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n Monopoly one rolls a pair of dice. Find the probability of getting a sum of 4.
Solution
In monopoly sum on the dice getting 4 is considered as an event Then n(A) = 3
ways (2,2), (1,3),(3,1) Total combinations of events = N = 36 So, the probability of getting sum
4 on pair of dice i.e. the probability of the event A = P(A) = 3/36 = 1/12.

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