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1
Chapter 4
!
!Extensions to
Extensions to Mendelian
Mendelian Genetics
Genetics
! Gene Interactions
2
Gene Interactions –
Extensions to Mendelian Genetics
• Just as different alleles of 1 gene can interact in complex
ways,
• 2 different genes can also act together to modify a
phenotype:
•2 genes 1 phenotype (Additive Gene Action)
Complementation (complementary gene action)
Epistasis (recessive and dominant)
Redundancy
3
Multifactorial Inheritance
• Vast majority of traits are determined by multiple factors:
– genetic as well as environmental.
• Gene interactions between two or more genes
– Example: Lentil Seed color.
• F1 all same, F2: 4 different phenotypes
• F2 phenotypic ratio is 9:3:3:1
– (same as F2 dihybrids in Mendel’s original crosses).
• Difference:
– in original crosses: 2 independent traits/phenotypes=2 independent genes;
• Seed color and seed shape
– here: multiple phenotypes of 1 trait=2 independent genes
• Seed color only.
4
You can tell this
genotype is caused
by more than one
gene :
• because there are 4
phenotypes not 3 in
F2
•1 gene F2 would
have 3 phenotypes
1:2:1 ratio
(Additive Gene Action)
5
F2 phenotypes
• Dominance Relationships:
– Tan is dominant to green
– Gray is dominant to green
– Brown is dominant to gray, green and tan.
– Tan and Gray are incompletely dominant, giving rise
to brown.
• Genotypic classes:
– Brown: A_B_
– Tan: A_bb
– Gray: aaB_
– Green: aabb
6
Complementary Gene Action
• Each genotypic class may not always dictate a unique phenotype
• A pair of genes can often work together to create a specific
phenotype. We call this complementary interaction.
• With this type of interaction we see 2 different phenotypes
instead of the 4 seen in 2 genes 1 phenotype
• Two or more genotypic classes may display an identical
phenotype.
– Example: Two lines of pure breeding white flowered pea plants
falling into different genotypic classes: AAbb & aaBB
The must have a dominant
allele in both genes to result in
the purple flower phenotype
7
8
9
Epistasis
• One gene’s allele masks the phenotype of the other
gene’s alleles.
• Four genotypic classes produce fewer than four
phenotypes.
• Different types of epistasis:
• Recessive epistasis: when the recessive allele of
one gene masks the effects of either allele of the
second gene.
• Dominant epistasis: when the dominant allele of
one gene masks the effects of either allele of the
second gene.
10
Recessive Epistasis
• Example 1: Coat color of Labrador retriever
• Example 2: ABO blood groups: Bombay
phenotype.
• Phenotypic ratios are 9:3:4 in F2.
11
X
P
F1
Coat-Color Inheritance in
Labrador Retrievers
golden black
black
12
Recessive Epistasis:
a recessive mutation in one gene masks the phenotypic effects of another
F1
X
F2
9 : 3 : 4
Appears like
incomplete
dominance because
some of the progeny
look like neither
parent, but the ratio
is wrong.
13
9 black: 3 brown: 4 golden
(9 B-E-: 3 bbE-: 3 B-ee: 1 bbee)
x
F2 BE Be bE be
BE
Be
bE
be
AACC
AACc
AacCC
AACc
AAcc
AacCc
Aaccc
AacCc
acacCC
acacCc acaccc
acacCc
Aaccc
AacCc
AacCC
AACc
BbEe
BbEe
BBEE BBEe BbEE BbEe
BBEe
BbEE
BbEe
BbEe
BbEe
BBee Bbee
bbEe
bbee
bbEE
Bbee bbEe
Dihybrid
Cross:
14
Molecular Explanation
Pigment production (B) and subsequent incorporation (E) into
the hair shaft are controlled by two separate genes. To be black,
both genes must function. Mutations in B (b) lead to brown
pigment. Mutations in E (e) lead to no pigment in coat.
gene B gene E
3
4
9
15
Recessive Epistasis
• Two genes involved in coat color determination.
• Gene B determines whether black (B) or brown (bb)
pigment is produced.
• Gene E determines if pigment is deposited in hair
– golden retrievers (ee) make either black (B-) or brown
(bb) pigment (look at noses)… but not in fur
• The recessive allele is epistatic to (stands over) other genes
when homozygous -- hence the name “recessive epistasis”
• Phenotypes do not segregate according to Mendelian ratios
(the phenotypic ratios are modified Mendelian ratios).
• epistasis - (Greek, to stand upon or stop) the differential
phenotypic expression of a genotype at one locus caused
by the genotype at another, non allelic, locus. A mutation
that exerts its expression by canceling the expression of the
alleles of another gene.
16
Dominant Epistasis
• caused by the dominant allele of one gene,
masking the action of either allele of the
other gene.
• Ratio is 12:3:1 instaed f 9:3:3:1
• Example: Summer Squash
17
18
Petal color in
snapdragons -
if Mendel had used
snap dragons for
his experiments,
he wouldn’t be
famous!
X
F1
F2 15/16 red; 1/16 white
P
AABB
A-B-
aabb
Redundancy: Duplicate Genes
19
AB Ab aB ab
AB
Ab
aB
ab
AACC
AACc
AacCC
AACc
AAcc
AacCc
Aaccc
AacCc
acacCC
acacCc acaccc
AacCC
AACc
AABB AABb
AAbb
AABb
AaBB AaBb aaBB
AaBb
AaBB AaBb
Aabb
aaBb
AaBb Aabb aaBb aabb
A-B- A-B-
X
15/16 A-B- red; 1/16 aabb white
Whenever a dominant gene is present, the trait is expressed.
One allele is sufficient to produce the pigment.
20
Hints for figuring out gene interactions:
Look at the F2 phenotypic ratios!!
• If one gene is involved in the trait, then the monohybrid
phenotypic ratio is:
3:1 or 1:2:1 or 2:1
• If two genes are involved in the trait, then the dihybrid
phenotypic ratio is:
9:3:3:1 or some permutation (9:4:3 or 9:7 or 12:3:1)
"The 1/16 class is always the double homozygous
recessive.
" Look for internal 3:1 ratios, which will indicate
dominance/recessive relationships for alleles within a gene.
21
Hints for figuring out gene interactions:
• 2 Genes 1 Phenotype (Additive Gene Action): You can tell
this genotype is caused by more than one gene because there
are 4 phenotypes not 3 in F2 (9:3:3:1)
– 1 gene F2 would have 3 phenotypes 1:2:1 ratio
• Complementary Gene Action: one good copy of each gene
is needed for expression of the final phenotype
– 9:7 ratio
• Epistasis: one gene can mask the effect of another gene
– 9:3:4 ratio for recessive epistasis
– 12:3:1 ratio for dominant epistasis
• Duplicate genes: only double mutant has mutant phenotype
– 15:1 ratio
22
variations on Mendelian inheritance
Gene
interaction
Inheritance
pattern A-/B- A-/bb aa/B- aabb ratio
Additive
Complementary
Recessive
Epistasis
Dominant
Epistasis
9
9
9
9
3
3
3
3 3
3
3
3 1
1
1
1
9:7
9:3:4
12:3:1
9:3:3:1
Each genotype results
in a unique phenotype
Onedominantallelefrom
eitherof twogenes needed
forphenotype
Homozyousrecessive
genotypeatone locus masks
expressionatsecond locus
Dominant allele at one
locus masks expression
at second locus
9 3 3 1 15:1
Duplicate
Genes
Atleastone dominant
allelefromeachoftwo
genesneeded forphenotype
23
true breeding brown dogs X true breeding white dogs
F1 = all white
F2 = 118 white
32 black
10 brown
# Find the genotypes of the dogs in each class:
What is the ratio?
12
3
1
How many genes? 2
What is the ratio of white to colored dogs? 12:4 = 3:1
This means that white is dominant to colored so let’s call
one gene: W= white w=colored
Sample Problem
24
What is the ratio of black to brown dogs? 3 : 1
So black must be dominant to brown. So we will call the
second gene: B=black and b=brown
What class of dogs are the double recessive homozygotes
and what is their genotype?
Brown - wwbb
What is the genotype of the black dogs?
Must be wwB-
What are the genotypes of the white dogs?
W_ B_ and W_bb # This is an example of dominant
epistasis (white).
F2 = 118 white
32 black
10 brown
25
Same Genotype may produce
different Phenotypes
• Penetrance: Genotype does not necessarily define phenotype.
The proportion of individuals with a given genotype express the
phenotype determines penetrance.
• 100% penetrance = all individuals show phenotype.
• 50% penetrance = half the individuals show phenotype.
– Example: retinoblastoma: only 75% individuals affected.
• Expressivity: the degree or intensity with which a particular
genotype is expressed in a phenotype in a given individual.
– Retinoblastoma: some have both eyes affected, some only one.
26
Modifier Effects
• Modifier Genes: they have a subtle, secondary effect which
alters the phenotypes produced by the primary genes.
– E.G. Tail length in mice. The mutant allele t causes a shortening of
the tail. Not all short tails are of the same length: another gene
affects the actual length. (Variable expressivity).
• Modifying environment: The environment may influence
the effect of a genotype on the phenotype.
– E.G.: Siamese cats: temperature dependent color of coat. Color
shows up only in extremities, where the temp is lower (enzyme for
pigment formation is active only at lower temp.)
27
Modifying environment:
The environmental influence of a genotype on the phenotype=
phenocopy
28
Modifying environment:
The environmental influence
of a genotype on the phenotype=
phenocopy
29
–Chapter 4
–# 15, 16, 19, 26
$
$DON
DON’
’T forget to take the online QUIZ!!
T forget to take the online QUIZ!!
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Gene Interaction.pdf

  • 1. 1 Chapter 4 ! !Extensions to Extensions to Mendelian Mendelian Genetics Genetics ! Gene Interactions
  • 2. 2 Gene Interactions – Extensions to Mendelian Genetics • Just as different alleles of 1 gene can interact in complex ways, • 2 different genes can also act together to modify a phenotype: •2 genes 1 phenotype (Additive Gene Action) Complementation (complementary gene action) Epistasis (recessive and dominant) Redundancy
  • 3. 3 Multifactorial Inheritance • Vast majority of traits are determined by multiple factors: – genetic as well as environmental. • Gene interactions between two or more genes – Example: Lentil Seed color. • F1 all same, F2: 4 different phenotypes • F2 phenotypic ratio is 9:3:3:1 – (same as F2 dihybrids in Mendel’s original crosses). • Difference: – in original crosses: 2 independent traits/phenotypes=2 independent genes; • Seed color and seed shape – here: multiple phenotypes of 1 trait=2 independent genes • Seed color only.
  • 4. 4 You can tell this genotype is caused by more than one gene : • because there are 4 phenotypes not 3 in F2 •1 gene F2 would have 3 phenotypes 1:2:1 ratio (Additive Gene Action)
  • 5. 5 F2 phenotypes • Dominance Relationships: – Tan is dominant to green – Gray is dominant to green – Brown is dominant to gray, green and tan. – Tan and Gray are incompletely dominant, giving rise to brown. • Genotypic classes: – Brown: A_B_ – Tan: A_bb – Gray: aaB_ – Green: aabb
  • 6. 6 Complementary Gene Action • Each genotypic class may not always dictate a unique phenotype • A pair of genes can often work together to create a specific phenotype. We call this complementary interaction. • With this type of interaction we see 2 different phenotypes instead of the 4 seen in 2 genes 1 phenotype • Two or more genotypic classes may display an identical phenotype. – Example: Two lines of pure breeding white flowered pea plants falling into different genotypic classes: AAbb & aaBB The must have a dominant allele in both genes to result in the purple flower phenotype
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  • 9. 9 Epistasis • One gene’s allele masks the phenotype of the other gene’s alleles. • Four genotypic classes produce fewer than four phenotypes. • Different types of epistasis: • Recessive epistasis: when the recessive allele of one gene masks the effects of either allele of the second gene. • Dominant epistasis: when the dominant allele of one gene masks the effects of either allele of the second gene.
  • 10. 10 Recessive Epistasis • Example 1: Coat color of Labrador retriever • Example 2: ABO blood groups: Bombay phenotype. • Phenotypic ratios are 9:3:4 in F2.
  • 11. 11 X P F1 Coat-Color Inheritance in Labrador Retrievers golden black black
  • 12. 12 Recessive Epistasis: a recessive mutation in one gene masks the phenotypic effects of another F1 X F2 9 : 3 : 4 Appears like incomplete dominance because some of the progeny look like neither parent, but the ratio is wrong.
  • 13. 13 9 black: 3 brown: 4 golden (9 B-E-: 3 bbE-: 3 B-ee: 1 bbee) x F2 BE Be bE be BE Be bE be AACC AACc AacCC AACc AAcc AacCc Aaccc AacCc acacCC acacCc acaccc acacCc Aaccc AacCc AacCC AACc BbEe BbEe BBEE BBEe BbEE BbEe BBEe BbEE BbEe BbEe BbEe BBee Bbee bbEe bbee bbEE Bbee bbEe Dihybrid Cross:
  • 14. 14 Molecular Explanation Pigment production (B) and subsequent incorporation (E) into the hair shaft are controlled by two separate genes. To be black, both genes must function. Mutations in B (b) lead to brown pigment. Mutations in E (e) lead to no pigment in coat. gene B gene E 3 4 9
  • 15. 15 Recessive Epistasis • Two genes involved in coat color determination. • Gene B determines whether black (B) or brown (bb) pigment is produced. • Gene E determines if pigment is deposited in hair – golden retrievers (ee) make either black (B-) or brown (bb) pigment (look at noses)… but not in fur • The recessive allele is epistatic to (stands over) other genes when homozygous -- hence the name “recessive epistasis” • Phenotypes do not segregate according to Mendelian ratios (the phenotypic ratios are modified Mendelian ratios). • epistasis - (Greek, to stand upon or stop) the differential phenotypic expression of a genotype at one locus caused by the genotype at another, non allelic, locus. A mutation that exerts its expression by canceling the expression of the alleles of another gene.
  • 16. 16 Dominant Epistasis • caused by the dominant allele of one gene, masking the action of either allele of the other gene. • Ratio is 12:3:1 instaed f 9:3:3:1 • Example: Summer Squash
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  • 18. 18 Petal color in snapdragons - if Mendel had used snap dragons for his experiments, he wouldn’t be famous! X F1 F2 15/16 red; 1/16 white P AABB A-B- aabb Redundancy: Duplicate Genes
  • 19. 19 AB Ab aB ab AB Ab aB ab AACC AACc AacCC AACc AAcc AacCc Aaccc AacCc acacCC acacCc acaccc AacCC AACc AABB AABb AAbb AABb AaBB AaBb aaBB AaBb AaBB AaBb Aabb aaBb AaBb Aabb aaBb aabb A-B- A-B- X 15/16 A-B- red; 1/16 aabb white Whenever a dominant gene is present, the trait is expressed. One allele is sufficient to produce the pigment.
  • 20. 20 Hints for figuring out gene interactions: Look at the F2 phenotypic ratios!! • If one gene is involved in the trait, then the monohybrid phenotypic ratio is: 3:1 or 1:2:1 or 2:1 • If two genes are involved in the trait, then the dihybrid phenotypic ratio is: 9:3:3:1 or some permutation (9:4:3 or 9:7 or 12:3:1) "The 1/16 class is always the double homozygous recessive. " Look for internal 3:1 ratios, which will indicate dominance/recessive relationships for alleles within a gene.
  • 21. 21 Hints for figuring out gene interactions: • 2 Genes 1 Phenotype (Additive Gene Action): You can tell this genotype is caused by more than one gene because there are 4 phenotypes not 3 in F2 (9:3:3:1) – 1 gene F2 would have 3 phenotypes 1:2:1 ratio • Complementary Gene Action: one good copy of each gene is needed for expression of the final phenotype – 9:7 ratio • Epistasis: one gene can mask the effect of another gene – 9:3:4 ratio for recessive epistasis – 12:3:1 ratio for dominant epistasis • Duplicate genes: only double mutant has mutant phenotype – 15:1 ratio
  • 22. 22 variations on Mendelian inheritance Gene interaction Inheritance pattern A-/B- A-/bb aa/B- aabb ratio Additive Complementary Recessive Epistasis Dominant Epistasis 9 9 9 9 3 3 3 3 3 3 3 3 1 1 1 1 9:7 9:3:4 12:3:1 9:3:3:1 Each genotype results in a unique phenotype Onedominantallelefrom eitherof twogenes needed forphenotype Homozyousrecessive genotypeatone locus masks expressionatsecond locus Dominant allele at one locus masks expression at second locus 9 3 3 1 15:1 Duplicate Genes Atleastone dominant allelefromeachoftwo genesneeded forphenotype
  • 23. 23 true breeding brown dogs X true breeding white dogs F1 = all white F2 = 118 white 32 black 10 brown # Find the genotypes of the dogs in each class: What is the ratio? 12 3 1 How many genes? 2 What is the ratio of white to colored dogs? 12:4 = 3:1 This means that white is dominant to colored so let’s call one gene: W= white w=colored Sample Problem
  • 24. 24 What is the ratio of black to brown dogs? 3 : 1 So black must be dominant to brown. So we will call the second gene: B=black and b=brown What class of dogs are the double recessive homozygotes and what is their genotype? Brown - wwbb What is the genotype of the black dogs? Must be wwB- What are the genotypes of the white dogs? W_ B_ and W_bb # This is an example of dominant epistasis (white). F2 = 118 white 32 black 10 brown
  • 25. 25 Same Genotype may produce different Phenotypes • Penetrance: Genotype does not necessarily define phenotype. The proportion of individuals with a given genotype express the phenotype determines penetrance. • 100% penetrance = all individuals show phenotype. • 50% penetrance = half the individuals show phenotype. – Example: retinoblastoma: only 75% individuals affected. • Expressivity: the degree or intensity with which a particular genotype is expressed in a phenotype in a given individual. – Retinoblastoma: some have both eyes affected, some only one.
  • 26. 26 Modifier Effects • Modifier Genes: they have a subtle, secondary effect which alters the phenotypes produced by the primary genes. – E.G. Tail length in mice. The mutant allele t causes a shortening of the tail. Not all short tails are of the same length: another gene affects the actual length. (Variable expressivity). • Modifying environment: The environment may influence the effect of a genotype on the phenotype. – E.G.: Siamese cats: temperature dependent color of coat. Color shows up only in extremities, where the temp is lower (enzyme for pigment formation is active only at lower temp.)
  • 27. 27 Modifying environment: The environmental influence of a genotype on the phenotype= phenocopy
  • 28. 28 Modifying environment: The environmental influence of a genotype on the phenotype= phenocopy
  • 29. 29 –Chapter 4 –# 15, 16, 19, 26 $ $DON DON’ ’T forget to take the online QUIZ!! T forget to take the online QUIZ!! Homework Problems