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CHAPTER 1

FUNCTIONS

FORM 4

PAPER 1
1.

Diagram 1 shows the relation between set A and set B.
2

p

4
6
8

q
r
Set A

Set B

Diagram 1
State
(a) the range of the relation,
(b) the type of the relation.
[2 marks]
2.

3.

R = {a, b, c}
S = {b, d , f , h, j}

Based on the above information, the relation between R and S is defined by the set of
ordered pairs {( a, b), ( a, d ), (b, f ), (b, h)} .
State
(a) the images of a
(b) the object of b
[2 marks]
Diagram 2 shows the linear function g .
x

g(x)

0
2
4
6

-2
0
k
4

Diagram 2
(a) State the value of k.
(b) Using the function notation, express g in terms of x.
[2 marks]
4.

Diagram 3 shows the function g : x →
x

x+k
, x ≠ 0 where k is a constant.
x
x +k
x

3
1
2

Diagram 3
Find the value of k.
1
CHAPTER 1
5.

Given the function

FUNCTIONS
g : x →x +1 ,

FORM 4

find the value of x such that g ( x) = 2 .

[2 marks]
[2 marks]

6.

Diagram 5 shows the graph of the function

f ( x ) = 2 x −6

for domain 0 ≤ x ≤ 4 .

f(x)
6

t

0

4

x

Diagram 5
State
(a) the value of t,
(b) the range of f(x) corresponding to the given domain.
[3 marks]
7.

Given the function f ( x) = 2 x +1 and g ( x) = 3 − kx , find
(a) f (2)
(b) the value of k such that gf ( 2) = −7
[3 marks]

8.

The following information is about the function g and the composite function g 2 .
g : x → a − bx ,

where a and b are constant and b > 0

g 2 : x → 9x + 8

Find the value of a and b.
[3 marks]
9.

Given the function f ( x) =

1
,
2x

x ≠ 0 and the composite function fg ( x) = 4 x .

Find
(a) g ( x)
(b) the value of x when gf ( x) = 2
[4 marks]
10
.

The function h is defined as h( x) =
Find
(a) h −1 ( x)
(b) h −1 ( 2)

7
,
3+ x

x ≠ −3 .

[3 marks]
2
CHAPTER 1
11
.

FUNCTIONS

FORM 4

Diagram 9 shows the function f maps x to y and the function g maps y to z.
x

f

y

g

z

5
4
1

Determine
(a) f −1 (1)
(b) gf (5)

[2 marks]
12
.

The following information refers to the function f and g.
f : x → 5 x +1
g : x → x −3

Find f

−
1

g ( x) .

[3 marks]
13
.

1
2

−1
Given the function g : x →3 x − h and g : x → kx − , where h and k are constants. Find

the value of h and of k.
[3marks]
14
.

Given the function h( x ) = 3x +1 and g ( x ) =

x
. Find
3

(a) h −1 (7)
(b) gh −1 ( x )
[4 marks]
15
.

Given the function f : x → 3 x − 2 and g : x → 2 x 2 − 3 .
Find
(a) f −1 ( 4)
(b) gf (x )
[4 marks]

ANSWER (PAPER 1)

3
CHAPTER 1

FUNCTIONS

FORM 4

2 (a)
(b)
3 (a)
(b)
4

1

many-to-one

1

b , d

1

a

1

k =2

1

g ( x) = x − 2

1

1

k =1

(b)

{4, 8}

1
+k
1 2
g  =
=3
1
2
2

1 (a)

1

x +1 = 2

5

or − ( x +1) = 2

x =1

6 (a)

x = −3

When f ( x ) = 0 , 2 x − 6 = 0

1
1
1

x =3
∴ t =3

(b)

Range :

7 (a)

f ( 2) = 5

(a)

(b)

0 ≤ f ( x) ≤ 6

(b)

1
1

g (5) = −7
3 − k (5) = −7

1

k =2

1

g 2 ( x ) = a − b( a − bx)

8

1

1

= a − ab + b 2 x
b2 = 9

and

a − ab = 8

b =3

9 (a)

(b)

1
= 4x
2 g ( x)
1
g ( x) =
,
8x
1
=2
1 
8 x 
2 

a = −4

1
1
1

x≠0

1
1

4
CHAPTER 1

FUNCTIONS
x=

10 (a)

x=

1
8

FORM 4
1
1

7
−3
y

7
−3 , x ≠ 0
x
1
h −1 ( 2) =
2

1

11 (a)

5

1

(b)

4

1

h −1 ( x) =

(b)

12

x=

14.
(a)

(b)

15 (a)

−1

f

(b)

1

( x − 3) −1
5
x −4
=
5
y +h
x=
3
1
k=
3
3
h =−
2
y −1
x=
3
7 −1
h −1 (7) =
=2
3
x −1
gh −1 ( x) = 3
3
x −1
=
9
y+2
x=
3
f

13.

y −1
5

g ( x) =

−1

1

( 4) = 2

1
1
1
1
1
1
1

1
1
1
1

gf ( x) = 2(3 x − 2) 2 − 3

= 18 x − 24 x + 5
2

1
1

5
CHAPTER 1

FUNCTIONS
x=

10 (a)

x=

1
8

FORM 4
1
1

7
−3
y

7
−3 , x ≠ 0
x
1
h −1 ( 2) =
2

1

11 (a)

5

1

(b)

4

1

h −1 ( x) =

(b)

12

x=

14.
(a)

(b)

15 (a)

−1

f

(b)

1

( x − 3) −1
5
x −4
=
5
y +h
x=
3
1
k=
3
3
h =−
2
y −1
x=
3
7 −1
h −1 (7) =
=2
3
x −1
gh −1 ( x) = 3
3
x −1
=
9
y+2
x=
3
f

13.

y −1
5

g ( x) =

−1

1

( 4) = 2

1
1
1
1
1
1
1

1
1
1
1

gf ( x) = 2(3 x − 2) 2 − 3

= 18 x − 24 x + 5
2

1
1

5

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F4 c1 functions__new__1_

  • 1. CHAPTER 1 FUNCTIONS FORM 4 PAPER 1 1. Diagram 1 shows the relation between set A and set B. 2 p 4 6 8 q r Set A Set B Diagram 1 State (a) the range of the relation, (b) the type of the relation. [2 marks] 2. 3. R = {a, b, c} S = {b, d , f , h, j} Based on the above information, the relation between R and S is defined by the set of ordered pairs {( a, b), ( a, d ), (b, f ), (b, h)} . State (a) the images of a (b) the object of b [2 marks] Diagram 2 shows the linear function g . x g(x) 0 2 4 6 -2 0 k 4 Diagram 2 (a) State the value of k. (b) Using the function notation, express g in terms of x. [2 marks] 4. Diagram 3 shows the function g : x → x x+k , x ≠ 0 where k is a constant. x x +k x 3 1 2 Diagram 3 Find the value of k. 1
  • 2. CHAPTER 1 5. Given the function FUNCTIONS g : x →x +1 , FORM 4 find the value of x such that g ( x) = 2 . [2 marks] [2 marks] 6. Diagram 5 shows the graph of the function f ( x ) = 2 x −6 for domain 0 ≤ x ≤ 4 . f(x) 6 t 0 4 x Diagram 5 State (a) the value of t, (b) the range of f(x) corresponding to the given domain. [3 marks] 7. Given the function f ( x) = 2 x +1 and g ( x) = 3 − kx , find (a) f (2) (b) the value of k such that gf ( 2) = −7 [3 marks] 8. The following information is about the function g and the composite function g 2 . g : x → a − bx , where a and b are constant and b > 0 g 2 : x → 9x + 8 Find the value of a and b. [3 marks] 9. Given the function f ( x) = 1 , 2x x ≠ 0 and the composite function fg ( x) = 4 x . Find (a) g ( x) (b) the value of x when gf ( x) = 2 [4 marks] 10 . The function h is defined as h( x) = Find (a) h −1 ( x) (b) h −1 ( 2) 7 , 3+ x x ≠ −3 . [3 marks] 2
  • 3. CHAPTER 1 11 . FUNCTIONS FORM 4 Diagram 9 shows the function f maps x to y and the function g maps y to z. x f y g z 5 4 1 Determine (a) f −1 (1) (b) gf (5) [2 marks] 12 . The following information refers to the function f and g. f : x → 5 x +1 g : x → x −3 Find f − 1 g ( x) . [3 marks] 13 . 1 2 −1 Given the function g : x →3 x − h and g : x → kx − , where h and k are constants. Find the value of h and of k. [3marks] 14 . Given the function h( x ) = 3x +1 and g ( x ) = x . Find 3 (a) h −1 (7) (b) gh −1 ( x ) [4 marks] 15 . Given the function f : x → 3 x − 2 and g : x → 2 x 2 − 3 . Find (a) f −1 ( 4) (b) gf (x ) [4 marks] ANSWER (PAPER 1) 3
  • 4. CHAPTER 1 FUNCTIONS FORM 4 2 (a) (b) 3 (a) (b) 4 1 many-to-one 1 b , d 1 a 1 k =2 1 g ( x) = x − 2 1 1 k =1 (b) {4, 8} 1 +k 1 2 g  = =3 1 2 2 1 (a) 1 x +1 = 2 5 or − ( x +1) = 2 x =1 6 (a) x = −3 When f ( x ) = 0 , 2 x − 6 = 0 1 1 1 x =3 ∴ t =3 (b) Range : 7 (a) f ( 2) = 5 (a) (b) 0 ≤ f ( x) ≤ 6 (b) 1 1 g (5) = −7 3 − k (5) = −7 1 k =2 1 g 2 ( x ) = a − b( a − bx) 8 1 1 = a − ab + b 2 x b2 = 9 and a − ab = 8 b =3 9 (a) (b) 1 = 4x 2 g ( x) 1 g ( x) = , 8x 1 =2 1  8 x  2  a = −4 1 1 1 x≠0 1 1 4
  • 5. CHAPTER 1 FUNCTIONS x= 10 (a) x= 1 8 FORM 4 1 1 7 −3 y 7 −3 , x ≠ 0 x 1 h −1 ( 2) = 2 1 11 (a) 5 1 (b) 4 1 h −1 ( x) = (b) 12 x= 14. (a) (b) 15 (a) −1 f (b) 1 ( x − 3) −1 5 x −4 = 5 y +h x= 3 1 k= 3 3 h =− 2 y −1 x= 3 7 −1 h −1 (7) = =2 3 x −1 gh −1 ( x) = 3 3 x −1 = 9 y+2 x= 3 f 13. y −1 5 g ( x) = −1 1 ( 4) = 2 1 1 1 1 1 1 1 1 1 1 1 gf ( x) = 2(3 x − 2) 2 − 3 = 18 x − 24 x + 5 2 1 1 5
  • 6. CHAPTER 1 FUNCTIONS x= 10 (a) x= 1 8 FORM 4 1 1 7 −3 y 7 −3 , x ≠ 0 x 1 h −1 ( 2) = 2 1 11 (a) 5 1 (b) 4 1 h −1 ( x) = (b) 12 x= 14. (a) (b) 15 (a) −1 f (b) 1 ( x − 3) −1 5 x −4 = 5 y +h x= 3 1 k= 3 3 h =− 2 y −1 x= 3 7 −1 h −1 (7) = =2 3 x −1 gh −1 ( x) = 3 3 x −1 = 9 y+2 x= 3 f 13. y −1 5 g ( x) = −1 1 ( 4) = 2 1 1 1 1 1 1 1 1 1 1 1 gf ( x) = 2(3 x − 2) 2 − 3 = 18 x − 24 x + 5 2 1 1 5