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This is Due to highest Cncentration of Comon Ions.pdf
This is Due to highest Cncentration of Comon Ions(SO42-) The reason is
\"Common Ion Effect\" (NH4)2SO4 has highest concentration of SO42-
Solution
This is Due to highest Cncentration of Comon Ions(SO42-) The reason is
\"Common Ion Effect\" (NH4)2SO4 has highest concentration of SO42-.
There is no reaction. The nearest I can think of .pdf
There is no reaction. The nearest I can think of involving the above is: MgCl2 + 2
NaOH = Mg(OH)2 + 2 NaCl
Solution
There is no reaction. The nearest I can think of involving the above is: MgCl2 + 2
NaOH = Mg(OH)2 + 2 NaCl.
The decomposition of hydrogen peroxide to gaseous.pdf
The decomposition of hydrogen peroxide to gaseous O2 and water is a spontaneous
process only means H2O2 is thermodynamically unstable. The fact that H2O2 is stable for long
periods of time indicates that H2O2 is kinetically stable. Thus. Adding catalyst will speed the
decomposition reaction up cause it decreases the activation energy.
Solution
The decomposition of hydrogen peroxide to gaseous O2 and water is a spontaneous
process only means H2O2 is thermodynamically unstable. The fact that H2O2 is stable for long
periods of time indicates that H2O2 is kinetically stable. Thus. Adding catalyst will speed the
decomposition reaction up cause it decreases the activation energy..
NaBr Na is metal and Br is electronegative. All.pdf
NaBr Na is metal and Br is electronegative. All others without metal
Solution
NaBr Na is metal and Br is electronegative. All others without metal.
it is not hydrolyzed because of steric hindrance .pdf
it is not hydrolyzed because of steric hindrance created by OEt group
Solution
it is not hydrolyzed because of steric hindrance created by OEt group.
Im not entirely sure what this is asking. I ass.pdf
I\'m not entirely sure what this is asking. I assume these are two processes being
performed on the molecule shown. I\'ve seen similar reactions and not exactly the same thing.
OsO4 usually adds OH cis if I recall to the inner carbons, but the OH groups are already there.
The second part of that might add SO2? For question 2 I\'m almost certain that the initial reaction
removes the OH groups on the original molecule and makes it into an epoxide. adding hydroxide
and H20 would make it a basic environment so an H+ in solution would protonate the epoxide.
OH would attach wherever the bond to the protonated epoxide was weakest, resulting in the
initial molecule with one of the centers having inverted stereochemistry 40% sure on all of this at
best. I just had my orgo final. good luck on yours :)
Solution
I\'m not entirely sure what this is asking. I assume these are two processes being
performed on the molecule shown. I\'ve seen similar reactions and not exactly the same thing.
OsO4 usually adds OH cis if I recall to the inner carbons, but the OH groups are already there.
The second part of that might add SO2? For question 2 I\'m almost certain that the initial reaction
removes the OH groups on the original molecule and makes it into an epoxide. adding hydroxide
and H20 would make it a basic environment so an H+ in solution would protonate the epoxide.
OH would attach wherever the bond to the protonated epoxide was weakest, resulting in the
initial molecule with one of the centers having inverted stereochemistry 40% sure on all of this at
best. I just had my orgo final. good luck on yours :).
ViewerFrame.java import javax.swing.JFrame;public class Viewer.pdf
ViewerFrame.java
import javax.swing.JFrame;
public class ViewerFrame extends JFrame
{
public ViewerFrame(){
OpsPanel OP = new OpsPanel();
add(OP);
}
public static void main(String[] args){
ViewerFrame v = new ViewerFrame();
v.setSize(1000,600);
v.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
v.setVisible(true);
}
}
OpsPanel.java
import java.awt.Graphics;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.util.ArrayList;
import java.util.Scanner;
import javax.swing.JPanel;
import java.awt.Font;
public class OpsPanel extends JPanel{
private int x = 50;
private int y = 50;
private int titleX = 50;
private int titleY = 30;
private Scanner in;
private String intLine1;
private String intLine2;
private String sign;
private ArrayList list = new ArrayList<>();
public OpsPanel(){
//Open file for reading and catch if file isn\'t there.
try{
in = new Scanner(new FileReader(\"addsAndSubtracts.txt\"));
}
catch(FileNotFoundException nf){
System.out.println(\"File Not Found!\");
}
while(in.hasNext()){
intLine1 = in.next();
sign = in.next();
intLine2 = in.next();
System.out.println(intLine1 + sign + intLine2);
list.add(new Ops(intLine1, intLine2, sign));
}
repaint();
}
@Override
public void paintComponent(Graphics g){
super.paintComponent(g);
g.setFont(new Font(g.getFont().getFontName(),Font.PLAIN, 20));
g.drawString(\"Operand 1 +/- Operand 2 = Result\", titleX, titleY);
g.setFont(new Font(g.getFont().getFontName(),Font.PLAIN, 12));
for (Ops o: list) {
o.drawInfo(g, x, y);
y+=15;
}
}
}
Ops.java
import java.util.LinkedList;
import java.awt.*;
import javax.swing.*;
//import java.util.Formatter;
public class Ops extends JPanel{
private String bigInt1;
private String sign1;
private String bigInt2;
private String sign2;
private String opSign;
private String calcSign;
private LinkedList largeInt;
private LinkedList smallInt;
private LinkedList resultInt;
public Ops(String bI1, String bI2, String sign){
//Save original sign for display.
opSign = sign;
//Save signs on strings.
if(bI1.charAt(0) == \'-\'){
bI1 = bI1.substring(1);
sign1 = \"-\";
}
else{
sign1 = \"\";
}
if(bI2.charAt(0) == \'-\'){
bI2 = bI2.substring(1);
sign2 = \"-\";
}
else{
sign2 = \"\";
}
//Test lengths for padding and other operations.
if(bI1.length() > bI2.length()){
}
else if(bI2.length() > bI1.length()){
}
else{
}
if(sign.equalsIgnoreCase(\"+\")){
if(sign1.equalsIgnoreCase(\"\") && sign2.equalsIgnoreCase(\"\")){
}
else{
}
}
}
public void calcResult(String bI1, String bI2, String calcS){
}
@Override
public String toString(){
String.format(\"\");
return sign1 + bigInt1 + \" \" + opSign + \" \" + sign2 + bigInt2 + \" = \" + resultInt;
}
public void drawInfo(Graphics g, int x, int y){
g.drawString(toString(), x,y);
}
}
Solution
ViewerFrame.java
import javax.swing.JFrame;
public class ViewerFrame extends JFrame
{
public ViewerFrame(){
OpsPanel OP = new OpsPanel();
add(OP);
}
public static void main(String[] args){
ViewerFrame v = new ViewerFrame();
v.setSize(1000,600);
v.se.
Recommended
This is Due to highest Cncentration of Comon Ions.pdf
This is Due to highest Cncentration of Comon Ions(SO42-) The reason is
\"Common Ion Effect\" (NH4)2SO4 has highest concentration of SO42-
Solution
This is Due to highest Cncentration of Comon Ions(SO42-) The reason is
\"Common Ion Effect\" (NH4)2SO4 has highest concentration of SO42-.
There is no reaction. The nearest I can think of .pdf
There is no reaction. The nearest I can think of involving the above is: MgCl2 + 2
NaOH = Mg(OH)2 + 2 NaCl
Solution
There is no reaction. The nearest I can think of involving the above is: MgCl2 + 2
NaOH = Mg(OH)2 + 2 NaCl.
The decomposition of hydrogen peroxide to gaseous.pdf
The decomposition of hydrogen peroxide to gaseous O2 and water is a spontaneous
process only means H2O2 is thermodynamically unstable. The fact that H2O2 is stable for long
periods of time indicates that H2O2 is kinetically stable. Thus. Adding catalyst will speed the
decomposition reaction up cause it decreases the activation energy.
Solution
The decomposition of hydrogen peroxide to gaseous O2 and water is a spontaneous
process only means H2O2 is thermodynamically unstable. The fact that H2O2 is stable for long
periods of time indicates that H2O2 is kinetically stable. Thus. Adding catalyst will speed the
decomposition reaction up cause it decreases the activation energy..
NaBr Na is metal and Br is electronegative. All.pdf
NaBr Na is metal and Br is electronegative. All others without metal
Solution
NaBr Na is metal and Br is electronegative. All others without metal.
it is not hydrolyzed because of steric hindrance .pdf
it is not hydrolyzed because of steric hindrance created by OEt group
Solution
it is not hydrolyzed because of steric hindrance created by OEt group.
Im not entirely sure what this is asking. I ass.pdf
I\'m not entirely sure what this is asking. I assume these are two processes being
performed on the molecule shown. I\'ve seen similar reactions and not exactly the same thing.
OsO4 usually adds OH cis if I recall to the inner carbons, but the OH groups are already there.
The second part of that might add SO2? For question 2 I\'m almost certain that the initial reaction
removes the OH groups on the original molecule and makes it into an epoxide. adding hydroxide
and H20 would make it a basic environment so an H+ in solution would protonate the epoxide.
OH would attach wherever the bond to the protonated epoxide was weakest, resulting in the
initial molecule with one of the centers having inverted stereochemistry 40% sure on all of this at
best. I just had my orgo final. good luck on yours :)
Solution
I\'m not entirely sure what this is asking. I assume these are two processes being
performed on the molecule shown. I\'ve seen similar reactions and not exactly the same thing.
OsO4 usually adds OH cis if I recall to the inner carbons, but the OH groups are already there.
The second part of that might add SO2? For question 2 I\'m almost certain that the initial reaction
removes the OH groups on the original molecule and makes it into an epoxide. adding hydroxide
and H20 would make it a basic environment so an H+ in solution would protonate the epoxide.
OH would attach wherever the bond to the protonated epoxide was weakest, resulting in the
initial molecule with one of the centers having inverted stereochemistry 40% sure on all of this at
best. I just had my orgo final. good luck on yours :).
ViewerFrame.java import javax.swing.JFrame;public class Viewer.pdf
ViewerFrame.java
import javax.swing.JFrame;
public class ViewerFrame extends JFrame
{
public ViewerFrame(){
OpsPanel OP = new OpsPanel();
add(OP);
}
public static void main(String[] args){
ViewerFrame v = new ViewerFrame();
v.setSize(1000,600);
v.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
v.setVisible(true);
}
}
OpsPanel.java
import java.awt.Graphics;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.util.ArrayList;
import java.util.Scanner;
import javax.swing.JPanel;
import java.awt.Font;
public class OpsPanel extends JPanel{
private int x = 50;
private int y = 50;
private int titleX = 50;
private int titleY = 30;
private Scanner in;
private String intLine1;
private String intLine2;
private String sign;
private ArrayList list = new ArrayList<>();
public OpsPanel(){
//Open file for reading and catch if file isn\'t there.
try{
in = new Scanner(new FileReader(\"addsAndSubtracts.txt\"));
}
catch(FileNotFoundException nf){
System.out.println(\"File Not Found!\");
}
while(in.hasNext()){
intLine1 = in.next();
sign = in.next();
intLine2 = in.next();
System.out.println(intLine1 + sign + intLine2);
list.add(new Ops(intLine1, intLine2, sign));
}
repaint();
}
@Override
public void paintComponent(Graphics g){
super.paintComponent(g);
g.setFont(new Font(g.getFont().getFontName(),Font.PLAIN, 20));
g.drawString(\"Operand 1 +/- Operand 2 = Result\", titleX, titleY);
g.setFont(new Font(g.getFont().getFontName(),Font.PLAIN, 12));
for (Ops o: list) {
o.drawInfo(g, x, y);
y+=15;
}
}
}
Ops.java
import java.util.LinkedList;
import java.awt.*;
import javax.swing.*;
//import java.util.Formatter;
public class Ops extends JPanel{
private String bigInt1;
private String sign1;
private String bigInt2;
private String sign2;
private String opSign;
private String calcSign;
private LinkedList largeInt;
private LinkedList smallInt;
private LinkedList resultInt;
public Ops(String bI1, String bI2, String sign){
//Save original sign for display.
opSign = sign;
//Save signs on strings.
if(bI1.charAt(0) == \'-\'){
bI1 = bI1.substring(1);
sign1 = \"-\";
}
else{
sign1 = \"\";
}
if(bI2.charAt(0) == \'-\'){
bI2 = bI2.substring(1);
sign2 = \"-\";
}
else{
sign2 = \"\";
}
//Test lengths for padding and other operations.
if(bI1.length() > bI2.length()){
}
else if(bI2.length() > bI1.length()){
}
else{
}
if(sign.equalsIgnoreCase(\"+\")){
if(sign1.equalsIgnoreCase(\"\") && sign2.equalsIgnoreCase(\"\")){
}
else{
}
}
}
public void calcResult(String bI1, String bI2, String calcS){
}
@Override
public String toString(){
String.format(\"\");
return sign1 + bigInt1 + \" \" + opSign + \" \" + sign2 + bigInt2 + \" = \" + resultInt;
}
public void drawInfo(Graphics g, int x, int y){
g.drawString(toString(), x,y);
}
}
Solution
ViewerFrame.java
import javax.swing.JFrame;
public class ViewerFrame extends JFrame
{
public ViewerFrame(){
OpsPanel OP = new OpsPanel();
add(OP);
}
public static void main(String[] args){
ViewerFrame v = new ViewerFrame();
v.setSize(1000,600);
v.se.
Z = (x-mean)sd = (82-70)8 = 1.50SolutionZ = (x-mean)sd = (8.pdf
Z = (x-mean)/sd = (82-70)/8 = 1.50
Solution
Z = (x-mean)/sd = (82-70)/8 = 1.50.
First remember that non polar compounds are solub.pdf
First remember that non polar compounds are soluble in non polar solvents (like
benzene in acetone) and polar compounds are soluble in polar solvents (like NaCl in H2O) Now
if you consider solubility in water, all polar compounds are soluble and the structure which can
make hydrogen bonding with water is also soluble like methanol which can form hydrogen
bonding with water.. First look at the structure to identify what kind of bonds are existing, if you
see any ionic bond it will be soluble in water. inorganic base is something like NaOH which has
the basic unit OH- which can easily take a proton from an organic acid and from a bond and
hence it will be soluble. organic base is soluble when organic acid is present because acid and
base has the larger tendency to get interacted and form a complex.
Solution
First remember that non polar compounds are soluble in non polar solvents (like
benzene in acetone) and polar compounds are soluble in polar solvents (like NaCl in H2O) Now
if you consider solubility in water, all polar compounds are soluble and the structure which can
make hydrogen bonding with water is also soluble like methanol which can form hydrogen
bonding with water.. First look at the structure to identify what kind of bonds are existing, if you
see any ionic bond it will be soluble in water. inorganic base is something like NaOH which has
the basic unit OH- which can easily take a proton from an organic acid and from a bond and
hence it will be soluble. organic base is soluble when organic acid is present because acid and
base has the larger tendency to get interacted and form a complex..
There are many types of malwares like Trojans, viruses, worms, rootk.pdf
There are many types of malwares like Trojans, viruses, worms, rootkits, and many more
We will here discuss about viruses and worms
Viruses are the programs that gets themselves replicated itself and gets into other files and
programs and destroys data or makes the file damaged so that the file becomes corrupt or
damaged. Whenever the user tries to open the infected files virus gets spread in other files.
Worms are self-activated programs. They spreads over the networks and infect the other
computers in the network without user’s knowledge and permission and sends the data of one
system to others.
Solution
There are many types of malwares like Trojans, viruses, worms, rootkits, and many more
We will here discuss about viruses and worms
Viruses are the programs that gets themselves replicated itself and gets into other files and
programs and destroys data or makes the file damaged so that the file becomes corrupt or
damaged. Whenever the user tries to open the infected files virus gets spread in other files.
Worms are self-activated programs. They spreads over the networks and infect the other
computers in the network without user’s knowledge and permission and sends the data of one
system to others..
The standard form of a complex number is a real number plusminus an.pdf
The standard form of a complex number is a real number plus/minus an imaginary number.
Divide each term in the numerator by the denominator.
(10 + i) / 14i =
(5/7)i + (1/14) = (1/14) (5/7)i
1/14 is the real part.
(5/7)i is the imaginary part.
Solution
The standard form of a complex number is a real number plus/minus an imaginary number.
Divide each term in the numerator by the denominator.
(10 + i) / 14i =
(5/7)i + (1/14) = (1/14) (5/7)i
1/14 is the real part.
(5/7)i is the imaginary part..
Question) one or more attributes that comprise a primary key in a ro.pdf
Question) one or more attributes that comprise a primary key in a row in a relational table
Answer ) Key attribute
Entity Integrity
Foreign Key
Composite key
Key Attribute : represents primary key. (main characteristics of an entity). It is an attribute, that
has distinct value for each entity/element in an entity set. For example, Roll number in a Student
Entity Type.
Solution
Question) one or more attributes that comprise a primary key in a row in a relational table
Answer ) Key attribute
Entity Integrity
Foreign Key
Composite key
Key Attribute : represents primary key. (main characteristics of an entity). It is an attribute, that
has distinct value for each entity/element in an entity set. For example, Roll number in a Student
Entity Type..
pls provide the dataSolutionpls provide the data.pdf
pls provide the data
Solution
pls provide the data.
Photosynthesis - is the unique process that is limited to plant king.pdf
Photosynthesis - is the unique process that is limited to plant kingdom.Green plants are able to
synthesize carbohydrates in there systems due to the presence of an uinique structure called
chloroplast.
The chloroplasts are present only in plant kingdom which gives them the ability to trap solar
energy convert it into chemical energy along with the synthesis of carbohydrates and evolution
of oxygen, so the process of photosynthesis does not only fix the carbon di oxide but in the
process also give out oxygen.
These chloroplasts are present in diverse groups of plant kingdom and may show structural
differences . Though they exhibit variations in their structure they perform the same function.The
chloroplasts are membrane bound organnels locate din the cytoplasm and are responsible for the
trapping of solar energy and converting it into chemical energy in the form of ATP and
NADPH due to the presence of the pigment chlorophyll and in the process liberate oxygen from
the water molecule through a series of reactions.
The number of chloroplasts per cell vary from one organism to the other they may be varying
from 1 as seen in algae or may be upto 100 per cell as seen in higher plants.the chloroplasts
develop from a pre existing plastids known as the proplastid.whcih can develop into a variety of
plastids like the chloroplast, leucoplast amyloplast etc.
They are considered to have originated from cyanobacteria through endosymbiosis .The
ancestors of chloroplasts are believed to be the cyanobacteria or the blue-green algae .They are
often found as symbionts with a number of other groups of organisms like the
fungi,pteridophytes angiosperms .The oxygen present in the atmosphere is attributed due to the
activity of these cyanobacteria.They do not have a nucleus or any membrane bound organnels .
The photosynthetic apparatus is embedded into folds of the external cell membrane, called
thylakoids and contain a bluish green pigment phycocyanin and chlorophyll a.
The green algae cor the chlorophytes have a definite chloroplast whose shape may vary among
different members it may be cup shaped as seen in simple chlamydomonas , ribbon like as in
spirogyra or disc like as in higher members of the group . The main pigments are chlorophyll a, b
along with carotenoids and xanthophylls and have starch as the storage product.
the members of red algae have additional pigments in there chloroplast like phycobilins and
phycocyanins in addition to chlorophyll and the starch they make is also called as floridean
starch unique to the group.The brown algae differ from the other groups due to the presence of
the pigment fucoxanthin along with chlorophyll a and c which gives them the color.
If we move to higher group of plants like the bryophytes , Pteriodophytes, Gymnosperms and the
Angiosperms the chloroplast represents a well organized double membrane structures with they
thylakoids, grana , stroma , intergaranal lamella , stromal lamella and have chlorophyll as the
main.
Please follow the code and comments for description a)CODE #.pdf
Please follow the code and comments for description :
a)
CODE :
#include // header file
using namespace std;
double factorial(double n); // required method with the double value
int main() // main method
{
int n;
cout << \"Enter a positive integer: \"; // prompt to get the integer value
cin >> n;
cout << \"Factorial of \" << n << \" = \" << factorial(n); // calluing the function
return 0;
}
double factorial(double n)
{
if(n!=1)
return n*factorial(n-1); // returning the result
}
OUTPUT :
Enter a positive integer: 6
Factorial of 6 = 720
b)
CODE :
#include // header file
#include
using namespace std;
int main() // main method
{
int count = 0; // required initialisations
string line;
ifstream file(\"input.txt\"); //Creating input filestream
while (getline(file, line)){ // iterating over the loop to get the data and count
count++;
cout << line << endl; // printing the data
}
cout << \"Numbers of lines in the file : \" << count << endl; // print the count
return 0;
}
input.txt :
Hi
Hello
How are You
Hope Your are Doing Good
See You
Tomorrow
Good Bye
Meet
You
LAter
OUTPUT :
Hi
Hello
How are You
Hope Your are Doing Good
See You
Tomorrow
Good Bye
Meet
You
LAter
Numbers of lines in the file : 10
Hope this is helpful.
Solution
Please follow the code and comments for description :
a)
CODE :
#include // header file
using namespace std;
double factorial(double n); // required method with the double value
int main() // main method
{
int n;
cout << \"Enter a positive integer: \"; // prompt to get the integer value
cin >> n;
cout << \"Factorial of \" << n << \" = \" << factorial(n); // calluing the function
return 0;
}
double factorial(double n)
{
if(n!=1)
return n*factorial(n-1); // returning the result
}
OUTPUT :
Enter a positive integer: 6
Factorial of 6 = 720
b)
CODE :
#include // header file
#include
using namespace std;
int main() // main method
{
int count = 0; // required initialisations
string line;
ifstream file(\"input.txt\"); //Creating input filestream
while (getline(file, line)){ // iterating over the loop to get the data and count
count++;
cout << line << endl; // printing the data
}
cout << \"Numbers of lines in the file : \" << count << endl; // print the count
return 0;
}
input.txt :
Hi
Hello
How are You
Hope Your are Doing Good
See You
Tomorrow
Good Bye
Meet
You
LAter
OUTPUT :
Hi
Hello
How are You
Hope Your are Doing Good
See You
Tomorrow
Good Bye
Meet
You
LAter
Numbers of lines in the file : 10
Hope this is helpful..
Optimized Waterfall processIs a common project methodology and it.pdf
Optimized Waterfall process:
Is a common project methodology and it is a sequential design project method that was originally
consider for software development but is now used for a diversity of project types. It is generally
having 6 phases
1. Necessities
2. Design
3. Execution
4. Verification
5. Deployment
6. Preservation
Payoffs of water fall process:
There are several payoff of water fall process as follows
a). proper for simple or smaller projects
b). Requirements are well understood
c). Easy to understand
d). Easy to manage
e). Clear milestones
f). general documentation
Pitfalls of water fall process:
a). does not allow scope changes.
b). does not allow for requirement changes.
c). No working product until near completion of project.
Solution
Optimized Waterfall process:
Is a common project methodology and it is a sequential design project method that was originally
consider for software development but is now used for a diversity of project types. It is generally
having 6 phases
1. Necessities
2. Design
3. Execution
4. Verification
5. Deployment
6. Preservation
Payoffs of water fall process:
There are several payoff of water fall process as follows
a). proper for simple or smaller projects
b). Requirements are well understood
c). Easy to understand
d). Easy to manage
e). Clear milestones
f). general documentation
Pitfalls of water fall process:
a). does not allow scope changes.
b). does not allow for requirement changes.
c). No working product until near completion of project..
Organism Entameoeba histolyticQ AIt can be analyzed by feces te.pdf
Organism :Entameoeba histolytic
Q A
It can be analyzed by feces tests, however take note of that specific different species are difficult
to recognize by microscopy alone. Trophozoites might be found in a new fecal spread and sores
in a standard feces test. ELISA or RIA can likewise be utilized
Q B
The dynamic (trophozoite) arrange exists just in the host and in crisp free defecation; growths
make due outside the host in water, in soils, and on sustenances, particularly under wet
conditions on the last mentioned.
Q C
Distinctive monophasic media that were created for E. histolytica are the egg yolk imbuement
medium of Balamuth , Jones\' medium , and TYSGM-9 . Of the diverse media created for the
xenic development of E. histolytica, just three media, diphasic Locke-egg, Robinson\'s medium
Q D
anaerobic
QE
Microscopy utilized in an indicative clinical research facility incorporate wet planning, fixation,
and for all time recolored smears for the distinguishing proof of E. histolytica/E. dispar/E.
moshkovskii in excrement. Tiny examination of an immediate saline (wet) mount is an
exceptionally uncaring strategy (<10%) which is performed on a crisp example .The example
ought to be analyzed inside 1 h of accumulation to hunt down motile trophozoites which may
contain RBCs. Be that as it may, in patients who don\'t present with intense looseness of the
bowels, trophozoites won\'t contain RBCs. Patients with asymptomatic carriage by and large
have just growths in the fecal example. In spite of the fact that the focus procedure is useful in
exhibiting sores, the utilization of forever recolored smears (trichrome or press hematoxylin) is
an imperative technique for recuperation and distinguishing proof of Entamoeba species.
Q F Q G
In most by far of cases, disease is asymptomatic and the bearer is uninformed they are tainted.
Be that as it may, in an expected 10% of cases E. histolytica causes ailment. Once the
trophozoites are excysted they colonize the extensive gut, staying on the surface of the bodily
fluid layer and sustaining on microscopic organisms and sustenance particles. Every so often,
and in light of obscure boosts, trophozoites travel through the bodily fluid layer where they
interact with the epithelial cell layer and begin the obsessive procedure. E. histolytica has a lectin
that ties to galactose and N-acetylgalactosamine sugars on the surface of the epithelial cells, The
lectin typically is utilized to tie microscopic organisms for ingestion. The parasite has a few
catalysts, for example, pore shaping proteins, lipases, and cysteine proteases, which are regularly
used to process microbes in nourishment vacuoles yet which can bring about lysis of the
epithelial cells by instigating cell putrefaction and apoptosis when the trophozoite interacts with
them and ties through the lectin. The trophozoites will then ingest these dead cells. This harm to
the epithelial cell layer draws in human resistant cells and these thusly can be lysed by .
It is the main program that implement the min(), max(), floor(), cei.pdf
It is the main program that implement the min(), max(), floor(), ceiling(), select(), rank(),delete(),
deleteMin(), deleteMax(), keys()
import java.util.NoSuchElementException;
public class BST, Value> {
private Node root;
private class Node {
private Key key;
private Value val;
private Node left, right;
private int size;
public Node(Key key, Value val, int size) {
this.key = key;
this.val = val;
this.size = size;
}
}
public BST() {
}
public boolean isEmpty() {
return size() == 0;
}
public int size() {
return size(root);
}
// return number of key-value pairs in BST rooted at x
private int size(Node x) {
if (x == null) return 0;
else return x.size;
}
public boolean contains(Key key) {
if (key == null) throw new NullPointerException(\"argument to contains() is null\");
return get(key) != null;
}
public Value get(Key key) {
return get(root, key);
}
private Value get(Node x, Key key) {
if (x == null) return null;
int cmp = key.compareTo(x.key);
if (cmp < 0) return get(x.left, key);
else if (cmp > 0) return get(x.right, key);
else return x.val;
}
public void put(Key key, Value val) {
if (key == null) throw new NullPointerException(\"first argument to put() is null\");
if (val == null) {
delete(key);
return;
}
root = put(root, key, val);
assert check();
}
private Node put(Node x, Key key, Value val) {
if (x == null) return new Node(key, val, 1);
int cmp = key.compareTo(x.key);
if (cmp < 0) x.left = put(x.left, key, val);
else if (cmp > 0) x.right = put(x.right, key, val);
else x.val = val;
x.size = 1 + size(x.left) + size(x.right);
return x;
}
public void deleteMax() {
if (isEmpty()) throw new NoSuchElementException(\"Symbol table underflow\");
root = deleteMax(root);
assert check();
}
private Node deleteMax(Node x) {
if (x.right == null) return x.left;
x.right = deleteMax(x.right);
x.size = size(x.left) + size(x.right) + 1;
return x;
}
public void delete(Key key) {
if (key == null) throw new NullPointerException(\"argument to delete() is null\");
root = delete(root, key);
assert check();
}
private Node delete(Node x, Key key) {
if (x == null) return null;
int cmp = key.compareTo(x.key);
if (cmp < 0) x.left = delete(x.left, key);
else if (cmp > 0) x.right = delete(x.right, key);
else {
if (x.right == null) return x.left;
if (x.left == null) return x.right;
Node t = x;
x = min(t.right);
x.right = deleteMin(t.right);
x.left = t.left;
}
x.size = size(x.left) + size(x.right) + 1;
return x;
}
public Key min() {
if (isEmpty()) throw new NoSuchElementException(\"called min() with empty symbol
table\");
return min(root).key;
}
private Node min(Node x) {
if (x.left == null) return x;
else return min(x.left);
}
public Key max() {
if (isEmpty()) throw new NoSuchElementException(\"called max() with empty symbol
table\");
return max(root).key;
}
private Node max(Node x) {
if (x.right == null) return x;
else return max(x.right);
}
public Key floor(Key key) {
if (key == null) throw new NullPointerException(\"argument to floor() is null\");
if (isEmpty()) throw ne.
An overlay network may be a electronic network thats designed on h.pdf
An overlay network may be a electronic network that\'s designed on high of another network.
Nodes within the overlay network will be thought of as being connected by virtual or logical
links, every of that corresponds to a path, maybe through several physical links, within the
underlying network. for instance, distributed systems like peer-to-peer networks and client-server
applications ar overlay networks as a result of their nodes run on high of the net. the net was
originally designed as AN overlay upon the phonephone network, whereas these days (through
the appearance of VoIP), the phonephone network is {increasingly|progressively|more ANd
more} turning into an overlay network designed on high of the net.
Overlay networks ar utilized in telecommunication due to the supply of digital circuit change
instrumentality and glass fibre.[1] Telecommunication transport networks ANd informatics
networks (which combined form up the broader Internet) ar all overlaid with a minimum of an
glass fibre layer, a transport layer ANd an informatics OR gate change layers (in the case of the
PSTN).
Enterprise non-public networks were initial overlaid on telecommunication networks like frame
relay and Asynchronous Transfer Mode packet change infrastructures however migration from
these (now legacy) infrastructures to informatics based mostly MPLS networks and virtual non-
public networks started (2001~2002).
From a physical posture overlay networks ar quite advanced (see Figure 1) as they mix varied
logical layers that ar operated and designed by varied entities (businesses, universities,
government etc.) however they permit separation of considerations that over time allowable the
buildup of a broad set of services that would not are planned by one telecommunication operator
(ranging from broadband net access, voice informatics or IPTV, competitive medium operators
etc.).[2]
13
down vote
One reason we have a tendency to clock flip flops so there is not any chaos once the outputs of
flip flops area unit fed through some logic functions and back to their own inputs.
If a flip-flop\'s output is employed to calculate its input, it behooves North American nation to
possess orderly behavior: to stop the flip-flop\'s state from dynamical till the output (and
therefore the input) is stable.
This duration permits North American nation to create computers, that area unit state machines:
they need a current state, and calculate their next state supported the present state and a few
inputs.
For example, suppose we would like to create a machine that \"computes\" AN incrementing
four bit count from 0000 to 1111, and so wraps around to 0000 and keeps going. we are able to
do that by employing a four bit register (which may be a bank of 4 D flip-flops). The output of
the register is place through a combinatorial logic perform that adds one (a four bit adder) to
supply the incremented worth. This worth is then merely fed back to the register. Now, whenever
the clock edge arr.
Alkylating agents, or their reactive intermediates, form covalent bo.pdf
Alkylating agents, or their reactive intermediates, form covalent bonds with deoxyribonucleic
acid (DNA), ribonucleic acid (RNA), and protein to form an adduct in which a methyl or ethyl
group is added. DNA adducts are believed to play a major role in mutagenesis and clastogenesis,
as well as in carcinogenesis. DNA adducts are formed at a number of reactive sites on nucleotide
bases. Common locations include the N-7 and O-6 of guanine which are shown to be associated
with mutagenesis and carcinogenesis. In general, it seems that alkylating agents that are not
particularly ionic in nature are localized more on the ring nitrogen atoms, whereas those that
have greater ionic character show greater preferences for reaction at the oxygen atoms in DNA
(crios).
folate antagonists: effect the folate metabolism, which is the target of two major drug groups:
folate antagonists (for example, methotrexate) and thymidylate synthase inhibitors (for example,
5-fluorouracil) (Robien, 2005) . Since Folic acid\'s primary function in the body is as a cofactor
to various methyltransferases involved in serine, methionine, thymidine and purine biosynthesis.
Consequently, antifolates inhibit cell division, DNA/RNA synthesis and repair and protein
synthesis, (NCI)
Solution
Alkylating agents, or their reactive intermediates, form covalent bonds with deoxyribonucleic
acid (DNA), ribonucleic acid (RNA), and protein to form an adduct in which a methyl or ethyl
group is added. DNA adducts are believed to play a major role in mutagenesis and clastogenesis,
as well as in carcinogenesis. DNA adducts are formed at a number of reactive sites on nucleotide
bases. Common locations include the N-7 and O-6 of guanine which are shown to be associated
with mutagenesis and carcinogenesis. In general, it seems that alkylating agents that are not
particularly ionic in nature are localized more on the ring nitrogen atoms, whereas those that
have greater ionic character show greater preferences for reaction at the oxygen atoms in DNA
(crios).
folate antagonists: effect the folate metabolism, which is the target of two major drug groups:
folate antagonists (for example, methotrexate) and thymidylate synthase inhibitors (for example,
5-fluorouracil) (Robien, 2005) . Since Folic acid\'s primary function in the body is as a cofactor
to various methyltransferases involved in serine, methionine, thymidine and purine biosynthesis.
Consequently, antifolates inhibit cell division, DNA/RNA synthesis and repair and protein
synthesis, (NCI).
Hi,I have updated the code as per your requirement. Highlighted th.pdf
Hi,
I have updated the code as per your requirement. Highlighted the code changes below.
Program2.java
import java.util.Scanner; // Needed for the Scanner class
import java.text.DecimalFormat; // Needed for 2 decimal place amounts
public class Program2
{
public static void main(String[] args)
{
BankAccount account; // To reference a BankAccount object
double balance, // The account\'s starting balance
interestRate, // The annual interest rate
pay, // The user\'s pay
cashNeeded; // The amount of cash to withdraw
// Create a Scanner object for keyboard input.
Scanner keyboard = new Scanner(System.in);
// Create an object for dollars and cents
DecimalFormat formatter = new DecimalFormat (\"#0.00\");
// Get the starting balance.
System.out.print(\"What is your account\'s \" + \"starting balance? \");
balance = keyboard.nextDouble();
// Get the monthly interest rate.
System.out.print(\"What is your an annual interest rate? \");
interestRate = keyboard.nextDouble();
// Create a BankAccount object.
account = new BankAccount(balance, interestRate);
// Get the amount of pay for the month.
System.out.print(\"How much were you paid this month? \");
pay = keyboard.nextDouble();
// Deposit the user\'s pay into the account.
System.out.println(\"We will deposit your pay \" + \"into your account.\");
account.deposit(pay);
System.out.println(\"Your current balance is \" + formatter.format( account.getBalance() ));
// Withdraw some cash from the account.
System.out.print(\"How much would you like \" + \"to withdraw? \");
cashNeeded = keyboard.nextDouble();
account.withdraw(cashNeeded);
// Add the monthly interest to the account.
account.addInterest();
// Display the interest earned and the balance.
System.out.println(\"This month you have earned \" + formatter.format( account.getInterest() ) +
\" in interest.\");
System.out.println(\"Now your balance is \"+ formatter.format( account.getBalance() ) );
}
}
BankAccount.java
public class BankAccount
{
private double balance; // Account balance
private double interestRate; // Interest rate
private double interest; // Interest earned
/**
* The constructor initializes the balance
* and interestRate fields with the values
* passed to startBalance and intRate. The
* interest field is assigned to 0.0.
*/
public BankAccount(double startBalance, double intRate)
{
balance = startBalance;
interestRate = intRate / (12 * 100);
interest = 0.0;
}
/**
* The deposit method adds the parameter
* amount to the balance field.
*/
public void deposit(double amount)
{
balance += amount;
}
/**
* The withdraw method subtracts the
* parameter amount from the balance
* field.
*/
public void withdraw(double amount)
{
balance -= amount;
}
/**
* The addInterest method adds the interest
* for the month to the balance field.
*/
public void addInterest()
{
interest = balance * interestRate;
balance += interest;
}
/**
* The getBalance method returns the
* value in the balance field.
*/
public double getBalance()
{
return balance;
}
/**
* The getIn.
dil. HCl than after it get hydrolysed completely the pH of the solut.pdf
dil. HCl than after it get hydrolysed completely the pH of the solution becomes constant.
From the given salts the solid substance may be Na2SO4 it is a salt which is formed by the
combination of strong acid and strong base.
Na2SO4 + 2 HCl --------> 2 NaCl + H2SO4 the slight increase in the pH of the solution is due
to the ionisation of Na2SO4 once it get ionized completely and their is complete formation of
H2SO4
their will be increase in pH and it remains constant.
Solution
dil. HCl than after it get hydrolysed completely the pH of the solution becomes constant.
From the given salts the solid substance may be Na2SO4 it is a salt which is formed by the
combination of strong acid and strong base.
Na2SO4 + 2 HCl --------> 2 NaCl + H2SO4 the slight increase in the pH of the solution is due
to the ionisation of Na2SO4 once it get ionized completely and their is complete formation of
H2SO4
their will be increase in pH and it remains constant..
I have selected Alibaba stock for analysis.As per the data given i.pdf
I have selected Alibaba stock for analysis.
As per the data given in yahoo finance, it is observed that the company is falling in terms of EPS
from 1.43 in 2016 to 0.69 in the first quarter of 2017. However, since then it has been reviving.
The analysts section shows a buy for this stock and it projects a growth of 50.7% in the next
quarter. The Company has a PE ratio of 51.87 and a market cap of $493.204 billion. The ROE is
17.81% and the ROA is 7.87% which are impressive numbers. Hence this seems to be a good
investment considering the past financials and growth prospects. The Company maintains a
healthy current ratio of 1.71 which shows that it has enough liquidity.
Solution
I have selected Alibaba stock for analysis.
As per the data given in yahoo finance, it is observed that the company is falling in terms of EPS
from 1.43 in 2016 to 0.69 in the first quarter of 2017. However, since then it has been reviving.
The analysts section shows a buy for this stock and it projects a growth of 50.7% in the next
quarter. The Company has a PE ratio of 51.87 and a market cap of $493.204 billion. The ROE is
17.81% and the ROA is 7.87% which are impressive numbers. Hence this seems to be a good
investment considering the past financials and growth prospects. The Company maintains a
healthy current ratio of 1.71 which shows that it has enough liquidity..
FalseHuman cells do not have separate genes for each antibody Mole.pdf
False
Human cells do not have separate genes for each antibody Molecules. human cells so not have
enough DNA to have a seperate genes for each antibody molecules. different DNA segment for
heavy and light chains for both constant and variable regions of DNA are rearranged in different
ways and producing different antibodies. usually the DNA have segments, for light chains the
DNA have V (V1,V2,V3,.......) and J segment (J1,J2,J5) in the variable region and Constant
region segment. where as the for heavy chains made from V,J and D segments in the variable
region and one of the 5 different constant region sites (Alpha,Gamma,Delta,Epicilon and Mu). in
the process of maturation the lymophocytes divides and genes undergo rearrangement.the DNA
sequence are assemebled the variable region is made by random selection of V and J segments in
the light chain and V,D and J gene segments in the heavy chains.and the constant region is made
by C segment present on the DNA for light chains and for the heavy chains the constant region is
made from one of the 5 different constant region sites on DNA.
Solution
False
Human cells do not have separate genes for each antibody Molecules. human cells so not have
enough DNA to have a seperate genes for each antibody molecules. different DNA segment for
heavy and light chains for both constant and variable regions of DNA are rearranged in different
ways and producing different antibodies. usually the DNA have segments, for light chains the
DNA have V (V1,V2,V3,.......) and J segment (J1,J2,J5) in the variable region and Constant
region segment. where as the for heavy chains made from V,J and D segments in the variable
region and one of the 5 different constant region sites (Alpha,Gamma,Delta,Epicilon and Mu). in
the process of maturation the lymophocytes divides and genes undergo rearrangement.the DNA
sequence are assemebled the variable region is made by random selection of V and J segments in
the light chain and V,D and J gene segments in the heavy chains.and the constant region is made
by C segment present on the DNA for light chains and for the heavy chains the constant region is
made from one of the 5 different constant region sites on DNA..
Cybercrime simply means crime that happens in cyberspace ie the wor.pdf
Cybercrime simply means crime that happens in cyberspace i:e the world of computer and the
Internet. In recent times cybercrime has increased exponentially and the reason being that the
society is becoming an information society, full of information exchange and all sorts of hacking
ways are easily available and its not easy be caught. In cybercrime money is a major motivator
for many cyber criminals, especially when hackers are hidden behind a network and have very
les chance of getting caught. Other motivations can be personal motivation, ideological
motivation etc.
Solution
Cybercrime simply means crime that happens in cyberspace i:e the world of computer and the
Internet. In recent times cybercrime has increased exponentially and the reason being that the
society is becoming an information society, full of information exchange and all sorts of hacking
ways are easily available and its not easy be caught. In cybercrime money is a major motivator
for many cyber criminals, especially when hackers are hidden behind a network and have very
les chance of getting caught. Other motivations can be personal motivation, ideological
motivation etc..
Unit 8 - Information and Communication Technology (Paper I).pdf
This slides describes the basic concepts of ICT, basics of Email, Emerging Technology and Digital Initiatives in Education. This presentations aligns with the UGC Paper I syllabus.
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Z = (x-mean)sd = (82-70)8 = 1.50SolutionZ = (x-mean)sd = (8.pdf
Z = (x-mean)/sd = (82-70)/8 = 1.50
Solution
Z = (x-mean)/sd = (82-70)/8 = 1.50.
First remember that non polar compounds are solub.pdf
First remember that non polar compounds are soluble in non polar solvents (like
benzene in acetone) and polar compounds are soluble in polar solvents (like NaCl in H2O) Now
if you consider solubility in water, all polar compounds are soluble and the structure which can
make hydrogen bonding with water is also soluble like methanol which can form hydrogen
bonding with water.. First look at the structure to identify what kind of bonds are existing, if you
see any ionic bond it will be soluble in water. inorganic base is something like NaOH which has
the basic unit OH- which can easily take a proton from an organic acid and from a bond and
hence it will be soluble. organic base is soluble when organic acid is present because acid and
base has the larger tendency to get interacted and form a complex.
Solution
First remember that non polar compounds are soluble in non polar solvents (like
benzene in acetone) and polar compounds are soluble in polar solvents (like NaCl in H2O) Now
if you consider solubility in water, all polar compounds are soluble and the structure which can
make hydrogen bonding with water is also soluble like methanol which can form hydrogen
bonding with water.. First look at the structure to identify what kind of bonds are existing, if you
see any ionic bond it will be soluble in water. inorganic base is something like NaOH which has
the basic unit OH- which can easily take a proton from an organic acid and from a bond and
hence it will be soluble. organic base is soluble when organic acid is present because acid and
base has the larger tendency to get interacted and form a complex..
There are many types of malwares like Trojans, viruses, worms, rootk.pdf
There are many types of malwares like Trojans, viruses, worms, rootkits, and many more
We will here discuss about viruses and worms
Viruses are the programs that gets themselves replicated itself and gets into other files and
programs and destroys data or makes the file damaged so that the file becomes corrupt or
damaged. Whenever the user tries to open the infected files virus gets spread in other files.
Worms are self-activated programs. They spreads over the networks and infect the other
computers in the network without user’s knowledge and permission and sends the data of one
system to others.
Solution
There are many types of malwares like Trojans, viruses, worms, rootkits, and many more
We will here discuss about viruses and worms
Viruses are the programs that gets themselves replicated itself and gets into other files and
programs and destroys data or makes the file damaged so that the file becomes corrupt or
damaged. Whenever the user tries to open the infected files virus gets spread in other files.
Worms are self-activated programs. They spreads over the networks and infect the other
computers in the network without user’s knowledge and permission and sends the data of one
system to others..
The standard form of a complex number is a real number plusminus an.pdf
The standard form of a complex number is a real number plus/minus an imaginary number.
Divide each term in the numerator by the denominator.
(10 + i) / 14i =
(5/7)i + (1/14) = (1/14) (5/7)i
1/14 is the real part.
(5/7)i is the imaginary part.
Solution
The standard form of a complex number is a real number plus/minus an imaginary number.
Divide each term in the numerator by the denominator.
(10 + i) / 14i =
(5/7)i + (1/14) = (1/14) (5/7)i
1/14 is the real part.
(5/7)i is the imaginary part..
Question) one or more attributes that comprise a primary key in a ro.pdf
Question) one or more attributes that comprise a primary key in a row in a relational table
Answer ) Key attribute
Entity Integrity
Foreign Key
Composite key
Key Attribute : represents primary key. (main characteristics of an entity). It is an attribute, that
has distinct value for each entity/element in an entity set. For example, Roll number in a Student
Entity Type.
Solution
Question) one or more attributes that comprise a primary key in a row in a relational table
Answer ) Key attribute
Entity Integrity
Foreign Key
Composite key
Key Attribute : represents primary key. (main characteristics of an entity). It is an attribute, that
has distinct value for each entity/element in an entity set. For example, Roll number in a Student
Entity Type..
pls provide the dataSolutionpls provide the data.pdf
pls provide the data
Solution
pls provide the data.
Photosynthesis - is the unique process that is limited to plant king.pdf
Photosynthesis - is the unique process that is limited to plant kingdom.Green plants are able to
synthesize carbohydrates in there systems due to the presence of an uinique structure called
chloroplast.
The chloroplasts are present only in plant kingdom which gives them the ability to trap solar
energy convert it into chemical energy along with the synthesis of carbohydrates and evolution
of oxygen, so the process of photosynthesis does not only fix the carbon di oxide but in the
process also give out oxygen.
These chloroplasts are present in diverse groups of plant kingdom and may show structural
differences . Though they exhibit variations in their structure they perform the same function.The
chloroplasts are membrane bound organnels locate din the cytoplasm and are responsible for the
trapping of solar energy and converting it into chemical energy in the form of ATP and
NADPH due to the presence of the pigment chlorophyll and in the process liberate oxygen from
the water molecule through a series of reactions.
The number of chloroplasts per cell vary from one organism to the other they may be varying
from 1 as seen in algae or may be upto 100 per cell as seen in higher plants.the chloroplasts
develop from a pre existing plastids known as the proplastid.whcih can develop into a variety of
plastids like the chloroplast, leucoplast amyloplast etc.
They are considered to have originated from cyanobacteria through endosymbiosis .The
ancestors of chloroplasts are believed to be the cyanobacteria or the blue-green algae .They are
often found as symbionts with a number of other groups of organisms like the
fungi,pteridophytes angiosperms .The oxygen present in the atmosphere is attributed due to the
activity of these cyanobacteria.They do not have a nucleus or any membrane bound organnels .
The photosynthetic apparatus is embedded into folds of the external cell membrane, called
thylakoids and contain a bluish green pigment phycocyanin and chlorophyll a.
The green algae cor the chlorophytes have a definite chloroplast whose shape may vary among
different members it may be cup shaped as seen in simple chlamydomonas , ribbon like as in
spirogyra or disc like as in higher members of the group . The main pigments are chlorophyll a, b
along with carotenoids and xanthophylls and have starch as the storage product.
the members of red algae have additional pigments in there chloroplast like phycobilins and
phycocyanins in addition to chlorophyll and the starch they make is also called as floridean
starch unique to the group.The brown algae differ from the other groups due to the presence of
the pigment fucoxanthin along with chlorophyll a and c which gives them the color.
If we move to higher group of plants like the bryophytes , Pteriodophytes, Gymnosperms and the
Angiosperms the chloroplast represents a well organized double membrane structures with they
thylakoids, grana , stroma , intergaranal lamella , stromal lamella and have chlorophyll as the
main.
Please follow the code and comments for description a)CODE #.pdf
Please follow the code and comments for description :
a)
CODE :
#include // header file
using namespace std;
double factorial(double n); // required method with the double value
int main() // main method
{
int n;
cout << \"Enter a positive integer: \"; // prompt to get the integer value
cin >> n;
cout << \"Factorial of \" << n << \" = \" << factorial(n); // calluing the function
return 0;
}
double factorial(double n)
{
if(n!=1)
return n*factorial(n-1); // returning the result
}
OUTPUT :
Enter a positive integer: 6
Factorial of 6 = 720
b)
CODE :
#include // header file
#include
using namespace std;
int main() // main method
{
int count = 0; // required initialisations
string line;
ifstream file(\"input.txt\"); //Creating input filestream
while (getline(file, line)){ // iterating over the loop to get the data and count
count++;
cout << line << endl; // printing the data
}
cout << \"Numbers of lines in the file : \" << count << endl; // print the count
return 0;
}
input.txt :
Hi
Hello
How are You
Hope Your are Doing Good
See You
Tomorrow
Good Bye
Meet
You
LAter
OUTPUT :
Hi
Hello
How are You
Hope Your are Doing Good
See You
Tomorrow
Good Bye
Meet
You
LAter
Numbers of lines in the file : 10
Hope this is helpful.
Solution
Please follow the code and comments for description :
a)
CODE :
#include // header file
using namespace std;
double factorial(double n); // required method with the double value
int main() // main method
{
int n;
cout << \"Enter a positive integer: \"; // prompt to get the integer value
cin >> n;
cout << \"Factorial of \" << n << \" = \" << factorial(n); // calluing the function
return 0;
}
double factorial(double n)
{
if(n!=1)
return n*factorial(n-1); // returning the result
}
OUTPUT :
Enter a positive integer: 6
Factorial of 6 = 720
b)
CODE :
#include // header file
#include
using namespace std;
int main() // main method
{
int count = 0; // required initialisations
string line;
ifstream file(\"input.txt\"); //Creating input filestream
while (getline(file, line)){ // iterating over the loop to get the data and count
count++;
cout << line << endl; // printing the data
}
cout << \"Numbers of lines in the file : \" << count << endl; // print the count
return 0;
}
input.txt :
Hi
Hello
How are You
Hope Your are Doing Good
See You
Tomorrow
Good Bye
Meet
You
LAter
OUTPUT :
Hi
Hello
How are You
Hope Your are Doing Good
See You
Tomorrow
Good Bye
Meet
You
LAter
Numbers of lines in the file : 10
Hope this is helpful..
Optimized Waterfall processIs a common project methodology and it.pdf
Optimized Waterfall process:
Is a common project methodology and it is a sequential design project method that was originally
consider for software development but is now used for a diversity of project types. It is generally
having 6 phases
1. Necessities
2. Design
3. Execution
4. Verification
5. Deployment
6. Preservation
Payoffs of water fall process:
There are several payoff of water fall process as follows
a). proper for simple or smaller projects
b). Requirements are well understood
c). Easy to understand
d). Easy to manage
e). Clear milestones
f). general documentation
Pitfalls of water fall process:
a). does not allow scope changes.
b). does not allow for requirement changes.
c). No working product until near completion of project.
Solution
Optimized Waterfall process:
Is a common project methodology and it is a sequential design project method that was originally
consider for software development but is now used for a diversity of project types. It is generally
having 6 phases
1. Necessities
2. Design
3. Execution
4. Verification
5. Deployment
6. Preservation
Payoffs of water fall process:
There are several payoff of water fall process as follows
a). proper for simple or smaller projects
b). Requirements are well understood
c). Easy to understand
d). Easy to manage
e). Clear milestones
f). general documentation
Pitfalls of water fall process:
a). does not allow scope changes.
b). does not allow for requirement changes.
c). No working product until near completion of project..
Organism Entameoeba histolyticQ AIt can be analyzed by feces te.pdf
Organism :Entameoeba histolytic
Q A
It can be analyzed by feces tests, however take note of that specific different species are difficult
to recognize by microscopy alone. Trophozoites might be found in a new fecal spread and sores
in a standard feces test. ELISA or RIA can likewise be utilized
Q B
The dynamic (trophozoite) arrange exists just in the host and in crisp free defecation; growths
make due outside the host in water, in soils, and on sustenances, particularly under wet
conditions on the last mentioned.
Q C
Distinctive monophasic media that were created for E. histolytica are the egg yolk imbuement
medium of Balamuth , Jones\' medium , and TYSGM-9 . Of the diverse media created for the
xenic development of E. histolytica, just three media, diphasic Locke-egg, Robinson\'s medium
Q D
anaerobic
QE
Microscopy utilized in an indicative clinical research facility incorporate wet planning, fixation,
and for all time recolored smears for the distinguishing proof of E. histolytica/E. dispar/E.
moshkovskii in excrement. Tiny examination of an immediate saline (wet) mount is an
exceptionally uncaring strategy (<10%) which is performed on a crisp example .The example
ought to be analyzed inside 1 h of accumulation to hunt down motile trophozoites which may
contain RBCs. Be that as it may, in patients who don\'t present with intense looseness of the
bowels, trophozoites won\'t contain RBCs. Patients with asymptomatic carriage by and large
have just growths in the fecal example. In spite of the fact that the focus procedure is useful in
exhibiting sores, the utilization of forever recolored smears (trichrome or press hematoxylin) is
an imperative technique for recuperation and distinguishing proof of Entamoeba species.
Q F Q G
In most by far of cases, disease is asymptomatic and the bearer is uninformed they are tainted.
Be that as it may, in an expected 10% of cases E. histolytica causes ailment. Once the
trophozoites are excysted they colonize the extensive gut, staying on the surface of the bodily
fluid layer and sustaining on microscopic organisms and sustenance particles. Every so often,
and in light of obscure boosts, trophozoites travel through the bodily fluid layer where they
interact with the epithelial cell layer and begin the obsessive procedure. E. histolytica has a lectin
that ties to galactose and N-acetylgalactosamine sugars on the surface of the epithelial cells, The
lectin typically is utilized to tie microscopic organisms for ingestion. The parasite has a few
catalysts, for example, pore shaping proteins, lipases, and cysteine proteases, which are regularly
used to process microbes in nourishment vacuoles yet which can bring about lysis of the
epithelial cells by instigating cell putrefaction and apoptosis when the trophozoite interacts with
them and ties through the lectin. The trophozoites will then ingest these dead cells. This harm to
the epithelial cell layer draws in human resistant cells and these thusly can be lysed by .
It is the main program that implement the min(), max(), floor(), cei.pdf
It is the main program that implement the min(), max(), floor(), ceiling(), select(), rank(),delete(),
deleteMin(), deleteMax(), keys()
import java.util.NoSuchElementException;
public class BST, Value> {
private Node root;
private class Node {
private Key key;
private Value val;
private Node left, right;
private int size;
public Node(Key key, Value val, int size) {
this.key = key;
this.val = val;
this.size = size;
}
}
public BST() {
}
public boolean isEmpty() {
return size() == 0;
}
public int size() {
return size(root);
}
// return number of key-value pairs in BST rooted at x
private int size(Node x) {
if (x == null) return 0;
else return x.size;
}
public boolean contains(Key key) {
if (key == null) throw new NullPointerException(\"argument to contains() is null\");
return get(key) != null;
}
public Value get(Key key) {
return get(root, key);
}
private Value get(Node x, Key key) {
if (x == null) return null;
int cmp = key.compareTo(x.key);
if (cmp < 0) return get(x.left, key);
else if (cmp > 0) return get(x.right, key);
else return x.val;
}
public void put(Key key, Value val) {
if (key == null) throw new NullPointerException(\"first argument to put() is null\");
if (val == null) {
delete(key);
return;
}
root = put(root, key, val);
assert check();
}
private Node put(Node x, Key key, Value val) {
if (x == null) return new Node(key, val, 1);
int cmp = key.compareTo(x.key);
if (cmp < 0) x.left = put(x.left, key, val);
else if (cmp > 0) x.right = put(x.right, key, val);
else x.val = val;
x.size = 1 + size(x.left) + size(x.right);
return x;
}
public void deleteMax() {
if (isEmpty()) throw new NoSuchElementException(\"Symbol table underflow\");
root = deleteMax(root);
assert check();
}
private Node deleteMax(Node x) {
if (x.right == null) return x.left;
x.right = deleteMax(x.right);
x.size = size(x.left) + size(x.right) + 1;
return x;
}
public void delete(Key key) {
if (key == null) throw new NullPointerException(\"argument to delete() is null\");
root = delete(root, key);
assert check();
}
private Node delete(Node x, Key key) {
if (x == null) return null;
int cmp = key.compareTo(x.key);
if (cmp < 0) x.left = delete(x.left, key);
else if (cmp > 0) x.right = delete(x.right, key);
else {
if (x.right == null) return x.left;
if (x.left == null) return x.right;
Node t = x;
x = min(t.right);
x.right = deleteMin(t.right);
x.left = t.left;
}
x.size = size(x.left) + size(x.right) + 1;
return x;
}
public Key min() {
if (isEmpty()) throw new NoSuchElementException(\"called min() with empty symbol
table\");
return min(root).key;
}
private Node min(Node x) {
if (x.left == null) return x;
else return min(x.left);
}
public Key max() {
if (isEmpty()) throw new NoSuchElementException(\"called max() with empty symbol
table\");
return max(root).key;
}
private Node max(Node x) {
if (x.right == null) return x;
else return max(x.right);
}
public Key floor(Key key) {
if (key == null) throw new NullPointerException(\"argument to floor() is null\");
if (isEmpty()) throw ne.
An overlay network may be a electronic network thats designed on h.pdf
An overlay network may be a electronic network that\'s designed on high of another network.
Nodes within the overlay network will be thought of as being connected by virtual or logical
links, every of that corresponds to a path, maybe through several physical links, within the
underlying network. for instance, distributed systems like peer-to-peer networks and client-server
applications ar overlay networks as a result of their nodes run on high of the net. the net was
originally designed as AN overlay upon the phonephone network, whereas these days (through
the appearance of VoIP), the phonephone network is {increasingly|progressively|more ANd
more} turning into an overlay network designed on high of the net.
Overlay networks ar utilized in telecommunication due to the supply of digital circuit change
instrumentality and glass fibre.[1] Telecommunication transport networks ANd informatics
networks (which combined form up the broader Internet) ar all overlaid with a minimum of an
glass fibre layer, a transport layer ANd an informatics OR gate change layers (in the case of the
PSTN).
Enterprise non-public networks were initial overlaid on telecommunication networks like frame
relay and Asynchronous Transfer Mode packet change infrastructures however migration from
these (now legacy) infrastructures to informatics based mostly MPLS networks and virtual non-
public networks started (2001~2002).
From a physical posture overlay networks ar quite advanced (see Figure 1) as they mix varied
logical layers that ar operated and designed by varied entities (businesses, universities,
government etc.) however they permit separation of considerations that over time allowable the
buildup of a broad set of services that would not are planned by one telecommunication operator
(ranging from broadband net access, voice informatics or IPTV, competitive medium operators
etc.).[2]
13
down vote
One reason we have a tendency to clock flip flops so there is not any chaos once the outputs of
flip flops area unit fed through some logic functions and back to their own inputs.
If a flip-flop\'s output is employed to calculate its input, it behooves North American nation to
possess orderly behavior: to stop the flip-flop\'s state from dynamical till the output (and
therefore the input) is stable.
This duration permits North American nation to create computers, that area unit state machines:
they need a current state, and calculate their next state supported the present state and a few
inputs.
For example, suppose we would like to create a machine that \"computes\" AN incrementing
four bit count from 0000 to 1111, and so wraps around to 0000 and keeps going. we are able to
do that by employing a four bit register (which may be a bank of 4 D flip-flops). The output of
the register is place through a combinatorial logic perform that adds one (a four bit adder) to
supply the incremented worth. This worth is then merely fed back to the register. Now, whenever
the clock edge arr.
Alkylating agents, or their reactive intermediates, form covalent bo.pdf
Alkylating agents, or their reactive intermediates, form covalent bonds with deoxyribonucleic
acid (DNA), ribonucleic acid (RNA), and protein to form an adduct in which a methyl or ethyl
group is added. DNA adducts are believed to play a major role in mutagenesis and clastogenesis,
as well as in carcinogenesis. DNA adducts are formed at a number of reactive sites on nucleotide
bases. Common locations include the N-7 and O-6 of guanine which are shown to be associated
with mutagenesis and carcinogenesis. In general, it seems that alkylating agents that are not
particularly ionic in nature are localized more on the ring nitrogen atoms, whereas those that
have greater ionic character show greater preferences for reaction at the oxygen atoms in DNA
(crios).
folate antagonists: effect the folate metabolism, which is the target of two major drug groups:
folate antagonists (for example, methotrexate) and thymidylate synthase inhibitors (for example,
5-fluorouracil) (Robien, 2005) . Since Folic acid\'s primary function in the body is as a cofactor
to various methyltransferases involved in serine, methionine, thymidine and purine biosynthesis.
Consequently, antifolates inhibit cell division, DNA/RNA synthesis and repair and protein
synthesis, (NCI)
Solution
Alkylating agents, or their reactive intermediates, form covalent bonds with deoxyribonucleic
acid (DNA), ribonucleic acid (RNA), and protein to form an adduct in which a methyl or ethyl
group is added. DNA adducts are believed to play a major role in mutagenesis and clastogenesis,
as well as in carcinogenesis. DNA adducts are formed at a number of reactive sites on nucleotide
bases. Common locations include the N-7 and O-6 of guanine which are shown to be associated
with mutagenesis and carcinogenesis. In general, it seems that alkylating agents that are not
particularly ionic in nature are localized more on the ring nitrogen atoms, whereas those that
have greater ionic character show greater preferences for reaction at the oxygen atoms in DNA
(crios).
folate antagonists: effect the folate metabolism, which is the target of two major drug groups:
folate antagonists (for example, methotrexate) and thymidylate synthase inhibitors (for example,
5-fluorouracil) (Robien, 2005) . Since Folic acid\'s primary function in the body is as a cofactor
to various methyltransferases involved in serine, methionine, thymidine and purine biosynthesis.
Consequently, antifolates inhibit cell division, DNA/RNA synthesis and repair and protein
synthesis, (NCI).
Hi,I have updated the code as per your requirement. Highlighted th.pdf
Hi,
I have updated the code as per your requirement. Highlighted the code changes below.
Program2.java
import java.util.Scanner; // Needed for the Scanner class
import java.text.DecimalFormat; // Needed for 2 decimal place amounts
public class Program2
{
public static void main(String[] args)
{
BankAccount account; // To reference a BankAccount object
double balance, // The account\'s starting balance
interestRate, // The annual interest rate
pay, // The user\'s pay
cashNeeded; // The amount of cash to withdraw
// Create a Scanner object for keyboard input.
Scanner keyboard = new Scanner(System.in);
// Create an object for dollars and cents
DecimalFormat formatter = new DecimalFormat (\"#0.00\");
// Get the starting balance.
System.out.print(\"What is your account\'s \" + \"starting balance? \");
balance = keyboard.nextDouble();
// Get the monthly interest rate.
System.out.print(\"What is your an annual interest rate? \");
interestRate = keyboard.nextDouble();
// Create a BankAccount object.
account = new BankAccount(balance, interestRate);
// Get the amount of pay for the month.
System.out.print(\"How much were you paid this month? \");
pay = keyboard.nextDouble();
// Deposit the user\'s pay into the account.
System.out.println(\"We will deposit your pay \" + \"into your account.\");
account.deposit(pay);
System.out.println(\"Your current balance is \" + formatter.format( account.getBalance() ));
// Withdraw some cash from the account.
System.out.print(\"How much would you like \" + \"to withdraw? \");
cashNeeded = keyboard.nextDouble();
account.withdraw(cashNeeded);
// Add the monthly interest to the account.
account.addInterest();
// Display the interest earned and the balance.
System.out.println(\"This month you have earned \" + formatter.format( account.getInterest() ) +
\" in interest.\");
System.out.println(\"Now your balance is \"+ formatter.format( account.getBalance() ) );
}
}
BankAccount.java
public class BankAccount
{
private double balance; // Account balance
private double interestRate; // Interest rate
private double interest; // Interest earned
/**
* The constructor initializes the balance
* and interestRate fields with the values
* passed to startBalance and intRate. The
* interest field is assigned to 0.0.
*/
public BankAccount(double startBalance, double intRate)
{
balance = startBalance;
interestRate = intRate / (12 * 100);
interest = 0.0;
}
/**
* The deposit method adds the parameter
* amount to the balance field.
*/
public void deposit(double amount)
{
balance += amount;
}
/**
* The withdraw method subtracts the
* parameter amount from the balance
* field.
*/
public void withdraw(double amount)
{
balance -= amount;
}
/**
* The addInterest method adds the interest
* for the month to the balance field.
*/
public void addInterest()
{
interest = balance * interestRate;
balance += interest;
}
/**
* The getBalance method returns the
* value in the balance field.
*/
public double getBalance()
{
return balance;
}
/**
* The getIn.
dil. HCl than after it get hydrolysed completely the pH of the solut.pdf
dil. HCl than after it get hydrolysed completely the pH of the solution becomes constant.
From the given salts the solid substance may be Na2SO4 it is a salt which is formed by the
combination of strong acid and strong base.
Na2SO4 + 2 HCl --------> 2 NaCl + H2SO4 the slight increase in the pH of the solution is due
to the ionisation of Na2SO4 once it get ionized completely and their is complete formation of
H2SO4
their will be increase in pH and it remains constant.
Solution
dil. HCl than after it get hydrolysed completely the pH of the solution becomes constant.
From the given salts the solid substance may be Na2SO4 it is a salt which is formed by the
combination of strong acid and strong base.
Na2SO4 + 2 HCl --------> 2 NaCl + H2SO4 the slight increase in the pH of the solution is due
to the ionisation of Na2SO4 once it get ionized completely and their is complete formation of
H2SO4
their will be increase in pH and it remains constant..
I have selected Alibaba stock for analysis.As per the data given i.pdf
I have selected Alibaba stock for analysis.
As per the data given in yahoo finance, it is observed that the company is falling in terms of EPS
from 1.43 in 2016 to 0.69 in the first quarter of 2017. However, since then it has been reviving.
The analysts section shows a buy for this stock and it projects a growth of 50.7% in the next
quarter. The Company has a PE ratio of 51.87 and a market cap of $493.204 billion. The ROE is
17.81% and the ROA is 7.87% which are impressive numbers. Hence this seems to be a good
investment considering the past financials and growth prospects. The Company maintains a
healthy current ratio of 1.71 which shows that it has enough liquidity.
Solution
I have selected Alibaba stock for analysis.
As per the data given in yahoo finance, it is observed that the company is falling in terms of EPS
from 1.43 in 2016 to 0.69 in the first quarter of 2017. However, since then it has been reviving.
The analysts section shows a buy for this stock and it projects a growth of 50.7% in the next
quarter. The Company has a PE ratio of 51.87 and a market cap of $493.204 billion. The ROE is
17.81% and the ROA is 7.87% which are impressive numbers. Hence this seems to be a good
investment considering the past financials and growth prospects. The Company maintains a
healthy current ratio of 1.71 which shows that it has enough liquidity..
FalseHuman cells do not have separate genes for each antibody Mole.pdf
False
Human cells do not have separate genes for each antibody Molecules. human cells so not have
enough DNA to have a seperate genes for each antibody molecules. different DNA segment for
heavy and light chains for both constant and variable regions of DNA are rearranged in different
ways and producing different antibodies. usually the DNA have segments, for light chains the
DNA have V (V1,V2,V3,.......) and J segment (J1,J2,J5) in the variable region and Constant
region segment. where as the for heavy chains made from V,J and D segments in the variable
region and one of the 5 different constant region sites (Alpha,Gamma,Delta,Epicilon and Mu). in
the process of maturation the lymophocytes divides and genes undergo rearrangement.the DNA
sequence are assemebled the variable region is made by random selection of V and J segments in
the light chain and V,D and J gene segments in the heavy chains.and the constant region is made
by C segment present on the DNA for light chains and for the heavy chains the constant region is
made from one of the 5 different constant region sites on DNA.
Solution
False
Human cells do not have separate genes for each antibody Molecules. human cells so not have
enough DNA to have a seperate genes for each antibody molecules. different DNA segment for
heavy and light chains for both constant and variable regions of DNA are rearranged in different
ways and producing different antibodies. usually the DNA have segments, for light chains the
DNA have V (V1,V2,V3,.......) and J segment (J1,J2,J5) in the variable region and Constant
region segment. where as the for heavy chains made from V,J and D segments in the variable
region and one of the 5 different constant region sites (Alpha,Gamma,Delta,Epicilon and Mu). in
the process of maturation the lymophocytes divides and genes undergo rearrangement.the DNA
sequence are assemebled the variable region is made by random selection of V and J segments in
the light chain and V,D and J gene segments in the heavy chains.and the constant region is made
by C segment present on the DNA for light chains and for the heavy chains the constant region is
made from one of the 5 different constant region sites on DNA..
Cybercrime simply means crime that happens in cyberspace ie the wor.pdf
Cybercrime simply means crime that happens in cyberspace i:e the world of computer and the
Internet. In recent times cybercrime has increased exponentially and the reason being that the
society is becoming an information society, full of information exchange and all sorts of hacking
ways are easily available and its not easy be caught. In cybercrime money is a major motivator
for many cyber criminals, especially when hackers are hidden behind a network and have very
les chance of getting caught. Other motivations can be personal motivation, ideological
motivation etc.
Solution
Cybercrime simply means crime that happens in cyberspace i:e the world of computer and the
Internet. In recent times cybercrime has increased exponentially and the reason being that the
society is becoming an information society, full of information exchange and all sorts of hacking
ways are easily available and its not easy be caught. In cybercrime money is a major motivator
for many cyber criminals, especially when hackers are hidden behind a network and have very
les chance of getting caught. Other motivations can be personal motivation, ideological
motivation etc..
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Z = (x-mean)sd = (82-70)8 = 1.50SolutionZ = (x-mean)sd = (8.pdf
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Hi,I have updated the code as per your requirement. Highlighted th.pdf
Hi,I have updated the code as per your requirement. Highlighted th.pdf
dil. HCl than after it get hydrolysed completely the pH of the solut.pdf
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FalseHuman cells do not have separate genes for each antibody Mole.pdf
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