java programming language The attached A12.txt file which has 2 columns with the first column being the name of the employee and the second column holding their salary. Read the data into a 2 dimensional array of size 1,000 rows. Once the data is inside the 2-D array print out the unsorted contents to the screen only of the rows that are currently in-use. Sort the data using selection sort from lowest salary to highest salary ensuring the name continues to match up with the corresponding salary. For only the rows that are currently in-use, print the sorted array to the screen and save the sorted data to an output file named \"Sorted.txt\". Turn in A12.txt, .java file, and Sorted.txt all in 1 zip file into blackboard. Solution // Employee.java import java.io.*; import java.util.*; import java.io.PrintWriter; public class Employee { public static String[][] selectionSort(String[][] employeeDetails, int size) { for (int i = 0; i < size - 1; i++) { //System.out.println( Integer.parseInt(employeeDetails[i][1])); int index = i; for (int j = i + 1; j < size; j++) if ( Integer.parseInt(employeeDetails[j][1]) < Integer.parseInt(employeeDetails[index][1]) ) index = j; String temp = employeeDetails[index][1]; employeeDetails[index][1] = employeeDetails[i][1]; employeeDetails[i][1] = temp; temp = employeeDetails[index][0]; employeeDetails[index][0] = employeeDetails[i][0]; employeeDetails[i][0] = temp; } return employeeDetails; } public static void main(String[] args) { File inputFile = new File(\"A12.txt\"); // Check if file exists if (!inputFile.exists()) { System.out.println(\"File does not exist!\"); System.exit(1); } String[][] employeeDetails = new String[1000][2]; int size = 0; BufferedWriter output = null; try(BufferedReader bf = new BufferedReader(new InputStreamReader(new FileInputStream(inputFile)))) { String str; while ((str = bf.readLine()) != null) { String[] tokens = str.split(\" \"); employeeDetails[size][0] = tokens[0]; employeeDetails[size][1] = tokens[1]; size++; } // output file File file = new File(\"Sorted.txt\"); output = new BufferedWriter(new FileWriter(file)); output.write(\"Employee details\ Name\\tSalary\ \"); for (int i = 0; i < size ;i++ ) { output.write(employeeDetails[i][0] + \"\\t\" + employeeDetails[i][1] + \"\ \"); } employeeDetails = selectionSort(employeeDetails,size); output.write(\"\ \ Employee details\ Name\\tSalary\ \"); for (int i = 0; i < size ;i++ ) { output.write(employeeDetails[i][0] + \"\\t\" + employeeDetails[i][1] + \"\ \"); } output.close(); } catch (FileNotFoundException exception) { System.out.println(\"File not found.\"); exception.printStackTrace(); } catch (IOException exception) { System.out.println(\"IO error.\"); exception.printStackTrace(); } } } /* A12.txt Ayush 34531 John 2341 Eoin 345321 Sorted.txt Employee details Name Salary Ayush 34531 John 2341 Eoin 345321 Employee details Name Salary John 2341 Ayush 34531 Eoin 345321 */.

1. java programming language
The attached A12.txt file which has 2 columns with the first column being the name of the
employee and the second column holding their salary. Read the data into a 2 dimensional array
of size 1,000 rows. Once the data is inside the 2-D array print out the unsorted contents to the
screen only of the rows that are currently in-use. Sort the data using selection sort from lowest
salary to highest salary ensuring the name continues to match up with the corresponding salary.
For only the rows that are currently in-use, print the sorted array to the screen and save the sorted
data to an output file named "Sorted.txt". Turn in A12.txt, .java file, and Sorted.txt all in 1 zip
file into blackboard.
Solution
// Employee.java
import java.io.*;
import java.util.*;
import java.io.PrintWriter;
public class Employee
{
public static String[][] selectionSort(String[][] employeeDetails, int size)
{
for (int i = 0; i < size - 1; i++)
{
//System.out.println( Integer.parseInt(employeeDetails[i][1]));
int index = i;
for (int j = i + 1; j < size; j++)
if ( Integer.parseInt(employeeDetails[j][1]) < Integer.parseInt(employeeDetails[index][1]) )
index = j;
String temp = employeeDetails[index][1];
employeeDetails[index][1] = employeeDetails[i][1];
employeeDetails[i][1] = temp;
temp = employeeDetails[index][0];
employeeDetails[index][0] = employeeDetails[i][0];
employeeDetails[i][0] = temp;

2. }
return employeeDetails;
}
public static void main(String[] args)
{
File inputFile = new File("A12.txt");
// Check if file exists
if (!inputFile.exists())
{
System.out.println("File does not exist!");
System.exit(1);
}
String[][] employeeDetails = new String[1000][2];
int size = 0;
BufferedWriter output = null;
try(BufferedReader bf = new BufferedReader(new InputStreamReader(new
FileInputStream(inputFile))))
{
String str;
while ((str = bf.readLine()) != null)
{
String[] tokens = str.split(" ");
employeeDetails[size][0] = tokens[0];
employeeDetails[size][1] = tokens[1];
size++;
}
// output file
File file = new File("Sorted.txt");
output = new BufferedWriter(new FileWriter(file));
output.write("Employee details NametSalary ");
for (int i = 0; i < size ;i++ )
{
output.write(employeeDetails[i][0] + "t" + employeeDetails[i][1] + " ");
}
employeeDetails = selectionSort(employeeDetails,size);

3. output.write(" Employee details NametSalary ");
for (int i = 0; i < size ;i++ )
{
output.write(employeeDetails[i][0] + "t" + employeeDetails[i][1] + " ");
}
output.close();
}
catch (FileNotFoundException exception)
{
System.out.println("File not found.");
exception.printStackTrace();
}
catch (IOException exception)
{
System.out.println("IO error.");
exception.printStackTrace();
}
}
}
/*
A12.txt
Ayush 34531
John 2341
Eoin 345321
Sorted.txt
Employee details
Name Salary
Ayush 34531
John 2341
Eoin 345321
Employee details
Name Salary
John 2341

4. Ayush 34531
Eoin 345321
*/