The document contains solutions to 26 multiple choice questions. The solutions provide step-by-step working to arrive at the answer choices A through E for each question. Some key steps involve simplifying fractions and expressions, evaluating probabilities, solving equations, and using logical reasoning to analyze word problems about topics like math, statistics, and probability.
The document discusses different types of interest:
1. Simple interest is calculated uniformly on the principal amount for a certain period at a given interest rate. The formula to calculate simple interest is I = PRN/100, where I is interest, P is principal, R is annual interest rate, and N is time in years.
2. Compound interest is when interest is added to the principal amount and earns interest itself. The document provides formulas to calculate compound interest compounded annually and semi-annually.
3. Principal is the amount borrowed or deposited. Interest is the money paid by the borrower to the lender for use of the money lent. The sum of principal and interest is called the
Soal matematika prediksi us sd 2016 masudMuhamad Masud
Teks tersebut berisi soal-soal ujian matematika SD kelas 6 yang mencakup berbagai materi seperti bilangan, aljabar, geometri, dan statistik. Soal-soal tersebut dijawab dengan memilih salah satu pilihan jawaban yang tersedia.
This document is the introduction to a physics exam consisting of multiple choice questions. It provides instructions for students on how to fill out the answer sheet and contains various physical constants and formulas that may be useful for answering the questions. The exam covers topics in physics including mechanics, electricity, waves, and radioactivity. Students are advised to show any working in the exam booklet and must answer all 40 questions in the 1 hour time period.
The document discusses different types of interest:
1. Simple interest is calculated uniformly on the principal amount for a certain period at a given interest rate. The formula to calculate simple interest is I = PRN/100, where I is interest, P is principal, R is annual interest rate, and N is time in years.
2. Compound interest is when interest is added to the principal amount and earns interest itself. The document provides formulas to calculate compound interest compounded annually and semi-annually.
3. Principal is the amount borrowed or deposited. Interest is the money paid by the borrower to the lender for use of the money lent. The sum of principal and interest is called the
Soal matematika prediksi us sd 2016 masudMuhamad Masud
Teks tersebut berisi soal-soal ujian matematika SD kelas 6 yang mencakup berbagai materi seperti bilangan, aljabar, geometri, dan statistik. Soal-soal tersebut dijawab dengan memilih salah satu pilihan jawaban yang tersedia.
This document is the introduction to a physics exam consisting of multiple choice questions. It provides instructions for students on how to fill out the answer sheet and contains various physical constants and formulas that may be useful for answering the questions. The exam covers topics in physics including mechanics, electricity, waves, and radioactivity. Students are advised to show any working in the exam booklet and must answer all 40 questions in the 1 hour time period.
This document provides an introduction to event-driven programming and forms using Delphi. It discusses using the canvas object and its methods to perform drawing. Key points covered include:
- How to use the canvas, pen, brush properties to control drawing
- Common canvas drawing methods like lineTo, rectangle, ellipse
- How to draw based on mouse cursor position
- Examples of using canvas to draw lines and shapes on a form or image
The document provides code examples of using the canvas methods to draw lines, rectangles, ellipses and text. It also discusses using the mouse cursor position to perform dynamic drawing. The goal is to teach the reader how to draw on a canvas in response to events like mouse clicks
Dokumen tersebut berisi soal ujian tengah semester mata pelajaran IPA untuk kelas III SDN 4 Seteluk yang meliputi materi tentang kelompok makhluk hidup, pertumbuhan, dan karakteristik beberapa hewan dan tumbuhan. Soal berisi pilihan ganda dan isian yang harus dijawab siswa dalam waktu 120 menit.
This document provides the mark scheme for the May/June 2014 Cambridge International Examinations IGCSE Physics exam. It explains the marking criteria and symbols used by examiners. The mark scheme provides detailed guidelines for awarding marks to answers on topics related to forces, pressure, kinetic molecular theory, and heat transfer. Examiners will use this mark scheme along with the question paper and examiner report to consistently apply standards when marking the exam.
This document consists of the exam paper for a mathematics exam taken in October/November 2010. It contains 11 multi-part questions testing a variety of math skills, including algebra, geometry, trigonometry, statistics, and functions. The exam is 2 hours and 30 minutes long and contains 130 total marks. Students are instructed to show their work and communicate their answers clearly.
The document discusses the use of variant question papers for assessments with large candidature. It states that CIE uses different but closely related variants of some question papers to maintain best assessment practices. Both variants assess the same content and skills. This means there are now two variant question papers, mark schemes, and principal examiner reports available where previously there was only one. The document contains both variants to give centers access to more past examination material. It provides a diagram showing the relationship between the question papers, mark schemes, and reports for the two variants. It also provides contact information for any questions about these changes.
Latihan soal ujian nasional matematika sdmardiyanto83
Dokumen tersebut berisi soal-soal ujian matematika SD/MI yang terdiri dari 50 soal pilihan ganda. Soal-soal tersebut meliputi materi seperti operasi hitung, geometri, pecahan, dan statistik.
Tes matematika kelas 7 terdiri dari soal pilihan ganda dan esai. Soal pilihan ganda meliputi materi seperti operasi hitung bilangan bulat dan pecahan, rumus luas dan volume bangun datar dan ruang, serta penyelesaian masalah. Soal esai membahas konsep seperti operasi hitung, sifat bilangan, dan penyelesaian masalah berdasarkan informasi yang diberikan. Tes ini mengukur pemahaman siswa terhadap berbagai konsep matematika kelas
6. latihan soal matematika barisan dan deret bilangan kelas 9 smplambok pakpahan
Dokumen tersebut berisi soal-soal tentang barisan dan deret bilangan untuk kelas 9 semester 2. Terdapat 20 soal pilihan ganda dan 5 soal esai yang membahas konsep-konsep seperti barisan aritmatika, deret geometri, rasio deret, dan jumlah suku deret.
Revised GRE quantitative questions by Rejan Chitrakar. This ebook is sufficient to be able to tackle all types of revised gre questions. All the best for your GRE!!!
The document discusses partial differential equations and their solutions. It can be summarized as:
1) A partial differential equation involves a function of two or more variables and some of its partial derivatives, with one dependent variable and one or more independent variables. Standard notation is presented for partial derivatives.
2) Partial differential equations can be formed by eliminating arbitrary constants or arbitrary functions from an equation relating the dependent and independent variables. Examples of each method are provided.
3) Solutions to partial differential equations can be complete, containing the maximum number of arbitrary constants allowed, particular where the constants are given specific values, or singular where no constants are present. Methods for determining the general solution are described.
This document provides an introduction to event-driven programming and forms using Delphi. It discusses using the canvas object and its methods to perform drawing. Key points covered include:
- How to use the canvas, pen, brush properties to control drawing
- Common canvas drawing methods like lineTo, rectangle, ellipse
- How to draw based on mouse cursor position
- Examples of using canvas to draw lines and shapes on a form or image
The document provides code examples of using the canvas methods to draw lines, rectangles, ellipses and text. It also discusses using the mouse cursor position to perform dynamic drawing. The goal is to teach the reader how to draw on a canvas in response to events like mouse clicks
Dokumen tersebut berisi soal ujian tengah semester mata pelajaran IPA untuk kelas III SDN 4 Seteluk yang meliputi materi tentang kelompok makhluk hidup, pertumbuhan, dan karakteristik beberapa hewan dan tumbuhan. Soal berisi pilihan ganda dan isian yang harus dijawab siswa dalam waktu 120 menit.
This document provides the mark scheme for the May/June 2014 Cambridge International Examinations IGCSE Physics exam. It explains the marking criteria and symbols used by examiners. The mark scheme provides detailed guidelines for awarding marks to answers on topics related to forces, pressure, kinetic molecular theory, and heat transfer. Examiners will use this mark scheme along with the question paper and examiner report to consistently apply standards when marking the exam.
This document consists of the exam paper for a mathematics exam taken in October/November 2010. It contains 11 multi-part questions testing a variety of math skills, including algebra, geometry, trigonometry, statistics, and functions. The exam is 2 hours and 30 minutes long and contains 130 total marks. Students are instructed to show their work and communicate their answers clearly.
The document discusses the use of variant question papers for assessments with large candidature. It states that CIE uses different but closely related variants of some question papers to maintain best assessment practices. Both variants assess the same content and skills. This means there are now two variant question papers, mark schemes, and principal examiner reports available where previously there was only one. The document contains both variants to give centers access to more past examination material. It provides a diagram showing the relationship between the question papers, mark schemes, and reports for the two variants. It also provides contact information for any questions about these changes.
Latihan soal ujian nasional matematika sdmardiyanto83
Dokumen tersebut berisi soal-soal ujian matematika SD/MI yang terdiri dari 50 soal pilihan ganda. Soal-soal tersebut meliputi materi seperti operasi hitung, geometri, pecahan, dan statistik.
Tes matematika kelas 7 terdiri dari soal pilihan ganda dan esai. Soal pilihan ganda meliputi materi seperti operasi hitung bilangan bulat dan pecahan, rumus luas dan volume bangun datar dan ruang, serta penyelesaian masalah. Soal esai membahas konsep seperti operasi hitung, sifat bilangan, dan penyelesaian masalah berdasarkan informasi yang diberikan. Tes ini mengukur pemahaman siswa terhadap berbagai konsep matematika kelas
6. latihan soal matematika barisan dan deret bilangan kelas 9 smplambok pakpahan
Dokumen tersebut berisi soal-soal tentang barisan dan deret bilangan untuk kelas 9 semester 2. Terdapat 20 soal pilihan ganda dan 5 soal esai yang membahas konsep-konsep seperti barisan aritmatika, deret geometri, rasio deret, dan jumlah suku deret.
Revised GRE quantitative questions by Rejan Chitrakar. This ebook is sufficient to be able to tackle all types of revised gre questions. All the best for your GRE!!!
The document discusses partial differential equations and their solutions. It can be summarized as:
1) A partial differential equation involves a function of two or more variables and some of its partial derivatives, with one dependent variable and one or more independent variables. Standard notation is presented for partial derivatives.
2) Partial differential equations can be formed by eliminating arbitrary constants or arbitrary functions from an equation relating the dependent and independent variables. Examples of each method are provided.
3) Solutions to partial differential equations can be complete, containing the maximum number of arbitrary constants allowed, particular where the constants are given specific values, or singular where no constants are present. Methods for determining the general solution are described.
The document contains 31 multi-step math word problems with solutions. The problems cover a range of topics including percentages, ratios, averages, probability, geometry, and more. The level of difficulty ranges from relatively simple to more complex.
This document contains 19 multiple choice questions with solutions. The questions cover a range of math and logic topics such as geometry, percentages, remainders, and inequalities. For each question, the correct multiple choice answers are indicated based on working through the logic presented in the short solutions. This provides a review of different types of multiple choice questions and reasoning through solutions in brief explanations.
This document provides an introduction to surds and indices. It discusses different types of numbers including rational and irrational numbers. It explains that surds like the square root of integers are either integers or irrational. The key properties of surds including simplifying expressions with surds are described. Index notation is also introduced as a shorthand for exponents. The basic rules for multiplying and dividing terms with indices are outlined.
The document provides a strategy guide for the GRE exam. It outlines the structure and format of the GRE, including the analytical writing, verbal reasoning, and quantitative reasoning sections. It also describes the different types of questions that may appear on the quantitative reasoning section, such as problems with a single correct answer, problems with multiple correct answers, quantitative comparison questions, and numerical entry questions. Examples of questions are provided for each type to illustrate the formats. The guide concludes by thanking the reader and providing contact information for additional GRE preparation resources.
The three key elements of a data sufficiency problem are:
1) The question setup which contains at least one unknown property
2) Statement (1) which provides known properties of the implied system
3) Statement (2) which also provides known properties of the implied system
To determine if the statements are sufficient to answer the question, we analyze if they allow us to determine the unknown properties within the implied system.
The document discusses several key factors that affect learning and memory. It describes the stages of memory as sensory memory, short-term memory, and long-term memory. It also discusses techniques for improving memory such as elaborative rehearsal, categorization, visualization, the use of mnemonic devices, and avoiding interference.
The document provides tips for GRE exam strategy. It recommends focusing on building concepts during classes rather than worrying too much about time. Students should book their exam dates 40-60 days after classes. The GRE may include an unscored section in any position, so students should treat each section separately. There is no negative marking, so students should attempt all questions by providing a feasible answer even if they have to guess. The document outlines a testing plan using various books and online platforms to focus on concepts, accuracy, and time management in preparation for achieving a target GRE score of 340.
The document contains 33 quantitative comparison questions from the revised GRE. Each question provides information about quantities, relations, or geometric figures and asks which quantity is greater. The solutions show that for many questions, the relationship between the quantities cannot be determined from the given information, since different assumptions lead to different answers. The overall high-level summary is:
- The document contains 33 quantitative comparison questions from the GRE with information about quantities, relations, or figures
- Many questions cannot be definitively answered, as different assumptions produce different results
- The solutions demonstrate that the relationship between quantities is indeterminate in these cases
This document provides a list of 100 GRE vocabulary words along with their definitions. The words cover a wide range of topics and parts of speech. Some words have multiple meanings depending on context. Mastering this vocabulary would help enhance one's verbal skills and performance on the GRE.
Probability and Statistics,
Gamma Function,
Formulas,
Numerical,
Practical Application,
BITS Pilani Curriculum,
First Year Notes
For more study material, visit:
www.akshansh.weebly.com
This document provides tips and recommendations for boosting one's GRE and TOEFL scores in order to gain admission to PhD programs. It recommends aiming for a 315 combined GRE score with 155 or higher on the verbal section and 160 or higher on the quantitative section. A minimum TOEFL score of 100 is suggested. The document also provides suggestions for academic background, projects, letters, timing, and website and book resources to utilize in test preparation.
This short document promotes creating presentations using Haiku Deck, a tool for making slideshows. It encourages the reader to get started making their own Haiku Deck presentation and sharing it on SlideShare. In a single sentence, it pitches the idea of using Haiku Deck to easily design presentations.
The document discusses the benefits of exercise for mental health. Regular physical activity can help reduce anxiety and depression and improve mood and cognitive functioning. Exercise causes chemical changes in the brain that may help protect against mental illness and improve symptoms.
This document contains 23 math and logic problems with multiple choice answers. It provides the problems, possible answers, and brief explanations for the answers. The problems cover a range of topics including algebra, percentages, probability, geometry and logical reasoning. The explanations are 1-2 sentences and directly reference the numbers, variables or diagrams in the problems to justify the answers. The document is designed to help students practice and learn how to solve different types of math and logic problems.
This document contains 26 math and logic problems with multiple choice answers. It provides the problems, possible answers, and explanations for the answers. The problems cover a range of topics including algebra, arithmetic, geometry, probability, factoring, and word problems. The explanations for the answers clearly show the step-by-step work and logic used to arrive at the correct solution for each problem.
The document contains questions related to CAT, MAT, GMAT entrance exams. It discusses various topics like probability, permutations and combinations, averages, ratios etc. and provides solutions to sample questions in 3-4 sentences each. The overall document aims to help exam preparation by providing practice questions on common quantitative topics.
The document contains 35 math and word problems. The assistant provides concise 3-sentence summaries for each problem:
1) A man discusses promoting entrepreneurship and free education for all. He needs support from others to achieve these goals.
2) The problem asks to rearrange the letters in "PROBLEM" to make 7-letter words without repetition, with the answer being 5040 possible arrangements.
3) The problem asks the probability that the third coin tossed will be heads if 10 coins are tossed simultaneously, with the answer being 1/2 or 512 possible outcomes out of 1024 total.
4) The problem asks to count the ways to post 5 letters into 3 post boxes with any number allowed
1. The document contains 10 math problems with solutions. The problems cover topics like arithmetic progressions, rates of change, probability, and geometry.
2. One problem involves finding the value of n given that the sum of even numbers between 1 and n is a specific value. The solution uses the formula for the sum of an arithmetic progression.
3. Another problem asks what fraction of a solution must be replaced if the original solution was 40% and replaced with 25% solution to get a final concentration of 35%. The solution sets up an equation to solve for the fraction replaced.
The document contains solutions to 18 math and probability problems. Some key details:
- Problem 1 involves finding an odd number n such that the sum of even numbers between 1 and n equals 79*80.
- Problem 2 calculates the price at which a bushel of corn costs the same as a peck of wheat, given changing prices.
- Problem 3 determines the minimum number of people needed to have over a 50% chance that one was born in a leap year.
The document provides information on numerical reasoning problems involving ratios, proportions, and arithmetic and geometric progressions. It includes 13 multi-step word problems with solutions. The problems cover topics such as ratios, proportions, mixtures, percentages, time and work, and profit and loss. The document aims to help students practice solving complex multi-concept numerical reasoning problems.
The document provides information on numerical reasoning concepts including arithmetic progression, geometric progression, formulas, ratio and proportion problems, alligation, and mixture problems. It includes 15 multi-step word problems covering these topics and their step-by-step solutions. The problems demonstrate how to set up and solve ratios, proportions, alligation and mixture scenarios to find unknown values.
The document provides information about the Management Aptitude Test (MAT) Afterschool Centre for Social Entrepreneurship and its PGPSE (Post Graduate Programme in Social Entrepreneurship) program. The 3-year integrated PGPSE program can be done along with civil service exams and provides an option to do a part-time job while studying. The 18-month PGPSE is available in both regular and distance learning modes and focuses on developing social entrepreneurs. Workshops on social entrepreneurship are also conducted across India.
This document appears to be a quiz on linear equations in one variable. It contains 20 multiple choice questions testing concepts like: transposing terms, identifying the highest power of a variable, determining the solution of an equation, identifying linear vs non-linear equations, and solving word problems that can be represented by linear equations. It also contains 17 statements to identify as true or false.
This document provides examples of math word problems and their step-by-step solutions. It begins with problems involving operations with fractions, decimals, and percentages. Later problems involve calculating percentages of quantities, percentage increases and decreases, and other rate and percentage applications. The document demonstrates how to set up and solve a variety of math problems systematically using proper order of operations and step-by-step work.
This document provides lessons and examples on ratio and proportion concepts to help students with analytical skills. It includes solved examples of ratio and proportion word problems. The document was created by Dr. T.K. Jain for free online entrepreneurship programs. It encourages students to help spread knowledge and social entrepreneurship. Links are provided to download additional free study materials on various topics.
This material is for PGPSE / CSE students of AFTERSCHOOOL. PGPSE / CSE are free online programme - open for all - free for all - to promote entrepreneurship and social entrepreneurship PGPSE is for those who want to transform the world. It is different from MBA, BBA, CFA, CA,CS,ICWA and other traditional programmes. It is based on self certification and based on self learning and guidance by mentors. It is for those who want to be entrepreneurs and social changers. Let us work together. Our basic idea is that KNOWLEDGE IS FREE & AND SHARE IT WITH THE WORLD
This document provides practice questions and tips in business mathematics. It contains multiple choice questions related to topics like ratios, percentages, profit and loss, time and work, averages, simple and compound interest, discounts, and permutations and combinations. The questions are intended to help students prepare for competitive exams in subjects like commerce and management.
This document provides practice questions and tips in business mathematics. It contains multiple choice questions related to topics like ratios, percentages, profit and loss, time and work, averages, simple and compound interest, discounts, and permutations and combinations. The questions are intended to help students prepare for competitive exams in subjects like commerce and management.
The document provides solutions to 15 problems from a CAT exam. Here are summaries of 3 of the problems:
1) The problem involves finding the remainder when a sum of terms of the form (163 + 173 + ...) is divided by 70. The solution shows the sum can be written as 70k, so the remainder is 0.
2) The problem involves 4 tanks losing chemical at different rates per minute. It is found that tank D loses chemical the fastest, at 50 units per minute, and will empty first after 20 minutes, when its initial 1000 units are completely lost.
3) The problem involves two circles intersecting at two points to form a square. It is noted that the area common to
This document provides examples of business mathematics problems with multiple choice options for solving. Some examples include:
1) A two digit number where the sum of the digits is 10 and subtracting 18 reverses the digits.
2) The ratio of volumes of two cylinders and the ratio of their heights is used to find the ratio of their diameters.
3) A group of 7,300 troops is divided into 4 groups so that halves and thirds of the groups are equal, calculating the size of each group.
The document provides examples of business mathematics problems with multiple choice options to solve. Some key problems discussed include:
- A two digit number where the sum of digits is 10 and subtracting 18 reverses the digits, with the answer being 73.
- A number where half exceeds 1/5th by 15, with the answer being 50.
- Ages of a person and their two sons based on information 5 years ago and now, with the answer being that the person's current age is 50.
B A S I C S T A T I S T I C S F O R N O N C O M M E R C E S T U D E N T SDr. Trilok Kumar Jain
This document provides examples of business mathematics problems with multiple choice options for solving. Some examples include:
1) A two digit number where the sum of the digits is 10 and subtracting 18 reverses the digits.
2) The ratio of volumes of two cylinders and the ratio of their heights is used to find the ratio of their diameters.
3) A group of 7,300 troops is divided into 4 groups so that halves and thirds of the groups are equal, calculating the size of each group.
The document provides information about a management aptitude test and social entrepreneurship program. It discusses developing change makers and offers a free, comprehensive program in social and spiritual entrepreneurship open to all. It then provides examples of math and reasoning questions along with solutions.
Ivanti’s Patch Tuesday breakdown goes beyond patching your applications and brings you the intelligence and guidance needed to prioritize where to focus your attention first. Catch early analysis on our Ivanti blog, then join industry expert Chris Goettl for the Patch Tuesday Webinar Event. There we’ll do a deep dive into each of the bulletins and give guidance on the risks associated with the newly-identified vulnerabilities.
Digital Banking in the Cloud: How Citizens Bank Unlocked Their MainframePrecisely
Inconsistent user experience and siloed data, high costs, and changing customer expectations – Citizens Bank was experiencing these challenges while it was attempting to deliver a superior digital banking experience for its clients. Its core banking applications run on the mainframe and Citizens was using legacy utilities to get the critical mainframe data to feed customer-facing channels, like call centers, web, and mobile. Ultimately, this led to higher operating costs (MIPS), delayed response times, and longer time to market.
Ever-changing customer expectations demand more modern digital experiences, and the bank needed to find a solution that could provide real-time data to its customer channels with low latency and operating costs. Join this session to learn how Citizens is leveraging Precisely to replicate mainframe data to its customer channels and deliver on their “modern digital bank” experiences.
Generating privacy-protected synthetic data using Secludy and MilvusZilliz
During this demo, the founders of Secludy will demonstrate how their system utilizes Milvus to store and manipulate embeddings for generating privacy-protected synthetic data. Their approach not only maintains the confidentiality of the original data but also enhances the utility and scalability of LLMs under privacy constraints. Attendees, including machine learning engineers, data scientists, and data managers, will witness first-hand how Secludy's integration with Milvus empowers organizations to harness the power of LLMs securely and efficiently.
How information systems are built or acquired puts information, which is what they should be about, in a secondary place. Our language adapted accordingly, and we no longer talk about information systems but applications. Applications evolved in a way to break data into diverse fragments, tightly coupled with applications and expensive to integrate. The result is technical debt, which is re-paid by taking even bigger "loans", resulting in an ever-increasing technical debt. Software engineering and procurement practices work in sync with market forces to maintain this trend. This talk demonstrates how natural this situation is. The question is: can something be done to reverse the trend?
Your One-Stop Shop for Python Success: Top 10 US Python Development Providersakankshawande
Simplify your search for a reliable Python development partner! This list presents the top 10 trusted US providers offering comprehensive Python development services, ensuring your project's success from conception to completion.
How to Interpret Trends in the Kalyan Rajdhani Mix Chart.pdfChart Kalyan
A Mix Chart displays historical data of numbers in a graphical or tabular form. The Kalyan Rajdhani Mix Chart specifically shows the results of a sequence of numbers over different periods.
Northern Engraving | Nameplate Manufacturing Process - 2024Northern Engraving
Manufacturing custom quality metal nameplates and badges involves several standard operations. Processes include sheet prep, lithography, screening, coating, punch press and inspection. All decoration is completed in the flat sheet with adhesive and tooling operations following. The possibilities for creating unique durable nameplates are endless. How will you create your brand identity? We can help!
The Microsoft 365 Migration Tutorial For Beginner.pptxoperationspcvita
This presentation will help you understand the power of Microsoft 365. However, we have mentioned every productivity app included in Office 365. Additionally, we have suggested the migration situation related to Office 365 and how we can help you.
You can also read: https://www.systoolsgroup.com/updates/office-365-tenant-to-tenant-migration-step-by-step-complete-guide/
[OReilly Superstream] Occupy the Space: A grassroots guide to engineering (an...Jason Yip
The typical problem in product engineering is not bad strategy, so much as “no strategy”. This leads to confusion, lack of motivation, and incoherent action. The next time you look for a strategy and find an empty space, instead of waiting for it to be filled, I will show you how to fill it in yourself. If you’re wrong, it forces a correction. If you’re right, it helps create focus. I’ll share how I’ve approached this in the past, both what works and lessons for what didn’t work so well.
Connector Corner: Seamlessly power UiPath Apps, GenAI with prebuilt connectorsDianaGray10
Join us to learn how UiPath Apps can directly and easily interact with prebuilt connectors via Integration Service--including Salesforce, ServiceNow, Open GenAI, and more.
The best part is you can achieve this without building a custom workflow! Say goodbye to the hassle of using separate automations to call APIs. By seamlessly integrating within App Studio, you can now easily streamline your workflow, while gaining direct access to our Connector Catalog of popular applications.
We’ll discuss and demo the benefits of UiPath Apps and connectors including:
Creating a compelling user experience for any software, without the limitations of APIs.
Accelerating the app creation process, saving time and effort
Enjoying high-performance CRUD (create, read, update, delete) operations, for
seamless data management.
Speakers:
Russell Alfeche, Technology Leader, RPA at qBotic and UiPath MVP
Charlie Greenberg, host
In the realm of cybersecurity, offensive security practices act as a critical shield. By simulating real-world attacks in a controlled environment, these techniques expose vulnerabilities before malicious actors can exploit them. This proactive approach allows manufacturers to identify and fix weaknesses, significantly enhancing system security.
This presentation delves into the development of a system designed to mimic Galileo's Open Service signal using software-defined radio (SDR) technology. We'll begin with a foundational overview of both Global Navigation Satellite Systems (GNSS) and the intricacies of digital signal processing.
The presentation culminates in a live demonstration. We'll showcase the manipulation of Galileo's Open Service pilot signal, simulating an attack on various software and hardware systems. This practical demonstration serves to highlight the potential consequences of unaddressed vulnerabilities, emphasizing the importance of offensive security practices in safeguarding critical infrastructure.
Monitoring and Managing Anomaly Detection on OpenShift.pdfTosin Akinosho
Monitoring and Managing Anomaly Detection on OpenShift
Overview
Dive into the world of anomaly detection on edge devices with our comprehensive hands-on tutorial. This SlideShare presentation will guide you through the entire process, from data collection and model training to edge deployment and real-time monitoring. Perfect for those looking to implement robust anomaly detection systems on resource-constrained IoT/edge devices.
Key Topics Covered
1. Introduction to Anomaly Detection
- Understand the fundamentals of anomaly detection and its importance in identifying unusual behavior or failures in systems.
2. Understanding Edge (IoT)
- Learn about edge computing and IoT, and how they enable real-time data processing and decision-making at the source.
3. What is ArgoCD?
- Discover ArgoCD, a declarative, GitOps continuous delivery tool for Kubernetes, and its role in deploying applications on edge devices.
4. Deployment Using ArgoCD for Edge Devices
- Step-by-step guide on deploying anomaly detection models on edge devices using ArgoCD.
5. Introduction to Apache Kafka and S3
- Explore Apache Kafka for real-time data streaming and Amazon S3 for scalable storage solutions.
6. Viewing Kafka Messages in the Data Lake
- Learn how to view and analyze Kafka messages stored in a data lake for better insights.
7. What is Prometheus?
- Get to know Prometheus, an open-source monitoring and alerting toolkit, and its application in monitoring edge devices.
8. Monitoring Application Metrics with Prometheus
- Detailed instructions on setting up Prometheus to monitor the performance and health of your anomaly detection system.
9. What is Camel K?
- Introduction to Camel K, a lightweight integration framework built on Apache Camel, designed for Kubernetes.
10. Configuring Camel K Integrations for Data Pipelines
- Learn how to configure Camel K for seamless data pipeline integrations in your anomaly detection workflow.
11. What is a Jupyter Notebook?
- Overview of Jupyter Notebooks, an open-source web application for creating and sharing documents with live code, equations, visualizations, and narrative text.
12. Jupyter Notebooks with Code Examples
- Hands-on examples and code snippets in Jupyter Notebooks to help you implement and test anomaly detection models.
Dandelion Hashtable: beyond billion requests per second on a commodity serverAntonios Katsarakis
This slide deck presents DLHT, a concurrent in-memory hashtable. Despite efforts to optimize hashtables, that go as far as sacrificing core functionality, state-of-the-art designs still incur multiple memory accesses per request and block request processing in three cases. First, most hashtables block while waiting for data to be retrieved from memory. Second, open-addressing designs, which represent the current state-of-the-art, either cannot free index slots on deletes or must block all requests to do so. Third, index resizes block every request until all objects are copied to the new index. Defying folklore wisdom, DLHT forgoes open-addressing and adopts a fully-featured and memory-aware closed-addressing design based on bounded cache-line-chaining. This design offers lock-free index operations and deletes that free slots instantly, (2) completes most requests with a single memory access, (3) utilizes software prefetching to hide memory latencies, and (4) employs a novel non-blocking and parallel resizing. In a commodity server and a memory-resident workload, DLHT surpasses 1.6B requests per second and provides 3.5x (12x) the throughput of the state-of-the-art closed-addressing (open-addressing) resizable hashtable on Gets (Deletes).
Dandelion Hashtable: beyond billion requests per second on a commodity server
Multiple choice qestions
1. MULTIPLE CHOICE QESTIONS - Select one answer choice
1. If 15!/3m
is an integer, what is the greatest possible value of m?
A. 4
B. 5
C. 6
D. 7
E. 8
Solution;
15!/3m
=15*14*13*…..*1/3m
=36
*5*4*2*……../3m
Since,
15=3*5, 12=3*4, 9=3*3, 6=3*2, 3=3*1
We can see, for 15!/3m
to be an integer, the maximum possible value of m could be 6.
Hence answer is C.
2. Which of the following numbers is farthest from the number 1 on the number line?
A. -10
B. -5
C. 0
D. 5
E. 10
Solution;
Clearly, the answer is either A or E.
distance between numbers 1 and -10=1-(-10)=1+10=11
distance between numbers 1 and 10=10-1=9
2. Hence answer is A.
3. A certain jar contains 60 jelly beans - 22 white, 18 green, 11 yellow, 5 red and 4 purple. If a
jelly bean is to be chosen at random, what is the probability that the jelly bean will neither be
red nor purple?
A. 0.09
B. 0.15
C. 0.54
D. 0.85
E. 0.91
Solution;
P(neither red nor purple)=P(White or Green or Yellow)
=22/60+18/60+11/60=51/60=0.85
Hence answer is D.
4. A certain store sells two types of pens: one type for $2 per pen and the other type for $3 per
pen. If a customer can spend up to $25 to buy pens at the store and there is no sales tax, what
is the greatest number of pens the customer can buy?
A. 9
B. 10
C. 11
D. 12
E. 20
Solution;
For buying greatest number of pens, the customer must buy maximum number of low cost
pens.
Hence she can buy 12 low cost pens for $24 and take $1 in return or she can buy 11 $2 pens for
$22 and a $3 pen for $3. In both cases she can buy a maximum of 12 pens.
3. Hence D is answer.
5. If y=3x and z=2y, what is x+y+z in terms of x?
A. 10x
B. 9x
C. 8x
D. 6x
E. 5x
Solution;
x+y+z=x+3x+2(3x)=10x
Hence A is the answer.
6. A certain shipping service charges an insurance fee of $0.75 when shipping any package
with contents worth $25.00 or less, and an insurance fee of $1.00 when shipping any package
with contents worth over $25.00. If Dan uses the shipping company to ship three packages
with contents worth $18.25, $25.00 and $127.50, what is the total insurance fee that the
company charges Dan to ship three packages?
A. $1.75
B. $2.25
C. $2.50
D. $2.75
E. $3.00
Solution;
0-$25 $0.75
$25.00+ $1.00
Total charge=($0.75*2)+$1.00=$2.50
Hence our answer is C.
4. 7. If 55 percent of the people who purchase a certain product are female, what is the ratio of
females who purchase the product to the number of males who purchase the product?
A. 11 to 9
B. 10 to 9
C. 9 to 10
D. 9 to 11
E. 5 to 9
Solution;
Total=100
Number of females purchasing the product=55
Number of males purchasing the product=100-55=45
So, Females/Males=55/45=11/9
Hence our answer is A.
8.
The figure above shows the graph of the function f in the x-y plane. What is the value of
f(f(-1))?
A. -2
B. -1
C. 0
D. 1
E. 2
5. Solution;
From the graph,
f(-1)=2
therefore, f(f(-1))=f(2)=1
Hence D is our answer.
9. By weight, liquid A makes up 8 percent of solution R and 18 percent of solution S. If 3 grams
of solution R are mixed with 7 grams of solution S, the liquid A accounts for what percent of
the weight of the resulting solution?
A. 10%
B. 13%
C. 15%
D. 19%
E. 26%
Solution;
In 100 grams solution of R, there are 8 grams of liquid A.
In 1 grams solution of R, there are 8/100 grams of liquid A.
In 3 grams solution of R, there are 8*3/100 grams of liquid A.
Similarly,
In 100 grams solution of S, there are 18 grams of liquid A.
In 1 gram solution of S, there are 18/100 grams of liquid A.
In 7 grams solution of S, there are 18*7/100 grams of liquid A.
That means, when the two solutions are mixed, the resulting 3+7=10 grams of solution will have
(8*3/100)+(18*7/100)=0.24+1.26=1.50 grams of liquid A.
Hence percentage of liquid A=1.50/10*100=15%
Hence our answer is C.
6. 10. Of the 700 members of a certain organization, 120 are lawyers. Two members of the
organization will be selected at random. Which of the following is closest to the probability
that NEITHER of the members selected will be a lawyer?
A. 0.5
B. 0.6
C. 0.7
D. 0.8
E. 0.9
Solution;
P(neither lawyer)=P(first not lawyer)*P(second not lawyer)
=580/700*579/699=0.686(=0.7)
Hence our answer is C.
Another method!!!
P(neither lawyer)=580C2/700C2=0.68 (=ways of selection of both non-lawyers/total selection)
11. A manager is forming a 6-person team to work on a certain project. From the 11 candidates
available for the team, the manager has already chosen 3 to be on the team. In selecting the
other 3 team members, how many different combinations of 3 of the remaining candidates
does the manager have to choose from?
A. 6
B. 24
C. 56
D. 120
E. 462
Solution;
From the 11 candidates, 3 have already been chosen. So for forming a 6 person team, the
manager has to select (6-3)=3 candidates out of (11-3)=8 candidates.
So, 8C3=8!/3!5!=56. That means our answer is C.
7. A. 0
B. 0
C. 0
D. 0
E. 0
12. Which of the following could be the graph of all values of x that satisfy the inequality
2-5x<=-(6x-5)/3?
Solution;
2-5x<=-(6x-5)/3
6-15x<=-6x+5
6-5<=15x-6x
1<=9x
1/9<=x
Hence our answer is C.
13. If 1+x+x2
+x3
=60, then the average of x,x2
,x3
and x4
is equal to which of the following?
A. 12x
B. 15x
C. 20x
D. 30x
E. 60x
Solution;
(x+x2
+x3
+x4
)/4=x(1+x+x2
+x3
)/4=x*60/4=15x
Hence our answer is B.
8. 14. The sequence of numbers a1, a2, a3,…..an,…. is defined by an=(1/n)-(1/n+2) for each integer
n>=1. What is the sum of the first 20 terms of this sequence?
A. (1+1/2)-1/20
B. (1+1/2)-(1/21+1/22)
C. 1-(1/20+1/23)
D. 1-1/22
E. 1/20-1/22
Solution;
a1=1/1-1/3
a2=1/2-1/4
a3=1/3-1/5
………………..
a1+a2+a3+……….a20=(1+1/2+1/3+…….+1/20)-(1/3+1/4+…….1/22)=(1+1/2)-(1/21+1/22)
Hence our answer is B.
15. What is the least positive integer that is NOT a factor of 25! and is NOT a prime number?
A. 26
B. 28
C. 36
D. 56
E. 58
Solution;
25!=25*24*23*22*…………………1
26=13*2
28=14*2
36=12*3
9. 56=7*8
58=29*2
That means 58 is not a factor of 25! since none of the factors of 25! is divisible by 29.
Hence our answer is E.
16. If 0<a<1<b, which of the following is true about the reciprocals of a and b?
A. 1<1/a<1/b
B. 1/a<1<1/b
C. 1/a<1/b<1
D. 1/b<1<1/a
E. 1/b<1/a<1
Solution;
a<1<b
Here a and b are both positive. Taking reciprocals,
1/a>1>1/b
Ex,0.1<1<2
taking reciprocals, 1/0.1>1/1>1/2 i.e., 10>1>0.5
Hence our answer is D.
17. Of the 750 participants in a professional meeting, 450 are female and 1/2 of the female and
1/4 of the male participants are less than 30 years old. If one of the participants will be
randomly selected to receive a prize, what is the probability that the person selected will be
less than 30 years old?
A. 1/8
B. 1/3
C. 3/8
D. 2/5
10. E. 3/4
Solution;
Female=450, Male=300
1/2 of female=1/2*450=225 (<30 years old)
1/4 of male=1/4*300=75 (<30 years old)
P(less than 30)=(225+75)/750=300/750=2/5
Hence our answer is D.
18. From the even numbers between 1 and 9, two different even numbers are to be chosen at
random. What is the probability that their sum will be 8?
A. 1/6
B. 3/16
C. 1/4
D. 1/3
E. 1/2
Solution;
Even numbers between 1 and 9 are 2,4,6 and 8.
There is just one combination for the sum to be 8 i.e. combination of 2 and 6.
Total number of combinations=4C2=6
Hence P(sum=8)=1/6
Hence A is our answer.
19. If x and y are the tens and the unit digit respectively of a product 725,278*67,066, what is
the value of x+y?
A. 12
B. 10
C. 8
11. D. 6
E. 4
Solution;
725278
*67066
.……….68
...……68
+
48
Now 4+8=12
Hence our answer is A.
20. What is the least possible value of x+y/xy if 2<=x<y<=11 and x and y are integers?
A. 22/121
B. 5/6
C. 21/110
D.13/22
E. 1
Solution;
x+y/xy=1/x+1/y
value of 1/x+1/y is least when both x and y are greatest.
From the given inequality,
the greatest possible value of x is 10 and that of y is 11.
So least possible value of x+y/xy is (10+11)/10*11=21/110.
Hence our answer is C.
12. 21. If 998*1002>106
-x, x could be
A. 1
B. 2
C. 3
D. 4
E. 5
Solution;
998*1002=(1000-2)(1000+2)=10002
-4=(103
)2
-4=106
-4
So, 106
-4>106
-x
i.e., -4>-x
i.e., x>4
Hence our answer is E.
22. To reproduce an old photograph, a photographer charges x dollars to make a negative,
3x/5 dollars for each of the first 10 prints and x/5 dollars for each print in access of 10 prints. If
$45 is the total charge to make a negative and 20 prints from an old photograph, what is the
value of x?
Solution;
A. 3
B. 3.5
C. 4
D. 4.5
E. 5
Solution;
x+3x/5*10+x/5*10=45
x+6x+2x=45
x=5. So our answer is E.
13. 23. A certain cake recipe states that the cake should be baked in a pan 8 inches in diameter. If
Jules wants to use the recipe to make a cake of the same depth but 12 inches in diameter, by
what factor should he multiply the recipe ingredients?
A. 5/2
B. 9/4
C. 3/2
D. 13/9
E. 4/3
Solution;
Volume of cake1=3.14*d12
*h1/4
Volume of cake2=3.14*d22
*h2/4
Now required factor of multiplication=V2/V1=(d2/d1)2
=(12/8)2
=(3/2)2
=9/4
Hence our answer is B.
24. A reading list for humanities course consists of 10 books, of which 4 are biographies and the
rest are novels. Each student is required to read a selection of 4 books from the list, including 2
or more biographies. How many selections of the 4 books satisfy the requirements?
A. 90
B. 115
C. 130
D. 144
E. 195
Solution;
Biographies Novels Combinations
2 2 4C2*6C2=90
3 1 4C3*6C1=24
4 0 4C4=1
14. Total ways=90+24+1=115
Hence our answer is B.
25. If the probability of choosing 2 red marbles without replacement from a bag of only red
and blue marbles is 3/55 and there are 3 red marbles in the bag, what is the total number of
marbles in the bag?
A. 8
B. 11
C. 55
D. 110
E. 165
Solution;
Let n be the number of blue marbles.
Then P(RR)=P(R)*P(R)=(3/3+n)*(2/2+n)=6/(3+n)(2+n)
or, 3/55=6/(3+n)(2+n)
or, 1/55=2/(3+n)(2+n)
or, 6+3n+2n+n2
=110
or, n2
+5n-104=0
or, n(n+13)-8(n+13)=0
or, (n+13)(n-8)=0
Since n cannot be negative, n=8.
Hence total number of marbles in the bag=8+3=11. So answer is B.
26. If 1/(211
)(517
) is expressed as a terminating decimal, how many non-zero digits will the
decimal have?
A. 1
B. 2
15. C. 4
D. 6
E. 11
Solution;
1/211
517
=1/211
*511
*56
=1/1011
*56
=(1/5)6
*10-11
=0.26
*10-11
=(2*10-1
)6
*10-11
=64*10-17
Hence there will be 2 non-zero digits in the decimal value.
Our answer is B.
27. Distance from Centerville(miles)
Freight train -10t+115
Passenger train -20t+150
The expressions in the table above give the distance from Centerville to each of two trains t
hours after 12:00 noon. At what time after 12:00 noon will the trains be equivalent from
Centerville?
A. 1:30
B. 3:30
C: 5:10
D. 8:50
E. 11:30
Solution;
-10t+115=-20t+150
10t=35
t=3.5 hours.
Hence, they will be equivalent from Centerville at 3:30.
Hence our answer is B.
16. 28. In state X, all vehicle license plates have 2 letters from the 26 letters of the alphabet
followed by 3 one-digit numbers. How many different license plates can State X have if
repetition of letters and numbers is allowed?
A. 23,400
B. 60,840
C. 67,600
D. 608,400
E. 676,000
Solution;
Total combinations=26*26*10*10*10=676000
Hence our answer is E.
29. A developer has land that has x feet of lake frontage. The land is to be subdivided into lots,
each of which is to have either 80 feet or 100 feet of lake frontage. If 1/9 of the lots are to have
80 feet of frontage each and the remaining 40 lots are to have 100 feet of frontage each,
what is the value of x?
A. 400
B. 3,200
C. 3,700
D. 4,400
E. 4,760
Solution;
1/9 of lots=40/8=5lots 80 feet of frontage each
8/9 of lots=40lots 100 feet of frontage each
x=5*80+40*100=400+4000=4,400
Hence our answer is D.
17. 30. Which of the following is not a factor of 1030
?
A. 250
B. 125
C. 32
D. 16
E. 6
Solution;
1030
=(2*5)30
=230
*530
250=53
*2
125=53
32=25
16=24
6=2*3
Our answer is E since 230
*530
does not have a factor of 3.
31. R
y T
Q x S
In the figure, QRS is an equilateral triangle and QTS is an isosceles triangle. If x=47, what is the
value of y?
A. 13
B. 23
C. 30
D. 47
E. 53
18. Solution;
=60-47=13
y
47 60
Hence our answer is A.
32. If k is an integer and 0.0010101*10k
>1000, what is the least possible value of k?
A. 2
B. 3
C. 4
D. 5
E. 6
Solution;
0.0010101*10k
>1000
If k=4, 0.0010101*10k
=0.0010101*104
=10.101<1000
Now k=5 too won't be working because it would become 101.01
So if k=6, 0.0010101*10k
=0.0010101*106
=1010.1
Any value of k greater than 6 would also satisfy the given equation. But 6 is the least integer.
hence our answer is E.
33.If n is a positive integer and k+2=3n
, which of the following could NOT be a value of k?
A. 1
B. 4
C. 7
D. 25
19. E. 79
Solution;
k=3n
-2
for n=1, k=31
-2=1
for n=2, k=32
-2=7
That means, 4 could not be the value of k since there are no integers in between 1 and 2.
Hence our answer is B.
34. -10 A B -2 C -1 0 D 2 E 10
Five points A,B,C,D and E are shown on a number line. What is the probability of all numbers
being negative if three numbers are selected at random?
A. 1/10
B. 3/5
C. 2/5
D. 4/5
E. 3/10
Solution;
A,B and C are 3 negative numbers and D,E are 2 positive numbers.
P(all negative)=3C3/5C3=number of ways of selection of 3 negative numbers/total ways
=1/10
Hence our answer is A.
35. Square T is formed by joining the mid-points of sides of square S. The perimeter of square S
is 40. What is the area of square T?
A. 45
B. 48
C. 49
20. D. 50
E. 52
Solution; 5 Square S
5 Square T
/52
+52
=/50 10
Perimeter of S=40
4l=40
l=10
Area=(/50)2
=50
Hence our answer is D.
36. How many different positive integers are there in which the tens digit is greater than 6 and
the units digit is less than 4?
A. 7
B. 9
C. 10
D. 12
E. 24
Solution;
tens digit needs to be greater than 6 i.e. it can be 7,8 or 9 so it has 3 choices.
units digit needs to be less than 4 i.e. it can be 0,1,2 or 3 so it has 4 choices.
Hence total number of ways=3*4=12. Our answer is D.
21. 37. If in 1998 there were 10,000 bias-motivated offenses based on ethnicity, how many more
offenses were based on religion than on sexual orientation?
A. 4
B. 40
C. 400
D.4000
E. 40,000
Solution;
10.0% 10000
1% 1000
16% 16000(religion)
15.6% 15600(sexual orientation)
16000-15600=400 Answer C.
22. 38. A rectangular game board is composed of identical squares arranged in a rectangular
array of r rows and r+1 columns. The r rows are numbered from 1 through r, and the r+1
columns are numbered from 1 through r+1. If r>10, which of the following represents the number
of squares on the board that are neither in the 4th row nor in the 7th column?
A. r2
-r
B. r2
-1
C. r2
D. r2
+1
E. r2
+r
Solution; r+1 columns
r
rows
Solution;
Here, r(r+1)=r2
+r is the area of the board.
Our answer must be less than this.
So we can eliminate choice E.
Sum of squares of 4th row and 7th column=(r+1)+r-1=2r
So required number of squares=r2
+r-2r=r2
-r
Hence our answer is A.
23. 39. S is a set containing 9 different numbers. T is a set containing 8 different numbers, all of
which are members of S. Which of the following statements CANNOT be true?
A. The mean of S is equal to the mean of T.
B. The median of S is equal to the median of T.
C. The range of S is equal to the range of T.
D. The mean of S is greater than the mean of T.
E. The range of S is less than the range of T.
Solution;
S={-4,-3,-2,-1,-0.5,0,1,2,3} and T={-4,-3,-2,-1,0,1,2,3}
mean of S=-4.5/9=-1/2
mean of T=-4/8=-1/2
Choice A can be true.
Next, let S={-4,-3,-2,-1,0,1,2,3,4} and T={-4,-3,-2,-1,0,1,2,3}
mean of S=0/9=0
mean of T=-4/9
Choice D can also be true.
If S={-4,-3,-2,-1,0,1,2,3,4} and T={-4,-3,-2,-1,1,2,3,4}
then range of S=4-(-4)=8
and range of T=4-(-4)=8
Choice C can be true as well.
Next, let S={-4,-3,-2,-1,1,2,3,4} and T={-4,-3,-2,-1,1,2,3,4}
then range of S=5-(-4)=8
and range of T=5-(-4)=9
Choice E can also be true.
24. 40. What is the greatest positive integer n such that 2n
is a factor of 1210
?
A. 10
B. 12
C. 16
D. 20
E. 60
Solution;
1210
=(2*2*3)10
=210*
210
*310
=220
*310
If n=20, then 1210
/220
=220
*310
/220
=310
But if n=21, then 1210
/221
=220
*310
/221
=310
/2
Hence the greatest possible value of n is 20. Hence our answer is D.
41. If x is an integer and y=9x+13, what is the greatest value of x for which y is less than 100?
A. 12
B. 11
C. 10
D. 9
E. 8
Solution;
Try with x=10
then y=9*10+13=103
That means we can eliminate choices A,B and C because, if x=10 gives y>100, then x=11 or 12 will
also give y>100.
Now try x=9, then y=9*9+13=94(<100)
x=8 will also give y<100. But since we need the greatest value of x for which y<100, our answer
is D.
25. 42. Each month, a certain manufacturing company's total expenses are equal to a fixed
monthly expense plus a variable expense that is directly proportional to the number of units
produced by the company during that month. If the company's total expenses for a month in
which it produces 20,000 units are $570,000 and the total expenses for a month in which it
produces 25,000 units are $705,000, what is the company's fixed monthly expense?
A. $27,000
B. $30,000
C. $67,500
D. $109,800
E. $135,000
Solution;
total expenses=fixed expense+variable expense
$570,000=fixed expense+k*20,000
$705,000=fixed expense+k*25,000
(variable expense=k*number of units produced)
Solving above equations, we get
135,000=5000k
k=27
So 570,000=fixed expense+(27*20,000)
fixed expense=30,000
Hence our answer is B.
43. A team has a record of 12 wins and 13 losses for the season. Three games remain. If the
probability of winning each remaining game is 1/2 and there are no draws, what is the
probability that the team will finish the season with a winning record?
A. 1/5
B. 1/4
C. 3/8
26. D. 1/2
E. 5/8
Solution;
The possible results of remaining 3 games are
WWW (12+3=15 wins and 13 losses win)
WWL (12+2=14 wins and 13+1=14 losses, no draws)
WLW
LWW
LWL (12+1=13 wins and 13+2=15 losses loss)
LLW (loss)
WLL (loss)
LLL (12 wins and 13+3=16 losses loss)
1 winning possibility out of 5 possibilities
so probability of winning the season=1/5, which is answer A.
44. How many three digit integers are odd and do not contain the digit 5?
A. 360
B. 320
C. 288
D. 256
E. 252
Solution;
8*9*4=288
can be from 1 to 9 except 5 8 choices
can be from 0 to 9 except 5 9 choices
can be 1,3,5 or 7 4 choices
27. Hence our answer is C.
45. When the fraction 1/37 is converted to a decimal, what is the 24th digit to the right of the
decimal place?
A. 0
B. 2
C. 3
D. 5
E. 7
Solution;
1/37=0.027027027…..
The pattern is repeating after the 3rd digit of the decimal i.e. 7. So the 24th digit after the
decimal is also 7 since 24 is divisible by 3.
Hence our answer is E.
46. What is the ratio of surface area of a cube to the surface area of a rectangular solid
identical to the cube in all ways except that its length has been doubled?
A. 1:4
B. 3:8
C. 1:2
D. 3:5
E. 2:1
Solution;
Let length of each edge of the cube be 1. Then, Surface area of cube, S1=6l2
=6
for the rectangular solid,
length=2, breadth=1 and height=1
Surface area of rectangular solid, S2=2(lb+bh+lh)=2(2*1+1*1+2*1)=10
28. S1/S2=6/10=3/5 which is choice D.
47. 12,2732
+12,2742
=
A. 299,235,509
B. 300,568,327
C. 301,277,605
D. 302,435,782
E. 303,053,291
Solution;
12,2732
+12,2742
=…………..9+…………6=………………5
The result must have unit digit 5. Hence our answer is C.
48. The quantity 22
33
55
66
will end in how many zeroes?
A. 0
B. 2
C. 3
D. 5
E. 6
Solution;
22
33
55
66
=22
33
55
(2*3)6
=22
33
55
26
36
=28
39
55
=23
25
39
55
=23
105
39
Hence there will be 5 zeroes. That means our answer is D.
49. Employee at a company is paid fixed salary of $90,000 annually plus 100 shares of that
company. After 9 months, he leaves the job and receives $65,000 and 80 shares. What is the
price of the share?
A. $450
B. $500
29. C. $700
D. $750
E. Cannot be determined from the given information.
Solution;
In 12 months, he gets $90,000 plus 100 shares.
In 1 month, he gets $90,000/12=$7,500 plus 100/12 shares.
In 9 months, he gets $7,500*9=$67,500 plus 100/12*9=75 shares.
Let each share worth $x.
Then 67,500+75x=65,000+80x
x=$500
Hence our answer is B.
50. Paint needs to be thinned to a ratio of 2 parts paint to 1.5 parts water. The painter has by
mistake added water so that he has 6 liters of paint which is half water and half paint. What
must he add to make the proportions of the mixture correct?
A. 1 liter paint
B. 1 liter water
C. 1/2 liter water and 1 liter paint
D. 1/2 liter paint and 1 liter water
E. 1/2 liter paint
Solution;
Paint:water=2/1.5=4/3(required)
In 6 liters of paint mixture, there are 1/2*6=3 liters of paint and 1/2*6=3 liters of water.
Now to make the ratio 4:3, he must add 1 liter paint to the mixture.
i.e., paint:water=(3+1)/3=4/3
Hence our answer is A.
30. 51. Kelly took three days to travel from City A to City B by automobile. On the first day, Kelly
traveled 2/5 of the distance from City A to City B and on the second day, she traveled 2/3 of
the remaining distance. Which of the following is equivalent to the fraction of the distance
from City A to City B that Kelly traveled on the third day?
A. 1-2/5-2/3
B. 1-2/5-2/3(2/5)
C. 1-2/5-2/5(1-2/3)
D. 1-2/5-2/3(1-2/5)
E. 1-2/5-2/3(1-2/5-2/3)
Solution;
1st day=2/5
remain=1-2/5
2nd day=2/3*(1-2/5)
3rd day=1-2/5-2/3(1-2/5)
Hence our answer is choice D.
52. If x and y are integers and x=50y+69, which of the following must be odd?
A. xy
B. x+y
C. x+2y
D. 3x-1
E. 3x+1
Solution;
50y is always even.
69 is odd.
So x must be odd. (even+odd=odd) and y can be either odd or even.
xy=odd*(odd or even)=odd or even
31. x+y=odd+(odd or even)=even or odd
x+2y=odd+even=odd
3x-1=3*odd-1=odd-1=even
3x+1=3*odd+1=odd+1=even
Hence our answer is choice C.
53. In the first half of the last year, a team won 60 percent of the games it played. In the
second half of the last year, the team played 20 games, winning 3 of them. If the team won 50
percent of the games it played last year, what was the total number of games the team
played last year?
A. 60
B. 70
C. 80
D. 90
E. 100
Solution;
Let number of games played in 1st half be x.
1st half=60% of x won=0.6x
2nd half=3 won out of 20 games
Number of games won in 1st half and 2nd half=50% of total number of games played
0.6x+3=0.5(x+20)
0.1x=7
x=70
Total number of games played=70+20=90
Hence our answer is D.
32. 54. In the sequence a1,a2,a3,……a100, the kth term is defined by ak=1/k-1/k+1 for all integers k
from 1 through 100. What is the sum of the 100 terms of this sequence?
A. 1/10,100
B. 1/101
C. 1/100
D. 100/101
E. 1
Solution;
a1=1-1/2
a2=1/2-1/3
a3=1/3-1/4
a4=1/4-1/5
…………………
…………………
a100=1/100-1/101
a1+a2+a3+a4+……..+a100=1-1/101=100/101
Hence our answer is choice D.
55. Eight hundred insects were weighed, and the resulting measurements in milligrams, are
summarized in the box plot below.
100 105 110 114 120 126 130 140 146
If the 80th percentile of the measurements is 130 mgs, about how many measurements are
between 126 mgs and 130 mgs?
A. 30
B. 32
33. C. 35
D. 40
E. 42
Solution;
75th percentile=126
80th percentile=130
So between 126 mgs and 130 mgs, there are 5% of total data.
5% of 800=5/100*800=40
Hence our answer is choice D.
56. There is a leak in the bottom of tank. This leak can empty a full tank in 8 hours. When the
tank is full, a tap is opened into the tank which intakes water at rate of 6 gallons per hour
and the tank is now emptied in 12 hours. What is the capacity of tank?
A. 28 gallons
B. 36 gallons
C. 144 gallons
D. 150 gallons
E. cannot be determined from the information given.
Solution;
Let capacity of tank be x.
In 1 hour, the leak empties x/8 gallons water.
In 1 hour, the tank intakes 6 gallons water.
In 1 hour, x/8-6 gallons water is emptied.
In 12 hours, 12(x/8-6) gallons water is emptied.
We are given, x gallon tank(full tank) is emptied in 12 hours.
So, 12(x/8-6)=x
1.5x-72=x
34. 0.5x=72
x=144
Hence C is our answer.
57. Set S includes elements {8,2,11,x,3,y} and has an average of 7 and a median of 5.5. If x<y,
then which of the following is the maximum possible value of x?
A. 0
B. 1
C. 2
D. 3
E. 4
Solution;
(8+2+11+x+3+y)/6=7
24+x+y=42
x+y=18
Median=5.5
if x=1, then y=17
1,2,3,8,11,17
median=(3+8)/2=5.5
if x=2, then y=16
2,2,3,8,11,16
median=(3+8)/2=5.5
if x=3, then y=15
2,3,3,8,11,15
median=(3+8)/2=5.5
if x=4, then y=14
35. 2,3,4,8,11,14
median=(4+8)/2=6
Hence maximum possible value of x is 3. So our answer is D.
58. If x+y=10, and xy=20, what is the value of 1/x+1/y?
A. 1/20
B. 1/15
C. 1/10
D. 1/2
E. 2
Solution;
1/x+1/y=(y+x)/xy=10/20=1/2
Hence our answer is D.
59. In a normal distribution, 68 percent of scores lie within one standard deviation of the
mean. If the SAT scores of all the high school juniors in the Center City followed a normal
distribution with a mean of 500 and a standard deviation of 100, and if 10,200 students
scored between 400 and 500, approximately how many students scored above 600?
A. 2,400
B. 4,800
C. 5,100
D. 7,200
E. 9,600
36. Solution;
34% 34%
2%14% 14% 2%
400 500 600
400-500 10,200
34% 10,200
1% 300
16% 4,800
Hence our answer is B.
60. John bought a $100 DVD player on sale at 8% off. How much did he pay including 8% sales
tax?
A. $84.64
B. $92.00
C. $96.48
D. $99.36
E. $100.00
Solution;
SP=92% of $100=$92 (excluding tax)
SP=108% of $92=$99.36
Hence our answer is D.
37. 61. For how many positive integers m<=100 is (m-5)(m-45) positive?
A. 45
B. 50
C. 58
D. 59
E. 60
Solution;
(m-5)(m-45)>0
Two possibilities
m-5>0 and m-45>0
So m>5 and m>45 m>45 and m<=100
So number of possible values of m in this case=100-45=55
m-5<0 and m-45<0
So m<5 and m<45 m<5
So number of possible values of m in this case=4
Hence our answer is 55+4=59, that means D.
62. If the average (arithmetic mean) of 3a and 4b is less than 50, and a is twice b, what is the
largest possible integer value of a?
A. 9
B. 10
C. 11
D. 19
E. 20
Solution;
(3a+4b)/2<50
38. 3a+4b<100
a=2b
2a=4b
So 3a+2a<100
5a<100
a<20
Since a needs to be an integer, a=19
So our answer is D.
63. x,y,a and b are positive integers. When x is divided by y, the remainder is 6. When a is
divided by b, the remainder is 9. Which of the following is NOT a possible value of y+b?
A. 24
B. 21
C. 20
D. 17
E. 15
Solution;
x divided by y gives remainder 6 means y>6
Ex, 12)18(1
-12
6
a divided by b gives remainder 9 means b>9
Ex, 10)19(1
-10
9
If y>6 and b>9, then y+b>15
39. Thus, 15 cannot be the sum of y and b.
So our answer is E.
64. A pair of dice is tossed twice. What is the probability that the first toss gives a total of either
7 or 11 and the second toss gives a total of 7 ?
A. 1/27
B. 1/18
C. 1/9
D. 1/6
E. 7/18
Solution;
1 2 3 4 5 6
1 (1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
2 (2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
3 (3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
4 (4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
5 (5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
6 (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
There are a total of 62
=36 possible outcomes in the first toss of a pair of coins as shown above.
P(total=7 or 11 in the first toss)=8/36
Again, there are same number of 36 possible outcomes in the second toss.
P(total=7 in the second toss)=6/36
P(total=7 or 11 in the first toss) and P(total=7 in the second toss)=8/36*6/36=2/9*1/6=1/27
Hence our answer is A.
40. 65. Three dice are rolled simultaneously. What is the probability that exactly two of the dice
will come up as the same number?
A. 5/12
B. 11/24
C. 25/54
D. 13/27
E. 1/2
Solution;
If we roll three dice simultaneously, then there will be a total of 63
=216 possible outcomes.
Let A,B and C be 3 dice.
If A and B come up same number, then there are 5 choices left with C.
Ex If A and B are both 1 or treating A and B as one unit, then C will have 5 choices left for
exactly two of the dice to come up as same number. (that means C cannot be 1)
So there are 6*5=30 ways that A and B come up as same number.
Likewise there are 30 ways that (B and C) and (C and A) come up as same number.
So there are 30*3=90 favorable outcomes.
So probability=90/216=45/108=15/36=5/12
Hence our answer is A.
66. Which of the following could be the median for a set of integers {97, 98, 56, x, 86}, given
that 20 < x < 80?
A. 71
B. 86
C. 91.5
D. 97
E. 397.5
Solution;
41. x,56,86,97,98
56,x,86,97,98
Hence our answer is B.
67. In the coordinate plane, rectangle WXYZ has vertices at (–2, –1), (–2, y), (4, y), and (4, –1).
If the area of WXYZ is 18, what is the length of its diagonal?
A. 3/2
B. 3/3
C. 3/5
D. 3/6
E. 3/7
Solution;
(-2,y) (4,y)
(-2,-1) (4,-1)
Area=18=6*(y+1)
y+1=3
y=2
Diagonal length=/(62
+32
)=/(36+9)=/45=/(5*9)=3/5
Hence answer is C.
68. In the repeating decimal 0.0653906539..., the 34th digit to the right of the decimal point is
A. 9
B. 6
42. C. 5
D. 3
E. 0
Solution;
The pattern is repeating after 5th digit. The 5th digit after the decimal is 9. So multiples of 5
will have the digit 9. Hence 35th digit is also 9 and a digit before it will be 3.
Hence our answer is D.
69. The numbers in data set S have a standard deviation of 5. If a new data set is formed by
adding 3 to each number in S, what is the standard deviation of the numbers in the new data
set?
A. 2
B. 3
C. 5
D. 8
E. 15
Solution;
Let S={0,5,10}
mean=15/3=5
sd= (0-5)2
+(5-5)2
+(10-5)2
= 50/3
3
S1={0+5,5+5,10+5}={5,10,15}
mean=30/3=10
sd= (5-10)2
+(15-10)2
+(15-15)2
= 50/3
3
That means, standard deviation of a set of numbers is not affected by adding same number to
each number.
Hence our answer is C.
70. Aisha's income in 2004 was 20 percent greater than her income in 2003. What is the ratio
of Aisha's income in 2004 to her income in 2003?
A. 1 to 5
B. 5 to 6
43. C. 6 to 5
D. 5 to 1
E. 20 to 1
Solution;
In 2003, income=100
In 2004, income=120
income(2004)/income(2003)=120/100=6/5
Hence our answer is C.
71. Jacob's weekly take-home pay is n dollars. Each week he uses 4n/5 dollars for expenses and
saves the rest. At those rates, how many weeks will it take Jacob to save $500, in terms of n?
A. 500/n
B. 2,500/n
C. n/625
D. n/2,500
E. 625n
Solution;
Expenses=4n/5 $
Save=(n-4n/5) $=n/5 $
In 1 week, save=n/5 $
in 5/n weeks, save=1 $
in 5/n*500=2,500/n weeks, save=500$
Hence our answer is B.
72. The operation ♥ is defined for all integers x and y as x♥y=xy-y. If x and y are positive
integers, which of the following CANNOT be zero?
A. x♥y
B. y♥x
C. (x-1)♥y
D. (x+1)♥y
E. x♥(y-1)
Solution;
44. x♥y=y(x-1) If x=1, then its value can be zero.
y♥x=yx-x=x(y-1) If y=1, then its value can be zero.
(x-1)♥y=(x-1)y-y=y(x-1-1)=y(x-2) If x=2, its value also can be zero.
(x+1)♥y=(x+1)y-y=xy+y-y=xy Its value cannot be zero since x and y are positive integers and the
product of two positive integers cannot be zero.
If we see choice E, x♥(y-1)=x(y-1)-(y-1)=(y-1)(x-1) If x=y=1, its value can be zero.
Hence our answer is D.
73. P, Q and R are three points in a plane, and R does not lie on line PQ. Which of the
following is true about the set of all points in the plane that are the same distance from all
three points?
A. It contains no points.
B. It contains one point.
C. It contains two points.
D. It is a line.
E. It is a circle.
Solution;
P Q
S
R
If any three non co-linear points are given, then we can find a point such that it is at same
distance from all given points. A circle can be drawn through points P,Q and R so that S is the
centre and SP=SQ=SR=radii of the circle. But note that the circle is not at same distance from
points P,Q and R. It's point S or the center of the circle which is at same distance from the
given points.
That means, the set of points that are the same distance from all three points contain just a
point.
Hence our answer is B.
45. 74. X and Y are two points on a plane. Which of the following is NOT true about the set of all
points in the plane that are the same distance from the given two points?
A. It is a straight line.
B. It contains infinite points.
C. It bisects the line joining X and Y.
D. It is perpendicular to the line joining X and Y.
E. It contains two points.
Solution;
X Y
The set of points that are same distance from X and Y will be perpendicular bisector of the line
joining X and Y.
Hence choice E is not true.
75. If x<y<0, which of the following inequalities must be true?
A. y+1<x
B. y-1<x
C. xy2
<x
D. xy<y2
E. xy<x2
Solution;
x<y<0
Let x=-2 and y=-1
then, -1+1>-2 or y+1>x So eliminate A.
and -1-1=-2 or y-1=x So eliminate B.
and -2*(-1)2
=-2 or xy2
=x So eliminate C.
and -2*(-1)>(-1)2
or xy>y2
So eliminate D.
and -2*(-1)<(-2)2
or xy>x2
So our answer is E.
46. 76. For all integers x, the function f is defined as follows.
f(x)=x-1 if x is even
=x+1 if x is odd
If a and b are integers and f(a)+f(b)=a+b, which of the following statements must be true?
A. a=b
B. a=-b
C. a+b is odd.
D. Both a and b are even.
E. Both a and b are odd.
Solution;
a=b
Let a=b=1
then f(a)+f(b)=f(1)+f(1)=(1+1)+(1+1)=4
and a+b=1+1=2 So choice A cannot be true.
Next, a=-b
Let a=1 and b=-1
then f(a)+f(b)=f(1)+f(-1)=(1+1)+(-1+1)=2
and a+b=1-1=0 So choice B cannot be true.
Next, a+b is odd
Let a=1 and b=2 so that a+b=3 which is odd.
then f(a)+f(b)=f(1)+f(2)=(1+1)+(2-1)=3
and a+b=1+2=3 So choice A can be true.
Next, both a and b are even
Let a=2 and b=4
then f(2)+f(4)=2-1+4-1=4
and a+b=2+4=6 So choice D is not true.
Next, both a and b are odd
Let x=1 and y=3
then f(1)+f(3)=1+1+3+1=6
and a+b=1+3=4 So choice E is not true.
Hence, our answer is C.
47. 77. If y-2
+2y-1
-15=0, which of the following could be the value of y?
A. 3
B. 1/5
C. -1/5
D. -1/3
E. -5
Solution;
1/y2
+2/y-15=0
1+2y-15y2
=0
15y2
-2y-1=0
15y2
-5y+3y-1=0
5y(3y-1)+1(3y-1)=0
(3y-1)(5y+1)=0
y=1/3 or -1/5
Hence our answer is C.
78. The figure shows the standard normal distribution, with mean 0 and standard deviation 1,
including approximate percents of the distribution corresponding to the six regions shown.
Ian rode the bus to work last year. His travel times to work were approximately normally
distributed, with a mean of 35 minutes and a standard deviation of 5 minutes. According to
the figure shown, approximately what percent of Ian's travel to work last year were less than
40 minutes?
A. 14%
B. 34%
C. 60%
D. 68%
E. 84%
48. Solution;
mean=35
sd=5
the number 1 standard deviation above mean=35+5=40
If we see the above bell curve, then percentage coverage above value 40 is 14+2=16%
So value below 40 will be 100-16=84%
Hence our answer is E.
79. 4 meters
10
4 meters
10 meters
The figure above shows the floor dimensions of an L-shaped room. All angles shown are right
angles. If carpeting costs $20 per square meter, what will carpeting for the entire floor of the
room cost?
A. $800
B. $1,280
C. $1,600
D. $1,680
E. $2,320
Solution;
4
10
4
10
Area of L shape=4*10+4*10-4*4=40+40-16=80-16=64 m2
So cost of carpeting=Total area of floor*cost per m2
=64*20=$1,280. So our answer is B.
49. 80. Mario purchased $600 worth of traveler's checks. If each check was either $20 or $50,
which of the following CANNOT be the number of $20 checks purchased?
A. 10
B. 15
C. 18
D. 20
E. 25
Solution;
let number of $20 checks purchased be x and number of $50 checks purchased be y.
then 20x+50y=600
2x+5y=60
Looking at this equation,
Since 5y=multiple of 5 which could be 5,10,15,20…. and the sum needs to be 60, 2x must be
multiples of 5 or, x needs to be multiples of 5.
Among the options given, choice C is not multiple of 5. So our it's our answer.
If we put x=18 in the above equation, then
2*18+5y=60
5y=60-36=24
y=4.8 which is not possible since number of tickets purchased cannot be in decimal.
81. a+b/c
d/e
If the value of the expression above is to be halved by doubling exactly one of the five
numbers a, b, c, d, or e, which should be doubled?
A. a
B. b
C. c
D. d
E. e
Solution;
a+b/c*e/d
For this expression to be halved, d should be doubled.
So our answer is D.
50. 82. In the figure above, arcs PR and QS are semi-circles with centers at Q and R respectively. If
PQ=5, what is the perimeter of the shaded region?
A. 5*3.14+5
B. 5*3.14+15
C. 10*3.14+10
D. 10*3.14+15
E. 100*3.14
Solution;
PQ=QR=RS=5
Circumference of each semicircle=3.14*5
Perimeter of shaded region=QP+circumference of semicircle with center Q+RS+ circumference
of semicircle with center Q=5+(3.14*5)+5+(3.14*5)=10*3.14+10
Hence our answer is C.
83. How many of the positive integers less than 25 are 2 less than an integer multiple of 4?
A. 2
B. 3
C. 4
D. 5
E. 6
Solution;
4k-2 where k=1,2,3…
for k=2 4k-2=6
for k=3 4k-2=10
for k=4 4k-2=14
for k=5 4k-2=18
51. for k=6 4k-2=22
Hence our answer is E.
OR, 4k-2<25
4k<27
k<27/4
that means k=6
84. The charge for a telephone call made at 10:00 a.m. from City Y to City X is $0.50 for the
first minute and $0.34 for each additional minute. At these rates, what is the difference
between the total cost of three 5-minute calls and the cost of one 15-minute call?
A. $0.00
B. $0.16
C. $0.32
D. $0.48
E. $1.00
Solution;
for three 5-minute calls,
total charge=3*(0.5+(0.34*4))=$5.58
for one 15-minute call,
charge=0.5+(0.34*14)=$5.26
So difference=5.58-5.26=$0.32
Hence our answer is C.
85. Which of the following is equivalent to the pair of inequalities x+6>10 and x-3<=5?
A. 2<=x<16
B. 2<=x<4
C. 2<x<=8
D. 4<x<=8
E. 4<=x<16
Solution;
x+6>10
x>10-6
x>4
52. Eliminate choices A, B and C since x>=2.
Now
x-3<=5
x<=5+3
x<=8
Hence, 4<x<=8 which is choice D.
86. In Town X, 64 percent of the population are employed, and 48 percent of the population
are employed males. What percent of the employed people in Town X are females?
A. 16%
B. 25%
C. 32%
D. 40%
E. 52%
Solution;
Let total population be 100
then 64 are employed
and 48% of 64=30.72 are employed males.
That means 64-30.72=33.28 are employed females.
employed female %=33.28/64*100=52
Hence our answer is E.
87. If p/q<1, and p and q are positive integers, which of the following must be greater than 1?
A. /p/q
B. p/q2
C. p/2q
D. q/p2
E. q/p
Solution;
Clearly, if p/q<1
then q/p>1. We need not try other choices. Our answer is E.
53. 88. A factory has 500 workers, 15 percent of whom are women. If 50 additional workers are to
be hired and all of the present workers remain, how many of the additional workers must be
women in order to raise the percent of women employees to 20 percent?
A. 3
B. 10
C. 25
D. 30
E. 35
Solution;
15% of 500=75 women
500-75=425 men
Let required number of women to be hired=x.
By question,
75+x=20% of (500+50)
75+x=110
x=110-75=35
Hence our answer is E.
89. A bar over a sequence of digits in a decimal indicates that the sequence repeats
indefinitely.
What is the value of (104
-102
)(0.0012)?
A. 0
B. 0.12
C. 1.2
D. 10
E. 12
Solution;
(104
-102
)(0.0012)=102
(102
-1)(0.0012)=99*0.12
Eliminate choices A and B.
If 10*0.12=1.21>1.2 So 99*0.12>1.2 so Eliminate choice C.
100*0.12=12.12 which is a little less than 12
So 99*0.12=12
Hence our answer is E.
54. 90. An empty pool being filled with water at a constant rate takes 8 hours to fill to 3/5 of its
capacity. How much more time will it take to finish filling the pool?
A. 5 hr 30 min
B. 5 hr 20 min
C. 4 hr 48 min
D. 3 hr 12 min
E. 2 hr 40 min
Solution;
3/5 parts=8 hours
1 part=8*5/3=40/3 hours
2/5 parts=40/3*2/5=16/3 hrs>5 hrs.
Eliminate C, D and E.
16/3=5 hours 20 min. Hence our answer is B.
91. John has 10 pairs of matched socks. If he loses 7 individual socks, what is the greatest
number of pairs of matched socks he can have left?
A. 7
B. 6
C. 5
D. 4
E. 3
Solution;
For the maximum number of pairs of matched shocks left, 3 pairs of matched socks must be
lost and remaining one individual sock can be from any pair.
Hence in all, he can have maximum 6 matched pairs of socks remaining.
Hence our answer is B.
Note: for minimum number of matched pair of socks left, all 7 lost individual socks must be
from different pair so that minimum number of matched pairs of socks remaining=10-7=3
92.
p q
(4,3)
55. In the x-y coordinate system above, the lines q and p are perpendicular. The point (3,a) is on
line p. What is the value of a?
A. 3
B. 4
C. 13/3
D. 14/3
E. 16/3
Solution;
slope of line q=3/4 ,it passes through origin.
So slope of line p=-4/3 since they are perpendicular to each other, the product of their slopes=-1)
Also slope of line p=(3-a)/(4-3)=(3-a)/1=3-a=-4/3
a=(4/3)+3=13/3.
Hence our answer is C.
93. John works for 5 days. His daily earnings are displayed on the above graph, If John earned
$35 on the sixth day, what would be the closest difference between the meadian and the
mode of the wages during the six days?
A. $5.5
B. $6.5
C. $7.5
D. $8.5
56. E.$9.5
Solution;
60,75,45,35,40,35
For median, arrange given data in ascending order.
35,35,40,45,60,75
median=value of (6+1)th/2=3.5th item=(40+45)/2=85/2=42.5
mode=35
median-mode=42.5-35=$7.5
Hence our answer is C.
94. The degree measures of the four angles of a quadrilateral are w, x, y and z respectively. If
w is the average of x, y and z, then x+y+z=
A. 45
B. 90
C. 120
D. 180
E. 270
Solution;
w+x+y+z=360
w=(x+y+z)/3
So (x+y+z)/3+(x+y+z)=360
4/3*(x+y+z)=360
x+y+z=360*3/4=90*3=270
Hence our answer is E.
95. In a certain school, special programs in French and Spanish are available. If there are N
students enrolled in the French program, and M students in the Spanish program, including P
students who enrolled in both programs, how many students are taking only one (but not
both) of the language programs?
A. N+M
B. N+M-P
C. N+M+P
D. N+M-2P
57. E. N+M+2P
Solution;
n(French only)+n(Spanish only)=(N-P)+(M-P)=N+M-2P
Hence our answer is D.
96. In the sequence of numbers x1,x2,x3,x4,x5, each number after the first is twice the preceding
number. If x5-x1 is 20, what is the value of x1?
A. 4/3
B. 5/4
C. 2
D. 5/2
E. 4
Solution;
x2=2x1
x3=4x1
x4=8x1
x5=16x1
x5-x1=20
16x1-x1=20
15x1=20
x1=20/15=4/3
Hence our answer is A.
97. If a, b, and c are consecutive positive integers and a<b<c, which of the following must be an
odd integer?
A. abc
B. a+b+c
C. a+bc
D. a(b+c)
E. (a+b)(b+c)
Solution;
a=1, b=2 and c=3
then abc=1*2*3=6 (even)
58. a+b+c=1+2+3=6 (even)
a+bc=1+(2*3)=7 (odd)
a(b+c)=1(2+3)=5 (odd)
(a+b)(b+c)=(1+2)(2+3)=15 (odd)
Let a=2, b=3 and c=4
then a+bc=2+(3*4)=14 (even)
a(b+c)=2(3+4)=14 (even)
and (a+b)(b+c)=(2+3)(3+4)=35 (odd)
Hence our answer is E.
98. If x can have values -3, 0, and 2, and y can have only the values -4, 2, and 3, what is the
greatest possible value for 2x+y2
?
A. 13
B. 15
C. 16
D. 20
E. 22
Solution;
For 2x+y2
to be maximum, 2x and y2
both must be maximum.
The maximum value of x is 2. So maximum value of 2x=2*2=4
The maximum value of y2
is at y=-4. So maximum value of y2
is (-4)2
=16
So maximum value of given expression is 4+16=20
Hence our answer is D.
99. If B is the midpoint of line segment AD and C is the midpoint of line segment BD, what is
the value of AB/AC?
A. 3/4
B. 2/3
C. 1/2
D. 1/3
E. 1/4
Solution;
59. A B C D
AB=BD=BC+CD=BC+BC=2BC
AC=AB+BC=2BC+BC=3BC
AB/AC=2/3
Hence our answer is B.
100. For each of n people, Margie bought a hamburger and a soda at a restaurant. For each
of n people, Paul bought 3 hamburgers and a soda at the same restaurant. If Margie spent a
total of $5.40 and Paul spent a total of $12.60, how much did Paul spend just for hamburgers?
(Assume that all hamburgers cost the same and all sodas cost the same.)
A. $10.80
B. $9.60
C. $7.20
D. $3.60
E. $2.40
Solution;
Let a hamburger cost $x and a soda cost $y.
then, for Margie, nx+ny=5.40 (i)
for Paul, 3nx+ny=12.60 (ii)
(ii)-(i) gives
2nx=7.2
nx=7.2/2=3.6
3nx=3*3.6=$10.8=cost of total hamburgers for Paul
Hence our answer is A.
101. The average (arithmetic mean) of five numbers is 25. After one of the numbers is removed,
the average (arithmetic mean) of the remaining numbers is 31. What number has been
removed?
A. 1
B. 6
C. 11
D. 24
60. E. It cannot be determined from the information given.
Solution;
sum of 5 numbers=5*25=125
After one number is removed,
sum of remaining 4 numbers=4*31=124
Hence 1 must have been removed.
So our answer is A.
102. C is a circle, L is a line, and P is a point on line L. If C, L and P are in the same plane and P
is inside C, how many points do C and L have in common?
A. 0
B. 1
C. 2
D. 3
E. 4
Solution;
L
P
C
Hence our answer is 2.
103. A board of length L feet is cut into two pieces such that the length of one piece is 1 foot
more than twice the length of the other piece. Which of the following is the length, in feet, of
the longer piece?
A. (L+2)/2
B. (2L+1)/2
C. (L-1)/3
D. (2L+3)/3
E. (2L+1)/3
61. Solution;
L1+L2=L
L2=L-L1
L1=2L2+1 (assuming L1 is longer)
L1=2(L-L1)+1=2L-2L1+1
3L1=2L+1
L1=(2L+1)/3
Hence our answer is E.
104. In the sunshine, an upright pole 12 feet tall is casting a shadow 8 feet long. At the same
time, a nearby upright pole is casting a shadow 10 feet long. If the lengths of the shadows are
proportional to the heights of the poles, what is the height, in feet, of the taller pole?
A. 10
B. 12
C. 14
D. 15
E. 18
Solution;
12 ft x
8 ft 10 ft
x/12=10/8
x=10/8*12=10/2*3=15 ft
Hence our answer is D.
105. List R:28, 23, 30, 25, 27
List S:22, 19, 15, 17, 20
Which of the following is true about List R and List S?
62. A. The first quartile of List S is greater than that of List R.
B. The median of List R is less than that of list S.
C. The mean of List S is greater than that of list R.
D. The standard deviation of List R is equal to that of list S.
E. The range of List R is greater than that of List S.
Solution;
List R:23,25,27,28,30
List S:15,17,19,20,22
1st quartile of List R=(5+1)th/4=6/4=1.5th item=mean of 1st and 2nd items=(23+25)/2=24
2nd quartile of List S=1.5th item=(15+17)/2=16
That means 1st quartile of List R is greater. Eliminate A.
Median of list R=27
Median of list S=19
That means median of list R is greater than that of list S. Eliminate B.
Mean of list R=(23+25+27+28+30)/5=26.6
Mean of list S=(15+17+19+20+22)/5=18.6
If you see the two lists carefully, you can see each term of list R is greater than that of list S and
the number of elements are equal in both lists. So mean of list R must be greater.
That means mean of list R is greater than that of list S. Eliminate C.
square of deviation for list R={(23-26.6)2
+(25-26.6)2
+(27-26.6)2
+(28-26.6)2
+(30-26.6)2
}/5
={3.62
+1.62
+0.42
+1.42
+3.42
}/5
square of deviation for list S={(15-18.6)2
+(17-18.6)2
+(19-18.6)2
+(20-18.6)2
+(22-18.6)2
}/5
={3.62
+1.62
+0.42
+1.42
+3.42
}/5
That means their standard deviations are equal. So our answer is D.
If you look at the two lists carefully, you can see the differences between any two consecutive
terms are same for both lists.
So without calculating, we can say standard deviations of the two lists are equal.
Range of list R=30-23=7
Range of list S=22-15=7
That means their range are equal.
106. If an ant runs randomly through an enclosed circular field of radius 2 feet with an inner
circle of 1 foot, what is the probability that the ant will be in the inner circle at any one time?
63. A. 1/8
B. 1/6
C. 1/4
D. 1/2
E. 1
Solution;
P(ant being in the inner circle)=area of inner circle/total area=3.14*12
/3.14*22
=1/4
Hence our answer is C.
107. In the triangle above, x is equal to
A. 12
B. 16
C. 15
D. 10
E. none of these
Solution;
64. x/20=12/15
x=12*20/15=16
Hence our answer is B.
108. The number of men in a certain class exceeds the number of women by 7. If the number of
men is 5/4 of the number of women, how many men are there in the class?
A. 21
B. 28
C. 35
D. 42
E. 63
Solution;
M-W=7
M=5W/4
So 5W/4-W=7
W/4=7
W=28
So our answer is B.
109. The volume of a cube is less than 25, and the length of one of its edges is a positive integer.
What is the largest possible value for the total area of the six faces?
A. 1
B. 6
C. 24
D. 54
E. 150
Solution;