The document outlines the design process for a complete air conditioning system in Bangi, Selangor, focusing on methodologies for cooling load estimation and ducting design. It details calculations for required airflow, number of diffusers, and duct layout while proposing a specific air conditioning unit due to factors like building size and energy efficiency. The conclusion emphasizes that larger cooling loads necessitate more complex and efficient air conditioning systems, supporting the project's objective of effective design based on calculated loads.

1. INTRODUCTION
OBJECTIVE : Designing a complete air conditioning system
LOCATION : Bangi, Selangor

2. FLOOR SELECTION

3. METHODOLOGY
-Cooling load estimation table
-Rectangular duct chart
-Round duct chart
-Air Condition Load Estimation table (Eg . Table 1 – Table 13)

6. Method for ducting design
1. Determine the air required
𝐶𝐹𝑀 =
𝑅𝑆𝐻
12 × 103
× 500
2. Determine no. of diffuser
𝑅𝑒𝑞𝑢𝑖𝑟𝑒𝑑 𝐷𝑖𝑓𝑓𝑢𝑠𝑒𝑟 =
𝐶𝐹𝑀
𝐶𝐹𝑀 𝑝𝑒𝑟 𝑑𝑖𝑓𝑓𝑢𝑠𝑒𝑟
3. Design ducting layout.
4. Throw radius
𝑙𝑒𝑛𝑔𝑡ℎ 𝑠𝑖𝑑𝑒 =
𝑇𝑜𝑡𝑎𝑙 𝑙𝑒𝑛𝑔𝑡ℎ
𝑇ℎ𝑟𝑜𝑤 𝑟𝑎𝑑𝑖𝑢𝑠

7. SECTION CFM hr FPM Φ of duct Side of
rectangular
5. Determine of ducting sizes using table below

10. Procedure
1. Choose the design and the location.
2. Calculate cooling load using cooling load estimation table.
3. Choose suitable air condition system.
4. Calculate ducting system.
5. Design ducting system.

11. Assumption of design requirement
1. Ceiling = 12ft
2. Maximum operation – 24hours
3. Room condition – 75F, 55%RH, 72gr/lb
4. Outside air – 92F, 60%RH, 136gr/lb
5. Total of people – 25
6. Sun movement – east to west

12. Result and design
Sample for cooling load table

15. DUCTING SYSTEM
DETERMINE CFM
𝐶𝐹𝑀 =
𝑅𝑆𝐻
1.09 𝑥 𝑇
=
134888
1.09 𝑥 17
= 7279.5 ≈ 7500 𝐶𝐹𝑀

16. DETERMINE NUMBER OF DIFFUSER
𝑅𝑒𝑞𝑢𝑖𝑟𝑒𝑑 𝑑𝑖𝑓𝑓𝑢𝑠𝑒𝑟 =
𝐶𝐹𝑀
𝐶𝐹𝑀 𝑝𝑒𝑟 𝑑𝑖𝑓𝑓𝑢𝑠𝑒𝑟
=
7500
937.5
= 8

17. DETERMINE LENGTH AND WIDE SIDE
𝐿𝑒𝑛𝑔𝑡ℎ 𝑠𝑖𝑑𝑒 =
𝐿𝑒𝑛𝑔𝑡ℎ
𝑁𝑜 𝑜𝑓 𝑇ℎ𝑟𝑜𝑤 𝑟𝑎𝑑𝑖𝑢𝑠
𝑊𝑖𝑑𝑒 𝑠𝑖𝑑𝑒 =
𝑊𝑖𝑑𝑒
𝑁𝑜 𝑜𝑓 𝑇ℎ𝑟𝑜𝑤 𝑟𝑎𝑑𝑖𝑢𝑠
=
70
8
=
40
4
= 8.75 ft = 10 ft

18. DUCTING LAYOUT

19. EQUAL FRACTION METHOD

20. Total Rsh and cooling load
• RSH = 134888 Btu/hr
• Grand Total heat (GTH) = 200768

21. Proposing air conditioning system
• We choose UATN SERIES UATN210CGY1X.

22. Product specification
• Horsepower = 21 hp
• Type – non inverter
• Refrigerant – r410A
• Rated cooling – 213btu/hr
• Rated power comsumption – 16900W
• CFM = 7600
• Dimension - 1,650 x 2,410 x 2,030 (mm)
• Weight – 930kg

23. Justification
Why choose this system?
• Bigger building
• Energy Efficient
• Maintenance wise
• To conserve space

24. Discussion
• From the result above we can determine the type of conditioning
system for a choosen building.
• We can indentified the cooling load needed for a floor or a building.
• Grand total heat is significant factor in determined in air conditioning
system.

25. Conclusion
As a conclusion, the larger cooling load the more complicated our
conditioning system and much more efficient air conditioning system to
be used.
We are able to design and complete our objective which is to design a
system based of calculation of cooling load.
Other than that ducting system dimension can be determined and
designing the ducting system.