Please write a function in C++ that reads from a txt file containing.pdf
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Please write a function in C++ that reads from a txt file containing two columns of integers. The function must find the union and intersection of the two columns. Thank you in advance for your help. Please write in basic beginner C++ code and include detailed comments so that I can understand the processes. Solution #include #include #include using namespace std; int main() { string name; cin>>name; ifstream ins; ins.open(name); int a,b; vector first,second; while(ins>>a) { ins>>b; first.push_back(a); second.push_back(b); } vector andd,orr; for(int i=0;i.
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Nessus is a network security toolIn a pragraph describe how it is .pdf
Nessus is a network security tool
In a pragraph describe how it is useful to a networksecurityspecialist and how it may be used for
harmfulpurposes by a hacker?
Note: provide relaiblerefrences for your answer.
Solution
Nessus:
Nessus is a proprietary vulnerability scanner.Nessus was developed by Tenable network security.
How it is useful?:
It is extremely good for discovering platform and network device vulnerabilities.
โขIt is a good automated tool for finding Mis configuration,default passwords and known
vulnerabilities on systems.
โขDenails of service against the TCP/IP stack by using malforme packets.
โขIt also has some web scanning options that can be configured,different types of ports scanning.
โขAnother useful Nessus opetion is the ability to enable(or) disable testing of embedded web
servers that may be adversely affectd, when scanned.
โขNessus provides the ability for the user to adjust how Nessus tests each CGI scrit and determine
the duration of the tests.
โขNessus also provides special features for Webmirroring.
How it may be used harmful purposses?:
If some one wanted to hack your local network,the first thing they do is run a vulnerability scan
then they\'d run a penetration test.
โขA vulnerability scan digs through the various devices on your network and looks for potential
holes,like open port,outdated software with known vulnerabilities.If they find any thing a hacker
would exploit them.
โขNessus is scan vulnerabilities and shoreup your home network.
โขNessus vulnerability scanner is fast and diverse tool that helps any size organization audit their
assets for security vulnerabilities.
โขsecurity center can organize network assets into categories through a combination of network
scanning,passive network monitoring and integration with existing asset and network
management data tools.
โขSecurity Center can manage scans of software under development to defect vulnerabilities,early
in the development cycle.
โขNessus is used to check the understanding operating system for any vulnerabilities in the
operating system application(or) database.
โขNessus can be used to check the configuration of the os,application and database.
โขNessus can performs a various of Web application audit to test for common aplication
vulnerabilities.
โขNessus provides special features for Web mirroring,allowing user to specify which part of the
website will be crawled(or)not.
โขNessus has ability to enable(or)disable testing of embedded web servers that may be adversely
affected when scanned.
โขThe pvs can monitor network traffic for encrypted data.
โขThe LCE can be used to monitor any logs generated by software.
โขLCE can make use of Web and Databse to look for application process and testing..
Luthans and Doh (2012) discuss two major forms of communication flow.pdf
Luthans and Doh discuss two forms of communication flow in organizations - upward communication, which involves information moving from lower to higher levels, and downward communication, which involves information moving from higher to lower levels. It is important for organizations to know which form of communication they use so they understand how information and feedback is shared throughout the organization.
Is the value of the Manufacturing Plant considered a long term or a .pdf
Is the value of the Manufacturing Plant considered a long term or a short term asset?
Solution
Answer :- Long term asset.
Explanation :- Manufacturing Plant would be considered as long-term asset because it would
appear (remain) in the balance sheet of firm / company for more than one financial (accounting)
year..
Indicate whether you agree or disagree with the following statements.pdf
Indicate whether you agree or disagree with the following statements and explain your
reasoning:
a) Rejean feels that an internal auditor that reports to the chief financial officer of the company
can be as independent as an auditor that reports to the audit committee.
b) Angela discovered a very material overstatement in the financial statements. She felt the
misstatement would have an impact on the decisions of users of the financial statements, and
indicated to her audit senior that she would be including it as an โemphasis of matterโ paragraph
in the audit report.
c) An auditor is responsible for the preparation and fair presentation of the financial statements
in accordance with IFRS, and for such internal control as is necessary to enable the preparation
of financial statements that are free from material misstatement, whether due to fraud or error.
d) An assurance engagement involves evaluation or measurement of subject matter against
criteria.
Solution
a) No, it can create conflict of interest and is not independent relationship as prescrbied best
practices for audit committeesโ oversight of internal auditors.
b) I agree with the statement as per INTERNATIONAL STANDARD ON AUDITING 706 ,
auditor should report misstatement which would have an impact on the decisions of users of the
financial statements, as an โemphasis of matterโ paragraph in the audit report.
c) I disagree as it is the responsibility of the management as per ISA 700
d) I agree, criterial like applicability of laws of land are evaluated and measured..
Identify any relative maxima or minima and intervals on which the fun.pdf
Identify any relative maxima or minima and intervals on which the function is decreasing and
increasing.
Solution
Maxima at (x, y) = ( 1, -1) ; we can see graph increases before the point and graph decreases
after
the point.
So, Interval of increase ( -inf , 1) , Interval of decrease (1,5)
Relative minima at (x, y) = (5, -10); we can see graph decreases before this point and increase
after
this point ( 5 , inf).
How exposure to an argument through mass media may have influenced o.pdf
How exposure to an argument through mass media may have influenced or not influenced
attitude change based on the level of involvement you have applied to your analysis (i.e. central
route or peripheral route processing). Provide example if you can, thanks!
Solution
Ans:- It is often stated that attitudes are comprised of two primary components, namely cognitive
and affective behaviour information. The way in which we evaluate something will be influenced
by these two factors. โCognitionโ refers primarily to the intelligent processing of information.
The term can also be used in a broader sense regarding the evaluation of knowledge and may
purely describe behaviour in terms of information flow or function (Wikipedia 2006). โAffectโ is,
however, used as a subordinate construct encompassing emotions and relatively transient moods
and feelings (Petty, Cacioppo, Sedikides & Strathman 1988: 357). The amount of mental
processing in which a person engages regarding a message varies along a continuum (Petty &
Cacioppo 1983: 23). At the core of the ELM is the elaboration continuum.
Routes of persuasion and the nature of the processing Whether persuasion occurs through the
central or peripheral route is determined by a personโs motivation and ability to think about the
issue-relevant information. According to Frederick (1996: 3), the most effective and efficient
advertisement emphasises the central route in message delivery, while using the peripheral route
only as a reinforcement of the cognitive approach. The central route The central route to
persuasion is highly dependent on the persuasive message content and quality (Petty & Cacioppo
1983: 21). The message recipient engages in issue-relevant thinking, characterised by
considerable cognitive (mental) elaboration (Perloff 2003: 129). Perloff (2003: 23) points out
that people process information centrally, by carefully evaluating message arguments,
considering the implications of communication ideas, and relating information to their own
knowledge and values. In simple terms, therefore, the central route to persuasion occurs when
the attitude of the audience, or individuals, is changed as a result of thoughtful consideration of
the message. Elaboration is high when the central route is utilised; in turn, involvement is also
high when individuals perceive that an issue is personally relevant and bears directly on their
own lives (Perloff 2003: 130). Attitudes that change along the central route persist longer and
predict subsequent behaviour. Factors that are part of the central route include prior knowledge
of the subject, strength of arguments and actual message content (Frederick 1996: 1). People
whose attitudes have been changed centrally are more likely to show attitude behaviour
consistency. When people participate in the extensive cognitive elaboration of central
processing, they build their own mental arguments and frequently access them, strengthening
their attitude; these attitudes are also .
Here is the company database--comments can be addedD.pdf
Here is the company database
--comments can be added
DROP TABLE works_on;
DROP TABLE dependent;
DROP TABLE project;
DROP TABLE dept_location;
ALTER TABLE department DROP CONSTRAINT fk_mgrssn CASCADE;
ALTER TABLE employee DROP CONSTRAINT fk_dno CASCADE;
DROP TABLE department;
DROP TABLE employee;
CREATE TABLE employee
(fnameVARCHAR2(12),
minitCHAR(1),
lnameVARCHAR2(12),
ssnCHAR(9) NOT NULL,
bdateDATE,
addressVARCHAR2(40),
sexCHAR(1),
salaryNUMBER(7) NOT NULL,
superssnCHAR(9) references employee(ssn),
/*superssnCHAR(9),*/
/*either way, but need to know superssn is from ssn*/
CONSTRAINT pk_ssn PRIMARY KEY (SSN));
ALTER TABLE employee ADD (dno NUMBER(2) NOT NULL);
INSERT INTO employee VALUES (\'Wolons\', \'E\', \'Aimee\', \'888665555\',
\'10-NOV-1927\', \'450 Stone, edsion, NJ\', \'F\', 55000, null,1);
INSERT INTO employee VALUES (\'Ramirez\', \'\', \'Damian\', \'987654321\',
\'20-JUN-1931\', \'291 Berry, albany, NY\', \'M\', 43000, \'888665555\',4);
INSERT INTO employee VALUES (\'Hall\', \'\', \'Nathan\', \'333445555\',
\'09-DEC-1945\', \'638 bruce, Oneonta, NY\', \'M\', 40000, \'888665555\',5);
INSERT INTO employee VALUES (\'Kelly\', \'\', \'David\', \'999778888\',
\'19-JUL-1958\', \'3321 central ave, New York, NY\', \'M\', 25000, \'987654321\',4);
INSERT INTO employee VALUES (\'Philip\', \'\', \'Dolensek\', \'123456789\',
\'09-JAN-1955\', \'731 clinton, Oneonta, NY\', \'M\', 30000, \'333445555\',5);
INSERT INTO employee VALUES (\'Reale\', \'\', \'Michael\', \'666884444\',
\'15-SEP-1952\', \'975 Fire Oak, Newark, NJ\', \'M\', 38000, \'333445555\',5);
INSERT INTO employee VALUES (\'Smith\', \'\', \'Jason\', \'453453453\',
\'31-JUL-1962\', \'5631 Rice, Harrison, NJ\', \'F\', 25000, \'333445555\',5);
INSERT INTO employee VALUES (\'Warren\', \'V\', \'Samantha\', \'987987987\',
\'29-MAR-1959\', \'908 Dallas, albany, NY\', \'F\', 25000, \'987654321\',4);
select e.fname, e.lname, s.fname, s.lname
from employee e, employee s
where e.superssn=s.ssn;
CREATE TABLE department
(dnameVARCHAR2(20) NOT NULL,
dnumberNUMBER(2) NOT NULL,
mgrssnCHAR(9) NOT NULL,
mgrstartdateDATE,
CONSTRAINT pk_dnumber PRIMARY KEY (DNUMBER),
CONSTRAINT fk_mgrssn FOREIGN KEY (mgrssn) REFERENCES employee (ssn));
INSERT INTO department VALUES (\'Research\',5 , \'333445555\', \'22-MAY-1978\');
INSERT INTO department VALUES (\'Administration\',4 , \'987654321\', \'01-JAN-1985\');
INSERT INTO department VALUES (\'Computing Service\', 1, \'888665555\', \'19-JUN-1971\');
ALTER TABLE employee ADD (CONSTRAINT fk_dno FOREIGN KEY (dno)
REFERENCES department(dnumber));
CREATE TABLE dept_location
(dnumberNUMBER(2) ,
dlocationVARCHAR2(20),
CONSTRAINT pk_num_loc PRIMARY key (dnumber, dlocation),
CONSTRAINT fk_dnumber FOREIGN KEY (dnumber) REFERENCES department(dnumber));
INSERT INTO dept_location VALUES (1,\'Fitzelle\');
INSERT INTO dept_location VALUES (4,\'Hunt union\');
INSERT INTO dept_location VALUES (5,\'Natza\');
INSERT INTO dept_location VALUES (5,\'Hunt union\');
INSERT INTO dept_location.
Find the IPv6 prefix of the address 20010fc3ca540 a0 10 if the .pdf
Find the IPv6 prefix of the address 2001::0fc3:ca54:0: a0: 10 if the prefix length is/64/48
Solution
Answer:
a) /64
Each octet in the ipv6 consists of 16 bits as each hexadecimal represents 4 bits, its prefix is :
2001:0:0:fc3::
It has 4 hexadecimal numbers = 16*4 = 64.
b) /48
Means first 48 bits are network part , hence the prefix of this ipv6 with prefix length 48 is : 2001:
0 : 0 ::.
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Nessus is a network security toolIn a pragraph describe how it is .pdf
Nessus is a network security tool
In a pragraph describe how it is useful to a networksecurityspecialist and how it may be used for
harmfulpurposes by a hacker?
Note: provide relaiblerefrences for your answer.
Solution
Nessus:
Nessus is a proprietary vulnerability scanner.Nessus was developed by Tenable network security.
How it is useful?:
It is extremely good for discovering platform and network device vulnerabilities.
โขIt is a good automated tool for finding Mis configuration,default passwords and known
vulnerabilities on systems.
โขDenails of service against the TCP/IP stack by using malforme packets.
โขIt also has some web scanning options that can be configured,different types of ports scanning.
โขAnother useful Nessus opetion is the ability to enable(or) disable testing of embedded web
servers that may be adversely affectd, when scanned.
โขNessus provides the ability for the user to adjust how Nessus tests each CGI scrit and determine
the duration of the tests.
โขNessus also provides special features for Webmirroring.
How it may be used harmful purposses?:
If some one wanted to hack your local network,the first thing they do is run a vulnerability scan
then they\'d run a penetration test.
โขA vulnerability scan digs through the various devices on your network and looks for potential
holes,like open port,outdated software with known vulnerabilities.If they find any thing a hacker
would exploit them.
โขNessus is scan vulnerabilities and shoreup your home network.
โขNessus vulnerability scanner is fast and diverse tool that helps any size organization audit their
assets for security vulnerabilities.
โขsecurity center can organize network assets into categories through a combination of network
scanning,passive network monitoring and integration with existing asset and network
management data tools.
โขSecurity Center can manage scans of software under development to defect vulnerabilities,early
in the development cycle.
โขNessus is used to check the understanding operating system for any vulnerabilities in the
operating system application(or) database.
โขNessus can be used to check the configuration of the os,application and database.
โขNessus can performs a various of Web application audit to test for common aplication
vulnerabilities.
โขNessus provides special features for Web mirroring,allowing user to specify which part of the
website will be crawled(or)not.
โขNessus has ability to enable(or)disable testing of embedded web servers that may be adversely
affected when scanned.
โขThe pvs can monitor network traffic for encrypted data.
โขThe LCE can be used to monitor any logs generated by software.
โขLCE can make use of Web and Databse to look for application process and testing..
Luthans and Doh (2012) discuss two major forms of communication flow.pdf
Luthans and Doh discuss two forms of communication flow in organizations - upward communication, which involves information moving from lower to higher levels, and downward communication, which involves information moving from higher to lower levels. It is important for organizations to know which form of communication they use so they understand how information and feedback is shared throughout the organization.
Is the value of the Manufacturing Plant considered a long term or a .pdf
Is the value of the Manufacturing Plant considered a long term or a short term asset?
Solution
Answer :- Long term asset.
Explanation :- Manufacturing Plant would be considered as long-term asset because it would
appear (remain) in the balance sheet of firm / company for more than one financial (accounting)
year..
Indicate whether you agree or disagree with the following statements.pdf
Indicate whether you agree or disagree with the following statements and explain your
reasoning:
a) Rejean feels that an internal auditor that reports to the chief financial officer of the company
can be as independent as an auditor that reports to the audit committee.
b) Angela discovered a very material overstatement in the financial statements. She felt the
misstatement would have an impact on the decisions of users of the financial statements, and
indicated to her audit senior that she would be including it as an โemphasis of matterโ paragraph
in the audit report.
c) An auditor is responsible for the preparation and fair presentation of the financial statements
in accordance with IFRS, and for such internal control as is necessary to enable the preparation
of financial statements that are free from material misstatement, whether due to fraud or error.
d) An assurance engagement involves evaluation or measurement of subject matter against
criteria.
Solution
a) No, it can create conflict of interest and is not independent relationship as prescrbied best
practices for audit committeesโ oversight of internal auditors.
b) I agree with the statement as per INTERNATIONAL STANDARD ON AUDITING 706 ,
auditor should report misstatement which would have an impact on the decisions of users of the
financial statements, as an โemphasis of matterโ paragraph in the audit report.
c) I disagree as it is the responsibility of the management as per ISA 700
d) I agree, criterial like applicability of laws of land are evaluated and measured..
Identify any relative maxima or minima and intervals on which the fun.pdf
Identify any relative maxima or minima and intervals on which the function is decreasing and
increasing.
Solution
Maxima at (x, y) = ( 1, -1) ; we can see graph increases before the point and graph decreases
after
the point.
So, Interval of increase ( -inf , 1) , Interval of decrease (1,5)
Relative minima at (x, y) = (5, -10); we can see graph decreases before this point and increase
after
this point ( 5 , inf).
How exposure to an argument through mass media may have influenced o.pdf
How exposure to an argument through mass media may have influenced or not influenced
attitude change based on the level of involvement you have applied to your analysis (i.e. central
route or peripheral route processing). Provide example if you can, thanks!
Solution
Ans:- It is often stated that attitudes are comprised of two primary components, namely cognitive
and affective behaviour information. The way in which we evaluate something will be influenced
by these two factors. โCognitionโ refers primarily to the intelligent processing of information.
The term can also be used in a broader sense regarding the evaluation of knowledge and may
purely describe behaviour in terms of information flow or function (Wikipedia 2006). โAffectโ is,
however, used as a subordinate construct encompassing emotions and relatively transient moods
and feelings (Petty, Cacioppo, Sedikides & Strathman 1988: 357). The amount of mental
processing in which a person engages regarding a message varies along a continuum (Petty &
Cacioppo 1983: 23). At the core of the ELM is the elaboration continuum.
Routes of persuasion and the nature of the processing Whether persuasion occurs through the
central or peripheral route is determined by a personโs motivation and ability to think about the
issue-relevant information. According to Frederick (1996: 3), the most effective and efficient
advertisement emphasises the central route in message delivery, while using the peripheral route
only as a reinforcement of the cognitive approach. The central route The central route to
persuasion is highly dependent on the persuasive message content and quality (Petty & Cacioppo
1983: 21). The message recipient engages in issue-relevant thinking, characterised by
considerable cognitive (mental) elaboration (Perloff 2003: 129). Perloff (2003: 23) points out
that people process information centrally, by carefully evaluating message arguments,
considering the implications of communication ideas, and relating information to their own
knowledge and values. In simple terms, therefore, the central route to persuasion occurs when
the attitude of the audience, or individuals, is changed as a result of thoughtful consideration of
the message. Elaboration is high when the central route is utilised; in turn, involvement is also
high when individuals perceive that an issue is personally relevant and bears directly on their
own lives (Perloff 2003: 130). Attitudes that change along the central route persist longer and
predict subsequent behaviour. Factors that are part of the central route include prior knowledge
of the subject, strength of arguments and actual message content (Frederick 1996: 1). People
whose attitudes have been changed centrally are more likely to show attitude behaviour
consistency. When people participate in the extensive cognitive elaboration of central
processing, they build their own mental arguments and frequently access them, strengthening
their attitude; these attitudes are also .
Here is the company database--comments can be addedD.pdf
Here is the company database
--comments can be added
DROP TABLE works_on;
DROP TABLE dependent;
DROP TABLE project;
DROP TABLE dept_location;
ALTER TABLE department DROP CONSTRAINT fk_mgrssn CASCADE;
ALTER TABLE employee DROP CONSTRAINT fk_dno CASCADE;
DROP TABLE department;
DROP TABLE employee;
CREATE TABLE employee
(fnameVARCHAR2(12),
minitCHAR(1),
lnameVARCHAR2(12),
ssnCHAR(9) NOT NULL,
bdateDATE,
addressVARCHAR2(40),
sexCHAR(1),
salaryNUMBER(7) NOT NULL,
superssnCHAR(9) references employee(ssn),
/*superssnCHAR(9),*/
/*either way, but need to know superssn is from ssn*/
CONSTRAINT pk_ssn PRIMARY KEY (SSN));
ALTER TABLE employee ADD (dno NUMBER(2) NOT NULL);
INSERT INTO employee VALUES (\'Wolons\', \'E\', \'Aimee\', \'888665555\',
\'10-NOV-1927\', \'450 Stone, edsion, NJ\', \'F\', 55000, null,1);
INSERT INTO employee VALUES (\'Ramirez\', \'\', \'Damian\', \'987654321\',
\'20-JUN-1931\', \'291 Berry, albany, NY\', \'M\', 43000, \'888665555\',4);
INSERT INTO employee VALUES (\'Hall\', \'\', \'Nathan\', \'333445555\',
\'09-DEC-1945\', \'638 bruce, Oneonta, NY\', \'M\', 40000, \'888665555\',5);
INSERT INTO employee VALUES (\'Kelly\', \'\', \'David\', \'999778888\',
\'19-JUL-1958\', \'3321 central ave, New York, NY\', \'M\', 25000, \'987654321\',4);
INSERT INTO employee VALUES (\'Philip\', \'\', \'Dolensek\', \'123456789\',
\'09-JAN-1955\', \'731 clinton, Oneonta, NY\', \'M\', 30000, \'333445555\',5);
INSERT INTO employee VALUES (\'Reale\', \'\', \'Michael\', \'666884444\',
\'15-SEP-1952\', \'975 Fire Oak, Newark, NJ\', \'M\', 38000, \'333445555\',5);
INSERT INTO employee VALUES (\'Smith\', \'\', \'Jason\', \'453453453\',
\'31-JUL-1962\', \'5631 Rice, Harrison, NJ\', \'F\', 25000, \'333445555\',5);
INSERT INTO employee VALUES (\'Warren\', \'V\', \'Samantha\', \'987987987\',
\'29-MAR-1959\', \'908 Dallas, albany, NY\', \'F\', 25000, \'987654321\',4);
select e.fname, e.lname, s.fname, s.lname
from employee e, employee s
where e.superssn=s.ssn;
CREATE TABLE department
(dnameVARCHAR2(20) NOT NULL,
dnumberNUMBER(2) NOT NULL,
mgrssnCHAR(9) NOT NULL,
mgrstartdateDATE,
CONSTRAINT pk_dnumber PRIMARY KEY (DNUMBER),
CONSTRAINT fk_mgrssn FOREIGN KEY (mgrssn) REFERENCES employee (ssn));
INSERT INTO department VALUES (\'Research\',5 , \'333445555\', \'22-MAY-1978\');
INSERT INTO department VALUES (\'Administration\',4 , \'987654321\', \'01-JAN-1985\');
INSERT INTO department VALUES (\'Computing Service\', 1, \'888665555\', \'19-JUN-1971\');
ALTER TABLE employee ADD (CONSTRAINT fk_dno FOREIGN KEY (dno)
REFERENCES department(dnumber));
CREATE TABLE dept_location
(dnumberNUMBER(2) ,
dlocationVARCHAR2(20),
CONSTRAINT pk_num_loc PRIMARY key (dnumber, dlocation),
CONSTRAINT fk_dnumber FOREIGN KEY (dnumber) REFERENCES department(dnumber));
INSERT INTO dept_location VALUES (1,\'Fitzelle\');
INSERT INTO dept_location VALUES (4,\'Hunt union\');
INSERT INTO dept_location VALUES (5,\'Natza\');
INSERT INTO dept_location VALUES (5,\'Hunt union\');
INSERT INTO dept_location.
Find the IPv6 prefix of the address 20010fc3ca540 a0 10 if the .pdf
Find the IPv6 prefix of the address 2001::0fc3:ca54:0: a0: 10 if the prefix length is/64/48
Solution
Answer:
a) /64
Each octet in the ipv6 consists of 16 bits as each hexadecimal represents 4 bits, its prefix is :
2001:0:0:fc3::
It has 4 hexadecimal numbers = 16*4 = 64.
b) /48
Means first 48 bits are network part , hence the prefix of this ipv6 with prefix length 48 is : 2001:
0 : 0 ::.
Explain the kinds of information that must be maintained in fixed as.pdf
Explain the kinds of information that must be maintained in fixed asset records during the asset
continuance phase.
Solution
Answer)
Here,Fixed assets continuance phase refers to update records accurately throughout their useful
life.
The information that is maintained is depreciation where different rates and methods may be
used for different assets which may be complex job but must be done accurately, any costs that
used to updation of asset and qualified for capitalisation, updation of estimated figures like
useful life of assets,expected salvage value and keeping track of physical location where the
asset is maintained..
Dr. P has a culture of stem cells and she wants them to specialize i.pdf
Dr. P has a culture of stem cells and she wants them to specialize into heart muscle cells for
treating a patients who suffered a heart attack that weakened his heart muscle. What will she
need to do to coax the stem cells into becoming heart muscle cells?
A. She will need to add certain chemicals to the culture, stimulating the cells to specialize.
B. She will need to expose the cells to human blood.
C. She will need to insert the cells into an embryo in the location where the heart would normally
develop.
D. She will need to zap the culture of cells with electricity, resembling the electrical signals of
the heart.
E. She will need to insert human heart genes into the nucleus of the stem cells.
Solution
Question : Dr. P has a culture of stem cells and she wants them to specialize into heart muscle
cells for treating a patients who suffered a heart attack that weakened his heart muscle. What will
she need to do to coax the stem cells into becoming heart muscle cells?
Answer: B. She will need to expose the cells to human blood..
Describe two ecological roles of fungi. Related concepts decomposer.pdf
Describe two ecological roles of fungi. Related concepts: decomposers, mycorrhizal symbiont.
Solution
Fungi as Decomposers
Fungi join bacteria as the primary decomposers in different ecosystems. They feed on the
organic remains of dead plants. They release special enzymes that break down lignin, a
structurally complex substance in wood. Because of their ability to break down wood, fungi are
considered the major wood decomposers in forests. To absorb organic matter, fungi release acids
to melt organic matter, and then they suck the acid back together with the melted organic matter.
Decomposing organic matter is considered by ecologists as the major ecological role of fungi.
Plant-Fungi Symbiosis
The symbiotic association between a vascular plant root and fungi is called mycorrhiza. In this
association, fungi colonize the roots of a plant and gain access to their tissues. The fungi build a
connection to the roots in such a way that they can exchange nutrients with each other. Plants
provide mycorrhizal fungi shelter and a supply of carbohydrates; in return, mycorrhizal fungi
improve the plantโs absorption capabilities for water and nutrients. Mycorrhizal fungi have a
larger surface-area ratio compared to roots, so they have higher absorptive capacity for water and
minerals. They make it easier for plants to absorb water and minerals in soils that are dry and
with low mineral concentration. Without mycorrhiza, it would be difficult for plants to absorb
water and minerals from such soils. It is estimated that about 90% of plants depends on
mycorrhizal fungi for survival..
Differential equations using phase plane analysis. Task 1 (Romeo .pdf
Differential equations using phase plane analysis. Task 1 (Romeo and Juliet). Let R and J be
variables which measure the love/hate that Romeo and Juliet, respectively, have for the other
star-erassed lower. We consider their relationship as described by a system of the form The
parameters a, b,c, d determine the evalution of their relationship ower time. The signs of the
variables a, b determine what kind of lover Romeo is, Of course, the signs of the variables c, d
play exactly the same roles for Juliet. For each arrangement of passible signs of a,b explain how
Romeo\'s feelings for Juliet change depending on the current state of things. Then make up a
descriptive name for the kind of lover Romeo is given those variables. (Remember that these
apply to Juliec just as well, so if you would rather, yau may work with J, e, d.) Please remember
that the sign of a number is either positive, negative, or zero Explore the different kinds of things
that happens when you pair poten- tial Romeos and Juliets. Which kinds of pairs are doomed to
terrible fates? Which pairs make for happy coll What interesting things ples? you say?
Solution
(1) dR/dT = aR+bJ = f(R,J) form here T is time
dR/dT = (1)(aR+bJ) dR/(aR+bJ) = dT {let us take J value as constant though it is given as a
variable consider nly this equation}
integrate on both sides we get 1/a ln(aR+bJ) + k = T
similarly in second equation if we take R as constant we get 1/d ln(cR+dJ) + k\' = T
we get aR+bJ = e^(a(T-k)) that is an exponential form
it comes closer to 0 only when a value is large and negative J value also similarly comes as
exponential form e^(d(T-K\'))
a(+ve) , b(+ve) love increases ; a(+ve), b(-ve) love increases so much with time
a(-ve) , b(+ve) love increases (since in equation -ve on both sides so get cancelled)
a(-ve) , b(-ve) love depends on b and J numerical values same thing applies to equation dJ/dT
(2) above we can see that in three cases love only increases with time only in 4th case it depends
on juliet when he is totally negative for her similarly for juliet only in one case it depends on
romeo
so we can conclude that love only increases with time and the couple in which love exists at least
with one will remain happy.
Develop a stack in c with dynamic memory allocation. Use the followi.pdf
Develop a stack in c with dynamic memory allocation. Use the following structure to create a
stack:t
typedef struct Element
{
char c;
struct Element *next;
} Element_Type, *Pointer_Type;
You need to develop the following functions:
1) push(): demands two arguemnts of which the first nominates a pointer. For example,
push(&x, โAโ) to push โAโ onto stack X. You need to allocate memory for a new element.
2) pop(): pops and returns the element on the top of the stack and frees the memory space which
was occupied by the element.
3) peep(): simply returns the character value of the top element of the stack. No pointers are
disturbed.
4) displayAll(): prints all character values of all elements of the stack from top to bottom.
void push(Pointer_Type *q, char ch){โฆโฆ}
char pop(Pointer_Type *q){โฆโฆ}
char peep(Pointer_Type *q){โฆโฆ}
void displayAll(Pointer_Type *q){โฆโฆ}
Test your stack and all functions with at least 10 elements.
Solution
#include
#include
#include
struct Element
{
char c;
struct Element *next;
};
struct Element *start=NULL;
void push()
{
char ele;
struct Element *new_ele,*temp;
int i=0;
for(temp=start;temp!=NULL;temp=temp->next)
{
i++;
}
if(i==10)
{
printf(\"Stack Overflow\");
getch();
}
else
{
new_ele=(struct Element *)malloc(sizeof(struct Element));
printf(\"Enter value for Element: \");
scanf(\"%c\",&new_ele->c);
new_ele->next=start;
start=new_ele;
}
}
void pop()
{
struct Element *temp,*temp2;
int i=0;
for(temp=start;temp!=NULL;temp=temp->next)
{
i++;
}
if(i==0)
{
printf(\"Underflow\");
getch();
}
else
{
temp2=start->next;
start=temp2;
printf(\"\ ***The value has been poped***\ \");
}
}
void display()
{
struct Element *temp;
printf(\"\ ****Stack Values****\ \");
for(temp=start;temp!=NULL;temp=temp->next)
{
printf(\"%c\ \",temp->c);
}
getch();
}
void peep()
{
struct Element *temp;
int pos,i=0,j=0;
printf(\"Please enter the position number: \");
scanf(\"%d\",&pos);
for(temp=start;temp!=NULL;temp=temp->next)
{
i++;
}
if(pos>i)
{
printf(\"\ Over Limit\ \");
getch();
}
else
{
temp=start;
for(j=0;jnext;
}
printf(\"\ The value of position %d is :%c\",pos,temp->c);
getch();
}
}
int main()
{
int ch;
while(ch!=6)
{
printf(\"\ 1.Push\ \");
printf(\"2.Pop\ \");
printf(\"3.Peep\ \");
printf(\"4.Display\ \");
printf(\"5.exit\ \");
printf(\"Enter your choice:\");
scanf(\"%d\",&ch);
switch(ch)
{
case 1: push();
break;
case 2: pop();
break;
case 3: peep();
break;
case 4: display();
break;
case 5: exit(0);
}
}
return 0;
}.
Define a struct type that represents a smartphone. The struct should.pdf
Define a struct type that represents a smartphone. The struct should store the following data:
model (a character array of size 30), color (a character), and storage space (an integer). The type
should be renamed from struct smartphone to Smartphone.
Solution
struct smartphone {
char model[30];
char color;
int storageSpace;
};
typedef smartphone Smartphone;.
Changes in the economy have determined that for the EZ shipping comp.pdf
Changes in the economy have determined that for the EZ shipping company, a surcharge will be
assessed on all packages that meet certain criteria. The surcharge is a function of the
characteristics of the package and the zip code to which it is sent.
1. The regular charges for shipping are calculated as follows:
For all weights five pounds and under, the shipping cost is $12.00.
For weights over five pounds, the charge is calculated as follows:
If length * width * height + weight is:
greater than 5 and less than or equal to 15, the shipping cost is 14.00
greater than 15 and less than or equal to 34, the shipping cost is 17.00
greater than 34 and less than or equal to 45, the shipping cost is 21.00
greater than 45 and less than or equal to 60, the shipping cost is 33.00
greater than 60, the shipping cost is 105.00
2. The additional charges are calculated as follows:
If the first digit of the zip code is a \"4\" then there is an additional surcharge of 5% on
the shipping cost.
If the first digit of the zip code is a \"6\" then there is an additional surcharge of 9% on the
shipping cost.
For all other zip codes there is an additional surcharge of 14% on the shipping cost.
3. Finally, if the zip code is even, then there is an additional surcharge of 2% of the shipping
cost.
Write a program that allows the user to input (in this order) the zip code, weight, length, width
and height of the package then prints out the following:
The zip code and dimensions of the package
The shipping cost
The surcharge
The total shipping cost (shipping cost plus surcharge(s))
I have written out the code and have been able to get it to run but when I added in the 2% for
even numbers portion of my code every thing went weird with my outputs. Every thing still
compiles and works but I am not recieving the outputs I desire. Any help remedying this would
be greatly appreciated.
import java.util.Scanner;
//allows use of scanner for keyboard inputs
public class Shipping
// Class titling
{
public static void main(String[] args)
{
{
int zip;
double weight;
double length;
double width;
double height;
double surcharge;
double surcharge2;
double shippingCost;
//Variables that will need defining for the shipping process
Scanner keyboard = new Scanner(System.in);
System.out.println(\"Hello, Welcome to EZ Shipping services! \ Please input the important
details of your shipment when prompted\");
System.out.println(\"What is the weight of your package? \");
weight = keyboard.nextDouble();
System.out.println(\"What is the length of your package? \");
length = keyboard.nextDouble();
System.out.println(\"What is the width of your package? \");
width = keyboard.nextDouble();
System.out.println(\"What is the height of youre package? \");
height = keyboard.nextDouble();
//Print outs for package detail inputs
double packages=length*width*height+weight;
//Package variables combined and stored
{
shippingCost = 12;
//Stock sipping cost 12$
}
if (weight >5)
{
if (packages >=5.1 || packages <= 1.
Broadly speaking, the economy consists of households, firms, governm.pdf
Broadly speaking, the economy consists of households, firms, government, and financial
institutions. Name two parts, areas, or types of government that can have influence over the
economy
Solution
Explanation:
- Financial policy:
Monetary Policy of any government can have major impact on economy of a nation since it has
the power to stimulate the economy and change the way economy behave. Financial policies are
performing major part in economy and it can make or break economy. How the taxes are levied
can majorly impact economy. Financial policies move control the flow of the money and it can
inject new money flow in system to revive it.
- Fiscal Policy:
Another major player in stimulating and impacting economy at it best is fiscal policy. Fiscal
policy mainly works to overcome from struggling economy and reduce the inflation in market.
Interest rate is popular tool to control the flow money through changing interest rates..
A committee consists of 13 Republicans and 16 Democrats. How many dif.pdf
A committee consists of 13 Republicans and 16 Democrats. How many different subcommittees
of 5 can be formed if the subcommittee must consist of 4 Republicans and 1 Democrats?
Solution
Total Republican = 13
Total democrats = 16
We need to select 4 Republican and 1 democrats.
Number of different subcommittee = 13C4 * 16C1
= 13!/(4!*9!) * 16!/(1!*15!)
= 11440.
2. July 01 Record the dividend received from the foreign subsidiary..pdf
2. July 01 Record the dividend received from the foreign subsidiary.
3. December 31 Record the equity in the net income of the foreign subsidiary.
4. December 31 Record the amortization of the differential. On January 1, 20X5, Pirate
Company acquired all of the outstanding stock of Ship Inc., a Norwegian company, at a cost of
$167,400 Ship\'s net assets on the date of acquisition were 700,000 kroner (NKr). On January 1,
20X5, the book and fair values of the Norwegiarn subsidiary\'s identifiable assets and liabilities
approximated their fair values except for property, plant, and equipment and patents acquired.
The fair value of Ship\'s property, plant, and equipment exceeded its book value by $18,000. The
remaining useful life of Ship\'s equipment at January 1, 20X5, was 10 years. The remainder of
the differential was attributable to a patent having an estimated useful life of 5 years. Ship\'s trial
balance on December 31, 20X5, in kroner, follows: Debits Credits NKr 160,000 218,000
277,000 609,000 Cash Accounts Receivable (net) Inventory Property, Plant & Equipment
Accumulated Depreciatiorn Accounts Payable Notes Payable Common Stock Retained Earnings
Sales Cost of Goods Sold Operating Expenses Depreciation Expense Dividends Paid Total NKr
167,000 91,000 209,000 430,000 270,000 745,000 421,000 125,000 61,000 41,000
NKr1,912,000 NKr1,912,000
Solution
TotalCash32,000Accounts Receivable43,600Inventory55,400Property, plant, &
machinery121,800Cost of Goods Sold84,200Operating expenses25,000Depreciation
Expense12,200Dividends Paid8,200Total382,400Total Debits382,400Accumulated
Depreciation33,400Accounts Payable18,200Notes Payable41,800Common Stock86,000Retained
Earnings54,000Sales149,000
Total382,400.
You have isolated a new virus, determined it has a lipid envelope,.pdf
You have isolated a new virus, determined it has a lipid envelope, and wish to characterize the
mechanism of entry. Discuss the important research questions you would ask and the types of
experiments you might use to address the questions.
You have isolated a new virus, determined it has a lipid envelope, and wish to characterize the
mechanism of entry. Discuss the important research questions you would ask and the types of
experiments you might use to address the questions.
Solution
Answer: (There may be several questions related to the attachment and entry process, a few have
been discussed)
The first encounter between a virus and a target cell occurs at the plasma membrane. It is here
that viruses first engage binding and entry receptors to initiate the infection process.
Specific research questions on the mechanism of entry of this virus may be:
1. Adhesion and attachment:
While normally non-specific in nature, different glycosphingolipids on the viral surface have
been reported to confer cell specificity: the sialyllactose moiety on human immunodeficiency
virus (HIV) membrane gangliosides, for instance, has been suggested to promote uptake of HIV
into mature dendritic cells (mDCs).
So, it can be asked whether the mechanism of entry is through specific glycosphingolipids and
new roles of these glycosphingolipids?
Experiments: Using liposomes to mimic the lipid composition and size of the virus, it can be
demonstrate whether gangliosides are the key molecules that mediate liposome uptake.
Liposome and VLP (virus like particle) capture assays on cultured cells, confocal microscopy
and neuraminidase assay with VLP and LUV (large unilamellar vescicles) can be used for the
investigation.
2. Lipid-mediated signalling for entry:
Low-density lipoprotein receptors, negatively charged phospholipids and gangliosides have all
been shown to assist entry of different viruses. Low-density lipoprotein receptors, also known as
cholesterol receptors, are used by several members of the Flaviviridae family, including hepatitis
C virus (HCV).
The interaction is likely to occur through lipoproteins associated with the virion, such as
cholesteryl esters and apolipoproteins (ApoB and ApoE) acquired during the assembly and
budding of virus.
So, it can be determined whether the LDL receptor acts as a receptor for this new virus and
whether the endocytosis of the virus correlated with the level of LDL receptors?.
Investigation of endocytosis of the virus by cultured cells in vitro can be demonstrated to have
LDL receptors with the use of anti-LDL receptor antibody or DiI-LDL uptake. These cell lines
can then be inoculated with a high titer virus positive serum. Intracellular viral RNA then can be
detected by using ISH.
To determine whether endocytosis of the virus correlated with the level of LDL receptor
expression on cells, the well known modulatory effect of lipoproteins on the LDL receptor can
be used to increase the number of LDL receptors (up-regulate) on cel.
Write the Java source code necessary to build a solution for the pro.pdf
Write the Java source code necessary to build a solution for the problem below:
Create a MyLinkedList class. Create methods in the class to add an item to the head, tail, or
middle of a linked list; remove an item from the head, tail, or middle of a linked list; check the
size of the list; and search for an element in the list.
Create a test class to use the newly created MyLinkedList class. Add the following names in to
the list: James, John, Michael, Peter, Allison, Daniel, George, Simon, Jason, and Mark. Your
program should allow the user to enter a name from the console, and then search to see if the
name exists in the list.
Solution
Hi, Please find my implementation.
Please let me know in case of any issue.
public class MyLinkedList {
static class Node{
String data;
Node next;
Node(String d){
data = d;
next =null;
}
}
private Node head;
public MyLinkedList() {
head = null;
}
public void append(String data){
if(head == null)
head = new Node(data);
else{
Node temp = head;
while(temp.next != null)
temp = temp.next;
temp.next = new Node(data);
}
}
public void addFront(String data){
Node newNode = new Node(data);
newNode.next = head;
head = newNode;
}
public void removeFromLast(){
if(head == null || head.next == null)
head = null;
else{
Node temp = head;
while(temp.next.next != null)
temp = temp.next;
temp.next = null; // removing last element
}
}
public void removeFirst(){
if(head == null)
return;
else
head = head.next;
}
public boolean search(String data){
Node temp = head;
while(temp != null){
if(temp.data.equals(data))
return true;
temp = temp.next;
}
return false;
}
public void addAtMiddle(String data){
Node slow = head;
Node fast = head;
Node prev = null;
Node newNode = new Node(data);
if(head == null || head.next == null){
newNode.next = head;
head = newNode;
return;
}
while(fast != null && fast.next != null){
fast = fast.next.next;
prev = slow;
slow = slow.next;
}
if(prev != null)
prev.next =newNode;
newNode.next = slow;
}
public void removeAtMiddle(){
Node slow = head;
Node fast = head;
Node prev = null;
if(head == null || head.next == null){
head = null;
return;
}
while(fast != null && fast.next != null){
fast = fast.next.next;
prev = slow;
slow = slow.next;
}
prev.next = slow.next;
}
public void display(){
Node temp = head;
while(temp != null){
System.out.print(temp.data+\" \");
temp =temp.next;
}
System.out.println();
}
}
public class MyLinkedListTest {
public static void main(String[] args) {
MyLinkedList list = new MyLinkedList();
list.addAtMiddle(\"James\");
list.display();
list.addAtMiddle(\"John\");
list.display();
list.addAtMiddle(\"Michael\");
list.display();
list.addAtMiddle(\"Peter\");
list.display();
list.addAtMiddle(\"Allison\");
list.display();
list.addFront(\"Daniel\");
list.display();
list.append(\"George\");
list.display();
list.addFront(\"Simon\");
list.display();
list.append(\"Jason\");
list.display();
list.addAtMiddle(\"Mark\");
list.display();
list.removeAtMiddle();
list.display();
list.removeFirst();
list.displ.
Why is agrobacterium tumfaciens useful to Kant biologists Describ.pdf
Why is agrobacterium tumfaciens useful to Kant biologists? Describe in detail the steps a
researcher must take to get the desired DNA to hitch a ride on the back of Agro.
Why is agrobacterium tumfaciens useful to Kant biologists? Describe in detail the steps a
researcher must take to get the desired DNA to hitch a ride on the back of Agro.
Solution
Reasons
Agrobacterium has a special plasmid called Ti (Tumor inducing) plasmid.It has TDNA (transfer
DNA) which has the capability of transferring into the the plant cell and induce tumors.
It is naturally attracted towards the wound site by chemicals
It can transfer foreign to plants
The Vie gene will induce the tumorogenic pathway
Method
Explants are a small portion of a plant. E.g.: seedling, protocols, leaf disc etc
A wound is created in explant and incubated with Agrobacterium and acetosyringone.
Acetosyringone is a phenolic product which attracts the Agrobacterium towards the wound.
The explant and Agrobacterium are co cultivated and are transferred to a selective medium
which contains antibiotic.
The presence of antibiotic resistant gene in the Explants will enable the selection and it is
transferred to a media which develops the transformed cell to a callus.
On adding appropriate plant nutrients, roots and shoots are generated. These are transferred to a
pot or field to develop into a adult plant..
Why are the payback and Accounting or Average Rate of Return sometim.pdf
Why are the payback and Accounting or Average Rate of Return sometimes refer as
unsophisticated methodologies?
Solution
The payback period is one of the most widely used tools for evaluating capital projects.The
payback period represents the number of years it takes for the cash flows from a project to
recover the projectโs initial investment.Payback period is considered as unsophisticated
methodologies because it does not account for time value of money.It does not consider cash
flows past the payback period.It is biased against long term projects such as research and
development and new product launches.
Accounting or Average Rate of Return is considered as unsophisticated methodologies because it
also does not account for time value of money.It does not consider the external factors that are
also affecting the profitability of project.Accounting or Average Rate of Return cannot be
applied in a project where investments are made in parts and in real life, a lot of investmentss are
made in parts.So, it is considered as unsophisticated methodologies..
Which of the following are potential differences between the Prokary.pdf
Which of the following are potential differences between the Prokaryotic and Eukaryotic ETC?
(Choose all that apply)
Prokaryotes have Branched ETC
Eukaryotes have longer ETC
Prokaryotes use different systems to respond to oxygen concentrations
All of the proteins in the ETC are shared between Prok. and Euk.
The P/O ratio is higher in Prkaryotes
The P/O ratio is higher in EukaryotesA.
Prokaryotes have Branched ETCB.
Eukaryotes have longer ETCC.
Prokaryotes use different systems to respond to oxygen concentrationsD.
All of the proteins in the ETC are shared between Prok. and Euk.E.
The P/O ratio is higher in PrkaryotesF.
The P/O ratio is higher in Eukaryotes
Solution
B)Eukaryotes have longer ETC
the electron transport chain is long in eukaryotes ascompared to the prokaryotes..
When dividing, do we need to report remainder Why When dividi.pdf
When dividing, do we need to report remainder? Why?
When dividing, do we need to report remainder? Why?
Solution
Sometimes when dividing there is something left over. It is called the remainder.
Example: There are 7 bones to share with 2 pups.
But 7 cannot be divided exactly into 2 groups, so each pup gets 3 bones,
and there is 1 left over..
What are socioecology and sociobiology What can they tell us about .pdf
What are socioecology and sociobiology? What can they tell us about primate behavior? Use at
least two non-human primate species in your answe
Solution
Answer:
Socioecology focuses on the relationship between social behavior and the natural environment
and favors selection for the individualโs daily survival. Sociobiology focuses on the genetic
predisposition to behaviors and those behaviorsโ enhancement of reproductive success.
Socioecology:
1. Primatologists consider the following environmental factors:
a. Quality and quantity of different foods
b. Distribution of food resources, water, predators and sleeping sites
c. Activity patterns (diurnal, nocturnal)
d. Relationship with other species
e. Impact of human activities
2. Environmental factors such as resource availability and predation have a strong influence on
group size and structure.
3. Multimale and multifemale groups have an advantage when predation pressure is high. Adult
males may join forces to chase and attack predators. (Savannah baboons have been known to kill
domestic dogs and to attack leopards and lions)
4. Solitary foraging may be related to diet and distribution of resources or predator avoidance.
Sociobiology:
1. Natural selection acts on behavior in the same way it acts on physical characteristics.
2. Behavior is a phenotypic expression and genes code for specific behaviors.
3. This approach provides an opportunity to study the effects natural selection has had in shaping
primate behavior.
Nonhuman primates are research subjects because they are so similar to humans. Shared ancestry
is a major reason why human and nonhuman primates have many characteristics in common:
tool use, long-lasting social relationships, and complex communication systems. By learning
about nonhuman primates we may come to learn more about ourselves.
Individuals of certain nonhuman primate species, however, are bipedal for some activities. By
studying those species of nonhuman primates that are occasionally bipedal, and discovering the
circumstances in which they display bipedality, we may gain some understanding of the factors
that promoted the evolution of bipedality in humans.
Human and nonhuman primates also share physiological characteristics. For example, the way in
which the brains of rhesus monkeys and humans are organized is similar. One brain area that has
been studied extensively is the visual system.
Neuroanatomical studies of the nonhuman primate brain have been extremely useful in helping
us to understand how the human brain functions and how we see. In this way, nonhuman
primates serve as models of particular processes. Study of nonhuman primates has also
contributed to our understanding of basic biological phenomena such as reproduction; to better
understanding of diseases such as AIDS.
Nonhuman primates are also studied because they are fascinating animals. They live in a wide
range of habitats, and show many interesting differences in behavior and life styles. For example,
in so.
Using the code below, answer the questionsFor the toolbar, press AL.pdf
Using the code below, answer the questions:For the toolbar, press ALT+F10 (PC) or
ALT+FN+F10 (Mac).
Solution
1. Wo is an interface which contains unimplemented methods. It is similar to class and contains
collection of abstract method. Here we can see it has one unimplemented methods doThat().
2. doThat() is implemented in Roo because the Roo class implements Wo , So any class that
implements Wo has to compulsory implement doThat() method , otherwise the compiler will
throw a compile time error saying implement the unimplemented methods.
c) List the methods available to a Roo object.
Parent as well as child class methods as well its own implemnted methods..
true or false Strategy formulation and execution is a sequential pr.pdf
true or false: Strategy formulation and execution is a sequential process
Solution
Correct answer is True
Strategy formulation and executon are the consecutive steps of the process of strategy
management. Once the information collection is over and the collected information is alalyzed,
the strategy is formulated and the implementation is done for the formulated strategies. It is
formulated by the evaluation of the execution process and taking the control measures..
The symptoms of depression that occur in a person diagnosed with bip.pdf
The symptoms of depression that occur in a person diagnosed with bipolar disorder are ____.
distinct from the symptoms in unipolar disorder
the same as the symptoms in major depressive disorder
distinct from the symptoms in major depressive disorder
the same as the symptoms in obsessive-compulsive disordera.
distinct from the symptoms in unipolar disorderb.
the same as the symptoms in major depressive disorderc.
distinct from the symptoms in major depressive disorderd.
the same as the symptoms in obsessive-compulsive disorder
Solution
The symptoms of depression that occur in a person diagnosed with bipolar disorder are distinct
from the symptoms in major depressive disorder ..
skeleton System.pdf (skeleton system wow)
๐ฅ๐ฅ๐ฅ๐ฅ๐ฅ๐ฅ๐ฅ๐ฅ๐ฅ
โ โุฅุถุบ ุจูู ุฅูุฏููู
โู
ู ุฃููู ุงูู
ูุงุฒู
ุงูุชู ุตู
ู
ุชูุง
ู
ูุฒู
ุฉ ุชุดุฑูุญ ุงูุฌูุงุฒ ุงูููููู (ูุธุฑู 3)
๐๐๐๐๐๐๐๐๐๐
ุชุชู
ูุฒ ูุฐูู ุงูู
ูุฒู
ุฉ ุจุนูุฏุฉ ู
ูู
ูุฒุงุช :
1- ู
ูุชุฑุฌู
ุฉ ุชุฑุฌู
ุฉ ุชููุงุณุจ ุฌู
ูุน ุงูู
ุณุชููุงุช
2- ุชุญุชูู ุนูู 78 ุฑุณู
ุชูุถูุญู ููู ููู
ุฉ ู
ูุฌูุฏุฉ ุจุงูู
ูุฒู
ุฉ (ููู ููู
ุฉ !!!!)
#ููู
_ู
ุงูู_ุฏุฑุฎ
3- ุฏูุฉ ุงููุชุงุจุฉ ูุงูุตูุฑ ุนุงููุฉ ุฌุฏุงู ุฌุฏุงู ุฌุฏุงู
4- ูููุงูู ุจุนุถ ุงูู
ุนููู
ุงุช ุชู
ุชูุถูุญูุง ุจุดูู ุชูุตููู ุฌุฏุงู (ุชูุนุชุจุฑ ูุฏู ุงูุทุงูุจ ุฃู ุงูุทุงูุจุฉ ุจุฅููุง ู
ุนููู
ุงุช ู
ูุจูู
ุฉ ูู
ุน ุฐูู ุชู
ุชูุถูุญ ูุฐูู ุงูู
ุนููู
ุงุช ุงูู
ูุจูู
ุฉ ุจุดูู ุชูุตููู ุฌุฏุงู
5- ุงูู
ูุฒู
ุฉ ุชุดุฑุญ ููุณูุง ุจ ููุณูุง ุจุณ ุชููู ุชุนุงู ุงูุฑุงูู
6- ุชุญุชูู ุงูู
ูุฒู
ุฉ ูู ุงูู ุณูุงูุฏ ุนูู ุฎุงุฑุทุฉ ุชุชุถู
ู ุฌู
ูุน ุชูุฑูุนุงุช ู
ุนููู
ุงุช ุงูุฌูุงุฒ ุงูููููู ุงูู
ุฐููุฑุฉ ูู ูุฐูู ุงูู
ูุฒู
ุฉ
ูุงุฎูุฑุงู ูุฐูู ุงูู
ูุฒู
ุฉ ุญูุงูู ุนูููู
ูุฅุชู
ูู ู
ููู
ุฅู ุชุฏุนููู ุจุงูุฎูุฑ ูุงูุตุญุฉ ูุงูุนุงููุฉ ููุท
ูู ุงูุชูููู ุฒู
ูุงุฆู ูุฒู
ููุงุชู ุ ุฒู
ูููู
ู
ุญู
ุฏ ุงูุฐูุจู ๐๐
๐ฅ๐ฅ๐ฅ๐ฅ๐ฅ๐ฅ๐ฅ๐ฅ๐ฅ
More Related Content
More from fckindswear
Explain the kinds of information that must be maintained in fixed as.pdf
Explain the kinds of information that must be maintained in fixed asset records during the asset
continuance phase.
Solution
Answer)
Here,Fixed assets continuance phase refers to update records accurately throughout their useful
life.
The information that is maintained is depreciation where different rates and methods may be
used for different assets which may be complex job but must be done accurately, any costs that
used to updation of asset and qualified for capitalisation, updation of estimated figures like
useful life of assets,expected salvage value and keeping track of physical location where the
asset is maintained..
Dr. P has a culture of stem cells and she wants them to specialize i.pdf
Dr. P has a culture of stem cells and she wants them to specialize into heart muscle cells for
treating a patients who suffered a heart attack that weakened his heart muscle. What will she
need to do to coax the stem cells into becoming heart muscle cells?
A. She will need to add certain chemicals to the culture, stimulating the cells to specialize.
B. She will need to expose the cells to human blood.
C. She will need to insert the cells into an embryo in the location where the heart would normally
develop.
D. She will need to zap the culture of cells with electricity, resembling the electrical signals of
the heart.
E. She will need to insert human heart genes into the nucleus of the stem cells.
Solution
Question : Dr. P has a culture of stem cells and she wants them to specialize into heart muscle
cells for treating a patients who suffered a heart attack that weakened his heart muscle. What will
she need to do to coax the stem cells into becoming heart muscle cells?
Answer: B. She will need to expose the cells to human blood..
Describe two ecological roles of fungi. Related concepts decomposer.pdf
Describe two ecological roles of fungi. Related concepts: decomposers, mycorrhizal symbiont.
Solution
Fungi as Decomposers
Fungi join bacteria as the primary decomposers in different ecosystems. They feed on the
organic remains of dead plants. They release special enzymes that break down lignin, a
structurally complex substance in wood. Because of their ability to break down wood, fungi are
considered the major wood decomposers in forests. To absorb organic matter, fungi release acids
to melt organic matter, and then they suck the acid back together with the melted organic matter.
Decomposing organic matter is considered by ecologists as the major ecological role of fungi.
Plant-Fungi Symbiosis
The symbiotic association between a vascular plant root and fungi is called mycorrhiza. In this
association, fungi colonize the roots of a plant and gain access to their tissues. The fungi build a
connection to the roots in such a way that they can exchange nutrients with each other. Plants
provide mycorrhizal fungi shelter and a supply of carbohydrates; in return, mycorrhizal fungi
improve the plantโs absorption capabilities for water and nutrients. Mycorrhizal fungi have a
larger surface-area ratio compared to roots, so they have higher absorptive capacity for water and
minerals. They make it easier for plants to absorb water and minerals in soils that are dry and
with low mineral concentration. Without mycorrhiza, it would be difficult for plants to absorb
water and minerals from such soils. It is estimated that about 90% of plants depends on
mycorrhizal fungi for survival..
Differential equations using phase plane analysis. Task 1 (Romeo .pdf
Differential equations using phase plane analysis. Task 1 (Romeo and Juliet). Let R and J be
variables which measure the love/hate that Romeo and Juliet, respectively, have for the other
star-erassed lower. We consider their relationship as described by a system of the form The
parameters a, b,c, d determine the evalution of their relationship ower time. The signs of the
variables a, b determine what kind of lover Romeo is, Of course, the signs of the variables c, d
play exactly the same roles for Juliet. For each arrangement of passible signs of a,b explain how
Romeo\'s feelings for Juliet change depending on the current state of things. Then make up a
descriptive name for the kind of lover Romeo is given those variables. (Remember that these
apply to Juliec just as well, so if you would rather, yau may work with J, e, d.) Please remember
that the sign of a number is either positive, negative, or zero Explore the different kinds of things
that happens when you pair poten- tial Romeos and Juliets. Which kinds of pairs are doomed to
terrible fates? Which pairs make for happy coll What interesting things ples? you say?
Solution
(1) dR/dT = aR+bJ = f(R,J) form here T is time
dR/dT = (1)(aR+bJ) dR/(aR+bJ) = dT {let us take J value as constant though it is given as a
variable consider nly this equation}
integrate on both sides we get 1/a ln(aR+bJ) + k = T
similarly in second equation if we take R as constant we get 1/d ln(cR+dJ) + k\' = T
we get aR+bJ = e^(a(T-k)) that is an exponential form
it comes closer to 0 only when a value is large and negative J value also similarly comes as
exponential form e^(d(T-K\'))
a(+ve) , b(+ve) love increases ; a(+ve), b(-ve) love increases so much with time
a(-ve) , b(+ve) love increases (since in equation -ve on both sides so get cancelled)
a(-ve) , b(-ve) love depends on b and J numerical values same thing applies to equation dJ/dT
(2) above we can see that in three cases love only increases with time only in 4th case it depends
on juliet when he is totally negative for her similarly for juliet only in one case it depends on
romeo
so we can conclude that love only increases with time and the couple in which love exists at least
with one will remain happy.
Develop a stack in c with dynamic memory allocation. Use the followi.pdf
Develop a stack in c with dynamic memory allocation. Use the following structure to create a
stack:t
typedef struct Element
{
char c;
struct Element *next;
} Element_Type, *Pointer_Type;
You need to develop the following functions:
1) push(): demands two arguemnts of which the first nominates a pointer. For example,
push(&x, โAโ) to push โAโ onto stack X. You need to allocate memory for a new element.
2) pop(): pops and returns the element on the top of the stack and frees the memory space which
was occupied by the element.
3) peep(): simply returns the character value of the top element of the stack. No pointers are
disturbed.
4) displayAll(): prints all character values of all elements of the stack from top to bottom.
void push(Pointer_Type *q, char ch){โฆโฆ}
char pop(Pointer_Type *q){โฆโฆ}
char peep(Pointer_Type *q){โฆโฆ}
void displayAll(Pointer_Type *q){โฆโฆ}
Test your stack and all functions with at least 10 elements.
Solution
#include
#include
#include
struct Element
{
char c;
struct Element *next;
};
struct Element *start=NULL;
void push()
{
char ele;
struct Element *new_ele,*temp;
int i=0;
for(temp=start;temp!=NULL;temp=temp->next)
{
i++;
}
if(i==10)
{
printf(\"Stack Overflow\");
getch();
}
else
{
new_ele=(struct Element *)malloc(sizeof(struct Element));
printf(\"Enter value for Element: \");
scanf(\"%c\",&new_ele->c);
new_ele->next=start;
start=new_ele;
}
}
void pop()
{
struct Element *temp,*temp2;
int i=0;
for(temp=start;temp!=NULL;temp=temp->next)
{
i++;
}
if(i==0)
{
printf(\"Underflow\");
getch();
}
else
{
temp2=start->next;
start=temp2;
printf(\"\ ***The value has been poped***\ \");
}
}
void display()
{
struct Element *temp;
printf(\"\ ****Stack Values****\ \");
for(temp=start;temp!=NULL;temp=temp->next)
{
printf(\"%c\ \",temp->c);
}
getch();
}
void peep()
{
struct Element *temp;
int pos,i=0,j=0;
printf(\"Please enter the position number: \");
scanf(\"%d\",&pos);
for(temp=start;temp!=NULL;temp=temp->next)
{
i++;
}
if(pos>i)
{
printf(\"\ Over Limit\ \");
getch();
}
else
{
temp=start;
for(j=0;jnext;
}
printf(\"\ The value of position %d is :%c\",pos,temp->c);
getch();
}
}
int main()
{
int ch;
while(ch!=6)
{
printf(\"\ 1.Push\ \");
printf(\"2.Pop\ \");
printf(\"3.Peep\ \");
printf(\"4.Display\ \");
printf(\"5.exit\ \");
printf(\"Enter your choice:\");
scanf(\"%d\",&ch);
switch(ch)
{
case 1: push();
break;
case 2: pop();
break;
case 3: peep();
break;
case 4: display();
break;
case 5: exit(0);
}
}
return 0;
}.
Define a struct type that represents a smartphone. The struct should.pdf
Define a struct type that represents a smartphone. The struct should store the following data:
model (a character array of size 30), color (a character), and storage space (an integer). The type
should be renamed from struct smartphone to Smartphone.
Solution
struct smartphone {
char model[30];
char color;
int storageSpace;
};
typedef smartphone Smartphone;.
Changes in the economy have determined that for the EZ shipping comp.pdf
Changes in the economy have determined that for the EZ shipping company, a surcharge will be
assessed on all packages that meet certain criteria. The surcharge is a function of the
characteristics of the package and the zip code to which it is sent.
1. The regular charges for shipping are calculated as follows:
For all weights five pounds and under, the shipping cost is $12.00.
For weights over five pounds, the charge is calculated as follows:
If length * width * height + weight is:
greater than 5 and less than or equal to 15, the shipping cost is 14.00
greater than 15 and less than or equal to 34, the shipping cost is 17.00
greater than 34 and less than or equal to 45, the shipping cost is 21.00
greater than 45 and less than or equal to 60, the shipping cost is 33.00
greater than 60, the shipping cost is 105.00
2. The additional charges are calculated as follows:
If the first digit of the zip code is a \"4\" then there is an additional surcharge of 5% on
the shipping cost.
If the first digit of the zip code is a \"6\" then there is an additional surcharge of 9% on the
shipping cost.
For all other zip codes there is an additional surcharge of 14% on the shipping cost.
3. Finally, if the zip code is even, then there is an additional surcharge of 2% of the shipping
cost.
Write a program that allows the user to input (in this order) the zip code, weight, length, width
and height of the package then prints out the following:
The zip code and dimensions of the package
The shipping cost
The surcharge
The total shipping cost (shipping cost plus surcharge(s))
I have written out the code and have been able to get it to run but when I added in the 2% for
even numbers portion of my code every thing went weird with my outputs. Every thing still
compiles and works but I am not recieving the outputs I desire. Any help remedying this would
be greatly appreciated.
import java.util.Scanner;
//allows use of scanner for keyboard inputs
public class Shipping
// Class titling
{
public static void main(String[] args)
{
{
int zip;
double weight;
double length;
double width;
double height;
double surcharge;
double surcharge2;
double shippingCost;
//Variables that will need defining for the shipping process
Scanner keyboard = new Scanner(System.in);
System.out.println(\"Hello, Welcome to EZ Shipping services! \ Please input the important
details of your shipment when prompted\");
System.out.println(\"What is the weight of your package? \");
weight = keyboard.nextDouble();
System.out.println(\"What is the length of your package? \");
length = keyboard.nextDouble();
System.out.println(\"What is the width of your package? \");
width = keyboard.nextDouble();
System.out.println(\"What is the height of youre package? \");
height = keyboard.nextDouble();
//Print outs for package detail inputs
double packages=length*width*height+weight;
//Package variables combined and stored
{
shippingCost = 12;
//Stock sipping cost 12$
}
if (weight >5)
{
if (packages >=5.1 || packages <= 1.
Broadly speaking, the economy consists of households, firms, governm.pdf
Broadly speaking, the economy consists of households, firms, government, and financial
institutions. Name two parts, areas, or types of government that can have influence over the
economy
Solution
Explanation:
- Financial policy:
Monetary Policy of any government can have major impact on economy of a nation since it has
the power to stimulate the economy and change the way economy behave. Financial policies are
performing major part in economy and it can make or break economy. How the taxes are levied
can majorly impact economy. Financial policies move control the flow of the money and it can
inject new money flow in system to revive it.
- Fiscal Policy:
Another major player in stimulating and impacting economy at it best is fiscal policy. Fiscal
policy mainly works to overcome from struggling economy and reduce the inflation in market.
Interest rate is popular tool to control the flow money through changing interest rates..
A committee consists of 13 Republicans and 16 Democrats. How many dif.pdf
A committee consists of 13 Republicans and 16 Democrats. How many different subcommittees
of 5 can be formed if the subcommittee must consist of 4 Republicans and 1 Democrats?
Solution
Total Republican = 13
Total democrats = 16
We need to select 4 Republican and 1 democrats.
Number of different subcommittee = 13C4 * 16C1
= 13!/(4!*9!) * 16!/(1!*15!)
= 11440.
2. July 01 Record the dividend received from the foreign subsidiary..pdf
2. July 01 Record the dividend received from the foreign subsidiary.
3. December 31 Record the equity in the net income of the foreign subsidiary.
4. December 31 Record the amortization of the differential. On January 1, 20X5, Pirate
Company acquired all of the outstanding stock of Ship Inc., a Norwegian company, at a cost of
$167,400 Ship\'s net assets on the date of acquisition were 700,000 kroner (NKr). On January 1,
20X5, the book and fair values of the Norwegiarn subsidiary\'s identifiable assets and liabilities
approximated their fair values except for property, plant, and equipment and patents acquired.
The fair value of Ship\'s property, plant, and equipment exceeded its book value by $18,000. The
remaining useful life of Ship\'s equipment at January 1, 20X5, was 10 years. The remainder of
the differential was attributable to a patent having an estimated useful life of 5 years. Ship\'s trial
balance on December 31, 20X5, in kroner, follows: Debits Credits NKr 160,000 218,000
277,000 609,000 Cash Accounts Receivable (net) Inventory Property, Plant & Equipment
Accumulated Depreciatiorn Accounts Payable Notes Payable Common Stock Retained Earnings
Sales Cost of Goods Sold Operating Expenses Depreciation Expense Dividends Paid Total NKr
167,000 91,000 209,000 430,000 270,000 745,000 421,000 125,000 61,000 41,000
NKr1,912,000 NKr1,912,000
Solution
TotalCash32,000Accounts Receivable43,600Inventory55,400Property, plant, &
machinery121,800Cost of Goods Sold84,200Operating expenses25,000Depreciation
Expense12,200Dividends Paid8,200Total382,400Total Debits382,400Accumulated
Depreciation33,400Accounts Payable18,200Notes Payable41,800Common Stock86,000Retained
Earnings54,000Sales149,000
Total382,400.
You have isolated a new virus, determined it has a lipid envelope,.pdf
You have isolated a new virus, determined it has a lipid envelope, and wish to characterize the
mechanism of entry. Discuss the important research questions you would ask and the types of
experiments you might use to address the questions.
You have isolated a new virus, determined it has a lipid envelope, and wish to characterize the
mechanism of entry. Discuss the important research questions you would ask and the types of
experiments you might use to address the questions.
Solution
Answer: (There may be several questions related to the attachment and entry process, a few have
been discussed)
The first encounter between a virus and a target cell occurs at the plasma membrane. It is here
that viruses first engage binding and entry receptors to initiate the infection process.
Specific research questions on the mechanism of entry of this virus may be:
1. Adhesion and attachment:
While normally non-specific in nature, different glycosphingolipids on the viral surface have
been reported to confer cell specificity: the sialyllactose moiety on human immunodeficiency
virus (HIV) membrane gangliosides, for instance, has been suggested to promote uptake of HIV
into mature dendritic cells (mDCs).
So, it can be asked whether the mechanism of entry is through specific glycosphingolipids and
new roles of these glycosphingolipids?
Experiments: Using liposomes to mimic the lipid composition and size of the virus, it can be
demonstrate whether gangliosides are the key molecules that mediate liposome uptake.
Liposome and VLP (virus like particle) capture assays on cultured cells, confocal microscopy
and neuraminidase assay with VLP and LUV (large unilamellar vescicles) can be used for the
investigation.
2. Lipid-mediated signalling for entry:
Low-density lipoprotein receptors, negatively charged phospholipids and gangliosides have all
been shown to assist entry of different viruses. Low-density lipoprotein receptors, also known as
cholesterol receptors, are used by several members of the Flaviviridae family, including hepatitis
C virus (HCV).
The interaction is likely to occur through lipoproteins associated with the virion, such as
cholesteryl esters and apolipoproteins (ApoB and ApoE) acquired during the assembly and
budding of virus.
So, it can be determined whether the LDL receptor acts as a receptor for this new virus and
whether the endocytosis of the virus correlated with the level of LDL receptors?.
Investigation of endocytosis of the virus by cultured cells in vitro can be demonstrated to have
LDL receptors with the use of anti-LDL receptor antibody or DiI-LDL uptake. These cell lines
can then be inoculated with a high titer virus positive serum. Intracellular viral RNA then can be
detected by using ISH.
To determine whether endocytosis of the virus correlated with the level of LDL receptor
expression on cells, the well known modulatory effect of lipoproteins on the LDL receptor can
be used to increase the number of LDL receptors (up-regulate) on cel.
Write the Java source code necessary to build a solution for the pro.pdf
Write the Java source code necessary to build a solution for the problem below:
Create a MyLinkedList class. Create methods in the class to add an item to the head, tail, or
middle of a linked list; remove an item from the head, tail, or middle of a linked list; check the
size of the list; and search for an element in the list.
Create a test class to use the newly created MyLinkedList class. Add the following names in to
the list: James, John, Michael, Peter, Allison, Daniel, George, Simon, Jason, and Mark. Your
program should allow the user to enter a name from the console, and then search to see if the
name exists in the list.
Solution
Hi, Please find my implementation.
Please let me know in case of any issue.
public class MyLinkedList {
static class Node{
String data;
Node next;
Node(String d){
data = d;
next =null;
}
}
private Node head;
public MyLinkedList() {
head = null;
}
public void append(String data){
if(head == null)
head = new Node(data);
else{
Node temp = head;
while(temp.next != null)
temp = temp.next;
temp.next = new Node(data);
}
}
public void addFront(String data){
Node newNode = new Node(data);
newNode.next = head;
head = newNode;
}
public void removeFromLast(){
if(head == null || head.next == null)
head = null;
else{
Node temp = head;
while(temp.next.next != null)
temp = temp.next;
temp.next = null; // removing last element
}
}
public void removeFirst(){
if(head == null)
return;
else
head = head.next;
}
public boolean search(String data){
Node temp = head;
while(temp != null){
if(temp.data.equals(data))
return true;
temp = temp.next;
}
return false;
}
public void addAtMiddle(String data){
Node slow = head;
Node fast = head;
Node prev = null;
Node newNode = new Node(data);
if(head == null || head.next == null){
newNode.next = head;
head = newNode;
return;
}
while(fast != null && fast.next != null){
fast = fast.next.next;
prev = slow;
slow = slow.next;
}
if(prev != null)
prev.next =newNode;
newNode.next = slow;
}
public void removeAtMiddle(){
Node slow = head;
Node fast = head;
Node prev = null;
if(head == null || head.next == null){
head = null;
return;
}
while(fast != null && fast.next != null){
fast = fast.next.next;
prev = slow;
slow = slow.next;
}
prev.next = slow.next;
}
public void display(){
Node temp = head;
while(temp != null){
System.out.print(temp.data+\" \");
temp =temp.next;
}
System.out.println();
}
}
public class MyLinkedListTest {
public static void main(String[] args) {
MyLinkedList list = new MyLinkedList();
list.addAtMiddle(\"James\");
list.display();
list.addAtMiddle(\"John\");
list.display();
list.addAtMiddle(\"Michael\");
list.display();
list.addAtMiddle(\"Peter\");
list.display();
list.addAtMiddle(\"Allison\");
list.display();
list.addFront(\"Daniel\");
list.display();
list.append(\"George\");
list.display();
list.addFront(\"Simon\");
list.display();
list.append(\"Jason\");
list.display();
list.addAtMiddle(\"Mark\");
list.display();
list.removeAtMiddle();
list.display();
list.removeFirst();
list.displ.
Why is agrobacterium tumfaciens useful to Kant biologists Describ.pdf
Why is agrobacterium tumfaciens useful to Kant biologists? Describe in detail the steps a
researcher must take to get the desired DNA to hitch a ride on the back of Agro.
Why is agrobacterium tumfaciens useful to Kant biologists? Describe in detail the steps a
researcher must take to get the desired DNA to hitch a ride on the back of Agro.
Solution
Reasons
Agrobacterium has a special plasmid called Ti (Tumor inducing) plasmid.It has TDNA (transfer
DNA) which has the capability of transferring into the the plant cell and induce tumors.
It is naturally attracted towards the wound site by chemicals
It can transfer foreign to plants
The Vie gene will induce the tumorogenic pathway
Method
Explants are a small portion of a plant. E.g.: seedling, protocols, leaf disc etc
A wound is created in explant and incubated with Agrobacterium and acetosyringone.
Acetosyringone is a phenolic product which attracts the Agrobacterium towards the wound.
The explant and Agrobacterium are co cultivated and are transferred to a selective medium
which contains antibiotic.
The presence of antibiotic resistant gene in the Explants will enable the selection and it is
transferred to a media which develops the transformed cell to a callus.
On adding appropriate plant nutrients, roots and shoots are generated. These are transferred to a
pot or field to develop into a adult plant..
Why are the payback and Accounting or Average Rate of Return sometim.pdf
Why are the payback and Accounting or Average Rate of Return sometimes refer as
unsophisticated methodologies?
Solution
The payback period is one of the most widely used tools for evaluating capital projects.The
payback period represents the number of years it takes for the cash flows from a project to
recover the projectโs initial investment.Payback period is considered as unsophisticated
methodologies because it does not account for time value of money.It does not consider cash
flows past the payback period.It is biased against long term projects such as research and
development and new product launches.
Accounting or Average Rate of Return is considered as unsophisticated methodologies because it
also does not account for time value of money.It does not consider the external factors that are
also affecting the profitability of project.Accounting or Average Rate of Return cannot be
applied in a project where investments are made in parts and in real life, a lot of investmentss are
made in parts.So, it is considered as unsophisticated methodologies..
Which of the following are potential differences between the Prokary.pdf
Which of the following are potential differences between the Prokaryotic and Eukaryotic ETC?
(Choose all that apply)
Prokaryotes have Branched ETC
Eukaryotes have longer ETC
Prokaryotes use different systems to respond to oxygen concentrations
All of the proteins in the ETC are shared between Prok. and Euk.
The P/O ratio is higher in Prkaryotes
The P/O ratio is higher in EukaryotesA.
Prokaryotes have Branched ETCB.
Eukaryotes have longer ETCC.
Prokaryotes use different systems to respond to oxygen concentrationsD.
All of the proteins in the ETC are shared between Prok. and Euk.E.
The P/O ratio is higher in PrkaryotesF.
The P/O ratio is higher in Eukaryotes
Solution
B)Eukaryotes have longer ETC
the electron transport chain is long in eukaryotes ascompared to the prokaryotes..
When dividing, do we need to report remainder Why When dividi.pdf
When dividing, do we need to report remainder? Why?
When dividing, do we need to report remainder? Why?
Solution
Sometimes when dividing there is something left over. It is called the remainder.
Example: There are 7 bones to share with 2 pups.
But 7 cannot be divided exactly into 2 groups, so each pup gets 3 bones,
and there is 1 left over..
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What are socioecology and sociobiology? What can they tell us about primate behavior? Use at
least two non-human primate species in your answe
Solution
Answer:
Socioecology focuses on the relationship between social behavior and the natural environment
and favors selection for the individualโs daily survival. Sociobiology focuses on the genetic
predisposition to behaviors and those behaviorsโ enhancement of reproductive success.
Socioecology:
1. Primatologists consider the following environmental factors:
a. Quality and quantity of different foods
b. Distribution of food resources, water, predators and sleeping sites
c. Activity patterns (diurnal, nocturnal)
d. Relationship with other species
e. Impact of human activities
2. Environmental factors such as resource availability and predation have a strong influence on
group size and structure.
3. Multimale and multifemale groups have an advantage when predation pressure is high. Adult
males may join forces to chase and attack predators. (Savannah baboons have been known to kill
domestic dogs and to attack leopards and lions)
4. Solitary foraging may be related to diet and distribution of resources or predator avoidance.
Sociobiology:
1. Natural selection acts on behavior in the same way it acts on physical characteristics.
2. Behavior is a phenotypic expression and genes code for specific behaviors.
3. This approach provides an opportunity to study the effects natural selection has had in shaping
primate behavior.
Nonhuman primates are research subjects because they are so similar to humans. Shared ancestry
is a major reason why human and nonhuman primates have many characteristics in common:
tool use, long-lasting social relationships, and complex communication systems. By learning
about nonhuman primates we may come to learn more about ourselves.
Individuals of certain nonhuman primate species, however, are bipedal for some activities. By
studying those species of nonhuman primates that are occasionally bipedal, and discovering the
circumstances in which they display bipedality, we may gain some understanding of the factors
that promoted the evolution of bipedality in humans.
Human and nonhuman primates also share physiological characteristics. For example, the way in
which the brains of rhesus monkeys and humans are organized is similar. One brain area that has
been studied extensively is the visual system.
Neuroanatomical studies of the nonhuman primate brain have been extremely useful in helping
us to understand how the human brain functions and how we see. In this way, nonhuman
primates serve as models of particular processes. Study of nonhuman primates has also
contributed to our understanding of basic biological phenomena such as reproduction; to better
understanding of diseases such as AIDS.
Nonhuman primates are also studied because they are fascinating animals. They live in a wide
range of habitats, and show many interesting differences in behavior and life styles. For example,
in so.
Using the code below, answer the questionsFor the toolbar, press AL.pdf
Using the code below, answer the questions:For the toolbar, press ALT+F10 (PC) or
ALT+FN+F10 (Mac).
Solution
1. Wo is an interface which contains unimplemented methods. It is similar to class and contains
collection of abstract method. Here we can see it has one unimplemented methods doThat().
2. doThat() is implemented in Roo because the Roo class implements Wo , So any class that
implements Wo has to compulsory implement doThat() method , otherwise the compiler will
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c) List the methods available to a Roo object.
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true or false Strategy formulation and execution is a sequential pr.pdf
true or false: Strategy formulation and execution is a sequential process
Solution
Correct answer is True
Strategy formulation and executon are the consecutive steps of the process of strategy
management. Once the information collection is over and the collected information is alalyzed,
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The symptoms of depression that occur in a person diagnosed with bip.pdf
The symptoms of depression that occur in a person diagnosed with bipolar disorder are ____.
distinct from the symptoms in unipolar disorder
the same as the symptoms in major depressive disorder
distinct from the symptoms in major depressive disorder
the same as the symptoms in obsessive-compulsive disordera.
distinct from the symptoms in unipolar disorderb.
the same as the symptoms in major depressive disorderc.
distinct from the symptoms in major depressive disorderd.
the same as the symptoms in obsessive-compulsive disorder
Solution
The symptoms of depression that occur in a person diagnosed with bipolar disorder are distinct
from the symptoms in major depressive disorder ..
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ุชูุถูุญูุง ุจุดูู ุชูุตููู ุฌุฏุงู (ุชูุนุชุจุฑ ูุฏู ุงูุทุงูุจ ุฃู ุงูุทุงูุจุฉ ุจุฅููุง ู
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