Reactivity of the metal Tendency to formcation
Tendency to loose outer elecrtons
E ooxid
1 / E ored
So the Eo cell = E ocathode - Eoanode is more, then themetal is more reactive to reduce the Cu
2+
Given
I. Zn/Zn 2+ || Cu 2+/Cu 1.072 V
II. Fe/Fe 2+ || Cu 2+/Cu 0.334 V
III. Mg/Mg 2+ || Cu 2+/Cu 1.640 V
IV. Pb/Pb 2+ || Cu 2+/Cu 0.459V
V. Sn/Sn 2+ || Cu 2+/Cu 0.600 V
So the order of reactivity is Mg > Zn > Sn > Pb >Fe
So the Eo cell = E ocathode - Eoanode is more, then themetal is more reactive to reduce the Cu
2+
Given
I. Zn/Zn 2+ || Cu 2+/Cu 1.072 V
II. Fe/Fe 2+ || Cu 2+/Cu 0.334 V
III. Mg/Mg 2+ || Cu 2+/Cu 1.640 V
IV. Pb/Pb 2+ || Cu 2+/Cu 0.459V
V. Sn/Sn 2+ || Cu 2+/Cu 0.600 V
So the order of reactivity is Mg > Zn > Sn > Pb >Fe
Solution
Reactivity of the metal Tendency to formcation
Tendency to loose outer elecrtons
E ooxid
1 / E ored
So the Eo cell = E ocathode - Eoanode is more, then themetal is more reactive to reduce the Cu
2+
Given
I. Zn/Zn 2+ || Cu 2+/Cu 1.072 V
II. Fe/Fe 2+ || Cu 2+/Cu 0.334 V
III. Mg/Mg 2+ || Cu 2+/Cu 1.640 V
IV. Pb/Pb 2+ || Cu 2+/Cu 0.459V
V. Sn/Sn 2+ || Cu 2+/Cu 0.600 V
So the order of reactivity is Mg > Zn > Sn > Pb >Fe
So the Eo cell = E ocathode - Eoanode is more, then themetal is more reactive to reduce the Cu
2+
Given
I. Zn/Zn 2+ || Cu 2+/Cu 1.072 V
II. Fe/Fe 2+ || Cu 2+/Cu 0.334 V
III. Mg/Mg 2+ || Cu 2+/Cu 1.640 V
IV. Pb/Pb 2+ || Cu 2+/Cu 0.459V
V. Sn/Sn 2+ || Cu 2+/Cu 0.600 V
So the order of reactivity is Mg > Zn > Sn > Pb >Fe.
Class XII d and f- block elements (part 2)Arunesh Gupta
This part contains ionisation enthalpies, oxidation states, metal oxides & oxocations, magnetic properties, coloured ions of d block elements, catalysts, interstitial compounds, alloy formation & some important conceptual questions with answers as hints. Also some reasoning questions are given to test the understanding of properties of d block elements.
Class XII d and f- block elements (part 2)Arunesh Gupta
This part contains ionisation enthalpies, oxidation states, metal oxides & oxocations, magnetic properties, coloured ions of d block elements, catalysts, interstitial compounds, alloy formation & some important conceptual questions with answers as hints. Also some reasoning questions are given to test the understanding of properties of d block elements.
In this ppt everything is available in a sequence and in a very easy way.... It will be very useful to you for your board exams ...
Many ppt also will be available very soon
2H2+O2=2H2O2 moles react with one mole of oxygen to give two moles.pdfinfo235816
2H2+O2=2H2O
2 moles react with one mole of oxygen to give two moles of water
in this case oxygen is sufficient but hydrogen is less
one mole of oxygen remains unreacted
so 2 moles of water are produced
Solution
2H2+O2=2H2O
2 moles react with one mole of oxygen to give two moles of water
in this case oxygen is sufficient but hydrogen is less
one mole of oxygen remains unreacted
so 2 moles of water are produced.
In this ppt everything is available in a sequence and in a very easy way.... It will be very useful to you for your board exams ...
Many ppt also will be available very soon
2H2+O2=2H2O2 moles react with one mole of oxygen to give two moles.pdfinfo235816
2H2+O2=2H2O
2 moles react with one mole of oxygen to give two moles of water
in this case oxygen is sufficient but hydrogen is less
one mole of oxygen remains unreacted
so 2 moles of water are produced
Solution
2H2+O2=2H2O
2 moles react with one mole of oxygen to give two moles of water
in this case oxygen is sufficient but hydrogen is less
one mole of oxygen remains unreacted
so 2 moles of water are produced.
Yellow fever is caused by the yellow fever virus and is spread by th.pdfinfo235816
Yellow fever is caused by the yellow fever virus and is spread by the bite of an infected female
mosquito. The mosquitoes feeds during the daytime. Chikungunya is caused by the chikungunya
virus. The virus is spread by the female mosquito.
It might be possible they could become established in the future. But mosquito control and
avoiding mosquito bites will control the endemic spread of the infection. Also vaccinations of
the travelers and immigrants will also avoid the spreading of the disease.
Solution
Yellow fever is caused by the yellow fever virus and is spread by the bite of an infected female
mosquito. The mosquitoes feeds during the daytime. Chikungunya is caused by the chikungunya
virus. The virus is spread by the female mosquito.
It might be possible they could become established in the future. But mosquito control and
avoiding mosquito bites will control the endemic spread of the infection. Also vaccinations of
the travelers and immigrants will also avoid the spreading of the disease..
Values are so important in life. The values kids learn at a young ag.pdfinfo235816
Values are so important in life. The values kids learn at a young age will be fruitful in their
personal and social life.
Solution
Values are so important in life. The values kids learn at a young age will be fruitful in their
personal and social life..
Time Value of Money (TVM) Value of the money does not remain same i.pdfinfo235816
Time Value of Money (TVM): Value of the money does not remain same it perishes over a span
of time of it its value go down over a period of time there are various factor one of the major
factor is inflation to compensate inflation and risk interest is given on the lending. So when we
take financial decisions like investment etc. we need to keep in mind the present value of the
inflow of the investment if that money will recovered after certain period of time or if it is series
of the inflow over a certain period of time then present value of all such inflows and also we
need to know what will be the future value of the money after certain period of time or if it is
series of inflow then future value of all such money at end of certain period.
The formula to know the present value of the annuities is PV=P((1-(1+r)^(-n))/r) where P is the
annuity, r is the discount rate and n is the number of period in the same manner formula to know
the future value of the annuity is FV =P *( {(((1+R)^N) - 1) / R}, where ) where P is the annuity,
r is the Interest rate and n is the number of period
Solution
Time Value of Money (TVM): Value of the money does not remain same it perishes over a span
of time of it its value go down over a period of time there are various factor one of the major
factor is inflation to compensate inflation and risk interest is given on the lending. So when we
take financial decisions like investment etc. we need to keep in mind the present value of the
inflow of the investment if that money will recovered after certain period of time or if it is series
of the inflow over a certain period of time then present value of all such inflows and also we
need to know what will be the future value of the money after certain period of time or if it is
series of inflow then future value of all such money at end of certain period.
The formula to know the present value of the annuities is PV=P((1-(1+r)^(-n))/r) where P is the
annuity, r is the discount rate and n is the number of period in the same manner formula to know
the future value of the annuity is FV =P *( {(((1+R)^N) - 1) / R}, where ) where P is the annuity,
r is the Interest rate and n is the number of period.
The shape is angular, because of the two pairs of.pdfinfo235816
The shape is angular, because of the two pairs of nonbonded electrons in O that
bend the molecule.
Solution
The shape is angular, because of the two pairs of nonbonded electrons in O that
bend the molecule..
Step1 Moles of ions from NaCl = 2x.46 = .92 Step2.pdfinfo235816
Step1 Moles of ions from NaCl = 2x.46 = .92 Step2 Moles of ions from MgCl2 =3
x.034 =.102 Step3 Moles of ions from MgSO4= 2x.019 =.038 Step4 CaSO4 is sparingly soluble
in water ; moles =.009 Step5 Total concentration of solute ions = 1.069 Moles Step6
Solution
being a dilute one ; molality is almost equal to molarity Step7 Osmotic pressure = 1.069 x .082 x
293 = 25.68 atm.
so that the reaction takes place and forms (=0 )b.pdfinfo235816
so that the reaction takes place and forms (=0 )bond with carbon in the place of oh
group
Solution
so that the reaction takes place and forms (=0 )bond with carbon in the place of oh
group.
In case of SO2 Dipole - Dipole forces are stron.pdfinfo235816
In case of SO2 : Dipole - Dipole forces are strongest MgCl2 : Ionic bonding forces
between Mg2+ and Cl-
Solution
In case of SO2 : Dipole - Dipole forces are strongest MgCl2 : Ionic bonding forces
between Mg2+ and Cl-.
D) None of the above. first nitration takes place.pdfinfo235816
D) None of the above. first nitration takes place when u add hno3 and then
sulphonation in ortho position. which has so3H..so either of nitrated product or sulphonated
product wid SO3H is formed..which is not present in options..
Solution
D) None of the above. first nitration takes place when u add hno3 and then
sulphonation in ortho position. which has so3H..so either of nitrated product or sulphonated
product wid SO3H is formed..which is not present in options...
Decrease in Entropy (S) always occurs when the ph.pdfinfo235816
Decrease in Entropy (S) always occurs when the phase changes from a less ordered
state (such as a gas), to a more ordered state (such as a solid) Decrease in Enthalpy (H) occurs
when a system loses energy. A gas has a high amount of internal energy (think hundreds of ping
pong balls bouncing around in a container), while a solid has the least internal energy (imagine
those same pingpong balls stacked into a lattice). Solid to gas causes an increase in entropy
(more random) and enthalpy (more energy) Solid to liquid still causes both entropy and enthalpy
to increase. Liquid to gas also causes an increase in both entropy and enthalpy for the same
reasons. The reverses of these reactions: Gas to solid, Gas to liquid, and Liquid to solid all have
a decrease in enthalpy and entropy. Example: Gas to Liquid. As a gas cools, it loses energy.
Eventually it will clump together to form a liquid, which decreases its entropy.
Solution
Decrease in Entropy (S) always occurs when the phase changes from a less ordered
state (such as a gas), to a more ordered state (such as a solid) Decrease in Enthalpy (H) occurs
when a system loses energy. A gas has a high amount of internal energy (think hundreds of ping
pong balls bouncing around in a container), while a solid has the least internal energy (imagine
those same pingpong balls stacked into a lattice). Solid to gas causes an increase in entropy
(more random) and enthalpy (more energy) Solid to liquid still causes both entropy and enthalpy
to increase. Liquid to gas also causes an increase in both entropy and enthalpy for the same
reasons. The reverses of these reactions: Gas to solid, Gas to liquid, and Liquid to solid all have
a decrease in enthalpy and entropy. Example: Gas to Liquid. As a gas cools, it loses energy.
Eventually it will clump together to form a liquid, which decreases its entropy..
The diploid genetic system is more intersting than th monoploid gene.pdfinfo235816
The diploid genetic system is more intersting than th monoploid genetic system due to followinf
reasons:Completely dominant allelesIncompletely dominant allelesCodominant allelesIn
complete dominance, the effect of one allele in heterozygous genotype completely masks the
other. The allele that masks the other is said to be dominant while the other which has been
masked is called recessive.Incomplete dominance is a form of inheritance in which one allele
for a specific trait is not completely expressed over its paired allele. This results in a third
phenotype in which the physical traits expressed are a combination of both alleles.Allels that are
masked or hidden by dominant alleles are known as recessive alleles. In some situations, both
alleles are expressed equally.Example : The flower\'s on Mendel\'s pea plant.Example: Pink
rosesExample: blood group AB
Solution
The diploid genetic system is more intersting than th monoploid genetic system due to followinf
reasons:Completely dominant allelesIncompletely dominant allelesCodominant allelesIn
complete dominance, the effect of one allele in heterozygous genotype completely masks the
other. The allele that masks the other is said to be dominant while the other which has been
masked is called recessive.Incomplete dominance is a form of inheritance in which one allele
for a specific trait is not completely expressed over its paired allele. This results in a third
phenotype in which the physical traits expressed are a combination of both alleles.Allels that are
masked or hidden by dominant alleles are known as recessive alleles. In some situations, both
alleles are expressed equally.Example : The flower\'s on Mendel\'s pea plant.Example: Pink
rosesExample: blood group AB.
Step-1Code the playing card and then sort the cards in a deck.Ste.pdfinfo235816
Step-1:Code the playing card and then sort the cards in a deck.
Step-2:Code the deck of cards then take a card from the deck.
Step-3:use the deck of cards and then rank distribution of cards.
PROGRAM IN VB.NET
Public Class Form1
02
Dim TheDeck As DeckOfCards
03
Dim Hands(NumberOfHands - 1) As HandOfCards
04
Const NumberOfHands As Integer = 10
05
06
07
Private Sub Form1_Paint(ByVal sender As Object, ByVal e
AsSystem.Windows.Forms.PaintEventArgs) Handles Me.Paint
08
If TheDeck IsNot Nothing Then
09
For i = 0 To NumberOfHands - 1
10
Hands(i).DrawHand(e.Graphics, 25, 25 + i * 65)
11
Next
12
End If
13
14
15
End Sub
16
17
18
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As
System.EventArgs)Handles Button1.Click
19
Console.WriteLine(\"--------\")
20
21
22
TheDeck = New DeckOfCards
23
TheDeck.ShuffleCards()
24
TheDeck.ShuffleCards()
25
\'TheDeck.ShuffleCards()
26
\' TheDeck.ShuffleCards()
27
For i = 0 To NumberOfHands - 1
28
Hands(i) = New HandOfCards
29
For c As Integer = 0 To 4
30
Hands(i).AddCard(TheDeck.TakeCard)
31
Next
32
Hands(i).SortHand()
33
Next
34
Array.Sort(Hands, New HandOfCards.HandComparer)
35
For i = 0 To NumberOfHands - 1
36
Console.WriteLine(\"{0}\" & vbTab & \"[{1}] = {2}\" & vbTab & \" {3}\" & vbTab &
\"[{4}]\" & vbTab & \" ({5})\", i + 1, Hands(i).ToString, Hands(i).SuitValueOfHand,
Hands(i).RankDistrubtion, Hands(i).NameOfHand, Hands(i).ValueOfHand)
37
Next
38
\'Console.WriteLine(\"Deck [{0}]\", TheDeck.DeckState)
39
\'Console.WriteLine(\"Deck [{0}]\", TheDeck.DeckState)
40
\'TheDeck.ShuffleCards()
41
\'Console.WriteLine(\"Deck [{0}]\", TheDeck.DeckState)
42
Me.Refresh()
43
End Sub
44
End Class
Public Class Form1
Solution
Step-1:Code the playing card and then sort the cards in a deck.
Step-2:Code the deck of cards then take a card from the deck.
Step-3:use the deck of cards and then rank distribution of cards.
PROGRAM IN VB.NET
Public Class Form1
02
Dim TheDeck As DeckOfCards
03
Dim Hands(NumberOfHands - 1) As HandOfCards
04
Const NumberOfHands As Integer = 10
05
06
07
Private Sub Form1_Paint(ByVal sender As Object, ByVal e
AsSystem.Windows.Forms.PaintEventArgs) Handles Me.Paint
08
If TheDeck IsNot Nothing Then
09
For i = 0 To NumberOfHands - 1
10
Hands(i).DrawHand(e.Graphics, 25, 25 + i * 65)
11
Next
12
End If
13
14
15
End Sub
16
17
18
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As
System.EventArgs)Handles Button1.Click
19
Console.WriteLine(\"--------\")
20
21
22
TheDeck = New DeckOfCards
23
TheDeck.ShuffleCards()
24
TheDeck.ShuffleCards()
25
\'TheDeck.ShuffleCards()
26
\' TheDeck.ShuffleCards()
27
For i = 0 To NumberOfHands - 1
28
Hands(i) = New HandOfCards
29
For c As Integer = 0 To 4
30
Hands(i).AddCard(TheDeck.TakeCard)
31
Next
32
Hands(i).SortHand()
33
Next
34
Array.Sort(Hands, New HandOfCards.HandComparer)
35
For i = 0 To NumberOfHands - 1
36
Console.WriteLine(\"{0}\" & vbTab & \"[{1}] = {2}\" & vbTab & \" {3}\" & vbTab &
\"[{4}]\" & vbTab & \" ({5})\", i + 1, Hands(i).ToString, Han.
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Reactivity of the metal Tendency to formcation .pdf
1. Reactivity of the metal Tendency to formcation
Tendency to loose outer elecrtons
E ooxid
1 / E ored
So the Eo cell = E ocathode - Eoanode is more, then themetal is more reactive to reduce the Cu
2+
Given
I. Zn/Zn 2+ || Cu 2+/Cu 1.072 V
II. Fe/Fe 2+ || Cu 2+/Cu 0.334 V
III. Mg/Mg 2+ || Cu 2+/Cu 1.640 V
IV. Pb/Pb 2+ || Cu 2+/Cu 0.459V
V. Sn/Sn 2+ || Cu 2+/Cu 0.600 V
So the order of reactivity is Mg > Zn > Sn > Pb >Fe
So the Eo cell = E ocathode - Eoanode is more, then themetal is more reactive to reduce the Cu
2+
Given
I. Zn/Zn 2+ || Cu 2+/Cu 1.072 V
II. Fe/Fe 2+ || Cu 2+/Cu 0.334 V
III. Mg/Mg 2+ || Cu 2+/Cu 1.640 V
IV. Pb/Pb 2+ || Cu 2+/Cu 0.459V
V. Sn/Sn 2+ || Cu 2+/Cu 0.600 V
So the order of reactivity is Mg > Zn > Sn > Pb >Fe
Solution
Reactivity of the metal Tendency to formcation
Tendency to loose outer elecrtons
E ooxid
1 / E ored
So the Eo cell = E ocathode - Eoanode is more, then themetal is more reactive to reduce the Cu
2+
2. Given
I. Zn/Zn 2+ || Cu 2+/Cu 1.072 V
II. Fe/Fe 2+ || Cu 2+/Cu 0.334 V
III. Mg/Mg 2+ || Cu 2+/Cu 1.640 V
IV. Pb/Pb 2+ || Cu 2+/Cu 0.459V
V. Sn/Sn 2+ || Cu 2+/Cu 0.600 V
So the order of reactivity is Mg > Zn > Sn > Pb >Fe
So the Eo cell = E ocathode - Eoanode is more, then themetal is more reactive to reduce the Cu
2+
Given
I. Zn/Zn 2+ || Cu 2+/Cu 1.072 V
II. Fe/Fe 2+ || Cu 2+/Cu 0.334 V
III. Mg/Mg 2+ || Cu 2+/Cu 1.640 V
IV. Pb/Pb 2+ || Cu 2+/Cu 0.459V
V. Sn/Sn 2+ || Cu 2+/Cu 0.600 V
So the order of reactivity is Mg > Zn > Sn > Pb >Fe
