This document provides revision notes for the VCE Physics exam, covering topics such as:
- Common exam questions that received less than 60%
- Conservation of energy principles
- Kinetic energy calculations during vertical motion
- Centripetal force and weightlessness in orbit
- Electromagnetism and induced currents
- Photoelectric effect and photon energies
- Atomic spectra and allowed energy levels
- Circuit diagrams and calculations
The notes emphasize key formulas, common mistakes to avoid, and concise explanations of challenging concepts.
9. The Total Energy will add to a constant amount. There is
no graph that shows the Kinetic Energy. If KE is included
there will always be a constant amount of energy.
10. The max speed will occur in the central position. When
extension and height from lowest point is 0.4m. The
missing energy from the total will be KE.
11. Initial vertical velocity is 10 m/s
ie. 20sin(30)=10
Reaches the highest point v=0.
NEVER use the velocity which is at an angle directly into any motion
formulae. BIG mistake. HUGE!
12. What is the time when it has
travelled 26m horizontally?
vh= 20cos(30)=17.32 m/s
13. Need to understand that the
reason they are weightless is the
Normal Force is ZERO and the
centrifical force comes from
gravity.
14. Like we stated in part a. However, you will probably get full marks by
quoting. Weightlessness is:
-The Normal reaction force is equal to ZERO.
-They are in a state of constant free fall.
-The only force acting on them is gravity.
-The centrifical force is equal to the gravitational force.
16. For Gravitational Motion write these formulae on your Cheat Sheet
DO NOT try to manipulate the equations in the exam.
Use T is seconds not minutes, hours
days
Use v in m/s not km/h
Know how your calculator uses scientific
notation
17. 1200 hours
=4.32 E 6 seconds
No
The mass of a satellite (planet) is independent of the period
and radius.
Any object orbiting at that radius from the star will have the
same period irrespective of the mass.
You could answer this by showing a formula and explaining
that it is independent of m
22. These are difficult questions
State the initial direction of the field: Down into the page
The induced current will have a B field that:
(OPPOSES THE CHANGE or KEEPS THE FIELD THE
SAME)
This will be down INTO the page.
Using the RH grip rule the current is clockwise.
You will get one mark for
guessing the correct direction.
If you write rubbish about the
reason will not lose the mark if the
arrow is correct.
29. Increasing the intensity means more photons of the same energy.
The ejected photoelectrons have the same max Energy as before.
The photon energy is linked to the frequency not the brightness.
Each photon can only interact with one electron.
If light was a wave light of any frequency would be able to emit
photoelectrons as the energy builds up.
30. The first excited state is 4.9eV of energy, it can
absorb 1.8 eV and move up into the 6.7eV state.
But can only emit 4.9 eV and move down into the 0
or ground state.
You could say there is NOT 4.9 - 1.8
= 3.1 eV energy level
31. 8.9 - 6.7 = 2.2 V
9.8 - 8.9 = 0.9 V
10.4 - 8.9 = 1.5 V
8.9 V
32. The length of the orbit is 2πR. A whole number multiple of
the wavelength must be equal to the length of the orbital
distance.
A diagram showing the standing waves and different orbits is
also acceptable answer