n Monopoly one rolls a pair of dice. Find the probability of getting a sum of 4. Solution In monopoly sum on the dice getting 4 is considered as an event Then n(A) = 3 ways (2,2), (1,3),(3,1) Total combinations of events = N = 36 So, the probability of getting sum 4 on pair of dice i.e. the probability of the event A = P(A) = 3/36 = 1/12..