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Presented by
Engr. Syed Ghulam Mustafa
Dy. Manager TSG (South) NTDC
In this lesson you will…
• Define electric current and ampere
• Describe the direction of charge flow in conventional current.
• Explain the origin of Ohm’s law.
• Calculate voltages, currents, or resistances with Ohm’s law.
• Describe a simple circuit.
Conventional Current
 Electrons are the charge that
flows through wires
 Historically thought positive
charges move
 Conventional current 
imaginary flow of positive
charges
 Flows from positive terminal and
into negative terminal
 Real current flows the opposite
way
 Think of water pumps
 Bigger pumps  more water flowing
 Skinny pipes (more resistance)  less water flow
 Electrical Circuits
 Bigger battery voltage  more current
 Big electrical resistance  less current
Resistors
 Device that offers
resistance to flow of
charges
 Copper wire has very little
resistance
 Symbols used for
 Resistor 
 Wire 
Kilowatt hours
 Electrical companies charge you for the amount of
electrical energy you use
 Measured in kilowatt hours (kWh)
 If electricity costs $0.15 per kWh how much does it
cost to operate the previous heater (P = 10.1 W) for
one month?
 $1.09
Alternating Current
 Charge flow reverses direction periodically
 Due to way that power plants generate power
 Simple circuit
Periodicity
 Voltage, Current, and Power fluctuate with time
 So we usually talk about the averages
 Why are you not supposed to use extension cords for
devices that use a lot of power like electric heaters?
 P = IV
 P is large so I is large
 The wire has some resistance
 The large current and little resistance can cause heating
 If wire gets too hot, the plastic insulation melts
Series Wiring
 More than one device
on circuit
 Same current through
each device
 Break in device means
no current
 Form one “loop”
 The resisters divide the
voltage between them
 V divide among
resistors
 V = V1 + V2 + V3
 V = IR
 V = IR1 + IR2 + IR3
 V = I(R1 + R2 +R3)
 V = IRS
 RS = R1 + R2 + R3 + …
 A 5.17 k resistor and a 10.09 k resistor are
connected in series. What is the equivalent
resistance?
 15.26 k
 Bathroom vanity lights are occasionally wired in
series. V = 120 V and you install 3 bulbs with R =
8 and 1 bulb with R = 12. What is the current,
voltage of each bulb, and the total power used?
 I = 3.33 A
 V = 26.7 V, 40 V
 Ptotal = 400 W
Parallel Wiring
 Same voltage across
several devices
 Typical house wiring
 Break in device has no
effect on current
 Resistors divide
current
Derivation
 Each branch draws current as if the other
wasn’t there
 Each branch draws less current than the power
supply gives
 R = V / I
 Overall circuit: Large I  Small R
 Smaller resistance than either branch
Ohms Law-  seriess and ckt understanding.pptx
Ohms Law-  seriess and ckt understanding.pptx
Ohms Law-  seriess and ckt understanding.pptx

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Ohms Law- seriess and ckt understanding.pptx

  • 1. Presented by Engr. Syed Ghulam Mustafa Dy. Manager TSG (South) NTDC
  • 2. In this lesson you will… • Define electric current and ampere • Describe the direction of charge flow in conventional current. • Explain the origin of Ohm’s law. • Calculate voltages, currents, or resistances with Ohm’s law. • Describe a simple circuit.
  • 3.
  • 4. Conventional Current  Electrons are the charge that flows through wires  Historically thought positive charges move  Conventional current  imaginary flow of positive charges  Flows from positive terminal and into negative terminal  Real current flows the opposite way
  • 5.  Think of water pumps  Bigger pumps  more water flowing  Skinny pipes (more resistance)  less water flow  Electrical Circuits  Bigger battery voltage  more current  Big electrical resistance  less current
  • 6.
  • 7. Resistors  Device that offers resistance to flow of charges  Copper wire has very little resistance  Symbols used for  Resistor   Wire 
  • 8.
  • 9.
  • 10.
  • 11. Kilowatt hours  Electrical companies charge you for the amount of electrical energy you use  Measured in kilowatt hours (kWh)  If electricity costs $0.15 per kWh how much does it cost to operate the previous heater (P = 10.1 W) for one month?  $1.09
  • 12. Alternating Current  Charge flow reverses direction periodically  Due to way that power plants generate power  Simple circuit
  • 13. Periodicity  Voltage, Current, and Power fluctuate with time  So we usually talk about the averages
  • 14.
  • 15.
  • 16.  Why are you not supposed to use extension cords for devices that use a lot of power like electric heaters?  P = IV  P is large so I is large  The wire has some resistance  The large current and little resistance can cause heating  If wire gets too hot, the plastic insulation melts
  • 17. Series Wiring  More than one device on circuit  Same current through each device  Break in device means no current  Form one “loop”  The resisters divide the voltage between them
  • 18.  V divide among resistors  V = V1 + V2 + V3  V = IR  V = IR1 + IR2 + IR3  V = I(R1 + R2 +R3)  V = IRS  RS = R1 + R2 + R3 + …
  • 19.  A 5.17 k resistor and a 10.09 k resistor are connected in series. What is the equivalent resistance?  15.26 k
  • 20.  Bathroom vanity lights are occasionally wired in series. V = 120 V and you install 3 bulbs with R = 8 and 1 bulb with R = 12. What is the current, voltage of each bulb, and the total power used?  I = 3.33 A  V = 26.7 V, 40 V  Ptotal = 400 W
  • 21. Parallel Wiring  Same voltage across several devices  Typical house wiring  Break in device has no effect on current  Resistors divide current
  • 22. Derivation  Each branch draws current as if the other wasn’t there  Each branch draws less current than the power supply gives  R = V / I  Overall circuit: Large I  Small R  Smaller resistance than either branch