2. “
Objectives:
At the end of the lesson, you
will be able to:
Illustrate the six trigonometric
ratios: sine, cosine, tangent,
cotangent, secant, and cosecant.
Solve right triangles given the
length of both sides.
2
3. 3
Direction: Tell the appropriate trigonometric ratio
(SOH, CAH, or TOA) to be used in each missing side
of ΔGIF.
1. ̅𝐹̅̅𝐼; trigonometric ratio: __________
2. ̅𝐹̅̅𝐺̅; trigonometric ratio: __________
For numbers 3 to 5, solve for the missing parts of
ΔGIF.
3. ̅𝐹̅̅𝐼 __________
4. ̅𝐹̅̅𝐺̅ __________
5. ∠F __________
21
c =
a
RECAP
I
F
G
31
29º
4. ➜ This topic covers the fourth and
last case of solving right
triangles in which the lengths of
the two legs are given.
4
5. ➜ The right triangle above has two legs
given, ̅𝐴̅̅𝐵̅ and ̅𝐵̅̅𝐶̅. Let us put all parts of the
triangle in a table and determine the
missing parts to be solved.
➜ So, in this case, the missing parts are the
hypotenuse and the two acute angles.
5
7. Given:
x = 15- leg 1
y = 10 - leg 2
Missing Parts to Solve:
(hypotenuse, two acute
angles):
1. z =?
2. ∠T =?
3. ∠E =?
7
EXAMPLE:
E
T
I
y = 10
x =15
z
8. Since two sides of
the triangle are
already given, use
the Pythagorean
Theorem to find the
hypotenuse.
8
1. Find i.
E
T
I
y = 10
x =15
z
9. By looking at the figure,
side t is opposite ∠T, and
side e is adjacent to ∠T.
To get the measure of
∠T, use TOA (tangent-
opposite-adjacent).
9
2. Find ∠T
E
T
I
y = 10
x =15
z
10. By looking at the figure,
side e is opposite ∠E,
and side t is adjacent to
∠E. To get the measure
of ∠E, use TOA
(tangent-opposite-
adjacent).
10
2. Find ∠E
E
T
I
y = 10
x =15
z
12. 12
Directions: Given the length of the two legs, find the length of
the hypotenuse. Round off your answers to two decimal
places.
LET’S PRACTICE!
LEG 1 LEG 2 HYPOTENUSE
1. 12 cm 6 cm
2. 10 cm 5 cm
3. 8 cm 5 cm
4. 14 cm 6 cm
5. 9 cm 15 cm
13. Direction: Solve for
the missing parts of
each right triangle.
13
KEEP PRACTICING!
A
B
C
x = 7 cm
z = 15cm
z
y
14. Direction: Solve for
the missing parts of
each right triangle.
14
X
Y
Z
a = 8
KEEP PRACTICING!
b = 5
c
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15
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16. 16
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