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System Properties
Presented by
Dr. Amany AbdElSamea
1
Outline
• Interconnections of System
• Classification of Systems
• Systems Example
• System Properties
2
Systems
3
Block Diagram Representation
4
Interconnection of Systems
5
Classification of Systems
6
Signal Processing Systems
7
Communication Systems
8
Control System
9
System Properties
 Memory
 Causality
 Stability
 Invertibility
 Time invariant
 Linearity
10
• The system is memoryless if it doesn’t need memory to store information from
past or future.
• The system is memoryless arbitrarily if the output at any time t0 depend on the
input at that time not past, not future.
• A System that is not memoryless is said to have memory.
• Although simple, a memoryless system is not very flexible. Since its current
output value cannot rely on past or future values of the input.
Static (Memoryless) and Dynamic
(Memory) system
11
Examples
12
Examples cont.,
13
Examples cont.,
14
Examples cont.,
15
Causal and Non-Causal System
Causal System:
A system is said to be causal if the response of a system at any instant of time depends only
on the present input, past input and past output but does not depend upon the future
input and future output
Ex: y(t) = 3x(t) + x(t-1)
Non-Causal system:
A system is said to be non-causal if the response of a system at any instant of time depends
on the future input and also on the present input, past input , past output.
Ex: y(t) = x(t+2) + x(t-1)
y(t) = x(-t) + x(t+4)
A memoryless system is always causal, although the converse is not necessarily true.
Note: online system (e.g. telephone) is causal
offline system (e.g. music) is non-causal
16
Examples
17
Examples
18
Invertibility
19
The System is invertible if the input signals can be generated from the output signals
Mathematically, the system is invertible if every element of output is corresponding to
only one element of input. (It is one to one)
If output is corresponding to more input so it is not invertible. 1
4
5
3
2
9
X(t) Y(t)
Examples cont.,
20
Ex: Y (t) = sin (x(t))
Input is an argument of sine function
X(t) = 0 y=sin (0) =0
X(𝝅) = 𝝅 y= sin (𝝅) =0
We get y for two inputs so it is not one to one so it is not invertible
Ex: Y (t) = 3 x(t) + 5
Y (t) – 5 = 3 X(t)
X(𝐭) =
𝐲 𝐭 −𝟓
𝟑
The system is invertible since the input signal is generated from the output
Time-invariant and Time-variant
Systems
21
• A system is said to be time invariant if the time shifts in the input signals
results in corresponding time shift in the output signal
• The input and output characteristics do not change with time. So if you repeat
the same test over time, you will get same output
• For a continuous time system
f[x(t1-t2)] = y(t1-t2)
• For a discrete time system,
F [x(n-k)] = y (n-k)
• If the above relation does not satisfy, then the system is said to be a time
variant system
• Practically speaking. Compared to time-varying systems. Time-invariant
systems are much easier to design and analyze, since their behavior does not
change with respect to time.
Time-invariant and Time-variant
Systems cont.,
22
System Delay by t0
X(t) Y(t) Y(t-t0
)
Delay by t0 System
X(t-t0) Y(t)
Y(t)= Y(t-t0)
Y(t)≠ Y(t-t0)
Time-invariant System
Time-variant System
Time Invariant Test
1- Shift input by T  Y(t)=x(t-t0)
2- Shift output by T  y(t-t0)
3- If Y(t)= Y(t-t0)
So the system is time invariant
Examples
23
Ex: Determine whether the following system is
time invariant or not:
Y (t) = x(2t)
Solution:
1- Y(t)= x(2t-T)
2- Y(t-T) = x(2(t-T))= x(2t-2T)
Y(t) ≠ Y(t-T)
Hence the system is not time invariant
Ex: Is the system is time invariant?
Y (t) = sin (x(t))
Solution:
1- Y(t)= sin (x(t-T))
2- Y(t-T) = sin (x(t-T))
Y(t)= Y(t-T)
Hence the system is time invariant
Time Invariant Test
1- Shift input by T  Y(t)=x(t-T)
2- Shift output by T  Y(t-T)
3- If Y(t)= Y(t-T)
So the system is time invariant
Examples cont.,
24
Ex: Determine whether the following system is
time invariant or not:
Y (t) = t x(t)
Solution:
1- Y (t) = t x(t-T)
2- Y(t-T) = (t-T) x(t-T)
Y (t) ≠ Y(t-T)
Hence the system is not time invariant
Ex: Determine whether the following system is time invariant or not
Y (t) = sin (x(t))
Solution:
1- Y (t) = sin (x(t-T))
2- Y(t-T) = sin (x(t-T))
Y (t) = y(t-T)
Hence the system is time invariant
Time Invariant Test
1- Shift input by T  Y(t)=x(t-T)
2- Shift output by T  Y(t-T)
3- If Y(t)= Y(t-T)
So the system is time invariant
Additivity, Homogeneity, and
Linearity
25
Linear and Non-linear System
26
• A system is said to be linear if it satisfy the superposition principle.
• Superposition principle depends on two laws
- Law of Additivity
- Law of homogeneity
1- Law of additivity (LoA)
It states that the weighted sum of input signal be equal to the weighted sum of output
signal corresponding to each of the individual input signal.
1- Apply X1(t)  y1(t)
2- Apply X2(t)  y2(t)
3- Apply (X1(t) + X2(t))  if output is (y1(t) + y2(t)) so the system follow the LoA
2- Law of Homogenity (LoH)
1- Apply k Y(T)
2- Apply k X(t)
If k x(t) = k Y(t) so if follow the law of homogeneity
If it satisfy 1 and 2 so the system is linear
Examples
27
Ex: Determine whether the following system is linear or not:
Y (t) = x(sint)
Solution:
1- Law of Additivity
Y1(t) = X1(sin t)
Y2(t) = X2(sin t)
Y1(t) + Y2(t) = X1(sin t) + X2(sin t)
X1(t) +X2(t) system  X1(sin t) + X2(sin t)
X1(t)+X2(t) = Y1(t) + Y2(t) so the system follow the law of Additivity
2- Law of Homogeneity
K Y(t) = k X (sin t)
K X(t)  system  k X(sin t)
K X(t) = k Y(t) so the system follow the law of Homogeneity
Since it follows Law of Additivity and Law of Homogeneity so it follow the law of
superposition so the system is linear
Stable and Non-Stable System
28
• Stability is very critical in reality because if the system is not stable, it will
be out of control.
• A system is said to be stable (Bounded input bounded output (BIBO stable)
when every bounded input produces bounded output. We mean by
bounded that the signal is limited to a finite range.
• Otherwise the system is not stable
Bounded signal Not Bounded signal
Ex : Determine whether the following system is stable or not
Y(t) =x(2t)
Solution:
If x(t) is bounded
X(2t) is bounded
Since 2 is time scaling function which just change signal in time direction not
amplitude direction
So y(t) is bounded so the system is stable
Ex :
Y(t) =x(t)/t
Solution:
At t  0 y=x(t)/0  Infinity
Y(t) is not bounded so the system is not stable
Examples
Questions

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Lect2-SignalProcessing (1).pdf

  • 2. Outline • Interconnections of System • Classification of Systems • Systems Example • System Properties 2
  • 10. System Properties  Memory  Causality  Stability  Invertibility  Time invariant  Linearity 10
  • 11. • The system is memoryless if it doesn’t need memory to store information from past or future. • The system is memoryless arbitrarily if the output at any time t0 depend on the input at that time not past, not future. • A System that is not memoryless is said to have memory. • Although simple, a memoryless system is not very flexible. Since its current output value cannot rely on past or future values of the input. Static (Memoryless) and Dynamic (Memory) system 11
  • 16. Causal and Non-Causal System Causal System: A system is said to be causal if the response of a system at any instant of time depends only on the present input, past input and past output but does not depend upon the future input and future output Ex: y(t) = 3x(t) + x(t-1) Non-Causal system: A system is said to be non-causal if the response of a system at any instant of time depends on the future input and also on the present input, past input , past output. Ex: y(t) = x(t+2) + x(t-1) y(t) = x(-t) + x(t+4) A memoryless system is always causal, although the converse is not necessarily true. Note: online system (e.g. telephone) is causal offline system (e.g. music) is non-causal 16
  • 19. Invertibility 19 The System is invertible if the input signals can be generated from the output signals Mathematically, the system is invertible if every element of output is corresponding to only one element of input. (It is one to one) If output is corresponding to more input so it is not invertible. 1 4 5 3 2 9 X(t) Y(t)
  • 20. Examples cont., 20 Ex: Y (t) = sin (x(t)) Input is an argument of sine function X(t) = 0 y=sin (0) =0 X(𝝅) = 𝝅 y= sin (𝝅) =0 We get y for two inputs so it is not one to one so it is not invertible Ex: Y (t) = 3 x(t) + 5 Y (t) – 5 = 3 X(t) X(𝐭) = 𝐲 𝐭 −𝟓 𝟑 The system is invertible since the input signal is generated from the output
  • 21. Time-invariant and Time-variant Systems 21 • A system is said to be time invariant if the time shifts in the input signals results in corresponding time shift in the output signal • The input and output characteristics do not change with time. So if you repeat the same test over time, you will get same output • For a continuous time system f[x(t1-t2)] = y(t1-t2) • For a discrete time system, F [x(n-k)] = y (n-k) • If the above relation does not satisfy, then the system is said to be a time variant system • Practically speaking. Compared to time-varying systems. Time-invariant systems are much easier to design and analyze, since their behavior does not change with respect to time.
  • 22. Time-invariant and Time-variant Systems cont., 22 System Delay by t0 X(t) Y(t) Y(t-t0 ) Delay by t0 System X(t-t0) Y(t) Y(t)= Y(t-t0) Y(t)≠ Y(t-t0) Time-invariant System Time-variant System Time Invariant Test 1- Shift input by T  Y(t)=x(t-t0) 2- Shift output by T  y(t-t0) 3- If Y(t)= Y(t-t0) So the system is time invariant
  • 23. Examples 23 Ex: Determine whether the following system is time invariant or not: Y (t) = x(2t) Solution: 1- Y(t)= x(2t-T) 2- Y(t-T) = x(2(t-T))= x(2t-2T) Y(t) ≠ Y(t-T) Hence the system is not time invariant Ex: Is the system is time invariant? Y (t) = sin (x(t)) Solution: 1- Y(t)= sin (x(t-T)) 2- Y(t-T) = sin (x(t-T)) Y(t)= Y(t-T) Hence the system is time invariant Time Invariant Test 1- Shift input by T  Y(t)=x(t-T) 2- Shift output by T  Y(t-T) 3- If Y(t)= Y(t-T) So the system is time invariant
  • 24. Examples cont., 24 Ex: Determine whether the following system is time invariant or not: Y (t) = t x(t) Solution: 1- Y (t) = t x(t-T) 2- Y(t-T) = (t-T) x(t-T) Y (t) ≠ Y(t-T) Hence the system is not time invariant Ex: Determine whether the following system is time invariant or not Y (t) = sin (x(t)) Solution: 1- Y (t) = sin (x(t-T)) 2- Y(t-T) = sin (x(t-T)) Y (t) = y(t-T) Hence the system is time invariant Time Invariant Test 1- Shift input by T  Y(t)=x(t-T) 2- Shift output by T  Y(t-T) 3- If Y(t)= Y(t-T) So the system is time invariant
  • 26. Linear and Non-linear System 26 • A system is said to be linear if it satisfy the superposition principle. • Superposition principle depends on two laws - Law of Additivity - Law of homogeneity 1- Law of additivity (LoA) It states that the weighted sum of input signal be equal to the weighted sum of output signal corresponding to each of the individual input signal. 1- Apply X1(t)  y1(t) 2- Apply X2(t)  y2(t) 3- Apply (X1(t) + X2(t))  if output is (y1(t) + y2(t)) so the system follow the LoA 2- Law of Homogenity (LoH) 1- Apply k Y(T) 2- Apply k X(t) If k x(t) = k Y(t) so if follow the law of homogeneity If it satisfy 1 and 2 so the system is linear
  • 27. Examples 27 Ex: Determine whether the following system is linear or not: Y (t) = x(sint) Solution: 1- Law of Additivity Y1(t) = X1(sin t) Y2(t) = X2(sin t) Y1(t) + Y2(t) = X1(sin t) + X2(sin t) X1(t) +X2(t) system  X1(sin t) + X2(sin t) X1(t)+X2(t) = Y1(t) + Y2(t) so the system follow the law of Additivity 2- Law of Homogeneity K Y(t) = k X (sin t) K X(t)  system  k X(sin t) K X(t) = k Y(t) so the system follow the law of Homogeneity Since it follows Law of Additivity and Law of Homogeneity so it follow the law of superposition so the system is linear
  • 28. Stable and Non-Stable System 28 • Stability is very critical in reality because if the system is not stable, it will be out of control. • A system is said to be stable (Bounded input bounded output (BIBO stable) when every bounded input produces bounded output. We mean by bounded that the signal is limited to a finite range. • Otherwise the system is not stable Bounded signal Not Bounded signal
  • 29. Ex : Determine whether the following system is stable or not Y(t) =x(2t) Solution: If x(t) is bounded X(2t) is bounded Since 2 is time scaling function which just change signal in time direction not amplitude direction So y(t) is bounded so the system is stable Ex : Y(t) =x(t)/t Solution: At t  0 y=x(t)/0  Infinity Y(t) is not bounded so the system is not stable Examples