My code is not matching up with the results.The output for the cod.pdf
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My code is not matching up with the results. The output for the code should be: >>> Test Teacher class Teacher: Paul Tan(8 sunset way) IM101 added. IM102 added. IM101 cannot be added. IM101 removed. IM101 removed. IM102 removed. IM102 cannot be removed. Person class: public class Person { private String name; private String address; public Person(String name, String address) { this.name = name; this.address = address; } public Person(String address){ this.address = address; } public String getName(){ return name; } public String getAddress(){ return address; } public void setAddress(String address){ this.address = address; } public String toString() { return name + \"(\" + address + \")\"; } } Teacher sub class import java.util.ArrayList; public class Teacher extends Person { private int numCourses = 0; private ArrayList courses = new ArrayList(); public Teacher(String name, String address){ super(name,address); } @Override public String toString() { return \"Teacher: \" + super.toString(); } public boolean addCourse (String course){ for (int i = 0; i < numCourses; i++) { if (courses.get(i).equals(course)) return false; } courses.add(course); numCourses++; return true; } public boolean removeCourse (String course){ boolean found = false; int courseIndex = -1; for (int j = 0; j < numCourses; j++) { if (courses.get(j).equals(course)) { courseIndex = j; found = true; break; } } if (found) { for (int k = courseIndex; k < numCourses-1; k++) { courses.get(k+1); } numCourses--; return true; } else { return false; } } } Person Launcer System.out.println(\"\ \"); System.out.println(\">>> Test Teacher class\"); Teacher tch = new Teacher (\"Paul Tan\", \"8 sunset way\"); System.out.println(tch); String[] courses = {\"IM101\", \"IM102\", \"IM101\"}; for (String course: courses) { if (tch.addCourse(course)) { System.out.println(course + \" added.\"); } else { System.out.println(course + \" cannot be added.\"); } } for (String course: courses) { if (tch.removeCourse(course)) { System.out.println(course + \" removed.\"); } else { System.out.println(course + \" cannot be removed.\"); } } System.out.println(\"\ \"); Solution // edit the below method like this : public boolean removeCourse (String course){ boolean found = false; int courseIndex = -1; for (int j = 0; j < numCourses; j++) { if (courses.get(j).equals(course)) { courseIndex = j; found = true; break; } } if (found) { courses.remove(course); numCourses--; return true; } else { return false; } }.
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Recommended
Modul Praktek Java OOP
Modul untuk Praktikum Pengolahan Database di Java dengan menggunakan konsep OOP Mata Pelajaran Pemrograman Internet dengan Java-JSP SMK Telkom Sandhy Putra Malang
Code Smells y Refactoring o haciendo que nuestro codigo huela (y se vea) mejo...
Code Smells y Refactoring o haciendo que nuestro codigo huela (y se vea) mejor
Mariano Sanchez
.NET Conf UY 2014
http://netconf.uy
Hello. Im currently working on the last section to my assignment a.pdf
Hello. I\'m currently working on the last section to my assignment and I\'m running into issues.
I\'ll post a screenshot of the directions provided to us, my 5 classes, and a screenshot of my
console output. Can you help me fix my code? I don\'t know where it\'s going wrong and I can\'t
figure it out. Please leave comments on what I did wrong so I can learn from it. Thank you so
much!
Here is the instructions from the pdf for reference on what I\'m trying to accomplish.
package campus;
public class Person {
private String id;
private String lastName;
private String firstName;
public Person(String id, String last, String first)
{
this.id = id;
this.lastName = last;
this.firstName = first;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getId() {
return id;
}
public String toString()
{
return id + \": \" + firstName + \" \" + lastName;
}
}
------
---Student.java---
package campus;
public class Student extends Person {
private String major;
private int level;
private Person obj;
public Student(String id, String last, String first, String focus, int level) {
super(id, last, first);// calling parent constructor
this.major = focus;
this.level = level;
obj = new Person(id, last, first);
}
public String getMajor() {
return major;
}
public void setMajor(String major) {
this.major = major;
}
public int getLevel() {
return level;
}
public void setLevel(int level) {
this.level = level;
}
@Override
public String toString() { // override toString() method
return \"id: \" + obj.getId() + \", Name: \" + obj.getFirstName() + \" \" + obj.getLastName()
+ \", major is \"
+ this.major + \" and their level is \" + this.level;
}
}
------
---Faculty.java---
package campus;
public class Faculty extends Person {
private String dept;
private String rank;
private Person obj;
public Faculty(String id, String last, String first, String focus, int level) {
super(id, last, first);// calling parent constructor
}
public String getDept() {
return dept;
}
public void setDept(String dept) {
this.dept = dept;
}
public String getRank() {
return rank;
}
public void setRank(int level) {
this.rank = rank;
}
@Override
public String toString() { // override toString() method
return \"id: \" + obj.getId() + \", Name: \" + obj.getFirstName() + \" \" + obj.getLastName()
+ \", deptartment is \"
+ this.dept + \" and their rank is \" + this.rank;
}
}
------
---Section.java---
package campus;
public class Section {
private String id;
private Faculty instructor;
private Student[] enrolled;
private int numofEnroll;
private int capacity;
private String location;
private String time;
private String semester;
public Section(String id, Faculty instructor, int capacity, String location, String time, String
semester) {
}
public Section(String id, int capacity) {
this.id = id;
this.capacity .
Team public class Team { private String teamId; priva.pdf
Team:
public class Team {
private String teamId;
private String name;
private String firstName;
private String lastName;
private String phoneNumber;
private String emailAddress;
Team(String teamId, String name, String firstName, String lastName, String phoneNumber,
String emailAddress) {
this.teamId = teamId;
this.name = name;
this.firstName = firstName;
this.lastName = lastName;
this.phoneNumber = phoneNumber;
this.emailAddress = emailAddress;
}
public String getTeamId() {
return teamId;
}
public void setTeamId(String teamId) {
this.teamId = teamId;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public String getPhoneNumber() {
return phoneNumber;
}
public void setPhoneNumber(String phoneNumber) {
this.phoneNumber = phoneNumber;
}
public String getEmailAddress() {
return emailAddress;
}
public void setEmailAddress(String emailAddress) {
this.emailAddress = emailAddress;
}
public static boolean checkEmailAddress(String emailAddress) {
return emailAddress.contains(\"@\");
}
@Override
public String toString() {
return \"Team [teamId=\" + teamId + \", name=\" + name + \", firstName=\" + firstName +
\", lastName=\" + lastName
+ \", phoneNumber=\" + phoneNumber + \", emailAddress=\" + emailAddress + \"]\";
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + ((emailAddress == null) ? 0 : emailAddress.hashCode());
result = prime * result + ((firstName == null) ? 0 : firstName.hashCode());
result = prime * result + ((lastName == null) ? 0 : lastName.hashCode());
result = prime * result + ((name == null) ? 0 : name.hashCode());
result = prime * result + ((phoneNumber == null) ? 0 : phoneNumber.hashCode());
result = prime * result + ((teamId == null) ? 0 : teamId.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
Team other = (Team) obj;
if (emailAddress == null) {
if (other.emailAddress != null)
return false;
} else if (!emailAddress.equals(other.emailAddress))
return false;
if (firstName == null) {
if (other.firstName != null)
return false;
} else if (!firstName.equals(other.firstName))
return false;
if (lastName == null) {
if (other.lastName != null)
return false;
} else if (!lastName.equals(other.lastName))
return false;
if (name == null) {
if (other.name != null)
return false;
} else if (!name.equals(other.name))
return false;
if (phoneNumber == null) {
if (other.phoneNumber != null)
return false;
} else if (!phoneNumber.equals(other.phoneNumber))
return false;
if (teamId == null) {
if (other.teamId != null)
return false;
} else if (!teamId.equals(other.teamId))
return false;
r.
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Code Smells y Refactoring o haciendo que nuestro codigo huela (y se vea) mejo...
Code Smells y Refactoring o haciendo que nuestro codigo huela (y se vea) mejor
Mariano Sanchez
.NET Conf UY 2014
http://netconf.uy
Hello. Im currently working on the last section to my assignment a.pdf
Hello. I\'m currently working on the last section to my assignment and I\'m running into issues.
I\'ll post a screenshot of the directions provided to us, my 5 classes, and a screenshot of my
console output. Can you help me fix my code? I don\'t know where it\'s going wrong and I can\'t
figure it out. Please leave comments on what I did wrong so I can learn from it. Thank you so
much!
Here is the instructions from the pdf for reference on what I\'m trying to accomplish.
package campus;
public class Person {
private String id;
private String lastName;
private String firstName;
public Person(String id, String last, String first)
{
this.id = id;
this.lastName = last;
this.firstName = first;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getId() {
return id;
}
public String toString()
{
return id + \": \" + firstName + \" \" + lastName;
}
}
------
---Student.java---
package campus;
public class Student extends Person {
private String major;
private int level;
private Person obj;
public Student(String id, String last, String first, String focus, int level) {
super(id, last, first);// calling parent constructor
this.major = focus;
this.level = level;
obj = new Person(id, last, first);
}
public String getMajor() {
return major;
}
public void setMajor(String major) {
this.major = major;
}
public int getLevel() {
return level;
}
public void setLevel(int level) {
this.level = level;
}
@Override
public String toString() { // override toString() method
return \"id: \" + obj.getId() + \", Name: \" + obj.getFirstName() + \" \" + obj.getLastName()
+ \", major is \"
+ this.major + \" and their level is \" + this.level;
}
}
------
---Faculty.java---
package campus;
public class Faculty extends Person {
private String dept;
private String rank;
private Person obj;
public Faculty(String id, String last, String first, String focus, int level) {
super(id, last, first);// calling parent constructor
}
public String getDept() {
return dept;
}
public void setDept(String dept) {
this.dept = dept;
}
public String getRank() {
return rank;
}
public void setRank(int level) {
this.rank = rank;
}
@Override
public String toString() { // override toString() method
return \"id: \" + obj.getId() + \", Name: \" + obj.getFirstName() + \" \" + obj.getLastName()
+ \", deptartment is \"
+ this.dept + \" and their rank is \" + this.rank;
}
}
------
---Section.java---
package campus;
public class Section {
private String id;
private Faculty instructor;
private Student[] enrolled;
private int numofEnroll;
private int capacity;
private String location;
private String time;
private String semester;
public Section(String id, Faculty instructor, int capacity, String location, String time, String
semester) {
}
public Section(String id, int capacity) {
this.id = id;
this.capacity .
Team public class Team { private String teamId; priva.pdf
Team:
public class Team {
private String teamId;
private String name;
private String firstName;
private String lastName;
private String phoneNumber;
private String emailAddress;
Team(String teamId, String name, String firstName, String lastName, String phoneNumber,
String emailAddress) {
this.teamId = teamId;
this.name = name;
this.firstName = firstName;
this.lastName = lastName;
this.phoneNumber = phoneNumber;
this.emailAddress = emailAddress;
}
public String getTeamId() {
return teamId;
}
public void setTeamId(String teamId) {
this.teamId = teamId;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public String getPhoneNumber() {
return phoneNumber;
}
public void setPhoneNumber(String phoneNumber) {
this.phoneNumber = phoneNumber;
}
public String getEmailAddress() {
return emailAddress;
}
public void setEmailAddress(String emailAddress) {
this.emailAddress = emailAddress;
}
public static boolean checkEmailAddress(String emailAddress) {
return emailAddress.contains(\"@\");
}
@Override
public String toString() {
return \"Team [teamId=\" + teamId + \", name=\" + name + \", firstName=\" + firstName +
\", lastName=\" + lastName
+ \", phoneNumber=\" + phoneNumber + \", emailAddress=\" + emailAddress + \"]\";
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + ((emailAddress == null) ? 0 : emailAddress.hashCode());
result = prime * result + ((firstName == null) ? 0 : firstName.hashCode());
result = prime * result + ((lastName == null) ? 0 : lastName.hashCode());
result = prime * result + ((name == null) ? 0 : name.hashCode());
result = prime * result + ((phoneNumber == null) ? 0 : phoneNumber.hashCode());
result = prime * result + ((teamId == null) ? 0 : teamId.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
Team other = (Team) obj;
if (emailAddress == null) {
if (other.emailAddress != null)
return false;
} else if (!emailAddress.equals(other.emailAddress))
return false;
if (firstName == null) {
if (other.firstName != null)
return false;
} else if (!firstName.equals(other.firstName))
return false;
if (lastName == null) {
if (other.lastName != null)
return false;
} else if (!lastName.equals(other.lastName))
return false;
if (name == null) {
if (other.name != null)
return false;
} else if (!name.equals(other.name))
return false;
if (phoneNumber == null) {
if (other.phoneNumber != null)
return false;
} else if (!phoneNumber.equals(other.phoneNumber))
return false;
if (teamId == null) {
if (other.teamId != null)
return false;
} else if (!teamId.equals(other.teamId))
return false;
r.
public class Person { private String name; private int age;.pdf
public class Person
{
private String name;
private int age;
public Person()
{
name=\"\";
age=0;
}
/**
Create a person with a given name and age.
@param name the name
@param age the age
*/
public Person(String name, int age)
{
this.name = name;
this.age = age;
}
/**
Get the name.
@return the name
*/
public String getName()
{
return name;
}
/**
Change the name.
@param name the name
*/
public void setName(String name)
{
this.name = name;
}
/**
Get the age.
@return the age
*/
public int getAge()
{
return age;
}
/**
Change the age.
@param age the age
*/
public void setAge()
{
this.age = age;
}
/**
Convert person to string form.
*/
public String toString()
{
return \"Name: \" + name + \"\\t\" + \"Age: \" + age;
}
}
OUTPUT should look like this!
Solution
solution
package com.prt.test;
public class Person
{
protected String name;
protected int age;
public Person()
{
name=\"\";
age=0;
}
/**
Create a person with a given name and age.
@param name the name
@param age the age
*/
public Person(String name, int age)
{
this.name = name;
this.age = age;
}
/**
Get the name.
@return the name
*/
public String getName()
{
return name;
}
/**
Change the name.
@param name the name
*/
public void setName(String name)
{
this.name = name;
}
/**
Get the age.
@return the age
*/
public int getAge()
{
return age;
}
/**
Change the age.
@param age the age
*/
public void setAge()
{
this.age = age;
}
/**
Convert person to string form.
*/
public String toString()
{
return \"Name: \" + name + \"\\t\" + \"Age: \" + age;
}
}
package com.prt.test;
public class Student extends Person implements Comparable{
private int studentId;
private String major;
/**
* @return the studentId
*/
public int getStudentId() {
return studentId;
}
/**
* @param studentId the studentId to set
*/
public void setStudentId(int studentId) {
this.studentId = studentId;
}
/**
* @return the major
*/
public String getMajor() {
return major;
}
/**
* @param major the major to set
*/
public void setMajor(String major) {
this.major = major;
}
public Student(String name, int age, int studentId, String major) {
super(name, age);
this.studentId = studentId;
this.major = major;
}
/* (non-Javadoc)
* @see java.lang.Object#toString()
*/
@Override
public String toString() {
return \"name:\" + name+ \"\\t\"+\"\\t\"+\"age:\"+ age+\"\\t\"+ \"studentId :\"+ studentId +
\"\\t\" +\" major:\"+ major;
}
public int compareTo(Student st){
if(studentId==st.studentId)
return 0;
else if(studentId>st.studentId)
return 1;
else
return -1;
}
}
package com.prt.test;
public class Instructor extends Person implements Comparable {
private double salary;
public Instructor(String name, int age, double salary) {
super(name, age);
this.salary = salary;
}
/**
* @return the salary
*/
public double getSalary() {
return salary;
}
/**
* @param salary
* the salary to set
*/
public void setSalary(double salary) {
this.salary = salary;
}
public int compareTo(Instructor is) {
if (salary == is.salary)
return 0;
else if (salary > is.salary)
return 1;
else
ret.
C# Is The Future
C# is here to stay, it is time to embrace one of the most popular languages of the future and learn what is coming. In this talk we will look at how C# has evolved over time, and why it is definitely here to stay!
Scala 2013 review
Slides from my talk at the Junction (Jan 24, 2013)
Single-core performance has hit a ceiling, and building web-scale multi-core applications using imperative programming models is nightmarishly difficult. Parallel programming creates a new set of challenges, best practices and design patterns. Scala is designed to enable building scalable systems, elegantly blending functional and object oriented paradigms into an expressive and concise language, while retaining interoperability with Java. Scala is the fastest growing JVM programming language, being rapidly adopted by leading companies such as Twitter, LinkedIn and FourSquare.
This presentation provides a comprehensive overview of the language, which managed to increase type safety while feeling more dynamic, being more concise and improving readability at the same time. We will see how Scala simplifies real life problems by empowering the developer with powerful functional programming primitives, without giving up on the object oriented paradigm. The overview includes tools for multi-core programming in Scala, the type system, collection framework and domain-specific languages. We’ll explore the power of compile-time meta-programming, which is made possible by the newly released Scala 2.10, and get a glimpse into what to expect from 2.11 in 2014.
We will also see how Scala helps overcome the inherent limitations of Java, such as type erasure, array covariance and boxing overhead.
Multiple examples emphasize how Scala pushes the JVM harder than any other mainstream language through the infinite number of boilerplate busters, increased type safety and productivity boosters from a Java developer’s perspective.
please help with java questionsJAVA CODEplease check my code and.pdf
please help with java questions
JAVA CODE
please check my code and help my questions
CLASS ADDRESS
public class Address{
private int streetNumber;
private String streetName;
private String city;
private String state;
private String country;
// streetNumber
// streetName
// city
// state
// country
public Address(int streetNumber, String streetName, String city, String state, String country) {
this.streetNumber = streetNumber;
this.streetName = streetName;
this.city = city;
this.state = state;
this.country = country;
}
//return the streetNumber
public int getStreetNumber() {
return streetNumber;
}
// set street number
public void setStreetNumber(int streetNumber) {
this.streetNumber = streetNumber;
}
//return the streetName
public String getStreetName() {
return streetName;
}
// set street name
public void setStreetName(String streetName) {
this.streetName = streetName;
}
//return the city
public String getCity() {
return city;
}
//set the city
public void setCity(String city) {
this.city = city;
}
//return the state
public String getState() {
return state;
}
//the state to set
public void setState(String state) {
this.state = state;
}
// return the country
public String getCountry() {
return country;
}
// tset country
public void setCountry(String country) {
this.country = country;
}
// see java.lang.Object#toString()
@Override
public String toString() {
return \" [streetNumber=\" + streetNumber + \", streetName=\" + streetName
+ \", city=\" + city + \", state=\" + state + \", country=\"
+ country + \"]\";
}
}
////////////////////////////////////////////////////////////////////////////////////////
CLASS PERSON
public class Person extends Address {
private String name;
public Person (int streetNumber, String streetName, String city, String state, String country,
String name) {
super(streetNumber, streetName, city, state, country);
this.name = name;
}
//retuurn name
public String getName() {
return name;
}
// set name
public void setName(String name) {
this.name = name;
}
//see java.lang.Object#toString()
@Override
public String toString() {
return \"Person [name=\" + name + \", getStreetNumber()=\"
+ getStreetNumber() + \", getStreetName()=\" + getStreetName()
+ \", getCity()=\" + getCity() + \", getState()=\" + getState()
+ \", getCountry()=\" + getCountry() + \", toString()=\"
+ super.toString() + \", getClass()=\" + getClass()
+ \", hashCode()=\" + hashCode() + \"]\";
}
}
/////////////////////////////////////////////////////////////////
CLASS STUDENT
import java.util.ArrayList;
import java.util.List;
public class Student extends Person {
private String CIN;
List courses;
public Student(int streetNumber, String streetName, String city, String state, String country,
String name, String CIN) {
super(streetNumber, streetName, city, state, country, name);
// Auto-generated constructor stub
this.CIN = CIN;
courses = new ArrayList();
}
// reutrn cin
public String getCIN() {
return CIN;
}
// set cin
public void setCIN(String cIN) {
CIN = cIN;
}
pub.
Add a private variable SSN to the person class- Add a private variable.pdf
Add a private variable SSN to the person class.
Add a private variable major to the student class.
Modify the InheritanceDemo to read the name, student Number, SSN, and the major.
Upload the the three modified files. You have to add the comments and explanations for the
modified files.
public class Person
{
private String name;
public Person( )
{
name = "No name yet";
}
public Person(String initialName)
{
name = initialName;
}
public void setName(String newName)
{
name = newName;
}
public String getName( )
{
return name;
}
public void writeOutput( )
{
System.out.println("Name: " + name);
}
public boolean hasSameName(Person otherPerson)
{
return this.name.equalsIgnoreCase(otherPerson.name);
}
}
public class Student extends Person
{
private int studentNumber;
public Student( )
{
super( );
studentNumber = 0;//Indicating no number yet
}
public Student(String initialName, int initialStudentNumber)
{
super(initialName);
studentNumber = initialStudentNumber;
}
public void reset(String newName, int newStudentNumber)
{
setName(newName);
studentNumber = newStudentNumber;
}
public int getStudentNumber( )
{
return studentNumber;
}
public void setStudentNumber(int newStudentNumber)
{
studentNumber = newStudentNumber;
}
public void writeOutput( )
{
System.out.println("Name: " + getName( ));
System.out.println("Student Number: " + studentNumber);
}
public boolean equals(Student otherStudent)
{
return this.hasSameName(otherStudent) &&
(this.studentNumber == otherStudent.studentNumber);
}
public String toString( )
{
return "Name: " + getName( ) +
"\nStudent number: " + studentNumber;
}
/* //For Optional Section
public boolean equals(Object otherObject)
{
if (otherObject == null)
return false;
else if (!(otherObject instanceof Student))
return false;
else
{
Student otherStudent = (Student)otherObject;
return (this.sameName(otherStudent)
&& (this.studentNumber ==
otherStudent.studentNumber));
}
}
*/
}
public class InheritanceDemo
{
public static void main(String[] args)
{
Student s = new Student( );
s.setName("Warren Peace");
s.setStudentNumber(1234);
s.writeOutput( );
}
}.
Java Class Design
This presentation provides an overview of key topics in Java class design; also covers best practices/tips and quiz questions. Based on our OCP 8 book.
HELP IN JAVACreate a main method and use these input files to tes.pdf
For the questions below, use the W3Schools customer orders database. You need to submit
thoroughly tested SQL statements. For your convenience and reference, relevant data model is
attached as a PDF document with the assignment in the Blackboard. Name of this document is
\"Relationship diagram for W3schools order pdf.\" 1) Write a query to show Customers\' Country
wise sales totals. Your query should show Customers\' Country name and the total sale value for
that Country 2) Write a query to show Product wise sales totals. Your query should Product
name and the total sale value for that Product. 3) Write a query to show the number of orders for
each shipper. Your query should show shipper name and the count of orders with the shipper. 4)
Write a query to show number of products in each product category. Your query should show
Category name and number of products in that category 5) Write a query that shows Customers\'
country wise customer count, and order count. Your query should show country name, total
number of customers from that country, and total number of orders from the customers of that
country 6) Write a query that shows the number of products supplied by each Supplier. Your
query should show Country name, supplier name and the count of products supplied by that
supplier. Note: Sale Price Orderdetails.Quantity Products.price (see an example in the class
slides deck) W3SCHOOLS SQL is located at http://www.w3schools.com/sql/default.asp
(Preferred browser is Chrome). On this page you will find a button called \"Try it yourself\".
Click on that button. You will be redirected to a page where you see a list of tables on the right
side of the page. It is highly recommended to click \'Restore Database\' button on this page
during every session. The page contains a box where you can type in an SQL statement
involving the listed tables. You type in your SQL statement in that box and click on \"Run
SQL\'\' button. The results will be displayed if your SQL statement is syntactically correct.
Solution
1. SELECT Customers.Country, SUM(OrderDetails.Quantity * Products.Price) AS Total_Sale
FROM Customers
LEFT JOIN Orders ON Customers.CustomerID=Orders.CustomerID
LEFT JOIN OrderDetails ON Orders.OrderId=OrderDetails.OrderId
LEFT JOIN Products ON OrderDetails.ProductId=Products.ProductId
Group BY Customers.Country;
2. SELECT Products.ProductName, SUM(OrderDetails.Quantity * Products.Price) AS
Total_Sale FROM Customers
LEFT JOIN Orders ON Customers.CustomerID=Orders.CustomerID
LEFT JOIN OrderDetails ON Orders.OrderId=OrderDetails.OrderId
LEFT JOIN Products ON OrderDetails.ProductId=Products.ProductId
Group BY Products.ProductName;
You can edit these query to get other results set..
Problem 1 Create Node class (or use what you have done in Lab4)• .pdf
Problem 1: Create Node class (or use what you have done in Lab4)
• Add methods to get and set, Data and Link
• Here the data is an object. (java object) your Linked List can hold any java class.
a) Create MyLinkedList2 class and write methods to
• Methods to insert nodes at the beginning, at the end and at a specific position. insertFirst(Node
x), insertLast(Node x) , insertLast(Node x, int pos)
• Methods to delete node from the beginning and from the end. delFirst(), delLast()
• Method to search the Linked List for a specific object. searchList(x Object)
• Method to Sort the Linked List in ascendant or descendant order according to the object
value(s). for example sorted by name, by age, by gpa. sortAsc(),sortDesc().
• Method to display all nodes objects (printing an object is related to its toString() method).
• Method to return the largest and smallest object in the list – maxList(), minList() according to
some specific object members.
. • Method to return the number of nodes – listSize()
• Method to merge two linked Lists into one. MyLinkedList2 list3= mergeList(MyLinkedList2
list1, MyLinkedList2 list2)
b) Create Main class : MyLinkedList2Demo
• Create a linked List LL1 and insert some objects to it. Use any a student java class.
• Fill LL1 by adding students from an input file.
• Display all the objects (students) in the List LL1
• Search for a particular object (Student by name or by Id or both) in LL1 and print true or false
• Sort LL1 and display it ( using asc and desc on multiple members)
• Perform all the delete methods on LL1.
• Perform all the insert methods on LL1.
• Call and run all the implemented methods in a sequential order. NB: Organize a nice output for
all the questions above.
Problem 2: Same as Pb1 using double linked lists. Create Nod3e and MyLinkedList3 classes.
--------------------------------------------------------------------------------------------------------------------
---------------------------------------------------
The input file :
id fname lname age gpa year college cuCourses totalCourses
201412345 Amna chamisi 17 2.1 2014 CIT 5 30
201112345 Amna chamisi 17 2.1 2014 ENG 31 32
201412345 Amna chamisi 17 2.1 2014 COE 5 29
201412345 Amna chamisi 17 2.1 2014 CIT 5 30
201412345 Amna chamisi 17 2.1 2014 CIT 5 30
201412345 Amna chamisi 17 2.1 2014 CIT 5 30
201412345 Amna chamisi 17 2.1 2014 CIT 5 30
Solution
/**
* Node.java
* @author
*
*/
public class Node {
public Object getObj() {
return obj;
}
public Node setObj(Object obj) {
this.obj = obj;
return this;
}
public Node getNext() {
return next;
}
public Node setNext(Node next) {
this.next = next;
return this;
}
private Object obj;
private Node next;
}
import java.util.Collections;
import java.util.Comparator;
import java.util.LinkedList;
/**
* MyLinkedList2.java
* @author
*
*/
public class MyLinkedList2 {
public void insertFirst(Node x) {
if (head == null) {
head = x;
} else {
x.setNext(head);
}
}
public void insertLast(Node x) {
if (head == null) {
head = x;
r.
why will it not display all of the entries-- output -nMenu n-Add Entr.pdf
why will it not display all of the entries??
output
/nMenu
n.Add Entry
d. Delete Entry
u. Update Entry
l. Search
a. View All
q. Exit
/nMenu
n.Add Entry
d. Delete Entry
u. Update Entry
l. Search
a. View All
q. Exit
n
Enter a name: carnea
Enter an address: 30 carrollton
New Contact has been added,
/nMenu
n.Add Entry
d. Delete Entry
u. Update Entry
l. Search
a. View All
q. Exit
n
Enter a name: Tesia
Enter an address: 1010 hancover
New Contact has been added,
/nMenu
n.Add Entry
d. Delete Entry
u. Update Entry
l. Search
a. View All
q. Exit
n.Add Entry
d. Delete Entry
u. Update Entry
l. Search
a. View All
q. Exit
a
All entries:
carnea:30 carrollton
THE CODE:
import java.util.Scanner;
public class AddressBook {
public static void main(String[] args) {
Tablea addressBook = new Tablea();
Scanner scanner = new Scanner(System.in);
String name, address;
String action = null;
boolean moreEntries = true;
while (moreEntries) {
System.out.println("/nMenu");
System.out.println("n.Add Entry");
System.out.println("d. Delete Entry");
System.out.println("u. Update Entry");
System.out.println("l. Search");
System.out.println("a. View All");
System.out.println("q. Exit");
action = scanner.nextLine();
// Insert a new entry into the address book
switch (action) {
case "n":
System.out.print("Enter a name: ");
name = scanner.nextLine();
System.out.print("Enter an address: ");
address = scanner.nextLine();
addressBook.insert(name, address);
System.out.println("New Contact has been added,");
break;
// Delete an entry from the address book
case "d":
System.out.println("Enter a name to delete: ");
name = scanner.nextLine();
boolean deleted = addressBook.delete(name);
if (deleted) {
System.out.println("Address deleted");
} else {
System.out.println("Name not found");
}
break;
// Update an entry in the address book
case "u":
System.out.print("Enter a name to update: ");
name = scanner.nextLine();
System.out.print("Enter a new address: ");
address = scanner.nextLine();
boolean updated = addressBook.update(name, address);
if (updated) {
System.out.println("Address updated");
} else {
System.out.println("Name not found");
}
break;
// Lookup an entry in the address book
case "l":
System.out.print("Enter a name to look up: ");
name = scanner.nextLine();
String result = addressBook.lookUp(name);
if (result != null) {
System.out.println("Address: " + result);
} else {
System.out.println("Name not found");
}
break;
// Display all entries in the address book
case "a":
System.out.println("All entries:");
addressBook.displayAll();
break;
// Quit the program
case"q":
System.out.println("Quitting...");
}
}
}
}
public class Node {
private String name;
private String address;
private Node next;
public Node(String name, String address) {
this.name = name;
this.address = address;
}
public String getName() {
return this.name;
}
public void setName(String name) {
this.name = name;
}
public String getAddress() {
return this.address;
}
public void setAddress(String address) {
this.address = addr.
Refactoring - Mejorando el diseño del código existente
Presentación enumerando y explicando técnicas de Refactoring tomadas del libro "Refactoring" de Martin Fowler
How do I fix this error - Exception in thread -main- java-lang-NullPoi.pdf
How do I fix this error "
Exception in thread "main" java.lang.NullPointerException: Cannot invoke "String.hashCode()"
because "action" is null
at AddressBook.main(AddressBook.java:25)"
import java.util.Scanner;
public class AddressBook {
public static void main(String[] args) {
Tablea addressBook = new Tablea();
Scanner scanner = new Scanner(System.in);
String name, address;
String action = null;
boolean moreEntries = true;
while (moreEntries) {
System.out.println("/nMenu");
System.out.println("n.Add Entry");
System.out.println("d. Delete Entry");
System.out.println("u. Update Entry");
System.out.println("l. Search");
System.out.println("a. View All");
System.out.println("q. Exit");
// Insert a new entry into the address book
switch (action) {
case "n":
System.out.print("Enter a name: ");
name = scanner.nextLine();
System.out.print("Enter an address: ");
address = scanner.nextLine();
addressBook.insert(name, address);
System.out.println("New Contact has been added,");
System.out.print("Add another entry? (y/n): ");
String answer = scanner.nextLine().toLowerCase();
moreEntries = answer.equals("y") || answer.equals("yes");
break;
// Delete an entry from the address book
case "d":
System.out.println("Enter a name to delete: ");
name = scanner.nextLine();
boolean deleted = addressBook.delete(name);
if (deleted) {
System.out.println("Address deleted");
} else {
System.out.println("Name not found");
}
break;
// Update an entry in the address book
case "u":
System.out.print("Enter a name to update: ");
name = scanner.nextLine();
System.out.print("Enter a new address: ");
address = scanner.nextLine();
boolean updated = addressBook.update(name, address);
if (updated) {
System.out.println("Address updated");
} else {
System.out.println("Name not found");
}
break;
// Lookup an entry in the address book
case "l":
System.out.print("Enter a name to look up: ");
name = scanner.nextLine();
String result = addressBook.lookUp(name);
if (result != null) {
System.out.println("Address: " + result);
} else {
System.out.println("Name not found");
}
break;
// Display all entries in the address book
case "a":
System.out.println("All entries:");
addressBook.displayAll();
break;
// Quit the program
case"q":
System.out.println("Quitting...");
}
}
}
}
Other files that go with it
public class Node {
private String name;
private String address;
private Node next;
Node() {
// add here ..
}
Node(String name, String address) {
// add here ..
this.name = name;
this.address = address;
this.next = null;
}
public String getKey() {
// add here ..
return this.name;
}
public void setKey(String name) {
// add here ..
this.name = name;
}
public String getValue() {
// add here ..
return this.address;
}
public void setValue(String address) {
// add here ..
this.address = address;
}
public Node getNext() {
// add here ..
return this.next;
}
public void setNext(Node next) {
// add here ..
this.next = next;
}
}
import java.util.Scanner;
public class Tablea {
private Node mark;
public Node.
What are the products of the secondary metabolism in plants Terpeno.pdf
What are the products of the secondary metabolism in plants? Terpenoids; Phenolic agents;
Flavonoids; Secondary metabolites; Nutraceuticals.
Solution
Plant Secondary metabolites have no known primary functions (such as growth, photosynthesis,
reproduction, or other \"primary\" functions).
Which of the following is incorrect about emergent propertiesA. T.pdf
Which of the following is incorrect about emergent properties?
A. They can be inferred just by studying the individual parts.
B. They emerge as individual components organized into complex systems.
C. They result from the way in which individual components interact.
D. They are in part responsible for the complexity of living systems.
Solution
A. They can be inferred just by studying the individual parts. -----> FALSE
B. They emerge as individual components organised into complex systems. ----> TRUE
C. They result from the way in which individual components interact. ------> TRUE
D. They are in part responsible for the complexity of living systems. ---> TRUE
Emergence is a phenomenon in which the complex entities are formed by the interactions among
the simple entities. The properties exhibited by the complex entities are exhibited by the simpler
entities. So, studying all parts of the system is necessary to infer the emergent properties..
More Related Content
Similar to My code is not matching up with the results.The output for the cod.pdf
public class Person { private String name; private int age;.pdf
public class Person
{
private String name;
private int age;
public Person()
{
name=\"\";
age=0;
}
/**
Create a person with a given name and age.
@param name the name
@param age the age
*/
public Person(String name, int age)
{
this.name = name;
this.age = age;
}
/**
Get the name.
@return the name
*/
public String getName()
{
return name;
}
/**
Change the name.
@param name the name
*/
public void setName(String name)
{
this.name = name;
}
/**
Get the age.
@return the age
*/
public int getAge()
{
return age;
}
/**
Change the age.
@param age the age
*/
public void setAge()
{
this.age = age;
}
/**
Convert person to string form.
*/
public String toString()
{
return \"Name: \" + name + \"\\t\" + \"Age: \" + age;
}
}
OUTPUT should look like this!
Solution
solution
package com.prt.test;
public class Person
{
protected String name;
protected int age;
public Person()
{
name=\"\";
age=0;
}
/**
Create a person with a given name and age.
@param name the name
@param age the age
*/
public Person(String name, int age)
{
this.name = name;
this.age = age;
}
/**
Get the name.
@return the name
*/
public String getName()
{
return name;
}
/**
Change the name.
@param name the name
*/
public void setName(String name)
{
this.name = name;
}
/**
Get the age.
@return the age
*/
public int getAge()
{
return age;
}
/**
Change the age.
@param age the age
*/
public void setAge()
{
this.age = age;
}
/**
Convert person to string form.
*/
public String toString()
{
return \"Name: \" + name + \"\\t\" + \"Age: \" + age;
}
}
package com.prt.test;
public class Student extends Person implements Comparable{
private int studentId;
private String major;
/**
* @return the studentId
*/
public int getStudentId() {
return studentId;
}
/**
* @param studentId the studentId to set
*/
public void setStudentId(int studentId) {
this.studentId = studentId;
}
/**
* @return the major
*/
public String getMajor() {
return major;
}
/**
* @param major the major to set
*/
public void setMajor(String major) {
this.major = major;
}
public Student(String name, int age, int studentId, String major) {
super(name, age);
this.studentId = studentId;
this.major = major;
}
/* (non-Javadoc)
* @see java.lang.Object#toString()
*/
@Override
public String toString() {
return \"name:\" + name+ \"\\t\"+\"\\t\"+\"age:\"+ age+\"\\t\"+ \"studentId :\"+ studentId +
\"\\t\" +\" major:\"+ major;
}
public int compareTo(Student st){
if(studentId==st.studentId)
return 0;
else if(studentId>st.studentId)
return 1;
else
return -1;
}
}
package com.prt.test;
public class Instructor extends Person implements Comparable {
private double salary;
public Instructor(String name, int age, double salary) {
super(name, age);
this.salary = salary;
}
/**
* @return the salary
*/
public double getSalary() {
return salary;
}
/**
* @param salary
* the salary to set
*/
public void setSalary(double salary) {
this.salary = salary;
}
public int compareTo(Instructor is) {
if (salary == is.salary)
return 0;
else if (salary > is.salary)
return 1;
else
ret.
C# Is The Future
C# is here to stay, it is time to embrace one of the most popular languages of the future and learn what is coming. In this talk we will look at how C# has evolved over time, and why it is definitely here to stay!
Scala 2013 review
Slides from my talk at the Junction (Jan 24, 2013)
Single-core performance has hit a ceiling, and building web-scale multi-core applications using imperative programming models is nightmarishly difficult. Parallel programming creates a new set of challenges, best practices and design patterns. Scala is designed to enable building scalable systems, elegantly blending functional and object oriented paradigms into an expressive and concise language, while retaining interoperability with Java. Scala is the fastest growing JVM programming language, being rapidly adopted by leading companies such as Twitter, LinkedIn and FourSquare.
This presentation provides a comprehensive overview of the language, which managed to increase type safety while feeling more dynamic, being more concise and improving readability at the same time. We will see how Scala simplifies real life problems by empowering the developer with powerful functional programming primitives, without giving up on the object oriented paradigm. The overview includes tools for multi-core programming in Scala, the type system, collection framework and domain-specific languages. We’ll explore the power of compile-time meta-programming, which is made possible by the newly released Scala 2.10, and get a glimpse into what to expect from 2.11 in 2014.
We will also see how Scala helps overcome the inherent limitations of Java, such as type erasure, array covariance and boxing overhead.
Multiple examples emphasize how Scala pushes the JVM harder than any other mainstream language through the infinite number of boilerplate busters, increased type safety and productivity boosters from a Java developer’s perspective.
please help with java questionsJAVA CODEplease check my code and.pdf
please help with java questions
JAVA CODE
please check my code and help my questions
CLASS ADDRESS
public class Address{
private int streetNumber;
private String streetName;
private String city;
private String state;
private String country;
// streetNumber
// streetName
// city
// state
// country
public Address(int streetNumber, String streetName, String city, String state, String country) {
this.streetNumber = streetNumber;
this.streetName = streetName;
this.city = city;
this.state = state;
this.country = country;
}
//return the streetNumber
public int getStreetNumber() {
return streetNumber;
}
// set street number
public void setStreetNumber(int streetNumber) {
this.streetNumber = streetNumber;
}
//return the streetName
public String getStreetName() {
return streetName;
}
// set street name
public void setStreetName(String streetName) {
this.streetName = streetName;
}
//return the city
public String getCity() {
return city;
}
//set the city
public void setCity(String city) {
this.city = city;
}
//return the state
public String getState() {
return state;
}
//the state to set
public void setState(String state) {
this.state = state;
}
// return the country
public String getCountry() {
return country;
}
// tset country
public void setCountry(String country) {
this.country = country;
}
// see java.lang.Object#toString()
@Override
public String toString() {
return \" [streetNumber=\" + streetNumber + \", streetName=\" + streetName
+ \", city=\" + city + \", state=\" + state + \", country=\"
+ country + \"]\";
}
}
////////////////////////////////////////////////////////////////////////////////////////
CLASS PERSON
public class Person extends Address {
private String name;
public Person (int streetNumber, String streetName, String city, String state, String country,
String name) {
super(streetNumber, streetName, city, state, country);
this.name = name;
}
//retuurn name
public String getName() {
return name;
}
// set name
public void setName(String name) {
this.name = name;
}
//see java.lang.Object#toString()
@Override
public String toString() {
return \"Person [name=\" + name + \", getStreetNumber()=\"
+ getStreetNumber() + \", getStreetName()=\" + getStreetName()
+ \", getCity()=\" + getCity() + \", getState()=\" + getState()
+ \", getCountry()=\" + getCountry() + \", toString()=\"
+ super.toString() + \", getClass()=\" + getClass()
+ \", hashCode()=\" + hashCode() + \"]\";
}
}
/////////////////////////////////////////////////////////////////
CLASS STUDENT
import java.util.ArrayList;
import java.util.List;
public class Student extends Person {
private String CIN;
List courses;
public Student(int streetNumber, String streetName, String city, String state, String country,
String name, String CIN) {
super(streetNumber, streetName, city, state, country, name);
// Auto-generated constructor stub
this.CIN = CIN;
courses = new ArrayList();
}
// reutrn cin
public String getCIN() {
return CIN;
}
// set cin
public void setCIN(String cIN) {
CIN = cIN;
}
pub.
Add a private variable SSN to the person class- Add a private variable.pdf
Add a private variable SSN to the person class.
Add a private variable major to the student class.
Modify the InheritanceDemo to read the name, student Number, SSN, and the major.
Upload the the three modified files. You have to add the comments and explanations for the
modified files.
public class Person
{
private String name;
public Person( )
{
name = "No name yet";
}
public Person(String initialName)
{
name = initialName;
}
public void setName(String newName)
{
name = newName;
}
public String getName( )
{
return name;
}
public void writeOutput( )
{
System.out.println("Name: " + name);
}
public boolean hasSameName(Person otherPerson)
{
return this.name.equalsIgnoreCase(otherPerson.name);
}
}
public class Student extends Person
{
private int studentNumber;
public Student( )
{
super( );
studentNumber = 0;//Indicating no number yet
}
public Student(String initialName, int initialStudentNumber)
{
super(initialName);
studentNumber = initialStudentNumber;
}
public void reset(String newName, int newStudentNumber)
{
setName(newName);
studentNumber = newStudentNumber;
}
public int getStudentNumber( )
{
return studentNumber;
}
public void setStudentNumber(int newStudentNumber)
{
studentNumber = newStudentNumber;
}
public void writeOutput( )
{
System.out.println("Name: " + getName( ));
System.out.println("Student Number: " + studentNumber);
}
public boolean equals(Student otherStudent)
{
return this.hasSameName(otherStudent) &&
(this.studentNumber == otherStudent.studentNumber);
}
public String toString( )
{
return "Name: " + getName( ) +
"\nStudent number: " + studentNumber;
}
/* //For Optional Section
public boolean equals(Object otherObject)
{
if (otherObject == null)
return false;
else if (!(otherObject instanceof Student))
return false;
else
{
Student otherStudent = (Student)otherObject;
return (this.sameName(otherStudent)
&& (this.studentNumber ==
otherStudent.studentNumber));
}
}
*/
}
public class InheritanceDemo
{
public static void main(String[] args)
{
Student s = new Student( );
s.setName("Warren Peace");
s.setStudentNumber(1234);
s.writeOutput( );
}
}.
Java Class Design
This presentation provides an overview of key topics in Java class design; also covers best practices/tips and quiz questions. Based on our OCP 8 book.
HELP IN JAVACreate a main method and use these input files to tes.pdf
For the questions below, use the W3Schools customer orders database. You need to submit
thoroughly tested SQL statements. For your convenience and reference, relevant data model is
attached as a PDF document with the assignment in the Blackboard. Name of this document is
\"Relationship diagram for W3schools order pdf.\" 1) Write a query to show Customers\' Country
wise sales totals. Your query should show Customers\' Country name and the total sale value for
that Country 2) Write a query to show Product wise sales totals. Your query should Product
name and the total sale value for that Product. 3) Write a query to show the number of orders for
each shipper. Your query should show shipper name and the count of orders with the shipper. 4)
Write a query to show number of products in each product category. Your query should show
Category name and number of products in that category 5) Write a query that shows Customers\'
country wise customer count, and order count. Your query should show country name, total
number of customers from that country, and total number of orders from the customers of that
country 6) Write a query that shows the number of products supplied by each Supplier. Your
query should show Country name, supplier name and the count of products supplied by that
supplier. Note: Sale Price Orderdetails.Quantity Products.price (see an example in the class
slides deck) W3SCHOOLS SQL is located at http://www.w3schools.com/sql/default.asp
(Preferred browser is Chrome). On this page you will find a button called \"Try it yourself\".
Click on that button. You will be redirected to a page where you see a list of tables on the right
side of the page. It is highly recommended to click \'Restore Database\' button on this page
during every session. The page contains a box where you can type in an SQL statement
involving the listed tables. You type in your SQL statement in that box and click on \"Run
SQL\'\' button. The results will be displayed if your SQL statement is syntactically correct.
Solution
1. SELECT Customers.Country, SUM(OrderDetails.Quantity * Products.Price) AS Total_Sale
FROM Customers
LEFT JOIN Orders ON Customers.CustomerID=Orders.CustomerID
LEFT JOIN OrderDetails ON Orders.OrderId=OrderDetails.OrderId
LEFT JOIN Products ON OrderDetails.ProductId=Products.ProductId
Group BY Customers.Country;
2. SELECT Products.ProductName, SUM(OrderDetails.Quantity * Products.Price) AS
Total_Sale FROM Customers
LEFT JOIN Orders ON Customers.CustomerID=Orders.CustomerID
LEFT JOIN OrderDetails ON Orders.OrderId=OrderDetails.OrderId
LEFT JOIN Products ON OrderDetails.ProductId=Products.ProductId
Group BY Products.ProductName;
You can edit these query to get other results set..
Problem 1 Create Node class (or use what you have done in Lab4)• .pdf
Problem 1: Create Node class (or use what you have done in Lab4)
• Add methods to get and set, Data and Link
• Here the data is an object. (java object) your Linked List can hold any java class.
a) Create MyLinkedList2 class and write methods to
• Methods to insert nodes at the beginning, at the end and at a specific position. insertFirst(Node
x), insertLast(Node x) , insertLast(Node x, int pos)
• Methods to delete node from the beginning and from the end. delFirst(), delLast()
• Method to search the Linked List for a specific object. searchList(x Object)
• Method to Sort the Linked List in ascendant or descendant order according to the object
value(s). for example sorted by name, by age, by gpa. sortAsc(),sortDesc().
• Method to display all nodes objects (printing an object is related to its toString() method).
• Method to return the largest and smallest object in the list – maxList(), minList() according to
some specific object members.
. • Method to return the number of nodes – listSize()
• Method to merge two linked Lists into one. MyLinkedList2 list3= mergeList(MyLinkedList2
list1, MyLinkedList2 list2)
b) Create Main class : MyLinkedList2Demo
• Create a linked List LL1 and insert some objects to it. Use any a student java class.
• Fill LL1 by adding students from an input file.
• Display all the objects (students) in the List LL1
• Search for a particular object (Student by name or by Id or both) in LL1 and print true or false
• Sort LL1 and display it ( using asc and desc on multiple members)
• Perform all the delete methods on LL1.
• Perform all the insert methods on LL1.
• Call and run all the implemented methods in a sequential order. NB: Organize a nice output for
all the questions above.
Problem 2: Same as Pb1 using double linked lists. Create Nod3e and MyLinkedList3 classes.
--------------------------------------------------------------------------------------------------------------------
---------------------------------------------------
The input file :
id fname lname age gpa year college cuCourses totalCourses
201412345 Amna chamisi 17 2.1 2014 CIT 5 30
201112345 Amna chamisi 17 2.1 2014 ENG 31 32
201412345 Amna chamisi 17 2.1 2014 COE 5 29
201412345 Amna chamisi 17 2.1 2014 CIT 5 30
201412345 Amna chamisi 17 2.1 2014 CIT 5 30
201412345 Amna chamisi 17 2.1 2014 CIT 5 30
201412345 Amna chamisi 17 2.1 2014 CIT 5 30
Solution
/**
* Node.java
* @author
*
*/
public class Node {
public Object getObj() {
return obj;
}
public Node setObj(Object obj) {
this.obj = obj;
return this;
}
public Node getNext() {
return next;
}
public Node setNext(Node next) {
this.next = next;
return this;
}
private Object obj;
private Node next;
}
import java.util.Collections;
import java.util.Comparator;
import java.util.LinkedList;
/**
* MyLinkedList2.java
* @author
*
*/
public class MyLinkedList2 {
public void insertFirst(Node x) {
if (head == null) {
head = x;
} else {
x.setNext(head);
}
}
public void insertLast(Node x) {
if (head == null) {
head = x;
r.
why will it not display all of the entries-- output -nMenu n-Add Entr.pdf
why will it not display all of the entries??
output
/nMenu
n.Add Entry
d. Delete Entry
u. Update Entry
l. Search
a. View All
q. Exit
/nMenu
n.Add Entry
d. Delete Entry
u. Update Entry
l. Search
a. View All
q. Exit
n
Enter a name: carnea
Enter an address: 30 carrollton
New Contact has been added,
/nMenu
n.Add Entry
d. Delete Entry
u. Update Entry
l. Search
a. View All
q. Exit
n
Enter a name: Tesia
Enter an address: 1010 hancover
New Contact has been added,
/nMenu
n.Add Entry
d. Delete Entry
u. Update Entry
l. Search
a. View All
q. Exit
n.Add Entry
d. Delete Entry
u. Update Entry
l. Search
a. View All
q. Exit
a
All entries:
carnea:30 carrollton
THE CODE:
import java.util.Scanner;
public class AddressBook {
public static void main(String[] args) {
Tablea addressBook = new Tablea();
Scanner scanner = new Scanner(System.in);
String name, address;
String action = null;
boolean moreEntries = true;
while (moreEntries) {
System.out.println("/nMenu");
System.out.println("n.Add Entry");
System.out.println("d. Delete Entry");
System.out.println("u. Update Entry");
System.out.println("l. Search");
System.out.println("a. View All");
System.out.println("q. Exit");
action = scanner.nextLine();
// Insert a new entry into the address book
switch (action) {
case "n":
System.out.print("Enter a name: ");
name = scanner.nextLine();
System.out.print("Enter an address: ");
address = scanner.nextLine();
addressBook.insert(name, address);
System.out.println("New Contact has been added,");
break;
// Delete an entry from the address book
case "d":
System.out.println("Enter a name to delete: ");
name = scanner.nextLine();
boolean deleted = addressBook.delete(name);
if (deleted) {
System.out.println("Address deleted");
} else {
System.out.println("Name not found");
}
break;
// Update an entry in the address book
case "u":
System.out.print("Enter a name to update: ");
name = scanner.nextLine();
System.out.print("Enter a new address: ");
address = scanner.nextLine();
boolean updated = addressBook.update(name, address);
if (updated) {
System.out.println("Address updated");
} else {
System.out.println("Name not found");
}
break;
// Lookup an entry in the address book
case "l":
System.out.print("Enter a name to look up: ");
name = scanner.nextLine();
String result = addressBook.lookUp(name);
if (result != null) {
System.out.println("Address: " + result);
} else {
System.out.println("Name not found");
}
break;
// Display all entries in the address book
case "a":
System.out.println("All entries:");
addressBook.displayAll();
break;
// Quit the program
case"q":
System.out.println("Quitting...");
}
}
}
}
public class Node {
private String name;
private String address;
private Node next;
public Node(String name, String address) {
this.name = name;
this.address = address;
}
public String getName() {
return this.name;
}
public void setName(String name) {
this.name = name;
}
public String getAddress() {
return this.address;
}
public void setAddress(String address) {
this.address = addr.
Refactoring - Mejorando el diseño del código existente
Presentación enumerando y explicando técnicas de Refactoring tomadas del libro "Refactoring" de Martin Fowler
How do I fix this error - Exception in thread -main- java-lang-NullPoi.pdf
How do I fix this error "
Exception in thread "main" java.lang.NullPointerException: Cannot invoke "String.hashCode()"
because "action" is null
at AddressBook.main(AddressBook.java:25)"
import java.util.Scanner;
public class AddressBook {
public static void main(String[] args) {
Tablea addressBook = new Tablea();
Scanner scanner = new Scanner(System.in);
String name, address;
String action = null;
boolean moreEntries = true;
while (moreEntries) {
System.out.println("/nMenu");
System.out.println("n.Add Entry");
System.out.println("d. Delete Entry");
System.out.println("u. Update Entry");
System.out.println("l. Search");
System.out.println("a. View All");
System.out.println("q. Exit");
// Insert a new entry into the address book
switch (action) {
case "n":
System.out.print("Enter a name: ");
name = scanner.nextLine();
System.out.print("Enter an address: ");
address = scanner.nextLine();
addressBook.insert(name, address);
System.out.println("New Contact has been added,");
System.out.print("Add another entry? (y/n): ");
String answer = scanner.nextLine().toLowerCase();
moreEntries = answer.equals("y") || answer.equals("yes");
break;
// Delete an entry from the address book
case "d":
System.out.println("Enter a name to delete: ");
name = scanner.nextLine();
boolean deleted = addressBook.delete(name);
if (deleted) {
System.out.println("Address deleted");
} else {
System.out.println("Name not found");
}
break;
// Update an entry in the address book
case "u":
System.out.print("Enter a name to update: ");
name = scanner.nextLine();
System.out.print("Enter a new address: ");
address = scanner.nextLine();
boolean updated = addressBook.update(name, address);
if (updated) {
System.out.println("Address updated");
} else {
System.out.println("Name not found");
}
break;
// Lookup an entry in the address book
case "l":
System.out.print("Enter a name to look up: ");
name = scanner.nextLine();
String result = addressBook.lookUp(name);
if (result != null) {
System.out.println("Address: " + result);
} else {
System.out.println("Name not found");
}
break;
// Display all entries in the address book
case "a":
System.out.println("All entries:");
addressBook.displayAll();
break;
// Quit the program
case"q":
System.out.println("Quitting...");
}
}
}
}
Other files that go with it
public class Node {
private String name;
private String address;
private Node next;
Node() {
// add here ..
}
Node(String name, String address) {
// add here ..
this.name = name;
this.address = address;
this.next = null;
}
public String getKey() {
// add here ..
return this.name;
}
public void setKey(String name) {
// add here ..
this.name = name;
}
public String getValue() {
// add here ..
return this.address;
}
public void setValue(String address) {
// add here ..
this.address = address;
}
public Node getNext() {
// add here ..
return this.next;
}
public void setNext(Node next) {
// add here ..
this.next = next;
}
}
import java.util.Scanner;
public class Tablea {
private Node mark;
public Node.
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3. A basidium is a sporangium that bursts to release many asexual spores
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1) true. A basidium contains 4 spore cells than 8 and so on which are formed by meosis which
result in the formation of haploid spore..
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Options::
Two correct options are not provided
Electrons are transferred by redox reactions in METS but not in PETS.
PETS has a 1 e- carrier to transfer electrons from PSII to PSI, but METS uses a 2 e- carrier to
transfer electrons from Complex III to Complex IV.
METS is dependent on a source of reducing power obtained from dietary nutrients, whereas
PETS obtains reducing power from light energy and the process of photooxidation.
The inner mitochondrial membrane is impermeable to protons, but the thylakoid membrane is
permeable to protons.
The electron carriers in METS use only Fe and S centers, whereas the electron carriers in PETS
only use Cu centers.
Chemical energy captured by METS and oxidative phosphorylation is limited to ATP, whereas
PETS and photophosphorylation together capture energy in the form of ATP and NADPH.
PETS uses the PQ cycle to translocate protons across the thylakoid membrane, whereas the Q
cycle in METS is used to tether cytochrome c to the inter-membrane space.
Electrons are transferred by redox reactions in METS but not in PETS.
PETS has a 1 e- carrier to transfer electrons from PSII to PSI, but METS uses a 2 e- carrier to
transfer electrons from Complex III to Complex IV.
METS is dependent on a source of reducing power obtained from dietary nutrients, whereas
PETS obtains reducing power from light energy and the process of photooxidation.
The inner mitochondrial membrane is impermeable to protons, but the thylakoid membrane is
permeable to protons.
The electron carriers in METS use only Fe and S centers, whereas the electron carriers in PETS
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Chemical energy captured by METS and oxidative phosphorylation is limited to ATP, whereas
PETS and photophosphorylation together capture energy in the form of ATP and NADPH.
PETS uses the PQ cycle to translocate protons across the thylakoid membrane, whereas the Q
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The disclosure of a contingent liability in the footnotes and on the balance sheet indicates that the
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Answer
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The application architeture is design by the application developer and dictates hoow the
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Solution
a)
The predominant architectural paradigms are:
1)Client-Server architecture
2)P2P architecture
3)Hybrid arcitecture.
Characteristics:
Client-Server architecture:
1)There is an always-on host, called the \"server\", whichservices requests from many other
hosts, called \"clients\".
2)The client-server architecture, clients do not directlycommunicate with each other.
3)Another characteristic of the client-server architecture isthat the server has a fixed, well known
address, called an IPaddress, because the server has a fixed, well-known addressand the server is
always on, then a client canalways contact the server by sending a packet to the server\'saddress
4)Application services that are based on the client-serverarchitecture are oftern infrastructure
intensive, since theyrequire the service providers to purchase, install, and maintainserver farms.
5)The popular services in client-server architectures such assearch engines(e.g.,Google), Internet
commerce (e.g.,Amazon ande-bay) and web based e-mail( e.g, Yahoo mail) etc.
P2P architecture:
1)There is minimal(or no) reliance on always-on infrastructureservers. Instead the application
exploits direct communicationbetween pairs of intermittently connected hoasts, calledpeers.
2)The most compelling features of P2P architectures is theirself-scalability.
3)P2P architectures are also cost effective, since theynormally don\'t require significant server
infrastructure and serverbandwidth.
4)The features of P2P applications are ISP friendly,securityand incentives.
5)Most popular and traffic-intensive applications are based onP2P architectures. It\'s include file
distribution (e.g.BitTorrent), file sharing(e.g. eMule and Lime Wire) and Internettelephony
(e.g.,Skype).etc.
Hybrid architecture:
The combining both client-server and P2P elements. Forexample, for many instant messaging
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Suppose a company’s ROE is 16. This company’s payout ratio is 40. .pdf
Suppose a company’s ROE is 16%. This company’s payout ratio is 40%. The required rate of
return on the stock is 15%. What is the sustainable growth rate of this company?
Solution
Retention ratio=1-payout ratio
=1-0.4
=0.6
Sustainable growth rate=(ROE*Retention ratio)/[1-(ROE*Retention ratio)]
=(0.16*0.6)/[1-(0.16*0.6)]
which is equal to
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Some historians have referred to many of the self-proclaimed “Darwin.pdf
Some historians have referred to many of the self-proclaimed “Darwinians”, such as Ernst
Haeckel, that followed in Darwin’s footsteps at the end of the 19th century as “pseudo-
Darwinians”. In what sense were they Darwinian? In what sense were they not Darwinian?
Most evolutionary scientists would agree that evolution has led to increased complexity of life on
Earth.
Select one:
True
False
Rice has a genome size of about 420-460 million base pairs while humans have a genome size of
about 3 billion base pairs. Of the following, which is a possible reason for this difference?
Select one:
a. Humans are more complex morphologically.
b. Rice is a plant, while humans are animals.
c. Humans have more genes than rice.
d. The human genome has a lot of mobile genetic elements.
e. The vertebrate lineage has a longer evolutionary history.
Solution
Answer A)Darwin\'s theory is based on natural selection and the servival of fittest.
According to the theory the characteristics which are best fitted transfer to the next progeny.
Living animal compete for food ,shelter and basic requirements for their survival, dominant wins
the competition and get selected by nature to reproduce.
Acquired characters of a species throughout its lifetime pass to its progeny through genetic
material.Thus over a period of time due to accumulation of characteristics a new species evolve.
Darwin\'s could not account for either mechanism for trait (character) transmission or the basis
of variability among individual.
Hence new modified theory given by a group of scientist which is called psuedo Darwinian
theory.
This theory is support Darwin s view on transmission acquired characters to next generation. But
all acquired characters do not pass to next generation only useful character transmite to next
generation.
It supports the natural selection theory too.
Points support Darwin theory-
1)Naturally selected animals are able to reproduce and transmit Acquired character to next
generation.
2)Survival of fittest
3) acquired characters transfer through genetic material.
Points of psuedo Darwinian theory not support Darwin theory-
1) All acquired characters do not transmit to next generation only useful character transmite.
2) Genes for the useful character can transfer trait if present in genital pole.
3)Human races are separate species which is rejected by Darwin.
4) Language evolve from speachless pre human.which is not mentioned in Darwin theory.
Answer 2)
E) The vertibrate lineage has a longer evolutionary history.
Vertibrates evolve from their ancestors contain large number of genes and thus large size of
genome because throughout the evolutionary period many characters are acquired in terms of
separate gene. More gene results in more complex structure ..
Please research Meaningful Use. Prepare a brief report on its origin.pdf
Please research Meaningful Use. Prepare a brief report on its origin, its purpose, how it is
conducted, etc. Please make sure you understand and explain the three different stages.
Solution
Meaningful Use(MU)
Purpose: The concept of meaningful use rested on the \'5 pillars\' of health outcomes policy
priorities, namely:
->Improving quality, safety, efficiency, and reducing health disparities
->Engage patients and families in their health
->Improve care coordination
->Improve population and public health
->Ensure adequate privacy and security protection for personal health information
Origin:
The American Reinvestment & Recovery Act (ARRA) was enacted on February 17, 2009.
ARRA includes many measures to modernize our nation\'s infrastructure,
one of which is the \"Health Information Technology for Economic and
Clinical Health (HITECH) Act\". The HITECH Act supports the concept of
electronic health records - meaningful use [EHR-MU], an effort led by
Centers for Medicare & Medicaid Services (CMS ) and the Office of the
National Coordinator for Health IT (ONC). HITECH proposes the meaningful
use of interoperable electronic health records throughout the United States
health care delivery system as a critical national goal. Meaningful Use is
defined by the use of certified EHR technology in a meaningful manner
(for example electronic prescribing); ensuring that the certified EHR
technology is connected in a manner that provides for the electronic
exchange of health information to improve the quality of care; and that
in using certified EHR technology the provider must submit to the Secretary
of Health & Human Services (HHS) information on quality of care and other measures.
How its conducted:
As in order to encourage widespread EHR adoption, promote innovation and to avoid
imposing excessive burden on healthcare providers, meaningful use was showcased
as a phased approach, which is divided into three stages which span 2011
(data capture and sharing), 2013 (advanced clinical processes) and 2015
(improved outcomes). The incentive payments range from $44,000 over 5 years
for the Medicare providers and $63,750 over 6 years for Medicaid providers
(starting in 2011). Participation in the CMS EHR incentive program is totally
voluntary, however if EPs or EHs fail to join in by 2015, there will be negative
adjustments to their Medicare/Medicaid fees starting at 1% reduction and escalating
to 3% reduction by 2017 and beyond.
The CDC currently offers several types of technical assistance to state and
local health departments related to Meaningful Use, including:
->Meaningful Use Public Health Technical Assistance Team - To request assistance
from this team, email meaningfuluse@cdc.gov with “Request for Technical Assistance”
in the Subject line.The CDC National Program of Cancer Registries provides support
and tools for cancer registries. For more info visit its official website
->The CDC Immunization Information Systems Support Branch (IISSB) provides technic.
Mention the major difference in the physical phenomena occurring rel.pdf
Mention the major difference in the physical phenomena occurring related to heat transfer in
external flow as opposed to internal flow.
Solution
Heat transfer is the exchange of thermal energy between physical systems. The rate ofheat
transfer is dependent on the temperatures of the systems and the properties of the intervening
medium through which the heat is transferred. The three fundamental modes of heat transfer are
conduction, convection and radiation.
On a microscopic scale, heat conduction occurs as hot, rapidly moving or vibrating atoms and
molecules interact with neighboring atoms and molecules, transferring some of their energy
(heat) to these neighboring particles. In other words, heat is transferred by conduction when
adjacent atoms vibrate against one another, or as electrons move from one atom to another.
Conduction is the most significant means of heat transfer within a solid or between solid objects
in thermal contact. Fluids—especially gases—are less conductive.Thermal contact conductance
is the study of heat conduction between solid bodies in contact.
Convection
The flow of fluid may be forced by external processes, or sometimes (in gravitational fields) by
buoyancy forces caused when thermal energy expands the fluid (for example in a fire plume),
thus influencing its own transfer. The latter process is often called \"natural convection\". All
convective processes also move heat partly by diffusion, as well. Another form of convection is
forced convection. In this case the fluid is forced to flow by use of a pump, fan or other
mechanical means.
Convective heat transfer, or convection, is the transfer of heat from one place to another by the
movement of fluids, a process that is essentially the transfer of heat via mass transfer. Bulk
motion of fluid enhances heat transfer in many physical situations, such as (for example)
between a solid surface and the fluid. Convection is usually the dominant form of heat transfer in
liquids and gases.
In a body of fluid that is heated from underneath its container, conduction and convection can be
considered to compete for dominance. If heat conduction is too great, fluid moving down by
convection is heated by conduction so fast that its downward movement will be stopped due to
its buoyancy, while fluid moving up by convection is cooled by conduction so fast that its
driving buoyancy will diminish. On the other hand, if heat conduction is very low, a large
temperature gradient may be formed and convection might be very strong..
Logical FallociesP1 All college students have pet monkeys.P2 J.pdf
Logical Fallocies
P1: All college students have pet monkeys.
P2: Janice is a college student.
C: Janice has a pet monkey.
Valid and Sound
Valid but not Sound
Not Valid, but Sound
Not Valid, Not Sound.
The answer Valid and Sound was found the be the wrong answer. Please give correct answer.
and reason why.
Solution
Based on the premise that all college students have pet monkeys , as Janice is a college student,
must have a pet monkey is valid , but it is unlikely , so the correct answer is VALID BUT NOT
SOUND..
IP Security One problem with Internet protocol (IP) is that it has.pdf
IP Security
One problem with Internet protocol (IP) is that it has no method for confirming the authenticity
and security of data as it moves through the net. IP datagrams are typically routed between
devices over disparate networks; as a result, information within these datagrams could be
intercepted and altered. As use of the Internet for critical applications has increased, the need for
enhancements to IP security became necessary. As a result, the Internet Engineering Task Force
(IETF) created a set of protocols called IP Security, or IPsec, to support the secure exchange of
packets over the Internet. IPsec is now a mandatory component of IPv6 and must be supported
for any IPv6 implementation. IPsec is implemented in IPv6 using the authentication header (AH)
and the encapsulating security payload (ESP) extension header.
Answer the following questions in a 3- to 4-page, APA-formatted paper:
1 What is IPsec, and why is it necessary? How is IPsec used in VPN?
2 Which network layer currently suffers from attacks, and why? At which layers of the
network stack architecture should a solution be attempted? Provide details.
3 How is IP security achieved? What is the basic authentication scheme? Which mechanisms
are used? What are some of the application venues of IPsec?
4 How is a VPN implemented on a server so that its clients can connect to it?
Remember to properly cite your sources according to APA guidelines.
Solution
IPSec
IPsec also known as IP Security.Internet Protocol Security is a framework for a set of protocols
that provide security for internet protocol. It can use cryptography to provide security. IPsec
support network level data integrity, data confidentiality. As it is integrated at the internet layer
(i.e. layer 3), it provides security for all the protocols in the TCP/IP. IPsec applied transparently
to the applications, there is no need to configure separate security for each application the uses
TCP/IP.
IPsec provides security for
IPsec provides two choices of security service: Authentication Header (AH), which essentially
allows authentication of the sender of data, and Encapsulating Security Payload (ESP), which
supports both authentication of the sender and encryption of data as well. The specific
information associated with each of these services is inserted into the packet in a header that
follows the IP packet header. Separate key protocols can be selected, such as the
ISAKMP/Oakley protocol.
IPsec is necessary for
Earlier security approaches have inserted security at the Application layer of the communications
model. IPsec is said to be especially useful for implementing virtual private networks and for
remote user access through dial-up connection to private networks. A big advantage of IPsec is
that security arrangements can be handled without requiring changes to individual user
computers. Cisco has been a leader in proposing IPsec as a standard (or combination of standards
and technologies) and has included support fo.
Genmo CorporationOn the night of February 27, 2012, certain recor.pdf
Genmo Corporation*
On the night of February 27, 2012, certain records of the Genmo Corporation were accidentally
destroyed by fire. Two days after that the principal owner had an appointment with an investor to
discuss the possible sale of the company. The owner needed as much information as could be
gathered for this purpose, recognizing that over a longer period of time a more complete
reconstruction would be possible.
On the morning of February 28, the following were available: (1) A balance sheet as of
December 31, 2010, and an income statement for 2010 (Exhibit 1) and (2) certain fragmentary
data and ratios that had been calculated from the current financial statements (Exhibit 2). The
statements themselves had been destroyed in the fire. (In ratios involving balance sheet amounts,
Genmo used yearend amounts rather than an average.) And (3) the following data (in thousands):
2011 revenues.............................................................. $10,281
Current liabilities, December 31, 2011 ......................... 2,285
EXHIBIT 1 Genmo Corporation Financial Statements
(thousands of dollars)
BALANCE SHEET
As of December 31, 2010
Assets
Current assets: Cash................................................................ $ 18
Marketable securities..................................... 494
Accounts receivable...................................... 728
Inventories...................................................... 972
Prepaid expenses........................................... 214
Total current assets..................................... 2,426
Investments……………………………………………. 898
Real estate, plant, and equipment........................... $4,727
Less: Accumulated depreciation..................... 2,433 2,294
Special tools............................................................. 171
Goodwill................................................................... 594
Total assets.............................................................. $6,383
Liabilities and Shareholders’ Equity
Current liabilities: Accounts payable............................................. $ 732
Loans payable.................................................. 266
Accrued liabilities.............................................. 1,232
Total current liabilities............................. 2,230
Long-term debt.......................................................... 250
Other noncurrent liabilities......................................... 951
Total liabilities............................................................ 3,431
Shareholders’ equity: Preferred stock................................................. 25
Common stock................................................. 54
Additional paid-in capital.................................. 667
Retained earnings............................................ 2,206
Total shareholders’ equity....................... 2,952
Total liabilities and shareholders’ equity.................... $6,383
Income Statement, 2010
Total revenu.
In the formula for determining a populations genotype frequencies, .pdf
In the formula for determining a population\'s genotype frequencies, the pq in the term 2pq is
necessary because the population is diploid. heterozygotes can come about in two ways. the
population is doubling in number. heterozygotes have two alleles. What is the founder effect? a
selection of the best-suited traits for the environment a series of chance events that change allele
frequency when a few individuals become isolated from a larger population, and their gene pool
differs from that source population a sudden change in the environment that reduces the size of
the population Which of the following activities occurs first in order to begin speciation? single
gene change formation of mechanical barrier to reproduction postzygotic hybrid sterility in
Drosophila interruption of gene flow between two populations A genetic change that caused a
certain Hox gene to be expressed along the tip of a vertebrate limb bud instead of farther back
helped make possible the evolution of the tetrapod limb. This type of change is illustrative of the
influence of environment on development. paedomorphosis. A change in a developmental gene
or in its regulation that altered the spatial organization of body parts. heterochrony. Which of
the following statements about dinoflagellates is true? They possess two flagella. All known
varieties are autotrophic. Their walls are usually composed of silica plates. Many types lack
mitochondria. Their dead cells accumulate on the seafloor and are mined to serve as a filtering
material.
Solution
Ans. 6: pq in the term 2pq is necessary because heterozygoted have two alleles, hence option D
is correct.
Ans. 7: Founder\'s effect is when few individuals separate from large population and their gene
pool differs from source population. Hence option C is correct.
Ans. 8: interruption of gene flow between two population is first step for speciation hence option
D is correct.
Ans. 9: the given process is best explained by option C.
Ans. 10: option E is more correct amongst the given options..
How is a cell membrane selectively permeable - what permeates and.pdf
How is a cell membrane selectively permeable - what permeates and what does not? How is a
dialysis membrane selectively permeable - what Dermeates and what does not?
Solution
The cell membrane is said to be selectively permeable as it allow some substances to enter
through while limiting the passage of others. Three ways in which the cell membrane controls
the movement of substances is diffusion, facilitated diffusion and active transport.
The cell membrane, or plasma membrane has lipid bilayer with their hydrophobic tails facing
each other and their hydrophilic heads in the exterior and interior of the cell membrane.
With diffusion, substances such as water, oxygen and carbon dioxide flow from a place of high
concentration to a place of low concentration.
In facilitated diffusion, ions and large molecules pass thru a membrane down their concentration
gradients.
Active transport require energy to power the pumps that pass substances from one side of the
membrane to the other in opposition to their concentration gradients. For example, the sodium-
potassium pump pumps 3 sodium ions out and 2 potassium ions into the cell using the ATP.
This dialysis membrane is selectively permeable regenerated cellulose used to illustrate the
principles of osmosis and diffusion.
Pores within the membrane allow the passage of water, most ions, and small molecules.
High molecular weight debris along with starch, polysaccharides, fats and protein are limited..
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My code is not matching up with the results.The output for the cod.pdf
- 1. My code is not matching up with the results. The output for the code should be: >>> Test Teacher class Teacher: Paul Tan(8 sunset way) IM101 added. IM102 added. IM101 cannot be added. IM101 removed. IM101 removed. IM102 removed. IM102 cannot be removed. Person class: public class Person { private String name; private String address; public Person(String name, String address) { this.name = name; this.address = address; } public Person(String address){ this.address = address; } public String getName(){ return name; } public String getAddress(){ return address; } public void setAddress(String address){ this.address = address;
- 2. } public String toString() { return name + "(" + address + ")"; } } Teacher sub class import java.util.ArrayList; public class Teacher extends Person { private int numCourses = 0; private ArrayList courses = new ArrayList(); public Teacher(String name, String address){ super(name,address); } @Override public String toString() { return "Teacher: " + super.toString(); } public boolean addCourse (String course){ for (int i = 0; i < numCourses; i++) { if (courses.get(i).equals(course)) return false; } courses.add(course); numCourses++; return true; } public boolean removeCourse (String course){ boolean found = false; int courseIndex = -1; for (int j = 0; j < numCourses; j++) { if (courses.get(j).equals(course)) { courseIndex = j; found = true; break;
- 3. } } if (found) { for (int k = courseIndex; k < numCourses-1; k++) { courses.get(k+1); } numCourses--; return true; } else { return false; } } } Person Launcer System.out.println(" "); System.out.println(">>> Test Teacher class"); Teacher tch = new Teacher ("Paul Tan", "8 sunset way"); System.out.println(tch); String[] courses = {"IM101", "IM102", "IM101"}; for (String course: courses) { if (tch.addCourse(course)) { System.out.println(course + " added."); } else { System.out.println(course + " cannot be added."); } } for (String course: courses) { if (tch.removeCourse(course)) { System.out.println(course + " removed."); } else { System.out.println(course + " cannot be removed."); } } System.out.println(" ");
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