This document provides the questions and solutions from the Chemistry Paper I section of the JEE Advanced 2013 exam. It includes 30 multiple choice questions in Section I, 5 multi-select questions in Section II, and 5 integer-value questions in Section III, along with the explanations for each answer. The questions cover topics in chemistry including thermodynamics, kinetics, equilibrium, organic chemistry, and coordination compounds.

1. JEE Advanced 2013 (02­Jun­13) Question & Solutions Paper­I ­ 1 ­ www. prernaclasses.com
Chemistry Paper­ I Jee Advance 2013
R
Prerna Tower, Road No ­ 2, Contractors Area, Bistupur, Jamshedpur ­ 831001, Tel ­ (0657)2221892, www.prernaclasses.com
PART II ­ CHEMISTRY
SECTION ­ I (Only One option Correct Type)
This section contains 10 multiple choice questions. Each question has four choices (A), (B),
(C) and (D) out of which ONLY ONE is correct.
21. Methylene blue, from its aqueous solution, is adsorbed on activated charcoal at 25°C. For this
process, the correct statement is:
(A) The adsorption requires activation at 25°C.
(B) The adsorption is accompanied by a decrease in enthalpy.
(C) The adsorption increases with increase of temperature.
(D) The adsorption is irreversible.
21. (B) It is physisorption. It is reversible and rate decreases with rise in temperature. Adsorption
is exothermic so DH = – ve
22. Upon treatment with ammoniacal H 2 S, the metal ion that precipitates as a sulfide is
(A) Fe(III) (B) Al (III) (C) Mg (II) (D) Zn (II)
22. (D) Zn 2+ is a group IV radical which only precipitates with ammonical medium because
the K sp value for ZnS is more
23. In the reaction,
[Q]0
[Q]
Time
P + Q ® R + S
the time taken for 75% reaction of P is twice the time taken for 50% reaction of P. The
concentration of Q varies with reaction time as shown in the figure. The overall order of the
reaction is
(A) 2 (B) 3 (C) 0 (D) 1
23. (D) Order with respect to P is ‘1’ as t½ is constant
Order with respect to Q is ‘0’ as concentration varies linearly with time.
So overall order is 1 + 0 = 1.

2. JEE Advanced 2013 (02­Jun­13) Question & Solutions Paper­I ­ 2 ­ www. prernaclasses.com
24. KI in acetone, undergoes S N 2 reaction with each P, Q, R and S. The rates of the reaction vary as
H3C Cl
P Q
Cl
Cl
R
O
Cl
S
(A) P > Q > R > S (B) S > P > R > Q
(C) P > R > Q > S (D) R > P > S > Q
24. (B) ‘S’ has highest S N 2 reactivity due to neighbouring group participation.
25. The standard enthalpies of formation of CO 2 (g), H 2 O(l) and glucose(s) at 25°C are
– 400 kJ/mol, – 300 kJ/ mol and – 1300 kJ/ mol, respectively. The standard enthalpy of combustion
per gram of glucose at 25°C is
(A) + 2900 kJ (B) – 2900 kJ (C) – 16.11 kJ (D) + 16.11 kJ
25. (C) C 6 H 12 O 6 + 6O 2 ® 6CO 2 + 6H 2 O
DH C = 6 × (– 300) + 6 × (– 400) – ( – 1300) = – 2900 kJ / mol.
Standard enthalpy of combustion per gram of glucose = – 2900 / 180 = – 16.11 kJ
26. Consider the following complex ions, P, Q and R
P = [FeF 6 ] 3– , Q = [V(H 2 O) 6 ] 2+ and R = [Fe(H 2 O) 6 ] 2+
The correct order of the complex ions, according to their spin­only magnetic moment values
(in B.M) is
(A) R <Q < P (B) Q <R < P (C) R < P < Q (D) Q < P < R
26. (B) [FeF 6 ] 3– Þ Fe 3+ has 5 unpaired electron
[V(H 2 O) 6 ] 2+ Þ V 2+ has 3 unpaired electron
[Fe(H 2 O) 6 ] 2+ Þ Fe 2+ has 4 unpaired electron
27. The compound that does NOT liberate CO 2 ,on treatment with aqueous sodium bicarbonate
solution, is
(A) Benzoic acid (B) Benzenesulphonic acid
(C) Salicylic acid (D) Carbolic acid (phenol)
27. (D) Phenol does not react with aqueous NaHCO 3 due to low acidity.
28. Sulfide ores are common for the metals
(A) Ag, Cu and Pb (B) Ag, Cu and Sn
(C) Ag, Mg and Pb (D) Al, Cu and Pb
28. (A) Sulphide ores are common for less electropositive metals like Ag, Cu, Pb

3. JEE Advanced 2013 (02­Jun­13) Question & Solutions Paper­I ­ 3 ­ www. prernaclasses.com
29. The arrangment of X – ions around A + ion in solid AX is given in the figure (not drawn to scale).
If the radius of X – is 250 pm, the radius of A + is
(A) 104 pm (B) 125 pm (C) 183 pm (D) 57 pm
X-
A +
29. (A) The given structure shows that A + is present in octahedral void made by X – .
r + / r – = 0.414 Þ r + / 250 = 0.414 Þ r + = 104 pm.
30. Concentrated nitric acid, upon long standing, turns yellow­brown due to the formation of
(A) NO (B) NO 2 (C) N 2 O (D) N 2 O 4
30. (B) Concentrated nitric acid upon long standing turns yellow­brown due to dissolved NO 2 .

4. JEE Advanced 2013 (02­Jun­13) Question & Solutions Paper­I ­ 4 ­ www. prernaclasses.com
SECTION ­ II (One or more options correct Type)
This section contains 5 multiple choice questions.
Each question has four choices (A), (B), (C) and (D), out of which ONE OR MORE are correct.
31. Among P, Q, R and S, the aromatic compound(s) is/are
(A) P (B) Q (C) R (D) S
Cl
P AlCl
¾¾ ®¾ 3
Q NaH
¾¾ ®¾
O O
R CO NH
C 115 100
) (
°-
¾¾¾¾ ®¾ 3 2 4
O
S HCl
¾¾ ®¾
31. (ABCD)
Cl
¾¾ ®¾ 3 AlCl
+ AlCl4
-
+
(Aromatic)
; ¾¾ ®¾NaH
+ H2
Na +-
(aromatic)
O O
(NH4)2CO3
N
H
100 ­115°C
(Aromatic )
; (Paal Knorr Pyrrole Synthesis)
O
¾¾ ®¾HCl
OH
Cl-+
(aromatic)
32. The initial rate of hydrolysis of methyl acetate (1M) by a weak acid (HA, 1M) is 1/100 th of that of
a strong acid (HX, 1M), at 25 °C. The K a of HA is
(A) 1 × 10 –4 (B) 1 × 10 –5 (C) 1 × 10 –6 (D) 1 × 10 –3
32. (A)
) (
) (
] [
] [
] ester ][ [
] ester ][ [
100
1
) (
) (
HX
HA
H
H
H k
H k
HX rate
HA rate
+
+
+
+
===
[H + ] (HA) = Ca = 10 –2 a = 10 –2 [Q C = 1]

5. JEE Advanced 2013 (02­Jun­13) Question & Solutions Paper­I ­ 5 ­ www. prernaclasses.com
4
4 2
.
-
-
»
´
=
-
= 10
99 0
10 1
1 ) (
a
aC
K HA a
33. Benzene and naphthalene form an ideal solution at room temperature. For this process, the true
statement(s) is (are)
(A) DG is positive (B) DS system is positive
(C) DS surroundings = 0 (D) DH = 0
33. (BCD) For ideal solution DH = 0
DS mixing for system = +ve
DS surrounding = 0 as no heat is exchanged with surrounding.
34. The pair(s) of coordination complexes/ions exhibiting the same kind of isomerism is (are)
(A) [Cr(NH 3 ) 5 Cl]Cl 2 and [Cr(NH 3 ) 4 Cl 2 ]Cl (B) [Co(NH 3 ) 4 Cl 2 ] + and [Pt(NH 3 ) 2 (H 2 O)Cl] +
(C) [CoBr 2 Cl 2 ] 2– and [PtBr 2 Cl 2 ] 2– (D) [Pt(NH 3 ) 3 (NO 3 )]Cl and [Pt(NH 3 ) 3 Cl]Br
34. (BD) [Co(NH 3 ) 4 Cl 2 ] + and [Pt(NH 3 ) 2 (H 2 O)Cl] + exhibit geometrical isomerism
[Pt(NH 3 ) 3 (NO 3 )]Cl and [Pt(NH 3 ) 3 Cl]Br exhibit ionisation isomerism
35. The hyperconjugative stabilities of tert­butyl cation and 2­butene, respectively, are due to
(A) s®p(empty) and s®p* electron delocalisations.
(B) s®s* and s®p electron delocalisations.
(C) s®p(filled) and s®p electron delocalisations.
(D) p(filled)®s* and s®p* electron delocalisations.
35. (A)
CH3
(s ­ p(empty))
C +
CH3
CH2 H
CH2 C
CH3
CH2 H H +
(s ­ p(filled))
CH2 C
CH3
CH3

6. JEE Advanced 2013 (02­Jun­13) Question & Solutions Paper­I ­ 6 ­ www. prernaclasses.com
SECTION ­ III (Integer value corret Type)
This section contains a group of5 questions.
The answer to each of the questions is a single­digit integer,ranging from 0 to 9.
36. A tetrapeptide has –COOH group on alanine. This produces glycine (Gly), valine (Val), phenyl
alanine (Phe) and alanine (Ala), on complete hydrolysis. For this tetrapeptide, the number of
possible sequences (primary structures) with –NH 2 group attached to a chiral center is
36. (4) Glycine is inactive, so it can not come as N–terminal amino acid. At the same time alanine
has to be present as C­terminal Therefore the possible combinations are.
Phe­Gly­Val­Ala
Phe­Val­Gly­Ala
Val­Phe­Gly­Ala
Val­Gly­Phe­Ala
37. The atomic masses of He and Ne are 4 and 20 a.m.u., respectively. The value of the de Broglie
wavelength of He gas at –73 °C is “M” times that of the de Broglie wavelength of Ne at 727 °C.
M is
37. (5) l = (h / mv)
M
RT
V
3
=
M
T
m
h
λ =
Ne
He
λ
λ
=
20
1000
20
4
200
4
´
´
h
h
= 5
38. The total number of lone­pairs of electrons in melamine is
38. (6) Melamine
NH2
NH2 NH2
N: :N
N

7. JEE Advanced 2013 (02­Jun­13) Question & Solutions Paper­I ­ 7 ­ www. prernaclasses.com
39. The total number of carboxylic acid groups in the product P is
O
O
O O
O
P
O H
O
O H
2 2
3
3
. 3
. 2
, . 1
¾¾¾ ®¾ D+
39. (2) O
O
O O
O
¾¾ ®¾
+O H 3 OH
O
O
OH
O
O
ation Decarboxyl
¾®¾D
O
O
+ 2CO 2
2 2
3
O H
O
¾®¾
HO
O
O
O
HO
O
40. EDTA 4– is ethylenediaminetetraacetate ion. The total number of N–Co–O bond angles in
[Co(EDTA)] 1– complex ion is
40. (8)