1. Solved Problems
Problem 7.124:
The compressed-air tank AB has a 250mm outside diameter and an 8mm
wall thickness. It is fitted with a collar by which a 40-KN force F is applied
at B in the horizontal direction. Knowing that the gage pressure inside the
tank is 5-MPa. Determine the maximum normal stress and the maximum
shearing stress at point K.
Solution:
Assume: neglect of the collar dimensions.
( )
( )

2. Using Mohr Circle:
√ ( )
,

3. Problem 7.120:
A torque of the magnitude T= 12 KN. m is applied to the end of a tank
containing compressed air under a pressure of 8 MPa. Knowing that the
tank has a 180-mm inner diameter and 12-mm wall thickness, determine
the maximum normal stress and the maximum shearing stress in the tank.
Solution:
= 90mm, t=12mm,
,
Torsion:
C1=90mm, C2=102mm, ( )
Using Mohr’s Circle:
√ ( )

4. Problem 7.121:
The tank shown has a 180-mm inner diameter and 12-mm wall thickness.
Knowing that the tank contains compressed air under a pressure of 8-
MPa, determine the magnitude T of the applied torque for which the
maximum normal stress is 75-MPa.
Solution:
,
Torsion:
C1=90mm, C2=102mm, ( )
Using Mohr’s Circle:

5. Problem 7.104:
The unpressurized cylindrical storage tank shown has a 5-mm wall
thickness and is made of steel having 450 MPa, ultimate strength in
tension. Determine the max h to which it can be filled with water if the
factor of safety of 4 is desired. (Specific weight of water=9810 N/m2.).
Solution:

6. ,
Solution:
( )
,
Using Mohr’s Circle:

7. Since,| | , stress point lies in 4th quadratic Equation of 4th
quadratic boundary is:
R= 34.612 MPa
√ ( )
Torsion:
C=16-mm,

8. Solution:
√ ( ) | |
Since,| | stress point lies in 4th
quadratic Equation of 4th quadratic boundary is:
| |

9. Solution:
( )
,
√ ( )
√
√ √
( )
( )

10. Problem 7.85:
The 44-mm diameter shaft AB is made of a grade of steel for
which the yield strength is 250 MPa. Using the maximum shearing
stress principle criterion, determine the magnitude of the force P
for which yield occurs when T= 1.5 KN. m.
Solution:
( )
√ ( ) ………………………………………………………………………….. (1)
√ ( ) ……………………………………………………………………………. (2)

11. Subtract (2) from (1):
√ = 174 MPa, ( )