BAHAGIANA
1)
I. Imej untuk b : { p,q}
II. Objek untuk p :{a,b}
III. Domain f :{a,b,c}
IV. Julat f :{p,q,r}
V. Jenis hubungan :Banyak kepada Satu
2) Fungsipolynomial berdarjah juga dikenali sebagai fungsikubik.
3)
𝑓(𝑥) =
1
x2−9
𝑓(𝑥) =
1
x2−32
𝑓(𝑥) =
1
(x+3)(x−3)
(x+3)(x-3)≠0
X=-3
X=3
4)
(a) domain f = 2x +1 ≥ 0
= 2x+1 ≥ -1
= 2 ≥ −
1
2
Df = {x|x£ R,x ≥ -
1
2
}
(b)
Julat f=y =√2𝑥 + 1
𝑦2
= 2𝑥 + 1
2x+1 =𝑦2
X= 𝑦2−1
2
x≥ −
1
2
−
1
2
=
𝑦2−1
2
-1=𝑦2
− 1
𝑦 ≥ 0
Jf = {𝑦|𝑦 ∈ 𝑅, 𝑦 ≥ 0}
5)
𝐾2
+ (√3)2
= 22
𝐾2
= 4 − 3
K =1
K =√1
= 1
tan 𝑄 =
1
√3
BAHAGIANB
1(a)
F([
2
3
] = 2 [−
2
3
] + 3
= −
4
3
+ 3
= −
4+9
3
= -
5
3
(b)
2𝑘 + 3 = 𝑥
2𝑘 = 𝑥 − 3
𝑘 =
x−3
2
𝑓−1
(𝑥) =
x−3
2
(c)
𝑘 =
𝑘−3
2
𝑘 =
2−3
2
𝑘 = −
1
2
𝑓−1
(2) = −
1
2
2)
𝑓𝑔( 𝑥) = 𝑓(10𝑥 − 12)
= −7(10𝑥 − 12) − 5
= −70𝑥 + 84 − 5
= −70𝑥 + 79
3)
( 𝑥)1𝑥 − 2| + 2
𝑥 − 2 ≥ 0
𝑥 ≥ 0
𝐽𝑓 {𝑥 ∈ 𝑅, 𝑓(𝑥) ≥ 3}
4)
𝑥 → 1 → (1 + 2)3
(12
− 6)
(27)(−5)
−135
7)
𝑐(2) + 7 = 𝑐(22) − 5
2(2) + 7 = 4𝑐 − 5
7 + 5 = 4𝑐 − 2𝑐
12 = 2𝑐
𝑐 =
12
2
𝑐 = 6
Kalkulus bahagian a n b
Kalkulus bahagian a n b
Kalkulus bahagian a n b
Kalkulus bahagian a n b

Kalkulus bahagian a n b

  • 1.
    BAHAGIANA 1) I. Imej untukb : { p,q} II. Objek untuk p :{a,b} III. Domain f :{a,b,c} IV. Julat f :{p,q,r} V. Jenis hubungan :Banyak kepada Satu 2) Fungsipolynomial berdarjah juga dikenali sebagai fungsikubik. 3) 𝑓(𝑥) = 1 x2−9 𝑓(𝑥) = 1 x2−32 𝑓(𝑥) = 1 (x+3)(x−3) (x+3)(x-3)≠0 X=-3 X=3 4) (a) domain f = 2x +1 ≥ 0 = 2x+1 ≥ -1 = 2 ≥ − 1 2 Df = {x|x£ R,x ≥ - 1 2 }
  • 2.
    (b) Julat f=y =√2𝑥+ 1 𝑦2 = 2𝑥 + 1 2x+1 =𝑦2 X= 𝑦2−1 2 x≥ − 1 2 − 1 2 = 𝑦2−1 2 -1=𝑦2 − 1 𝑦 ≥ 0 Jf = {𝑦|𝑦 ∈ 𝑅, 𝑦 ≥ 0} 5) 𝐾2 + (√3)2 = 22 𝐾2 = 4 − 3 K =1 K =√1 = 1 tan 𝑄 = 1 √3
  • 3.
    BAHAGIANB 1(a) F([ 2 3 ] = 2[− 2 3 ] + 3 = − 4 3 + 3 = − 4+9 3 = - 5 3 (b) 2𝑘 + 3 = 𝑥 2𝑘 = 𝑥 − 3 𝑘 = x−3 2 𝑓−1 (𝑥) = x−3 2 (c) 𝑘 = 𝑘−3 2 𝑘 = 2−3 2 𝑘 = − 1 2 𝑓−1 (2) = − 1 2
  • 4.
    2) 𝑓𝑔( 𝑥) =𝑓(10𝑥 − 12) = −7(10𝑥 − 12) − 5 = −70𝑥 + 84 − 5 = −70𝑥 + 79 3) ( 𝑥)1𝑥 − 2| + 2 𝑥 − 2 ≥ 0 𝑥 ≥ 0 𝐽𝑓 {𝑥 ∈ 𝑅, 𝑓(𝑥) ≥ 3} 4) 𝑥 → 1 → (1 + 2)3 (12 − 6) (27)(−5) −135
  • 6.
    7) 𝑐(2) + 7= 𝑐(22) − 5 2(2) + 7 = 4𝑐 − 5 7 + 5 = 4𝑐 − 2𝑐 12 = 2𝑐 𝑐 = 12 2 𝑐 = 6