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Generalized Formula For 
Consecutive Square Number’s 
Arithmetic Progression in Hyper 
Dimension or Multi Dimension 
[Hyper Dimension or Multi Dimension 
= 2 Dimension, 3 Dimension, 4 
Dimension…….Nth Dimension or infinite 
Dimension]
Formula 
A.P [(N-D)^2] 
= H(N) * [ F+L ] + [ μ + H(N)*[ F * (F+(H(N)-3 ) ) ]]
Formula Symbol meanings 
H(N) = R * C * Face * Cube * …. * Nth 
Dimension 
F = First Number in square 
L = Last Number in square 
μ = Hyper dimensional Constant
Hyper dimensional Constant 
1. If H(N) greater than or equal to 5 
then; 
퐻(푁)[ 퐴 ∗ 퐴 − 4 + 1] 
μ = 2[ H(N) -3 ] + 퐴=5 
2. If H(N) from 1 to 4 
then ; {H(N), μ} => { 1, 0} , {2,-1},{3,-1},{4,2}
Example : 3 Dimension 
A.P [(N-D)^2] 
= H(N) * [ F+L ] + [ μ + H(N)*[ F * (F+(H(N)-3 ) ) ]] 
A.P [(3-D)^2] 
= [R*C*Face] * [ F+L ] + [ μ + [R*C*Face] *[ F * 
(F+([R*C *Face] -3 ) ) ]]
Example 3 Dimension 
3 D 
6^2 7^2 
3^2 
8^2 9^2 
2^2 
4^2 5^2
Example 3 Dimension with calculations 
A.P [(3-D)^2] 
= [R*C*Face] * [ F+L ] + [ μ + [R*C*Face] *[ F * (F+([R*C *Face] -3 ) ) ]] 
Here R=2, C= 2, Face =2 , F= 2, L =9 
so H(N) = R*C*Face = 2* 2 * 2 
μ condition, H(N) = 8, H(N)>= 5 
퐻(푁)[ 퐴 ∗ 퐴 − 4 + 1] 
μ = 2[ H(N) -3 ] + 퐴=5 
8 [ 퐴 ∗ 퐴 − 4 + 1] 
= 2[ 8 -3 ] + 퐴=5 
= 2[5] + [5+1] +[12+1]+[21+1]+[33+1] 
=10+6+13+22+33 
= 84
Example 3 Dimension with calculations 
A.P [(3-D)^2] 
= [R*C*Face] * [ F+L ] + [ μ + [R*C*Face] *[ F * (F+([R*C 
*Face] -3 ) ) ]] 
= [8] *[2+9] + [84 + [8*[2* 2+(8-3)]]] 
= 88+[84+8*[14]] 
= 88 + 84+ 112 = 88 + 196 
= 284
Checking 
2^2+ 3 ^2 + 4^2 + 5^2 + 6^2 + 7^2 + 8^2 + 9^2 
= 4+9+16+25+36+49+64+81 
=284 
 Finally …. Happy

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Generalized formula for Square Numbers in Hyper Dimensions

  • 1. Generalized Formula For Consecutive Square Number’s Arithmetic Progression in Hyper Dimension or Multi Dimension [Hyper Dimension or Multi Dimension = 2 Dimension, 3 Dimension, 4 Dimension…….Nth Dimension or infinite Dimension]
  • 2. Formula A.P [(N-D)^2] = H(N) * [ F+L ] + [ μ + H(N)*[ F * (F+(H(N)-3 ) ) ]]
  • 3. Formula Symbol meanings H(N) = R * C * Face * Cube * …. * Nth Dimension F = First Number in square L = Last Number in square μ = Hyper dimensional Constant
  • 4. Hyper dimensional Constant 1. If H(N) greater than or equal to 5 then; 퐻(푁)[ 퐴 ∗ 퐴 − 4 + 1] μ = 2[ H(N) -3 ] + 퐴=5 2. If H(N) from 1 to 4 then ; {H(N), μ} => { 1, 0} , {2,-1},{3,-1},{4,2}
  • 5. Example : 3 Dimension A.P [(N-D)^2] = H(N) * [ F+L ] + [ μ + H(N)*[ F * (F+(H(N)-3 ) ) ]] A.P [(3-D)^2] = [R*C*Face] * [ F+L ] + [ μ + [R*C*Face] *[ F * (F+([R*C *Face] -3 ) ) ]]
  • 6. Example 3 Dimension 3 D 6^2 7^2 3^2 8^2 9^2 2^2 4^2 5^2
  • 7. Example 3 Dimension with calculations A.P [(3-D)^2] = [R*C*Face] * [ F+L ] + [ μ + [R*C*Face] *[ F * (F+([R*C *Face] -3 ) ) ]] Here R=2, C= 2, Face =2 , F= 2, L =9 so H(N) = R*C*Face = 2* 2 * 2 μ condition, H(N) = 8, H(N)>= 5 퐻(푁)[ 퐴 ∗ 퐴 − 4 + 1] μ = 2[ H(N) -3 ] + 퐴=5 8 [ 퐴 ∗ 퐴 − 4 + 1] = 2[ 8 -3 ] + 퐴=5 = 2[5] + [5+1] +[12+1]+[21+1]+[33+1] =10+6+13+22+33 = 84
  • 8. Example 3 Dimension with calculations A.P [(3-D)^2] = [R*C*Face] * [ F+L ] + [ μ + [R*C*Face] *[ F * (F+([R*C *Face] -3 ) ) ]] = [8] *[2+9] + [84 + [8*[2* 2+(8-3)]]] = 88+[84+8*[14]] = 88 + 84+ 112 = 88 + 196 = 284
  • 9. Checking 2^2+ 3 ^2 + 4^2 + 5^2 + 6^2 + 7^2 + 8^2 + 9^2 = 4+9+16+25+36+49+64+81 =284  Finally …. Happy