The compound is neutral. The Ammonium ion (NH4+) .pdf
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The compound is neutral. The Ammonium ion (NH4+) has a overall charge of +1 The nitrogen atom (-3) Hydrogen atom (+1). The Sulfate ion (SO4 2-) has overall charge of -2. (- 2) for oxygen atom (+6) for sulfur atom Solution The compound is neutral. The Ammonium ion (NH4+) has a overall charge of +1 The nitrogen atom (-3) Hydrogen atom (+1). The Sulfate ion (SO4 2-) has overall charge of -2. (- 2) for oxygen atom (+6) for sulfur atom.
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0 repersent even 1 for odd parity bitSolution0 repersent eve.pdf
0 repersent even 1 for odd parity bit
Solution
0 repersent even 1 for odd parity bit.
(1) What is the purpose of a VLAN trunkAns) A trunk is a line or .pdf
(1) What is the purpose of a VLAN trunk?
Ans) A trunk is a line or link designed to handle many signals simultaneously, and that connects
major switching centers or nodes in communication system. The transmitted data can be voice(as
in the conventinal telephone system) data, computer programs, images, video or control signals.
Trunks are used to interconnect switches to form nerwors, and to interconnect local area
nerworks(LAN) to form wide area networks (WAN) or virtual LAN (VLANs). A trunk often
consists of multiple wires, cables, or fiber opric strands to maximize the available bandwidth and
the number of channels that can be accommodated. A trunk can also be a broadband wireless
link. The use and management of trunks in a communications system is known as trunking. It
minimizes the number of physical signal paths, and thus the total amount of cable hardware,
required to serve a given number of suscribers in a nerwork.
In Cisco networks, trunking is special function can be assigned to a port, making thar port
capable of carrying traffic for any or all of the VLANs accessible by particular switch. such a
port is called a trunk port, in contrast to an access port, which carries traffic only to and from the
specific VLAN assigned to it. A trunk port marks frames with special identifying tags (either ISL
tags or 802.1Q tags) as they pass between switches, so easch frame can be routed to its intended
VLAN. An access port does nor provide such tags, because the VLAN for it is pre-assigned, and
identiying markers are therefore unnecessary.
Trunking:-
1)VLANs are local to each swithc\'s database, and VLAN infromation is not passed between
switches.
2)Trunk linksprovies VLAN identification for frames travelling between switches.
3)Cisco seitches have two Ethernet trunking mechanisms: ISL and IEEE 802.1Q
4)certain types of switches can negotiate trunk links.
5)Trunks carry trafic from all VLANs to and from the switch by default but can be configured to
carry only specified VLAN traffic.
6)Trunk links must be configured to allow trunking on each end of the link
2)Will a router always choose a static route over an OSPF route?
Ans) OSPF is an interior gatway routing protocaol that uses link states rather than distance
vectors for path selecation. OSPF propagates link-state advertisments rather than table updates.
Because only LSAs are exchnged, rather than entire routing table, OSPF nerwork converge more
quickly than RIP nerworks. OSPF supports MD5 and clear text neighbor authentication.
Authentiction should be used with all routing protocols when possible because route
redistribution between OSPF and other protocols when possible because route redistribution
between OSPF and other protocols (like RIP) can potentially be used by attackers to subvert
routing information. If NAT is used, if OSPF is operating on public and private areas, and if
address filtering is required, then you need to run two OSPF processes—one process for the
public areas and one .
viscosity and surface tension are both related to.pdf
viscosity and surface tension are both related to intermolecularforces (IMFs)
pentane is nonpolar and cannot H-bond, so only LDF is possible(London Dispersion Force)
pentanal is polar, but cannot H-bond => (Dipole-Dipole) pentanol has an OH group, so it can H-
bond => (HydrogenBonding) With higher IMFs, you get greater surface tension and
greaterviscosity (since the liquid molecules are more attracted to eachother) In order of
decreasing IMF: (and thus decreasing viscosity/surfacetension) pentanol pentanal pentane
Solution
viscosity and surface tension are both related to intermolecularforces (IMFs)
pentane is nonpolar and cannot H-bond, so only LDF is possible(London Dispersion Force)
pentanal is polar, but cannot H-bond => (Dipole-Dipole) pentanol has an OH group, so it can H-
bond => (HydrogenBonding) With higher IMFs, you get greater surface tension and
greaterviscosity (since the liquid molecules are more attracted to eachother) In order of
decreasing IMF: (and thus decreasing viscosity/surfacetension) pentanol pentanal pentane.
Imports System.Net.Sockets Imports System.Text Public Class Form1 .pdf
Imports System.Net.Sockets Imports System.Text Public Class Form1 Dim clientSocket As
New System.Net.Sockets.TcpClient() Dim serverStream As NetworkStream Dim readData
As String Dim infiniteCounter As Integer Private Sub Button1_Click(ByVal sender As
System.Object, _ ByVal e As System.EventArgs) Handles Button1.Click Dim
outStream As Byte() = _ System.Text.Encoding.ASCII.GetBytes(TextBox2.Text + \"$\")
serverStream.Write(outStream, 0, outStream.Length) serverStream.Flush() End Sub
Private Sub msg() If Me.InvokeRequired Then Me.Invoke(New
MethodInvoker(AddressOf msg)) Else TextBox1.Text = TextBox1.Text + _
Environment.NewLine + \" >> \" + readData End If End Sub Private Sub
Button2_Click(ByVal sender As System.Object, _ ByVal e As System.EventArgs) Handles
Button2.Click readData = \"Conected to Chat Server ...\" msg()
clientSocket.Connect(\"127.0.0.1\", 8888) \'Label1.Text = \"Client Socket Program - Server
Connected ...\" serverStream = clientSocket.GetStream() Dim outStream As Byte() =
_ System.Text.Encoding.ASCII.GetBytes(TextBox3.Text + \"$\")
serverStream.Write(outStream, 0, outStream.Length) serverStream.Flush() Dim
ctThread As Threading.Thread = _ New Threading.Thread(AddressOf getMessage)
ctThread.Start() End Sub Private Sub getMessage() For infiniteCounter = 1 To 2
infiniteCounter = 1 serverStream = clientSocket.GetStream() Dim buffSize As
Integer Dim inStream(10024) As Byte buffSize = clientSocket.ReceiveBufferSize
serverStream.Read(inStream, 0, buffSize) Dim returndata As String = _
System.Text.Encoding.ASCII.GetString(inStream) readData = \"\" + returndata
msg() Next End Sub End Class
Solution
Imports System.Net.Sockets Imports System.Text Public Class Form1 Dim clientSocket As
New System.Net.Sockets.TcpClient() Dim serverStream As NetworkStream Dim readData
As String Dim infiniteCounter As Integer Private Sub Button1_Click(ByVal sender As
System.Object, _ ByVal e As System.EventArgs) Handles Button1.Click Dim
outStream As Byte() = _ System.Text.Encoding.ASCII.GetBytes(TextBox2.Text + \"$\")
serverStream.Write(outStream, 0, outStream.Length) serverStream.Flush() End Sub
Private Sub msg() If Me.InvokeRequired Then Me.Invoke(New
MethodInvoker(AddressOf msg)) Else TextBox1.Text = TextBox1.Text + _
Environment.NewLine + \" >> \" + readData End If End Sub Private Sub
Button2_Click(ByVal sender As System.Object, _ ByVal e As System.EventArgs) Handles
Button2.Click readData = \"Conected to Chat Server ...\" msg()
clientSocket.Connect(\"127.0.0.1\", 8888) \'Label1.Text = \"Client Socket Program - Server
Connected ...\" serverStream = clientSocket.GetStream() Dim outStream As Byte() =
_ System.Text.Encoding.ASCII.GetBytes(TextBox3.Text + \"$\")
serverStream.Write(outStream, 0, outStream.Length) serverStream.Flush() Dim
ctThread As Threading.Thread = _ New Threading.Thread(AddressOf getMessage)
ctThread.Start() End Sub Private Sub getMessage() For infiniteCounter = 1 To 2
infiniteCounter = 1 serverStream = clientSocket.GetStream() Dim buffSi.
What is Fluorescence Electrons in an atom or a m.pdf
What is Fluorescence? Electrons in an atom or a molecule can absorb the energy in
the electromagnetic radiation and thereby excite to an upper energy state. This upper energy state
is unstable; therefore, electron likes to come back to the ground state. When coming back, it
emits the absorbed wavelength. In this relaxation process, they emit excess energy as photons.
This relaxation process is known as fluorescence. Fluorescence takes place much more rapidly.
Generally, it completes in about 10-5 s or less time from the time of excitation. In atomic
fluorescence, gaseous atoms fluoresce when they are exposed to radiation with a wavelength that
exactly matches one of the absorption lines of the element. For example, gaseous sodium atoms
absorb and excite by absorbing 589 nm radiations. Relaxation takes place after this by
reemission of fluorescent radiation of the identical wavelength. Because of this, we can use
fluorescence to identify different elements. When excitation and reemission wavelengths are the
same, the resulting emission is called resonance fluorescence. Other than fluorescence, there are
other mechanisms by which an excited atom or molecule can give up its excess energy and relax
to its ground state. Nonradiative relaxation and fluorescence emissions are two such important
mechanisms. Because of many mechanisms, the lifetime of an excited state is brief. The relative
number of molecules that fluoresce is small because fluorescence requires structural features that
slow the rate of the nonradiative relaxation and enhance the rate of fluorescence. In most
molecules, these features are not there; therefore, they undergo nonradiative relaxation, and
fluorescence does not occur. Molecular fluorescence bands are made up of a large number of
closely spaced lines; therefore, usually it is hard to resolve. What is Phosphorescence? When
molecules absorb light and go to the excited state they have two options. They can either release
energy and come back to the ground state immediately or undergo other non-radiative processes.
If the excited molecule undergoes a non radiative process, it emits some energy and come to a
triplet state where the energy is somewhat lesser than the energy of the exited state, but it is
higher than the ground state energy. Molecules can stay a bit longer in this less energy triplet
state. This state is known as the metastable state. Then metastable state (triplet state) can slowly
decay by emitting photons, and come back to the ground state (singlet state). When this happens
it is known as phosphorescence. What is the difference between Fluorescence and
Phosphorescence? • When light is supplied to a sample of molecules, we immediately see the
fluorescence. Fluorescence stops as soon as we take away the light source. But phosphorescence
tends to stay little longer even after the irradiating light source is removed. • Fluorescence takes
place when excited energy is released, and the molecule comes back to the gro.
The F- will react with water to form HF and OH F-.pdf
The F- will react with water to form HF and OH F- + H2O====> HF + OH- Kb
for this reaction is 1.58 x 10^-11 At equilibrium, [F-] = .17 - x [HF] = x [OH-] = x The reactant
is consumed by some amount x while the products are formed by some amount x Kb =
concentration of products/reactants = x*x/(.17-x) = 1.58x 10^-11 x^2 + 1.58 x 10^-11x - 2.68 x
10^-12 = 0 Solve for x, x = 1.64 x 10^-6 [HF]= x = 1.64 x 10^-6 M [OH-] = x = 1.64 x 10^-6 M
We know, [H3O+]*[OH-] = 10^-14 [H3O+] = 10^-14/(1.64 x 10^-6) = 6.09 x 10^-9 Hope this
helped
Solution
The F- will react with water to form HF and OH F- + H2O====> HF + OH- Kb
for this reaction is 1.58 x 10^-11 At equilibrium, [F-] = .17 - x [HF] = x [OH-] = x The reactant
is consumed by some amount x while the products are formed by some amount x Kb =
concentration of products/reactants = x*x/(.17-x) = 1.58x 10^-11 x^2 + 1.58 x 10^-11x - 2.68 x
10^-12 = 0 Solve for x, x = 1.64 x 10^-6 [HF]= x = 1.64 x 10^-6 M [OH-] = x = 1.64 x 10^-6 M
We know, [H3O+]*[OH-] = 10^-14 [H3O+] = 10^-14/(1.64 x 10^-6) = 6.09 x 10^-9 Hope this
helped.
Step1 NaF is the correct answer Step2 Na+ + e --.pdf
Step1 NaF is the correct answer Step2 Na+ + e ----> Na ; 2 Na(s) + 2H2O(l)---
>2NaOH(aq)+ H2(g) Step3 2F- -----> F2(g) +2e Step4 2F2 (g) +2 H2O(l)------> 4HF(aq )+ O2
(g)
Solution
Step1 NaF is the correct answer Step2 Na+ + e ----> Na ; 2 Na(s) + 2H2O(l)---
>2NaOH(aq)+ H2(g) Step3 2F- -----> F2(g) +2e Step4 2F2 (g) +2 H2O(l)------> 4HF(aq )+ O2
(g).
SO3 wont react with molecular oxygen because in S.pdf
SO3 wont react with molecular oxygen because in SO3 sulphurs oxidation state is
+6 which is the maximum oxidation number possible for sulphur, hence it can\'t react with
oxygen and expand its oxidation state.
Solution
SO3 wont react with molecular oxygen because in SO3 sulphurs oxidation state is
+6 which is the maximum oxidation number possible for sulphur, hence it can\'t react with
oxygen and expand its oxidation state..
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(1) What is the purpose of a VLAN trunkAns) A trunk is a line or .pdf
(1) What is the purpose of a VLAN trunk?
Ans) A trunk is a line or link designed to handle many signals simultaneously, and that connects
major switching centers or nodes in communication system. The transmitted data can be voice(as
in the conventinal telephone system) data, computer programs, images, video or control signals.
Trunks are used to interconnect switches to form nerwors, and to interconnect local area
nerworks(LAN) to form wide area networks (WAN) or virtual LAN (VLANs). A trunk often
consists of multiple wires, cables, or fiber opric strands to maximize the available bandwidth and
the number of channels that can be accommodated. A trunk can also be a broadband wireless
link. The use and management of trunks in a communications system is known as trunking. It
minimizes the number of physical signal paths, and thus the total amount of cable hardware,
required to serve a given number of suscribers in a nerwork.
In Cisco networks, trunking is special function can be assigned to a port, making thar port
capable of carrying traffic for any or all of the VLANs accessible by particular switch. such a
port is called a trunk port, in contrast to an access port, which carries traffic only to and from the
specific VLAN assigned to it. A trunk port marks frames with special identifying tags (either ISL
tags or 802.1Q tags) as they pass between switches, so easch frame can be routed to its intended
VLAN. An access port does nor provide such tags, because the VLAN for it is pre-assigned, and
identiying markers are therefore unnecessary.
Trunking:-
1)VLANs are local to each swithc\'s database, and VLAN infromation is not passed between
switches.
2)Trunk linksprovies VLAN identification for frames travelling between switches.
3)Cisco seitches have two Ethernet trunking mechanisms: ISL and IEEE 802.1Q
4)certain types of switches can negotiate trunk links.
5)Trunks carry trafic from all VLANs to and from the switch by default but can be configured to
carry only specified VLAN traffic.
6)Trunk links must be configured to allow trunking on each end of the link
2)Will a router always choose a static route over an OSPF route?
Ans) OSPF is an interior gatway routing protocaol that uses link states rather than distance
vectors for path selecation. OSPF propagates link-state advertisments rather than table updates.
Because only LSAs are exchnged, rather than entire routing table, OSPF nerwork converge more
quickly than RIP nerworks. OSPF supports MD5 and clear text neighbor authentication.
Authentiction should be used with all routing protocols when possible because route
redistribution between OSPF and other protocols when possible because route redistribution
between OSPF and other protocols (like RIP) can potentially be used by attackers to subvert
routing information. If NAT is used, if OSPF is operating on public and private areas, and if
address filtering is required, then you need to run two OSPF processes—one process for the
public areas and one .
viscosity and surface tension are both related to.pdf
viscosity and surface tension are both related to intermolecularforces (IMFs)
pentane is nonpolar and cannot H-bond, so only LDF is possible(London Dispersion Force)
pentanal is polar, but cannot H-bond => (Dipole-Dipole) pentanol has an OH group, so it can H-
bond => (HydrogenBonding) With higher IMFs, you get greater surface tension and
greaterviscosity (since the liquid molecules are more attracted to eachother) In order of
decreasing IMF: (and thus decreasing viscosity/surfacetension) pentanol pentanal pentane
Solution
viscosity and surface tension are both related to intermolecularforces (IMFs)
pentane is nonpolar and cannot H-bond, so only LDF is possible(London Dispersion Force)
pentanal is polar, but cannot H-bond => (Dipole-Dipole) pentanol has an OH group, so it can H-
bond => (HydrogenBonding) With higher IMFs, you get greater surface tension and
greaterviscosity (since the liquid molecules are more attracted to eachother) In order of
decreasing IMF: (and thus decreasing viscosity/surfacetension) pentanol pentanal pentane.
Imports System.Net.Sockets Imports System.Text Public Class Form1 .pdf
Imports System.Net.Sockets Imports System.Text Public Class Form1 Dim clientSocket As
New System.Net.Sockets.TcpClient() Dim serverStream As NetworkStream Dim readData
As String Dim infiniteCounter As Integer Private Sub Button1_Click(ByVal sender As
System.Object, _ ByVal e As System.EventArgs) Handles Button1.Click Dim
outStream As Byte() = _ System.Text.Encoding.ASCII.GetBytes(TextBox2.Text + \"$\")
serverStream.Write(outStream, 0, outStream.Length) serverStream.Flush() End Sub
Private Sub msg() If Me.InvokeRequired Then Me.Invoke(New
MethodInvoker(AddressOf msg)) Else TextBox1.Text = TextBox1.Text + _
Environment.NewLine + \" >> \" + readData End If End Sub Private Sub
Button2_Click(ByVal sender As System.Object, _ ByVal e As System.EventArgs) Handles
Button2.Click readData = \"Conected to Chat Server ...\" msg()
clientSocket.Connect(\"127.0.0.1\", 8888) \'Label1.Text = \"Client Socket Program - Server
Connected ...\" serverStream = clientSocket.GetStream() Dim outStream As Byte() =
_ System.Text.Encoding.ASCII.GetBytes(TextBox3.Text + \"$\")
serverStream.Write(outStream, 0, outStream.Length) serverStream.Flush() Dim
ctThread As Threading.Thread = _ New Threading.Thread(AddressOf getMessage)
ctThread.Start() End Sub Private Sub getMessage() For infiniteCounter = 1 To 2
infiniteCounter = 1 serverStream = clientSocket.GetStream() Dim buffSize As
Integer Dim inStream(10024) As Byte buffSize = clientSocket.ReceiveBufferSize
serverStream.Read(inStream, 0, buffSize) Dim returndata As String = _
System.Text.Encoding.ASCII.GetString(inStream) readData = \"\" + returndata
msg() Next End Sub End Class
Solution
Imports System.Net.Sockets Imports System.Text Public Class Form1 Dim clientSocket As
New System.Net.Sockets.TcpClient() Dim serverStream As NetworkStream Dim readData
As String Dim infiniteCounter As Integer Private Sub Button1_Click(ByVal sender As
System.Object, _ ByVal e As System.EventArgs) Handles Button1.Click Dim
outStream As Byte() = _ System.Text.Encoding.ASCII.GetBytes(TextBox2.Text + \"$\")
serverStream.Write(outStream, 0, outStream.Length) serverStream.Flush() End Sub
Private Sub msg() If Me.InvokeRequired Then Me.Invoke(New
MethodInvoker(AddressOf msg)) Else TextBox1.Text = TextBox1.Text + _
Environment.NewLine + \" >> \" + readData End If End Sub Private Sub
Button2_Click(ByVal sender As System.Object, _ ByVal e As System.EventArgs) Handles
Button2.Click readData = \"Conected to Chat Server ...\" msg()
clientSocket.Connect(\"127.0.0.1\", 8888) \'Label1.Text = \"Client Socket Program - Server
Connected ...\" serverStream = clientSocket.GetStream() Dim outStream As Byte() =
_ System.Text.Encoding.ASCII.GetBytes(TextBox3.Text + \"$\")
serverStream.Write(outStream, 0, outStream.Length) serverStream.Flush() Dim
ctThread As Threading.Thread = _ New Threading.Thread(AddressOf getMessage)
ctThread.Start() End Sub Private Sub getMessage() For infiniteCounter = 1 To 2
infiniteCounter = 1 serverStream = clientSocket.GetStream() Dim buffSi.
What is Fluorescence Electrons in an atom or a m.pdf
What is Fluorescence? Electrons in an atom or a molecule can absorb the energy in
the electromagnetic radiation and thereby excite to an upper energy state. This upper energy state
is unstable; therefore, electron likes to come back to the ground state. When coming back, it
emits the absorbed wavelength. In this relaxation process, they emit excess energy as photons.
This relaxation process is known as fluorescence. Fluorescence takes place much more rapidly.
Generally, it completes in about 10-5 s or less time from the time of excitation. In atomic
fluorescence, gaseous atoms fluoresce when they are exposed to radiation with a wavelength that
exactly matches one of the absorption lines of the element. For example, gaseous sodium atoms
absorb and excite by absorbing 589 nm radiations. Relaxation takes place after this by
reemission of fluorescent radiation of the identical wavelength. Because of this, we can use
fluorescence to identify different elements. When excitation and reemission wavelengths are the
same, the resulting emission is called resonance fluorescence. Other than fluorescence, there are
other mechanisms by which an excited atom or molecule can give up its excess energy and relax
to its ground state. Nonradiative relaxation and fluorescence emissions are two such important
mechanisms. Because of many mechanisms, the lifetime of an excited state is brief. The relative
number of molecules that fluoresce is small because fluorescence requires structural features that
slow the rate of the nonradiative relaxation and enhance the rate of fluorescence. In most
molecules, these features are not there; therefore, they undergo nonradiative relaxation, and
fluorescence does not occur. Molecular fluorescence bands are made up of a large number of
closely spaced lines; therefore, usually it is hard to resolve. What is Phosphorescence? When
molecules absorb light and go to the excited state they have two options. They can either release
energy and come back to the ground state immediately or undergo other non-radiative processes.
If the excited molecule undergoes a non radiative process, it emits some energy and come to a
triplet state where the energy is somewhat lesser than the energy of the exited state, but it is
higher than the ground state energy. Molecules can stay a bit longer in this less energy triplet
state. This state is known as the metastable state. Then metastable state (triplet state) can slowly
decay by emitting photons, and come back to the ground state (singlet state). When this happens
it is known as phosphorescence. What is the difference between Fluorescence and
Phosphorescence? • When light is supplied to a sample of molecules, we immediately see the
fluorescence. Fluorescence stops as soon as we take away the light source. But phosphorescence
tends to stay little longer even after the irradiating light source is removed. • Fluorescence takes
place when excited energy is released, and the molecule comes back to the gro.
The F- will react with water to form HF and OH F-.pdf
The F- will react with water to form HF and OH F- + H2O====> HF + OH- Kb
for this reaction is 1.58 x 10^-11 At equilibrium, [F-] = .17 - x [HF] = x [OH-] = x The reactant
is consumed by some amount x while the products are formed by some amount x Kb =
concentration of products/reactants = x*x/(.17-x) = 1.58x 10^-11 x^2 + 1.58 x 10^-11x - 2.68 x
10^-12 = 0 Solve for x, x = 1.64 x 10^-6 [HF]= x = 1.64 x 10^-6 M [OH-] = x = 1.64 x 10^-6 M
We know, [H3O+]*[OH-] = 10^-14 [H3O+] = 10^-14/(1.64 x 10^-6) = 6.09 x 10^-9 Hope this
helped
Solution
The F- will react with water to form HF and OH F- + H2O====> HF + OH- Kb
for this reaction is 1.58 x 10^-11 At equilibrium, [F-] = .17 - x [HF] = x [OH-] = x The reactant
is consumed by some amount x while the products are formed by some amount x Kb =
concentration of products/reactants = x*x/(.17-x) = 1.58x 10^-11 x^2 + 1.58 x 10^-11x - 2.68 x
10^-12 = 0 Solve for x, x = 1.64 x 10^-6 [HF]= x = 1.64 x 10^-6 M [OH-] = x = 1.64 x 10^-6 M
We know, [H3O+]*[OH-] = 10^-14 [H3O+] = 10^-14/(1.64 x 10^-6) = 6.09 x 10^-9 Hope this
helped.
Step1 NaF is the correct answer Step2 Na+ + e --.pdf
Step1 NaF is the correct answer Step2 Na+ + e ----> Na ; 2 Na(s) + 2H2O(l)---
>2NaOH(aq)+ H2(g) Step3 2F- -----> F2(g) +2e Step4 2F2 (g) +2 H2O(l)------> 4HF(aq )+ O2
(g)
Solution
Step1 NaF is the correct answer Step2 Na+ + e ----> Na ; 2 Na(s) + 2H2O(l)---
>2NaOH(aq)+ H2(g) Step3 2F- -----> F2(g) +2e Step4 2F2 (g) +2 H2O(l)------> 4HF(aq )+ O2
(g).
SO3 wont react with molecular oxygen because in S.pdf
SO3 wont react with molecular oxygen because in SO3 sulphurs oxidation state is
+6 which is the maximum oxidation number possible for sulphur, hence it can\'t react with
oxygen and expand its oxidation state.
Solution
SO3 wont react with molecular oxygen because in SO3 sulphurs oxidation state is
+6 which is the maximum oxidation number possible for sulphur, hence it can\'t react with
oxygen and expand its oxidation state..
Milk neutralises the basics formed. .pdf
Milk neutralises the basics formed.
Solution
Milk neutralises the basics formed..
Li + 2H2O = Li(OH)2 + 2H2 moles of Li =1.0502 Mo.pdf
Li + 2H2O = Li(OH)2 + 2H2 moles of Li =1.0502 Moles of water =1.05 Since 1
moles of Li reacts with 2 moles of water so 0.525 moles of Li will not react . Mass of H2 gas
releases = 1.05*2 =2.1 gram
Solution
Li + 2H2O = Li(OH)2 + 2H2 moles of Li =1.0502 Moles of water =1.05 Since 1
moles of Li reacts with 2 moles of water so 0.525 moles of Li will not react . Mass of H2 gas
releases = 1.05*2 =2.1 gram.
In mathematics, if G is a group, and H is a subgr.pdf
In mathematics, if G is a group, and H is a subgroup of G, and g is an element of G,
then gH = {gh : h an element of H?} is a left coset of H in G, and Hg = {hg : h an element of H?}
is a right coset of H in G. Only when H is normal will the right and left cosets of H coincide,
which is one definition of normality of a subgroup. A coset is a left or right coset of some
subgroup in G. Since Hg = g?(?g-1Hg?), the right cosets Hg (of H?) and the left cosets g?(?g-
1Hg?) (of the conjugate subgroup g-1Hg?) are the same. Hence it is not meaningful to speak of a
coset as being left or right unless one first specifies the underlying subgroup. In other words: a
right coset of one subgroup equals a left coset of a different (conjugate) subgroup. If the left
cosets and right cosets are the same then H is a normal subgroup and the cosets form a group
called the quotient group. The map gH?(gH)-1=Hg-1 defines a bijection between the left cosets
and the right cosets of H, so the number of left cosets is equal to the number of right cosets. The
common value is called the index of H in G. For abelian groups, left cosets and right cosets are
always the same. If the group operation is written additively then the notation used changes to
g+H or H+g. Cosets are a basic tool in the study of groups; for example they play a central role
in Lagrange\'s theorem. Examples et G be the multiplicative group of {-1,1}, and H the trivial
subgroup (1,*). Then -1H={-1}, 1H=H are the sole cosets of H in G. Let G be the additive group
of integers Z = {..., -2, -1, 0, 1, 2, ...} and H the subgroup mZ = {..., -2m, -m, 0, m, 2m, ...}
where m is a positive integer. Then the cosets of H in G are the m sets mZ, mZ+1, ... mZ+(m-1),
where mZ+a={..., -2m+a, -m+a, a, m+a, 2m+a, ...}. There are no more than m cosets, because
mZ+m=m(Z+1)=mZ. The coset mZ+a is the congruence class of a modulo m.[1] Another
example of a coset comes from the theory of vector spaces. The elements (vectors) of a vector
space form an abelian group under vector addition. It is not hard to show that subspaces of a
vector space are subgroups of this group. For a vector space V, a subspace W, and a fixed vector
a in V, the sets are called affine subspaces, and are cosets (both left and right, since the group is
abelian). In terms of geometric vectors, these affine subspaces are all the \"lines\" or \"planes\"
parallel to the subspace, which is a line or plane going through the origin
Solution
In mathematics, if G is a group, and H is a subgroup of G, and g is an element of G,
then gH = {gh : h an element of H?} is a left coset of H in G, and Hg = {hg : h an element of H?}
is a right coset of H in G. Only when H is normal will the right and left cosets of H coincide,
which is one definition of normality of a subgroup. A coset is a left or right coset of some
subgroup in G. Since Hg = g?(?g-1Hg?), the right cosets Hg (of H?) and the left cosets g?(?g-
1Hg?) (of the conjugate subgroup g-1Hg?) are the same. Hence it is .
Use of technology and innovation in Healthcare centerSolutionU.pdf
Use of technology and innovation in Healthcare center
Solution
Use of technology and innovation in Healthcare center.
There are 22 different cuttings.The number of possible tiling of t.pdf
There are 22 different cuttings.
The number of possible tiling of triangular piece nX2, using the above three kinds of pieces:
n=22
Solution
There are 22 different cuttings.
The number of possible tiling of triangular piece nX2, using the above three kinds of pieces:
n=22.
Sorry for the late response, but please rate!SolutionS.pdf
Sorry for the late response, but please rate!
Solution
Sorry for the late response, but please rate!.
Option D is the correct answer. As the morphogen is responsible for .pdf
Option D is the correct answer. As the morphogen is responsible for the patterning of anterior
parts like head it\'s presence in the posterior end will result in formation of head. This way the
organism will be having two heads.
Solution
Option D is the correct answer. As the morphogen is responsible for the patterning of anterior
parts like head it\'s presence in the posterior end will result in formation of head. This way the
organism will be having two heads..
d. Al2S3 note Al is in oxidation state of +3, a.pdf
d. Al2S3 note: Al is in oxidation state of +3, and S is of -2. to balance the charge,
there need two Al and three S in this molecule.
Solution
d. Al2S3 note: Al is in oxidation state of +3, and S is of -2. to balance the charge,
there need two Al and three S in this molecule..
In number of government and private case studies include that the in.pdf
In number of government and private case studies include that the insiders are threat to the
organizations as they knowingly participate in cyberattacks have broad range of motivations ,
financial gain ,revenge , desire for recognition and power response to blackmail , loyality to
others in the organizations .organizations must balance the need to access the information for
conducting business with protecting this information from unauthorised access and to the secret
information is considered as an external threat and it is also malicious threat to organization and
that comes from people within the organization such as employees , former employees ,
contractors and bussiness associates . there are types of insider threats as threats occur for
various reasons in some cases individuals use their access to sensitive information for personal or
financial gain and they join the third parties such as other organizations or hacking groups and
operate on their behalf to gain access from within the network of trust and share a sensitive
information and another type of insider threat is referred to as logic bomb and in this harmful
software is left running on computer systems by former employe and which cause the problems
to complete disaster . insider threats can be intentional or unintentional and this term can be
referred to individual who gain insider access using false information but who is not a true
employee or an officer of the organization .
Insider threats are very difficult to detect , identify and block the outside attacks consider a
former employee using an unauthorized login and it wont raise the same security flag as an
outsider attempts to gain the access to company secret information or compny network and for
this reason insider threats are not detected before access is granted or damage is done . there are
many more factors that make insider threats more difficult to detect as for one many individuals
with authorized access are also aware of certain security measures which they must find a way to
avoid detection and insider threats dont have to get around firewalls or other network based
security measures as they work within the network and finally many organizations simply lack
the visibility into users access and data activity ie required to sufficiently detect and defend
against the insider threats and these are not only present in bussiness organizations but these
threats are present in mordern security program so this is the reason why insiders are considered
as threat to the organizations.
Solution
In number of government and private case studies include that the insiders are threat to the
organizations as they knowingly participate in cyberattacks have broad range of motivations ,
financial gain ,revenge , desire for recognition and power response to blackmail , loyality to
others in the organizations .organizations must balance the need to access the information for
conducting business with protecting this information from u.
Benzoic Acid is insoluble in nonpolar solvents li.pdf
Benzoic Acid is insoluble in nonpolar solvents like petroleumether, yet on the other
hand biphenyl is very soluble in petroleumether. So dissolve your crude product in petroleum
ether, then do avacume distilation. You can do a spectoscopic analysis of thesolution which
remains in the vacume flask for traces ofbiphenyl.
Solution
Benzoic Acid is insoluble in nonpolar solvents like petroleumether, yet on the other
hand biphenyl is very soluble in petroleumether. So dissolve your crude product in petroleum
ether, then do avacume distilation. You can do a spectoscopic analysis of thesolution which
remains in the vacume flask for traces ofbiphenyl..
Hi, Please find my code. I have added comment against each line, ple.pdf
Hi, Please find my code. I have added comment against each line, please go through each
comment.
Please let me know in case of any issue.
######## input.txt ###########
Alexis
Jonathan
Colby
Mason
Casey Clarence
Winston
Terry
Jeremy
Maya
########## Java Program ###########
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import java.util.ArrayList;
import java.util.Scanner;
public class ArrayListTest {
public static void main(String[] args) throws IOException {
Scanner sc = new Scanner(System.in);
// asking for input file name
System.out.print(\"Enter input file name: \");
String fileName = sc .next();
// now opening file using FieReader
FileReader fr = new FileReader(fileName);
//wrapping file reader into BufferedReader
BufferedReader br = new BufferedReader(fr);
// declaring nameList ArrayList
ArrayList nameList = new ArrayList();
// now reading name from fiel
String name;
while((name = br.readLine()) != null){
// adding currently read name in list
nameList.add(name);
}
// closing file reader
br.close();
fr.close();
// printting nameList on Screen
System.out.println(nameList.toString());
//adding \"Michael\"
nameList.add(\"Michael\");
System.out.println(\"Name List after adding Michael: \");
System.out.println(nameList.toString());
// adding \"Lucy\" at position 2 (index 1)
nameList.add(1, \"Lucy\");
System.out.println(\"Printing name list after adding Lucy at position 2: \");
System.out.println(nameList.toString());
// code to find \"Michael\"
int index = nameList.indexOf(\"Michael\");
System.out.println(\"Michael is at index: \"+index);
// replacing Michael with Mike , first removing Michael
nameList.remove(index);
// adding Mike at index
nameList.add(index, \"Mike\");
System.out.println(\"After replacing Michael with Mike\");
System.out.println(nameList.toString());
System.out.print(\"Enter a name to be deleted: \");
String s = sc.next();
// finding index of s
index = nameList.indexOf(s);
if(index == -1)
System.out.println(s+ \"is not present in name list\");
else{
System.out.println(s+\" is at index \"+index);
nameList.remove(index);
System.out.println(\"After removing \"+s+\", name list: \");
System.out.println(nameList.toString());
}
}
}
/*
Output:
Enter input file name: input.txt
[Alexis, Jonathan, Colby, Mason, Casey Clarence, Winston, Terry, Jeremy, Maya]
Name List after adding Michael:
[Alexis, Jonathan, Colby, Mason, Casey Clarence, Winston, Terry, Jeremy, Maya, Michael]
Printing name list after adding Lucy at position 2:
[Alexis, Lucy, Jonathan, Colby, Mason, Casey Clarence, Winston, Terry, Jeremy, Maya,
Michael]
Michael is at index: 10
After replacing Michael with Mike
[Alexis, Lucy, Jonathan, Colby, Mason, Casey Clarence, Winston, Terry, Jeremy, Maya, Mike]
Enter a name to be deleted: Colby
Colby is at index 3
After removing Colby, name list:
[Alexis, Lucy, Jonathan, Mason, Casey Clarence, Winston, Terry, Jeremy, Maya, Mike]
*/
Solution
Hi, Please find my code. I have added comment against .
First it crosses the saturated liquid line and then traces the isoth.pdf
First it crosses the saturated liquid line and then traces the isothermal curve while inside the
vapor dome and then crosses the saturated vapor line.
Solution
First it crosses the saturated liquid line and then traces the isothermal curve while inside the
vapor dome and then crosses the saturated vapor line..
B doublet is correct note the neighboring C has .pdf
B doublet is correct note: the neighboring C has only one H that split CH3 into a
doublet.
Solution
B doublet is correct note: the neighboring C has only one H that split CH3 into a
doublet..
failing to reject the null hypothesis means there is not sufficient .pdf
failing to reject the null hypothesis means there is not sufficient evidence for his conclusion.
Solution
failing to reject the null hypothesis means there is not sufficient evidence for his conclusion..
CounterfactualCounterfactual thinking gained attention from a psy.pdf
Counterfactual:
Counterfactual thinking gained attention from a psychological point of view. Cognitive scientists
studied the mental representations and cognitive processes that bring about the creation of
counterfactuals developed the study of counterfactual thought, showing that people tend to think
\'if only\' more often about exceptional events than about normal events.
Early research on counterfactual thinking took a particular point of view, the thoughts were the
sign of difficult skills, psychological error or bias. As research increased, a new wave of
approach began, taking a functional view, believing that counterfactual thinking served as a
largely beneficial behavioral controller.
Scientists, however, need to be a little clear. Scientists have to be able to describe the nature of
that association. In order to do so, they have developed terminology to describe the causal
relationship between two events. They say that causes are necessary,sufficient, neither, or both.
Understanding Causality:
Solution
Counterfactual:
Counterfactual thinking gained attention from a psychological point of view. Cognitive scientists
studied the mental representations and cognitive processes that bring about the creation of
counterfactuals developed the study of counterfactual thought, showing that people tend to think
\'if only\' more often about exceptional events than about normal events.
Early research on counterfactual thinking took a particular point of view, the thoughts were the
sign of difficult skills, psychological error or bias. As research increased, a new wave of
approach began, taking a functional view, believing that counterfactual thinking served as a
largely beneficial behavioral controller.
Scientists, however, need to be a little clear. Scientists have to be able to describe the nature of
that association. In order to do so, they have developed terminology to describe the causal
relationship between two events. They say that causes are necessary,sufficient, neither, or both.
Understanding Causality:.
A) Sugar may precipitate out. the dissolving capa.pdf
A) Sugar may precipitate out. the dissolving capacity of gases increases with
decreases of temperature but dissolving capacity of solids decreases with decreases of
temperature, so the result
Solution
A) Sugar may precipitate out. the dissolving capacity of gases increases with
decreases of temperature but dissolving capacity of solids decreases with decreases of
temperature, so the result.
As the graph labels are not clear I am assuming that the data is for.pdf
As the graph labels are not clear I am assuming that the data is for births/ deaths per thousand.
In the late 19th century, Mexico\'s population was characterised by a high birthrate offset by a
high death rate.
After 1900, Mexico\'s demographic transition underwent a significant change. First, the death
rate significantly fell during 1910 - 1925. This could have been due to better sanitation, health
coverage etc. The decrease in death rate kept falling till 1975 after which it has more or less
stabilised.to around 5 per thousand.
The birth rate con tinued to be high ( around 45 per thousand) till 1975 after which it has seen a
significant reduction. Currently the birthrate is around 20 per thousand. So during this period,
Mexico\'s population would have grown significantly. The fall of the birth rate after the seventies
could be due to the use of family planning and contraceptives.
By 2050, the birth rate and death rate in Mexico will be more or less equal although the birth rate
is projected to be slightly higher. It may happen that the birth rate by 2050 in Mexico will reach
the population replacement level.
It is difficult to give the correct age structure of Mexico in 2050 with this graph but it can be
safely said that Mexico will have a low birth and death rate, the life expectancy of its population
should be near to that of developed nations. It will also have many senior citizens (due to the fall
in the death rate).
More data will be required about the distribution of the population age wise to have a better idea
of the age structure of the population.
Solution
As the graph labels are not clear I am assuming that the data is for births/ deaths per thousand.
In the late 19th century, Mexico\'s population was characterised by a high birthrate offset by a
high death rate.
After 1900, Mexico\'s demographic transition underwent a significant change. First, the death
rate significantly fell during 1910 - 1925. This could have been due to better sanitation, health
coverage etc. The decrease in death rate kept falling till 1975 after which it has more or less
stabilised.to around 5 per thousand.
The birth rate con tinued to be high ( around 45 per thousand) till 1975 after which it has seen a
significant reduction. Currently the birthrate is around 20 per thousand. So during this period,
Mexico\'s population would have grown significantly. The fall of the birth rate after the seventies
could be due to the use of family planning and contraceptives.
By 2050, the birth rate and death rate in Mexico will be more or less equal although the birth rate
is projected to be slightly higher. It may happen that the birth rate by 2050 in Mexico will reach
the population replacement level.
It is difficult to give the correct age structure of Mexico in 2050 with this graph but it can be
safely said that Mexico will have a low birth and death rate, the life expectancy of its population
should be near to that of developed nations. It will also have many senio.
B(three lines)S(one line)F and then add 2 dots on B and 6 on F.S.pdf
B(three lines)S(one line)F and then add 2 dots on B and 6 on F.
Solution
B(three lines)S(one line)F and then add 2 dots on B and 6 on F..
Natural birth techniques - Mrs.Akanksha Trivedi Rama University
Natural birth techniques - Mrs.Akanksha Trivedi Rama UniversityAkanksha trivedi rama nursing college kanpur.
Natural birth techniques are various type such as/ water birth , alexender method, hypnosis, bradley method, lamaze method etcMore Related Content
More from apnashop1
Milk neutralises the basics formed. .pdf
Milk neutralises the basics formed.
Solution
Milk neutralises the basics formed..
Li + 2H2O = Li(OH)2 + 2H2 moles of Li =1.0502 Mo.pdf
Li + 2H2O = Li(OH)2 + 2H2 moles of Li =1.0502 Moles of water =1.05 Since 1
moles of Li reacts with 2 moles of water so 0.525 moles of Li will not react . Mass of H2 gas
releases = 1.05*2 =2.1 gram
Solution
Li + 2H2O = Li(OH)2 + 2H2 moles of Li =1.0502 Moles of water =1.05 Since 1
moles of Li reacts with 2 moles of water so 0.525 moles of Li will not react . Mass of H2 gas
releases = 1.05*2 =2.1 gram.
In mathematics, if G is a group, and H is a subgr.pdf
In mathematics, if G is a group, and H is a subgroup of G, and g is an element of G,
then gH = {gh : h an element of H?} is a left coset of H in G, and Hg = {hg : h an element of H?}
is a right coset of H in G. Only when H is normal will the right and left cosets of H coincide,
which is one definition of normality of a subgroup. A coset is a left or right coset of some
subgroup in G. Since Hg = g?(?g-1Hg?), the right cosets Hg (of H?) and the left cosets g?(?g-
1Hg?) (of the conjugate subgroup g-1Hg?) are the same. Hence it is not meaningful to speak of a
coset as being left or right unless one first specifies the underlying subgroup. In other words: a
right coset of one subgroup equals a left coset of a different (conjugate) subgroup. If the left
cosets and right cosets are the same then H is a normal subgroup and the cosets form a group
called the quotient group. The map gH?(gH)-1=Hg-1 defines a bijection between the left cosets
and the right cosets of H, so the number of left cosets is equal to the number of right cosets. The
common value is called the index of H in G. For abelian groups, left cosets and right cosets are
always the same. If the group operation is written additively then the notation used changes to
g+H or H+g. Cosets are a basic tool in the study of groups; for example they play a central role
in Lagrange\'s theorem. Examples et G be the multiplicative group of {-1,1}, and H the trivial
subgroup (1,*). Then -1H={-1}, 1H=H are the sole cosets of H in G. Let G be the additive group
of integers Z = {..., -2, -1, 0, 1, 2, ...} and H the subgroup mZ = {..., -2m, -m, 0, m, 2m, ...}
where m is a positive integer. Then the cosets of H in G are the m sets mZ, mZ+1, ... mZ+(m-1),
where mZ+a={..., -2m+a, -m+a, a, m+a, 2m+a, ...}. There are no more than m cosets, because
mZ+m=m(Z+1)=mZ. The coset mZ+a is the congruence class of a modulo m.[1] Another
example of a coset comes from the theory of vector spaces. The elements (vectors) of a vector
space form an abelian group under vector addition. It is not hard to show that subspaces of a
vector space are subgroups of this group. For a vector space V, a subspace W, and a fixed vector
a in V, the sets are called affine subspaces, and are cosets (both left and right, since the group is
abelian). In terms of geometric vectors, these affine subspaces are all the \"lines\" or \"planes\"
parallel to the subspace, which is a line or plane going through the origin
Solution
In mathematics, if G is a group, and H is a subgroup of G, and g is an element of G,
then gH = {gh : h an element of H?} is a left coset of H in G, and Hg = {hg : h an element of H?}
is a right coset of H in G. Only when H is normal will the right and left cosets of H coincide,
which is one definition of normality of a subgroup. A coset is a left or right coset of some
subgroup in G. Since Hg = g?(?g-1Hg?), the right cosets Hg (of H?) and the left cosets g?(?g-
1Hg?) (of the conjugate subgroup g-1Hg?) are the same. Hence it is .
Use of technology and innovation in Healthcare centerSolutionU.pdf
Use of technology and innovation in Healthcare center
Solution
Use of technology and innovation in Healthcare center.
There are 22 different cuttings.The number of possible tiling of t.pdf
There are 22 different cuttings.
The number of possible tiling of triangular piece nX2, using the above three kinds of pieces:
n=22
Solution
There are 22 different cuttings.
The number of possible tiling of triangular piece nX2, using the above three kinds of pieces:
n=22.
Sorry for the late response, but please rate!SolutionS.pdf
Sorry for the late response, but please rate!
Solution
Sorry for the late response, but please rate!.
Option D is the correct answer. As the morphogen is responsible for .pdf
Option D is the correct answer. As the morphogen is responsible for the patterning of anterior
parts like head it\'s presence in the posterior end will result in formation of head. This way the
organism will be having two heads.
Solution
Option D is the correct answer. As the morphogen is responsible for the patterning of anterior
parts like head it\'s presence in the posterior end will result in formation of head. This way the
organism will be having two heads..
d. Al2S3 note Al is in oxidation state of +3, a.pdf
d. Al2S3 note: Al is in oxidation state of +3, and S is of -2. to balance the charge,
there need two Al and three S in this molecule.
Solution
d. Al2S3 note: Al is in oxidation state of +3, and S is of -2. to balance the charge,
there need two Al and three S in this molecule..
In number of government and private case studies include that the in.pdf
In number of government and private case studies include that the insiders are threat to the
organizations as they knowingly participate in cyberattacks have broad range of motivations ,
financial gain ,revenge , desire for recognition and power response to blackmail , loyality to
others in the organizations .organizations must balance the need to access the information for
conducting business with protecting this information from unauthorised access and to the secret
information is considered as an external threat and it is also malicious threat to organization and
that comes from people within the organization such as employees , former employees ,
contractors and bussiness associates . there are types of insider threats as threats occur for
various reasons in some cases individuals use their access to sensitive information for personal or
financial gain and they join the third parties such as other organizations or hacking groups and
operate on their behalf to gain access from within the network of trust and share a sensitive
information and another type of insider threat is referred to as logic bomb and in this harmful
software is left running on computer systems by former employe and which cause the problems
to complete disaster . insider threats can be intentional or unintentional and this term can be
referred to individual who gain insider access using false information but who is not a true
employee or an officer of the organization .
Insider threats are very difficult to detect , identify and block the outside attacks consider a
former employee using an unauthorized login and it wont raise the same security flag as an
outsider attempts to gain the access to company secret information or compny network and for
this reason insider threats are not detected before access is granted or damage is done . there are
many more factors that make insider threats more difficult to detect as for one many individuals
with authorized access are also aware of certain security measures which they must find a way to
avoid detection and insider threats dont have to get around firewalls or other network based
security measures as they work within the network and finally many organizations simply lack
the visibility into users access and data activity ie required to sufficiently detect and defend
against the insider threats and these are not only present in bussiness organizations but these
threats are present in mordern security program so this is the reason why insiders are considered
as threat to the organizations.
Solution
In number of government and private case studies include that the insiders are threat to the
organizations as they knowingly participate in cyberattacks have broad range of motivations ,
financial gain ,revenge , desire for recognition and power response to blackmail , loyality to
others in the organizations .organizations must balance the need to access the information for
conducting business with protecting this information from u.
Benzoic Acid is insoluble in nonpolar solvents li.pdf
Benzoic Acid is insoluble in nonpolar solvents like petroleumether, yet on the other
hand biphenyl is very soluble in petroleumether. So dissolve your crude product in petroleum
ether, then do avacume distilation. You can do a spectoscopic analysis of thesolution which
remains in the vacume flask for traces ofbiphenyl.
Solution
Benzoic Acid is insoluble in nonpolar solvents like petroleumether, yet on the other
hand biphenyl is very soluble in petroleumether. So dissolve your crude product in petroleum
ether, then do avacume distilation. You can do a spectoscopic analysis of thesolution which
remains in the vacume flask for traces ofbiphenyl..
Hi, Please find my code. I have added comment against each line, ple.pdf
Hi, Please find my code. I have added comment against each line, please go through each
comment.
Please let me know in case of any issue.
######## input.txt ###########
Alexis
Jonathan
Colby
Mason
Casey Clarence
Winston
Terry
Jeremy
Maya
########## Java Program ###########
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import java.util.ArrayList;
import java.util.Scanner;
public class ArrayListTest {
public static void main(String[] args) throws IOException {
Scanner sc = new Scanner(System.in);
// asking for input file name
System.out.print(\"Enter input file name: \");
String fileName = sc .next();
// now opening file using FieReader
FileReader fr = new FileReader(fileName);
//wrapping file reader into BufferedReader
BufferedReader br = new BufferedReader(fr);
// declaring nameList ArrayList
ArrayList nameList = new ArrayList();
// now reading name from fiel
String name;
while((name = br.readLine()) != null){
// adding currently read name in list
nameList.add(name);
}
// closing file reader
br.close();
fr.close();
// printting nameList on Screen
System.out.println(nameList.toString());
//adding \"Michael\"
nameList.add(\"Michael\");
System.out.println(\"Name List after adding Michael: \");
System.out.println(nameList.toString());
// adding \"Lucy\" at position 2 (index 1)
nameList.add(1, \"Lucy\");
System.out.println(\"Printing name list after adding Lucy at position 2: \");
System.out.println(nameList.toString());
// code to find \"Michael\"
int index = nameList.indexOf(\"Michael\");
System.out.println(\"Michael is at index: \"+index);
// replacing Michael with Mike , first removing Michael
nameList.remove(index);
// adding Mike at index
nameList.add(index, \"Mike\");
System.out.println(\"After replacing Michael with Mike\");
System.out.println(nameList.toString());
System.out.print(\"Enter a name to be deleted: \");
String s = sc.next();
// finding index of s
index = nameList.indexOf(s);
if(index == -1)
System.out.println(s+ \"is not present in name list\");
else{
System.out.println(s+\" is at index \"+index);
nameList.remove(index);
System.out.println(\"After removing \"+s+\", name list: \");
System.out.println(nameList.toString());
}
}
}
/*
Output:
Enter input file name: input.txt
[Alexis, Jonathan, Colby, Mason, Casey Clarence, Winston, Terry, Jeremy, Maya]
Name List after adding Michael:
[Alexis, Jonathan, Colby, Mason, Casey Clarence, Winston, Terry, Jeremy, Maya, Michael]
Printing name list after adding Lucy at position 2:
[Alexis, Lucy, Jonathan, Colby, Mason, Casey Clarence, Winston, Terry, Jeremy, Maya,
Michael]
Michael is at index: 10
After replacing Michael with Mike
[Alexis, Lucy, Jonathan, Colby, Mason, Casey Clarence, Winston, Terry, Jeremy, Maya, Mike]
Enter a name to be deleted: Colby
Colby is at index 3
After removing Colby, name list:
[Alexis, Lucy, Jonathan, Mason, Casey Clarence, Winston, Terry, Jeremy, Maya, Mike]
*/
Solution
Hi, Please find my code. I have added comment against .
First it crosses the saturated liquid line and then traces the isoth.pdf
First it crosses the saturated liquid line and then traces the isothermal curve while inside the
vapor dome and then crosses the saturated vapor line.
Solution
First it crosses the saturated liquid line and then traces the isothermal curve while inside the
vapor dome and then crosses the saturated vapor line..
B doublet is correct note the neighboring C has .pdf
B doublet is correct note: the neighboring C has only one H that split CH3 into a
doublet.
Solution
B doublet is correct note: the neighboring C has only one H that split CH3 into a
doublet..
failing to reject the null hypothesis means there is not sufficient .pdf
failing to reject the null hypothesis means there is not sufficient evidence for his conclusion.
Solution
failing to reject the null hypothesis means there is not sufficient evidence for his conclusion..
CounterfactualCounterfactual thinking gained attention from a psy.pdf
Counterfactual:
Counterfactual thinking gained attention from a psychological point of view. Cognitive scientists
studied the mental representations and cognitive processes that bring about the creation of
counterfactuals developed the study of counterfactual thought, showing that people tend to think
\'if only\' more often about exceptional events than about normal events.
Early research on counterfactual thinking took a particular point of view, the thoughts were the
sign of difficult skills, psychological error or bias. As research increased, a new wave of
approach began, taking a functional view, believing that counterfactual thinking served as a
largely beneficial behavioral controller.
Scientists, however, need to be a little clear. Scientists have to be able to describe the nature of
that association. In order to do so, they have developed terminology to describe the causal
relationship between two events. They say that causes are necessary,sufficient, neither, or both.
Understanding Causality:
Solution
Counterfactual:
Counterfactual thinking gained attention from a psychological point of view. Cognitive scientists
studied the mental representations and cognitive processes that bring about the creation of
counterfactuals developed the study of counterfactual thought, showing that people tend to think
\'if only\' more often about exceptional events than about normal events.
Early research on counterfactual thinking took a particular point of view, the thoughts were the
sign of difficult skills, psychological error or bias. As research increased, a new wave of
approach began, taking a functional view, believing that counterfactual thinking served as a
largely beneficial behavioral controller.
Scientists, however, need to be a little clear. Scientists have to be able to describe the nature of
that association. In order to do so, they have developed terminology to describe the causal
relationship between two events. They say that causes are necessary,sufficient, neither, or both.
Understanding Causality:.
A) Sugar may precipitate out. the dissolving capa.pdf
A) Sugar may precipitate out. the dissolving capacity of gases increases with
decreases of temperature but dissolving capacity of solids decreases with decreases of
temperature, so the result
Solution
A) Sugar may precipitate out. the dissolving capacity of gases increases with
decreases of temperature but dissolving capacity of solids decreases with decreases of
temperature, so the result.
As the graph labels are not clear I am assuming that the data is for.pdf
As the graph labels are not clear I am assuming that the data is for births/ deaths per thousand.
In the late 19th century, Mexico\'s population was characterised by a high birthrate offset by a
high death rate.
After 1900, Mexico\'s demographic transition underwent a significant change. First, the death
rate significantly fell during 1910 - 1925. This could have been due to better sanitation, health
coverage etc. The decrease in death rate kept falling till 1975 after which it has more or less
stabilised.to around 5 per thousand.
The birth rate con tinued to be high ( around 45 per thousand) till 1975 after which it has seen a
significant reduction. Currently the birthrate is around 20 per thousand. So during this period,
Mexico\'s population would have grown significantly. The fall of the birth rate after the seventies
could be due to the use of family planning and contraceptives.
By 2050, the birth rate and death rate in Mexico will be more or less equal although the birth rate
is projected to be slightly higher. It may happen that the birth rate by 2050 in Mexico will reach
the population replacement level.
It is difficult to give the correct age structure of Mexico in 2050 with this graph but it can be
safely said that Mexico will have a low birth and death rate, the life expectancy of its population
should be near to that of developed nations. It will also have many senior citizens (due to the fall
in the death rate).
More data will be required about the distribution of the population age wise to have a better idea
of the age structure of the population.
Solution
As the graph labels are not clear I am assuming that the data is for births/ deaths per thousand.
In the late 19th century, Mexico\'s population was characterised by a high birthrate offset by a
high death rate.
After 1900, Mexico\'s demographic transition underwent a significant change. First, the death
rate significantly fell during 1910 - 1925. This could have been due to better sanitation, health
coverage etc. The decrease in death rate kept falling till 1975 after which it has more or less
stabilised.to around 5 per thousand.
The birth rate con tinued to be high ( around 45 per thousand) till 1975 after which it has seen a
significant reduction. Currently the birthrate is around 20 per thousand. So during this period,
Mexico\'s population would have grown significantly. The fall of the birth rate after the seventies
could be due to the use of family planning and contraceptives.
By 2050, the birth rate and death rate in Mexico will be more or less equal although the birth rate
is projected to be slightly higher. It may happen that the birth rate by 2050 in Mexico will reach
the population replacement level.
It is difficult to give the correct age structure of Mexico in 2050 with this graph but it can be
safely said that Mexico will have a low birth and death rate, the life expectancy of its population
should be near to that of developed nations. It will also have many senio.
B(three lines)S(one line)F and then add 2 dots on B and 6 on F.S.pdf
B(three lines)S(one line)F and then add 2 dots on B and 6 on F.
Solution
B(three lines)S(one line)F and then add 2 dots on B and 6 on F..
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