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Group members

 Ademola Alimayu
 Reisha Flemming
 Ronnie Christian
  Floyd Bartlett
Introduction
 Bungee jumping involves jumping from a tall
 structure while connected to a large elastic cord
 The tall structure is usually a fixed object, such as
 a building, bridge or crane in some cases it can
 also be a mobile medium such as a hot air
 balloon or helicopter that has the ability to hover.
Design Specification
Material used:
 4’ length of 1.5mm electrical wire
 rubber bands
 a hook
 a 2” x 2” x 2” wooden block
 a plastic plate of 1” of water
 5’ wooden stand
Spring constant
 This was obtained by measuring the original
length of the rubber band and then adding the
2*2*2 cubic block and measuring its extension.
                 (Xe- Xo)=X
                    F=ma
     Hence the spring constant K = (ma)/x
 Using m= 0.060kg, a = g = 9.8, Xe- Xo=0.005m
               K=(.06x9.8)/.005
                 =117.6N/m
What is the stiffness of a chain of N
rubber bands?

                                     W K1
                            KN
                                     Nd N


                             The stiffness of a chain of
           Nd                rubber bands is inversely
                             proportional to the number
                             of bands



                 W
Where are we?
 We have the stiffness of
  an average rubber band
  K1
                                  W    K1
                             KN
 We have the length of           Nd   N
  an average rubber band
  L1
 We have a way to
  predict the slack length
  and stiffness of a chain
  of N rubber bands
                             LN    NL1
Conservation of Energy gives drop distance as
a function of the # N of RBs

     1                              K AV
  wh   K N (h LN )2 where K N            and LN      NLAV
     2                               N
                                2
               w         w                      w
     h   LN                             2 LN
               KN        KN                     KN
                                    2
                    w     w                     w
         N    L1                         2 L1
                    K1    K1                    K1
 Essentially:
   ½ kx2 = ½ mv2 + mgh,
where m=mass of block, v= velocity of block during
  motion, h=height above datum level for the system
Substituting values determined for k and x, we get:

                   ½ (k/2n)(h-nL)2 = ½ mv2 + mgh
        So, ½ (117/2n)(0.0229-.072n)2 = ½ 0.06x(4.89)2 +
                           (0.06x9.8x0.279)
                    Solving gives n = 1.2 bands
 Note velocity, v determined from conservation of energy mgH= ½
                              mv2 + mgh
 At equilibrum point, v = u + at
However initial velocity =0, so using v=5.04s (from
 conservation of energy for first system)

                 T = 5.04/9.8 = 0.5s
       For oscillation, T (period) = 2(pi)√m/k
                        =0.15s
   So time to reach water = 0.5 + (.15/2) = 0.6s
  From experiment, time to settle (come to rest) =
                          4.7s
    Also Lifetime of system, bands fail after 3-4
                        attenpts.
 Sources of Errors
- Length not true due to looping and hooks
- Also system is not fixed so energy dissipated (eg
 dampening effect of water.

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Systems power point

  • 1. Group members Ademola Alimayu Reisha Flemming Ronnie Christian Floyd Bartlett
  • 2. Introduction  Bungee jumping involves jumping from a tall structure while connected to a large elastic cord The tall structure is usually a fixed object, such as a building, bridge or crane in some cases it can also be a mobile medium such as a hot air balloon or helicopter that has the ability to hover.
  • 3. Design Specification Material used:  4’ length of 1.5mm electrical wire  rubber bands  a hook  a 2” x 2” x 2” wooden block  a plastic plate of 1” of water  5’ wooden stand
  • 4. Spring constant  This was obtained by measuring the original length of the rubber band and then adding the 2*2*2 cubic block and measuring its extension.  (Xe- Xo)=X  F=ma  Hence the spring constant K = (ma)/x  Using m= 0.060kg, a = g = 9.8, Xe- Xo=0.005m  K=(.06x9.8)/.005  =117.6N/m
  • 5. What is the stiffness of a chain of N rubber bands? W K1 KN Nd N The stiffness of a chain of Nd rubber bands is inversely proportional to the number of bands W
  • 6. Where are we?  We have the stiffness of an average rubber band K1 W K1 KN  We have the length of Nd N an average rubber band L1  We have a way to predict the slack length and stiffness of a chain of N rubber bands LN NL1
  • 7. Conservation of Energy gives drop distance as a function of the # N of RBs 1 K AV wh K N (h LN )2 where K N and LN NLAV 2 N 2 w w w h LN 2 LN KN KN KN 2 w w w N L1 2 L1 K1 K1 K1
  • 8.  Essentially: ½ kx2 = ½ mv2 + mgh, where m=mass of block, v= velocity of block during motion, h=height above datum level for the system Substituting values determined for k and x, we get: ½ (k/2n)(h-nL)2 = ½ mv2 + mgh So, ½ (117/2n)(0.0229-.072n)2 = ½ 0.06x(4.89)2 + (0.06x9.8x0.279) Solving gives n = 1.2 bands Note velocity, v determined from conservation of energy mgH= ½ mv2 + mgh
  • 9.  At equilibrum point, v = u + at However initial velocity =0, so using v=5.04s (from conservation of energy for first system) T = 5.04/9.8 = 0.5s For oscillation, T (period) = 2(pi)√m/k =0.15s So time to reach water = 0.5 + (.15/2) = 0.6s From experiment, time to settle (come to rest) = 4.7s Also Lifetime of system, bands fail after 3-4 attenpts.
  • 10.  Sources of Errors - Length not true due to looping and hooks - Also system is not fixed so energy dissipated (eg dampening effect of water.