Common Mechanical Operation
Section 3
Eng. Kareem H. Mokhtar
Belt conveyor
F= 0.02 – 0.04
T3 = 1.1 T2
So we need to calculate mb (mass of belt), midlers (mass of idlers), and m(mass of solid)
Per unit length
Belt conveyor
Mb (mass of belt per unit length) = B * x * density of belt
1000 - 1500 kg/m3
(4 mm)
(2 mm)
Belt conveyor
Midlers (mass of idlers)
7800 kg/m3
Mass of idler per unit length =
𝑚𝑎𝑠𝑠 𝑜𝑓 𝑖𝑑𝑙𝑒𝑟 ∗ 𝑁𝑜.𝑜𝑓 𝑖𝑑𝑙𝑒𝑟
𝐿𝑒𝑛𝑔𝑡ℎ
Idlers spacing if 2000 kg/m3  1100 mm to 1500 mm
if heavier  1000, 1300 mm
Length / spacing
Belt conveyor
Mass of solids per unit length = mass flow rate / velocity
Velocity  assume 1 m/s if not stated
Bucket Elevator
Assume
Chain speed --> 0.2 – 1 m/s (usually 0.5m/s)
Spacing  300 mm to 450 mm
Let us solve
• A) Lecture questions
• B) The sheet
Sheet 3
Section 3

Section 3