1. This document discusses probability concepts including independence, mutually exclusive events, conditional probability, and Bayes' theorem. It provides examples of calculating probabilities for various scenarios involving items in boxes, balls in urns, medical tests, and surveys.
2. Key concepts covered include defining sample spaces, favorable outcomes, partitions, and computing probabilities using formulas like P(A|B), P(A union B), and Bayes' theorem.
3. Examples involve problems like calculating the probability of items/balls with certain properties being selected from groups with known compositions.
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I am Christopher, T.I am a Mathematics Assignment Expert at eduassignmenthelp.com. I hold a PhD. in Mathematics, University of Alberta, Canada. I have been helping students with their Assignments for the past 7 years. I solve assignments related to Mathematics.
Visit eduassignmenthelp.com or email info@eduassignmenthelp.com . You can also call on +1 678 648 4277 for any assistance with Mathematics Assignments.
I am Josh U. I am a Probability Assignment Expert at statisticsassignmenthelp.com. I hold a Masters in Statistics from St. Edward’s University, USA.
I have been helping students with their homework for the past 5 years. I solve assignments related to Probability. Visit statisticsassignmenthelp.com or email info@statisticsassignmenthelp.com.
You can also call on +1 678 648 4277 for any assistance with Probability Assignments.
I am Christopher, T.I am a Mathematics Assignment Expert at eduassignmenthelp.com. I hold a PhD. in Mathematics, University of Alberta, Canada. I have been helping students with their Assignments for the past 7 years. I solve assignments related to Mathematics.
Visit eduassignmenthelp.com or email info@eduassignmenthelp.com . You can also call on +1 678 648 4277 for any assistance with Mathematics Assignments.
Some Basic concepts of Probability along with advanced concepts on Medical probability & Probability in Gambling. A lot of Sample Questions and Practice Questions will help you understand and apply the concepts in real life.
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Elementary Statistics Practice Test 2 Solutions
Chapter 4: Probability
Richard's entangled aventures in wonderlandRichard Gill
Since the loophole-free Bell experiments of 2020 and the Nobel prizes in physics of 2022, critics of Bell's work have retreated to the fortress of super-determinism. Now, super-determinism is a derogatory word - it just means "determinism". Palmer, Hance and Hossenfelder argue that quantum mechanics and determinism are not incompatible, using a sophisticated mathematical construction based on a subtle thinning of allowed states and measurements in quantum mechanics, such that what is left appears to make Bell's argument fail, without altering the empirical predictions of quantum mechanics. I think however that it is a smoke screen, and the slogan "lost in math" comes to my mind. I will discuss some other recent disproofs of Bell's theorem using the language of causality based on causal graphs. Causal thinking is also central to law and justice. I will mention surprising connections to my work on serial killer nurse cases, in particular the Dutch case of Lucia de Berk and the current UK case of Lucy Letby.
Some Basic concepts of Probability along with advanced concepts on Medical probability & Probability in Gambling. A lot of Sample Questions and Practice Questions will help you understand and apply the concepts in real life.
Please Subscribe to this Channel for more solutions and lectures
http://www.youtube.com/onlineteaching
Elementary Statistics Practice Test 2 Solutions
Chapter 4: Probability
Richard's entangled aventures in wonderlandRichard Gill
Since the loophole-free Bell experiments of 2020 and the Nobel prizes in physics of 2022, critics of Bell's work have retreated to the fortress of super-determinism. Now, super-determinism is a derogatory word - it just means "determinism". Palmer, Hance and Hossenfelder argue that quantum mechanics and determinism are not incompatible, using a sophisticated mathematical construction based on a subtle thinning of allowed states and measurements in quantum mechanics, such that what is left appears to make Bell's argument fail, without altering the empirical predictions of quantum mechanics. I think however that it is a smoke screen, and the slogan "lost in math" comes to my mind. I will discuss some other recent disproofs of Bell's theorem using the language of causality based on causal graphs. Causal thinking is also central to law and justice. I will mention surprising connections to my work on serial killer nurse cases, in particular the Dutch case of Lucia de Berk and the current UK case of Lucy Letby.
Introduction:
RNA interference (RNAi) or Post-Transcriptional Gene Silencing (PTGS) is an important biological process for modulating eukaryotic gene expression.
It is highly conserved process of posttranscriptional gene silencing by which double stranded RNA (dsRNA) causes sequence-specific degradation of mRNA sequences.
dsRNA-induced gene silencing (RNAi) is reported in a wide range of eukaryotes ranging from worms, insects, mammals and plants.
This process mediates resistance to both endogenous parasitic and exogenous pathogenic nucleic acids, and regulates the expression of protein-coding genes.
What are small ncRNAs?
micro RNA (miRNA)
short interfering RNA (siRNA)
Properties of small non-coding RNA:
Involved in silencing mRNA transcripts.
Called “small” because they are usually only about 21-24 nucleotides long.
Synthesized by first cutting up longer precursor sequences (like the 61nt one that Lee discovered).
Silence an mRNA by base pairing with some sequence on the mRNA.
Discovery of siRNA?
The first small RNA:
In 1993 Rosalind Lee (Victor Ambros lab) was studying a non- coding gene in C. elegans, lin-4, that was involved in silencing of another gene, lin-14, at the appropriate time in the
development of the worm C. elegans.
Two small transcripts of lin-4 (22nt and 61nt) were found to be complementary to a sequence in the 3' UTR of lin-14.
Because lin-4 encoded no protein, she deduced that it must be these transcripts that are causing the silencing by RNA-RNA interactions.
Types of RNAi ( non coding RNA)
MiRNA
Length (23-25 nt)
Trans acting
Binds with target MRNA in mismatch
Translation inhibition
Si RNA
Length 21 nt.
Cis acting
Bind with target Mrna in perfect complementary sequence
Piwi-RNA
Length ; 25 to 36 nt.
Expressed in Germ Cells
Regulates trnasposomes activity
MECHANISM OF RNAI:
First the double-stranded RNA teams up with a protein complex named Dicer, which cuts the long RNA into short pieces.
Then another protein complex called RISC (RNA-induced silencing complex) discards one of the two RNA strands.
The RISC-docked, single-stranded RNA then pairs with the homologous mRNA and destroys it.
THE RISC COMPLEX:
RISC is large(>500kD) RNA multi- protein Binding complex which triggers MRNA degradation in response to MRNA
Unwinding of double stranded Si RNA by ATP independent Helicase
Active component of RISC is Ago proteins( ENDONUCLEASE) which cleave target MRNA.
DICER: endonuclease (RNase Family III)
Argonaute: Central Component of the RNA-Induced Silencing Complex (RISC)
One strand of the dsRNA produced by Dicer is retained in the RISC complex in association with Argonaute
ARGONAUTE PROTEIN :
1.PAZ(PIWI/Argonaute/ Zwille)- Recognition of target MRNA
2.PIWI (p-element induced wimpy Testis)- breaks Phosphodiester bond of mRNA.)RNAse H activity.
MiRNA:
The Double-stranded RNAs are naturally produced in eukaryotic cells during development, and they have a key role in regulating gene expression .
Observation of Io’s Resurfacing via Plume Deposition Using Ground-based Adapt...Sérgio Sacani
Since volcanic activity was first discovered on Io from Voyager images in 1979, changes
on Io’s surface have been monitored from both spacecraft and ground-based telescopes.
Here, we present the highest spatial resolution images of Io ever obtained from a groundbased telescope. These images, acquired by the SHARK-VIS instrument on the Large
Binocular Telescope, show evidence of a major resurfacing event on Io’s trailing hemisphere. When compared to the most recent spacecraft images, the SHARK-VIS images
show that a plume deposit from a powerful eruption at Pillan Patera has covered part
of the long-lived Pele plume deposit. Although this type of resurfacing event may be common on Io, few have been detected due to the rarity of spacecraft visits and the previously low spatial resolution available from Earth-based telescopes. The SHARK-VIS instrument ushers in a new era of high resolution imaging of Io’s surface using adaptive
optics at visible wavelengths.
THE IMPORTANCE OF MARTIAN ATMOSPHERE SAMPLE RETURN.Sérgio Sacani
The return of a sample of near-surface atmosphere from Mars would facilitate answers to several first-order science questions surrounding the formation and evolution of the planet. One of the important aspects of terrestrial planet formation in general is the role that primary atmospheres played in influencing the chemistry and structure of the planets and their antecedents. Studies of the martian atmosphere can be used to investigate the role of a primary atmosphere in its history. Atmosphere samples would also inform our understanding of the near-surface chemistry of the planet, and ultimately the prospects for life. High-precision isotopic analyses of constituent gases are needed to address these questions, requiring that the analyses are made on returned samples rather than in situ.
This presentation explores a brief idea about the structural and functional attributes of nucleotides, the structure and function of genetic materials along with the impact of UV rays and pH upon them.
Slide 1: Title Slide
Extrachromosomal Inheritance
Slide 2: Introduction to Extrachromosomal Inheritance
Definition: Extrachromosomal inheritance refers to the transmission of genetic material that is not found within the nucleus.
Key Components: Involves genes located in mitochondria, chloroplasts, and plasmids.
Slide 3: Mitochondrial Inheritance
Mitochondria: Organelles responsible for energy production.
Mitochondrial DNA (mtDNA): Circular DNA molecule found in mitochondria.
Inheritance Pattern: Maternally inherited, meaning it is passed from mothers to all their offspring.
Diseases: Examples include Leber’s hereditary optic neuropathy (LHON) and mitochondrial myopathy.
Slide 4: Chloroplast Inheritance
Chloroplasts: Organelles responsible for photosynthesis in plants.
Chloroplast DNA (cpDNA): Circular DNA molecule found in chloroplasts.
Inheritance Pattern: Often maternally inherited in most plants, but can vary in some species.
Examples: Variegation in plants, where leaf color patterns are determined by chloroplast DNA.
Slide 5: Plasmid Inheritance
Plasmids: Small, circular DNA molecules found in bacteria and some eukaryotes.
Features: Can carry antibiotic resistance genes and can be transferred between cells through processes like conjugation.
Significance: Important in biotechnology for gene cloning and genetic engineering.
Slide 6: Mechanisms of Extrachromosomal Inheritance
Non-Mendelian Patterns: Do not follow Mendel’s laws of inheritance.
Cytoplasmic Segregation: During cell division, organelles like mitochondria and chloroplasts are randomly distributed to daughter cells.
Heteroplasmy: Presence of more than one type of organellar genome within a cell, leading to variation in expression.
Slide 7: Examples of Extrachromosomal Inheritance
Four O’clock Plant (Mirabilis jalapa): Shows variegated leaves due to different cpDNA in leaf cells.
Petite Mutants in Yeast: Result from mutations in mitochondrial DNA affecting respiration.
Slide 8: Importance of Extrachromosomal Inheritance
Evolution: Provides insight into the evolution of eukaryotic cells.
Medicine: Understanding mitochondrial inheritance helps in diagnosing and treating mitochondrial diseases.
Agriculture: Chloroplast inheritance can be used in plant breeding and genetic modification.
Slide 9: Recent Research and Advances
Gene Editing: Techniques like CRISPR-Cas9 are being used to edit mitochondrial and chloroplast DNA.
Therapies: Development of mitochondrial replacement therapy (MRT) for preventing mitochondrial diseases.
Slide 10: Conclusion
Summary: Extrachromosomal inheritance involves the transmission of genetic material outside the nucleus and plays a crucial role in genetics, medicine, and biotechnology.
Future Directions: Continued research and technological advancements hold promise for new treatments and applications.
Slide 11: Questions and Discussion
Invite Audience: Open the floor for any questions or further discussion on the topic.
What is greenhouse gasses and how many gasses are there to affect the Earth.moosaasad1975
What are greenhouse gasses how they affect the earth and its environment what is the future of the environment and earth how the weather and the climate effects.
Comparing Evolved Extractive Text Summary Scores of Bidirectional Encoder Rep...University of Maribor
Slides from:
11th International Conference on Electrical, Electronics and Computer Engineering (IcETRAN), Niš, 3-6 June 2024
Track: Artificial Intelligence
https://www.etran.rs/2024/en/home-english/
Professional air quality monitoring systems provide immediate, on-site data for analysis, compliance, and decision-making.
Monitor common gases, weather parameters, particulates.
2. 1 . The number of total items = 12
The number of chosen items = 2
The number of defective items = 4
The number of possible outcomes
The number of non defective items= 8
A = { both items are defective }
The number of favorable outcomes for
getting both items are defective
P ( both items are defective )
3. The number of favorable outcomes for
getting both items are non defective
B = { both items is non defective }
P ( both items are non defective )
4. 2 . The number of red balls = 2
The number of blue balls = 4
The number of white balls = 5
The number of possible outcomes
The number of total balls = 11
The number of selected balls = 4
The number of favorable outcomes for
getting exactly two white balls
E = { exactly two white balls }
P ( exactly two white balls )
5. The number of favorable outcomes for getting at least
two white balls
P ( at least two white balls )
The number of favorable outcomes for getting at most
two blue balls
P ( at most two blue balls )
6. The number of favorable outcomes for getting
particular 1 red ball always include and at most
two blue balls
P ( Particular 1 red ball always include and at
most two blue balls )
7. 3 . The number of boys = 5
The number of teachers = 3
The number of possible outcomes
The number of persons in a committee = 6
The number of favorable outcomes for
getting majority of boys
P ( majority of boys )
8. 5 . The number of men = 10
The number of possible outcomes
The number of men in a group = 6
The number of favorable outcome that a certain 2
men are included in a group
P ( a certain two men are included )
9. 6 . The number of red balls = 3
The number of black balls = 5
The number of yellow balls = 4
The number of chosen balls = 3
The number of possible outcomes
The number of favorable outcomes for
getting all yellow
The number of total balls = 12
10. The number of possible outcomes
The number of favorable outcomes
forgetting all yellow
The number of favorable outcomes for
getting one of each color
P ( one of each colour )
12. 8 .The number of possible outcomes
The number of favorable outcomes for
getting both are white
P ( both are white ) =
The number of favorable outcomes for
getting both are black
P ( both are black ) =
The number of favorable outcomes for getting 1 white
and 1 black
P ( 1 white and 1 black ) =
14. 4 .The number of possible outcomes
The number of favorable outcomes for
getting both are red
P ( both are red ) =
The number of favorable outcomes for getting
different colour
P ( different colour ) =
16. The number of possible outcomes
The number of ways that exactly two white
P ( exactly two white )
The number of ways that at least two white
P ( at least two white )
18. 7 .The number of possible outcomes
The number of favorable outcomes such that A still
contain 5 white and 3 red balls
P ( A still contain 5 white and 3 red ) =
The number of favorable outcomes that taken red
from B
P ( taken red from B ) =
19. The number of favorable outcomes such that B still
contain 4 white and 1 red balls
P ( B still contain 4 white and 1 red ) =
The number of favorable outcomes such that A still
contain 6 white
P ( A still contain 6 white ) =
21. The number of possible outcomes
The number of ways that A still 5 white
P ( A still 5 white )
The number of ways that A still 4 white
P ( A still 4 white )
22. 9 . The number of possible blood groups
The probability that 3 of 5 blood donor will
be A+
23. 10. The number of possible outcomes
The number of ways that two of them are defective
P ( exactly two white )
The number of ways that at least one defective
P ( at least one defective )
24. 12. The number of possible outcomes
The number of ways that correct answer
P ( exactly 6 question correctly )
25. 13. The number of possible outcomes
The number of ways that at least 8 words known
P ( at least 8 words known )
26. 14. The number of possible outcomes
The number of ways that selected brand B
P ( selected brand B )
The number of ways that selected brand B and C
P ( selected brand B and C )
27. The number of ways that selected at least one of
the two brands B and C
P ( at least one of the brand B and C )
28. Conditional Probability
Consider the following problem :
One hundred items consists of 20 defective
and 80 non defective items. Suppose we
choose two items
( a ) with replacement
( b ) without replacement
A = { the first item is defective }
B = { the second item is defective }
29. ( i ) If we are chosen with replacement
(ii) If we are chosen without replacement
Let A and B be two events associated
with an experiment. We denote by p ( B/ A)
the conditional probability of the event B
given that A occurred.
30. Whenever we compute p( B / A) we
are computing p ( B ) with respect to
the reduce sample space A, rather than
with respect to the original sample
space
31. A class has 12 boys and 4 girls. If three
students are selected at random from the
class what is the probability that they are
all boys
Let A = the first student is boy
B = the second student is boy
C = the third student is boy
32. In a certain school, 25% of the students
failed mathematics, 15 % of the student
failed chemistry, and 10% of the students
failed both mathematics and chemistry. A
student is selected at random
( i ) If he failed chemistry, what is the
probability that he failed mathematics ?
( ii ) If he failed mathematics, what is the
probability that he failed chemistry?
( iii ) What is the probability that he failed
mathematics or chemistry?
33. Let M = {students who failed mathematics}
C = { students who failed chemistry }
P ( M ) = 0.25 ,
( i )The probability that a student failed
mathematics, given that he has failed
chemistry is
P ( C ) = 0.15 ,
34. ( ii )The probability that a student failed
chemistry, given that he has failed
mathematics is
( iii ) P( M U C )
35. X
A1 A2 -------- An
Let X be an event with respect to S and
A1 , A2 , ….. , An be a partition of S. Then
we may write
36. Let X be an event with respect to S and
A1 , A2 , ….. , An be a partition of S. Then
we may write
38. We are given three boxes as follows:
Box A has 10 light bulbs of which 4 are
defective.
Box B has 6 light bulbs of which 1 is
defective
Box C has 8 light bulbs of which 3 are
defective
We selected a box at random and draw a
bulb at random. What is the probability
that the bulb is defective.
43. Suppose a bulb is draw at random and is
found to be defective. Find the probability
that the bulb was draw by box A.
44. Suppose a bulb is draw at random and is
found to be non defective. Find the
probability that the bulb was draw by box
A.
45. Suppose a bulb is draw at random and is
found to be defective. Find the probability
that the bulb was not drawn by box A.
Suppose a bulb is draw at random and is
found to be non defective. Find the
probability that the bulb was not drawn by
box A.
46. A coin weighted so that P ( H ) = 2/3 and
P ( T ) = 1/3, is tossed. If head appears, then
a number is selected at random from the
number 1 through 9; if tail appears, then
a number is selected at random from the
number 1 through 5. Find the probability
that an even number is selected.
Let X be the event that an even number
is selected
47. Let X be the event that an even number
is selected
48. If the number is even, what is the
probability that the coin was head?
49. Three machines A , B and C produce
respectively 50 % , 30 % and 20 % of the
total number of items of a factory. The
percentages of defective output of these
machines are 3 % , 4 % and 5 % . If an
items in selected at random, find the
probability that the item is defective.
Suppose that an item is selected at
random and found to be defective.
55. We are given three boxes as follows:
Box A has 12 white 4 red and 4 blue
balls .
Box B has 6 white 2 red and 2 blue balls.
Box C has 9 white 4 red and 2 blue balls.
We selected a box at random and draw a
ball at random. Suppose a ball is draw at
random and is found to be white. Find the
probability that the ball was not draw by
box A.
59. There are five urns, and they are numbered 1 to
5. Each urn contains 10 balls. Urn i has i
defective balls, i = 1 , 2 , 3 , 4, 5. Consider the
following random experiment. First an urn is
selected at random and then a ball is selected
at random from the selected urn.( i ) What is
the probability that a selected ball is defective.
( ii ) If we have already selected ball and noted
that is defective, what is the probability that is
not come from urn 5.
62. If a certain desease is present, then a blood test
will reveal it 95 % of the time. But the test will
also indicate the present of the disease 2 % of
the time when in fact the person tested is free
of the disease; that is, the test gives a false
positive 2 % of the time. If 0.3 % of the general
population actually has the disease, what is the
probability that a person chosen at random from
the population has the disease given that he or
she is tested positive.
64. Let X be persons with certain disease by a
blood test
65.
66. A medical test has been designed to detect the
presence of certain disease. Among those who
have the disease, the probability that the disease
will be detected by the test is 0.95. However,
the probability that the disease will erroneously
indicate the present of the disease in those who
do not actually have it is 0.04. It is estimated
that 4 % of the population who take this test
have the disease. If the test administerted to an
induvidual is positive, what is the probability
that the person actually has the disease ?
67. X
A
4 %
B
96 %
0.95 0.04
0.05 0.96
Let A be the person with disease
Let B be the prrson without disease
70. Based on data obtained from the institute of
Dental Research. It has been determined that
42 % of 12-years olds have never had a cavity,
34 % of 13-year-olds have never had a cavity,
and 28 % of 14-year-olds have never had a
cavity. Suppose a child is selected at random
from a group of 24 junior high school students
that includes six 12-year-olds, eight 13-year-olds.
and ten 14-year-olds. If this child does not have
a cavity, what is the probability that the child is
14-year-old ?
72. Let A be the 12-year-olds child
Let B be the 13-year-olds child
Let C be the 14-year-olds child
Let X be the child who never had cavity
73.
74.
75. A study was conducted among a certain group
of union members whose health insurance
policies second opinions prior to surgery. Of
those member whose doctors advised them to
have surgery, 20 % were informed by a second
doctor that no surgery. Of these 70 % took the
second doctor’s opinion and did no go through
with the surgery. Of the members who were
advised to have surgery by both doctors, 95 %
went through with the surgery. What is the
probability that a union member who had
surgery was adivised to do by a second doctor ?
77. Let A be the merber imform by a second
doctor that no surgery was needed.
Let B be the merber imform by a second
doctor that surgery was needed.
Let X be the merber who had surgery.
78.
79. Raserchers weighed 1976 3-year-old from low-
incomes famillyes in 20 cities. Each child is
classified by race ( white , black , Hispanic ) and
by weight ( normal weight , over weight,or obese )
The results are tabulated as follows:
weight %
Races Childrem Normal over Obese
White 400 68 % 18% 14 %
Black 1000 68 % 15 % 17 %
Hispanic 600 56 % 20 % 24 %
80. If a participant in the researcher is selected
at random and is found to be obese, what
is the probability that the 3-year-olds is
white ? Hispanic ?