Please answer all parts thank you!Parents PrPr YY rr x PrPr.pdf
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Please answer all parts thank you! Parents: Pr/Pr Y/Y r/r x Pr/Pr y/y R/R What are the phenotypes of the parents?_______________________________________ F1 genotype:___________________________F1 phenotype:______________________ Draw a Punnett Square representing the F2 generation: Parents: Y/Y Pr/Pr R/R x Y/Y pr/pr r/r What are the phenotypes of the parents?_______________________________________ F1 genotype:___________________________F1 phenotype:______________________ Draw a Punnett Square representing the F2 generation: Solution DominantRecessive Purple (Pr) Red (pr) Yellow (Y) White (y) Coloured (R) Colourless (r) 1. Phenotypes of the parents: Pr/Pr Y/Y r/r X Pr/Pr y/y R/R purple, yellow, colourless X purple, white, coloured F1 genotype : Pr Y r X Pr y R F1 phenotype : purple yellow colourless X purple white coloured F2 : ----------R ----------> Pr Y R (Purple, Yellow, Coloured) --------- Y ----------- r -----------> Pr Y r (Purple yellow colourless) Pr------- ----------R ----------> Pr y R (purple white coloured) -------- y ----------- r -----------> Pr y r (purple white colourless) 2. Phenotypes of the parents: Y/Y Pr/Pr R/R x Y/Y pr/pr r/r yellow, purple, coloured X yellow, red, colourless F1 genotype : Y Pr R X Y pr r F1 phenotype : yellow, purple, coloured X yellow, red, colourless F2 : ----------R ----------> Y Pr R (Yellow, Purple, Coloured) -------- Pr ----------- r -----------> Y Pr r ( yellow Purple colourless) Y------- ----------R ---------->Y pr R (yellow red coloured) -------- pr --------- r -----------> Y pr r (yellow red colourless) Apart from punnett square we can also know the F2 gametes by this above method. since I am not having a scaner right now to represent this problem through punnett square method, I am representing it like this. sorry for the inconvience if any..
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I have been working on this ROCK, PAPER, SCISSORS project for the pa.pdf
I have been working on this ROCK, PAPER, SCISSORS project for the past 6 days or so, and
it\'s still giving me absolute fits. I have created two pictureBox controls in the designer, and here
is my current source
code:
namespace ROCK_PAPER_SCISSORS_GAME_2
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
sim iComputer As Integer = 0;
Private iWins As Integer = 0;
Private iDraw As Integer = 0;
Private iLose As Integer = 0;
private void rockButton_Click(object sender, EventArgs e)
{
{
playerLabel.Text = \"Rock\";
PicBox.Image = \"Rock.bmp\";
int iComputer = rand.Next(3);
computerLabel.Text = \"Paper\";
scoreLabel.Text = \"You lose!\";
iLose = iLose + 1;
}
if (iComputer == 2)
{
pic.Image = \"Rock.bmp\";
computerLabel.Text = \"Rock\";
scoreLabel.Text = \"Draw!\";
iDraw = iDraw + 1;
}
if (iComputer = 3)
{
.Image = \"Scissors.bmp\";
computerLabel.Text = \"Scissors\";
scoreLabel.Text = \"You win!\";
iWins = iWins + 1;
}
{
LabelWins1.Text = iWins;
LabelDraw1.Text = iDraw;
LabelLose1.Text = iLose;
}
}
private void paperButton_Click(object sender, EventArgs e)
{
{
playerLabel.Text = \"Paper\";
int iComputer = rand.Next(3);
computerLabel.Text = iComputer;
}
if (iComputer == 1)
{
computerLabel.Text = \"Paper\";
scoreLabel.Text = \"Draw\";
iDraw = iDraw + 1;
}
if (iComputer == 2)
{
computerLabel.Text = \"Paper\";
scoreLabel.Text = \"Draw\";
iDraw = iDraw + 1;
}
if (iComputer == 3)
{
computerLabel.Text = \"Scissor\";
scoreLabel.Text = \"You lose!\";
iLose.Text = iLose + 1;
}
{
LabelWins1.Text = iWins;
LabelDraw1.Text = iDraw;
LabelLose1.Text = iLose;
}
}
private void scissorsButton_Click(object sender, EventArgs e)
{
{
int iComputer = rand.Next(3);
computerLabel.Text = iComputer;
LabelWins1.Text = iWins;
LabelDraw1.Text = iDraw;
LabelLose.Text = iLose;
}
if (iComputer == 1)
{
computerLabel.Text = \"Paper\";
scoreLabel.Text = \"You win!\";
iWins = iWins + 1;
}
if (iComputer == 2)
{
computerLabel.Text = \"Rock\";
scoreLabel.Text = \"You lose!\";
iLose = iLose + 1;
}
if (iComputer == 3)
{
computerLabel.Text = \"Scissor\";
scoreLabel.Text = \"Draw\";
iDraw = iDraw + 1;
}
{
LabelWins1.Text = iWins;
LabelDraw1.Text = iDraw;
LabelLose1.Text = iLose;
}
}
private void resetButton_Click(object sender, EventArgs e)
{
iLose = 0;
iDraw = 0;
iWins = 0;
LabelWins1.Text = iWins;
LabelDraw1.Text = iDraw;
LabelLose1.Text = iLose;
playerLabel.Text = \"\";
computerLabel.Text = \"\";
picComputer.Image = Nothing;
picPlayer.Image = Nothing;
scoreLabel.Text = \"\";
}
}
private void DisplayImages(int randomImage, PictureBox picBox)
// Get the current Application working directory.
string imgPath = Environment.CurrentDirectory
+ \"\\\\picBoxImage\\\\\";
// Use switch case to display the respective images in PictureBox.
switch (randomImage)
{
case 1:
// picBox.ImageLocation =
// imgPath + \"Rock.BMP\";
// break;
picBox.Image = ROCK_PAPER_SCISSORS_GAME_2.
Properties.Resources.Rock;
break;
case 2:
// picBox.ImageLocation =
// imgPath + \"Paper.BMP\";
// br.
Describe tolerance as a immunologic function. What is the consequenc.pdf
Describe tolerance as a immunologic function. What is the consequence of loss of tolerance? ( ¾
page? 2 solid paragraphs)
Solution
Immune tolerance is an act of self tolerance. Self tolerance could be seen against certain
antigens. Tolerance is a physiological mechanism. Due to immune tolerance, the body response
to an antigen either decreases or completely get eliminated. Due to this self tolerance, it leads to
suppressing of allergic responses against antigens. Due to this self tolerance, the host in which
the immune tolerance observed shows chronic infections instead of their elimination. Due to this
self tolerance within the host, the auto reactive lymphocytes become inactivated. Within the
mother due to immune-tolerance, the attack on fetuses has been severe. Due to this imbalance,
leads to autoimmunity through triggering T-helper cell functioning. When the body loses its
tolerance to self antigens, leads to autoimmune disorders such as thyroiditis, multiple sclerosis,
rheumatoid arthritis and systemic lupus erythematosus..
Answer the following question about human evolution as inferred from.pdf
Answer the following question about human evolution as inferred from genome sequencing.
Summarize the demographc history of humans that explains how certain populations acquired
Neandertal and Denisovan DNA. (4 sentence maximum)
Solution
There is a hypothesis that anatomically modern human inbreed with the Neandertal population.
Neandertal genome project presented genetic evidence that interbreeding did took place. Portion
of Neanderthal admixture is present in the DNA of modern Eurasians and Oceanians, and nearly
absent in sub-Saharan African populations. Some part of the genome of Melanesians is derived
from Denisovan DNA. It is possily because of early migration of the ancestors of melanesians
into southeast asia..
40.Classification of a network as a LAN or a WAN is not relevant to .pdf
40.Classification of a network as a LAN or a WAN is not relevant to wireless communication
topologies.
1) True
2) False
44. Which of the following is NOT an example of a business term category that should be
addressed in the contract negotiations?
1) License term, renewal, termination
2) Risk-sharing terms
3) Upgrades and enhancements
4) Interfaces and conversions
45. Which of the following computing attributes is essential to conducting analytical research on
the scope of mapping the human genome?
1) High-speed computation capability
2) Robust data encryption
3) Wireless data transmission
4) Expert system interface
50.The market for financial applications software is BEST described as
1) entrepreneurial.
2) niche.
3) concentrated.
4) volatile.
52.Which of the following describes cellular digital packet data?
1) WAN architecture
2) Infrared technology
3) Used in Internet communication
4) Transmitted on a T1 line
57.What is network physical topology?
1) Configuration of computer and peripheral devices
2) Data transmission protocols
3) Network operating systems
4) Placement of router devices
68.Which of the following describes computer-assisted medical instrumentation?
1) Is used for both data capture and data display
2) Has limited application beyond routine monitoring, such as monitoring of vital signs
3) Is a passive technology used primarily in the clinical laboratory
4) Requires hard-wired configuration
71.Which of the following is an example of a utility program?
1) Virus scan software
2) Multiplexer
3) USB port
4) Digital voice translator
Solution
Please follow the data and description :
40) Wireless Network Topology :
It is a logical topology and shows how the computers connect and interact each other when there
is no physical connection, no cables connecting the computers. The computers communicate
each other directly, using the wireless devices. Wireless networks can have infrastructure or ad
hoc topology. So this does not deals with the types of communication networks that is either a
LAN or a WAN.
So the answer is OPTION 2 (False).
44) Contract negotiation :
It is the process of give and take policy that the parties go through to reach an agreement. Or, in
general as they often say in the terms of business, \"you don\'t get what you deserve; you get
what you negotiate.\" So this does involve with the process of risk management, license terms
and the renewal or the termination of it, any changes during the implementation or evne in the
execution process. But this does not go with the process of interfaces and conversion process.
So the answer is OPTION 4 (Interfaces and COnversions).
45) In the process of computing the mapping for the human genome there are some attributers
that needs to be fulfilled during the process so as to achieve the efficient resutls. Some of them
are the highly relaible data, fast computing, data mining, data warehousing and so on.
So the answer is OPTION 1 (High-speed computation capability).
50) Financial a.
12.9 Program Online shopping cart (continued) (C++)This program e.pdf
12.9 Program: Online shopping cart (continued) (C++)
This program extends the earlier \"Online shopping cart\" program. (Consider first saving your
earlier program).
(1) Extend the ItemToPurchase class per the following specifications:
Parameterized constructor to assign item name, item description, item price, and item quantity
(default values of 0). (1 pt)
Public member functions
SetDescription() mutator & GetDescription() accessor (2 pts)
PrintItemCost() - Outputs the item name followed by the quantity, price, and subtotal
PrintItemDescription() - Outputs the item name and description
Private data members
string itemDescription - Initialized in default constructor to \"none\"
Ex. of PrintItemCost() output:
Ex. of PrintItemDescription() output:
(2) Create three new files:
ShoppingCart.h - Class declaration
ShoppingCart.cpp - Class definition
main.cpp - main() function (Note: main()\'s functionality differs from the warm up)
Build the ShoppingCart class with the following specifications. Note: Some can be function
stubs (empty functions) initially, to be completed in later steps.
Default constructor
Parameterized constructor which takes the customer name and date as parameters (1 pt)
Private data members
string customerName - Initialized in default constructor to \"none\"
string currentDate - Initialized in default constructor to \"January 1, 2016\"
vector < ItemToPurchase > cartItems
Public member functions
GetCustomerName() accessor (1 pt)
GetDate() accessor (1 pt)
AddItem()
Adds an item to cartItems vector. Has parameter ItemToPurchase. Does not return anything.
RemoveItem()
Removes item from cartItems vector. Has a string (an item\'s name) parameter. Does not return
anything.
If item name cannot be found, output this message: Item not found in cart. Nothing removed.
ModifyItem()
Modifies an item\'s description, price, and/or quantity. Has parameter ItemToPurchase. Does not
return anything.
If item can be found (by name) in cart, check if parameter has default values for description,
price, and quantity. If not, modify item in cart.
If item cannot be found (by name) in cart, output this message: Item not found in cart. Nothing
modified.
GetNumItemsInCart() (2 pts)
Returns quantity of all items in cart. Has no parameters.
GetCostOfCart() (2 pts)
Determines and returns the total cost of items in cart. Has no parameters.
PrintTotal()
Outputs total of objects in cart.
If cart is empty, output this message: SHOPPING CART IS EMPTY
PrintDescriptions()
Outputs each item\'s description.
Ex. of PrintTotal() output:
Ex. of PrintDescriptions() output:
(3) In main(), prompt the user for a customer\'s name and today\'s date. Output the name and
date. Create an object of type ShoppingCart. (1 pt)
Ex.
(4) Implement the PrintMenu() function. PrintMenu() has a ShoppingCart parameter, and
outputs a menu of options to manipulate the shopping cart. Each option is represented by a single
character. Build and output the menu within the function.
If the an inval.
A sterile item is free ofmicrobes.endospores.viruses.prions..pdf
A sterile item is free of
microbes.
endospores.
viruses.
prions.
microbes, endospores, AND viruses.
Solution
Answer :- option (microbes, endospores, viruses.
Explanation :- The sterile item means free from microorganisms like microbes and viruses or
endoapores. Sterilisation is done through radiations or autoclaving..
Both mitochondria and chloroplasts... A. obtain electrons from water .pdf
Both mitochondria and chloroplasts... A. obtain electrons from water B. are surrounded by a
single membrane C. release oxygen as a by-product D. use chemiosmosis to produce ATP E. use
a hydrogen ion concentration gradient to produce ATP F. reduce NAD+, forming NADH Hide
response Change response D
Solution
1. Answer is D.
Both mitochondria and chloroplast use chemiosmosis to produce ATP.
Chemiosmosis is the movement of ions across the semi permeable membrane down their
electrochemical gradient.
Chemiosmosis can be seen in mitochondria and chloroplast and as well as in most bacteria and
archaea.
Mitochondria use the energy of NADH and FADH2 while the chloroplast uses theNADPH.
Protons are produced when the splitting of light occurs that gives a proton gradient.
2. Answer is A.
As the electrons flow along the electron transport chain during cellular respiration the pH of
intermediate space decreases.
In mitochondria , the flow of electrons from NADH and FADH2 to oxygen molecule.
It is coupled to the uphill transport of protons from the matrix across the inner membrane of
mitochondria to the intermembrane space giving the proto motive force..
Low platelet count it a recessively inherited trait. Reevaluation of .pdf
Low platelet count it a recessively inherited trait. Reevaluation of the genetic screen indicates
that Nikoleta is homozygous dominant normal for a trait that causes low platelet count and her
husband is homozygous recessive If the F, offspring has normal platelets and beta-thalassemia.
What are the parental gametes? Based on the F_1 progeny phenotype given and the parental
gametes, write the two possible genotypes. What is the gamete frequency it the two genotypes in
(b) were crossed with each other? What is the phenotype frequency for the cross in (c)? Use the
evidence from the case to advice Nikoleta and her husband about having a family. Nikoleta and
her husband Andrew conceived four times. What are the possible combinations for a boy and get
for each time Mrs. Stamos became pregnant?
Solution
Legends-
XX-female
XY-male
HH/hh-homozygous trait for platelets count
Hh-heterozygous trait for platelets count
1.a. The parental gametes will be –
XHXH - homozygous dominant mother
XhY- homozygous recessive
b. possible genotype are- 2XHXh and 2XHY
c. gamete frequency for XHXh will be 2/4=1/2
gamete frequency for XHY will be 2/4=1/2
d. phenotype frequency is as follows
Parents Homozygous dominant mother Homozygous recessive father
XHXH XhY
Gametes XH XH
Xh Y
Male/female
XH
XH
Xh
XHXh
heterozygous dominant
XHXh
heterozygous dominant
Y
XHY
heterozygous dominant
XHY
heterozygous dominant
F1 progeny
2. From the f1 progeny it is clear that all offspring are heterozygous, as platelets count is
homozygous recessive trait. All children will be normal.
Male/female
XH
XH
Xh
XHXh
heterozygous dominant
XHXh
heterozygous dominant
Y
XHY
heterozygous dominant
XHY
heterozygous dominant.
Recommended
I have been working on this ROCK, PAPER, SCISSORS project for the pa.pdf
I have been working on this ROCK, PAPER, SCISSORS project for the past 6 days or so, and
it\'s still giving me absolute fits. I have created two pictureBox controls in the designer, and here
is my current source
code:
namespace ROCK_PAPER_SCISSORS_GAME_2
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
sim iComputer As Integer = 0;
Private iWins As Integer = 0;
Private iDraw As Integer = 0;
Private iLose As Integer = 0;
private void rockButton_Click(object sender, EventArgs e)
{
{
playerLabel.Text = \"Rock\";
PicBox.Image = \"Rock.bmp\";
int iComputer = rand.Next(3);
computerLabel.Text = \"Paper\";
scoreLabel.Text = \"You lose!\";
iLose = iLose + 1;
}
if (iComputer == 2)
{
pic.Image = \"Rock.bmp\";
computerLabel.Text = \"Rock\";
scoreLabel.Text = \"Draw!\";
iDraw = iDraw + 1;
}
if (iComputer = 3)
{
.Image = \"Scissors.bmp\";
computerLabel.Text = \"Scissors\";
scoreLabel.Text = \"You win!\";
iWins = iWins + 1;
}
{
LabelWins1.Text = iWins;
LabelDraw1.Text = iDraw;
LabelLose1.Text = iLose;
}
}
private void paperButton_Click(object sender, EventArgs e)
{
{
playerLabel.Text = \"Paper\";
int iComputer = rand.Next(3);
computerLabel.Text = iComputer;
}
if (iComputer == 1)
{
computerLabel.Text = \"Paper\";
scoreLabel.Text = \"Draw\";
iDraw = iDraw + 1;
}
if (iComputer == 2)
{
computerLabel.Text = \"Paper\";
scoreLabel.Text = \"Draw\";
iDraw = iDraw + 1;
}
if (iComputer == 3)
{
computerLabel.Text = \"Scissor\";
scoreLabel.Text = \"You lose!\";
iLose.Text = iLose + 1;
}
{
LabelWins1.Text = iWins;
LabelDraw1.Text = iDraw;
LabelLose1.Text = iLose;
}
}
private void scissorsButton_Click(object sender, EventArgs e)
{
{
int iComputer = rand.Next(3);
computerLabel.Text = iComputer;
LabelWins1.Text = iWins;
LabelDraw1.Text = iDraw;
LabelLose.Text = iLose;
}
if (iComputer == 1)
{
computerLabel.Text = \"Paper\";
scoreLabel.Text = \"You win!\";
iWins = iWins + 1;
}
if (iComputer == 2)
{
computerLabel.Text = \"Rock\";
scoreLabel.Text = \"You lose!\";
iLose = iLose + 1;
}
if (iComputer == 3)
{
computerLabel.Text = \"Scissor\";
scoreLabel.Text = \"Draw\";
iDraw = iDraw + 1;
}
{
LabelWins1.Text = iWins;
LabelDraw1.Text = iDraw;
LabelLose1.Text = iLose;
}
}
private void resetButton_Click(object sender, EventArgs e)
{
iLose = 0;
iDraw = 0;
iWins = 0;
LabelWins1.Text = iWins;
LabelDraw1.Text = iDraw;
LabelLose1.Text = iLose;
playerLabel.Text = \"\";
computerLabel.Text = \"\";
picComputer.Image = Nothing;
picPlayer.Image = Nothing;
scoreLabel.Text = \"\";
}
}
private void DisplayImages(int randomImage, PictureBox picBox)
// Get the current Application working directory.
string imgPath = Environment.CurrentDirectory
+ \"\\\\picBoxImage\\\\\";
// Use switch case to display the respective images in PictureBox.
switch (randomImage)
{
case 1:
// picBox.ImageLocation =
// imgPath + \"Rock.BMP\";
// break;
picBox.Image = ROCK_PAPER_SCISSORS_GAME_2.
Properties.Resources.Rock;
break;
case 2:
// picBox.ImageLocation =
// imgPath + \"Paper.BMP\";
// br.
Describe tolerance as a immunologic function. What is the consequenc.pdf
Describe tolerance as a immunologic function. What is the consequence of loss of tolerance? ( ¾
page? 2 solid paragraphs)
Solution
Immune tolerance is an act of self tolerance. Self tolerance could be seen against certain
antigens. Tolerance is a physiological mechanism. Due to immune tolerance, the body response
to an antigen either decreases or completely get eliminated. Due to this self tolerance, it leads to
suppressing of allergic responses against antigens. Due to this self tolerance, the host in which
the immune tolerance observed shows chronic infections instead of their elimination. Due to this
self tolerance within the host, the auto reactive lymphocytes become inactivated. Within the
mother due to immune-tolerance, the attack on fetuses has been severe. Due to this imbalance,
leads to autoimmunity through triggering T-helper cell functioning. When the body loses its
tolerance to self antigens, leads to autoimmune disorders such as thyroiditis, multiple sclerosis,
rheumatoid arthritis and systemic lupus erythematosus..
Answer the following question about human evolution as inferred from.pdf
Answer the following question about human evolution as inferred from genome sequencing.
Summarize the demographc history of humans that explains how certain populations acquired
Neandertal and Denisovan DNA. (4 sentence maximum)
Solution
There is a hypothesis that anatomically modern human inbreed with the Neandertal population.
Neandertal genome project presented genetic evidence that interbreeding did took place. Portion
of Neanderthal admixture is present in the DNA of modern Eurasians and Oceanians, and nearly
absent in sub-Saharan African populations. Some part of the genome of Melanesians is derived
from Denisovan DNA. It is possily because of early migration of the ancestors of melanesians
into southeast asia..
40.Classification of a network as a LAN or a WAN is not relevant to .pdf
40.Classification of a network as a LAN or a WAN is not relevant to wireless communication
topologies.
1) True
2) False
44. Which of the following is NOT an example of a business term category that should be
addressed in the contract negotiations?
1) License term, renewal, termination
2) Risk-sharing terms
3) Upgrades and enhancements
4) Interfaces and conversions
45. Which of the following computing attributes is essential to conducting analytical research on
the scope of mapping the human genome?
1) High-speed computation capability
2) Robust data encryption
3) Wireless data transmission
4) Expert system interface
50.The market for financial applications software is BEST described as
1) entrepreneurial.
2) niche.
3) concentrated.
4) volatile.
52.Which of the following describes cellular digital packet data?
1) WAN architecture
2) Infrared technology
3) Used in Internet communication
4) Transmitted on a T1 line
57.What is network physical topology?
1) Configuration of computer and peripheral devices
2) Data transmission protocols
3) Network operating systems
4) Placement of router devices
68.Which of the following describes computer-assisted medical instrumentation?
1) Is used for both data capture and data display
2) Has limited application beyond routine monitoring, such as monitoring of vital signs
3) Is a passive technology used primarily in the clinical laboratory
4) Requires hard-wired configuration
71.Which of the following is an example of a utility program?
1) Virus scan software
2) Multiplexer
3) USB port
4) Digital voice translator
Solution
Please follow the data and description :
40) Wireless Network Topology :
It is a logical topology and shows how the computers connect and interact each other when there
is no physical connection, no cables connecting the computers. The computers communicate
each other directly, using the wireless devices. Wireless networks can have infrastructure or ad
hoc topology. So this does not deals with the types of communication networks that is either a
LAN or a WAN.
So the answer is OPTION 2 (False).
44) Contract negotiation :
It is the process of give and take policy that the parties go through to reach an agreement. Or, in
general as they often say in the terms of business, \"you don\'t get what you deserve; you get
what you negotiate.\" So this does involve with the process of risk management, license terms
and the renewal or the termination of it, any changes during the implementation or evne in the
execution process. But this does not go with the process of interfaces and conversion process.
So the answer is OPTION 4 (Interfaces and COnversions).
45) In the process of computing the mapping for the human genome there are some attributers
that needs to be fulfilled during the process so as to achieve the efficient resutls. Some of them
are the highly relaible data, fast computing, data mining, data warehousing and so on.
So the answer is OPTION 1 (High-speed computation capability).
50) Financial a.
12.9 Program Online shopping cart (continued) (C++)This program e.pdf
12.9 Program: Online shopping cart (continued) (C++)
This program extends the earlier \"Online shopping cart\" program. (Consider first saving your
earlier program).
(1) Extend the ItemToPurchase class per the following specifications:
Parameterized constructor to assign item name, item description, item price, and item quantity
(default values of 0). (1 pt)
Public member functions
SetDescription() mutator & GetDescription() accessor (2 pts)
PrintItemCost() - Outputs the item name followed by the quantity, price, and subtotal
PrintItemDescription() - Outputs the item name and description
Private data members
string itemDescription - Initialized in default constructor to \"none\"
Ex. of PrintItemCost() output:
Ex. of PrintItemDescription() output:
(2) Create three new files:
ShoppingCart.h - Class declaration
ShoppingCart.cpp - Class definition
main.cpp - main() function (Note: main()\'s functionality differs from the warm up)
Build the ShoppingCart class with the following specifications. Note: Some can be function
stubs (empty functions) initially, to be completed in later steps.
Default constructor
Parameterized constructor which takes the customer name and date as parameters (1 pt)
Private data members
string customerName - Initialized in default constructor to \"none\"
string currentDate - Initialized in default constructor to \"January 1, 2016\"
vector < ItemToPurchase > cartItems
Public member functions
GetCustomerName() accessor (1 pt)
GetDate() accessor (1 pt)
AddItem()
Adds an item to cartItems vector. Has parameter ItemToPurchase. Does not return anything.
RemoveItem()
Removes item from cartItems vector. Has a string (an item\'s name) parameter. Does not return
anything.
If item name cannot be found, output this message: Item not found in cart. Nothing removed.
ModifyItem()
Modifies an item\'s description, price, and/or quantity. Has parameter ItemToPurchase. Does not
return anything.
If item can be found (by name) in cart, check if parameter has default values for description,
price, and quantity. If not, modify item in cart.
If item cannot be found (by name) in cart, output this message: Item not found in cart. Nothing
modified.
GetNumItemsInCart() (2 pts)
Returns quantity of all items in cart. Has no parameters.
GetCostOfCart() (2 pts)
Determines and returns the total cost of items in cart. Has no parameters.
PrintTotal()
Outputs total of objects in cart.
If cart is empty, output this message: SHOPPING CART IS EMPTY
PrintDescriptions()
Outputs each item\'s description.
Ex. of PrintTotal() output:
Ex. of PrintDescriptions() output:
(3) In main(), prompt the user for a customer\'s name and today\'s date. Output the name and
date. Create an object of type ShoppingCart. (1 pt)
Ex.
(4) Implement the PrintMenu() function. PrintMenu() has a ShoppingCart parameter, and
outputs a menu of options to manipulate the shopping cart. Each option is represented by a single
character. Build and output the menu within the function.
If the an inval.
A sterile item is free ofmicrobes.endospores.viruses.prions..pdf
A sterile item is free of
microbes.
endospores.
viruses.
prions.
microbes, endospores, AND viruses.
Solution
Answer :- option (microbes, endospores, viruses.
Explanation :- The sterile item means free from microorganisms like microbes and viruses or
endoapores. Sterilisation is done through radiations or autoclaving..
Both mitochondria and chloroplasts... A. obtain electrons from water .pdf
Both mitochondria and chloroplasts... A. obtain electrons from water B. are surrounded by a
single membrane C. release oxygen as a by-product D. use chemiosmosis to produce ATP E. use
a hydrogen ion concentration gradient to produce ATP F. reduce NAD+, forming NADH Hide
response Change response D
Solution
1. Answer is D.
Both mitochondria and chloroplast use chemiosmosis to produce ATP.
Chemiosmosis is the movement of ions across the semi permeable membrane down their
electrochemical gradient.
Chemiosmosis can be seen in mitochondria and chloroplast and as well as in most bacteria and
archaea.
Mitochondria use the energy of NADH and FADH2 while the chloroplast uses theNADPH.
Protons are produced when the splitting of light occurs that gives a proton gradient.
2. Answer is A.
As the electrons flow along the electron transport chain during cellular respiration the pH of
intermediate space decreases.
In mitochondria , the flow of electrons from NADH and FADH2 to oxygen molecule.
It is coupled to the uphill transport of protons from the matrix across the inner membrane of
mitochondria to the intermembrane space giving the proto motive force..
Low platelet count it a recessively inherited trait. Reevaluation of .pdf
Low platelet count it a recessively inherited trait. Reevaluation of the genetic screen indicates
that Nikoleta is homozygous dominant normal for a trait that causes low platelet count and her
husband is homozygous recessive If the F, offspring has normal platelets and beta-thalassemia.
What are the parental gametes? Based on the F_1 progeny phenotype given and the parental
gametes, write the two possible genotypes. What is the gamete frequency it the two genotypes in
(b) were crossed with each other? What is the phenotype frequency for the cross in (c)? Use the
evidence from the case to advice Nikoleta and her husband about having a family. Nikoleta and
her husband Andrew conceived four times. What are the possible combinations for a boy and get
for each time Mrs. Stamos became pregnant?
Solution
Legends-
XX-female
XY-male
HH/hh-homozygous trait for platelets count
Hh-heterozygous trait for platelets count
1.a. The parental gametes will be –
XHXH - homozygous dominant mother
XhY- homozygous recessive
b. possible genotype are- 2XHXh and 2XHY
c. gamete frequency for XHXh will be 2/4=1/2
gamete frequency for XHY will be 2/4=1/2
d. phenotype frequency is as follows
Parents Homozygous dominant mother Homozygous recessive father
XHXH XhY
Gametes XH XH
Xh Y
Male/female
XH
XH
Xh
XHXh
heterozygous dominant
XHXh
heterozygous dominant
Y
XHY
heterozygous dominant
XHY
heterozygous dominant
F1 progeny
2. From the f1 progeny it is clear that all offspring are heterozygous, as platelets count is
homozygous recessive trait. All children will be normal.
Male/female
XH
XH
Xh
XHXh
heterozygous dominant
XHXh
heterozygous dominant
Y
XHY
heterozygous dominant
XHY
heterozygous dominant.
Lists can contain other lists as elements. For example the list HAIR.pdf
The document describes a "multilevel" list called HAIRY that contains other lists as elements. It presents a problem to write a function called flatten that takes a possibly multi-level list as an argument and returns a new single-level list containing the same elements in the same overall order. The function is demonstrated by flattening HAIRY into a single list of its elements.
Match the modified stem to its correct definition.StolonRhizome.pdf
Match the modified stem to its correct definition.
Stolon
Rhizome
Tuber
Bulb
Corm
Stem succulence
Cladophyll
A simple modified stem that stores starch below ground, like a potato.
A belowground modified stem consisting of many compressed internodes with whorls of leaves
surrounding and protecting the stem.
Stems that have become modified to store water and serve as a primary photosynthetic organ in
desert environments.
A stem that has been modified to resemble a leaf.
A modified stem that grows horizontally below the surface of the ground.
A modified stem that grows horizontally above the surface of the ground.
A belowground modified stem for storing starch consisting of a single thick internode wrapped
in papery leaves. - A. B. C. D. E. F. G.
Stolon - A. B. C. D. E. F. G.
Rhizome - A. B. C. D. E. F. G.
Tuber - A. B. C. D. E. F. G.
Bulb - A. B. C. D. E. F. G.
Corm - A. B. C. D. E. F. G.
Stem succulence - A. B. C. D. E. F. G.
CladophyllA.
A simple modified stem that stores starch below ground, like a potato.B.
A belowground modified stem consisting of many compressed internodes with whorls of leaves
surrounding and protecting the stem.C.
Stems that have become modified to store water and serve as a primary photosynthetic organ in
desert environments.D.
A stem that has been modified to resemble a leaf.E.
A modified stem that grows horizontally below the surface of the ground.F.
A modified stem that grows horizontally above the surface of the ground.G.
A belowground modified stem for storing starch consisting of a single thick internode wrapped
in papery leaves.
Solution
Stem succulence - a modified stem to store water and serve as a primary photosynthesis organ in
desert environment and condition..!!
Cladophyll - I is the stem which is being modified to resemble as a leaf which can perform
photosynthesis too..!! Eg:- Asparagus.
Bulb- a below ground modified stem consisting of many compressed internode with whorls of
leaves surrounding and protecting the main interior middle stem.. Eg:- onion..!!
Tuber- a simple modified stem that stores starch below ground, like a potato..!!
Corm- a below ground modified stem for storing starch consisting of a single thick internode
wrapped in papery leaves..!!
Rhizome - a modified stem that grows horizontally below the surface of the ground which can
form adventitious roots and shoots..
Stolon - a modified stem that grows horizontal above the surface of the ground.. They are called
runner...
JAVAAdd to the code at the bottom to do the following two things.pdf
JAVA:
Add to the code at the bottom to do the following two things
1. A \"Monitoring.java\" class that contains a “main(…)” method that will instantiate a
“animalsHabitat” object and call the methods in it.
2. Proper comments and formatting in this .java file and the one that you will create.
PROMPT:
Create a program for a zookeeper monitoring system using two classes. One to be used to
determine what the user wants to do, monitor animals or habitats. The other to read the file for
the chosen action (listed below as animal/habitat file). Create a monitoring system that does all
of the following:
1) Asks a user if they want to monitor an animal, monitor a habitat, or exit
2)Displays a list of animal/habitat options (based on the previous selection) as read from either
the animals or habitats file o Asks the user to enter one of the options
3) Displays the monitoring information by finding the appropriate section in the file
4) Separates sections by the category and selection (such as “Animal - Lion” or “Habitat -
Penguin”)
5) Uses a dialog box to alert the zookeeper if the monitor detects something out of the normal
range (These will be denoted in the files by a new line starting with *****. Do not display the
asterisks in the dialog.)
6) Allows a user to return to the original options
Animals file: (saved on local)
Details on lions
Details on tigers
Details on bears
Details on giraffes
Animal - Lion
Name: Leo
Age: 5
*****Health concerns: Cut on left front paw
Feeding schedule: Twice daily
Animal - Tiger
Name: Maj
Age: 15
Health concerns: None
Feeding schedule: 3x daily
Animal - Bear
Name: Baloo
Age: 1
Health concerns: None
*****Feeding schedule: None on record
Animal - Giraffe
Name: Spots
Age: 12
Health concerns: None
Feeding schedule: Grazing
Habitat file: (Saved on local)
Details on penguin habitat
Details on bird house
Details on aquarium
Habitat - Penguin
Temperature: Freezing
*****Food source: Fish in water running low
Cleanliness: Passed
Habitat - Bird
Temperature: Moderate
Food source: Natural from environment
Cleanliness: Passed
Habitat - Aquarium
Temperature: Varies with output temperature
Food source: Added daily
*****Cleanliness: Needs cleaning from algae
Code so far:
package monitoring;
import java.io.FileInputStream;
import java.io.IOException;
import java.util.*;
public class animalsHabitat {
private String filePath;
final private Scanner scnr;
public animalsHabitat() {
filePath = \"C:\\\\mylocalfolder\";
scnr = new Scanner(System.in);
}
public void askForWhichDetails(String fileName) throws IOException {
FileInputStream fileByteStream = null; // File input stream
Scanner inFS = null; // Scanner object
String textLine = null;
ArrayList aList1 = new ArrayList();
int i = 0;
int option = 0;
boolean bailOut = false;
// Try to open file
fileByteStream = new FileInputStream(filePath + fileName + \".txt\");
inFS = new Scanner(fileByteStream);
while (inFS.hasNextLine() && bailOut == false) {
textLine = inFS.nextLine();
if (textLine.cont.
Let (X,T) be a topological space,.A subset X. Suppose that for all x .pdf
Let (X,T) be a topological space,.A subset X. Suppose that for all x epsilon A, U epsilon T s.t. x
epsilon U subset A. Show that.4 is open in X.
Solution
take the union of all such open sets
i.e. Union of U_x for all x in A
Union U_x is open since U_x is open for all x.
and Union U_x = A (Union U_x is a subset of A and A is subset of Union U_x)
So A is open.
Choose the best possible answer for each of the following multiple ch.pdf
Choose the best possible answer for each of the following multiple choice problems. Each
answer is worth Anthropology is a diverse discipline. Choose the combination of subfields that
best describes anthropology in the United States: Socio/cultural anthropology, biological
anthropology, linguistic anthropology. Socio/cultural anthropology, biological anthropology.
Socio/cultural anthropology, biological anthropology, linguistic anthropology, archaeology.
Socio/cultural anthropology, biological anthropology, archaeology. What are physical
anthropologists studying: The behavior, ecology, and culture of nonhuman primates. Culture in
humans and nonhuman primates. The biology of humans within the framework of evolution with
an emphasis on the interaction between biology and culture. Human speech within the
framework of evolution. Physical anthropologists follow the scientific method to produce new
knowledge. Which sequence of scientific inquiry is correct: collect data in the lab or in the wild
identify a problem/question or state a hypothesis related to a phenomenon observe a
phenomenon in the natural world test a hypothesis analyze the data discuss the research findings
in a publication (1) (3) (5) (2) (4) (6) (3) (2) (1) (5) (4) (6) (2) (3) (1) (4) (6) (5) (3) (1) (4) (5)
(2) (6) Charles R. Darwin is usually credited with the discovery of how new species can arise
from existing ones, but who was the other scientist who likewise discovered this principle of
evolution at around the same time as Darwin? August Weismann Alfred Russel Wallace Jean-
Baptiste de Lamarck John Ray
Solution
21. c
Explanation: Anthropology is a very diverse discipline. It is related to studies on various aspects
of human beings. These aspects can be social, cultural, related to biology, related to language etc.
So, option \'c\' stating four sub-disciplines is correct.
22. c
Explanation: Physical anthropology is a branch of anthropology. It is also known as biological
anthropology. This discipline relates to biological and behavioral aspects of human beings. These
include human physiology, anatomy, behavioral ecology of humans, primatology, population
genetics etc.
23. b
Explanation: First you need to observe a phenomenon in the natural world. Then identify a
problem, test a hypothesis and in the end, the research findings are published.
24. b
Explanation: Wallace was the scientist who discovered the principle of evolution at the same
time along with Darwin. Please note that Lamarck was the first one to discover this principle,
and had done the work before Darwin and Wallace..
If T is a bounded and self-adjoint operator on a Hilbert space and T_.pdf
If T is a bounded and self-adjoint operator on a Hilbert space and T_2 = T, show that T is the
orthogonal projection onto its range.
Solution
Since T is bounded and also self joint we have
T = T* and T* = T
Since TT* = T*T
we get TT = T*T*
i.e. T is normal.
So it follows that T is the orthogonal projection onto its range..
Philippine Edukasyong Pantahanan at Pangkabuhayan (EPP) Curriculum
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𝐃𝐢𝐬𝐜𝐮𝐬𝐬 𝐭𝐡𝐞 𝐄𝐏𝐏 𝐂𝐮𝐫𝐫𝐢𝐜𝐮𝐥𝐮𝐦 𝐢𝐧 𝐭𝐡𝐞 𝐏𝐡𝐢𝐥𝐢𝐩𝐩𝐢𝐧𝐞𝐬:
- Understand the goals and objectives of the Edukasyong Pantahanan at Pangkabuhayan (EPP) curriculum, recognizing its importance in fostering practical life skills and values among students. Students will also be able to identify the key components and subjects covered, such as agriculture, home economics, industrial arts, and information and communication technology.
𝐄𝐱𝐩𝐥𝐚𝐢𝐧 𝐭𝐡𝐞 𝐍𝐚𝐭𝐮𝐫𝐞 𝐚𝐧𝐝 𝐒𝐜𝐨𝐩𝐞 𝐨𝐟 𝐚𝐧 𝐄𝐧𝐭𝐫𝐞𝐩𝐫𝐞𝐧𝐞𝐮𝐫:
-Define entrepreneurship, distinguishing it from general business activities by emphasizing its focus on innovation, risk-taking, and value creation. Students will describe the characteristics and traits of successful entrepreneurs, including their roles and responsibilities, and discuss the broader economic and social impacts of entrepreneurial activities on both local and global scales.
What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...
What is Digital Literacy? A guest blog from Andy McLaughlin, University of Aberdeen
LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UP
This Dissertation explores the particular circumstances of Mirzapur, a region located in the
core of India. Mirzapur, with its varied terrains and abundant biodiversity, offers an optimal
environment for investigating the changes in vegetation cover dynamics. Our study utilizes
advanced technologies such as GIS (Geographic Information Systems) and Remote sensing to
analyze the transformations that have taken place over the course of a decade.
The complex relationship between human activities and the environment has been the focus
of extensive research and worry. As the global community grapples with swift urbanization,
population expansion, and economic progress, the effects on natural ecosystems are becoming
more evident. A crucial element of this impact is the alteration of vegetation cover, which plays a
significant role in maintaining the ecological equilibrium of our planet.Land serves as the foundation for all human activities and provides the necessary materials for
these activities. As the most crucial natural resource, its utilization by humans results in different
'Land uses,' which are determined by both human activities and the physical characteristics of the
land.
The utilization of land is impacted by human needs and environmental factors. In countries
like India, rapid population growth and the emphasis on extensive resource exploitation can lead
to significant land degradation, adversely affecting the region's land cover.
Therefore, human intervention has significantly influenced land use patterns over many
centuries, evolving its structure over time and space. In the present era, these changes have
accelerated due to factors such as agriculture and urbanization. Information regarding land use and
cover is essential for various planning and management tasks related to the Earth's surface,
providing crucial environmental data for scientific, resource management, policy purposes, and
diverse human activities.
Accurate understanding of land use and cover is imperative for the development planning
of any area. Consequently, a wide range of professionals, including earth system scientists, land
and water managers, and urban planners, are interested in obtaining data on land use and cover
changes, conversion trends, and other related patterns. The spatial dimensions of land use and
cover support policymakers and scientists in making well-informed decisions, as alterations in
these patterns indicate shifts in economic and social conditions. Monitoring such changes with the
help of Advanced technologies like Remote Sensing and Geographic Information Systems is
crucial for coordinated efforts across different administrative levels. Advanced technologies like
Remote Sensing and Geographic Information Systems
9
Changes in vegetation cover refer to variations in the distribution, composition, and overall
structure of plant communities across different temporal and spatial scales. These changes can
occur natural.
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More from fasttracksunglass
Lists can contain other lists as elements. For example the list HAIR.pdf
The document describes a "multilevel" list called HAIRY that contains other lists as elements. It presents a problem to write a function called flatten that takes a possibly multi-level list as an argument and returns a new single-level list containing the same elements in the same overall order. The function is demonstrated by flattening HAIRY into a single list of its elements.
Match the modified stem to its correct definition.StolonRhizome.pdf
Match the modified stem to its correct definition.
Stolon
Rhizome
Tuber
Bulb
Corm
Stem succulence
Cladophyll
A simple modified stem that stores starch below ground, like a potato.
A belowground modified stem consisting of many compressed internodes with whorls of leaves
surrounding and protecting the stem.
Stems that have become modified to store water and serve as a primary photosynthetic organ in
desert environments.
A stem that has been modified to resemble a leaf.
A modified stem that grows horizontally below the surface of the ground.
A modified stem that grows horizontally above the surface of the ground.
A belowground modified stem for storing starch consisting of a single thick internode wrapped
in papery leaves. - A. B. C. D. E. F. G.
Stolon - A. B. C. D. E. F. G.
Rhizome - A. B. C. D. E. F. G.
Tuber - A. B. C. D. E. F. G.
Bulb - A. B. C. D. E. F. G.
Corm - A. B. C. D. E. F. G.
Stem succulence - A. B. C. D. E. F. G.
CladophyllA.
A simple modified stem that stores starch below ground, like a potato.B.
A belowground modified stem consisting of many compressed internodes with whorls of leaves
surrounding and protecting the stem.C.
Stems that have become modified to store water and serve as a primary photosynthetic organ in
desert environments.D.
A stem that has been modified to resemble a leaf.E.
A modified stem that grows horizontally below the surface of the ground.F.
A modified stem that grows horizontally above the surface of the ground.G.
A belowground modified stem for storing starch consisting of a single thick internode wrapped
in papery leaves.
Solution
Stem succulence - a modified stem to store water and serve as a primary photosynthesis organ in
desert environment and condition..!!
Cladophyll - I is the stem which is being modified to resemble as a leaf which can perform
photosynthesis too..!! Eg:- Asparagus.
Bulb- a below ground modified stem consisting of many compressed internode with whorls of
leaves surrounding and protecting the main interior middle stem.. Eg:- onion..!!
Tuber- a simple modified stem that stores starch below ground, like a potato..!!
Corm- a below ground modified stem for storing starch consisting of a single thick internode
wrapped in papery leaves..!!
Rhizome - a modified stem that grows horizontally below the surface of the ground which can
form adventitious roots and shoots..
Stolon - a modified stem that grows horizontal above the surface of the ground.. They are called
runner...
JAVAAdd to the code at the bottom to do the following two things.pdf
JAVA:
Add to the code at the bottom to do the following two things
1. A \"Monitoring.java\" class that contains a “main(…)” method that will instantiate a
“animalsHabitat” object and call the methods in it.
2. Proper comments and formatting in this .java file and the one that you will create.
PROMPT:
Create a program for a zookeeper monitoring system using two classes. One to be used to
determine what the user wants to do, monitor animals or habitats. The other to read the file for
the chosen action (listed below as animal/habitat file). Create a monitoring system that does all
of the following:
1) Asks a user if they want to monitor an animal, monitor a habitat, or exit
2)Displays a list of animal/habitat options (based on the previous selection) as read from either
the animals or habitats file o Asks the user to enter one of the options
3) Displays the monitoring information by finding the appropriate section in the file
4) Separates sections by the category and selection (such as “Animal - Lion” or “Habitat -
Penguin”)
5) Uses a dialog box to alert the zookeeper if the monitor detects something out of the normal
range (These will be denoted in the files by a new line starting with *****. Do not display the
asterisks in the dialog.)
6) Allows a user to return to the original options
Animals file: (saved on local)
Details on lions
Details on tigers
Details on bears
Details on giraffes
Animal - Lion
Name: Leo
Age: 5
*****Health concerns: Cut on left front paw
Feeding schedule: Twice daily
Animal - Tiger
Name: Maj
Age: 15
Health concerns: None
Feeding schedule: 3x daily
Animal - Bear
Name: Baloo
Age: 1
Health concerns: None
*****Feeding schedule: None on record
Animal - Giraffe
Name: Spots
Age: 12
Health concerns: None
Feeding schedule: Grazing
Habitat file: (Saved on local)
Details on penguin habitat
Details on bird house
Details on aquarium
Habitat - Penguin
Temperature: Freezing
*****Food source: Fish in water running low
Cleanliness: Passed
Habitat - Bird
Temperature: Moderate
Food source: Natural from environment
Cleanliness: Passed
Habitat - Aquarium
Temperature: Varies with output temperature
Food source: Added daily
*****Cleanliness: Needs cleaning from algae
Code so far:
package monitoring;
import java.io.FileInputStream;
import java.io.IOException;
import java.util.*;
public class animalsHabitat {
private String filePath;
final private Scanner scnr;
public animalsHabitat() {
filePath = \"C:\\\\mylocalfolder\";
scnr = new Scanner(System.in);
}
public void askForWhichDetails(String fileName) throws IOException {
FileInputStream fileByteStream = null; // File input stream
Scanner inFS = null; // Scanner object
String textLine = null;
ArrayList aList1 = new ArrayList();
int i = 0;
int option = 0;
boolean bailOut = false;
// Try to open file
fileByteStream = new FileInputStream(filePath + fileName + \".txt\");
inFS = new Scanner(fileByteStream);
while (inFS.hasNextLine() && bailOut == false) {
textLine = inFS.nextLine();
if (textLine.cont.
Let (X,T) be a topological space,.A subset X. Suppose that for all x .pdf
Let (X,T) be a topological space,.A subset X. Suppose that for all x epsilon A, U epsilon T s.t. x
epsilon U subset A. Show that.4 is open in X.
Solution
take the union of all such open sets
i.e. Union of U_x for all x in A
Union U_x is open since U_x is open for all x.
and Union U_x = A (Union U_x is a subset of A and A is subset of Union U_x)
So A is open.
Choose the best possible answer for each of the following multiple ch.pdf
Choose the best possible answer for each of the following multiple choice problems. Each
answer is worth Anthropology is a diverse discipline. Choose the combination of subfields that
best describes anthropology in the United States: Socio/cultural anthropology, biological
anthropology, linguistic anthropology. Socio/cultural anthropology, biological anthropology.
Socio/cultural anthropology, biological anthropology, linguistic anthropology, archaeology.
Socio/cultural anthropology, biological anthropology, archaeology. What are physical
anthropologists studying: The behavior, ecology, and culture of nonhuman primates. Culture in
humans and nonhuman primates. The biology of humans within the framework of evolution with
an emphasis on the interaction between biology and culture. Human speech within the
framework of evolution. Physical anthropologists follow the scientific method to produce new
knowledge. Which sequence of scientific inquiry is correct: collect data in the lab or in the wild
identify a problem/question or state a hypothesis related to a phenomenon observe a
phenomenon in the natural world test a hypothesis analyze the data discuss the research findings
in a publication (1) (3) (5) (2) (4) (6) (3) (2) (1) (5) (4) (6) (2) (3) (1) (4) (6) (5) (3) (1) (4) (5)
(2) (6) Charles R. Darwin is usually credited with the discovery of how new species can arise
from existing ones, but who was the other scientist who likewise discovered this principle of
evolution at around the same time as Darwin? August Weismann Alfred Russel Wallace Jean-
Baptiste de Lamarck John Ray
Solution
21. c
Explanation: Anthropology is a very diverse discipline. It is related to studies on various aspects
of human beings. These aspects can be social, cultural, related to biology, related to language etc.
So, option \'c\' stating four sub-disciplines is correct.
22. c
Explanation: Physical anthropology is a branch of anthropology. It is also known as biological
anthropology. This discipline relates to biological and behavioral aspects of human beings. These
include human physiology, anatomy, behavioral ecology of humans, primatology, population
genetics etc.
23. b
Explanation: First you need to observe a phenomenon in the natural world. Then identify a
problem, test a hypothesis and in the end, the research findings are published.
24. b
Explanation: Wallace was the scientist who discovered the principle of evolution at the same
time along with Darwin. Please note that Lamarck was the first one to discover this principle,
and had done the work before Darwin and Wallace..
If T is a bounded and self-adjoint operator on a Hilbert space and T_.pdf
If T is a bounded and self-adjoint operator on a Hilbert space and T_2 = T, show that T is the
orthogonal projection onto its range.
Solution
Since T is bounded and also self joint we have
T = T* and T* = T
Since TT* = T*T
we get TT = T*T*
i.e. T is normal.
So it follows that T is the orthogonal projection onto its range..
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Lists can contain other lists as elements. For example the list HAIR.pdf
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JAVAAdd to the code at the bottom to do the following two things.pdf
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Let (X,T) be a topological space,.A subset X. Suppose that for all x .pdf
Let (X,T) be a topological space,.A subset X. Suppose that for all x .pdf
Choose the best possible answer for each of the following multiple ch.pdf
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If T is a bounded and self-adjoint operator on a Hilbert space and T_.pdf
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Philippine Edukasyong Pantahanan at Pangkabuhayan (EPP) Curriculum
(𝐓𝐋𝐄 𝟏𝟎𝟎) (𝐋𝐞𝐬𝐬𝐨𝐧 𝟏)-𝐏𝐫𝐞𝐥𝐢𝐦𝐬
𝐃𝐢𝐬𝐜𝐮𝐬𝐬 𝐭𝐡𝐞 𝐄𝐏𝐏 𝐂𝐮𝐫𝐫𝐢𝐜𝐮𝐥𝐮𝐦 𝐢𝐧 𝐭𝐡𝐞 𝐏𝐡𝐢𝐥𝐢𝐩𝐩𝐢𝐧𝐞𝐬:
- Understand the goals and objectives of the Edukasyong Pantahanan at Pangkabuhayan (EPP) curriculum, recognizing its importance in fostering practical life skills and values among students. Students will also be able to identify the key components and subjects covered, such as agriculture, home economics, industrial arts, and information and communication technology.
𝐄𝐱𝐩𝐥𝐚𝐢𝐧 𝐭𝐡𝐞 𝐍𝐚𝐭𝐮𝐫𝐞 𝐚𝐧𝐝 𝐒𝐜𝐨𝐩𝐞 𝐨𝐟 𝐚𝐧 𝐄𝐧𝐭𝐫𝐞𝐩𝐫𝐞𝐧𝐞𝐮𝐫:
-Define entrepreneurship, distinguishing it from general business activities by emphasizing its focus on innovation, risk-taking, and value creation. Students will describe the characteristics and traits of successful entrepreneurs, including their roles and responsibilities, and discuss the broader economic and social impacts of entrepreneurial activities on both local and global scales.
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LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UP
This Dissertation explores the particular circumstances of Mirzapur, a region located in the
core of India. Mirzapur, with its varied terrains and abundant biodiversity, offers an optimal
environment for investigating the changes in vegetation cover dynamics. Our study utilizes
advanced technologies such as GIS (Geographic Information Systems) and Remote sensing to
analyze the transformations that have taken place over the course of a decade.
The complex relationship between human activities and the environment has been the focus
of extensive research and worry. As the global community grapples with swift urbanization,
population expansion, and economic progress, the effects on natural ecosystems are becoming
more evident. A crucial element of this impact is the alteration of vegetation cover, which plays a
significant role in maintaining the ecological equilibrium of our planet.Land serves as the foundation for all human activities and provides the necessary materials for
these activities. As the most crucial natural resource, its utilization by humans results in different
'Land uses,' which are determined by both human activities and the physical characteristics of the
land.
The utilization of land is impacted by human needs and environmental factors. In countries
like India, rapid population growth and the emphasis on extensive resource exploitation can lead
to significant land degradation, adversely affecting the region's land cover.
Therefore, human intervention has significantly influenced land use patterns over many
centuries, evolving its structure over time and space. In the present era, these changes have
accelerated due to factors such as agriculture and urbanization. Information regarding land use and
cover is essential for various planning and management tasks related to the Earth's surface,
providing crucial environmental data for scientific, resource management, policy purposes, and
diverse human activities.
Accurate understanding of land use and cover is imperative for the development planning
of any area. Consequently, a wide range of professionals, including earth system scientists, land
and water managers, and urban planners, are interested in obtaining data on land use and cover
changes, conversion trends, and other related patterns. The spatial dimensions of land use and
cover support policymakers and scientists in making well-informed decisions, as alterations in
these patterns indicate shifts in economic and social conditions. Monitoring such changes with the
help of Advanced technologies like Remote Sensing and Geographic Information Systems is
crucial for coordinated efforts across different administrative levels. Advanced technologies like
Remote Sensing and Geographic Information Systems
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Changes in vegetation cover refer to variations in the distribution, composition, and overall
structure of plant communities across different temporal and spatial scales. These changes can
occur natural.
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Philippine Edukasyong Pantahanan at Pangkabuhayan (EPP) Curriculum
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Please answer all parts thank you!Parents PrPr YY rr x PrPr.pdf
- 1. Please answer all parts thank you! Parents: Pr/Pr Y/Y r/r x Pr/Pr y/y R/R What are the phenotypes of the parents?_______________________________________ F1 genotype:___________________________F1 phenotype:______________________ Draw a Punnett Square representing the F2 generation: Parents: Y/Y Pr/Pr R/R x Y/Y pr/pr r/r What are the phenotypes of the parents?_______________________________________ F1 genotype:___________________________F1 phenotype:______________________ Draw a Punnett Square representing the F2 generation: Solution DominantRecessive Purple (Pr) Red (pr) Yellow (Y) White (y) Coloured (R) Colourless (r) 1. Phenotypes of the parents: Pr/Pr Y/Y r/r X Pr/Pr y/y R/R purple, yellow, colourless X purple, white, coloured F1 genotype : Pr Y r X Pr y R F1 phenotype : purple yellow colourless X purple white coloured F2 : ----------R ----------> Pr Y R (Purple, Yellow, Coloured) --------- Y ----------- r -----------> Pr Y r (Purple yellow colourless) Pr------- ----------R ----------> Pr y R (purple white coloured) -------- y ----------- r -----------> Pr y r (purple white colourless) 2. Phenotypes of the parents: Y/Y Pr/Pr R/R x Y/Y pr/pr r/r yellow, purple, coloured X yellow, red, colourless F1 genotype : Y Pr R X Y pr r F1 phenotype : yellow, purple, coloured X yellow, red, colourless F2 : ----------R ----------> Y Pr R (Yellow, Purple, Coloured) -------- Pr
- 2. ----------- r -----------> Y Pr r ( yellow Purple colourless) Y------- ----------R ---------->Y pr R (yellow red coloured) -------- pr --------- r -----------> Y pr r (yellow red colourless) Apart from punnett square we can also know the F2 gametes by this above method. since I am not having a scaner right now to represent this problem through punnett square method, I am representing it like this. sorry for the inconvience if any.