JEE Mathematics/ Lakshmikanta Satapathy/ Angle between two lines in space/ Direction cosines and Direction ratios, Parallel and Perpendicular lines/ Point of intersection of two lines
JEE Mathematics/ Lakshmikanta Satapathy/ 2D Geometry part 13/ Equation of Ellipse in cartesian and parametric forms derived with the related concepts with explanation of the parameter
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CHAPTER 5 : THE STRAIGHT LINE
EXERCISE 1
1. In the diagram , PQ is a straight line.
Answer :a)…………………….….
b)………………………
2.
y Q (5,18)
3 P
0 x
Find
a) the gradient of PQ
b) the equation of straight line PQ Answer :a)………………………
b)………………………
3. Determine the gradient of the straight line y = 9
4
+
−
x
Answer :…………………
4.
y
F
E(-2,6)
0 G
5. Determine the y-intercept of the straight line 2y – x = -
Find
(a) the y-intercept,
(b) the gradient ,
of the straight line.
The diagram shows two straight lines, EF and FG, on a Cartesian plane. The gradient of EF
is 1 and the distance of FG is 10 units. The x-intercept of FG is
Answer :………………………….
y
x
1 2
– 1
– 2
– 3
– 4
2
4
– 2
P
Q
0
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6. The gradient of the straight line 2x + 6y = 13
Answer :………………………...
7. The x - intercept of the straight line 4x – 2y = 12 is
Answer :………………………
8. In the diagram, AB is a straight line.
y
A -12
0 x
-3
B
What is the gradient of AB ?
Answer :………………………..
9. In the diagram, OR = OS. The equation of RS is
y
S
R x
-4 0
Answer:…………………………
10. In the diagram , MLT is a right-angled triangle.
.
y
L(6,7)
M T(6,4)
0 x
Find
a) the coordinate of M,
b) the equation of the straight line LT.
Answer :.a)….............................
b)…………………….
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CHAPTER 5 : THE STRAIGHT LINE
EXERCISE 2
1. y
P Q (3,5)
O R x
2.
y
Q(0,5)
R(12,3)
P
0 x
S(4,k)
In the diagram, PQRS is a parallelogram. The equation of the straight line RS is
2y = x – 6. Find
a) the value of k,
b) the gradient of the straight line QR,
Answer: a)……………………
b)………………….
The diagram shows a parallelogram OPQR. Given that the gradient of OP = -
3
5
.
The x-intercept of line QR is …......
Answer :………………………
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3. In the diagram, OPQR is a parallelogram and O is the origin.
Find
a) the gradient of the straight line OR,
b) the equation of the straight line PQ
y Q
R(2,4)
P(6,1)
0 x
Answer: a)…………………
b)………………….
4. In the diagram PQRS is a parallelogram
P(-2,12) y
Q
S 0 x
R
a) Given that the gradient of line PQ is -3,
find the equation of PQ
b) Find the coordinate of point R.
Answer a).................................
b) ................................
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5. In the diagram, LH is a straight line.
Given that the gradient of the straight line LH is -1.
y
L(-3,9)
H(0,k)
0 x
Find
(a) the value of k,
(b) the equation of the stragiht line LH.
Answer: a)……………………
b)…………………….
6. In the diagram above, ABCD is a parallelogram and O is the origin. The straight
line BD is parallel with the y-axis and the equation of line AB is y =
3
2
x + 4.
y B(6,10)
A C
0 D x
Find
(a) the x-intercept of the straight line AB,
(b) the gradient of AD,
Answer: a)……………………
b)……………………
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43
y
Q(4,8)
S(10,2)
0 P(2,0) R x
7. In the diagram, PQ is parallel to RS and O is the origin.
Find
a) the gradient of RS
b) the x- intercept of RS
Answer: a)……………………
b)……………………
8. In the diagram OM =
3
1
OA and the length of the straight line OA is 9 units.
y
A B
0 M x
(a) Find the coordinate of point B.
(b) Calculate the gradient of line MB. Answer a)..................................
b)..................................
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9. In the diagram, CD is parallel to EF.
y
D
y = 3x+5 F
0 x
C
Find E(-1,-4)
(a) the x-intercept of line CD,
(b) the equation of straight line EF.
Answer: a)……………………
b)……………………
10. In the diagram, EFGH is a parallelogram. Given that the gradient of line EF is
2
5
. Find
the coordinate of point G.
y
E H(8,5)
.
F 0 G x
Answer: ……………………
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CHAPTER 5 : THE STRAIGHT LINE
DIAGNOSTIC TEST
1. In Diagram 1, MN is a straight line.
Find the gradient of MN.
A -2
B
4
3
C -
4
3
D 2
2. Given that the equation of a straight line is x – 2y + 3 = 0. Find the x-intercept of
the straight line.
A -1
B -2
C -3
D -4
3. In Diagram 2, the length of OC is 2 units.
The gradient of line BC is
A 3
B 4
C -4
y
O
x
C
B A(10,6)
⋅
⋅
⋅
Diagram 2
N
M
8
6
0
y
x
Diagram 1
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D -3
4. Based on Diagram 3, find the equation of line PR.
A y = -x – 6
B y = -x + 6
C y = x + 6
D y = x – 6
5. In Diagram 4, the equation of the line WZ is y =
4
3
x.
Q (8, k) is a point on the line WZ.
Find the value of k.
A 6
B 7
C 8
D 9
6. The equation of a straight line passing through the point ( -3, 8 ) and parallel to
the line y =
3
2
x + 5 is
A y =
3
2
x + 8
B 3y = 2x + 10
C 3y = 2x + 30
D y =
3
2
x -3
0
y
Z
x
Q (8, k)
W
⋅ Diagram 4
O
P(8,2)
R(-2,-8)
y
⋅
⋅
x
Diagram 3
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7. In Diagram 5, OE = OG. Find the gradient of line EG.
A 1
B -1
C 2
D -2
8. In Diagram 6, find the gradient of the line OU.
A 1
B -1
C 2
D -2
9. The y-intercept of the straight line 4y = 3 – 2x is
A
4
3
B -
2
1
C -
4
3
D
2
1
G
E
x
y
0
Diagram 5
0
y
U(-3,6)
x
⋅
Diagram 6
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10. In Diagram 7, the length of OP is 10 units. The equation of line PR is
A y =
5
4
x + 8
B y = -
5
4
x + 8
C y =
4
5
x +4
D y = -
4
5
x + 4
P
R J ( 4, 8 )
0
x
y
⋅
⋅
⋅ Diagram 7
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CHAPTER 5 : THE STRAIGHT LINE
EXERCISE 1
1. y R(5,7)
Q(1,4)
x
P(-1,0) O
S
Diagram 1
In Diagram 1, straight lines PQ and RS are parallel. Find the
a) gradient of the line PQ ,
b) equation of the line RS ,
c) x-intercept of the line RS.
2. y.
N
K x
O M(5,0)
L
Diagram 2
In Diagram 2, straight lines KL and MN are parallel. The equation of the line KL is
y + 3x + 3 = 0. Find the
a) gradient of the line KL ,
b) equation of the line MN ,
c) y-intercept of the line MN.
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3. y F(3,k) G(7,10)
E
x
Diagram 3
In Diagram 3, straight line FG is parallel to the x-axis while the lines EF and GH are
parallel. The gradient of the line EF is 2.
a) State the value of k ,
b) Find the equation of the line GH ,
c) Find the coordinates of the point E .
4. y
M (5,20)
L
O x
K
Diagram 4
In Diagram 4, OKLM is a parallelogram and line ML is parallel to the y-axis.Point L is
on the x-axis.
a) State the coordinates of the point L ,
b) Find the y-intercept of the line KL,
c) Find the equation of the line KL.
O H
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5.
y
V(8, k)
U
T(-2,1)
x
S O W
Diagram 5
In Diagram 5 , the equation of the straight line STUV is 2y = x + 4. The lines OT and
UW are parallel. Find the
a) value of k ,
b) y-intercept of the line STUV ,
c) equation of the line UW .
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CHAPTER 5 : THE STRAIGHT LINE
EXERCISE 2
1.
Diagram 1
The equation of the straight line AB in Diagram 1 is .
16
2 +
= x
y
a) State the equation of the straight line BC,
b) Find the x-intercept of the straight line AB,
c) Find the equation of AC.
2.
Diagram 2
In Diagram 2, the straight line UV is parallel to CD. O is the origin.
a) Calculate the gradient of line CD,
b) Find the equation of line UZV,
c) Find x- intercept of line UZV.
Z (6,5)
Y
U
V
C (-2,3)
D (8,-2)
O
B(-3,10)
A O
C
x
y
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53
3. y
R
Q (h , 3 )
x
P( -8, 0 ) 0 S ( 6, 0 )
Diagram 3
In Diagram 3, the gradient of the straight line PQR is 3.Find the
a) value of h
b) y-intercept of the line RS
c) equation of the line RS
4. y
B (2 , 8 )
C
A (2 , 3 )
x
0
Diagram 4
In Diagram 4, OABC is a parallelogram. Find the
a) coordinates of C
b) equation of the straight line BC
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5.
Y
Q S
12
-4 3 X
P R
Diagram 5
In Diagram 5, straight lines PQ and RS are parallel.
a) State the gradient of PQ
b) Find the equation of RS
c) Find the intercept of RS
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CHAPTER 5 : THE STRAIGHT LINE
DIAGNOSTIC TEST
1.
In Diagram 1, A and D are located on the y-axis and ABCD is a parallelogram.
If the gradient of AB = -
2
1
,
a) State the gradient of CD.
b) Determine the coordinates of D.
c) Find the equation of the straight line AB.
[ 5 marks ]
2.
Diagram 2 shows a triangle PQR.
a) State the y-intercept of the straight line PQ,
b) Find the equation of the straight line QR,
c) Find the equation of a straight line that passes through P and parallel to the straight
line QR.
[ 5 marks ]
Diagram 1
A
B (6, 5)
C (6, 0)
D
x
y
O
P (0, 9)
Q (5, 7)
O
R (0, -5)
x
Diagram 2
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56
3.
In Diagram 3, MN = 12 units and parallel to the y-axis. Given NO = 6 units and
PO =
3
2
MN,
a) State the coordinates of P,
b) Find the gradient of the straight line PM,
c) Find the equation of the straight line PM.
[ 5 marks ]
4.
In Diagram 4 , two straight lines AB and CD intersect at point (-1, 3). Given the gradient of
AB is -1, find the
a) value of k,
b) equation of the straight line AB,
c) coordinates of point E.
[ 5 marks]
A
B
C
D
O
x
y
M
N
O
P
x
y
Diagram 3
y = 2x + k
Diagram 4
E
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5.
In Diagram 5, OQ and PR intersect at M which is midpoint of OQ. Given O is the
origin. Find
a) the value of h and k,
b) the equation of the straight line PR .
[ 5 marks]
y
Q (h, k)
M (4, 3)
P (-3, 6)
O
x
Diagram 5
R