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BahanKuliahFisikaDasar2 
OptikaFisis 
oleh 
Ishafit 
http://hafit.pfis.uad.ac.id 
Program StudiPendidikanFisika 
UNIVERSITAS AHMAD DAHLAN 
YogyakartaHubble Space Telescope
OptikaFisik(PysicalOptics) 
|Optical Interference (IntefrerensiOptik) 
zDouble-Slit Interference 
zThin-Film Interference 
|Optical Diffraction (DifraksiOptik) 
zSingle-Slit Diffraction 
zDiffraction Gratings 
|Polarization oh Light (PolarisasiCahaya)
Physics Phenomenon 
Newton's RingsA band of color appears wherever the distance between the two pieces of glass causes light of that color to interfere constructively, making the waves bouncing off the two surfaces reinforce each other ©1993-2003 Microsoft Corporation. All rights reserved.
Physics Phenomenon 
Thin-film interferenceThin-film interference is the interference of light waves reflecting off the top surface of a film with the waves reflecting from the bottom surface.If the thickness of the film is on the order of the wavelength of light, then colorful patterns can be obtained, as shown in the image below,
Physics PhenomenonCharacteristic SpectraEvery chemical element has a characteristic spectrum, or particular distribution of electromagnetic radiation. Because of these “signature” wavelength patterns, it is possible to identify the constituentsof an unknown substance by analyzing its spectrum; this technique is called spectroscopy ©1993-2003 Microsoft Corporation. All rights reserved.
Double-Slit Interference 
•Physics Working Model
Physics Working ModelConstructive InterferenceWevefrontWevefront 
Light Source 
Destructive Interference
Double-Slit Interference (Young Interference) 
|Interferensioptikdapatterjadijikaduagelombang(cahaya) secarasimultanhadirdalamdaerahyang samaS1S2d θθ PySumbusistemr1r2rΔ)sin(111tkrmωψψ−= )sin(222tkrmωψψ−= L1mψ 2mψ mψ 1kr2kr δδψψψψψcos2212221mmmmm++= )(1212rrkkrkr−=−=δ rrrΔ=−= λπλπδ2)(212 θsindr=Δ
Double-Slit Interference (Young Interference) 
|Interferensikonstruktifterjadijika: 
πδn2=L,2,1,0=n λθnd=sin πδλθ 2sin=d ππλθ 22sinnd= |Interferensidestruktifterjadijika: πδ)12(+=nL,2,1,0=n λθ) 21(sin+=nd ππλθ 2)12(sin+ =nd
Penentuanpanjanggelombangdenganinterferensiduacelah 
Dari gambardiperoleh: L θtanLy= S1S2d θθ PySumbusistemr1r2rΔ:maka jikadL>> θsinLy= dnLyn λ = nLdyn=λ
ContohSoal: 
|Celahgandayang berjarak0,100 mm berada1,20 m darilayartampilan. Cahayadenganpanjanggelombangλ=500 nm jatuhpadacelahdarisumberyang jauh. Berapajarakantarinterferensiterangpertamadankeduapadalayar? 
•Interferensiterang(konstruktifordepertaman=1) 
λθnd=sin34911000,5m1000,1m)10500)(1(sin− − − ×= ××== dnλθ Inimerupakansudutkecil, sehingga: radiansatuan dalam dengan , tansin111θθθθ≈≈ 
Dengandemikianordepertamaakanmunculpadajarak: mm 00,6)10m)(5,00 20,1(-311=×==θLy•Interferensiterang(konstruktiforden=2) mm 0,12212=== dLLyλθ 
Jadi, jarakantarapusatmaksimuminterferensiterangadalah(y2-y1)=6,00 mm 
y1 
y2
InterferensiolehLapisanTipis(Thin-Film Interference) GejalaFisikaModel Kerja
Air (n=1) Soap film (n>1) Air (n=1) Incident light1800Phase change18000000Phase changeReflected lightTransmitted lightSurface 1Surface 2tDari teoridaneksperimenelektro- magnetik, diperoleh: 1.Jikan1<n2, phase gelombangcahayabergeser1800padaprosespemantulan2.Jikan1>n2, phase gelombangcahayatidakbergeserpadaprosespemantulanIntereferensidestruktifterjadiketika: med2λmt= Intereferensikonstruktifterjadiketika: med) 21(2λ+=mt
Panjanggelombangdimedium dapatdinyatakandenganpanjanggelombangdalamvacuum, yaitu: ncnncvλυυυλ=⎟⎠ ⎞ ⎜⎝ ⎛=⎟⎠ ⎞ ⎜⎝ ⎛==11mednmt λ =2nmtλ ⎟⎠ ⎞ ⎜⎝ ⎛+= 212 
The sum of the phase changes caused by both reflections is equal to 00or 3600 
(Constructive) 
The sum of the phase changes caused by both reflections is equal to 1800 
(Destructive) nmt λ =2nmtλ ⎟⎠ ⎞ ⎜⎝ ⎛+= 212 
(Destructive) 
(Constructive)
ContohSoal: 
|Gelembungsabuntampakhijau(λ=540 nm) dititikpermukaandepanpaling dekatdenganpengamat. Berapaketebalanminimumnya? (anggapn=1,35) 
|Cahayadipantulkantegaklurusdarititikpadapermukaansferisyang paling dekatdenganpengamat. Perbedaanlintasanadalah2t (t=ketebalanlapisansabun). Cahayayang dipantulkandaripermukaanpertama(lebihluar) mengalamiperubahanfase½λ(indeksbias sabunlebihbesardariudara), sedangkanpermukaankedua(bagiandalamtidak. Sehinggacahayahijauakancerahketikaperbedaanlintasanminimum ½λ, sehingga: nt22 λ =nm 100)35,1)(4( nm) 540( 4=== ntλ
ContohSoal: 
BerapaketebalanpelapisoptikMgF2yang indeksbiasnyan=1,38 dandirancanguntukmenghilangkancahayaterpantuldenganpanjanggelombangterpusatpada550 nm padasaatjatuhnormal padakacadengann=1,50? n=1,38n=1,50sinardatangsinarpantulnm 6,99)38,1)(4( nm) 550( 4=== ntλ
Difraksi(Diffraction) 
PerilakuPartikel 
PerilakuGelombang
PolaDifraksi
Difraksi(Diffraction)
Single Slit Diffraction EquationD λθ=sin 
(first minimum) 
λθmD=sin 
(m= 1, 2, 3, ……)
ContohSoal: Maksimumdaridifraksicelahtunggal. Cahayadenganpanjanggelombang750 nm melewaticelahyang lebarnya1,0x10-3 mm. Berapalebarmaksimumpusat(a) dalamderajat, dan(b) dalamsentimeter, padalayaryang jaraknya20 cm? 75,0m 101m105,7sin67= ××==− − D λθ 049 (a)=θ cm 46)49cm)(tan 20(22 (b)0==x
Diffraction Grating
Spektrum

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FISIKA DASAR 2

  • 1. BahanKuliahFisikaDasar2 OptikaFisis oleh Ishafit http://hafit.pfis.uad.ac.id Program StudiPendidikanFisika UNIVERSITAS AHMAD DAHLAN YogyakartaHubble Space Telescope
  • 2. OptikaFisik(PysicalOptics) |Optical Interference (IntefrerensiOptik) zDouble-Slit Interference zThin-Film Interference |Optical Diffraction (DifraksiOptik) zSingle-Slit Diffraction zDiffraction Gratings |Polarization oh Light (PolarisasiCahaya)
  • 3. Physics Phenomenon Newton's RingsA band of color appears wherever the distance between the two pieces of glass causes light of that color to interfere constructively, making the waves bouncing off the two surfaces reinforce each other ©1993-2003 Microsoft Corporation. All rights reserved.
  • 4. Physics Phenomenon Thin-film interferenceThin-film interference is the interference of light waves reflecting off the top surface of a film with the waves reflecting from the bottom surface.If the thickness of the film is on the order of the wavelength of light, then colorful patterns can be obtained, as shown in the image below,
  • 5. Physics PhenomenonCharacteristic SpectraEvery chemical element has a characteristic spectrum, or particular distribution of electromagnetic radiation. Because of these “signature” wavelength patterns, it is possible to identify the constituentsof an unknown substance by analyzing its spectrum; this technique is called spectroscopy ©1993-2003 Microsoft Corporation. All rights reserved.
  • 7. Physics Working ModelConstructive InterferenceWevefrontWevefront Light Source Destructive Interference
  • 8. Double-Slit Interference (Young Interference) |Interferensioptikdapatterjadijikaduagelombang(cahaya) secarasimultanhadirdalamdaerahyang samaS1S2d θθ PySumbusistemr1r2rΔ)sin(111tkrmωψψ−= )sin(222tkrmωψψ−= L1mψ 2mψ mψ 1kr2kr δδψψψψψcos2212221mmmmm++= )(1212rrkkrkr−=−=δ rrrΔ=−= λπλπδ2)(212 θsindr=Δ
  • 9. Double-Slit Interference (Young Interference) |Interferensikonstruktifterjadijika: πδn2=L,2,1,0=n λθnd=sin πδλθ 2sin=d ππλθ 22sinnd= |Interferensidestruktifterjadijika: πδ)12(+=nL,2,1,0=n λθ) 21(sin+=nd ππλθ 2)12(sin+ =nd
  • 10. Penentuanpanjanggelombangdenganinterferensiduacelah Dari gambardiperoleh: L θtanLy= S1S2d θθ PySumbusistemr1r2rΔ:maka jikadL>> θsinLy= dnLyn λ = nLdyn=λ
  • 11. ContohSoal: |Celahgandayang berjarak0,100 mm berada1,20 m darilayartampilan. Cahayadenganpanjanggelombangλ=500 nm jatuhpadacelahdarisumberyang jauh. Berapajarakantarinterferensiterangpertamadankeduapadalayar? •Interferensiterang(konstruktifordepertaman=1) λθnd=sin34911000,5m1000,1m)10500)(1(sin− − − ×= ××== dnλθ Inimerupakansudutkecil, sehingga: radiansatuan dalam dengan , tansin111θθθθ≈≈ Dengandemikianordepertamaakanmunculpadajarak: mm 00,6)10m)(5,00 20,1(-311=×==θLy•Interferensiterang(konstruktiforden=2) mm 0,12212=== dLLyλθ Jadi, jarakantarapusatmaksimuminterferensiterangadalah(y2-y1)=6,00 mm y1 y2
  • 13. Air (n=1) Soap film (n>1) Air (n=1) Incident light1800Phase change18000000Phase changeReflected lightTransmitted lightSurface 1Surface 2tDari teoridaneksperimenelektro- magnetik, diperoleh: 1.Jikan1<n2, phase gelombangcahayabergeser1800padaprosespemantulan2.Jikan1>n2, phase gelombangcahayatidakbergeserpadaprosespemantulanIntereferensidestruktifterjadiketika: med2λmt= Intereferensikonstruktifterjadiketika: med) 21(2λ+=mt
  • 14. Panjanggelombangdimedium dapatdinyatakandenganpanjanggelombangdalamvacuum, yaitu: ncnncvλυυυλ=⎟⎠ ⎞ ⎜⎝ ⎛=⎟⎠ ⎞ ⎜⎝ ⎛==11mednmt λ =2nmtλ ⎟⎠ ⎞ ⎜⎝ ⎛+= 212 The sum of the phase changes caused by both reflections is equal to 00or 3600 (Constructive) The sum of the phase changes caused by both reflections is equal to 1800 (Destructive) nmt λ =2nmtλ ⎟⎠ ⎞ ⎜⎝ ⎛+= 212 (Destructive) (Constructive)
  • 15. ContohSoal: |Gelembungsabuntampakhijau(λ=540 nm) dititikpermukaandepanpaling dekatdenganpengamat. Berapaketebalanminimumnya? (anggapn=1,35) |Cahayadipantulkantegaklurusdarititikpadapermukaansferisyang paling dekatdenganpengamat. Perbedaanlintasanadalah2t (t=ketebalanlapisansabun). Cahayayang dipantulkandaripermukaanpertama(lebihluar) mengalamiperubahanfase½λ(indeksbias sabunlebihbesardariudara), sedangkanpermukaankedua(bagiandalamtidak. Sehinggacahayahijauakancerahketikaperbedaanlintasanminimum ½λ, sehingga: nt22 λ =nm 100)35,1)(4( nm) 540( 4=== ntλ
  • 16. ContohSoal: BerapaketebalanpelapisoptikMgF2yang indeksbiasnyan=1,38 dandirancanguntukmenghilangkancahayaterpantuldenganpanjanggelombangterpusatpada550 nm padasaatjatuhnormal padakacadengann=1,50? n=1,38n=1,50sinardatangsinarpantulnm 6,99)38,1)(4( nm) 550( 4=== ntλ
  • 20. Single Slit Diffraction EquationD λθ=sin (first minimum) λθmD=sin (m= 1, 2, 3, ……)
  • 21. ContohSoal: Maksimumdaridifraksicelahtunggal. Cahayadenganpanjanggelombang750 nm melewaticelahyang lebarnya1,0x10-3 mm. Berapalebarmaksimumpusat(a) dalamderajat, dan(b) dalamsentimeter, padalayaryang jaraknya20 cm? 75,0m 101m105,7sin67= ××==− − D λθ 049 (a)=θ cm 46)49cm)(tan 20(22 (b)0==x