A function is a ‘job’
The notation f(x) defines a function named
f. This is read as “y is a function of x.” The
letter x represents the input value, or
independent variable. The letter y is
replaced by f(x) and represents the output
value, or dependent variable.
x
You are familiar with function notation like:
y = 5x + 3 or y= x2 + 4x + 6
y = f(x) means that y is a function of x.
You read f(x) as ‘f of x’.
So, if y = x2 + 2, we can also write
f(x) = x2 + 2
If f(x) = 3x + 7, find:
(a) f(1) = 3(1) + 7
= 3 + 7
= 10
(b) f(4) = 3(4) + 7
= 12 + 7
= 19
(c) f(-2) = 3(-2) + 7
= -6 + 7
= 1
Let f(x) = 4x2 – 3, find:
(a) f(3) = 4(3)2 – 3
= 4(9) - 3
= 36 - 3
(b) f(-5)
= 33
= 4(-5)2 – 3
= 4(25) - 3
= 100 - 3
= 97
(1) Let f(x) = 7x – 8. Find the value of:
(a) f(2) (b) f(8) (c) f(-8)
(2) Let f(x) = 3x2 + 2. Find the value of each of these.
(a) f(4) (b) f(-1) (c) f(22)
(3) Let g(x) = 3x2 – 2x + 1. Find:
(a) g(3) (b) g(-2) (c) g(0)
If g(x) = 5x - 9, then:
(a) Solve g(x) = 21
⇒ 5x – 9 = 21
⇒ 5x = 30
⇒ x = 6
(b) Solve g(x) = -64
⇒ 5x - 9 = -64
⇒ 5x = -55
⇒ x = -11
If f(x) = x2 – 3x, then solve f(x) = 4.
⇒ x2 – 3x = 4
⇒ x2 – 3x – 4 = 0
⇒ (x - 4)(x + 1) = 0
⇒ (x - 4) = 0 or (x + 1) = 0
⇒ x = 4 or x = -1
(1) Let h(x) = 2x – 5. Solve h(x) = 7.
(2) Let g(x) = 4x - 3. Solve g(x) = 0.
(3) h(x) = x2 – 2
(a) Find h(3) and h(-6)
(b) Solve h(x) = 7
(4) Let f(x) = 3x2 – 11x.
(a) Find f(-3)
(b) Solve f(x) = 20
If h(x) = 2x + 7, then write an expression for:
(a) h(3x) = 2(3x) + 7
= 6x + 7
(c) 4h(x) = 4(2x + 7)
= 8x + 28
(b) 3h(x) = 3(2x + 7)
= 6x + 21
Let f(x) = x2 + 7, then write an expression for:
(a) f(x) +2 = (x2 + 7) + 2
= x2 + 9
(b) f(x + 2) = (x +2)2 + 7
= (x +2) (x +2) + 7
= x2 + 4x + 4 + 7
= x2 + 4x + 11
• AGUDA, Mark Clifford
• ALCANTRA, John Alfred
• ALTURA, Marjorie
• CASTRO, Danny
• DELA CRUZ, Christian James
• DELA CRUZ, Jerimie
• CORSINO, Brian
• FABRO, Cristine
• GADONG, Karl Said
• GAGTAN, Darlfred John
• GOROSPE, Christian
• HADAP, Karren Jae

Function-Notation in Calculus (Group1) 2B.pptx

  • 1.
    A function isa ‘job’
  • 2.
    The notation f(x)defines a function named f. This is read as “y is a function of x.” The letter x represents the input value, or independent variable. The letter y is replaced by f(x) and represents the output value, or dependent variable.
  • 3.
    x You are familiarwith function notation like: y = 5x + 3 or y= x2 + 4x + 6 y = f(x) means that y is a function of x. You read f(x) as ‘f of x’. So, if y = x2 + 2, we can also write f(x) = x2 + 2
  • 4.
    If f(x) =3x + 7, find: (a) f(1) = 3(1) + 7 = 3 + 7 = 10 (b) f(4) = 3(4) + 7 = 12 + 7 = 19 (c) f(-2) = 3(-2) + 7 = -6 + 7 = 1
  • 5.
    Let f(x) =4x2 – 3, find: (a) f(3) = 4(3)2 – 3 = 4(9) - 3 = 36 - 3 (b) f(-5) = 33 = 4(-5)2 – 3 = 4(25) - 3 = 100 - 3 = 97
  • 6.
    (1) Let f(x)= 7x – 8. Find the value of: (a) f(2) (b) f(8) (c) f(-8) (2) Let f(x) = 3x2 + 2. Find the value of each of these. (a) f(4) (b) f(-1) (c) f(22) (3) Let g(x) = 3x2 – 2x + 1. Find: (a) g(3) (b) g(-2) (c) g(0)
  • 7.
    If g(x) =5x - 9, then: (a) Solve g(x) = 21 ⇒ 5x – 9 = 21 ⇒ 5x = 30 ⇒ x = 6 (b) Solve g(x) = -64 ⇒ 5x - 9 = -64 ⇒ 5x = -55 ⇒ x = -11
  • 8.
    If f(x) =x2 – 3x, then solve f(x) = 4. ⇒ x2 – 3x = 4 ⇒ x2 – 3x – 4 = 0 ⇒ (x - 4)(x + 1) = 0 ⇒ (x - 4) = 0 or (x + 1) = 0 ⇒ x = 4 or x = -1
  • 9.
    (1) Let h(x)= 2x – 5. Solve h(x) = 7. (2) Let g(x) = 4x - 3. Solve g(x) = 0. (3) h(x) = x2 – 2 (a) Find h(3) and h(-6) (b) Solve h(x) = 7 (4) Let f(x) = 3x2 – 11x. (a) Find f(-3) (b) Solve f(x) = 20
  • 10.
    If h(x) =2x + 7, then write an expression for: (a) h(3x) = 2(3x) + 7 = 6x + 7 (c) 4h(x) = 4(2x + 7) = 8x + 28 (b) 3h(x) = 3(2x + 7) = 6x + 21
  • 11.
    Let f(x) =x2 + 7, then write an expression for: (a) f(x) +2 = (x2 + 7) + 2 = x2 + 9 (b) f(x + 2) = (x +2)2 + 7 = (x +2) (x +2) + 7 = x2 + 4x + 4 + 7 = x2 + 4x + 11
  • 12.
    • AGUDA, MarkClifford • ALCANTRA, John Alfred • ALTURA, Marjorie • CASTRO, Danny • DELA CRUZ, Christian James • DELA CRUZ, Jerimie • CORSINO, Brian • FABRO, Cristine • GADONG, Karl Said • GAGTAN, Darlfred John • GOROSPE, Christian • HADAP, Karren Jae