module

1. GUESS THE WORD TO BE FORMED BY DOING
ADDITION OR SUBTRACTION FROM THE GIVEN
PICTURES AND LETTERS.
GUES
S
WHAT

3. The rate of motion; act or state of
moving.
- ads
+
- d
SPEED

4. The rate of change of position along a
straight line with respect of time.
- as + lo +
VELOCITY

5. - sk + - celb
ACCELERATION
- L
The rate of change of the velocity

6. The property of a body that is a measure of the amount of
material it contains and causes it to have weight in a
- p + - gra
MASS

7. - my
+
- g
- ry
MOMENTUM

8. - S
+
- A
- L +
IMPULSE

9. DISCUSSI
ONGRADE 9 - JADE

10. MOMENTU
M
AND
LESSON
GRADE 9 SCIENCE

11. 02
03
01
LEARNING
OBJECTIVES
identify the factors that affect momentum and impulse to
collisions of objects.
appreciate the importance of momentum in real life
situations.
solve problems by using momentum- impulse formulas for
different for different objects.

12. PROJECTILE MOTION

13. Let's assume there's a car speeding toward you,
out of control without its brakes, at a speed of 27
m/s (60 mph). Can you stop it by standing in front
of it and holding out your hand?

14. Unless you're Superman, you probably don't want to try
stopping a moving car by holding out your hand.
It's too big, and it's moving way too fast.

19. WHAT DO YOU MEAN BY
MOMENTUM?

20. Things we need to consider in defining
momentum:
a. The object has a mass.
b. The object is moving.
• Any moving object with a quantity of matter
has momentum.
• Momentum simply means mass in motion.

22. Mathematically, it is expressed
as:

23. Sample Problem 1:
Find the momentum of a bumper car if it has a total
mass of 280 kg and a velocity of 3.2 m/s.
Given :
p= ?
m= 280 kg
v= 3.2 m/s
Solution:
p= mv
p= (280 kg) (3.2 m/s )
p= 896 kg m/s
⋅

24. Sample Problem 2:
The momentum of a second bumper car is 675 kg⋅
m/s. What is its velocity if its total mass is 300 kg?
Given :
p= 675 kg m/s
⋅
m= 300 kg
v= ?
Solution:
v= p ÷ m
v= (675 kg m/s)÷ (300 kg)
⋅
v= 2.25 m/s

25. Sample Problem 3:
A car has a velocity of 20 m/sec and its momentum
is 1500 kg m/s. Find the mass of the car.
⋅
Given :
p= 1500 kg m/s
⋅
v= 20 m/sec
m=?
Solution:
m= p ÷ v
m= 1500 kg m/s) ÷(20 m/sec)
⋅
m= 2.25 kg

26. ... LET’S SOLVE
TOGETHER ...
1 . What is the momentum of a 20 kg boy
running north at 2 m/s?
2. A beach ball is rolling in a straight line towards
you at a speed of 0.5 m/s. Its momentum is 0.25
kg. m/s. What is the mass of the beach ball?
3. A 0.5 kg ball has a momentum of 0.05 kg.m/s
to the left. What is its velocity?

28. ... LET’S CHECK
TOGETHER ...

29. ... LET’S CHECK
TOGETHER ...

30. ... LET’S CHECK
TOGETHER ...

31. WHAT IS THE MOMENTUM OF AN OBJECT THAT IS NOT
MOVING?
If any object of any mass is not moving, it has zero momentum
since its velocity is zero.

32. What do you think will happen to
the bus after if it passes along a
curvyroad?
a. it will slow down
b. it will speed up
c. its velocity will not change

33. a. it increases
b. it decreases
c. it does not change at all
How will you describe the velocity of
thebus?

34. a. it increases
b. it decreases
c. it does not change at all
What can you say about the mass of
thebus?

35. When the object slows down or moves faster,
its velocity decreases or increases. If there is a
change in the velocity or the mass of an object,
there is also a change in momentum. And that
change of momentum is called IMPULSE.

36. Force is needed to change the momentum of a
body.
Impulse = Change in momentum I = Δp
The first line is our familiar equation F = ma.
The second line expresses the acceleration as the change in
velocity divided by the change in time. This is the basic
definition of acceleration.
The third line is arrived at through algebra by multiplying each
side of the equation by delta t, canceling it on the right,
effectively moving it over to the left.

37. The left side of the third line is called
the impulse on the object. That is,
impulse is equal to the net force times
the length of time over which that
force is applied.
The right side of the third line is called
the change in momentum. So, we say
the impulse equals the change in
momentum. More about the change in
momentum later. For now, we will take
The impulse equals the
change in momentum.

38. I = Ft
Impulse is equal to the net force on the object
times the time period over which this force is
applied.
I - is the impulse
F - is the applied force
t- is the elapsed time
Body change their momentum through collisions.

39. Sample 1

40. Sample 2

41. Sample 3
A 0.2 kg baseball is thrown, and it takes 0.05 seconds for the
pitcher's hand to apply a force to accelerate the ball. Calculate the
force exerted by the pitcher's hand to achieve an impulse of 4 N·s
on the baseball.
Solution:
I = (Force) (time)
4 N·s = F (0.05 s)/ 0.05 s
4 N·s/0.05 s
80 N = F
Given:
F = ?
t = 0.05 s
I = 4 N·s

42. ... LET’S SOLVE
TOGETHER ...
1 .What is the impulse imparted by a
rocket that exerts 3.9 N for 2.6 seconds?
2. For what time must you exert a force of 50 kg
m/s² to get an impulse of 12 kg. m/s?
3. A soccer player kicks a ball with an impulse of 15
N·s. If the contact time between the player's foot
and the ball is 0.1 seconds, what force was exerted
on the ball during the kick?

44. ... LET’S SOLVE TOGETHER ...
1 .What is the impulse imparted by a
rocket that exerts 3.9 N for 2.6 seconds?
Given:
F = 3.9 N
t = 2.6 s
I = ?
Solution:
I = (Force) (time)
I = (3.9 N ) ( 2.6 s )
I = 10. 14 N·s

45. ... LET’S SOLVE TOGETHER ...
Given:
F = 50 kg m/s²
I = 12 kg. m/s
t = ?
Solution:
I = (Force) (time)
(12 kg.m/s)/(50 kg. m/s²) = (50 kg m/s²) (t)/
(50 kg. m/s²)
12/ 50 s = t
t= 0.24 s
2. For what time must you exert a force of 50 kg
m/s² to get an impulse of 12 kg. m/s?

46. ... LET’S SOLVE TOGETHER ...
3. A soccer player kicks a ball with an impulse of 15 N·s. If
the contact time between the player's foot and the ball is
0.1 seconds, what force was exerted on the ball during
the kick?
Given:
F = ?
t = 0.1 s
I = 15 N·s
Solution:
I = (Force) (time)
15 N·s = F (0.1 s)/ 0.1 s
15 N·s/0.1 s
150 N = F

47. The force of impact is directly proportional to the
momentum of the body and inversely
proportional to the time of contact.

50. What do you think is the impulse of an
object moving with constant momentum?
Constant - no change
There is no impulse or zero impulse for objects
moving with constant momentum.

51. Therefore, this shows the
relationship between impulse
and momentum. A change in
momentum is equal to
impulse.

53. • Which of the two cars has the greater change of velocity?
Car A

54. 2. Which car has the greater change in momentum? Explain
your answer.
Car A, because it travels faster than Car B therefore it has
greater velocity.

55. 3. Which car has the greater impulse?
Car A, because it has greater change in momentum.

57. HOW DOES AN
UNDERSTANDING OF
MOMENTUM AND
IMPULSE BENEFIT US
IN REAL-LIFE
SITUATIONS?

58. ARE YOU READY?

59. ASSESSME
NT
1. p = 200 kg·m/s ; v= ? ; m= 50 kg
2. p = ? ; v = 25 m/s ; m= 1500 kg
3. p = 600 kg·m/s ; v= 30 m/s ; m = ?
4. p = 2500 kg·m/s ; v = ? ; m = 15 kg
5. p = 1000 kg·m/s ; v= 50 m/s ; m =?
A.
Momentu
m
Directions. In a ½ crosswise , apply the momentum formula (p = mv ) to
determine the missing values in each item.

60. 1. You apply a force of 50 Newtons to an object for a duration of 2 seconds.
Calculate the impulse and the resulting change in momentum.
2. If an object experiences an impulse of 300 N·s, and the force applied to it is 75
Newtons, how long did the force act on the object?
3. A car experiences an impulse of 5000 N·s during a collision, and the collision lasts for
0.2 seconds. Calculate the average force exerted on the car during the collision.
4. You want to launch a rocket into space, and you need to apply a force of 200,000
Newtons for a duration of 120 seconds to achieve the necessary impulse. Calculate the
impulse and the resulting change in momentum.
5. A bullet weighing 24.0g strikes a big tree with a velocity of 510. If the bullet comes to
a stop after travelling 6.00cm inside the tree, what is the average force exerted by the
tree on the bullet?
B.
Impulse
Show the complete solution to each of the problem below.

61. ASSIGNME
NT
Part 1. Answer and explain the following.
1. Begin by defining momentum and impulse in your own
words.
2. Explain the difference between momentum and impulse.
3. Provide a real-world example that illustrates the concept of
momentum.

62. ASSIGNME
NT
Part 2. Solve the following problems:
a. Calculate the momentum of an object with a mass of 300 kg and
a velocity of 10 m/s.
b. Calculate the impulse experienced by a 1500 N force acting on an
object for 4 seconds.
c. A soccer ball has a mass of 0.4 kg and is kicked with a velocity of
16 m/s. Calculate its momentum.

63. ASSIGNME
NT
Part 3. Real-World Applications
Research and describe one real-world application where the
understanding of momentum and impulse is crucial. Explain how
these concepts are utilized in that application.

64. Submission Guidelines
- Organize your assignment neatly in a document.
- Clearly label each part (Part 1, Part 2, Part 3).
- Show all calculations and provide explanations where
necessary.
- Include any additional resources or references you used for
research.
- Submit your assignment by [insert submission method and

65. THANK YOU
AND
GOD BLESS