Suppose that 14% of people are left handed. If you pick two people at random, what is the probability that (1) they both are left handed? (round your answer to 2 decimal places) (2) only one of them is left handed? (round your answer to 2 decimal places) Solution 1) P(both left handed) = 0.14*0.14 = 0.0196 [ANSWER] ******************** b) There are two ways to do this, that is, the first one is left handed and the scond is right handed, or the other way around. Hence, we mutliply the product of probabilities by 2: P(one is left handed) = 2*0.14*(1-0.14) = 0.2408 [ANSWER].