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This document describes setting up torque equilibrium for a beam with weights on each end to solve for the unknown far end force. It finds the far end force is 1500 N. It then uses vertical force equilibrium to solve for the near end force, finding it to be 1900 N.
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P13 037
The shear stress on an aluminum rod due to the weight of a 1200 kg object hanging from it is calculated to be 6.5 × 106 N/m2 based on the force applied, cross-sectional area of the rod, and radius. The shear modulus of the aluminum is used to calculate the vertical deflection of the rod under this stress as 1.1 × 10−5 m by relating the shear stress, length of the rod, and modulus.
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This document summarizes solutions to 4 questions regarding pile capacity and pile group design:
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The document discusses methods for determining the load carrying capacity of pile foundations. The load carrying capacity has two components: skin friction and end bearing. Several methods are available to calculate skin friction and end bearing for cast-in-situ and driven piles. The document provides equations that can be used to calculate the ultimate skin friction and end bearing capacity for cohesive and cohesionless soils. The total ultimate load capacity is the sum of the skin friction and end bearing capacities. The design load capacity applies a factor of safety of 4.0 to the ultimate load capacity.
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P13 037
The shear stress on an aluminum rod due to the weight of a 1200 kg object hanging from it is calculated to be 6.5 × 106 N/m2 based on the force applied, cross-sectional area of the rod, and radius. The shear modulus of the aluminum is used to calculate the vertical deflection of the rod under this stress as 1.1 × 10−5 m by relating the shear stress, length of the rod, and modulus.
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This document summarizes solutions to 4 questions regarding pile capacity and pile group design:
1. It calculates the load carrying capacity of a precast concrete pile driven into soil using engineering news formula.
2. It designs a friction pile group to carry 3000 kN including the weight of the pile cap, selecting a pile length, diameter, and number based on soil properties and factor of safety.
3. It determines the load carried by skin friction of a square pile penetrating clay using soil cohesion and pile surface area.
4. It calculates the optimum spacing for a group of 16 circular piles in clay by equating load carried by group action and piles individually.
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Course Email: mth101@vu.edu.pk
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2. Diagrams and equations are provided to solve for variables like tension, normal force, angle of incline, and components of forces.
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This document discusses the design of singly reinforced concrete beams. It covers:
1) Concrete stress distribution and equivalent stress blocks. The depth and location of the neutral axis are defined.
2) Strength analysis using equilibrium of forces and moments. Flexural strength equations are developed.
3) Determination of steel ratios including balanced, maximum, and minimum ratios based on material strengths and code requirements.
4) Procedure to determine the flexural strength of a beam given its dimensions and material properties.
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1. CloudSat and CALIPSO satellite observations were used to analyze cloud vertical distributions across cold and warm fronts in extratropical cyclones in the Northern and Southern Hemispheres.
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3. The GISS GCM model captured the general features but underestimated cloud fraction due to problems with moisture transport along and across fronts at the coarse resolution of the model. Improving moisture transport, including simulating slantwise convection, could help the model better represent extratropical cyclone clouds.
Pile capacity equations
The document discusses methods for determining the load carrying capacity of pile foundations. The load carrying capacity has two components: skin friction and end bearing. Several methods are available to calculate skin friction and end bearing for cast-in-situ and driven piles. The document provides equations that can be used to calculate the ultimate skin friction and end bearing capacity for cohesive and cohesionless soils. The total ultimate load capacity is the sum of the skin friction and end bearing capacities. The design load capacity applies a factor of safety of 4.0 to the ultimate load capacity.
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A group of 16 square piles extends 12 m into stiff clay soil, underlain by rock at 24 m depth. Pile dimensions are 0.3 m x 0.3 m. Undrained shear strength of clay increases linearly from 50 kPa at surface to 150 kPa at rock. Factor of safety for group capacity is 2.5. Determine group capacity and individual pile capacity.
The group capacity is calculated to be 1600 kN. The individual pile capacity is determined to be 100 kN. The factor of safety of 2.5 is then applied to determine the safe load capacity.
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Principles of soil dynamics 3rd edition das solutions manual
Download at: https://goo.gl/NfK7oK
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For the first problem, the document calculates the path loss, received power, noise power, and C/N ratio for a satellite system operating at 6.1 GHz. The C/N ratio at the transponder output was found to be 26.4 dB.
The second problem performs similar calculations for a different satellite operating at 3.875 GHz, serving the contiguous US from a distance of 39,000 km. The gain of the satellite antenna was calculated to be 29.6 dB, and the C/N ratio for the receiving earth station was found to be 29.6 dB.
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1. The document describes a method to experimentally determine the coefficient of restitution of different objects like balls through drop tests.
2. The coefficient of restitution can be calculated from the ratio of the heights or times of successive bounces. A phone app is used to precisely measure the times from the sounds of impacts.
3. Drop tests are performed with different balls, recording at least 6-7 bounces. The time data is analyzed to calculate the average coefficient of restitution for each ball tested.
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The document contains solutions to physics problems involving kinematics, dynamics, work, energy, momentum, rotation, and torque. Key points include:
- Expressions are derived for the kinetic energy of translation and rotation, and the total kinetic energy of objects like disks and rings.
- Problems calculate accelerations, velocities, times, distances, energies, moments of inertia, and torques for objects rolling down inclines and rotating on an axis.
- Vector dot and cross products are used to find angles between vectors and rotational quantities like torque.
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1. The document discusses GPS signal power received on Earth from satellites in low Earth orbit. It calculates the free space path loss over the 20,000 km distance to be approximately 180.4 dB.
2. GPS satellites transmit signals at 25.6 Watts with a 13 dBi antenna gain, resulting in an effective isotropic radiated power of around 500 Watts or 27 dBW.
3. Accounting for the 180.4 dB free space path loss and 2 dB of atmospheric loss, the received power at the Earth's surface is calculated to be -155 dBW, which has a 5 dB margin above the specification of -160 dBW.
E. Sefusatti, Tests of the Initial Conditions of the Universe after Planck
This document outlines Emiliano Sefusatti's presentation on testing the initial conditions of the universe using data from the Planck satellite. The presentation covers predictions from inflation like a flat, homogeneous universe with a nearly scale-invariant power spectrum. It discusses how Planck improved constraints on non-Gaussianity parameters like fNL compared to WMAP. For example, Planck reduced errors on the local fNL parameter by a factor of 2-4 depending on the shape. The implications of Planck's results are explored through the example of constraints on a DBI inflation model.
Question and Answers on Terzaghi’s Bearing Capacity Theory (usefulsearch.org)...
This document contains solved examples of questions on bearing capacity from previous year question papers. It includes 6 questions calculating the ultimate bearing capacity, safe bearing capacity, and size of footing for given soil properties and loading conditions using Terzaghi and general shear failure theories. The properties provided are unit weight, cohesion, friction angle, and bearing capacity factors. Depths, widths, loads, and factors of safety are also given. The step-by-step workings and solutions are shown for each question.
Problem i ph o 26
1) A spacecraft measures the redshift of photons emitted from the surface of a star to determine the star's mass M and radius R. As it approaches the star, it measures the velocity needed for resonant absorption of photons by He+ ions.
2) The experimental data gives the velocity needed for resonance at different distances from the star. This data is plotted to determine M and R graphically.
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Principles of soil dynamics 3rd edition das solutions manual
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The document discusses calculating the vertical and horizontal force components of hinges supporting a door. It states that each vertical hinge supports half the door's weight, so the vertical force is 1.3 x 102 N. It then uses a torque calculation around the top hinge to find the horizontal force component at the bottom hinge is 80 N, and by the equilibrium of horizontal forces, the horizontal component at the top hinge must be of the same magnitude but opposite direction.
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A balance has arms of length 1 and 2, and masses m1 and m2. The equations for torque equilibrium when the balance is balanced are m1*1=m2*2 and m1=m2*2. Dividing the equations and solving for the unknown mass gives the result that m = √(m1*m2).
P13 057
The document analyzes the forces at a knot holding a 5 kg mass at a 30 degree angle. It represents the static friction force and weight of the 5 kg mass as the sides of a right triangle. It finds that the static friction force equals the weight of the 5 kg mass multiplied by the tangent of 30 degrees. For the static friction force to be at its maximum, it must equal the coefficient of static friction multiplied by the weight of the 10 kg object. Equating these expressions allows one to calculate that the coefficient of static friction equals 0.29.
P13 056
The document shows a calculation of the torque equilibrium for a rod with forces applied at different distances from the fulcrum. The perpendicular force F⊥ required for equilibrium is calculated to be 8.7 N based on a 40 N force applied 2.6 cm from the fulcrum and the distance to the fulcrum being 12 cm.
P13 053
1) The document describes calculating the critical condition for a cube to begin sliding when a force P is applied to its top surface.
2) It sets static friction equal to its maximum value and models the normal force as acting at the bottom corner below where P is applied.
3) Equating the torques due to static friction and the force of gravity yields the critical condition that the coefficient of friction μ must equal L/2h.
P13 052
The cube has side length l and volume V=l^3. The document calculates the pressure p required using the formula p=BΔV/V, where B is a constant and ΔV is the change in volume. It shows that ΔV/V ≈ 3Δl/l. Plugging in the values for a cube where the side length increases from 85.0 cm to 85.5 cm, it calculates the required pressure p is approximately 2.4 × 10^9 N/m^2.
P13 051
The document summarizes calculating torques and forces on a gymnastics beam system. It states that for computing torques, the axis is chosen at support 2 and clockwise is positive. Equating the torques leads to an expression for the upward force F1 at support 1 of 1163 N. It then states that balancing vertical forces gives an expression relating F1, F2, the masses and gravity, from which F2 is calculated to be 1740 N.
P13 050
The document describes calculating the forces acting on a beam attached to a hinge by a cable and balanced force. It finds that the cable exerts 88N of tension to balance the 50N force on the beam and no net torque. It then calculates the x and y components of the hinge force as 30N rightward and 97N upward to balance all the forces acting on the beam.
P13 048
This document describes calculating torques and forces on a beam hinged at one end. It finds that for a 12m beam with a 400N tension and angles of 40 and 50 degrees, the weight on the beam is 671N. Equilibrium equations show the horizontal hinge force is 400N of tension and the vertical force is approximately 670N of weight.
P13 047
1) The document describes calculating the torque on a ladder leaning against a wall and finding the horizontal force needed to keep it from sliding.
2) Key values given include the applied force F, the weight W, and moment arms used to calculate torque.
3) The torque equation is set to zero and rearranged to solve for the horizontal ground force Fgx for different values of F and W.
P13 046
This document describes the tensions in two strings (T and T') that are supporting a weight (W). It provides the force equilibrium equations relating the horizontal and vertical forces of T, T', and W. Solving these simultaneous equations yields that T = 15 N and T' = 29 N.
P13 045
The force exerted on the beam is 7900 N. To find the required cross-sectional area, the formula F/A = Su/6 is used, giving an area of 9.5 x 10-4 m2. Taking the square root of this area gives the thickness of 0.031 m.
P13 044
A steel cable supporting a 670 kg load experiences an elastic stretch proportional to its free length. For a cable length of 12m, the calculated stretch is 0.0008m. For a longer cable length of 350m, the calculated stretch increases to 0.023m due to the cable's increased free length.
P13 043
The document calculates the strain, stress, and Young's modulus of a rope used for rock climbing. It determines that the strain is 1.9 × 10−3 based on the rope's stretched length. The stress is calculated to be 1.3 × 107 N/m2 by relating the force of a 95 kg climber to the rope's cross-sectional area. Finally, it divides the stress by the strain to determine the rope's Young's modulus is 6.9 × 109 N/m2.
P13 042
The document summarizes the calculation of:
1) The volume of sand contained within a cylinder and cone of given dimensions is 6.78 cubic meters.
2) The weight of the sand is calculated to be 1.20 × 105 Newtons based on the volume and density.
3) An equation for stress as a function of radius is derived, with stress proportional to 13r + 40000 pascals.
4) The force on the cylinder is integrated and calculated to be 1.04 × 105 Newtons.
5) The fractional reduction in calculated force compared to measured weight is 13%.
P13 041
The document describes the equations used to determine the angle and tension required to move a log just before it begins to slide. It provides three equations setting the horizontal and vertical forces equal to the maximum static friction and torque, which are solved simultaneously to find the angle is 51 degrees when the coefficient of static friction is 0.8. The tension is then calculated to be 0.64 times the weight of the log.
P13 040
The flat roof of a building has an area of 870 square meters. The volume of material directly above an underground tunnel 60 meters deep is 52,200 cubic meters. With the material having a density of 2,800 kg/m3, the total mass supported by steel columns is 1.46 x 108 kg. The weight supported is 1.4 x 109 Newtons, requiring around 75 columns each able to support 400,000 Newtons over 960 square meters.
P13 038
The brick compresses the two cylinders equally by an amount Δ. This means the force exerted by each cylinder is proportional to its cross-sectional area and elastic modulus. The ratio of the forces is 4:1. Combining this with the equation that the total force equals the weight gives the individual forces as 4W/5 and W/5. Computing torques about the center of mass confirms the 4:1 ratio of the distances of the forces from the center.
P13 036
The Young's modulus (E) of a material was calculated from its stress-strain curve to be 7.5 × 1010 N/m2 based on a stress of 150 × 106 N/m2 and strain of 0.002. The linear range of the curve extended to approximately 2.9 × 108 N/m2, which represents the yield strength of the material where plastic deformation begins.
P13 034
(1) The document discusses the balancing of blocks on a table to determine the maximum height possible given constraints on the center of mass of each block.
(2) For part (a), the maximum height is found to be 9L/8 when the center of mass of each upper block must be above the edge of the lower block.
(3) For part (b), a more subtle condition is considered where forces are exerted between blocks; here the maximum height is found to be 7L/6.
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Do elements of globalization, such as Foreign Direct Investment (FDI), negatively affect the ability of countries in the Global South to preserve their culture? This research aims to answer this question by employing a cross-sectional comparative case study analysis utilizing methods of difference. Thailand and Cambodia are compared as they are in the same region and have a similar culture. The metric of difference between Thailand and Cambodia is their ability to preserve their culture. This ability is operationalized by their respective attitudes towards FDI; Thailand imposes stringent regulations and limitations on FDI while Cambodia does not hesitate to accept most FDI and imposes fewer limitations. The evidence from this study suggests that FDI from globally influential countries with high gross domestic products (GDPs) (e.g. China, U.S.) challenges the ability of countries with lower GDPs (e.g. Cambodia) to protect their culture. Furthermore, the ability, or lack thereof, of the receiving countries to protect their culture is amplified by the existence and implementation of restrictive FDI policies imposed by their governments.
My study abroad in Bali, Indonesia, inspired this research topic as I noticed how globalization is changing the culture of its people. I learned their language and way of life which helped me understand the beauty and importance of cultural preservation. I believe we could all benefit from learning new perspectives as they could help us ideate solutions to contemporary issues and empathize with others.
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1：1制作加拿大麦吉尔大学毕业证硕士学历证书原版一模一样
原版一模一样【微信：741003700 】【加拿大麦吉尔大学毕业证硕士学历证书】【微信：741003700 】学位证，留信认证（真实可查，永久存档）offer、雅思、外壳等材料/诚信可靠,可直接看成品样本，帮您解决无法毕业带来的各种难题！外壳，原版制作，诚信可靠，可直接看成品样本。行业标杆！精益求精，诚心合作，真诚制作！多年品质 ,按需精细制作，24小时接单,全套进口原装设备。十五年致力于帮助留学生解决难题，包您满意。
本公司拥有海外各大学样板无数，能完美还原海外各大学 Bachelor Diploma degree, Master Degree Diploma
1:1完美还原海外各大学毕业材料上的工艺：水印，阴影底纹，钢印LOGO烫金烫银，LOGO烫金烫银复合重叠。文字图案浮雕、激光镭射、紫外荧光、温感、复印防伪等防伪工艺。材料咨询办理、认证咨询办理请加学历顾问Q/微741003700
留信网认证的作用:
1:该专业认证可证明留学生真实身份
2:同时对留学生所学专业登记给予评定
3:国家专业人才认证中心颁发入库证书
4:这个认证书并且可以归档倒地方
5:凡事获得留信网入网的信息将会逐步更新到个人身份内，将在公安局网内查询个人身份证信息后，同步读取人才网入库信息
6:个人职称评审加20分
7:个人信誉贷款加10分
8:在国家人才网主办的国家网络招聘大会中纳入资料，供国家高端企业选择人才
Does teamwork really matter? Looking beyond the job posting to understand lab...
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快速制作美国迈阿密大学牛津分校毕业证文凭证书英文原版一模一样
原版一模一样【微信：741003700 】【美国迈阿密大学牛津分校毕业证文凭证书】【微信：741003700 】学位证，留信认证（真实可查，永久存档）offer、雅思、外壳等材料/诚信可靠,可直接看成品样本，帮您解决无法毕业带来的各种难题！外壳，原版制作，诚信可靠，可直接看成品样本。行业标杆！精益求精，诚心合作，真诚制作！多年品质 ,按需精细制作，24小时接单,全套进口原装设备。十五年致力于帮助留学生解决难题，包您满意。
本公司拥有海外各大学样板无数，能完美还原海外各大学 Bachelor Diploma degree, Master Degree Diploma
1:1完美还原海外各大学毕业材料上的工艺：水印，阴影底纹，钢印LOGO烫金烫银，LOGO烫金烫银复合重叠。文字图案浮雕、激光镭射、紫外荧光、温感、复印防伪等防伪工艺。材料咨询办理、认证咨询办理请加学历顾问Q/微741003700
留信网认证的作用:
1:该专业认证可证明留学生真实身份
2:同时对留学生所学专业登记给予评定
3:国家专业人才认证中心颁发入库证书
4:这个认证书并且可以归档倒地方
5:凡事获得留信网入网的信息将会逐步更新到个人身份内，将在公安局网内查询个人身份证信息后，同步读取人才网入库信息
6:个人职称评审加20分
7:个人信誉贷款加10分
8:在国家人才网主办的国家网络招聘大会中纳入资料，供国家高端企业选择人才
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在线办理(GU毕业证书)美国贡萨加大学毕业证学历证书一模一样
学校原件一模一样【微信：741003700 】《(GU毕业证书)美国贡萨加大学毕业证学历证书》【微信：741003700 】学位证，留信认证（真实可查，永久存档）原件一模一样纸张工艺/offer、雅思、外壳等材料/诚信可靠,可直接看成品样本，帮您解决无法毕业带来的各种难题！外壳，原版制作，诚信可靠，可直接看成品样本。行业标杆！精益求精，诚心合作，真诚制作！多年品质 ,按需精细制作，24小时接单,全套进口原装设备。十五年致力于帮助留学生解决难题，包您满意。
本公司拥有海外各大学样板无数，能完美还原。
1:1完美还原海外各大学毕业材料上的工艺：水印，阴影底纹，钢印LOGO烫金烫银，LOGO烫金烫银复合重叠。文字图案浮雕、激光镭射、紫外荧光、温感、复印防伪等防伪工艺。材料咨询办理、认证咨询办理请加学历顾问Q/微741003700
【主营项目】
一.毕业证【q微741003700】成绩单、使馆认证、教育部认证、雅思托福成绩单、学生卡等！
二.真实使馆公证(即留学回国人员证明,不成功不收费)
三.真实教育部学历学位认证（教育部存档！教育部留服网站永久可查）
四.办理各国各大学文凭(一对一专业服务,可全程监控跟踪进度)
如果您处于以下几种情况：
◇在校期间，因各种原因未能顺利毕业……拿不到官方毕业证【q/微741003700】
◇面对父母的压力，希望尽快拿到；
◇不清楚认证流程以及材料该如何准备；
◇回国时间很长，忘记办理；
◇回国马上就要找工作，办给用人单位看；
◇企事业单位必须要求办理的
◇需要报考公务员、购买免税车、落转户口
◇申请留学生创业基金
留信网认证的作用:
1:该专业认证可证明留学生真实身份
2:同时对留学生所学专业登记给予评定
3:国家专业人才认证中心颁发入库证书
4:这个认证书并且可以归档倒地方
5:凡事获得留信网入网的信息将会逐步更新到个人身份内，将在公安局网内查询个人身份证信息后，同步读取人才网入库信息
6:个人职称评审加20分
7:个人信誉贷款加10分
8:在国家人才网主办的国家网络招聘大会中纳入资料，供国家高端企业选择人才
一比一原版(UoB毕业证)伯明翰大学毕业证如何办理
UoB本科学位证成绩单【微信95270640】伯明翰大学没毕业>办理伯明翰大学毕业证成绩单【微信UoB】UoB毕业证成绩单UoB学历证书UoB文凭《UoB毕业套号文凭网认证伯明翰大学毕业证成绩单》《哪里买伯明翰大学毕业证文凭UoB成绩学校快递邮寄信封》《开版伯明翰大学文凭》UoB留信认证本科硕士学历认证
如果您是以下情况，我们都能竭诚为您解决实际问题：【公司采用定金+余款的付款流程，以最大化保障您的利益，让您放心无忧】
1、在校期间，因各种原因未能顺利毕业，拿不到官方毕业证+微信95270640
2、面对父母的压力，希望尽快拿到伯明翰大学伯明翰大学硕士毕业证成绩单；
3、不清楚流程以及材料该如何准备伯明翰大学伯明翰大学硕士毕业证成绩单；
4、回国时间很长，忘记办理；
5、回国马上就要找工作，办给用人单位看；
6、企事业单位必须要求办理的；
面向美国乔治城大学毕业留学生提供以下服务:
【★伯明翰大学伯明翰大学硕士毕业证成绩单毕业证、成绩单等全套材料，从防伪到印刷，从水印到钢印烫金，与学校100%相同】
【★真实使馆认证（留学人员回国证明），使馆存档可通过大使馆查询确认】
【★真实教育部认证，教育部存档，教育部留服网站可查】
【★真实留信认证，留信网入库存档，可查伯明翰大学伯明翰大学硕士毕业证成绩单】
我们从事工作十余年的有着丰富经验的业务顾问，熟悉海外各国大学的学制及教育体系，并且以挂科生解决毕业材料不全问题为基础，为客户量身定制1对1方案，未能毕业的回国留学生成功搭建回国顺利发展所需的桥梁。我们一直努力以高品质的教育为起点，以诚信、专业、高效、创新作为一切的行动宗旨，始终把“诚信为主、质量为本、客户第一”作为我们全部工作的出发点和归宿点。同时为海内外留学生提供大学毕业证购买、补办成绩单及各类分数修改等服务；归国认证方面，提供《留信网入库》申请、《国外学历学位认证》申请以及真实学籍办理等服务，帮助众多莘莘学子实现了一个又一个梦想。
专业服务，请勿犹豫联系我
如果您真实毕业回国，对于学历认证无从下手，请联系我，我们免费帮您递交
诚招代理：本公司诚聘当地代理人员，如果你有业余时间，或者你有同学朋友需要，有兴趣就请联系我
你赢我赢，共创双赢
你做代理，可以帮助伯明翰大学同学朋友
你做代理，可以拯救伯明翰大学失足青年
你做代理，可以挽救伯明翰大学一个个人才
你做代理，你将是别人人生伯明翰大学的转折点
你做代理，可以改变自己，改变他人，给他人和自己一个机会大块就啃啃得满嘴满脸猴屁股般的红艳大家一个劲地指着对方吃吃地笑瓜裂得古怪奇形怪状却丝毫不影响瓜味甜丝丝的满嘴生津遍地都是瓜横七竖八的活像掷满了一地的大石块摘走二三只爷爷是断然发现不了的即便发现爷爷也不恼反而教山娃辨认孰熟孰嫩孰甜孰淡名义上是护瓜往往在瓜棚里坐上一刻饱吃一顿后山娃就领着阿黑漫山遍野地跑阿黑是一条黑色的大猎狗挺机灵的是山娃多年的忠实伙伴平时山娃上学阿黑也摇头晃脑地跟去暑假用不着上学阿钩
Using Online job postings and survey data to understand labour market trends
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Suzanne Spiteri’s recent report on improving the quality and accessibility of job postings to reduce employment barriers for neurodivergent people.
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Improving the quality and accessibility of job postings is one way to reduce employment barriers for neurodivergent people.Who Is the Largest Producer of Soybean in India Now.pdf
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The Impact of GST Payments on Loan Approvals
Understanding how timely GST payments influence a lender's decision to approve loans, this topic explores the correlation between GST compliance and creditworthiness. It highlights how consistent GST payments can enhance a business's financial credibility, potentially leading to higher chances of loan approval.
一比一原版美国新罕布什尔大学(unh)毕业证学历认证真实可查
永久可查学历认证【微信：A575476】【美国新罕布什尔大学(unh)毕业证成绩单Offer】【微信：A575476】（留信学历认证永久存档查询）采用学校原版纸张、特殊工艺完全按照原版一比一制作（包括：隐形水印，阴影底纹，钢印LOGO烫金烫银，LOGO烫金烫银复合重叠，文字图案浮雕，激光镭射，紫外荧光，温感，复印防伪）行业标杆！精益求精，诚心合作，真诚制作！多年品质 ,按需精细制作，24小时接单,全套进口原装设备，十五年致力于帮助留学生解决难题，业务范围有加拿大、英国、澳洲、韩国、美国、新加坡，新西兰等学历材料，包您满意。
【业务选择办理准则】
一、工作未确定，回国需先给父母、亲戚朋友看下文凭的情况，办理一份就读学校的毕业证【微信：A575476】文凭即可
二、回国进私企、外企、自己做生意的情况，这些单位是不查询毕业证真伪的，而且国内没有渠道去查询国外文凭的真假，也不需要提供真实教育部认证。鉴于此，办理一份毕业证【微信：A575476】即可
三、进国企，银行，事业单位，考公务员等等，这些单位是必需要提供真实教育部认证的，办理教育部认证所需资料众多且烦琐，所有材料您都必须提供原件，我们凭借丰富的经验，快捷的绿色通道帮您快速整合材料，让您少走弯路。
留信网认证的作用:
1:该专业认证可证明留学生真实身份
2:同时对留学生所学专业登记给予评定
3:国家专业人才认证中心颁发入库证书
4:这个认证书并且可以归档倒地方
5:凡事获得留信网入网的信息将会逐步更新到个人身份内，将在公安局网内查询个人身份证信息后，同步读取人才网入库信息
6:个人职称评审加20分
7:个人信誉贷款加10分
8:在国家人才网主办的国家网络招聘大会中纳入资料，供国家高端企业选择人才
→ 【关于价格问题（保证一手价格）
我们所定的价格是非常合理的，而且我们现在做得单子大多数都是代理和回头客户介绍的所以一般现在有新的单子 我给客户的都是第一手的代理价格，因为我想坦诚对待大家 不想跟大家在价格方面浪费时间
对于老客户或者被老客户介绍过来的朋友，我们都会适当给一些优惠。
选择实体注册公司办理，更放心，更安全！我们的承诺：可来公司面谈，可签订合同，会陪同客户一起到教育部认证窗口递交认证材料，客户在教育部官方认证查询网站查询到认证通过结果后付款，不成功不收费！
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- 1. 61. (a) Setting up equilibrium of torques leads to L L Ffar end L = (73 kg)(9.8 m/s2 ) + (2700 N) 4 2 which yields Ffar end = 1.5 × 103 N. (b) Then, equilibrium of vertical forces provides Fnear end = (73)(9.8) + 2700 − Ffar end = 1.9 × 103 N .