdf
Uscinski and his co-authors describe how belief in political conspir.pdf
Uscinski and his co-authors describe how belief in political conspir.pdf
Uno de los beneficios del estado de flujos de efectivo es que ayuda .pdf
Uno de los beneficios del estado de flujos de efectivo es que ayuda .pdf
Recently uploaded
Acetabularia Information For Class 9 .docx
Acetabularia acetabulum is a single-celled green alga that in its vegetative state is morphologically differentiated into a basal rhizoid and an axially elongated stalk, which bears whorls of branching hairs. The single diploid nucleus resides in the rhizoid.
CACJapan - GROUP Presentation 1- Wk 4.pdf
Macroeconomics- Movie Location
This will be used as part of your Personal Professional Portfolio once graded.
Objective:
Prepare a presentation or a paper using research, basic comparative analysis, data organization and application of economic information. You will make an informed assessment of an economic climate outside of the United States to accomplish an entertainment industry objective.
special B.ed 2nd year old paper_20240531.pdf
Instagram:-
https://instagram.com/special_education_needs_01?igshid=YmMyMTA2M2Y=
WhatsApp:-
https://chat.whatsapp.com/JVakNIYlSV94x7bwunO3Dc
YouTube:-
https://youtube.com/@special_education_needs
Teligram :- https://t.me/special_education_needs
Slide Shere :-
https://www.slideshare.net/shabnambano20?utm_campaign=profiletracking&utm_medium=sssite&utm_source=ssslideview
Azure Interview Questions and Answers PDF By ScholarHat
Azure Interview Questions and Answers PDF By ScholarHat
How to Make a Field invisible in Odoo 17
It is possible to hide or invisible some fields in odoo. Commonly using “invisible” attribute in the field definition to invisible the fields. This slide will show how to make a field invisible in odoo 17.
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH ANSWERS.
Supporting (UKRI) OA monographs at Salford.pptx
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
Natural birth techniques - Mrs.Akanksha Trivedi Rama University
Natural birth techniques - Mrs.Akanksha Trivedi Rama UniversityAkanksha trivedi rama nursing college kanpur.
Natural birth techniques are various type such as/ water birth , alexender method, hypnosis, bradley method, lamaze method etc2024.06.01 Introducing a competency framework for languag learning materials ...
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
The French Revolution Class 9 Study Material pdf free download
The French Revolution, which began in 1789, was a period of radical social and political upheaval in France. It marked the decline of absolute monarchies, the rise of secular and democratic republics, and the eventual rise of Napoleon Bonaparte. This revolutionary period is crucial in understanding the transition from feudalism to modernity in Europe.
For more information, visit-www.vavaclasses.com
Overview on Edible Vaccine: Pros & Cons with Mechanism
This ppt include the description of the edible vaccine i.e. a new concept over the traditional vaccine administered by injection.
Unit 2- Research Aptitude (UGC NET Paper I).pdf
This slide describes the research aptitude of unit 2 in the UGC NET paper I.
MASS MEDIA STUDIES-835-CLASS XI Resource Material.pdf
mass media studies
CBSE
Full Book
for class 11th
Chapter -12, Antibiotics (One Page Notes).pdf
This is a notes for the D.Pharm students and related to the antibiotic drugs.
How libraries can support authors with open access requirements for UKRI fund...
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Event Link:-
https://meetups.mulesoft.com/events/details/mulesoft-mysore-presents-exploring-gemini-ai-and-integration-with-mulesoft/
Agenda
● Java 17 Upgrade Overview
● Why and by when do customers need to upgrade to Java 17?
● Is there any immediate impact to upgrading to Mule Runtime 4.6 and beyond?
● Which MuleSoft products are in scope?
For Upcoming Meetups Join Mysore Meetup Group - https://meetups.mulesoft.com/mysore/
YouTube:- youtube.com/@mulesoftmysore
Mysore WhatsApp group:- https://chat.whatsapp.com/EhqtHtCC75vCAX7gaO842N
Speaker:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Organizers:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Giridhar Meka - https://www.linkedin.com/in/giridharmeka
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Shyam Raj Prasad-
https://www.linkedin.com/in/shyam-raj-prasad/
Recently uploaded (20)
Azure Interview Questions and Answers PDF By ScholarHat
Azure Interview Questions and Answers PDF By ScholarHat
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
Natural birth techniques - Mrs.Akanksha Trivedi Rama University
Natural birth techniques - Mrs.Akanksha Trivedi Rama University
2024.06.01 Introducing a competency framework for languag learning materials ...
2024.06.01 Introducing a competency framework for languag learning materials ...
The French Revolution Class 9 Study Material pdf free download
The French Revolution Class 9 Study Material pdf free download
Overview on Edible Vaccine: Pros & Cons with Mechanism
Overview on Edible Vaccine: Pros & Cons with Mechanism
MASS MEDIA STUDIES-835-CLASS XI Resource Material.pdf
MASS MEDIA STUDIES-835-CLASS XI Resource Material.pdf
How libraries can support authors with open access requirements for UKRI fund...
How libraries can support authors with open access requirements for UKRI fund...
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Use the code below from the previous assignment that we need to exte.pdf
- 1. Use the code below from the previous assignment that we need to extend just follow the instructions above. ***Make sure after you are done to show the output of your results*** main.cpp #include #include "Contact.h" int main() { // create Contact object using parameterized constructor Contact c1("Barbara", "Liskov", "Huberman", "404 Ridgeway Dr", "NC", "27403", "336-274- 3344"); // show contact details c1.showContact(); cout << endl; // create Contact object using default constructor Contact c2; // test the overloaded input and output operators cin >> c2; cout << endl; cout << c2; return 0; } Address.h #ifndef ADDRESS_H #define ADDRESS_H #include using namespace std; // create a class named Address class Address { private: // private instance variables
- 2. string streetAddress, state, zip; public: // default constructor Address() { // initialize instance variables with empty strings streetAddress = ""; state = ""; zip = ""; } // parameterized constructor Address(string streetAddress, string state, string zip) { // initialize instance variables to given parameters this->streetAddress = streetAddress; this->state = state; this->zip = zip; } // copy constructor Address(const Address &a) { streetAddress = a.streetAddress; state = a.state; zip = a.zip; } // setters for all instance variables void setStreetAddress(string streetAddress) { this->streetAddress = streetAddress; } void setState(string state) { this->state = state; } void setZip(string zip) { this->zip = zip; } // getters for all instance variables string getStreetAddress() { return streetAddress; } string getState() { return state; } string getZip() { return zip; } // method to display the address void showAddress() {
- 3. cout << streetAddress << "n" << state << " " << zip << endl; } // declare the overloaded input and output operators friend ostream &operator<<(ostream &out, const Address &a); friend istream &operator>>(istream &in, Address &a); }; // define the overloaded output operator ostream &operator<<(ostream &out, const Address &a) { out << a.streetAddress << "n" << a.state << " " << a.zip << endl; return out; } // define the overloaded input operator istream &operator>>(istream &in, Address &a) { cout << "Enter street address: "; getline(in, a.streetAddress); cout << "Enter state: "; getline(in, a.state); cout << "Enter zip: "; getline(in, a.zip); return in; } #endif Contact.h #ifndef CONTACT_H #define CONTACT_H #include #include "Name.h" #include "Address.h" using namespace std; // create a class named Contact
- 4. class Contact { private: // private instance variables Name name; Address address; string phone; public: // default constructor Contact() { // initialize phone with empty string phone = ""; } // parameterized constructor Contact(string first_name, string last_name, string middle_name, string streetAddress, string state, string zip, string phone) { // initialize name and address to given strings setName(first_name, last_name, middle_name); setAddress(streetAddress, state, zip); // initialize phone to the given parameter this->phone = phone; } // copy constructor Contact(const Contact &c) { name = c.name; address = c.address; phone = c.phone; } // setters for all instance variables void setName(string first_name, string last_name, string middle_name) { this->name.setFirst_Name(first_name); this->name.setLast_Name(last_name);
- 5. this->name.setMiddle_Name(middle_name); } void setAddress(string streetAddress, string state, string zip) { this->address.setStreetAddress(streetAddress); this->address.setState(state); this->address.setZip(zip); } void setPhone(string phone) { this->phone = phone; } // getters for all instance variables string getName() { return name.getFirst_Name() + " " + name.getMiddle_Name() + " " + name.getMiddle_Name(); } string getAddress() { return address.getStreetAddress() + ", " + address.getState() + " - " + address.getZip(); } string getPhone() { return phone; } // method to display the contact details void showContact() { name.showName(); address.showAddress(); cout << phone << endl; } // declare the overloaded input and output operators friend ostream &operator<<(ostream &out, const Contact &c); friend istream &operator>>(istream &in, Contact &c); }; // define the overloaded output operator ostream &operator<<(ostream &out, const Contact &c) { out << c.name; out << c.address; out << c.phone << endl;
- 6. return out; } // define the overloaded input operator istream &operator>>(istream &in, Contact &c) { in >> c.name; in >> c.address; cout << "Enter phone number: "; getline(in, c.phone); return in; } #endif Name.h #ifndef NAME_H #define NAME_H #include using namespace std; // create a class named Name class Name { private: // private instance variables string first_name, last_name, middle_name; public: // default constructor Name() { // initialize instance variables with empty strings first_name = ""; last_name = ""; middle_name = ""; } // parameterized constructor Name(string first_name, string last_name, string middle_name) {
- 7. // initialize instance variables to given parameters this->first_name = first_name; this->last_name = last_name; this->middle_name = middle_name; } // copy constructor Name(const Name &n) { first_name = n.first_name; last_name = n.last_name; middle_name = n.middle_name; } // setters for all instance variables void setFirst_Name(string first_name) { this->first_name = first_name; } void setLast_Name(string last_name) { this->last_name = last_name; } void setMiddle_Name(string middle_name) { this->middle_name = middle_name; } // getters for all instance variables string getFirst_Name() { return first_name; } string getLast_Name() { return last_name; } string getMiddle_Name() { return middle_name; } // method to display the name void showName() { cout << last_name << ", " << first_name << " " << middle_name[0] << "." << endl; } // declare the overloaded input and output operators friend ostream &operator<<(ostream &out, const Name &n); friend istream &operator>>(istream &in, Name &n); }; // define the overloaded output operator ostream &operator<<(ostream &out, const Name &n) { out << n.last_name << ", " << n.first_name << " " << n.middle_name[0] << "." << endl; return out; }
- 8. // define the overloaded input operator istream &operator>>(istream &in, Name &n) { cout << "Enter first name: "; getline(in, n.first_name); cout << "Enter last name: "; getline(in, n.last_name); cout << "Enter middle name: "; getline(in, n.middle_name); return in; } #endif The purpose of this assignment is to assess your ability to do the following: - Implement a class with static data. - Implement classes utilizing aggregating relationships. - Utilize aggregate objects in a software solution. - Utilize file input/output in a C++ program. For this assignment, you will extend the Contact Management System 1 by creating a ContactManager class to manage a collection of Contact objects. Before starting your assignment, ensure that your Name, Address, and Contact class are error free. Step 1: Add a public static integer variable called total Ct to the Contact class. Add a private integer instance variable called identifier and a private member function, setIdentifier (), to the Contact class as shown below. Initialize totalct in your .cpp file and implement setIdentifier() as shown here: Declare a ContactManager class according to the given UML design. Implement the functions according to the following specification: - The constructor needs an empty body. The job of the constructor is to initialize the instance variables in the class. The instance variable here is a vector that is initialized by the vector class constructor. There are no additional steps needed in the ContactManager constructor. - getContact () takes an integer id and searches contacts to find a Contact with a matching identifier. The matching Contact is returned. If no matching Contact is found, return a default Contact object. - getContacts () takes a string l_name and searches the contacts to find all Contact objects with a matching last name. The function returns a vector of all matching Contact objects. - addContact() prompts the user for a new contact data, creates a Contact object, and adds the contact to contacts. - showContact() displays the contacts in a formatted output. - saveContacts() writes all of the contact data to the output source out. - loadContacts() loads raw contact data from the input source in, assigns each Contact object an identifier, and adds each Contact to contacts.