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SLIDESMANIA
SOALAN PILIHAN TRIAL
SPM 2022
MODUL BOOSTER
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E
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N
FE
B
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SLIDESMANIA
Rajah 8 menunjukkan sektor OJKL dan sektor OMN masing-masing dengan pusat
sepunya O.
Figure 8 shows the OJKL sector and the OMN with a common center O respectively
Hitung/calculate
(a) perimeter, dalam cm, seluruh rajah itu
the perimeter, the whoe diagram in cm
80°
50°
5 cm
M
N
P
L
K
J
O
Rajah 8
Perimeter = arc JKL + LM + arc MN + NO +
OJ
=
230
360
× 2 ×
22
7
× 10 + 5 +
50
360
× 2 ×
22
7
× 15 + 15 + 10
63
16
83

K1
N1
REMEMBER!!!!!
arc = 2   j
K1
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C
D
E
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N
FE
B
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AU
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SE
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NO
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DE
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SLIDESMANIA
Rajah 8 menunjukkan sektor OJKL dan sektor OMN masing-masing dengan pusat
sepunya O.
Figure 8 shows the OJKL sector and the OMN with a common center O respectively
Hitung/calculate
(a) luas, dalam cm2, Kawasan berlorek
the area cm2, of the shaded region
80°
50°
5 cm
M
N
P
L
K
J
O
Rajah 8
Area LPNM=area ONM - area OPL
Area shaded region=area OLKJ-area LPNM
50
360
×
22
7
× 152 −
230
360
×
22
7
× 102
+
=
6875
126
12650
63
+
50
360
×
22
7
× 102
6875
126
6875
126
=
3575
14
=255.36
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
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NO
V
DE
C
SLIDESMANIA
a)Perimeter seluruh rajah/perimeter whole
diagram.
perimeter = 34
.5
Jawapan:
Arc RQ+QP+arc PTS+SR
(
𝟗𝟎
𝟑𝟔𝟎
× 𝟐 ×
𝟐𝟐
𝟕
× 𝟕) +3.5
+(
𝟐𝟕𝟎
𝟑𝟔𝟎
× 𝟐 ×
𝟐𝟐
𝟕
× 𝟑. 𝟓) + 3.5
A
B
C
D
E
F
G
JA
N
FE
B
MA
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AP
R
MA
Y
JU
N
JU
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AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
b)Luas kawasan berlorek/area shaded region
luas kws berlorek/ area of shaded region
= 61 .25
270
360
× 2 ×
22
7
× 3.52
Area STP+area ORQ - area triangle OPS
+
90
360
×
22
7
× 72
-
1
2
× 3.5 × 3.5
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B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
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NO
V
DE
C
SLIDESMANIA
a) LUAS KAWASAN BERLOREK
Luas PQRS – LUAS LENGKOK PTQ + LUAS
LENGKOK PTU
7 × 10 −
90
360
×
22
7
(7)2+
30
360
×
22
7
× (7)2
70 - 38
1
2
+ 12
5
6
= 44
1
3
7
7
b) PERIMETER KAWASAN BERLOREK
PU+ pjg Lengkok UT+TS +SR+RQ+pjg lengkok QT
7+ 30
360
× 2 ×
22
7
(7) +3+7+10+ 90
360
× 2 ×
22
7
(7)
= 48.67
1 1 1
1
1
1
1
1
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B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
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MA
Y
JU
N
JU
L
AU
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SE
P
OC
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NO
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DE
C
SLIDESMANIA
SLIDESMANIA
RANGKAIAN TEORI GRAF
GRAPH NETWORK THEORY
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B
C
D
E
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JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
SLIDESMANIA
Graf mudah/
simple graph
R
U
Q
T
P
S
V
W
2 3
1
4
5
6
V
E
Graf yang tidak mengandungi
gelung atau berbilang
tepi
A graph that does not contain
loops or multiple edges
- Bilangan darjah ialah 2E
- The number of degrees is 2E
Ʃd(V) = 2n(E)
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
SLIDESMANIA
Graf Berbilang tepi dan gelung
Multi-edge and loop graphs
A
B
E D
C
Gelung/loop
Berbilang tepi/multiple edges
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
SLIDESMANIA
Contoh
2 3
1
4
5
6
Bagi setiap graf, tentukan
(i) V dan n(V)
(ii) E dan n(E)
(iii) Bilangan darjah
1
V = {1, 2, 3, 4, 5, 6 }
n(V) = 6
E = {(1,2),(1,6),(2,3),(2,5),(3,4),(3,5),(4,5),(5,6) }
n(E) = 8
d(1) = 2
d(2) = 3
d(3) = 3
d(4) = 2
d(5) = 4
d(6) = 2
Jumlah = 16
Ʃd(V) = 2n(E)
= 2 × 8
= 16
V= vertex/bucu E=Edge/tepi d= degree/darjah
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
SLIDESMANIA
A
B
E D
C
V = {A, B, C, D, E }
n(V) = 5
E = {(A,B), (A,B), (A, E), (B,C), (B,D), (B,E), (C,C), (C,D), (D,E), (D,E)}
n(E) = 10
d(A) = 3
d(B) = 5
d(C) = 4
d(D) = 4
d(E) = 4
Jumlah = 20
Ʃd(V) = 2n(E)
= 2 × 10
= 20
Bilangan darjah setiap
gelung ialah 2
Bagi setiap graf, tentukan
(i) V dan n(V)
(ii) E dan n(E)
(iii) Bilangan darjah
Contoh
2 V= vertex/bucu E=Edge/tepi d= degree/darjah
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
SLIDESMANIA
Lukis graf yang mempunyai gelung dan berbilang tepi bagi bilangan darjah
yang diberikan
Draw a graph that has loops and multiple edges for the given number of
of degrees
a) 3, 3, 4 b) 2, 2, 4,6, 6
𝑛 𝑉 = 3 𝑉 = {𝐴, 𝐵, 𝐶}
3+ 3+4 =
10
Ʃd(V) = 2n(E)
10 = 2𝑛 𝐸
𝑛 𝐸 = 5
•
•
•
A
C
B
example
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
SLIDESMANIA
Pokok/ Tree Graf mudah tanpa gelung dan berbilang tepi
A simple graph without loops and multiple
edges
Semua bucu mesti berkait dan setiap pasangan bucu dikaitkan oleh
satu tepi sahaja
All vertices must be connected and every pair of vertices is linked by
one edge only
Bilangan tepi = bilangan bucu – 1
Number of edges = number of vertices –
1
Kenalpasti pokok atau bukan pokok daripada rajah-rajah di bawah
Identify the tree or not from the diagrams below
a) n(E) = 4
n(V) = 4
n(E) ≠ 𝑛 𝑉 − 1
Bukan pokok
contoh
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
SLIDESMANIA
Kenalpasti pokok atau bukan pokok daripada rajah-rajah di bawah
Identify the tree or not from the diagrams below
b)
Graf mudah tanpa gelung dan berbilang tepi
A simple graph without loops and multiple edges
Semua bucu mesti berkait dan setiap pasangan bucu dikaitkan oleh satu tepi sahaja
All vertices must be connected and every pair of vertices is linked by one edge only
Bilangan tepi = bilangan bucu – 1
Number of edges = number of vertices – 1
n(E) = 7
n(V) = 6
n(E) ≠ 𝑛 𝑉 − 1
Bukan pokok
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
SLIDESMANIA
Pokok/ Tree
• Graf mudah tanpa gelung dan berbilang tepi
• A simple graph without loops and multiple edges
• Semua bucu mesti berkait dan setiap pasangan bucu dikaitkan oleh satu
• tepi sahaja
• All vertices must be connected and every pair of vertices is linked by one
• edge only
• Bilangan tepi = bilangan bucu – 1
• Number of edges = number of vertices – 1
c)
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
SLIDESMANIA
Pokok/ Tree
• Graf mudah tanpa gelung dan berbilang tepi
• A simple graph without loops and multiple edges
• Semua bucu mesti berkait dan setiap pasangan bucu dikaitkan oleh satu
• tepi sahaja
• All vertices must be connected and every pair of vertices is linked by one
• edge only
• Bilangan tepi = bilangan bucu – 1
• Number of edges = number of vertices – 1
pokok
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
SLIDESMANIA
d)
Pokok/ Tree
• Graf mudah tanpa gelung dan berbilang tepi
• A simple graph without loops and multiple edges
• Semua bucu mesti berkait dan setiap pasangan bucu dikaitkan oleh satu
• tepi sahaja
• All vertices must be connected and every pair of vertices is linked by one
• edge only
• Bilangan tepi = bilangan bucu – 1
• Number of edges = number of vertices – 1
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
SLIDESMANIA
Pokok/ Tree
• Graf mudah tanpa gelung dan berbilang tepi
• A simple graph without loops and multiple edges
• Semua bucu mesti berkait dan setiap pasangan bucu dikaitkan oleh satu
• tepi sahaja
• All vertices must be connected and every pair of vertices is linked by one
• edge only
• Bilangan tepi = bilangan bucu – 1
• Number of edges = number of vertices – 1
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
SLIDESMANIA
Graf mudah/
simple graph
R
U
Q
T
P
S
V
W
2 3
1
4
5
6
V
E
Graf Berbilang tepi dan gelung
Multi-edge and loop graphs
A
B
E D
C
Gelung/loop
Berbilang tepi/multiple edges
Graf mudah/A simple graph
- Graf yang tidak
mengandungi
gelung atau berbilang tepi
A graph that does not contain
loops or multiple edges
- Bilangan darjah ialah 2E
- The number of degrees is 2E
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
SLIDESMANIA
2 3
1
4
5
6
Bagi setiap graf, tentukan
(i) V dan n(V)
(ii) E dan n(E)
(iii) Bilangan darjah
1
V = {1, 2, 3, 4, 5, 6 }
n(V) = 6
E = {(1,2),(1,6),(2,3),(2,5),(3,4),(3,5),(4,5),(5,6) }
n(E) = 8
d(1) = 2
d(2) = 3
d(3) = 3
d(4) = 2
d(5) = 4
d(6) = 2
Jumlah = 16
Ʃd(V) = 2n(E)
= 2 × 8
= 16
Contoh :
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
SLIDESMANIA
A
B
E D
C
V = {A, B, C, D, E }
n(V) = 5
E = {(A,B), (A,B), (A, E), (B,C), (B,D), (B,E), (C,C), (C,D), (D,E), (D,E)}
n(E) = 10
d(A) = 3
d(B) = 5
d(C) = 4
d(D) = 4
d(E) = 4
Jumlah = 20
Ʃd(V) = 2n(E)
= 2 × 10
= 20
Bilangan darjah
setiap gelung ialah
2
Bagi setiap graf, tentukan
(i) V dan n(V)
(ii) E dan n(E)
(iii) Bilangan darjah
2
Contoh :
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
JA
N
{(S,R),(R,Q),(R,Q),(P,Q),(P,P), (S,P)}
d(P)= 4
d(Q)= 3
d(R)= 3
d(S)= 2
Bukan graf mudah kerana terdapat gelung atau berbilang tepi
Not a simple graph because there are loops or multiple edges
1
1 1
1
1
1
1
1 1
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
JA
N
GARIS LURUS
STRAIGHT LINE
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
JA
N
𝑚𝑅𝑆=-
𝑝𝑖𝑛𝑡𝑎𝑠𝑎𝑛 𝑦
𝑝𝑖𝑛𝑡𝑎𝑠𝑎𝑛 𝑥
= −
2
4
= -
1
2
Koordinat/coordinate
P =(0,6)
𝑦 = 𝑚𝑥 + 𝑐
6 = −
1
2
(0) +𝑐
𝑐 = 6
Persamaan/equation PQ : 𝑦 = −
1
2
𝑥 + 6
b) Gantikan (2,5) dalam 𝑦 = 𝑚𝑥 + 𝑐
LHS
𝑦 = −
1
2
(2) + 6
y= 5
Ya titik (2,5) berada pada garis PQ
Yes, point (2,5) is on the line PQ
LHS = RHS
1
1
1
1
1
𝑚𝑅𝑆=-
𝑦 𝑖𝑛𝑡𝑒𝑟𝑐𝑒𝑝𝑡
𝑥 𝑖𝑛𝑡𝑒𝑟𝑐𝑒𝑝𝑡
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
JA
N
2𝑦 = 5𝑥 + 7
𝑦 =
5
2
𝑥+
7
2
𝑚 =
5
2
−3,4 𝑑𝑎𝑛 (−1,9) kirakan kecerunan
𝑚 =
9 − 4
−1 − (−3)
𝑚 =
5
2
Kedua-dua garis mempunyai kecerunan yang sama, maka kedua-dua garis tersebut adalah selari
Both lines have the same gradient, so the two lines are parallel
1
1
1
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
UBAHAN
VARIATION
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
JA
N
𝑦 𝛼 𝑝𝑎
𝑥𝑏
𝑦 𝛼 𝑝3
𝑥2 𝑎 = 3 𝑏 = 2
𝑦 𝛼 𝑥2
b)
𝑦 = 𝑘 𝑥2
4 = 𝑘 (
1
2
)2
4 = 𝑘 (
1
4
)
4x4 = 𝑘
16 = 𝑘
𝑦 = 16 𝑥2
64 = 16 𝑥2
64
16
= 𝑝2
4 = 𝑝2
2 = 𝑝
1 1
1
1
1
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
JA
N
𝑗𝛼
𝑟
3
𝑚
𝑗 = 𝑘
𝑟
3
𝑚
9 = 𝑘
6
3
8
9 = 𝑘
6
2
9 = 3𝑘
3 = 𝑘
𝑗 = 3
4
3
64 𝑗 = 3
64
64
Cube root of m
1
1
1
1
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
JA
N
MATRIKS
MATRICES
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
JA
N
(4 2 + 𝑝(0) 4 5 + 7𝑝)
=(8 −15)
20 + 7𝑝 = −15 7𝑝 = −15 − 20
7𝑝 = −35
𝑝 = −5
4 −2
3 −1
=
1
4 −1 − 3(−2)
−1 2
−3 4
=
1
2
−1 2
−3 4
=
−
1
2
1
−3
2
2
≈ −
𝑘 1
3
2
𝑣
𝑘 = −
1
2 v = 2
1
1 1
Songsangkan
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
JA
N
4 −2
3 −1
𝑥
𝑦 =
1
3
=
1
4 −1 − 3(−2)
−1 2
−3 4
𝑥
𝑦
1
3
𝑥 =
5
2
𝑦 =
9
2
1
1
1
1
6𝑥 + 4𝑦 = 11
2𝑥 + 3𝑦 = 6
6 4
2 3
𝑥
𝑦 =
11
6
=
1
6 3 − 4(2)
3 −4
−2 6
𝑥
𝑦
11
6
x=RM0.90 y=RM1.40
Beza harga/ Price difference
= 1.40-0.9
= RM0.50
1
1
1
1
1
1
1
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
JA
N
4 5
1 2
𝑥
𝑦 =
41
14
=
1
4 2 − 5(1)
2 −5
−1 4
41
14
𝑥 = 4 𝑦 = 5
1
1
1
40𝑥 + 50𝑦 = 410
5𝑥 + 10𝑦 = 70
4𝑥 + 5𝑦 = 41
𝑥 + 2𝑦 = 14
1
1
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
JA
N
1 4
3
2
5
1,2,3 ∩1,5
P ∩ 𝑅`
1
1 4
3
2
5
P` ∪ (𝑄` ∩ 𝑅)
4,5 ∪ (1,2 ∩ 2,3,4)
4,5 ∪ 2
2,4,5
1
2
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
JA
N
L
X∩ 𝑌 z
X ∩ 𝑌 ∪ 𝑍
𝑍 ∪ (X ∩ 𝑌)
OR
2
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
JA
N
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
JA
N
8 -10
1 2 3 4
-4 -3 -2 -1 0
5
20
15
10
-5
-10
-15
-20
•
•
•
•
•
•
• •
-1.52
-5.5
y=13
x= 3.1
1 1
Uniform axes
P1
k2
All point plot correctly
N1
Smooth curve
1
1
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
JA
N
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
JA
N
1
1
1
1
1
1
1
1
1
1
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
JA
N
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
JA
N
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
Isipadu gabungan
Isipadu Prisma+ isipadu semi selinder
Luas keratan rentas x pjg +
1
2
𝜋jt
1
2
× (18 + 10) × 6 × 7+
1
2
×
22
7
× 3.5 × 6
588+155.5
703.5
1 1 1
1
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
JA
N
Benar/True
Akas : Jika 3
𝑥 𝑖𝑎𝑙𝑎ℎ 𝑖𝑛𝑡𝑒𝑔𝑒𝑟, 𝑚𝑎𝑘𝑎 𝑥 𝑖𝑎𝑙𝑎ℎ 𝑘𝑢𝑎𝑠𝑎 3 𝑠𝑒𝑚𝑝𝑢𝑟𝑛𝑎
Converse: If 3
𝑥 is a integer, then x is perfct power of 3
Songsangan: Jika x bukan kuasa 3 sempurna maka 3
𝑥 bukan integer
Inverse: If x is not a perfect power of 3 then ∛(𝑥 ) is not an integer
Benar/true
Benar/True
n(n-1) where n=1,2,3…
6 ialah nombor genap/ 6 is an even number
y ialah nombor positif/ y is square number
𝑠𝑖𝑛30° ≠ 0.5
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
JA
N
1 × 82 + 4 × 81 + 80
Matematik =
Sejarah = 25 × 1 + 24 × 0 + 23 × 1 + 22 × 1 + 21 × 0 + 20 × 1
= 98
= 45
Beza= 98 -45
=53
1
1
1
1
1
1
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
JA
N
1
1
1
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
F
Notebook F
A
B
C
D
E
F
G
JA
N
FE
B
MA
R
AP
R
MA
Y
JU
N
JU
L
AU
G
SE
P
OC
T
NO
V
DE
C
SLIDESMANIA
G
Notebook G

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