POLYNOMIALS
BY:
Dr. VIVEK NAITHANI
T.G.T (MATHEMATICS), KVS
COPYRIGHT INFORMATION: CC by SA 4.0
DEFINITION
An algebraic expression that contain two or more terms is called a
polynomial.
Each term of a polynomial has a co-efficient.
For an algebraic expression to qualify for being a polynomial it is
necessary that the power of variable in each term must be a positive
integer.
e.g. –x3+4x2+7x-2, 3y2+5y-7 etc.
𝑥 +
1
𝑥
is not a polynomial as the power of x in second term is -1
𝑦+5y is not a polynomial as the power of y is fraction in first term.
A polynomial in variable can be expressed generally as
anxn +an-1xn-1+an-2xn-2+…………..+ a2x2+a1x+a0
where
an, an-1, an-2, …………., a2, a1, a0 are all constants not
all zero and n is any positive integer.
DEGREE OF A POLYNOMIAL
The degree of a polynomial is the highest power of the
variable appearing in the polynomial.
e.g.: The degree of the polynomial x2-6x +7 is 2 as the
highest power of x appearing in the given polynomial is 2.
3x5+4x2-2. Here the highest power of variable is 5 so the
degree is 5
CLASSIFICATION OF POLYNOMIALS:
S.No. DEGREE NAME OF POLYNOMIAL
1 Zero (0) Constant Polynomial
2 One (1) Linear Polynomial
3 Two (2) Quadratic Polynomial
4 Three (3) Cubic Polynomial
5 Four (4) Bi-Quadratic Polynomial
The polynomials on the basis of their degree can be classified
as:
PRACTICE QUESTIONS
S.No. POLYNOMIAL DEGREE
1 2 – y2 – y3 + 2y8
2 x5 – x4 + 3
3 5x2 + 3x + π
4 2 – x2 + x3
5 4t4 + 5t3 – t2 + 6
Write the degree of following polynomials.
ZEROES OF A POLYNOMIAL:
 The zero or root of a polynomial p(x) is the value of x at
which p(x) = 0.
 If for x=a, p(a) = 0 then we say x=a is the zero or root of p(x).
 E.g.: p(x) = x2- 5x+6 is a polynomial.
For x= 2, we get p(2) = (2)2 – 5(2) +6
= 4 -10 +6 = 10-10 =0
Hence x=2 is a root or zero of p(x).
GEOMETRICAL MEANING OF ZEROES OF A
POLYNOMIAL
 If p(x) is a polynomial and we plot the graph of p(x) on a graph
sheet. The number of points of intersection of graph pf p(x) and
X –axis represent the number of zeroes or roots of p(x).
 A linear polynomial graph meets X axis at only one point.
 A quadratic polynomial graph meets the X – axis at maximum two
points.
 A cubic polynomial graph meets the X – axis at maximum three
points.
GRAPH OF A LINEAR POLYNOMIAL
Here p(x) = 5x-15, meets the X axis at A (3,0).
So, x=3 is a root or zero of p(x).
Graph of a linear function meets X –axis
at maximum one point
GRAPH OF A QUADRATIC FUNCTION
Here p(x) = x2-x-6 meets X axis at A (-2,0) and B (3,0). So x= -2 and x=3 are the
roots of p(x).
The graph of a quadratic polynomial is a parabola
and meets X –axis at maximum two points
GRAPH OF A CUBIC FUNCTION
Here p(x) = x3-7x; meets X- axis at A(-2.6,0); B(0,0); C(2.6,0). So,
x= -2.6, 0 and +2.6 are the roots of p(x).
RELATIONSHIP BETWEEN ZEROES AND CO-
EFFICIENTS OF A POLYNOMIAL
If ax2+bx+c is a quadratic polynomial whose roots are α and β.
Then
Sum of roots α + β =
−𝒃
𝒂
=
−(𝒄𝒐𝒆𝒇𝒇𝒊𝒄𝒊𝒆𝒏𝒕 𝒐𝒇 𝒙)
(𝒄𝒐−𝒆𝒇𝒇𝒊𝒄𝒊𝒆𝒏𝒕 𝒐𝒇 𝒙𝟐)
Product of roots α X β =
c
a
=
𝑐𝑜𝑛𝑠𝑡𝑎𝑛𝑡
(𝒄𝒐−𝒆𝒇𝒇𝒊𝒄𝒊𝒆𝒏𝒕 𝒐𝒇 𝒙𝟐)
The quadratic polynomial is: x2 –(Sum) x + (Product)
If ax3+bx2+cx+d is a cubic polynomial whose roots
are α, β and γ, then
α + β + γ =
−𝒃
𝒂
=
− (𝒄𝒐𝒆𝒇𝒇𝒊𝒄𝒊𝒆𝒏𝒕 𝒐𝒇 𝒙𝟐 )
(𝒄𝒐−𝒆𝒇𝒇𝒊𝒄𝒊𝒆𝒏𝒕 𝒐𝒇 𝒙𝟑)
αβ + βγ + γα =
𝒄
𝒂
=
(𝒄𝒐−𝒆𝒇𝒇𝒊𝒄𝒊𝒆𝒏𝒕 𝒐𝒇 𝒙)
(𝒄𝒐−𝒆𝒇𝒇𝒊𝒄𝒊𝒆𝒏𝒕 𝒐𝒇 𝒙𝟑)
α X β X γ =
−𝒅
𝒂
=
−(𝒄𝒐𝒏𝒔𝒕𝒂𝒏𝒕 )
(𝒄𝒐−𝒆𝒇𝒇𝒊𝒄𝒊𝒆𝒏𝒕 𝒐𝒇 𝒙𝟑)
FIND THE ZEROES AND VERIFY THE
RELATIONSHIP BETWEEN CO-EFFS. & ZEROES
(i) p(x) = x2- 2x- 8 Solving by splitting the
middle term
= x2 -4x+2x-8 now regrouping and taking
out common factors
= x(x-4) + 2 (x-4)
= (x-4) (x+2)
For p(x) = 0 ; Either x-4 = 0 ⇒ x=4
or x+2 = 0 ⇒ x = -2
Hence zeroes are α = 4 and β = -2
Now the coefficients are
a = 1; b = -2 and c = -8
The sum of roots α + β = 4 +(-2) = 4-2 =
2
−𝑏
𝑎
=
−(−2)
1
= 2
Hence α + β =
−𝑏
𝑎
Product of roots = α X β = 4 X (-2) = -8
𝑐
𝑎
=
(−8)
1
= -8
Hence α X β =
𝑐
𝑎
Hence relation is verified.
(ii) 6x2 – 3 -7x
First arranging the terms in descending
order of power
6x2- 7x – 3 Solving by splitting the middle
term
= 6x2 – 9x+ 2x -3 Regrouping and taking out
common factor
= 3x(2x-3) +1 (2x-3)
= (2x-3) (3x+1)
For p(x) = 0
Either 2x-3 = 0 ⇒ 2x= 3 ⇒ x= 3/2
Or 3x+1 = 0 ⇒ 3x = -1 ⇒ x = -1/3
Hence zeroes are α = 3/2 and β = -1/3
Now the coefficients are
a = 6; b = -7 and c = -3
The sum of roots α + β =
3
2
+ (
−1
3
)
=
9−2
6
=
7
6
−𝑏
𝑎
=
−(−7)
6
=
7
6
The product of the roots α X β =
3
2
X (
−1
3
) =
−1
2
𝑐
𝑎
=
−3
6
=
−1
2
Hence relation is verified.
PRACTICE QUESTIONS:
Q. Find a polynomial sum and product of whose roots are 4 and 1
respectively.
Solution: Here Sum (S) = 4 and product (P) = 1
Polynomial = x2- (Sum) x + Product
= x2 – 4x +1
Q. Find a polynomial whose roots are 2 and 5.
Solution: Here α = 2 and β = 5
Sum = α + β = 2 + 5 = 7
Product = α X β = 2 X 5 = 10
Polynomial = x2- (Sum) x + Product
= x2 – 7x +10
DIVISION ALGORITHM FOR POLYNOMIALS
If p(x) and g(x) are any two polynomials with g(x) ≠
𝟎 then we can find polynomials q(x) and r(x) such that
p(x) = g(x) × q(x) + r(x) where r(x) = 0 or
degree of r(x) < degree of g(x).
Here again, we see that
Dividend = Divisor × Quotient + Remainder
Divide: 3x2-x3-3x+5 by x-1-x2
Here Divisor is x-1-x2 = -x2 + x -1
and Dividend = 3x2– x3 -3x +5 = -x3 +3x2 – 3x + 5
Divide x4-3x2+4x+5 by x2-x+1
On dividing x3- 3x2+x+2 by a polynomial g(x) the
quotient = x-2 and remainder = -2x+4. Find g (x).
THANK
YOU BY:
Dr. VIVEK NAITHANI
T.G.T (MATHEMATICS), KVS
COPYRIGHT INFORMATION: CC by SA 4.0

Polynomials

  • 1.
    POLYNOMIALS BY: Dr. VIVEK NAITHANI T.G.T(MATHEMATICS), KVS COPYRIGHT INFORMATION: CC by SA 4.0
  • 2.
    DEFINITION An algebraic expressionthat contain two or more terms is called a polynomial. Each term of a polynomial has a co-efficient. For an algebraic expression to qualify for being a polynomial it is necessary that the power of variable in each term must be a positive integer. e.g. –x3+4x2+7x-2, 3y2+5y-7 etc. 𝑥 + 1 𝑥 is not a polynomial as the power of x in second term is -1 𝑦+5y is not a polynomial as the power of y is fraction in first term.
  • 3.
    A polynomial invariable can be expressed generally as anxn +an-1xn-1+an-2xn-2+…………..+ a2x2+a1x+a0 where an, an-1, an-2, …………., a2, a1, a0 are all constants not all zero and n is any positive integer.
  • 4.
    DEGREE OF APOLYNOMIAL The degree of a polynomial is the highest power of the variable appearing in the polynomial. e.g.: The degree of the polynomial x2-6x +7 is 2 as the highest power of x appearing in the given polynomial is 2. 3x5+4x2-2. Here the highest power of variable is 5 so the degree is 5
  • 5.
    CLASSIFICATION OF POLYNOMIALS: S.No.DEGREE NAME OF POLYNOMIAL 1 Zero (0) Constant Polynomial 2 One (1) Linear Polynomial 3 Two (2) Quadratic Polynomial 4 Three (3) Cubic Polynomial 5 Four (4) Bi-Quadratic Polynomial The polynomials on the basis of their degree can be classified as:
  • 6.
    PRACTICE QUESTIONS S.No. POLYNOMIALDEGREE 1 2 – y2 – y3 + 2y8 2 x5 – x4 + 3 3 5x2 + 3x + π 4 2 – x2 + x3 5 4t4 + 5t3 – t2 + 6 Write the degree of following polynomials.
  • 7.
    ZEROES OF APOLYNOMIAL:  The zero or root of a polynomial p(x) is the value of x at which p(x) = 0.  If for x=a, p(a) = 0 then we say x=a is the zero or root of p(x).  E.g.: p(x) = x2- 5x+6 is a polynomial. For x= 2, we get p(2) = (2)2 – 5(2) +6 = 4 -10 +6 = 10-10 =0 Hence x=2 is a root or zero of p(x).
  • 8.
    GEOMETRICAL MEANING OFZEROES OF A POLYNOMIAL  If p(x) is a polynomial and we plot the graph of p(x) on a graph sheet. The number of points of intersection of graph pf p(x) and X –axis represent the number of zeroes or roots of p(x).  A linear polynomial graph meets X axis at only one point.  A quadratic polynomial graph meets the X – axis at maximum two points.  A cubic polynomial graph meets the X – axis at maximum three points.
  • 9.
    GRAPH OF ALINEAR POLYNOMIAL Here p(x) = 5x-15, meets the X axis at A (3,0). So, x=3 is a root or zero of p(x). Graph of a linear function meets X –axis at maximum one point
  • 10.
    GRAPH OF AQUADRATIC FUNCTION Here p(x) = x2-x-6 meets X axis at A (-2,0) and B (3,0). So x= -2 and x=3 are the roots of p(x). The graph of a quadratic polynomial is a parabola and meets X –axis at maximum two points
  • 11.
    GRAPH OF ACUBIC FUNCTION Here p(x) = x3-7x; meets X- axis at A(-2.6,0); B(0,0); C(2.6,0). So, x= -2.6, 0 and +2.6 are the roots of p(x).
  • 12.
    RELATIONSHIP BETWEEN ZEROESAND CO- EFFICIENTS OF A POLYNOMIAL If ax2+bx+c is a quadratic polynomial whose roots are α and β. Then Sum of roots α + β = −𝒃 𝒂 = −(𝒄𝒐𝒆𝒇𝒇𝒊𝒄𝒊𝒆𝒏𝒕 𝒐𝒇 𝒙) (𝒄𝒐−𝒆𝒇𝒇𝒊𝒄𝒊𝒆𝒏𝒕 𝒐𝒇 𝒙𝟐) Product of roots α X β = c a = 𝑐𝑜𝑛𝑠𝑡𝑎𝑛𝑡 (𝒄𝒐−𝒆𝒇𝒇𝒊𝒄𝒊𝒆𝒏𝒕 𝒐𝒇 𝒙𝟐) The quadratic polynomial is: x2 –(Sum) x + (Product)
  • 13.
    If ax3+bx2+cx+d isa cubic polynomial whose roots are α, β and γ, then α + β + γ = −𝒃 𝒂 = − (𝒄𝒐𝒆𝒇𝒇𝒊𝒄𝒊𝒆𝒏𝒕 𝒐𝒇 𝒙𝟐 ) (𝒄𝒐−𝒆𝒇𝒇𝒊𝒄𝒊𝒆𝒏𝒕 𝒐𝒇 𝒙𝟑) αβ + βγ + γα = 𝒄 𝒂 = (𝒄𝒐−𝒆𝒇𝒇𝒊𝒄𝒊𝒆𝒏𝒕 𝒐𝒇 𝒙) (𝒄𝒐−𝒆𝒇𝒇𝒊𝒄𝒊𝒆𝒏𝒕 𝒐𝒇 𝒙𝟑) α X β X γ = −𝒅 𝒂 = −(𝒄𝒐𝒏𝒔𝒕𝒂𝒏𝒕 ) (𝒄𝒐−𝒆𝒇𝒇𝒊𝒄𝒊𝒆𝒏𝒕 𝒐𝒇 𝒙𝟑)
  • 14.
    FIND THE ZEROESAND VERIFY THE RELATIONSHIP BETWEEN CO-EFFS. & ZEROES (i) p(x) = x2- 2x- 8 Solving by splitting the middle term = x2 -4x+2x-8 now regrouping and taking out common factors = x(x-4) + 2 (x-4) = (x-4) (x+2) For p(x) = 0 ; Either x-4 = 0 ⇒ x=4 or x+2 = 0 ⇒ x = -2 Hence zeroes are α = 4 and β = -2 Now the coefficients are a = 1; b = -2 and c = -8 The sum of roots α + β = 4 +(-2) = 4-2 = 2 −𝑏 𝑎 = −(−2) 1 = 2 Hence α + β = −𝑏 𝑎 Product of roots = α X β = 4 X (-2) = -8 𝑐 𝑎 = (−8) 1 = -8 Hence α X β = 𝑐 𝑎 Hence relation is verified.
  • 15.
    (ii) 6x2 –3 -7x First arranging the terms in descending order of power 6x2- 7x – 3 Solving by splitting the middle term = 6x2 – 9x+ 2x -3 Regrouping and taking out common factor = 3x(2x-3) +1 (2x-3) = (2x-3) (3x+1) For p(x) = 0 Either 2x-3 = 0 ⇒ 2x= 3 ⇒ x= 3/2 Or 3x+1 = 0 ⇒ 3x = -1 ⇒ x = -1/3 Hence zeroes are α = 3/2 and β = -1/3 Now the coefficients are a = 6; b = -7 and c = -3 The sum of roots α + β = 3 2 + ( −1 3 ) = 9−2 6 = 7 6 −𝑏 𝑎 = −(−7) 6 = 7 6 The product of the roots α X β = 3 2 X ( −1 3 ) = −1 2 𝑐 𝑎 = −3 6 = −1 2 Hence relation is verified.
  • 16.
    PRACTICE QUESTIONS: Q. Finda polynomial sum and product of whose roots are 4 and 1 respectively. Solution: Here Sum (S) = 4 and product (P) = 1 Polynomial = x2- (Sum) x + Product = x2 – 4x +1 Q. Find a polynomial whose roots are 2 and 5. Solution: Here α = 2 and β = 5 Sum = α + β = 2 + 5 = 7 Product = α X β = 2 X 5 = 10 Polynomial = x2- (Sum) x + Product = x2 – 7x +10
  • 17.
    DIVISION ALGORITHM FORPOLYNOMIALS If p(x) and g(x) are any two polynomials with g(x) ≠ 𝟎 then we can find polynomials q(x) and r(x) such that p(x) = g(x) × q(x) + r(x) where r(x) = 0 or degree of r(x) < degree of g(x). Here again, we see that Dividend = Divisor × Quotient + Remainder
  • 18.
    Divide: 3x2-x3-3x+5 byx-1-x2 Here Divisor is x-1-x2 = -x2 + x -1 and Dividend = 3x2– x3 -3x +5 = -x3 +3x2 – 3x + 5
  • 19.
  • 20.
    On dividing x3-3x2+x+2 by a polynomial g(x) the quotient = x-2 and remainder = -2x+4. Find g (x).
  • 22.
    THANK YOU BY: Dr. VIVEKNAITHANI T.G.T (MATHEMATICS), KVS COPYRIGHT INFORMATION: CC by SA 4.0