The document contains worked examples of word problems involving multiplication and division. It provides step-by-step explanations and diagrams showing how to extract relevant information, model the relationships mathematically, and arrive at the solution. The problems cover a range of scenarios involving groups of people, costs, lengths, and masses. Key steps involve identifying the quantities given, determining relationships between quantities, and setting up and solving equations to find the unknown value.

1. Primary 4
Multiplication
and
Division Word Problems

2. Multiplication & Division Problem Sums
There were 4 times as many children as adults in a
party. After 16 adults left, the number of children in
the party was 20 times the number of the remaining
adults. How many people attended the party?

3. Multiplication & Division Problem Sums
There were 4 times as many children as adults in a
party. After 16 adults left, the number of children in
the party was 20 times the number of the remaining
adults. How many people attended the party?
Extract Info:
C -> 4u Draw the models
A -> 1u according to your
extracted info.
Notice the number of children
remains unchanged.
Therefore, we multiply 4u by
5 to get 20u for the children.
Logically, we also multiply 1u
by 5 for the adults.
C -> 20u ?
A -> 5u - 16

4. Multiplication & Division Problem Sums
There were 4 times as many children as adults in a
party. After 16 adults left, the number of children in
the party was 20 times the number of the remaining
adults. How many people attended the party?
Extracted Info
C -> 20u
A -> 5u - 16
C
?
A
16

5. Multiplication & Division Problem Sums
There were 4 times as many children as adults in a
party. After 16 adults left, the number of children in
the party was 20 times the number of the remaining
adults. How many people attended the party?
Extracted Info
C -> 20u
A -> 5u - 16
C
?
A
16
4u -> 16
1u -> 16 ÷ 4 = 4

6. Multiplication & Division Problem Sums
There were 4 times as many children as adults in a
party. After 16 adults left, the number of children in
the party was 20 times the number of the remaining
adults. How many people attended the party?
Extracted Info
C -> 20u
A -> 5u - 16
C
?
A
16
4u -> 16
1u -> 16 ÷ 4 = 4
25u -> 25 x 4 = 100
100 people attended the party.

7. Multiplication & Division Problem Sums
Mark went shopping with twice as much money as
Paul. After Paul spent $60, Mark had 6 times as
much money as Paul. How much more money did Mark
bring along for shopping than Paul?

8. Multiplication & Division Problem Sums
Mark went shopping with twice as much money as
Paul. After Paul spent $60, Mark had 6 times as
much money as Paul. How much more money did Mark
bring along for shopping than Paul?
Extract Info:
Mark -> 2u Draw the models
Paul -> 1u according to your
extracted info.
Notice Mark's money remains
unchanged. Therefore, we
multiply 2u by 3 to get 6u for
Mark. Logically, we also multiply
1u by 3 for Paul.
Mark -> (2u x 3) = 6u
Paul -> (1u x 3) = 3u - 60

9. Multiplication & Division Problem Sums
Mark went shopping with twice as much money as
Paul. After Paul spent $60, Mark had 6 times as
much money as Paul. How much more money did Mark
bring along for shopping than Paul?
Extract Info:
Mark -> (2u x 3) = 6u
Paul -> (1u x 3) = 3u - 60
Mark
?
Paul
60

10. Multiplication & Division Problem Sums
Mark went shopping with twice as much money as
Paul. After Paul spent $60, Mark had 6 times as
much money as Paul. How much more money did Mark
bring along for shopping than Paul?
Extract Info:
Mark -> (2u x 3) = 6u
Paul -> (1u x 3) = 3u - 60
Mark 2u -> 60
?
Paul
60

11. Multiplication & Division Problem Sums
Mark went shopping with twice as much money as
Paul. After Paul spent $60, Mark had 6 times as
much money as Paul. How much more money did Mark
bring along for shopping than Paul?
Extract Info:
Mark -> (2u x 3) = 6u
Paul -> (1u x 3) = 3u - 60
Mark 2u -> 60
1u -> 60 ÷ 2 = 30
?
Paul
60

12. Multiplication & Division Problem Sums
Mark went shopping with twice as much money as
Paul. After Paul spent $60, Mark had 6 times as
much money as Paul. How much more money did Mark
bring along for shopping than Paul?
Extract Info:
Mark -> (2u x 3) = 6u
Paul -> (1u x 3) = 3u - 60
Mark 2u -> 60
1u -> 60 ÷ 2 = 30
? 3u -> 30 x 3 = 90
Paul
60 Mark brought $90 more
than Paul.

13. Multiplication & Division Problem Sums
The total cost of 3 erasers and 5 pens is $52. Each
pen costs $8. Find the cost of each eraser.
Extract Info:
3E + 5P = 52 (Total cost)
P = 8
We know the cost of 1 pen. So let's find the cost of
5 pens.

14. Multiplication & Division Problem Sums
The total cost of 3 erasers and 5 pens is $52. Each
pen costs $8. Find the cost of each eraser.
Extract Info:
3E + 5P = 52 (Total cost)
P = 8
P -> $8
5P -> 5 x $8 = $40

15. Multiplication & Division Problem Sums
The total cost of 3 erasers and 5 pens is $52. Each
pen costs $8. Find the cost of each eraser.
Extract Info:
3E + 5P = 52 (Total cost)
P = 8
P -> $8
5P -> 5 x $8 = $40
Cost of 3 erasers -> Total cost – Cost of 5 pens
-> $52 – $40
-> $12

16. Multiplication & Division Problem Sums
The total cost of 3 erasers and 5 pens is $52. Each
pen costs $8. Find the cost of each eraser.
Extract Info:
3E + 5P = 52 (Total cost)
P = 8
P -> $8
5P -> 5 x $8 = $40
Cost of 3 erasers -> Total cost – Cost of 5 pens
-> $52 – $40
-> $12
Cost of 1 eraser -> $12 ÷ 3 = $4

17. Multiplication & Division Problem Sums
The total length of 4 ropes and 6 strings is 334cm.
The length of each rope is 46cm. Find the length of
each string.
Extract Info:
4R + 6S = 334 (Total length)
R = 46
We know the length of 1 rope. So let's find the
length of 4 ropes.

18. Multiplication & Division Problem Sums
The total length of 4 ropes and 6 strings is 334cm.
The length of each rope is 46cm. Find the length of
each string.
Extract Info:
4R + 6S = 334 (Total length)
R = 46
We know the length of 1 rope. So let's find the
length of 4 ropes.
R -> 46 cm
4R -> 46 x 4 = 184 cm

19. Multiplication & Division Problem Sums
The total length of 4 ropes and 6 strings is 334cm.
The length of each rope is 46cm. Find the length of
each string.
Extract Info:
4R + 6S = 334 (Total length)
R = 46
We know the length of 1 rope. So let's find the
length of 4 ropes.
R -> 46 cm
4R -> 46 x 4 = 184 cm
Length of 6 strings -> Total length – 4R
-> 334 – 184
-> 150 cm

20. Multiplication & Division Problem Sums
The total length of 4 ropes and 6 strings is 334cm.
The length of each rope is 46cm. Find the length of
each string.
Extract Info:
4R + 6S = 334 (Total length)
R = 46
We know the length of 1 rope. So let's find the
length of 4 ropes.
R -> 46 cm
4R -> 46 x 4 = 184 cm
Length of 6 strings -> Total length – 4R
-> 334 – 184
-> 150 cm
Length of 1 string -> 150 ÷ 6 = 25 cm

21. Multiplication & Division Problem Sums
The total mass of 3 watermelons and 8 mangoes is
76kg. Each watermelon weighs 12kg. Find the mass of
each mango.
Extract Info:
3W + 8M = 76 (Total mass)
W = 12
We know the mass of 1 watermelon. So let's find the
mass of 3 watermelons.

22. Multiplication & Division Problem Sums
The total mass of 3 watermelons and 8 mangoes is
76kg. Each watermelon weighs 12kg. Find the mass of
each mango.
Extract Info:
3W + 8M = 76 (Total mass)
W = 12
We know the mass of 1 watermelon. So let's find the
mass of 3 watermelons.
W -> 12 kg
3W -> x =
Mass of 8 mangoes -> Total mass – 3W
Mass of 1 mango -> Mass of 8 mangoes ÷ 8 =