(shady) conditions will most likely have a-fewer chloroplasts than sun.docx
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(shady) conditions will most likely have a.fewer chloroplasts than sun-loving plant leaves b.more chloroplasts than sun-loving plant leaves c.the same number of chloroplasts as sun-loving plant leaves d.no chloroplasts 2- A guard cell is a.part of the leaf's protection against animals b.a protective part of the seed coat c. part of a structure controlling the stomata d.none of the above 3- A leaf that is not divided into leaflets is termed aa.simple leaf c.compound leaf b.palmate leaf d.pinnate leaf 4- The primary function of a leaf is to a.engage in photosynthesis and produce carbohydrates b.catch water from rain c.protect the plant from drying out by providing shade d.produce seeds for the next generation of plants 5- An internode is the a.space between two successive nodes on the same stem b.dormant meristematic tissue at the base of a leaf c.vascular tissue that connects a lateral node to a leaf d.structure that supports the leaf node 6- The attachment site of a leaf to a stem is called the a.petiole c.node b.axillary bud d.blade 7- Given the diagram above, the letter O represents a ( n ) a.node c.internode b.axillary bud d.shoot 8- The vein of a leaf is a.support tissue c.epidermal tissue b.vascular tissue d.both a and b .
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Of the three morphological types of leaves, how would you classify th.pdf
Of the three morphological types of leaves, how would you classify the pine leaf? Explain. The
tiny plants that form along the edges of leaves of plants such as Kalanchoe are genetically
identical to the parent. Why? What is the significance of having mom stomata on the lower side
of a leaf than on the upper side in dicots? What is/are the advantage(s) of having a palisade layer
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the leaf takes place in the spongy parenchyma. The protective layer of the abscission zone
becomes the leaf scar. Cactus spines form from modified stems.
Solution
4.Pines belong to the order Pinales, family Pinaceae and the genus pinus. Usually they have 4
types of leaves. Siblings will have 4 to 20 whorl of cotyledons, the anger plants develop small
leaves which are long single and arranged spirally on the shoot. Later after 6 months they grow
into scaly leaves vichare arranged like Juvenile leaves they are usually non photosynthetic and
brown in colour the adult leaves or needles or green and are arranged in bundles. Classification
of pines is based on the characters of leaf ,seed and cone. Sub genus strobus and Ducampopinus
both contain one fibro vascular bundles per leaf where as the sub genus Pinus contains two
fibrovascular bundles per leaf.
5. Basically kalanchoe plant is an example of asexual reproduction. In these plants the new ones
developed vegetatively known as bulbils in phylloclade margins whivh eventually drop off and
developed roots in the soil. As a result the newly developed plans are identical to mother plant
genetically.
6. The arrangement of leaves is the reason behind the presence of most tomato on the lower
epidermis in dicotyledons as the leaves are directly exposed to sunlight you to the horizontal
arrangement you are stomata present on the upper epidermis to prevent excess water loss.
7. The layer just below the upper epidermis is called palisade layer chloroplast are present in this
layer so this layer is mainly responsible for carrying out photosynthesis. As the light energy is
received mostly by the upper part of leaf the pslisade tissue is present in upper surface of dicot
leaves.
8. Basic structural differences between C3 and C4 plant leaves:
C3 plants :the leaves do not possess kranz anatomy, chloroplast have only one type, mesophyll
cells carry out photosynthesis, photosynthesis can be performed only when the stomata are open.
C3 plants considered less efficient in photosynthesis. the bundle sheath cells usually do not
contain chloroplast.
C4 plants :the leaves have kranzs anatomy ,chloroplasts are of dimorphic ,their bundle sheaths
contain prominent chloroplasts, mesophyll cells can do initial fixation, they can perform
photosynthesis even when the s.
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Of the three morphological types of leaves, how would you classify th.pdf
Of the three morphological types of leaves, how would you classify the pine leaf? Explain. The
tiny plants that form along the edges of leaves of plants such as Kalanchoe are genetically
identical to the parent. Why? What is the significance of having mom stomata on the lower side
of a leaf than on the upper side in dicots? What is/are the advantage(s) of having a palisade layer
on the upper surface of dicot leaves? Discuss the basic structural differences between the leaves
of C_3 and C_4 plants. Determine if each of the following statements is true or false. In the
leaves of dicotyledons, the stomata are arranged in parallel rows. Most of the photosynthesis of
the leaf takes place in the spongy parenchyma. The protective layer of the abscission zone
becomes the leaf scar. Cactus spines form from modified stems.
Solution
4.Pines belong to the order Pinales, family Pinaceae and the genus pinus. Usually they have 4
types of leaves. Siblings will have 4 to 20 whorl of cotyledons, the anger plants develop small
leaves which are long single and arranged spirally on the shoot. Later after 6 months they grow
into scaly leaves vichare arranged like Juvenile leaves they are usually non photosynthetic and
brown in colour the adult leaves or needles or green and are arranged in bundles. Classification
of pines is based on the characters of leaf ,seed and cone. Sub genus strobus and Ducampopinus
both contain one fibro vascular bundles per leaf where as the sub genus Pinus contains two
fibrovascular bundles per leaf.
5. Basically kalanchoe plant is an example of asexual reproduction. In these plants the new ones
developed vegetatively known as bulbils in phylloclade margins whivh eventually drop off and
developed roots in the soil. As a result the newly developed plans are identical to mother plant
genetically.
6. The arrangement of leaves is the reason behind the presence of most tomato on the lower
epidermis in dicotyledons as the leaves are directly exposed to sunlight you to the horizontal
arrangement you are stomata present on the upper epidermis to prevent excess water loss.
7. The layer just below the upper epidermis is called palisade layer chloroplast are present in this
layer so this layer is mainly responsible for carrying out photosynthesis. As the light energy is
received mostly by the upper part of leaf the pslisade tissue is present in upper surface of dicot
leaves.
8. Basic structural differences between C3 and C4 plant leaves:
C3 plants :the leaves do not possess kranz anatomy, chloroplast have only one type, mesophyll
cells carry out photosynthesis, photosynthesis can be performed only when the stomata are open.
C3 plants considered less efficient in photosynthesis. the bundle sheath cells usually do not
contain chloroplast.
C4 plants :the leaves have kranzs anatomy ,chloroplasts are of dimorphic ,their bundle sheaths
contain prominent chloroplasts, mesophyll cells can do initial fixation, they can perform
photosynthesis even when the s.
Match the following term to its correct definitionpalisade parench.pdf
Match the following term to its correct definition
palisade parenchyma
bundle sheath
leaf trace
petiole
spongy parenchyma
leaf
loosely packed cells on the underside of a leaf with large intercellular spaces for gas exchange
a layer of cells surrounding the vascular tissue that are responsible for both nutrient loading and
providing structure
a structure that subtends an axillary bud
columnar, closely-packed chlorenchyma cells on the upper surface of the leaf; primary
photosynthetic tissue of most plants.
a stalk
the point at which stem vascular bundles branch before entering the leaf - A. B. C.
D. E. F.
palisade parenchyma - A. B. C. D. E. F.
bundle sheath - A. B. C. D. E. F.
leaf trace - A. B. C. D. E. F.
petiole - A. B. C. D. E. F.
spongy parenchyma - A. B. C. D. E. F.
leafA.
loosely packed cells on the underside of a leaf with large intercellular spaces for gas exchangeB.
a layer of cells surrounding the vascular tissue that are responsible for both nutrient loading and
providing structureC.
a structure that subtends an axillary budD.
columnar, closely-packed chlorenchyma cells on the upper surface of the leaf; primary
photosynthetic tissue of most plants.E.
a stalkF.
the point at which stem vascular bundles branch before entering the leaf
Solution
Answer:
1. Palisade parenchyma----D. columnar, closely-packed chlorenchyma cells on the upper surface
of the leaf; primary photosynthetic tissue of most plants.
2. bundle sheath---B. a layer of cells surrounding the vascular tissue that are responsible for both
nutrient loading and providing structure
3. Leaf trace----F. the point at which stem vascular bundles branch before entering the leaf
4. Petiole---E. a stalk
5. spongy parenchyma----A. loosely packed cells on the underside of a leaf with large
intercellular spaces for gas exchange
6. leaf---C. a structure that subtends an axillary bud.
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Similar to (shady) conditions will most likely have a-fewer chloroplasts than sun.docx
Match the following term to its correct definitionpalisade parench.pdf
Match the following term to its correct definition
palisade parenchyma
bundle sheath
leaf trace
petiole
spongy parenchyma
leaf
loosely packed cells on the underside of a leaf with large intercellular spaces for gas exchange
a layer of cells surrounding the vascular tissue that are responsible for both nutrient loading and
providing structure
a structure that subtends an axillary bud
columnar, closely-packed chlorenchyma cells on the upper surface of the leaf; primary
photosynthetic tissue of most plants.
a stalk
the point at which stem vascular bundles branch before entering the leaf - A. B. C.
D. E. F.
palisade parenchyma - A. B. C. D. E. F.
bundle sheath - A. B. C. D. E. F.
leaf trace - A. B. C. D. E. F.
petiole - A. B. C. D. E. F.
spongy parenchyma - A. B. C. D. E. F.
leafA.
loosely packed cells on the underside of a leaf with large intercellular spaces for gas exchangeB.
a layer of cells surrounding the vascular tissue that are responsible for both nutrient loading and
providing structureC.
a structure that subtends an axillary budD.
columnar, closely-packed chlorenchyma cells on the upper surface of the leaf; primary
photosynthetic tissue of most plants.E.
a stalkF.
the point at which stem vascular bundles branch before entering the leaf
Solution
Answer:
1. Palisade parenchyma----D. columnar, closely-packed chlorenchyma cells on the upper surface
of the leaf; primary photosynthetic tissue of most plants.
2. bundle sheath---B. a layer of cells surrounding the vascular tissue that are responsible for both
nutrient loading and providing structure
3. Leaf trace----F. the point at which stem vascular bundles branch before entering the leaf
4. Petiole---E. a stalk
5. spongy parenchyma----A. loosely packed cells on the underside of a leaf with large
intercellular spaces for gas exchange
6. leaf---C. a structure that subtends an axillary bud.
Similar to (shady) conditions will most likely have a-fewer chloroplasts than sun.docx (20)
Match the following term to its correct definitionpalisade parench.pdf
Match the following term to its correct definitionpalisade parench.pdf
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[
{
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(i) Werck the icon to vere the trpssictons) More info Requirements 1-.docx
(i) Werck the icon to vere the trpssictons) More info Requirements 1. Joumake thin trangackons 2. Cwcinte the balince in Retaned Eamingen en Decutber 31,2027 Asturhe the balerio on dantary 1, 2027 ans f 5 Dod atid red liccene les tho yoar was t44s 000 3. Fiepare the stocktoldes' equity secton of the hadince shent as of December 31, 202 t flefe was to prefored alock nsepid pror to the 2007 tiansptions. Jan. 1. Lssued 70,000 stares of $10 par vatue common stock for a total of $1 , 050 , 000 . Dec. 31: Paid the cash dividends Dec 31. Distributed the stock dividend Requirement 2, Cakulate the balance in Retained Earnings on December 31, 2027. Assume the bakance on danuary 1,2027 was $5 , 000 and net income for tho yoar was $445 , 000 Complote the table below to calculate the balance in Rotained Earnings on December 31, 2027. Bevicre the iournal entyes from fequicencent i.
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(a) The vector xRN has L different entries- For example- L-4 for x--3-.docx
(a) The vector x R N has L different entries. For example, L = 4 for x = [ 3 , 4 , 4 , 5 , 3 , 1 , 5 , 3 ] . One can express x as x = S u , where u R L satisfies ( u ) i < ( u ) j if i < j and S is a matrix that contains only zeros and ones. Write the function repeated_entries, which takes x as input and returns S and u .
.
#include -iostream- #include -vector- #include -Date-h- #include -Pers.docx
#include <iostream>
#include <vector>
#include "Date.h"
#include "Person.h"
#include "DateException.h"
#include "PersonExceptions.h"
int main() {
std::string firstName;
std::string lastName;
int birthMonth;
int birthDay;
int birthYear;
float height;
float weight;
char answer = 'y';
std::vector<CIST2362::Person> personDatabase; // vector of Person Objects
// input person objects
// You must catch exceptions properly
while (toupper(answer) == 'Y') {
std::cin >> firstName;
std::cin >> lastName;
std::cin >> birthMonth;
std::cin >> birthDay;
std::cin >> birthYear;
std::cin >> weight;
std::cin >> height;
// place person objects into vector
// ENTER CODE HERE
std::cin >> answer;
}
// output the person objects
// ENTER CODE HERE
return 0;
}
(Date.cpp)
#include "Date.h"
#include "DateException.h"
#include <sstream>
namespace CIST2362 {
Date::Date() {
// ENTER CODE HERE
}
Date::Date(int m, int d, int y) {
// ENTER CODE HERE
}
void Date::setNames() {
names[0] = "January";
names[1] = "Febraury";
names[2] = "March";
names[3] = "April";
names[4] = "May";
names[5] = "June";
names[6] = "July";
names[7] = "August";
names[8] = "September";
names[9] = "October";
names[10] = "November";
names[11] = "December";
}
void Date::setMonth(int m) {
// ENTER CODE HERE
}
void Date::setDay(int d) {
// ENTER CODE HERE
}
void Date::setYear(int y) {
// ENTER CODE HERE
}
std::string Date::getDateShort() {
// ENTER CODE HERE
return "M/D/Y";
}
std::string Date::getDateLong() {
// ENTER CODE HERE
return "Month Day, Year";
}
} // CIST2362
(Date.h)
#ifndef LESSON_5_PROGRAMMING_ASSIGNMENT_DATE_H
#define LESSON_5_PROGRAMMING_ASSIGNMENT_DATE_H
#include <iostream>
#include <string>
namespace CIST2362 {
// Constants
const int NUM_MONTHS = 12;
class Date {
private:
int month;
int day;
int year;
// An array of strings to hold
// the names of the months
std::string names[NUM_MONTHS];
// Private member function to assign
// the month names to the names array
void setNames();
public:
// Constructors
Date();
Date(int, int, int);
// Mutators
void setMonth(int m);
void setDay(int d);
void setYear(int y);
// Functions to print the date
std::string getDateShort();
std::string getDateLong();
};
} // CIST2362
#endif //LESSON_5_PROGRAMMING_ASSIGNMENT_DATE_H
(DateException.cpp)
#include "DateException.h"
namespace CIST2362 {
// ENTER CODE HERE
} // CIST2362
(DateException.h)
#ifndef LESSON_5_PROGRAMMING_ASSIGNMENT_DATEEXCEPTION_H
#define LESSON_5_PROGRAMMING_ASSIGNMENT_DATEEXCEPTION_H
#include <exception>
namespace CIST2362 {
// Exception classes
class InvalidDay: public std::exception {
public:
// ENTER CODE HERE
};
class InvalidMonth: public std::exception {
public:
// ENTER CODE HERE
};
class InvalidYear: public std::exception {
public:
// ENTER CODE HERE
};
} // CIST2362
#endif //LESSON_5_PROGRAMMING_ASSIGNMENT_DATEEXCEPTION_H
(Person.cpp)
#include <sstream>
#include <iomanip>
#include "Person.h"
#include ".
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