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Starbucks Wait Time Analysis

        Data Collected on
     4/26/2012 and 4/29/2012

        Brandon R. Theiss
    Brandon.Theiss@gmail.com
Motivation
• Reliability is defined as:
   – the probability of a product performing its intended
     function under stated conditions for a defined period
     of time.
• This definition unfortunately too narrowly defines the
  term in the context of a tangible product.
• Services represent 76.8% of the overall Gross Domestic
  Product of the United States or 11.9 Trillion dollars.
• A more applicable definition is therefore
   – The ability of process to perform its intended function
     under customer specified conditions for a customer
     defined period of time.
Objective
• To study the reliability of the Starbucks
  beverage delivery system to provide a
  beverage to a customer prior to reaching
  their critical wait time.
About Starbucks
• Founded 1971, in Seattle’s Pike Place
  Market. Original name of company was
  Starbucks Coffee, Tea and Spices, later
  changed to Starbucks Coffee Company.
• In United States:
  – 50 states, plus the District of Columbia
  – 7,087 Company-operated stores
  – 4,081 Licensed stores
Representative Stores
• Two of the 7,087 company operated
  stores were selected by geographical
  convenience
  – Marlboro NJ
  – New Brunswick NJ
About Marlboro NJ




Marlboro is a Township in Monmouth County, New Jersey. It has
a population of 40,191 with a median household income of
$101,322
About New Brunswick




New Brunswick is a city in Middlesex County, New Jersey. It has
a population of 55,181 with a median household income of
$36,080
Measurement System
Measurement Procedure
1. Click Start on 1 of 10 timers in the
   Custom Application
2. Enter Identifying characteristic in textbox
3. Click Stop when the customer receives
   their beverage or leaves the store. Data
   is automatically recorded with times
   measured in milliseconds
4. Click Reset for the next customer
Marlboro NJ Location
Marlboro Wait Time Data
Does the Data Follow a Weibull
         Distribution?
                                      Histogram of Time
                                              Weibull
                 25                                                       Shape    2.007
                                                                          Scale   216106
                                                                          N           94

                 20


                 15
     Frequency




                 10


                 5



                 0
                      0   100000   200000      300000   400000   500000
                                            Time
Does the Data Follow a Gamma
         Distribution?
                                    Histogram of Time
                                           Gamma
               25                                                       Shape   3.977
                                                                        Scale   47936
                                                                        N          94

               20



               15
   Frequency




               10



               5



               0
                    0   100000   200000      300000   400000   500000
                                          Time
Can the arrivals
 of customers
be Modeled as
  a Poisson
   Process?

Goodness-of-Fit Test for Poisson Distribution
Data column: Marlboro
Poisson mean for Marlboro = 5.22222
                              Poisson               Contribution
Marlboro Observed Probability Expected                 to Chi-Sq
<=3                 7       0.235206      4.23371        1.80748
4                   2       0.167197      3.00954        0.33865
5                   3       0.174628      3.14330        0.00653
6                   1       0.151991      2.73583        1.10135
7                   1       0.113390      2.04102        0.53097
>=8                 4       0.157589      2.83660        0.47716
  N N* DF      Chi-Sq P-Value
18   0   4 4.26215          0.372
Formal Test for the Data Being
    Normally Distributed
                                        Probability Plot for Time
                                                 Normal - 95% CI
              99.9
                                                                                              Goodness of Fit Test

               99
                                                                                              AD = 2.887
                                                                                              P-Value < 0.005
               95
               90
               80
               70
    Percent




               60
               50
               40
               30
               20
               10
                5

                1


               0.1
                  -200000 -100000   0   100000   200000   300000   400000   500000   600000
                                                 Time
Formal Test for the Data Being
    Gamma Distributed
                       Probability Plot for Time
                            Gamma - 95% CI
              99.9
                                                             Goodness of Fit Test
               99
               95                                            AD = 0.699
               90                                            P-Value = 0.075
               80
               70
               60
               50
               40
    Percent




               30
               20

               10
                5


                1




               0.1
               10000      100000                   1000000
                           Time
Formal Test for the Data Being
    Weibull Distributed
                             Probability Plot for Time
                                  Weibull - 95% CI
              99.9
                99                                                 Goodness of Fit Test

               90
                                                                   AD = 1.509
               80
               70                                                  P-Value < 0.010
               60
               50
               40
               30
               20
    Percent




               10

                5
                3
                2

                1




               0.1
                     10000              100000           1000000
                                 Time
Mean Time To Beverage and
  “Reliability” at Marlboro

 Biased                 Unbiased
 190652.872424565 ms    190652.916039948 ms
 3.17754787374275 min   3.1775486006658 min




  Biased                Unbiased
  0.8727                0.8754
Is the Process Capable Based
    Upon a Gamma Model?
                                           Process Capability of Time
                                     Calculations Based on Gamma Distribution Model

                                LB                           USL
           P rocess D ata                                                                O v erall C apability
    LB                0                                                                    Pp            *
    Target            *                                                                    PPL           *
    USL               300000                                                               PPU        0.29
    S ample M ean 190653                                                                   P pk       0.29
    S ample N         94
                                                                                      Exp. O v erall P erformance
    S hape            3.97724
                                                                                      P P M < LB               *
    S cale            47936
                                                                                      P P M > U S L 127306.05
    O bserv ed P erformance                                                           P P M Total      127306.05
    P P M < LB         0.00
    P P M > U S L 95744.68
    P P M Total    95744.68




                                0        100000 200000     300000   400000 500000
Is the Process Capable Based
    Upon a Weibull Model?
                                           Process Capability of Time
                                     Calculations Based on Weibull Distribution Model

                                LB                            USL
           P rocess D ata                                                                  O v erall C apability
    LB                0                                                                      Pp            *
    Target            *                                                                      PPL           *
    USL               300000                                                                 PPU        0.32
    S ample M ean 190653                                                                     P pk       0.32
    S ample N         94
                                                                                        Exp. O v erall P erformance
    S hape            2.00713
                                                                                        P P M < LB               *
    S cale            216106
                                                                                        P P M > U S L 144910.81
    O bserv ed P erformance                                                             P P M Total      144910.81
    P P M < LB         0.00
    P P M > U S L 95744.68
    P P M Total    95744.68




                                0        100000 200000      300000   400000 500000
Is the Beverage Delivery
                                              Process in Control?
                                                I-MR Chart of Marlboro                                                                                               I-MR Chart of Marlboro
                                                                                                                                                          Using Box-Cox Transformation With Lambda = 0.50
                    600000
                                                                                         1
                                                                                        1 1 1                                              800
                                                 1 1                                                                                                                                                          1
                                                                                                                                                                                                             1 1 1
Individual V alue




                    450000
                                                                                                         U C L=407256                                                                                                         UCL=679.6




                                                                                                                        Individual Value
                                                                                                                                           600
                    300000
                                                                                                         _
                                                                                                                                                                                                                              _
                                                                                                         X=190653                                                                                                             X=422.7
                    150000                                                                                                                 400


                         0
                                                                                                         LC L=-25950                       200
                                                                                                                                                                                                                              LCL=165.8
                             1   10   19   28          37       46       55   64   73   82          91
                                                            O bser vation                                                                        1   10   19    28         37      46         55   64   73   82          91
                                                                                                                                                                                Observation

                                                                                                1
                                                  11                                                                                                                  11                                             1
                    400000                                                                                                                 450
M oving Range




                    300000
                                                                                                                                                                                                                              UCL=315.6




                                                                                                                        Moving Range
                                                                                                         U C L=266097                      300

                    200000

                                                                                                         __                                150                                                                                __
                    100000
                                                                                                         M R=81443                                                                                                            MR=96.6

                         0                                                                               LC L=0                             0                                                                                 LCL=0

                             1   10   19   28          37       46       55   64   73   82          91                                           1   10   19    28         37      46         55   64   73   82          91
                                                            O bser vation                                                                                                       Observation
New Brunswick NJ Location
New Brunswick Wait Time Data
Does the Data Follow a Weibull
         Distribution?
                                        Histogram of Time
                                              Weibull
                 40                                                             Shape    1.994
                                                                                Scale   273830
                                                                                N          198


                 30
     Frequency




                 20




                 10




                 0
                      0   100000   200000   300000   400000   500000   600000
                                             Time
Does the Data Follow a Gamma
         Distribution?
                                      Histogram of Time
                                             Gamma
               40                                                           Shape   3.080
                                                                            Scale   78771
                                                                            N         198


               30
   Frequency




               20




               10




               0
                    0   100000   200000   300000 400000   500000   600000
                                             Time
Can the arrivals
 of customers
be Modeled as
  a Poisson
   Process?


Goodness-of-Fit Test for Poisson Distribution
Data column: New Brunswick
Poisson mean for New Brunswick = 9.9
New                            Poisson                Contribution
Brunswick Observed Probability Expected                  to Chi-Sq
<=6                   4       0.136574      2.73148       0.589107
7 - 8                 3       0.207617      4.15235       0.319795
9 - 10                5       0.251357      5.02715       0.000147
11 - 12               4       0.205390      4.10780       0.002829
>=13                  4       0.199062      3.98123       0.000088
 N N* DF         Chi-Sq P-Value
20    0  3 0.911967           0.823
Formal Test for the Data Being
    Normally Distributed
                                            Probability Plot for Time
                                                    Normal - 95% CI
              99.9
                                                                                            Goodness of Fit Test
               99
                                                                                            AD = 1.680
               95                                                                           P-Value < 0.005
               90
               80
               70
    Percent




               60
               50
               40
               30
               20
               10
                5

                1

               0.1

                     00       00   0       00     00      00      00     00     00     00
                  000     0 00           00     00      00     00      00     00     00
                -2      -1             10     20     30      40      50     60     70
                                                   Time
Formal Test for the Data Being
    Gamma Distributed
                            Probability Plot for Time
                                 Gamma - 95% CI
             99.9
                                                                  Goodness of Fit Test
              99
              95                                                  AD = 0.911
              90                                                  P-Value = 0.023
              80
              70
              60
              50
              40
   Percent




              30
              20

              10
               5


               1




              0.1
                    10000       100000                  1000000
                                 Time
Formal Test for the Data Being
    Weibull Distributed
                             Probability Plot for Time
                                  Weibull - 95% CI
              99.9
                99                                                 Goodness of Fit Test

               90
                                                                   AD = 0.441
               80
               70                                                  P-Value > 0.250
               60
               50
               40
               30
               20
    Percent




               10

                5
                3
                2

                1




               0.1
                     10000           100000              1000000
                                  Time
Why Might the Data Not Follow
        a Gamma?
Poisson    Gamma                       ?
                                               Gamma * ? =?




                                  Make Drink
           Wait in Line
                                   Process
Arrival                                        Deliver
To Store                  Order                Drink
                          Drink



                    What We Measured
Is the Process Capable Based
    Upon a Weibull Model?
                                     Process Capability of Time
                               Calculations Based on Weibull Distribution Model

                               LB                    USL
          P rocess D ata                                                             O v erall C apability
   LB                0                                                                 Pp            *
   Target            *                                                                 PPL           *
   USL               300000                                                            PPU        0.15
   S ample M ean 242647                                                                P pk       0.15
   S ample N         198
                                                                                  E xp. O v erall P erformance
   S hape            1.99408
                                                                                  P P M < LB                *
   S cale            273830
                                                                                  P P M > U S L 301307.05
    O bserv ed P erformance                                                       P P M Total       301307.05
   P P M < LB           0.00
   P P M > U SL 303030.30
   P P M Total    303030.30




                               0    100000 200000 300000 400000 500000 600000
Is the Process Capable Based
    Upon a Gamma Model?
                                    Process Capability of Time
                              Calculations Based on Gamma Distribution Model

                              LB                    USL
         P rocess D ata                                                                 O v erall C apability
  LB                0                                                                     Pp            *
  Target            *                                                                     PPL           *
  USL               300000                                                                PPU        0.13
  S ample M ean 242647                                                                    P pk       0.13
  S ample N         198
                                                                                     E xp. O v erall P erformance
  S hape            3.0804
                                                                                     P P M < LB                *
  S cale            78771.2
                                                                                     P P M > U S L 283036.30
   O bserv ed P erformance                                                           P P M Total       283036.30
  P P M < LB           0.00
  P P M > U S L 303030.30
  P P M Total    303030.30




                              0    100000   200000 300000   400000 500000   600000
Mean Time To Beverage and
“Reliability” at New Brunswick


  Biased           Unbiased
  242688.9419 ms   242371.0724 ms
  4.0448 mins      4.0395 mins




  Biased           Unbiased
  0.6987           0.6993
Is the Beverage Delivery
                                         Process in Control?

                                           I-MR Chart of New Brunswick                                                                                                  I-MR Chart of New Brunswick
                                                            1     1
                                                                                                                                                                  Using Box-Cox Transformation With Lambda = 0.50
                    600000                                      11
                                                                                     1                                                                                                    1     1
                                                                                          1          1                                     800                                                11                        1
                                                                                                         U C L=485623                                                                                                                   UCL=733.1
Individual V alue




                    450000




                                                                                                                        Individual Value
                                                                                                                                           600
                    300000                                                                               _                                                                                                                              _
                                                                                                         X=242647                                                                                                                       X=473.9
                                                                                                                                           400
                    150000


                         0                                                                               LC L=-330                         200                                                                                          LCL=214.7
                                                                                                                                                     1        1   1 1                                   1                    1
                                                                                                                                                                                                    1       1
                             1   21   41     61   81         101       121   141   161         181                                               1

                                                       O bser vation                                                                             1       21       41     61      81        101          121     141   161         181
                                                                                                                                                                                      Observation

                                                                                          1
                    480000                                   1 11
                                                                                         1
                                                               1                                                                           600
                                                              1                          1                                                                                                                                    1
                                                                                                                                                                                                                             1
                    360000                                                               1 1
Moving Range




                                                                                                                                                                                              1                              1
                                                                                                                                                                                           11 1




                                                                                                                        Moving Range
                                                                                                                                                                                                    1                       1
                                                                                                         U C L=298497                      400                                              1
                    240000                                                                                                                                                                                                              UCL=318.4


                                                                                                         __                                200
                    120000                                                                                                                                                                                                              __
                                                                                                         M R=91359
                                                                                                                                                                                                                                        MR=97.4

                         0                                                                               LC L=0                             0                                                                                           LCL=0
                             1   21   41     61   81         101       121   141   161         181                                               1       21       41     61      81        101          121     141   161         181
                                                       O bser vation                                                                                                                  Observation
Marlboro   New Brunswick
Starbucks Wait Time Analysis

COMBINED
Is there a difference between
Marlboro and New Brunswick?
                             Histogram of Marlboro, New Brunswick
                                              Gamma
                40                                                       Variable
                                                                         Marlboro
                                                                         New Brunswick

                                                                     Shape Scale    N
                30                                                    3.977 47936 94
                                                                      3.080 78771 198
    Frequency




                20




                10




                0
                     0   100000 200000 300000 400000 500000 600000
                                         Data
Is there a difference between
Marlboro and New Brunswick?
  Kruskal-Wallis Test: Wait Times versus Location


  Kruskal-Wallis Test on C2


  Subscripts          N    Median   Ave Rank           Z
  Marlboro           94    173350      121.6    -3.47
  New Brunswick     198    216245      158.3        3.47
  Overall           292                146.5


  H = 12.04    DF = 1     P = 0.001
  H = 12.04    DF = 1     P = 0.001   (adjusted for
  ties)
Combined Wait Time Data
Does the Data Follow a Weibull
         Distribution?
                                      Histogram of Combined
                                                Weibull
                 35                                                             Shape    1.954
                                                                                Scale   255391
                                                                                N          292
                 30

                 25
     Frequency




                 20

                 15

                 10

                 5

                 0
                      0   100000   200000    300000  400000   500000   600000
                                            Combined
Does the Data Follow a Gamma
         Distribution?
                                     Histogram of Combined
                                              Gamma
                35                                                             Shape   3.201
                                                                               Scale   70580
                                                                               N         292
                30

                25
    Frequency




                20

                15

                10

                5

                0
                     0   100000   200000    300000  400000   500000   600000
                                           Combined
Are the Arrival Rates the Same?

                                Histogram of Marlboro, New Brunswick
                                                           2   4   6   8   10   12   14   16
                                 Marlboro                          New Brunswick
                9

                8

                7

                6
    Frequency




                5

                4

                3

                2

                1

                0
                    2   4   6     8   10    12   14   16
Are the Arrival Rates the Same?
  Kruskal-Wallis Test: Arrivals versus Location


  Kruskal-Wallis Test on Arrivals


  Location            N   Median   Ave Rank           Z
  Marlboro          18     4.500        12.4      -3.76
  New Brunswick     20    10.000        25.9       3.76
  Overall           38                  19.5


  H = 14.11    DF = 1     P = 0.000
  H = 14.26    DF = 1     P = 0.000    (adjusted for
  ties)
Can the arrivals
 of customers
be Modeled as
  a Poisson
   Process?
Goodness-of-Fit Test for Poisson Distribution

Data column: Combined

Poisson mean for Combined = 7.68421
                        Poisson                 Contribution
Combined Observed Probability Expected             to Chi-Sq
<=4             10     0.119196   4.52945            6.60719
5                3     0.102708   3.90291            0.20888
6                4     0.131538   4.99846            0.19945
7                2     0.144396   5.48703            2.21602
8                4     0.138696   5.27044            0.30624
9                3     0.118419   4.49991            0.49995
10               3     0.090995   3.45782            0.06062
11               1     0.063566   2.41551            0.82950
>=12             8     0.090486   3.43846            6.05144
  N N* DF    Chi-Sq P-Value
38   0   7 16.9793     0.018
Why Might the data set of Combined
  Arrivals Not Represent a Poisson
              Process?

• Not a large enough data set
• Not constant arrival rate
  – Different demand for Beverages at different
    stores at different times
• Other factors are influencing the
  independence of events
  – Traffic lights
Formal Test for the Data Being
    Normally Distributed
                                              Probability Plot for Combined
                                                            Normal - 95% CI
              99.9
                                                                                                          Goodness of Fit Test
               99
                                                                                                          AD = 4.293
               95                                                                                         P-Value < 0.005
               90
               80
               70
    Percent




               60
               50
               40
               30
               20
               10
                5

                1

               0.1
                        0           00   0         0       0        0       0       0        0        0
                      00       00                00     00       00       00      00      00       00
                 00          10                00     00       00       00      00      00      00
               -2           -                1       2       3        4       5       6        7
                                                        Combined
Formal Test for the Data Being
    Gamma Distributed
                         Probability Plot for Combined
                                 Gamma - 95% CI
              99.9
                                                                   Goodness of Fit Test
               99
               95                                                  AD = 0.594
               90                                                  P-Value = 0.141
               80
               70
               60
               50
               40
    Percent




               30
               20

               10
                5



                1




               0.1
                 10000         100000                    1000000
                              Combined
Formal Test for the Data Being
    Weibull Distributed
                             Probability Plot for Combined
                                     Weibull - 95% CI
              99.9
                99                                                     Goodness of Fit Test

               90
                                                                       AD = 0.959
               80
               70                                                      P-Value = 0.016
               60
               50
               40
               30
               20
    Percent




               10

                5
                3
                2

                1




               0.1
                     10000             100000                1000000
                                  Combined
Mean Time To Beverage and
       “Reliability”

 Biased           Unbiased
 225908.8493 ms   226153.1587 ms
 3.7651 mins      3.7692 mins




  Biased          Unbiased
  0.7629          0.7617
Is the Process Capable Based
    Upon a Gamma Model?
                                        Process Capability of Combined
                                     Calculations Based on Gamma Distribution Model

                                LB                       USL
           P rocess D ata                                                                O v erall C apability
    LB                0                                                                    Pp            *
    Target            *                                                                    PPL           *
    USL               300000                                                               PPU        0.16
    S ample M ean 225909                                                                   P pk       0.16
    S ample N         292
                                                                                      Exp. O v erall P erformance
    S hape            3.20075
                                                                                      P P M < LB               *
    S cale            70580
                                                                                      P P M > U S L 237100.41
     O bserv ed P erformance                                                          P P M Total      237100.41
    P P M < LB           0.00
    P P M > U S L 236301.37
    P P M Total    236301.37




                                0       100000 200000 300000 400000 500000 600000
Is the Process Capable Based
    Upon a Weibull Model?
                                        Process Capability of Combined
                                     Calculations Based on Weibull Distribution Model

                                LB                        USL
           P rocess D ata                                                                    O v erall C apability
    LB                0                                                                        Pp            *
    Target            *                                                                        PPL           *
    USL               300000                                                                   PPU        0.19
    S ample M ean 225909                                                                       P pk       0.19
    S ample N         292
                                                                                          Exp. O v erall P erformance
    S hape            1.95393
                                                                                          P P M < LB               *
    S cale            255391
                                                                                          P P M > U S L 254194.23
     O bserv ed P erformance                                                              P P M Total      254194.23
    P P M < LB           0.00
    P P M > U S L 236301.37
    P P M Total    236301.37




                                0        100000 200000   300000 400000 500000    600000
Is the Process Capable Based
    Upon a Weibull Model?




   The corresponds to a Sigma level of 4. The Goal is 6!
Is the Process Capable Based
    Upon a Gamma Model?




   The corresponds to a Sigma level of 2. The Goal is 6!
Conclusions
• The amount of time a customer waits at a Starbucks is
  dependent on which location they visit.
• Regardless of location, Starbucks is incapable of reliably
  delivering a beverage in less than 5 minutes
• There is evidence to suggest that the arrivals follow a
  Poisson distribution which is supported by the literature
• There is evidence to suggest that the wait times follow a
  gamma distribution which the literature would suggest
•   Academics
                       About the Author
     –   MS Industrial Engineering Rutgers University
     –   BS Electrical & Computer Engineering Rutgers University
     –   BA Physics Rutgers University
• Awards
     –   ASQ Top 40 Leader in Quality Under 40.
•   Professional
     –   Principal Industrial Engineer -Medtronic
     –   Master Black belt- American Standard Brands
     –   Systems Engineer- Johnson Scale Co
•   Certifications
     –   ASQ Certified Manager of Quality/ Org Excellence Cert # 13788
     –   ASQ Certified Quality Auditor Cert # 41232
     –   ASQ Certified Quality Engineer Cert # 56176
     –   ASQ Certified Reliability Engineer Cert #7203
     –   ASQ Certified Six Sigma Green Belt Cert # 3962
     –   ASQ Certified Six Sigma Black Belt Cert # 9641
     –   ASQ Certified Software Quality Engineer Cert # 4941
•   Publications
     –   Going with the Flow- The importance of collecting data without holding up your processes-
         Quality Progress March 2011
     –   "Numbers Are Not Enough: Improved Manufacturing Comes From Using Quality Data the
         Right Way" (cover story). Industrial Engineering Magazine- Journal of the Institute of
         Industrial Engineers September (2011): 28-33. Print
?

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Starbucks Wait Time Analysis

  • 1. Starbucks Wait Time Analysis Data Collected on 4/26/2012 and 4/29/2012 Brandon R. Theiss Brandon.Theiss@gmail.com
  • 2. Motivation • Reliability is defined as: – the probability of a product performing its intended function under stated conditions for a defined period of time. • This definition unfortunately too narrowly defines the term in the context of a tangible product. • Services represent 76.8% of the overall Gross Domestic Product of the United States or 11.9 Trillion dollars. • A more applicable definition is therefore – The ability of process to perform its intended function under customer specified conditions for a customer defined period of time.
  • 3. Objective • To study the reliability of the Starbucks beverage delivery system to provide a beverage to a customer prior to reaching their critical wait time.
  • 4. About Starbucks • Founded 1971, in Seattle’s Pike Place Market. Original name of company was Starbucks Coffee, Tea and Spices, later changed to Starbucks Coffee Company. • In United States: – 50 states, plus the District of Columbia – 7,087 Company-operated stores – 4,081 Licensed stores
  • 5. Representative Stores • Two of the 7,087 company operated stores were selected by geographical convenience – Marlboro NJ – New Brunswick NJ
  • 6. About Marlboro NJ Marlboro is a Township in Monmouth County, New Jersey. It has a population of 40,191 with a median household income of $101,322
  • 7. About New Brunswick New Brunswick is a city in Middlesex County, New Jersey. It has a population of 55,181 with a median household income of $36,080
  • 9. Measurement Procedure 1. Click Start on 1 of 10 timers in the Custom Application 2. Enter Identifying characteristic in textbox 3. Click Stop when the customer receives their beverage or leaves the store. Data is automatically recorded with times measured in milliseconds 4. Click Reset for the next customer
  • 12. Does the Data Follow a Weibull Distribution? Histogram of Time Weibull 25 Shape 2.007 Scale 216106 N 94 20 15 Frequency 10 5 0 0 100000 200000 300000 400000 500000 Time
  • 13. Does the Data Follow a Gamma Distribution? Histogram of Time Gamma 25 Shape 3.977 Scale 47936 N 94 20 15 Frequency 10 5 0 0 100000 200000 300000 400000 500000 Time
  • 14. Can the arrivals of customers be Modeled as a Poisson Process? Goodness-of-Fit Test for Poisson Distribution Data column: Marlboro Poisson mean for Marlboro = 5.22222 Poisson Contribution Marlboro Observed Probability Expected to Chi-Sq <=3 7 0.235206 4.23371 1.80748 4 2 0.167197 3.00954 0.33865 5 3 0.174628 3.14330 0.00653 6 1 0.151991 2.73583 1.10135 7 1 0.113390 2.04102 0.53097 >=8 4 0.157589 2.83660 0.47716 N N* DF Chi-Sq P-Value 18 0 4 4.26215 0.372
  • 15. Formal Test for the Data Being Normally Distributed Probability Plot for Time Normal - 95% CI 99.9 Goodness of Fit Test 99 AD = 2.887 P-Value < 0.005 95 90 80 70 Percent 60 50 40 30 20 10 5 1 0.1 -200000 -100000 0 100000 200000 300000 400000 500000 600000 Time
  • 16. Formal Test for the Data Being Gamma Distributed Probability Plot for Time Gamma - 95% CI 99.9 Goodness of Fit Test 99 95 AD = 0.699 90 P-Value = 0.075 80 70 60 50 40 Percent 30 20 10 5 1 0.1 10000 100000 1000000 Time
  • 17. Formal Test for the Data Being Weibull Distributed Probability Plot for Time Weibull - 95% CI 99.9 99 Goodness of Fit Test 90 AD = 1.509 80 70 P-Value < 0.010 60 50 40 30 20 Percent 10 5 3 2 1 0.1 10000 100000 1000000 Time
  • 18. Mean Time To Beverage and “Reliability” at Marlboro Biased Unbiased 190652.872424565 ms 190652.916039948 ms 3.17754787374275 min 3.1775486006658 min Biased Unbiased 0.8727 0.8754
  • 19. Is the Process Capable Based Upon a Gamma Model? Process Capability of Time Calculations Based on Gamma Distribution Model LB USL P rocess D ata O v erall C apability LB 0 Pp * Target * PPL * USL 300000 PPU 0.29 S ample M ean 190653 P pk 0.29 S ample N 94 Exp. O v erall P erformance S hape 3.97724 P P M < LB * S cale 47936 P P M > U S L 127306.05 O bserv ed P erformance P P M Total 127306.05 P P M < LB 0.00 P P M > U S L 95744.68 P P M Total 95744.68 0 100000 200000 300000 400000 500000
  • 20. Is the Process Capable Based Upon a Weibull Model? Process Capability of Time Calculations Based on Weibull Distribution Model LB USL P rocess D ata O v erall C apability LB 0 Pp * Target * PPL * USL 300000 PPU 0.32 S ample M ean 190653 P pk 0.32 S ample N 94 Exp. O v erall P erformance S hape 2.00713 P P M < LB * S cale 216106 P P M > U S L 144910.81 O bserv ed P erformance P P M Total 144910.81 P P M < LB 0.00 P P M > U S L 95744.68 P P M Total 95744.68 0 100000 200000 300000 400000 500000
  • 21. Is the Beverage Delivery Process in Control? I-MR Chart of Marlboro I-MR Chart of Marlboro Using Box-Cox Transformation With Lambda = 0.50 600000 1 1 1 1 800 1 1 1 1 1 1 Individual V alue 450000 U C L=407256 UCL=679.6 Individual Value 600 300000 _ _ X=190653 X=422.7 150000 400 0 LC L=-25950 200 LCL=165.8 1 10 19 28 37 46 55 64 73 82 91 O bser vation 1 10 19 28 37 46 55 64 73 82 91 Observation 1 11 11 1 400000 450 M oving Range 300000 UCL=315.6 Moving Range U C L=266097 300 200000 __ 150 __ 100000 M R=81443 MR=96.6 0 LC L=0 0 LCL=0 1 10 19 28 37 46 55 64 73 82 91 1 10 19 28 37 46 55 64 73 82 91 O bser vation Observation
  • 22. New Brunswick NJ Location
  • 23. New Brunswick Wait Time Data
  • 24. Does the Data Follow a Weibull Distribution? Histogram of Time Weibull 40 Shape 1.994 Scale 273830 N 198 30 Frequency 20 10 0 0 100000 200000 300000 400000 500000 600000 Time
  • 25. Does the Data Follow a Gamma Distribution? Histogram of Time Gamma 40 Shape 3.080 Scale 78771 N 198 30 Frequency 20 10 0 0 100000 200000 300000 400000 500000 600000 Time
  • 26. Can the arrivals of customers be Modeled as a Poisson Process? Goodness-of-Fit Test for Poisson Distribution Data column: New Brunswick Poisson mean for New Brunswick = 9.9 New Poisson Contribution Brunswick Observed Probability Expected to Chi-Sq <=6 4 0.136574 2.73148 0.589107 7 - 8 3 0.207617 4.15235 0.319795 9 - 10 5 0.251357 5.02715 0.000147 11 - 12 4 0.205390 4.10780 0.002829 >=13 4 0.199062 3.98123 0.000088 N N* DF Chi-Sq P-Value 20 0 3 0.911967 0.823
  • 27. Formal Test for the Data Being Normally Distributed Probability Plot for Time Normal - 95% CI 99.9 Goodness of Fit Test 99 AD = 1.680 95 P-Value < 0.005 90 80 70 Percent 60 50 40 30 20 10 5 1 0.1 00 00 0 00 00 00 00 00 00 00 000 0 00 00 00 00 00 00 00 00 -2 -1 10 20 30 40 50 60 70 Time
  • 28. Formal Test for the Data Being Gamma Distributed Probability Plot for Time Gamma - 95% CI 99.9 Goodness of Fit Test 99 95 AD = 0.911 90 P-Value = 0.023 80 70 60 50 40 Percent 30 20 10 5 1 0.1 10000 100000 1000000 Time
  • 29. Formal Test for the Data Being Weibull Distributed Probability Plot for Time Weibull - 95% CI 99.9 99 Goodness of Fit Test 90 AD = 0.441 80 70 P-Value > 0.250 60 50 40 30 20 Percent 10 5 3 2 1 0.1 10000 100000 1000000 Time
  • 30. Why Might the Data Not Follow a Gamma? Poisson Gamma ? Gamma * ? =? Make Drink Wait in Line Process Arrival Deliver To Store Order Drink Drink What We Measured
  • 31. Is the Process Capable Based Upon a Weibull Model? Process Capability of Time Calculations Based on Weibull Distribution Model LB USL P rocess D ata O v erall C apability LB 0 Pp * Target * PPL * USL 300000 PPU 0.15 S ample M ean 242647 P pk 0.15 S ample N 198 E xp. O v erall P erformance S hape 1.99408 P P M < LB * S cale 273830 P P M > U S L 301307.05 O bserv ed P erformance P P M Total 301307.05 P P M < LB 0.00 P P M > U SL 303030.30 P P M Total 303030.30 0 100000 200000 300000 400000 500000 600000
  • 32. Is the Process Capable Based Upon a Gamma Model? Process Capability of Time Calculations Based on Gamma Distribution Model LB USL P rocess D ata O v erall C apability LB 0 Pp * Target * PPL * USL 300000 PPU 0.13 S ample M ean 242647 P pk 0.13 S ample N 198 E xp. O v erall P erformance S hape 3.0804 P P M < LB * S cale 78771.2 P P M > U S L 283036.30 O bserv ed P erformance P P M Total 283036.30 P P M < LB 0.00 P P M > U S L 303030.30 P P M Total 303030.30 0 100000 200000 300000 400000 500000 600000
  • 33. Mean Time To Beverage and “Reliability” at New Brunswick Biased Unbiased 242688.9419 ms 242371.0724 ms 4.0448 mins 4.0395 mins Biased Unbiased 0.6987 0.6993
  • 34. Is the Beverage Delivery Process in Control? I-MR Chart of New Brunswick I-MR Chart of New Brunswick 1 1 Using Box-Cox Transformation With Lambda = 0.50 600000 11 1 1 1 1 1 800 11 1 U C L=485623 UCL=733.1 Individual V alue 450000 Individual Value 600 300000 _ _ X=242647 X=473.9 400 150000 0 LC L=-330 200 LCL=214.7 1 1 1 1 1 1 1 1 1 21 41 61 81 101 121 141 161 181 1 O bser vation 1 21 41 61 81 101 121 141 161 181 Observation 1 480000 1 11 1 1 600 1 1 1 1 360000 1 1 Moving Range 1 1 11 1 Moving Range 1 1 U C L=298497 400 1 240000 UCL=318.4 __ 200 120000 __ M R=91359 MR=97.4 0 LC L=0 0 LCL=0 1 21 41 61 81 101 121 141 161 181 1 21 41 61 81 101 121 141 161 181 O bser vation Observation
  • 35. Marlboro New Brunswick Starbucks Wait Time Analysis COMBINED
  • 36. Is there a difference between Marlboro and New Brunswick? Histogram of Marlboro, New Brunswick Gamma 40 Variable Marlboro New Brunswick Shape Scale N 30 3.977 47936 94 3.080 78771 198 Frequency 20 10 0 0 100000 200000 300000 400000 500000 600000 Data
  • 37. Is there a difference between Marlboro and New Brunswick? Kruskal-Wallis Test: Wait Times versus Location Kruskal-Wallis Test on C2 Subscripts N Median Ave Rank Z Marlboro 94 173350 121.6 -3.47 New Brunswick 198 216245 158.3 3.47 Overall 292 146.5 H = 12.04 DF = 1 P = 0.001 H = 12.04 DF = 1 P = 0.001 (adjusted for ties)
  • 39. Does the Data Follow a Weibull Distribution? Histogram of Combined Weibull 35 Shape 1.954 Scale 255391 N 292 30 25 Frequency 20 15 10 5 0 0 100000 200000 300000 400000 500000 600000 Combined
  • 40. Does the Data Follow a Gamma Distribution? Histogram of Combined Gamma 35 Shape 3.201 Scale 70580 N 292 30 25 Frequency 20 15 10 5 0 0 100000 200000 300000 400000 500000 600000 Combined
  • 41. Are the Arrival Rates the Same? Histogram of Marlboro, New Brunswick 2 4 6 8 10 12 14 16 Marlboro New Brunswick 9 8 7 6 Frequency 5 4 3 2 1 0 2 4 6 8 10 12 14 16
  • 42. Are the Arrival Rates the Same? Kruskal-Wallis Test: Arrivals versus Location Kruskal-Wallis Test on Arrivals Location N Median Ave Rank Z Marlboro 18 4.500 12.4 -3.76 New Brunswick 20 10.000 25.9 3.76 Overall 38 19.5 H = 14.11 DF = 1 P = 0.000 H = 14.26 DF = 1 P = 0.000 (adjusted for ties)
  • 43. Can the arrivals of customers be Modeled as a Poisson Process? Goodness-of-Fit Test for Poisson Distribution Data column: Combined Poisson mean for Combined = 7.68421 Poisson Contribution Combined Observed Probability Expected to Chi-Sq <=4 10 0.119196 4.52945 6.60719 5 3 0.102708 3.90291 0.20888 6 4 0.131538 4.99846 0.19945 7 2 0.144396 5.48703 2.21602 8 4 0.138696 5.27044 0.30624 9 3 0.118419 4.49991 0.49995 10 3 0.090995 3.45782 0.06062 11 1 0.063566 2.41551 0.82950 >=12 8 0.090486 3.43846 6.05144 N N* DF Chi-Sq P-Value 38 0 7 16.9793 0.018
  • 44. Why Might the data set of Combined Arrivals Not Represent a Poisson Process? • Not a large enough data set • Not constant arrival rate – Different demand for Beverages at different stores at different times • Other factors are influencing the independence of events – Traffic lights
  • 45. Formal Test for the Data Being Normally Distributed Probability Plot for Combined Normal - 95% CI 99.9 Goodness of Fit Test 99 AD = 4.293 95 P-Value < 0.005 90 80 70 Percent 60 50 40 30 20 10 5 1 0.1 0 00 0 0 0 0 0 0 0 0 00 00 00 00 00 00 00 00 00 00 10 00 00 00 00 00 00 00 -2 - 1 2 3 4 5 6 7 Combined
  • 46. Formal Test for the Data Being Gamma Distributed Probability Plot for Combined Gamma - 95% CI 99.9 Goodness of Fit Test 99 95 AD = 0.594 90 P-Value = 0.141 80 70 60 50 40 Percent 30 20 10 5 1 0.1 10000 100000 1000000 Combined
  • 47. Formal Test for the Data Being Weibull Distributed Probability Plot for Combined Weibull - 95% CI 99.9 99 Goodness of Fit Test 90 AD = 0.959 80 70 P-Value = 0.016 60 50 40 30 20 Percent 10 5 3 2 1 0.1 10000 100000 1000000 Combined
  • 48. Mean Time To Beverage and “Reliability” Biased Unbiased 225908.8493 ms 226153.1587 ms 3.7651 mins 3.7692 mins Biased Unbiased 0.7629 0.7617
  • 49. Is the Process Capable Based Upon a Gamma Model? Process Capability of Combined Calculations Based on Gamma Distribution Model LB USL P rocess D ata O v erall C apability LB 0 Pp * Target * PPL * USL 300000 PPU 0.16 S ample M ean 225909 P pk 0.16 S ample N 292 Exp. O v erall P erformance S hape 3.20075 P P M < LB * S cale 70580 P P M > U S L 237100.41 O bserv ed P erformance P P M Total 237100.41 P P M < LB 0.00 P P M > U S L 236301.37 P P M Total 236301.37 0 100000 200000 300000 400000 500000 600000
  • 50. Is the Process Capable Based Upon a Weibull Model? Process Capability of Combined Calculations Based on Weibull Distribution Model LB USL P rocess D ata O v erall C apability LB 0 Pp * Target * PPL * USL 300000 PPU 0.19 S ample M ean 225909 P pk 0.19 S ample N 292 Exp. O v erall P erformance S hape 1.95393 P P M < LB * S cale 255391 P P M > U S L 254194.23 O bserv ed P erformance P P M Total 254194.23 P P M < LB 0.00 P P M > U S L 236301.37 P P M Total 236301.37 0 100000 200000 300000 400000 500000 600000
  • 51. Is the Process Capable Based Upon a Weibull Model? The corresponds to a Sigma level of 4. The Goal is 6!
  • 52. Is the Process Capable Based Upon a Gamma Model? The corresponds to a Sigma level of 2. The Goal is 6!
  • 53. Conclusions • The amount of time a customer waits at a Starbucks is dependent on which location they visit. • Regardless of location, Starbucks is incapable of reliably delivering a beverage in less than 5 minutes • There is evidence to suggest that the arrivals follow a Poisson distribution which is supported by the literature • There is evidence to suggest that the wait times follow a gamma distribution which the literature would suggest
  • 54. Academics About the Author – MS Industrial Engineering Rutgers University – BS Electrical & Computer Engineering Rutgers University – BA Physics Rutgers University • Awards – ASQ Top 40 Leader in Quality Under 40. • Professional – Principal Industrial Engineer -Medtronic – Master Black belt- American Standard Brands – Systems Engineer- Johnson Scale Co • Certifications – ASQ Certified Manager of Quality/ Org Excellence Cert # 13788 – ASQ Certified Quality Auditor Cert # 41232 – ASQ Certified Quality Engineer Cert # 56176 – ASQ Certified Reliability Engineer Cert #7203 – ASQ Certified Six Sigma Green Belt Cert # 3962 – ASQ Certified Six Sigma Black Belt Cert # 9641 – ASQ Certified Software Quality Engineer Cert # 4941 • Publications – Going with the Flow- The importance of collecting data without holding up your processes- Quality Progress March 2011 – "Numbers Are Not Enough: Improved Manufacturing Comes From Using Quality Data the Right Way" (cover story). Industrial Engineering Magazine- Journal of the Institute of Industrial Engineers September (2011): 28-33. Print
  • 55. ?