Department	
  of	
  Chemistry	
  
PbI2(s)  Pb(aq)
2+
+ 2I(aq)
−
K = [Pb2+
][I−
]2
ΔGo
= 46.1 kJ/mol ⇒ [Pb2+
] = 1.14 ×10−3
M
measured: [Pb2+
] = 1.37 ×10−3
M
K = e−ΔGo
/RT
Explain	
  the	
  difference	
  
Department	
  of	
  Chemistry	
  
solute(water)  solute(octanol)
log(Pwo)	
  =	
  3.37	
  
ΔGo
= −19.2 kJ/mol
What	
  is	
  the	
  most	
  probable	
  sign	
  of	
  ΔSo	
  and	
  why?	
  
Department	
  of	
  Chemistry	
  
CH3COOH  CH3COO−
+ H+
pKa = −log Ka( )
Ka =
[CH3COO−
][H+
]
[CH3COOH]
the	
  pKa	
  in	
  water	
  is	
  4.76.	
  	
  Is	
  the	
  pKa	
  higher	
  or	
  lower	
  DMSO	
  and	
  why?	
  
S	
  
ε	
  =	
  47	
  
Department	
  of	
  Chemistry	
  
P + L  P ⋅L
Ligand	
  binding	
  to	
  the	
  enzyme	
  carbonic	
  anhydrase	
  (at	
  25	
  oC)	
  
ΔSo	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  9.7	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  	
  67.4	
  J/molK	
  
DOI:	
  10.1002/anie.201301813	
  
Explain	
  the	
  difference	
  in	
  ΔSo	
  	
  
Department	
  of	
  Chemistry	
  
Explain	
  why	
  ΔSo	
  is	
  posiUve	
  
hWp://youtu.be/zKNmBjqGijI	
  
ΔSo
= 25.8 J/molK
at 25 o
C
(Video	
  of	
  benzamidine	
  
binding	
  to	
  trypsin)	
  

Short answer questions on thermodynamics

  • 1.
    Department  of  Chemistry   PbI2(s)  Pb(aq) 2+ + 2I(aq) − K = [Pb2+ ][I− ]2 ΔGo = 46.1 kJ/mol ⇒ [Pb2+ ] = 1.14 ×10−3 M measured: [Pb2+ ] = 1.37 ×10−3 M K = e−ΔGo /RT Explain  the  difference  
  • 2.
    Department  of  Chemistry   solute(water)  solute(octanol) log(Pwo)  =  3.37   ΔGo = −19.2 kJ/mol What  is  the  most  probable  sign  of  ΔSo  and  why?  
  • 3.
    Department  of  Chemistry   CH3COOH  CH3COO− + H+ pKa = −log Ka( ) Ka = [CH3COO− ][H+ ] [CH3COOH] the  pKa  in  water  is  4.76.    Is  the  pKa  higher  or  lower  DMSO  and  why?   S   ε  =  47  
  • 4.
    Department  of  Chemistry   P + L  P ⋅L Ligand  binding  to  the  enzyme  carbonic  anhydrase  (at  25  oC)   ΔSo                                        9.7                                                                    67.4  J/molK   DOI:  10.1002/anie.201301813   Explain  the  difference  in  ΔSo    
  • 5.
    Department  of  Chemistry   Explain  why  ΔSo  is  posiUve   hWp://youtu.be/zKNmBjqGijI   ΔSo = 25.8 J/molK at 25 o C (Video  of  benzamidine   binding  to  trypsin)