Degrees
Sl.                                                    Level of
             Test                 Formula                                  of
No.                                                  Significance
                                                                        Freedom

                                 Chi Square Test
      Test            for                          As per given in
1     Goodness         of                          the question or        (n-1)
      Fit:                                         else 0.05.
                                  E=

      Test            for
      independence                                 As per given in
2.                                                 the question or      (r-1)(c-1)
      of attributes              E=
                                                   else 0.05.


                                       T-Test
                                                   As per given in
                                 t=
      Test for Single                              the question or
      Mean                                         else         0.05.
3                                                                         (n-1)
                                 S=                (Depends on the
                                                   type of tail of
                                                   test)
                                                   As per given in
                            t=
      Test            for                          the question or

      difference                                   else         0.05.
4                                                                       (m+n-2)
      mean                                         (Depends on the
                            S=                     type of tail of
                                                   test)

                                  t=               As per given in
      Test for Paired                              the question or
5                                                                         (n-1)
      t Test                                       else         0.05.
                                 S=
                                                   (Depends on the

PraveenKumar Keskar                                                               1
type of tail of
                                                   test)
                                        F – Test
                        f=    if,


                                       or                            (m-1,n-1)
     Test         for
6                                                          0.05.        or
     Variance
                        f=    if,                                    (n-1,m-1)




                                        Z – Test
     Test for Single
                              Z=                      0.05 = 1.96
7    mean                                                 Or            Nil
                                                      0.01 = 2.58

     Test         for
                             Z=                       0.05 = 1.96
8    difference    of                                     Or            Nil
     mean                                             0.01 = 2.58

     Test         for             Z=                  0.05 = 1.96
9                                                         Or            Nil
     proportion
                                                      0.01 = 2.58

                             Z=
     Test         for
                                                      0.05 = 1.96
10   difference    of                                     Or            Nil
     proportion                                       0.01 = 2.58
                             P=

                                       Run Test

                              Z=
                                                      0.05 = 1.96
11   Run Test                                             Or            Nil
                             E=                       0.01 = 2.58



PraveenKumar Keskar                                                           2
=




PraveenKumar Keskar       3

Hypothesis testing. (in table)

  • 1.
    Degrees Sl. Level of Test Formula of No. Significance Freedom Chi Square Test Test for As per given in 1 Goodness of the question or (n-1) Fit: else 0.05. E= Test for independence As per given in 2. the question or (r-1)(c-1) of attributes E= else 0.05. T-Test As per given in t= Test for Single the question or Mean else 0.05. 3 (n-1) S= (Depends on the type of tail of test) As per given in t= Test for the question or difference else 0.05. 4 (m+n-2) mean (Depends on the S= type of tail of test) t= As per given in Test for Paired the question or 5 (n-1) t Test else 0.05. S= (Depends on the PraveenKumar Keskar 1
  • 2.
    type of tailof test) F – Test f= if, or (m-1,n-1) Test for 6 0.05. or Variance f= if, (n-1,m-1) Z – Test Test for Single Z= 0.05 = 1.96 7 mean Or Nil 0.01 = 2.58 Test for Z= 0.05 = 1.96 8 difference of Or Nil mean 0.01 = 2.58 Test for Z= 0.05 = 1.96 9 Or Nil proportion 0.01 = 2.58 Z= Test for 0.05 = 1.96 10 difference of Or Nil proportion 0.01 = 2.58 P= Run Test Z= 0.05 = 1.96 11 Run Test Or Nil E= 0.01 = 2.58 PraveenKumar Keskar 2
  • 3.